A molecule is

A a group of atoms bonded by ionic bonds.
B a group of atoms bonded by covalent bonds.
C a group of ions bonded by covalent bonds.
D a group of atoms bonded by metallic bonds.

Answer:

true

Explanation:

The work done by the system is -11.82 L atm and the change in internal energy of water during vaporization is 161.36 kJ.

The problem describes the endothermic vaporization of 1 mole of liquid water at 100.9°C and 1.00 atm. We are given the volume occupied by 1.00 mole of liquid and vapor water at 100.0°C and 1.00 atm. Using this information, we can calculate the change in volume when 1 mole of liquid water vaporizes.
The work done by the system is equal to -PΔV, where P is the constant pressure of 1.00 atm and ΔV is the change in volume. Substituting the values, we get work done = -1.00 atm x [(30.62 L) - (18.80 mL/1000)] = -11.82 L atm.
The change in internal energy can be calculated using the first law of thermodynamics, ΔE = q + w. Since the process is endothermic, q is positive and equal to the heat absorbed during vaporization. Using the given enthalpy change and moles of water vaporized, we get q = (4.25 mol) x (40.7 kJ/mol) = 173.18 kJ.

Therefore, ΔE = 173.18 kJ - 11.82 L atm = 161.36 kJ.
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Answer:

Global wind

Explanation:

The jet streams go around the whole earth from west to east

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Answer:

19.5%

Explanation:

the air required for human breathing is 19.5 percent.

Acetic acid (pKa = 4.73) and sodium acetate might be used to create a pH 5.0 buffer solution (the conjugate base of acetic acid). The acid's ideal concentration ratio.

Acetic acid (pKa = 4.73) and sodium acetate might be used to create a buffer solution with a pH of 5.0. A reasonable place to start would be the ideal concentration ratio of the acid and its conjugate base, which is around 1:1.

Using sodium acetate and hydrochloric acid, create a pH 5.0 buffer Acetic acid's pKa is 4.73, therefore a buffer's ideal pH would be close to that value. One would need to modify the concentrations of the acid and its conjugate base in order to get a pH of 5.0. To produce a pH 5.0 buffer, one would need to add around 2.7 mL of 1.0 M HCl to 5.0 g of sodium acetate, assuming a final volume of 100 mL.

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Answer:

Answers Anonymous answered Sulfur has 6 valence electrons so it needs 2 more for an octet and it will then have a charge of negative 2

Explanation:

From the calculation, the age of the sample of carbon - 14 is 9156 years.

The term radioactivity refers to the fact that a substance could disintegrate spontaneously when left alone.

Now, given that;

0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life

t = age of the sample

No = amount of sample originally present

N = amount of sample present at time t

Hence;

0.693/5730 =  2.303/t  log (9216/3072)

1.2 * 10^-4 =  2.303/t * 0.4771

1.2 * 10^-4 = 1.09876/t

t =  1.09876/1.2 * 10^-4

t = 9156 years

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To determine if MgCO3 will precipitate from the solution, we need to compare the ion product (Q) with the solubility product (Ksp) of MgCO3. The ion product (Q) is calculated by multiplying the concentrations of the ions involved in the dissociation of MgCO3.

The balanced equation for the dissociation of MgCO3 is:

MgCO3(s) ⇌ Mg2+(aq) + CO32-(aq) Given that the concentration of Mg2+ is 1.5×10^−3 M, we can calculate the concentration of CO32- using stoichiometry. Since 1 mole of MgCO3 dissociates to give 1 mole of Mg2+ and 1 mole of CO32-, the concentration of CO32- is also 1.5×10^−3 M.

The ion product (Q) is then calculated as:

Q = [Mg2+][CO32-] = (1.5×10^−3 M)(1.5×10^−3 M) = 2.25×10^−6

Comparing Q with the solubility product (Ksp) of MgCO3 (6.82×10^−6), we find that Q < Ksp. This means that the ion product is smaller than the solubility product, indicating that no MgCO3 will precipitate from the solution. Therefore, based on the given concentrations and the solubility product of MgCO3, no MgCO3 will precipitate from the solution when 50.0 mg of Na2CO3 is added to 150.0 ml of the solution.

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Answer:

True

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Explanation:

Answer:

True

Explanation:

A study of the spectrum of the sun led to the discovery of helium.

The dot structure of the compound that is referred to here is shown in  the image attached.

A dot structure, often called a Lewis structure or an electron dot structure, depicts how atoms and valence electrons are arranged in a molecule or ion. Around the atomic symbols, valence electrons are represented by dots.

Each atom's symbol in a dot structure is surrounded by dots that stand in for the atom's valence electrons. The electrons in an atom's outermost shell known as valence electrons participate in chemical bonding.

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Answer:What is used up in and stops a chemical reaction? (a) percent yield (b) limiting reactant (c) theoretical yield (d) excess reactant

The correct option is (b)

Explanation:

A chemical reaction is a chemical combination,rearrangement or disintegration of chemical substance(s) (called reactants) to form new chemical substance(s) (called products).

A limiting reactant is the reactant that is totally used up during the course of a reaction. When this reactant is used up, it limits the amount of products formed and eventually stops the chemical reaction.

Explanation:

The limiting reagent is the reactant that is used up completely. This stops the reaction and no further products are made. ... This method is most useful when there are only two reactants. The limiting reagent can also be derived by comparing the amount of products that can be formed from each reactant.

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(b)

only CaCO3

Explanation:

Given:

Alkaline solution= 2 x 10^-4 M in CO32-Pool water was originally 4 x 10^-3 M in Mg2+, 6 x 10^-4 M in Ca2+ and 8 x 10^-7 M in Fe2+

Precipitate should be of:

MgCO3, CaCO3 and FeCO3

We know that:

Mg2+ + CO32- → MgCO3Ca2+ + CO32- → CaCO3Fe2+ + CO32- → FeCO3Thus, for MgCO3 to form, [CO32-] should be 4 x 10^-3 M which is not possible in the given question.

For CaCO3 to form,[CO32-] should be 6 x 10^-4 M which is possible.

So, precipitate should be only CaCO3.

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A redox reaction involves oxidation one species and reduction of other species. Oxidation is the process of the lose of electron and it occurs at anode and reduction is the gain of electrons. Thus option d is false.

A redox reaction is a type of reaction in which both oxidation and reduction occurs each for different species. One reactant species oxidizes by losing electron into the other species and the species which gained the electron is reduced.

Oxidation is the process by which an element or group forms its higher oxidation state by losing electron. Reduction is the process by which an element forms its lower oxidation state through gaining electron.

In an electrolysis two electrodes undergo redox reaction where the electrode at which oxidation occurs is called anode and the electrode where reduction takes place is called cathode. Thus option c is incorrect.

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The precipitation in the northeastern United States is approximately 12.6 to 25.2 times more acidic (in terms of hydrogen ion concentration) than precipitation in the South Pacific.

Precipitation in the northeastern United States is significantly more acidic than precipitation in the South Pacific. On average, the pH of precipitation in the northeastern United States is around 4.2 to 4.4, while the pH of precipitation in the South Pacific is around 5.6 to 5.8.

To calculate the difference in hydrogen ion concentration ([H+]) between these two pH values, we can use the equation:

pH = -log[H+]

Rearranging the equation gives:

[H+] = 10^(-pH)

Therefore, the [H+] in precipitation in the northeastern United States can be calculated as:

[H+] = 10^(-4.2) to 10^(-4.4)

And the [H+] in precipitation in the South Pacific can be calculated as:

[H+] = 10^(-5.6) to 10^(-5.8)

Taking the average of the range of [H+] values for each region, we get:

[H+] in northeastern US precipitation = 6.31 x 10^(-5) to 3.98 x 10^(-5) mol/L

[H+] in South Pacific precipitation = 2.51 x 10^(-6) to 1.58 x 10^(-6) mol/L

The ratio of the [H+] in northeastern US precipitation to that in South Pacific precipitation can be calculated by dividing the former by the latter:

[H+] ratio = ([H+] in northeastern US precipitation) / ([H+] in South Pacific precipitation)

Taking the average of the [H+] ratios for the two pH ranges, we get:

[H+] ratio = 12.59 to 25.18

Therefore, precipitation in the northeastern United States is approximately 12.6 to 25.2 times more acidic (in terms of hydrogen ion concentration) than precipitation in the South Pacific.

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Answer:

it could harbor dangerous chemicals that damage the car if released

it could be holding parts together

it could have something dangerous inside

Answer:

Explanation:

Heat energy always moves from hot to cold. The sunlight doesn't reach certain parts of the ocean due to it being so deep. The water above it absorbs it. So because this top water absorbs all the heat/energy, it is a lot warmer and is constantly transferring heat to the colder parts through kinetic energy. The warmer water has particles that have way more kinetic energy than the cold particles below it. And more kinetic energy means more movement, so that's why they transfer their heat to the colder particles.

I dont actually know if Im correct or not. Im just guessing based on what I know about physics.

The volume in cm³ of oxygen evolved at STP is 0.056 dm³ and the correct option is option A.

STP stands for standard temperature and pressure. STP refers to a specific pressure and temperature used to report on the properties of matter.

According to IUPAC( International Union of Pure and Applied Chemistry), it is defined as -

It is generally needed to test and compare physical and chemical processes where temperature and pressure plays an important role as they keep on varying from one place to another.

Given,

Current = 5A

time = 193s

Q = current × time

= 193 × 5

= 965 C

4 × 96500 = 22.4

965 = x

x = ( 22.4 × 965) ÷ ( 4 × 96500)

x = 0.056 dm³

Thus, the ideal selection is option A.

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The initial rate is determined through multiplication of initial concentration of a thiosulfate ion by half in a Kinetics of the Iodine Clock Reaction procedure. Hence correct choice is thiosulfate ion.

A popular demonstrative reaction in chemistry courses that typically calls for toxic or dangerous substances is the iodine clock reaction. 2 clear liquids are combined in the process to produce a third clear liquid. After a while, the solution abruptly changes to a dark blue color.

The starch & the iodine do exchange some electrical charges. The distances between energy levels are altered as a result, changing the electron configurations. The complex gets its vivid blue color from the additional spacings, which preferentially absorb visible light.

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The complete question is -

In the Kinetics of an Iodine Clock Reaction procedure, the initial rate is calculated by multiplying the initial concentration of ______________ by half, and dividing by the elapsed time as measured with ___________.

Answer-

thiosulfate ion and stop watch are filled in blank area.

A triple bond may consist of one sigma bond and two pi bonds.

Sigma bonds are the most powerful kind of covalent chemical bond. they're fashioned by way of head-on overlapping among atomic orbitals. Sigma bonding is most surely described for diatomic molecules the usage of the language and equipment of symmetry businesses

Sigma bond is a covalent bond formed by overlap of atomic orbitals and hybrid orbitals along the bond axis. The sigma bond in the a hydrogen molecule is formed by overlap of a pair of 1s orbitals, one from each hydrogen atom.

The pi bond is the same as that of the p orbital when seen down the bond axis.

A pi bond is a weaker chemical covalent bond than a sigma bond.

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Soda water, wood, air, soil, vinegar, filtered tea.

Answer:

Homogeneous mixtures : Soda water, vinegar and filtered tea. Heterogeneous mixtures : Wood and soil.

As per the given reaction one mole of magnesium hydroxide reacts with 2 moles of potassium metal to give one mole of Mg. Therefore, 12 moles of potassium reacts to give 6 moles of Mg metal.

In a displacement reaction, one element or group is displaced from the reactant by the other reactant. The given reaction is an example of single displacement reaction.

As per the balanced chemical equation of the reaction, 1 mole of magnesium hydroxide reacts with 2 moles potassium metal to form one mole of Mg metal and 2 moles of potassium hydroxide.

Here, 12 moles of potassium is taken. Then, the number of moles of Mg metal formed is just half the number of moles of K. That is 6 moles of magnesium metal.

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The reaction related to your question is given below:

Mg(OH)₂ + 2K ⇒2KOH + Mg

The given question is 98, 99, 100 , 90, 98 , 100

Mean= \(\frac{Sum of observations}{Number of observations}\)

In mathematics and statistics, the average is the average of a set of values. The mean can be calculated in a number of ways, including the simple arithmetic mean (adding the numbers and dividing the sum by the number of observations), the geometric mean, or the harmonic mean.

Sum of observations is 98+99+100+90+98+100

The summation is 585

The number of observations is 6.

= \(\frac{98+99+100+90+98+100}{6}\)

= 97.5

So, the answer is 97.5

find the answer in the attached image. please mark as brainliest if it is helpful.

Answer:

N2O is an empirical formula

Explanation:

A.) P4O10   NO:  Can be reduced to P2O5

B.) C2H4    NO:  Can be reduced to CH2

C.) H2O2     NO:  Can be reduced to H O

D.) N2O     YES, the formula cannot be reduced any further.

Answer:

energy

that seems like the most relevant answer

Answer:

Molecular mass of NH3 = ( 14 + 3 ) = 17 g

\(PV = \frac{m}{m _{r}} RT \\ P \times 50.0 \times {10}^{ - 6} = \frac{68.0}{17} \times 8.314 \times (30.0 + 273) \\ P = \frac{68.0 \times 8.314 \times 303}{17 \times 50.0 \times {10}^{ - 6} } \\ P = 2.02 \times {10}^{8} \: Pascals\)

Answer and Explanation: Many nuclei are radioactive, which means they emit particles to become stable. In the process, they also become a different element. There are 3 types of decay:

Problem #1:

1.) Astatine: Z = 85 and  A = 211

Alpha decay: \({{A=211} \atop {Z=85}} \right. At\) ⇒ \({{207} \atop {83}} \right. Bi + {{4} \atop {2}} \right. \alpha\)

The isotope created is Bismuth

Characteristics: Z = 83; e⁻ = 83; n = A - Z = 207 - 83 = 124

The isotope is Bismuth with 83 protons, 83 electrons and 124 neutrons.

Problem #2

1.) Lead: Z = 82 and A = 82

Beta decay: \({{209} \atop {82}} \right. Pb\) ⇒ \({{209} \atop {81}} \right. Tl+{{0} \atop {-1}} \right. \beta\)

The isotope created is talium.

2.) \({{209} \atop {82}} \right. Pb\) ⇒ \({{209} \atop {81}} \right. Tl+{{0} \atop {-1}} \right. \beta\)

\({{209} \atop {81}} \right. Tl\) ⇒ \({{205} \atop {79}} \right. Au+{{4} \atop {2}} \right. \alpha\)

\({{205} \atop {79}} \right. Au\) ⇒ \({{205} \atop {78}} \right. Pt+{{0} \atop {-1}} \right. \beta\)

3.) The isotope created is \({{205} \atop {78}} \right. Pt\).

p⁺ = 78; e⁻ = 78; n = 127

The isotope created ahs 78 protons, 78 electrons and 127 neutrons.