A long, straight conveyor belt at a sushi restaurant carries sushi past customers with a constant velocity. If the sushi roll you want is 4.30 m to the right of you 11.0 s after exiting the little door at the beginning of the conveyor belt, and it is still 2.10 m to the right of you 10.0 s later, how far is the little door to the right of you?

Answer:

B

Explanation:

quantization of energy is only seen in atoms

Answer:

A:The dissaperance of a solid stirred in water

Answer:

The answer is 8m N

Explanation:

When a tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward. then the distance traveled by it is 82 m and the displacement covered by it is 26 m in a southward direction

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.

Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.

Thus, when a tennis ball travels 16 meters to the north, 22 meters to the south, 12 meters to the north, and 32 meters to the south. then it has a covered distance of  82 meters and has covered 26 meters of displacement in a southerly direction.

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The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

clouds are created when water vapor and invisible gas turns into water droplets and these water droplets form tiny particles like dust and float in the air.

you have cumulus

cirrus

cirrostraus  

Explanation:

Answer:

\(V_{pa}=690km/hr\)

Explanation:

In order to solve this problem, we can start by drawing a diagram of what the problem looks like. (See attached picture).

We can treat this as a vector problem, so we can start by finding the velocities of the plane with respect to the earth as it goes north and east. Velocity is found by using the following formula:

\(Velocity=\frac{distance}{time}\)

so

\(V_{paN}= \frac{780km}{2hr}\)

\(V_{paN}=390 km/hr\)

Since air isn't affecting the north direction of the plane, we will keep this as the velocity due north.

Now let's find the velocity of the plane with respect to the earth towards the east:

\(V_{pE}=\frac{810km}{2hr}\)

\(V_{pE}=405 km/hr \)

In this case, since the wind is blowing from east to west, then it affects directly the velocity of the plane with respect to the earth, so we can use the following formula to determine the Velocity of the plane with respect to the air in the eastern direction:

\(V_{paE}-V_{a}=V_{pE}\)

so we can solve this for the velocity of the plane on the air towards the east, so we get:

\(V_{paE}=V_{pE}+V_{a}\)

so we get:

\(V_{paE}=405 km/hr + 165km/hr\)

\(V_{paE}=570 km/hr\)

So now we can use this data to find the velocity of the plane with respect to the air:

\(V_{pa}=\sqrt{V_{paN}^{2}+V_{paE}^{2}}\)

so we get:

\(V_{pa}=\sqrt{(390km/hr)^{2}+(570km/hr)^{2}}\)

\(V_{pa}=690.65 km/hr\)

Answer:

Is pushed by another object

Explanation:

According to Newton's third law

Every action in the universe has opposite and equal reaction.

Or

\(\\ \sf\dashrightarrow F_A=-F_B\)

An object exerts a reaction force when it ____.

A. is pulled by another object

B. maintains its direction of motion

C. has a net force of zero

D. is pushed by another object

Your answer will be (D)

Answer:

The value is      \(A = 39315 \ m^2\)

Explanation:

From the question we are told that

    The velocity which the rover is suppose to land with is  \(v = 1 \ m/s\)

    The  mass of the rover and the parachute is  \(m = 2270 \ kg\)

     The  drag coefficient is  \(C__{D}} = 0.5\)

      The atmospheric density of Earth  is  \(\rho = 1.2 \ kg/m^3\)

     The acceleration due to gravity in Mars is  \(g_m = 3.689 \ m/s^2\)

Generally the Mars  atmosphere density is mathematically represented as

          \(\rho_m = 0.71 * \rho\)

=>        \(\rho_m = 0.71 * 1.2\)

=>        \(\rho_m = 0.852 \ kg/m^3\)

Generally the drag force on the rover and the parachute  is mathematically represented as

          \(F__{D}} = m * g_{m}\)

=>       \(F__{D}} = 2270 * 3.689\)  

=>       \(F__{D}} = 8374 \ N\)  

Gnerally this drag force is mathematically represented as

         \(F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}\)

Here A is the frontal area

So  

         \(A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }\)

=>       \(A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }\)

=>       \(A = 39315 \ m^2\)

Answer:

the max is 2,500 or less

Explanation:

because you cant owe anymore

The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)

The magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.

So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.

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Answer: As i know, please see the Explanation

Explanation:The cell contains 3% salt, so we can safely assume that it contains 100%−3%=97% water.

500 energy sted dissipated as thermal energy.

In the question total work done is

W= force x displacement

= 150x 20

=3000 J

But we know that work is done against weight and against frictional force

Work done against friction is dissipated as thermal energy

So resolving g to components

g sin(Q) will be parallel to inclined plane

So we have work done = mg sinQ x S

= 25 x 10 x 10/20

=2500 J

So thermal energy dissipation = 3000-2500

=500 J

What is thermal energy?

Thermal energy is the energy contained inside a system that is accountable for its temperature. Heat is the passage of thermal energy. Thermodynamics is a whole field of physics that deals with how heat is transmitted between various systems and how work is done in the process.

Hence B  is a correct answer.

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The total mass of water vapor in the air in the apartment can be calculated using the formula for absolute humidity. The total mass is approximately 5.04 kg.

To calculate the total mass of water vapor in the air, we need to determine the volume of the apartment and then use the formula for absolute humidity.

Calculate the volume of the apartment: The volume of the apartment can be calculated by multiplying its dimensions: Volume = length x width x height = 18 m x 9 m x 6 m = 972 cubic meters.

Determine the vapor pressure: The relative humidity of 59 percent indicates that the air is holding 59 percent of the maximum amount of water vapor it can hold at the given temperature.

Find the saturation vapor pressure: The saturation vapor pressure is the maximum pressure of water vapor that air can hold at a given temperature. At 25°C, the saturation vapor pressure is approximately 3.17 kPa.

Calculate the actual vapor pressure: The actual vapor pressure can be calculated by multiplying the saturation vapor pressure by the relative humidity: Actual vapor pressure = Relative humidity x Saturation vapor pressure = 0.59 x 3.17 kPa = 1.867 kPa.

Calculate the mass of water vapour: The mass of water vapor can be determined using the formula for absolute humidity: Mass = Absolute humidity x Volume = (Actual vapor pressure / (0.287 kJ/(kg·K) x Temperature)) x Volume. In this case, the temperature is 25°C, which is 298 K.

Mass = (1.867 kPa / (0.287 kJ/(kg·K) x 298 K)) x 972 m^3 = 5.04 kg.

Therefore, the total mass of water vapor in the air in the apartment is approximately 5.04 kg.

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Answer:

no entiendo tu pregunta

Hellow!

For this use the next formula:

Vf = Vo + gt

Initial velocity is zero, so the formula simplificate:

Vf = gt

Data:

Vf = Final velocity = ?

g = Gravity = 9.8 m/s²

t = Time = 12 s

Replacing according our data:

Vf = 9.8 m/s² * 12 s

Vf = 117.8 m/s

The final velocity will be 117.8 meters per second.

Answer:

1.74

Explanation:

"How do you calculate the mechanical advantage of a block and tackle pulley?

To calculate the mechanical advantage, we can either divide the weight of the object being lifted by the force required to lift it or we can divide the amount of rope we have to pull by the distance the object moves."

If we use the rope method the mech advantage is  33.0/16.5 = 2

  now if we use the forces   MA = 225/129 =1.74 <==== this is not equal to '2' as we first found due to energy being lost to friction/deformation of rope etc.              SO I would say the true mechanical advantage = 1.74  

Efficiency =  1.74/2 = 87%

Answer:

his distance is too small (r = 0.01 mm), therefore the cut can be at any distance

Explanation:

For this exercise let's use the ampere law.

Let's use a cylinder as the circulating surface

          ∫ B. ds = μ₀ I

in this case the field is circular and ds is circular therefore the angle between them is zero and cos 0 = 1

          B 2π r =  μ₀ I

          r =  \(\frac{\mu_o I}{2\pi B}\)

The field needed to demagnetize the card is B = 1000 gauss = 0.1 T

          r = \(\frac{4\pi 10^{-7} 5.0 }{2\pi \ 0.1}\)

           r = 2 10⁻⁷  5.0/0.1

          r = 1  10⁻⁵ m

this distance is too small (r = 0.01 mm), therefore the cut can be at any distance

The overall energy of the biker at the midpoint of the hill is 12,702.5 joules (J).

To determine the overall energy of the biker, we need to consider both the kinetic energy and potential energy at the midpoint of the hill.

1. Kinetic Energy:

The kinetic energy (KE) of an object is given by the formula:

KE = 1/2 * mass * velocity^2

Substituting the values:

Mass (m) = 55 kg

Velocity (v) = 13 m/s

KE = 1/2 * 55 kg * (13 m/s)^2

KE = 1/2 * 55 kg * 169 m^2/s^2

KE = 1/2 * 55 kg * 169 m^2/s^2

KE = 1/2 * 9235 kg·m^2/s^2

KE = 4617.5 J

2. Potential Energy:

The potential energy (PE) of an object is given by the formula:

PE = mass * gravitational acceleration * height

Substituting the values:

Mass (m) = 55 kg

Gravitational acceleration (g) = 9.8 m/s^2

Height (h) = 15 m

PE = 55 kg * 9.8 m/s^2 * 15 m

PE = 8085 J

3. Overall Energy:

The overall energy (E) is the sum of the kinetic energy and potential energy:

E = KE + PE

E = 4617.5 J + 8085 J

E = 12702.5 J

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Answer:

identify who they are as a person

Explanation:

Answer:

4

Explanation:

As you can see in the free body diagram there are 4 forces acting on the body.

Answer:

i think its B

(could possibly be C but i think its B)

Explanation:

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

Force = 50N

Weight = Mass × Gravity = 25

Mass = 25 ÷ 10 = 2.5Kg

Time = 5 Seconds

we know

Force = mass × acceleration

50 = 2.5 × Velocity ÷ Time

50÷2.5 = Velocity ÷ 5

Velocity = 250 ÷ 2.5

Velocity = 100m/s.

Answer:

100m/s

Explanation:

force(f) = 50N

weight = 25N

weight = mass × gravity

25 = m × 10

25 = 10m

m = 25/10

m = 2.5kg

time(t) = 5sec

impulse formula

ft = m(∆v)

by substituting

50 × 5 = 2.5∆v

250 = 2.5∆v

∆v = 250/2.5

∆v = 100m/s

i hope this helped

Answer: the answer is corect of what everone else said

Explanation:

Starting from rest and accelerating at 4.8 m/s², the plane's velocity at time t is

v(t) = (4.8 m/s²) t

so that after 15 s, its speed at takeoff be

v(15 s) = (4.8 m/s²) * (15 s) = 72 m/s

In this time it takes for the plane to take off, it will travel a distance at time t of

x(t) = 1/2 (4.8 m/s²) t²

and it takes 15 s to take off, so the runway would have to have a length of

x(15 s) = 1/2 (4.8 m/s²) * (15 s)² = 540 m

Answer:

Suppose you take two non-zero displacements represented by vectors A & B. The magnitude of A is 6 and the magnitude of B is 1. What is the magnitude of the smallest displacement you can end up from the starting point?

The smallest displacement would be when the vectors are in the opposite direction, therefore, the magnitude of the minimum displacement is 5.

Explanation:

Answer:

its distance and displacement

Explanation:

The average power of the signal Y(t) is approximately 4.166 W.

The energy of the signal Y(t) over one period is approximately 0.833 J.

We can calculate the average power:

P = (1/T) ∫0ⁿ |Y(t)|² dt

P = (1/0.1) ∫_0⁰¹ [(-4 + Cos(2π10t - π/4)) + Si²(2π20t)] dt

P = 2 ∫0⁰¹[16 + Cos²(2π10t - π/4) - 8Cos(2π10t - π/4)] dt

P = 2 [16t + (1/2)(t/2 + Sin(4π10t - π/2))/20 - 4Sin(2π10t - π/4)]0⁰₁

P ≈ 4.166 W

We can calculate the energy:

E = ∫-∞^∞ |Y(t)|² dt

E = T ∫0ⁿ |Y(t)|² dt

E = 0.1 ∫0^⁰¹ [(-4 + Cos(2π10t - π/4))² + Sin²(2π20t)] dt

E = 0.2 ∫0⁰¹ [16 + Cos²(2π10t - π/4) - 8Cos(2π10t - π/4)] dt

E = 0.2 [16t + (1/2)(t/2 + Sin(4π10t - π/2))/20 - 4Sin(2π10t - π/4)]0⁰¹

E ≈ 0.833 J

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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