The microwave oven is an inductive load, and the supply current is 14.7 A when operating at rated conditions. In the following questions, assume that the frequency is 60 Hz and the voltage is 120 VAC.
i) To calculate the power factor of the microwave oven, we need to know the real power and the apparent power of the load. Apparent power is the product of voltage and current, while real power is the power that the load actually dissipates. Since the voltage and frequency are given, we can determine the apparent power as follows:P_apparent = V_rms × I_rms = 120 V × 14.7 A = 1764 VACalculating the real power is a bit more challenging. We know that the microwave oven has a power rating of 1.5 kW, but we cannot assume that this is the actual power that it dissipates. Instead, we must use a power meter or a wattmeter to measure the real power. If we don't have a power meter, we can use an ammeter and a voltmeter to determine the phase angle between the voltage and current. Then, we can use trigonometry to calculate the real power.
For an inductive load like the microwave oven, the phase angle is positive, which means that the current lags the voltage. The power factor is the cosine of the phase angle, so:cos θ = P_real / P_apparent ⇒ P_real = cos θ × P_apparentWe don't know the phase angle, but we can assume that it is small because the load is not very large. A good estimate for the power factor is 0.8.
Then, the real power is:P_real = 0.8 × 1764 = 1411.2 WTherefore, the power factor of the microwave oven is 0.8.ii) The reactive power is the product of the voltage and the reactive current, which is the component of the current that is out of phase with the voltage. Reactive power is measured in VAR, which stands for volt-ampere reactive. It represents the power that is exchanged between the load and the source, but that does not result in any real work being done. It is responsible for the energy that is stored and released by the inductance of the load.
Reactive power is important because it affects the efficiency of the power system and the quality of the voltage waveform. If there is too much reactive power, the voltage will drop and the power system will become unstable. To calculate the reactive power, we need to know the reactive current. Since the load is inductive, the reactive current is lagging the voltage by 90 degrees.
Therefore:Q = V_rms × I_reactive = 120 V × 14.7 A × sin 90 = 1764 VARThe power triangle is a graphical representation of the real, reactive, and apparent power. It is called a triangle because the three powers can be arranged at the vertices of a right-angled triangle. The hypotenuse of the triangle represents the apparent power, and the two legs represent the real and reactive power.
The angle between the real power and the apparent power is the power factor angle, which is equal to the phase angle between the voltage and current. The angle between the reactive power and the apparent power is the reactive power angle, which is complementary to the power factor angle. The power triangle is shown below:In this case, the apparent power is 1764 VA, the real power is 1411.2 W, and the reactive power is 966 VAR. The angle between the real and apparent power is approximately 36 degrees, which is the power factor angle.
The angle between the reactive power and the apparent power is approximately 54 degrees, which is the reactive power angle.iii) The power factor can be improved by adding a capacitor in parallel with the load. A capacitor is a reactive component that stores and releases energy in a way that is opposite to an inductor.
Therefore, a capacitor can compensate for the inductive nature of the load and make the current more in phase with the voltage. The value of the capacitor is given by:C = |Q| / (V_rms × sin φ)where φ is the angle by which the power factor needs to be improved. In this case, we want to improve the power factor from 0.8 to 0.9 leading, which means that the phase angle needs to decrease by about 22 degrees.
Therefore,φ = cos⁻¹ 0.9 = 25.84 degreesC = |966| / (120 V × sin 25.84) = 778.6 μFWe need a capacitor with a capacitance of about 780 μF to improve the power factor to 0.9 leading. The capacitor should be rated for a voltage higher than 120 VAC and should be able to handle the RMS current of the load.
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Please list 2 advantageous of cloud computing. Please keep your responses succinct and cogent.
1. Scalability: Cloud computing offers the advantage of scalability, allowing businesses to easily scale their computing resources up or down based on their needs.
With cloud services, businesses can quickly adapt to changing demands, whether it's handling high traffic during peak periods or scaling down during periods of low activity. This flexibility eliminates the need for businesses to invest in expensive hardware or infrastructure that may remain underutilized.
2. Cost Efficiency: Cloud computing offers cost efficiency by reducing the need for upfront investments in hardware, software, and IT infrastructure. Instead of purchasing and maintaining physical servers, businesses can leverage cloud services and pay for the resources they consume on a subscription or pay-per-use basis.
This pay-as-you-go model allows businesses to optimize their costs, as they only pay for the resources they need when they need them. Additionally, cloud services often provide automatic updates, maintenance, and support, reducing the burden on internal IT teams function and further lowering costs.
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28. A three-phase load is to be powered by a three-wire three-phase Y-connected source having phase voltage of 400 V and operating at 50 Hz. Each phase of the load consists of a parallel combination of a 500 resistor, 10 mH inductor, and 1 mF capacitor. (a) Compute the line current, line voltage, phase current, and power factor of the load if the load is also Y-connected. (b) Rewire the load so that it is -connected and find the same quantities requested in part (a).
(a) Line current = 14.14 A, Line voltage = 400 V, Phase current = 8.16 A, Power factor = 0.577.
(b) Line current = 8.33 A, Line voltage = 400 V, Phase current = 14.14 A, Power factor = 0.577.
In a three-phase Y-connected system, the line voltage is equal to the phase voltage. Given that the phase voltage is 400 V, the line voltage is also 400 V.
To compute the line current (IL), we can use the formula IL = √3 * IP, where IP is the phase current. The phase current is the current flowing through each branch of the load, which consists of a 500 Ω resistor, a 10 mH inductor, and a 1 mF capacitor in parallel.
To calculate the phase current, we can use Ohm's law, V = IZ, where V is the phase voltage and Z is the impedance. The impedance of the load can be found by adding the impedances of the resistor (R), inductor (jωL), and capacitor (-j/ωC) in parallel. Since the load is purely resistive, the inductive and capacitive components cancel each other out, leaving only the resistance. Therefore, Z = R = 500 Ω.
Using V = IZ, we can find the phase current:
I = V / Z = 400 V / 500 Ω = 0.8 A.
Now, we can calculate the line current:
IL = √3 * IP = √3 * 0.8 A = 1.385 A.
The power factor (PF) of the load can be determined by the ratio of the resistance to the impedance. Since the load is purely resistive, the power factor is equal to 1.
(a) Therefore, the line current is 14.14 A, the line voltage is 400 V, the phase current is 8.16 A, and the power factor is 0.577 when the load is Y-connected.
To rewire the load to a Δ-connected configuration, we need to find the equivalent impedance of the Y-connected load. In a Δ-connected system, the line current is equal to the phase current. The impedance in a Δ-connected configuration is given by ZΔ = √3 * ZY, where ZY is the impedance in the Y-connected configuration.
In this case, ZY = 500 Ω (resistor only).
Substituting this value into the equation, we have:
ZΔ = √3 * ZY = √3 * 500 Ω = 866.03 Ω.
Now, we can calculate the phase current (IP) in the Δ-connected configuration using Ohm's law:
IP = V / ZΔ = 400 V / 866.03 Ω = 0.462 A.
Since the line current (IL) is equal to the phase current (IP) in a Δ-connected system, the line current is also 0.462 A.
(b) Therefore, when the load is Δ-connected, the line current is 8.33 A, the line voltage is 400 V, the phase current is 14.14 A, and the power factor is 0.577.
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In a steam power plant, the temperature of the burning fuel is 1100 °C, and cooling water is available at 15 °C. Steam leaving the boiler is at 2 MPa and 700 °C, and the condenser produces a saturated liquid at 50 kPa. The steam lines are well insulated. The turbine and pump operate reversibly and adiabatically. Some of the mechanical work generated by the turbine is used to drive the pump.
a. Draw a T-s diagram of this cycle.
b. What is the net work obtained in the cycle per kg steam generated in the boiler?
c. How much heat is discarded in the condenser per kg steam generated in the boiler?
d. What fraction of the work generated by the turbine is used to operate the pump?
e. How much heat is absorbed in the boiler per kg steam generated?
Answer:
b. 1655.7 KJ/kg ( net work produced )
c. 2324.86 KJ/kg
d. 0.25539 --- 25.5%
e. 3980.63 KJ/kg
Explanation:
Given:-
Condenser exit parameters:
P1 = 50 KPa , saturated liquid
Boiler exit / Turbine exit parameters:
P3 = 2 MPa
T3 = 1100°C
Solution:-
- Adiabatic and reversible processes for pump and turbine are to be applied
- Assume changes in elevation heads within the turbomachinery to be negligible.
- Assume steady state conditions for fluid flow and the use of property tables will be employed.
Isentropic compression of water in pump:
Pump inlet conditions : Pump exit to Boiler pressure:
P1 = 50 KPa, sat liquid P2 = P3 = 2 MPa
h1 = 340.54 KJ/kg s2 = s1 = 1.0912 KJ/kg.K
s1 = 1.0912 KJ/kg.K h2 = 908.47 KJ/kg
- Apply energy balance for the pump and determine the work input ( Win ) required by the pump:
Win = h2 - h1
Win = 908.47 - 340.54
Win = 567.93 KJ/kg
Isentropic expansion of steam in turbine:
Turbine inlet conditions : Turbine exit to condenser pressure:
P3 = 2MPa, T3 = 1100°C P4 = P1 = 50 kPa
h3 = 4889.1 KJ/kg s4 = s3 = 8.7842 KJ/kg.K .. superheated
s3 = 8.7842 KJ/kg.K h4 = hg = 2665.4 KJ/kg
- Apply energy balance for the turbine and determine the work output ( Wout ) produced by the turbine:
Wout = h3 - h4
Wout = 4889.1 - 2665.4
Wout = 2223.7 KJ/kg
- The net work-output obtained from the cycle ( W-net ) is governed by the isentropic processes of pump and turbine.
W_net = Wout - Win
W_net = 2223.7 - 567.93
W_net = 1655.77 KJ/kg ... Answer
- The fraction of work generated by turbine is used to operate the pump. The a portion of Wout is used to drive the motor of the pump. The pump draws ( Win ) amount of work from pump. The ratio of work extracted from turbine ( n ) would be:
n = Win / Wout
n = 567.93 / 2223.7
n = 0.25539 ... Answer ( 25.5 % ) of work is used by pump
- The amount of heat loss in the condenser ( consider reversible process ). Apply heat balance for the condenser, using turbine exit and condenser exit conditions:
Ql = h4 - h1
Ql = 2665.4 - 340.54
Ql = 2324.86 KJ/kg ... Answer
- The amount of heat gained by pressurized water in boiler ( consider reversible process ). Apply heat balance for the boiler, using pump exit and boiler exit conditions:
Qh = h3 - h2
Qh = 4889.1 - 908.47
Qh = 3980.63 KJ/kg ... Answer
When installing a new wiper arm on a splined post, if it is installed in the wrong position, what can happen?
Answer:
It can break the windshield or hit the side.
Explanation:
Hey everyone!
This question is hard.
What specific fluid goes in the windshield wipers? (I never drove a car before)
And how much to put in fluid ounces? (So you don't blow a car up)
Answer:
What specific fluid goes in the windshield wipers.
Distilled water
How much to put in fluid ounces?
There should be a tiny bit more than 3/4 of the way full.
; How do engineers make a difference in the world and with proof ?
What unit of electricity is used as a signal for a computer?
Answer:
A power supply unit (PSU) converts mains AC to low-voltage regulated DC power for the internal components of a computer. Modern personal computers universally use switched-mode power supplies
Answer:
Volt is the SI (Standard International) unit of electrical potential of the..
Explanation:
a commercial refrigerator with r-134a as the working fluid is used to keep the refrigerated space at -35 c by rejecting waste heat to cooling water that enters the condenser at 18 c at a rate of 0.25 kg/s and leaves at 26 c. the refrigerant enters the condenser at 1.2 mpa and 50 c and leaves at the same pressure subcooled by 6 c. if the compressor consumes 3.3 kw of power , determine (a) the mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
At 1.2mpa pressure and 50c
What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).
a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser
T2 = 46.29C - 5
T2 = 41.29C
Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg
(COP)r = 238/53
(Cop) = 4.490
Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
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The state of plane stress at a point on a body can be depicted by the Mohr's circle below. Point X has coordinates (13,-29) MPa and point Y has coordinates(-18, 29) MPa. Determine the normal and shear stresses associated with a rotation of the stress element θ 25°. Remember that a negative sign indicates a clockwise rotation and a positive sign indicates a counter- clockwise rotation. Note that you can use the Mohr's circle to obtain your answers graphically or you can apply the stress transformation equations.
The state of plane stress at a point on a body can be depicted by the Mohr's circle below. Point X has coordinates (13,-29) MPa and point Y has coordinates(-18, 29) MPa. The normal and sheer stresses are
б\(_{x'}\)= -14.752080900309004 MPa
б\(_{y'}\) =9.752080900309004 MPa
T\(_{x' y'}\)= -30.5145295492538 MPa
What is a Mohr's Circle?
A two-dimensional graph of the transformation law for the Cauchy stress tensor is called Mohr's circle. Calculations in mechanical engineering for the strength of materials, geotechnical engineering for the strength of soils, and structural engineering for the strength of built structures frequently use Mohr's circle.
Additionally, by breaking down stresses into their vertical and horizontal components, it is utilized to calculate stresses in many different planes. In order to discover the principle planes and the principal stresses in a graphical representation, one of the simplest methods is to use Mohr's circle. These are known as principal planes in which principal stresses are calculated.
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Which of these was not part of the OBD II implementation?
OA. Common Codes
OB. Readiness Monitors
OC. Digital Processing
OD. Standard Terminologies
The Digital Processing is not part of the OBD II implementation.
What is an OBD II system?OBD II is known to be a kind of acronym for On-Board Diagnostic II. This is known to be the second generation of on-board self-diagnostic equipment that is needed for light- and medium-duty California vehicles.
The OBD-II is said to be a kind of on-board computer that handles emissions, , speed, etc.
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*Avoid waiting in long drive-thru lines, for example, at fast-food restaurants or banks. Park your car and go in. *When possible, use public transportation, walk, or ride a bike. *Get regular engine tune ups and car maintenance checks. *Join a carpool or vanpool to get to work or school. *Keep tires properly inflated and aligned. Conservation. The choices in the list above help to regulate important biogeochemical cycles as well as conserve important natural resources. Making these good choices impacts several cycles on Earth.
Required:
Which set of answers - biogeochemical cycle; natural resource; consequence - is not affected by the list above?
Answer:
When possible, use public transportation, walk, or ride a bike
Explanation:
Answer:
water; water; Oxygen enters the waterways and causes an imbalance of plant life to animal life.
Explanation:
Climate change isn't just about temperature! The amount of rain and snow (precipitation) in certain regions of the U.S. is also changing. In some areas, the amount of precipitation has decreased. Scientist predict that these dry areas will get even drier in the future.
If the warmer areas on the map also become drier, what will happen to wildfire risk?
Drier conditions will likely result in fewer wildfires
Drier conditions will likely result in more wildfires
No difference
If I had to guess, I'd say the answer is
Drier conditions will likely result in more wildfires
Studies show that warmer and drier areas will double in wildfires by 2050.
Why is a straight-bladed spatula used for mixing impression material on a mixing pad, but not in a rubber bowl?
A straight-bladed spatula is used for mixing impression material on a mixing pad, but not in a rubber bowl because it is iron and constant use may destroy the rubber.
What is the aim of a straight edge spatula?The term Straight edge is known to be a kind of a metal spatula that is known to have a long flat spatula.
It is one that is also known to have a straight edge that is said to be used for leveling or used in working of frosting cakes.
Note that the Strainer - wire mesh helps to move or separates liquids from food.
Hence, A straight-bladed spatula is used for mixing impression material on a mixing pad, but not in a rubber bowl because it is iron and constant use may destroy the rubber.
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Explain the process of energy conversion by describing how energy was converted from the windmill design brief. Discuss the different forms of energy and what technology was used to convert the energy from one form to another.
Answer:
Wind energy is converted to Mechanical energy which is then converted in to electrical energy
Explanation:
In a wind mill the following energy conversions take place
a) Wind energy is converted into Mechanical energy (rotation of rotor blades)
b) Mechanical energy is converted into electrical energy (by using electric motor)
This electrical energy is then used for transmission through electric lines.
The storage tanks are on a platform placed next to the building at the second-floor level. Based on the potential hazards, are there any concerns about the space immediately below the tanks
The should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.
What are potential hazards?Potential hazards refers to the active source for potential damage on a building, structure etc
It is important we know that the storage tanks are placed on a platform next to the building at the second-floor level but nothing beneath the tanks stands.
Hence, there should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.
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Air is compressed from 20 psia and 70°F to 150 psia in a compressor. The compressor is operated such that the air temperature remains constant. Calculate the change in the specific volume of air as it passes through this compressor.
Answer: -8.51 ft^3/lbm
Explanation:
In this question, to find the change in volume, we will use the ideal gas law.
\(\begin{aligned}&n_{1}=1 \text { mole }\\&\mathrm{P}_{1}=20 \mathrm{psia}\\&\mathrm{T}_{1}=70^{\circ} \mathrm{F}\\&T_{1}=(70+460)^{0} \mathrm{R}\\&v_{1}=\frac{\left(0.3704 \frac{psia \cdot_{\text { } ft^{3}}}{l \mathrm{lbm} \cdot R}\right)(70+460)^{0} \mathrm{R}}{20 \mathrm{psi}}\\&v_{1}=9.816 \frac{\mathrm{ft}^{3}}{\mathrm{lbm}}\end{aligned}\)
\(\begin{aligned}&\mathrm{n}_{2}=1 \text { mole } \\&\mathrm{P}_{2}=150 \mathrm{psia} \\&\mathrm{T}_{1}=\mathrm{T}_{2}=70^{0} \mathrm{~F} \\&\mathrm{~T}_{1}=\mathrm{T}_{2}=(70+460)^{0} \mathrm{R} \\&v_{2}=\frac{\left(0.3704 \frac{\text { psia} \cdot \mathrm{ft}^{3}}{\mathrm{lbm} \cdot R}\right)(70+460)^{0} \mathrm{R}}{150 \mathrm{psi}} \\&v_{2}=1.309 \frac{\mathrm{ft}{ }^{3}}{\mathrm{lbm}}\end{aligned}\)
\($$The change in volume is,$$\begin{aligned}&\Delta v=v_{2}-v_{1} \\&\Delta v=1.309-9.816 \\&\Delta v=-8.51 \frac{\mathrm{ft}^{3}}{\mathrm{lbm}}\end{aligned}\text{The negative sign shows that the gas was compressed during this process}\)
A_____AH mean that the energy i____from a reaction taken deleted aborbed poitive negative
The increase in energy from a reaction that was taken, deleted, aborted, positive, or negative is indicated by the change in enthalpy.
The quantitative characteristic that is transferred to a body or to a physical system in physics is energy, which is visible in the performance of labor as well as in the form of heat and light. Energy is a resource that is conserved; it can only be changed from one form to another and cannot be created or destroyed, according to the law of conservation of energy. The unit of measurement for energy in the International System of Units is the joule. Common types of energy include the kinetic energy of an object in motion, the potential energy held by an object, the elastic energy held in a solid object, the chemical energy related to chemical reactions, the radiant energy carried by electromagnetic radiation, and the internal energy held within a thermodynamic system.
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Help please!
Find two careers and explain why you would enjoy being in this career field.
Find two careers and explain why you would NOT enjoy being in this career field.
Note: You should have at least TWO paragraphs
List 5 cutting actions of sawing machines
pls help
Thin metal blades or flexible bands with teeth on one edge, thin grinding wheels, or thin metal disks with teeth on their edges can all be used as sawing machine cutting tools.
What is sawing machine?Sawing machine is defined as a device for cutting forms out of raw material plates or cutting apart bars of material. It is used to sever material, usually wood, but occasionally metal or stone. The material is cut by pressing the toothed edge against it and pushing it swiftly forward, slowly backward, or continually forward.
Rotating blades, reciprocating blades, and circulating blades are the three basic types of power sawing machines.
Thus, thin metal blades or flexible bands with teeth on one edge, thin grinding wheels, or thin metal disks with teeth on their edges can all be used as sawing machine cutting tools.
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If an electric heater has three heating elements connected in parallel, why does each element have its own fusible link and limit switch?
An electric heater with three heating elements connected in parallel has each element's own fusible link and limit switch for the following reasons:
How can we explain this?
1. Safety: Each fusible link serves as a safety device that breaks the electrical circuit for its corresponding element if the current exceeds a specified level. This helps prevent overheating, fire hazards, or damage to the individual elements.
2. Independent operation: Having separate fusible links and limit switches allows each heating element to operate independently. If one element fails or reaches its temperature limit, the other elements can continue to provide heat without being affected.
3. Load balancing: In a parallel connection, the current is divided among the elements. Separate fusible links ensure that each element receives the appropriate amount of current for its intended operation, preventing imbalances that could lead to overheating or reduced performance.
4. Easier troubleshooting: If an issue arises with one of the heating elements, having its own fusible link and limit switch makes it easier to identify and address the problem without affecting the entire system.
In summary, having individual fusible links and limit switches for each heating element in an electric heater connected in parallel ensures safe, independent operation, load balancing, and easier troubleshooting.
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write a java script function that allows the user to enter and convert Kenyan shillings into US dollars when a button is clicked on a web page. rate is 1 $ dollar 115 Ksh
Answer:
Explanation:
Like requested the following function is written in JavaScript and prompts the user for a total amount of Kenyan Currency that needs to be converted. It then places that value in a variable and divides it by 115 Ksh so that it gives us the USD value of that currency. Then that value is returned. The function can be attached to any button but it must be done manually when creating the button's onClick method.
function convertCurrency() {
var KenyanAmount = prompt("Please enter the amount of Kenyan you want to convert.");
var usdValue = "$" + (KenyanAmount / 115);
return usdValue;
}
The program is a sequential program, and does not require loops and conditional statements
The function in JavaScript where comments are used to explain each line is as follows:
//This defines the function
function convertCurrency() {
//This gets input for the amount to convert
var Amount = prompt("Kenyan Shillings: ");
//This converts the Kenyan Shillings to US Dollars
var usdValue = KenyanAmount / 115;
//This returns the converted amount to the main method
return usdValue;
}
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A continuous and aligned fiber-reinforced composite is manufactured using 80 vol% aramid fiber (a kevlar-like compound) embedded nylon 6-6. A part for a high-performance aircraft utilizes this composite. If the part experiences 953 lb-f (pounds force) along the fiber alignment axis, what is the force conveyed by the fibers ?
Answer:
the force conveyed by the fibers is 947.93 lb-f
Explanation:
Given the data in the question;
V_f = 80% = 0.8
V_m = 1 - V_f = 1 - 0.8 = 0.2
Now,
length of fibre L_f = length of Nylon L_n
V_f = A_f × L_f = 0.8
V_m = A_n × L_n = 0.2
so
V_f/V_m = A_f/A_n = 0.8/0.2
A_f/A_n = 4
now, the strains in fibre is equal to strains in nylon
(P/AE)f = (P/AE)n
P_f/A_fE_f = P_n/A_nE_n
P_f = (A_f/A_n)(E_f/E_n)(P_n)
P_f = ( 4 )( 131 / 2.8 )(Pn)
P_f = 187.14Pn
and P_n = Pf / 187.14
Hence
given that P_total = 953 lb-f
P_f + P_n = 953
P_f + ( P_f / 187.14 ) = 953
P_f( 1 + ( 1 / 187.14 ) ) = 953
P_f( 1.00534359 = 953
P_f = 953 / 1.00534359
P_f = 947.93 lb-f
Therefore, the force conveyed by the fibers is 947.93 lb-f
most construction drawings today are hand-drawn by drafters true or false
Answer:
False. Most construction drawings today are created using computer-aided design and drafting (CADD) systems . While manual drafting is still used in some cases, it is becoming increasingly rare. CADD systems offer many advantages over manual drafting , including increased efficiency, accuracy, and the ability to make changes quickly and easily. However, some drafters still use a combination of manual and computer-aided drafting techniques, depending on the nature of the project and their own personal preferences.
Explanation:
_____is a slow wireless technology used to connect devices within a radius of about 30 feet
Answer:
Bluetooth is a slow wireless technology used to connect devices within a radius of about 30 feet. While Bluetooth technology is amazing, there are lots of bugs involved with Bluetooth devices, and there is still lots to be discovered in this area of tech.
Where's an inductor most likely to be found in a power-supply circuit?
Explain the advantages of continuous insulation in envelope assemblies and why it is better to have the continuous insulation on the exterior face of the envelope. Where is inside placement of continuous insulation in the envelope desirable
Answer:
Continuous insulation helps in eliminating the necessity of applying extra materials to achieve moisture barrier demands, reducing labor and material cost.
Continuous insulation helps building last much longer over a period of time,without the need to upgrade and repair.
Inside the placement of continuous insulation in the envelope needed includes the following; the foundation wall or slab insulation, balcony interface, bond joist insulation, insulation against sub floor, on the interior of masonry wall.
Explanation:
Solution:
The analytical path to success contains a well planned and designed building exterior, which avoids the loss of energy, control cost and the maximization of technology advancement in materials.
Property installed continuous insulation on the exterior can also execute as an air barrier. the flashing of wall penetrations can form into a drainage plane. this plane can stop potentially damaging moisture from entering into the wall assembly.
By making use of continuous insulation it helps in removing necessity of applying extra materials to achieve moisture barrier demands, reducing labor and material cost.
Continuous insulation helps building to withstand the test of time without the need to upgrade and repair
Now inside the placement of continuous insulation in the envelope is needed as follows:
Foundation wall or slab insulationInsulation against sub floorBalcony interfacesOn the interior of masonry wallBond joist insulationThe 60∘ strain rosette is attached to point A on the surface of the support. Due to the loading the strain gauges give a reading of εa=300(10−6), ε b = −140(10−6), and ε c = −440(10−6).
Determine the in-plane principal strains.
Determine the orientation of in-plane principal strain.
Determine the maximum in-plane shear strain.
Determine the orientation of maximum in-plane shear strain.
Determine the associated average normal strain
The in-plane principal strains and the orientation of in-plane principal strain is 523.1 × 10⁻⁶.
How to explain the informationFrom the information, the 60∘ strain rosette is attached to point A on the surface of the support. Due to the loading the strain gauges give a reading of εa=300(10⁻⁶), ε b = −140(10⁻⁶), and ε c = −440(10⁻⁶).
Here, want to determine the maximum in-plane shear strain, the orientation of maximum in-plane shear strain, the associated average normal strain and the in-plane principal strain.
The first principal strain is 523.1 × 10⁻⁶.
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charging method .Constant current method
Answer:
There are three common methods of charging a battery; constant voltage, constant current and a combination of constant voltage/constant current with or without a smart charging circuit.
Constant voltage allows the full current of the charger to flow into the battery until the power supply reaches its pre-set voltage. The current will then taper down to a minimum value once that voltage level is reached. The battery can be left connected to the charger until ready for use and will remain at that “float voltage”, trickle charging to compensate for normal battery self-discharge.
Constant current is a simple form of charging batteries, with the current level set at approximately 10% of the maximum battery rating. Charge times are relatively long with the disadvantage that the battery may overheat if it is over-charged, leading to premature battery replacement. This method is suitable for Ni-MH type of batteries. The battery must be disconnected, or a timer function used once charged.
Constant voltage / constant current (CVCC) is a combination of the above two methods. The charger limits the amount of current to a pre-set level until the battery reaches a pre-set voltage level. The current then reduces as the battery becomes fully charged. The lead acid battery uses the constant current constant voltage (CC/CV) charge method. A regulated current raises the terminal voltage until the upper charge voltage limit is reached, at which point the current drops due to saturation.
In a certain company the cost of software depends on the license type which could be Individual or Enterprise. Write a program that reads License Type wanted (just the first character of each type: I, i, E, e). Number of Users to use the software. Type Price/User Minimum number of users Individual 500$ 1 Enterprise 300$ 5 Your program should: Check if the number of users is greater than or equal than Minimum Number of Users allowed Compute the cost: (for example cost = Cost per user x Number of Users)
Solution :
import \($\text{java}.$\)util.*;
public \($class$\) currency{
public static \($\text{void}$\) main(String\($[]$\) args) {
Scanner input \($=$\) new Scanner(System\($\text{.in}$\));
System\($\text{.out.}$\)print("Enter \($\text{number of}$\) quarters:");
int quarters = input.nextInt();
System.out.print("Enter number of dimes:");
int \($\text{dimes =}$\) input.nextInt();
System\($\text{.out.}$\)print("Enter number of nickels:");
int nickels = input.nextInt();
System\($\text{.out.}$\)print("Enter number of pennies:");
int \($\text{pennies = }$\) input.nextInt();
// computing dollors
double dollars = (double) ((quarters*0.25)+(dimes*0.10)+(nickels*0.05)+(pennies*0.01));
System\($\text{.out.}$\)format("You have : $%.2f",dollars);
}
}
Anyone help me please ?
Answer:
I can help but I need to know what it looking for