Answer:
1. Temperature= 869.35 K
2. Pressure of combustion = 12994.043 kpa
3. Thrust = 127x10⁶N
Explanation:
this problem has been fully explained in the attachment. please use it to get a clearer explanation of the answer.
1.
The temperature = (273+2400k) - (3800)²/2(4003)
= 2673 - 14440000/8006
= 2673 - 1803.65
= 869.35 K
Approximately 869.4K
2. We first get mach number
= 3800/√1.3(923.8)(869.35)
= 3800/1021.78
= 3.719
Pressure = 100kpa[1+2.07464415]^1.3/0.3
= 12995.043kpa
C. Thrust
Pi/4(3800)²(0.3)²(100x10³)/(923.8)(869.4)
= 12678.621
= 126.781 kN
Thrust is approximately 127kN = 127x10⁶N
John ties a rope to a 15 kg crate and pulls it up an inclined plane at a constant speed υ as in (Figure 2). The coefficient of kinetic friction between the crate and the plane is 0.20. Assume the rope is parallel with the surface of the plane. What is the tension in the rope? Derive an expression for the tension in the rope for an arbitrary mass M and an inclination angle θ, for the case of a frictionless incline.
The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
What is the main reason of tension in the rope?The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
Therefore, Every physical object in contact with another one applies some force to that object.
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A child throws a stone into a pond. The stone creates ripples
when it hits the water. These ripples spread across the pond.
The child thinks that a leaf floating on the pond will move to the edge of
the pond with the ripples. Explain whether or not she is correct.
No, the youngster is mistaken. The leaf won't float to the edge of the pond due to the stone's waves.
What do pond ripples result from when a stone is tossed into the water?When a stone is put into a body of water, it creates waves that change in a stunning pattern, radiating outward from a centre that eventually goes still. The growing ring is referred to as a wave packet.
How can throwing a stone into water cause ripples to appear?A circle-shaped pattern of ripples is created on the water's surface when a stone is tossed into stillness. The particles vibrate due to the stone's kinetic energy. The particles in the subsequent layers receive the energy.
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How might form and function of a structure influence
each other?
Answer:
Explanation:
Form must follow function, otherwise the design of a structure is a failure. For example, the function (purpose) of a bridge is to provide a means of crossing an obstacle, such as a body of water, a valley, another road, etc. The form of the bridge must serve the purpose of providing safe and reliable passage of pedestrians, vehicles, trains, etc. A most basic form of a bridge is a beam design: simple, efficient, cost-effective, functional. If budget and public sentiment allow, additions to the design can be incorporated to make the bridge more aesthetically pleasing, but such additions do not add to the basic function.
A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 15 degrees above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?
Answer: See below
Explanation:
Given:
Mass of the Mercedes-Benz (m) = 1700 kg
Inclination of the road (θ) = 15.0
The free body diagram is shown in figure attached below
a) The normal force is equal to the cos component of the weight of the car.
\(\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}\)
b) The static force will be equal to the weight's sin component.
\(\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}\)
A ramp is set at 32° to the ground. A briefcase of mass 3.2 kg is pushed to the top of the ramp, increasing its GPE by 37 J. How long is the ramp?
When heat is added or removed from a substance, it's temperature and thermal energy will be ______.
Directly Proportional
Temperature is directly proportional to heat. The more the heat more the temperature there are a number of scales like degree Celsius, Fahrenheit, and Kalvin (SI Unit) of temperature which is calculated by the mercury.
As on high heat, mercury expands and on its expansion, we measure on a scale which simply means more the heat more the expansion, and more the temperature on the scale, and wise- versa.
And if we talk about thermal energy(Q) is also directly proportional to a change in temperature (negative when temperature decreases and increases on increasing the temperature). where Q = mc*(change in temperature). where m for the mass, and C is the constant for the type of substance we are taking to transfer the heat.
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The Complete Question is -
How Heat is related to temperature and thermal energy?
Suppose that 2 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 42 cm. (a) How much work is needed to stretch the spring from 32 cm to 34 cm
Answer:
Workdone = 0.025 Joules
Explanation:
Given the following data;
Workdone = 2J
Extension = 42 - 24 = 18 cm to meters = 18/100 = 0.18m
The workdone to stretch a string is given by the formula;
Workdone = ½ke²
Where;
k is the constant of elasticity.
e is the extension of the string.
We would solve for string constant, k;
2 = ½*k*0.18²
2 = ½*k*0.0324
Cross-multiplying, we have;
4 = 0.0324k
k = 4/0.0324
k = 123.46 N/m
a. To find the workdone when e = 32, 34.
Extension = 34 - 32 = 2 to meters = 2/100 = 0.02m
Workdone = ½*123.46*0.02²
Workdone = 61.73 * 0.0004
Workdone = 0.025 Joules
Therefore, the amount of work (in J) needed to stretch the spring from 32 cm to 34 cm is 0.67.
1. Multiple light bulbs are connected in series across a 120.0 V
source of emf. The current in the circuit is 1.25 A. If each light
bulb has a resistance of 3.00 £2, how many light bulbs are in
the circuit?
2. If the resistance of bulb A is 6 2, the resistance of bulb B is
18 02, and the equivalence resistance of the circuit is 1202,
what is the resistance of bulb C?
1) Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs: n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs. There are 32 light bulbs in the circuit.
2) The total resistance is equal to the sum of individual resistances: R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω. The resistance of bulb C is 96 Ω.
In a series circuit, the total resistance is equal to the sum of individual resistances. Using Ohm's Law, we can find the total resistance:
R = V/I = 120.0 V/1.25 A = 96 Ω
Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs:
n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs
Therefore, there are 32 light bulbs in the circuit.
In a series circuit, the total resistance is equal to the sum of individual resistances:
R_eq = R_A + R_B + R_C
Substituting the given values:
120 Ω = 6 Ω + 18 Ω + R_C
Solving for R_C:
R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω
Therefore, the resistance of bulb C is 96 Ω.
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What is friction and weight and what is hooks law
Answer:
Hooke's law states that the applied force F equals a constant k times the displacement or change in length x, or F = kx. ... Hooke's law describes the elastic properties of materials only in the range in which the force and displacement are proportional.
Explanation:
A wagon, Initially traveling at a constant 3.6 m/s, starts going down a hill that creates an acceleration of
1.6 m/s2. What is the wagon's velocity 4.8 s after it starts accelerating down the hill?
2. Gerard is riding his bicycle directly east. His maximum
instantaneous velocity was 8 meters per second and his
minimum instantaneous velocity was 0 meters per second. He
covered 7.20 kilometers in 20.0 minutes. What is his average
velocity for the ride?
Gerard's average velocity for the ride is 6 meters per second.
To find Gerard's average velocity for the ride, we can use the formula:
Average velocity = Total displacement / Total time
First, we need to convert the distance traveled from kilometers to meters:
7.20 kilometers * 1000 = 7200 meters
Next, we convert the time from minutes to seconds:
20.0 minutes * 60 = 1200 seconds
Now, we can calculate the total displacement by subtracting the initial position from the final position. Since Gerard is riding directly east, there is no change in the east-west direction, so the displacement is equal to the distance traveled:
Total displacement = 7200 meters
Finally, we substitute the values into the average velocity formula:
Average velocity = 7200 meters / 1200 seconds
Average velocity = 6 meters per second
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Does ISO sensibilty in photography have a unit of measurement?
Ex: like lux, or nit, etc...
ISO sensitivity in photography does not have a specific unit of measurement.
ISO sensitivity in photography does not have a specific unit of measurement. ISO stands for International Organization for Standardization, and it is a standardized scale used to measure the sensitivity of a camera's image sensor to light. It is commonly referred to as "ISO speed" or "ISO value."
The ISO scale typically ranges from low values, such as ISO 100 or 200, to higher values like ISO 1600 or even higher. The higher the ISO value, the more sensitive the camera's sensor is to light, allowing for capturing images in low-light conditions without the need for longer exposure times.
ISO sensitivity is not expressed in units like lux or nit, which are measurements of illuminance or luminance, respectively. Lux measures the amount of light per unit area, while nit measures the brightness of a light source.
ISO sensitivity is a relative scale that represents the amplification of the sensor's signal. As the ISO value increases, the sensor's sensitivity is increased, but at the cost of introducing more digital noise and reducing image quality.
In summary, ISO sensitivity in photography does not have a specific unit of measurement. It is a standardized scale used to indicate the sensitivity of a camera's image sensor to light, allowing photographers to adjust exposure settings and capture images in various lighting conditions.
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Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed
Answer: The scenario violates the second law of thermodynamics.
Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.
Please help me asap with all I’ll mark you brainly
The point that represents maximum potential energy is W.
The point that represents potential energy at 0 joules is Z.
The point that represents potential energy at 50 percent is Y.
The point that represents maximum kinetic energy is X.
Potential energy is the energy held through an object because of its function relative to other items, stresses inside itself, its electric-powered fee, or different elements. potential energy is energy this is saved – or conserved - in an object or substance. This saved energy is based totally on the position, arrangement, or state of the object or substance.
Potential energy refers to the stored energy within an object that exists because of the item's role, country, or arrangement. Potential energy is the strength this is stored in an item because of its function relative to some 0 roles. An item possesses gravitational capability strength if it is located at a top above (or beneath) the zero top.
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The amount of energy needed to a power a 0.20kw bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of
The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.
To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:
Potential energy (PE) = mass (m) × gravity (g) × height (h)
Where:
m = 2.5 kg (mass of the object)
g = 9.8 m/s² (acceleration due to gravity on Earth)
h = ? (height)
First, let's find the height (h) by rearranging the formula:
h = PE / (m × g)
Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):
Energy (E) = power (P) × time (t)
E = 0.20 kW × 1 min × 3,600 J/kW
Now, we can substitute the values into the equation to find the height:
h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)
Calculating the expression on the right side:
h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)
Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.
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what two things make up an ionic bond?
In one type of Combustion reaction, _______ is combined with oxygen to create heat and light.
A) nitrogen
B) carbon
C) hydrogen
Answer:
carbon.
Explanation:
the reaction would then create c02 as a product
What is the best anime show to watch? I need to watch some more anime and I need some shows lol
Try watching Demon Slayer on Netflix. It's a new series, and it's very entertaining to watch!! :)
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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The moon weighs 7x1022kg and we are about 380,000,000m away from the moon. If you weigh 50kg, how much gravitational force does the moon have on you? (G=6.7x10-¹¹)
The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:
F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².
Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.
The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.
Therefore, we have:
m₁ = 50 kg
m₂ = 7 × 10²² kg
r = 380,000,000 m
G = 6.7 × 10⁻¹¹ N m²/kg²
Substituting these values into the formula, we get:
F = (G × m₁ × m₂) / r²
F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²
F = 1.15 N
Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
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/ Assignment 01 Science teachers think practical science is a good thing. a. Agree b. Disagree c. Uncertain
It is reasonable to conclude that science teachers generally agree that practical science is beneficial. Therefore, option (A) is correct.
Practical science refers to hands-on activities, experiments, and applications of scientific concepts in real-world settings. Science teachers, who are experts in their field and experienced in teaching science, understand the importance of practical science in facilitating students' understanding, engagement, and application of scientific principles.
Practical science allows students to develop critical thinking, problem-solving, and inquiry skills, as well as promoting a deeper understanding of scientific concepts. It also fosters curiosity, creativity, and a passion for science, making it an effective and essential component of science education.
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In hiking, what fitness component is required of you
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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A 1.20 kg copper rod resting on two horizontal rails 0.90 m apart carries a
current I = 55.0 A from one rail to the other. The coefficient of static friction
between the rod and rails is μs= 0.60.
(a) What is the smallest vertical magnetic field B that would cause the rod to
slide?
(b) Suppose a B field is directed at some angle to the vertical φ, with the current
along the rod directed into the page, as shown. Find an expression for B as a
function of φ for the case when the rod is just on the verge of beginning to slide.
(c) Find the value of φ which yields the smallest value of B that would cause
the rod to slide, together with the corresponding value of B.
(a) The smallest vertical magnetic field B that would cause the rod to
slide is 0.145 Tesla for given The coefficient of static friction
between the rod and rails is μs= 0.60
What is magnetic field ?A magnetic field is a vector field that describes the magnetic influence on moving charges, currents, and magnetic materials. A moving charge in a magnetic field is subjected to a force that is perpendicular to both its own velocity and the magnetic field.
(a) using formula
μs × m × g = I × L × B
μs= 0.60
M= 1.2 kg
I = current = 55.0 A
L = Length = 0.9 m
magnetic field (B) = 0.145 Tesla
(b) expression
force (f) = I × L × B × sinФ
(c) given B = 0.145 Tesla
μs × m × g= I × L × B × sinФ
Ф = 90°
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The equation for the period of a pendulum is T=2 Square Root of L/g.
How does your equation from 1B relate to the pendulum equation?
Use the pendulum equation to calculate the period of a 1.50 m pendulum. Remember that the value of "g" is 9.81 m/s2.
Compare your calculated period (from 3B) to your data by using the graph you constructed. Explain any possible sources for error if your graph does not agree with your calculated results.
Answer:
T = 2.457 s
Explanation:
In this exercise we have the response of a simple pendulum consisting of a ball supported by an inextensible thread of negligible mass, the period of this system for small oscillations is
T = 2π √L/g
indicate that the length of the pendulum is L = 1.50 m
let's calculate the period
T = 2π √ (1.50 / 9.81)
T = 2.457 s
It asks us to compare with the value found in a graph, in general in simple pendulum experiments the constructed graph is T2 against L, which gives us a line and from which the equation of the line with the slope and the point of cut, in this equation the length is entered and the period is calculated.
In many cases the values found by the two methods are similar, but not the same, this is due to errors in time measurements, the most common are
* launch the pendulum from slightly different points
* reaction time when switching the timer on and off
* errors in reading the points for calculating the graph.
Which measurement has three significant figures? A 0.015m B 105m C 150m D 1.050
Answer:
B.105
Explanation:
Non-zero digits are always significant.
Zeros between significant digits are also significant.
Trailing zeros are significant only after a decimal point.
0.015 has 2 significant figures.
105 has 3 significant figures.
150 has 2 significant figures.
1.050 has 4 significant figures.
A jet requires 5 seconds of acceleration from rest to cover a 94 m distance. What was the acceleration?
When ever there is a change in Velocity, there will be Acceleration. Let us now understand the concept of Acceleration with illustrative examples.
Let's suppose I have a car moving with a constant Velocity of 90 km along a straight line. It can be seen that the helicopter flying at roughly a speed of 20,000 km.
using the equation of motion formula;
S = ut + 1/2 + at²
Given,
S = 94 m
t = 5 sec
U = 0 initial velocity
S = ut + 1/2at²
94 = 0 + 1/2a 5²
a = (94 × 2)/ 25
Acceleration = 7.52 m/s²
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reposting this question
jacob is kayaking across the chattooga river at a velocity of 2.5 m/s east. the river current today is 6 m/s south. find is velocity and direction,
Upon crossing the Chattooga River, the Jacob's last speed was measured at 6.5 m/s, with the direction of travel being to the south-east.
Describe the resulting velocity vector in detail.The overall vector velocity of an object is in fact the sum of its individual vector velocities.The sum of the vector forces exerted on an object are represented by the scalar product of its mass and acceleration vector.We measure two perpendicular velocities due to the kayaker and the river: 2.5 m/s downstream inside a southerly direction and 6 m/s across the river in such an easterly direction.
The Pythagorean Theorem makes the following predictions about the amount of a resultant velocity:
v = √(2.5)² + (6)²
v = √42.25
v = 6.5 m/s
The direction that results will be south-east.
As a result, the Jacob's final speed when it crosses the Chattooga River is determined to be 6.5 m/s, with the direction of travel being south-east.
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The radius of the circular path of an ion in a mass spectrometer is given by r=1/B √2Vaccelm/q. Use this equation to explain how a mass spectrometer is able to separate ions of different masses.
The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path
What is the mass spectrometer?From the formula in the question;
B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.
The accelerating voltage used to move the ions is called Vaccelm.
The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.
The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.
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In an optics experiment, a lens is placed between a luminous object and a screen, give three possible reasons to account for the absence of an image on the screen.
In an optics experiment, the three possible reasons to account for the absence of an image on the screen. are:
Image not in focus.Wrong focus plane.Slide not centered.What is the above terms about?Image out of focus - The picture is frequently just out of focus. Perhaps you over-focused on one area, making it impossible for you to see a clear picture. Some folks struggle to locate a clear image and repeatedly turn the focus knob. The focus can be lost considerably more readily at higher magnifications, which is a special issue.
Incorrect focus plane - It's possible that you can see a clear image, but not of the thing you're trying to see. In this instance, it's likely that you were more interested in the dust on the slide's or cover glass' surface than the object itself. With the low magnification objective in place, it is preferable to start anew in this situation and refocus.
Lastly, Uncentered slides - This is yet another frequent issue. Are you attempting to study a region of the slide that does not include the object of interest or are you truly gazing at the specimen? Perhaps you cannot see anything because you are looking at a region of the slide that is completely devoid of specimens.
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