A mixture of 33. 6 g of Cr(NO3)2 and 60. 5 g of CuSO4 is dissolved in sufficient water to make 98 mL of solution, where the cations react. In the reaction, copper metal is formed and each chromium ion loses one electron. How many electrons are transferred in the balanced net ionic equation with the smallest whole-number coefficients?


1. 5e-


2. 2e-


3. 7e-


4. 4e-


5. 1e-


(Part 2) What is the molar concentration of SO4^2- anions in the solution? Answer in units of M

Answer:

What is all that stuff

Explanation:

Answer:

option d. 56/26 Fe is the correct answer.

Answer:

the substance mixture can be sperate by filtration, distillation, and freezing.

Answer:

A

Explanation:

Saturated means all the carbon atoms has four single bonds around it. These bonds are strong and won't break easily therefore saturated hydrocarbons aren't very reactive

Unsaturated means in one instance the C has a double bond with another carbon. This double bond can be easily broken therefore making unsaturated compounds more reactive than saturated compounds

So saturation deals with the type of bonds the carbon has with other carbon atoms. (The C-C bonds)

Answer:

selenium, fluorine and neon

Explanation:

the less valence electrons an element has, the more reactive.

selenium has 6 valence electrons

fluorine has 7 valence electrons

neon has 8 valence electrons

So, it is ordered from the least number of valence electrons to the most

The claim that vinyl gloves have a higher leak rate than latex gloves is supported by the study at a significance level of 0.005.

To determine if vinyl gloves have a higher leak rate than latex gloves, we can conduct a hypothesis test.

The z-value is calculated as:

z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))

where p₁ and p₂ are the sample proportions, and n₁ and n₂ are the sample sizes.

Certainly! Let's calculate the z-value to determine if vinyl gloves have a higher leak rate than latex gloves.

For vinyl gloves:

Sample size (n₁) = 240

Leaking gloves (x₁) = 0.63 * 240 = 151.2 (approximated to 151)

For latex gloves:

Sample size (n₂) = 240

Leaking gloves (x₂) = 0.07 * 240 = 16.8 (approximated to 17)

We will calculate the z-value using the formula:

z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))

where p₁ and p₂ are the sample proportions.

p₁ = x₁ / n₁ = 151 / 240 ≈ 0.629

p₂ = x₂ / n₂ = 17 / 240 ≈ 0.071

Calculating the z-value:

z = (0.629 - 0.071) / √((0.629 * (1 - 0.629) / 240) + (0.071 * (1 - 0.071) / 240))

z ≈ 13.239

The calculated z-value is approximately 13.239. To determine if the claim is supported, we compare this value to the critical z-value for a one-tailed test at a significance level of 0.005.

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To prepare a fractionating column from a standard distillation column, the correct answer is to pack metal mesh or glass beads into the distillation column.

A fractionating column is used in distillation to separate the components of a mixture based on their boiling points.

It contains a packed section where the vapor can condense and revaporize multiple times before exiting the column. By doing so, components with higher boiling points condense more readily and revaporize less, resulting in a separation of the mixture.

The packing material in the fractionating column provides a larger surface area for condensation and revaporization, which is essential to achieve effective separation. Therefore, packing metal mesh or glass beads into a standard distillation column can effectively convert it into a fractionating column.

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Answer:

B)

Explanation:

it has 5

a. Example of physical change: Melting of ice

Example of chemical change: Burning of paper

b. Example of physical property: Density of a substance

Example of chemical property: Reactivity of a substance

a. A known example of a physical change is the change of state of water. When water is heated, it undergoes a physical change from a solid state (ice) to a liquid state (water) and further to a gaseous state (water vapor). The chemical composition of water remains the same throughout these changes, and only the arrangement and energy of the water molecules change.

On the other hand, a known example of a chemical change is the combustion of wood. When wood is burned, it undergoes a chemical change where the molecules of wood react with oxygen from the air to produce carbon dioxide, water vapor, and other combustion products. The chemical composition of wood is altered during this process, and new substances are formed.

b. Physical properties are characteristics of a substance that can be observed or measured without changing its chemical composition. For example, the physical properties of water include its boiling point, melting point, density, color, and transparency. These properties describe how water behaves and reacts under different conditions, but they do not involve any changes in its chemical identity.

Chemical properties, on the other hand, describe the ability of a substance to undergo chemical changes and react with other substances. For example, the ability of iron to rust when exposed to oxygen and moisture is a chemical property. It involves a chemical reaction where iron reacts with oxygen to form iron oxide.

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Answer:

the water would most likely become more acidic.

Explanation:

this is due to carbon dioxide being slightly acidic, it dissolves into the water inturn decreasing the pH.


i also posted this on your question a minute ago before you posted it in the right catagory.

Answer:

A- SImilar to both copper and oxygen

Explanation:

If copper and oxygen react to form copper oxide, a compound of both Copper and Oxygen, they most likely have traits from both elements, therefore its A

In a chromatography experiment, the rf value is calculated by dividing the distance traveled by the compound by the distance traveled by the solvent front. The rf value indicates the relative affinity of the compound for the stationary phase (chromatography paper) compared to the mobile phase (solvent).

In this case, the student calculated an rf value of 0.70 for alanine and 0.91 for leucine. The higher the rf value, the farther the compound travels on the chromatography paper. Therefore, leucine traveled higher on the chromatography paper compared to alanine.

Since the rf value is calculated by dividing the distance traveled by the compound by the distance traveled by the solvent front, a higher rf value indicates that the compound has a greater affinity for the mobile phase (solvent) and thus travels a greater distance on the chromatography paper. Conversely, a lower rf value indicates that the compound has a greater affinity for the stationary phase (chromatography paper) and thus travels a shorter distance.

Therefore, based on the given rf values, leucine traveled higher on the chromatography paper compared to alanine.

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Answer:

812.3 kilogram/cubic meter

Explanation:

I used an online calculator.

Hope I helped!

To determine which pairs of solvents would make good extraction systems, several factors need to be considered, such as solubility, selectivity, and safety.

One example of a good extraction system is using a polar solvent, such as water or ethanol, with a non-polar solvent, such as hexane or diethyl ether. This type of system is ideal for extracting compounds with different polarities, as the polar solvent will dissolve polar compounds, while the non-polar solvent will dissolve non-polar compounds.

Another example is using two immiscible solvents, such as chloroform and methanol, which can be used for the extraction of lipids or other compounds from biological samples. The immiscible solvents can be separated easily after extraction, which makes it a convenient extraction system.

In summary, the choice of solvents for an extraction system depends on the specific application and the properties of the target compounds. It is important to consider the solubility, selectivity, and safety of the solvents to achieve the best results.

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The clay should be fired at a speed of 1.79 m/s (to two significant figures) in order to stop the car.

To solve this problem, we can use the conservation of momentum principle, which states that the total momentum of an isolated system remains constant. In this case, the initial momentum of the car and the final momentum of the car plus the clay must be equal in magnitude and opposite in direction.

Mass of the car (m1) = 1200 kg

Initial velocity of the car (v1) = 1.8 m/s

Mass of the clay (m2) = 10 kg

Final velocity of the car plus the clay (v2) = 0 m/s (since we want to stop the car)

Using the conservation of momentum principle, we can write:

m1v1 = (m1 + m2)v2

Solving for v2, we get:

v2 = (m1v1) / (m1 + m2)

Substituting the given values, we get:

v2 = (1200 kg x 1.8 m/s) / (1200 kg + 10 kg)

v2 = 1.79 m/s

Therefore, the clay should be fired at a speed of 1.79 m/s (to two significant figures) in order to stop the car.

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(complete question)

a 1200 kg car is rolling at 1.8 m/s. you would like to stop the car by firing a 10 kg blob of sticky clay at it. how fast should you fire the clay? express your answer to two significant figures and include the appropriate units.

We can see here that the both measurements are accurate. This is the true because the both values are in the correct number of significant figures.

The term density has to do with the ratio of the mass to the density of the object. We know that the accuracy of a measurement has a lot to do with the number of significant figures in the measurement. In this case, we are told that two students in a lab are asked to calculate the density of a block with a mass of 31.0 g; they are not told how many digits to round their measurements. Student A finds length to be 2 cm width to be 4 cm and height 8 cm. Student B finds the length to be 2.65 cm, width to be 4.20 cm, and height to be 8.35 cm.

For the first student, the density is obtained as;

Density = mass/ volume

= 31.0 g/ 2 cm * 4 cm *  8 cm

= 0.5 g/cm^3

For the second student;

Density = mass/ volume

= 31.0 g/2.65 cm * 4.20 cm * 8.35 cm

= 0.33 g/cm^3

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If a catalyst is added to a system at equilibrium and the temperature and pressure remain constant, there will be no effect on the position of equilibrium or the value of the equilibrium constant.

The role of a catalyst is to speed up the rate of the forward and reverse reactions by providing an alternative pathway with a lower activation energy. This means that both the forward and reverse reactions will occur at a faster rate, but the ratio of products to reactants at equilibrium remains the same. As a result, the concentrations of reactants and products at equilibrium will remain unchanged, and the value of the equilibrium constant will not be affected. However, the time taken to reach equilibrium will be reduced due to the increased reaction rate.

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Answer:

ok you got it you just need to add.

Explanation:

add 5 times and she what you get.

Under identical conditions, it would take the same amount of gaseous I2 to effuse from the same container as it did for N2O, but it would take longer.

This is because I2 is a larger molecule than N2O, so it has greater difficulty passing through the small spaces in the container. The larger the molecule, the slower the effusion rate.

In general, effusion rates are inversely proportional to the square root of the molecular weight of a gas. This means that the molecular weight of I2 is four times larger than that of N2O, so it would take approximately twice as long for I2 to effuse from the container. In this case, it would take approximately 98 seconds for the same amount of gaseous I2 to effuse from the container under identical conditions.

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Answer:

Explanation:

(i) Which one of these structures A to E represents a noble gas?

Noble gases have completely filled outer most orbital. It means they have 8 valence electrons. Picture D have 8 valence electrons thus it represent noble gas.

(ii) Which two of these structures represent atoms from the same group of the periodic table?

Atoms present in same group having same number of valence electrons.

Picture A and C both have one valence electron thus both are present in same group.

(iii) Which one of these structures represents an atom with an atomic number of 8?

Picture B have total 8 number of electrons it means this atom have atomic number 8. So answer is picture B.

(iv) Which one of these structures forms a stable ion by gaining one electron?

Ions are formed by gaining or losing the electrons. When an atom gain electron anion is formed. There are 7 electron in outer orbital of picture E when it gain one electron outer orbital become completely filled thus form stable ion.

(v) Which one of these structures is in period 3 of the periodic table?

Picture C have 11 electron it means this atom have atomic number 11 which represent sodium. Sodium is present in period 3. Thus answer is picture C.

Explanation:

you need to review these formulas

Answer:

the wave model of light is useful for explaining brightness, color, and the frequency-dependent bending of light at a surface between media. For example, students could observe some of the wave behaviors or light by observing that when light passes through a small opening the waves spread out. They could observe that if the wavelength is short, the waves spread out very little, whereas longer wavelengths spread out more

Explanation:

Answer:

Neutral subatomic particle that is a constituent of every atomic nucleus except ordinary hydrogen.

Explanation:

At STP (Standard Temperature and Pressure), iodine is present in a crystalline form, whereas fluorine is in a gaseous form. Iodine is also soluble in ethanol and produces a tincture of iodine. Typically, a 2% iodine mass is present in a tincture of iodine.

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At STP, iodine (I2) is a solid crystal and fluorine (F2) is a gas. A sample of I2 at STP is held together by van der Waals forces, which are weaker intermolecular forces. On the other hand, a sample of F2 at STP is held together by much stronger intermolecular forces than I2 due to its smaller size.

Therefore, F2 has stronger intermolecular forces than I2. It can be explained in a long answer as follows:At standard temperature and pressure, iodine (I2) is a solid crystalline substance. Its physical state is a solid because the intermolecular forces that bind the iodine molecules together are weak van der Waals forces. These forces are much weaker than chemical bonds, and they hold molecules in a condensed phase like a liquid or a solid. The forces of attraction between the iodine atoms in I2 are much weaker than the forces of attraction between the fluorine atoms in F2.

As a result, the boiling point of I2 is much lower than the boiling point of F2. F2 is a gas at STP since it is held together by much stronger intermolecular forces than I2 due to its smaller size. Fluorine has an electron density that is spread out over a larger area than iodine, making it more polarizable. The larger polarizability leads to stronger instantaneous dipoles and, as a result, stronger London dispersion forces. Since intermolecular forces are responsible for determining the physical state of a substance, F2 is a gas, whereas I2 is a solid. As a result, F2 has stronger intermolecular forces than I2.

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The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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Answer:

The insect exerts no force on the windshield, and the windshield strikes the insect with a large force.

Explanation:

:#D

1.) H2SO4 is the limiting reagent ; 2.) Excess H2SO4 = 41.66 g ; 3.) Theoretical yield of CaSO4 is 73.40 g. ;  4.) Percent yield of HF is 74.4%.

Reactant that is totally consumed when chemical reaction is completed is called limiting reagent.

1.) Moles of CaF2 = 42.0 g / 78.07 g/mol = 0.5386 mol

Moles of H2SO4 = 94.5 g / 98.08 g/mol = 0.9637 mol

Using the stoichiometric ratios, 0.5386 moles of CaF2 would produce 2 x 0.5386 = 1.0772 moles of HF, while 0.9637 moles of H2SO4 would produce only 0.9637 moles of HF. Therefore, H2SO4 is the limiting reagent.

2.) 0.9637 moles H2SO4 x (1 mole CaF2 / 1 mole H2SO4) = 0.9637 moles CaF2

This means that only 0.5386 moles of CaF2 was actually consumed in the reaction. Therefore, 0.9637 - 0.5386 = 0.4251 moles of H2SO4 was left over.

Excess H2SO4 = 0.4251 mol x 98.08 g/mol = 41.66 g

3.) Moles of CaSO4 produced = Moles of CaF2 consumed = 0.5386 mol

Mass of CaSO4 produced = 0.5386 mol x 136.14 g/mol = 73.40 g

Therefore, the theoretical yield of CaSO4 is 73.40 g.

4.) As percent yield = (Actual yield /Theoretical yield) x100

Percent yield = (14.2 g / (0.9637 mol x 20.01 g/mol)) x 100 = 74.4%

Therefore, the percent yield of HF is 74.4%.

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Answer:

Explanation:

1 )

amount of heat required = mass x specific heat x rise in temperature

= 25 x 4.2 x 20 = 2100 J .

2 )

Amount of heat required

= mass x latent heat of vaporisation

= 50 x 2260 = 113000 J  .

3 )

Amount of heat required in melting the ice

= mass x latent heat of fusion

= 15 x 336 = 5040 J

4)

heat released in cooling water

= mass x specific heat x fall in temperature

= 5 x 4.2 x 10

= 210 J

5 )

amount of heat required = mass x specific heat x rise in temperature

84 = mass x 4.2 x 10

mass = 2 grams .