A motorcycle has a mass of 250 kg. it goes around a 13.7 m radius turn at 96.5 km/h. 9720 N is the centripetal force on the motorcycle.
To find the centripetal force on the motorcycle, we can use the formula for centripetal force:
F = m * a
where F is the centripetal force, m is the mass of the object, and a is the centripetal acceleration. To find the centripetal acceleration, we can use the formula for centripetal acceleration:
a = v^2 / r
where a is the centripetal acceleration, v is the velocity, and r is the radius of the curve. In this case, we know that the mass of the motorcycle is 250 kg, the velocity is 96.5 km/h, and the radius of the curve is 13.7 m. To find the centripetal acceleration, we need to convert the velocity from km/h to m/s. Since 1 km/h is equal to 1000 m/3600 s = 0.2778 m/s, the velocity in m/s is 96.5 km/h * 0.2778 m/s/km/h = 26.7 m/s.
For centripetal force and centripetal acceleration, we get:
F = m * a
= 250 kg * (v^2 / r)
= 250 kg * (26.7 m/s)^2 / 13.7 m
= 9720 N
Therefore, the centripetal force on the motorcycle is 9720 N.
Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics. The tension of the rope provides the centripetal force on an object that is swinging around on the end of a rope in a horizontal plane. The rope illustration is a pull-related example. In some situations, such as when a wall's natural reaction serves as the centripetal force for a wall of death or a Rotor rider, the centripetal force can also be provided as a "push" force.
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A train is moving parallel and adjacent to a highway with a constant speed of 28 m/s. a car is traveling in the same direction as the train at 53 m/s. the car‚äôs horn sounds at 580 hz and the train‚äôs whistle sounds at 340 hz. when the car is behind the train what fre quency does an occupant of the car observe for the train whistle? the speed of sound is 343 m/s. answer in units of hz
The frequency is 983.56Hz, will be heard by the occupants of the car moving at the given speed.
What is Frequency?
It is the number of cycles or vibrations a body in periodic motion experiences during one unit of time, as well as the number of waves that pass, a fixed point in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration.
What are the calculations?
Given,
Speed of train = 28 m/s
Speed of car = 53 m/s
Frequency of car's horn = 580 Hz
Frequency of train's whistle = 340 Hz
When the car is behind the train, the frequency of the car is:
By using formula of frequency = \(f_{c} = f_{t ( 1 + \frac{V_{c} }{V_{t} } )\)
Put the value into the formula = \(fc = 340 * (1 + \frac{53}{28} )\)
\(fc =\) 983.56Hz
Hence, frequency is 983Hz, will be heard by the occupants of the car.
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An atom of the isotope 137Ba consists of how many protons (p), neutrons (n), andelectrons (e)?A) 56 p, 137 n, 56 e D) 56 p, 56 n, 56 eB) 56 p, 81 n, 56 e E) 81 p, 56 n, 81 eC) 137 p, 81 n, 56 e
The answer is B) 56 p, 81 n, 56 e. This is because the isotope 137Ba has a mass number of 137, which is the sum of its protons and neutrons.
Since the atomic number of barium (Ba) is 56, this means that there are 56 protons in the nucleus of this isotope.
To find the number of neutrons, we can subtract the number of protons from the mass number:
137 - 56 = 81
Therefore, there are 81 neutrons in the nucleus of this isotope.
Isotopes are atoms of an element with varying atomic masses but the same atomic number, meaning they have different numbers of neutrons but the same number of protons and, consequently, the same chemical characteristics.
Radioisotopes, as well as stable and unstable isotopes, can exist.
Therefore, a radioisotope is a chemical element with an unstable nucleus, or one with an unbalanced ratio of protons to neutrons. As a result, until this element reaches stability, it emits ionising radiation as a way of dissipating its surplus energy.
The unstable form of an element that releases radiation to change into a more stable form is known as a radioisotope, to put it simply.
Finally, because the atom is neutral (meaning it has no overall charge), it must also have 56 electrons, since the number of electrons in an atom is equal to the number of protons in the nucleus.
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Force = 700 N , Pressure = 10 Pascal
Area = ?
Answer :-
Force is 70 meter² .Explanation :-
As per the provided information in the given question, Force is given as 700 Newton. Pressure is given as 10 Pascal. And, we have been asked to calculate the Area.
For calculating the Area , we will use the Formula :-
\( \bigstar \: \: \: \boxed {\sf { \: Area \: = \: \dfrac {Force}{Pressure \: } }} \)
Therefore , by Substituting the given values in the above Formula :-
\( \Longrightarrow \: \: \: \sf {Area \: = \: \dfrac {Force}{Pressure}} \)
\( \Longrightarrow \: \: \: \sf {Area \: = \: \dfrac {700}{10}} \)
\( \Longrightarrow \: \: \: \bf {Area \: = \: 70} \)
Hence :-
Area = 70 meter² .\( \underline {\rule {180pt}{4pt}} \)
Will give correct answer brainliest
Answer:
1 Answer 200.
2 Answer. 250
An electric field E points toward you, and its magnitude is increasing. Will the induced magnetic field be clockwise or counterclockwise? What if E points away from you and is decreasing?
When the electric field is pointing towards you and its magnitude is increasing the induced magnetic field will be clockwise and when the electric field is pointing away from you and its magnitude is decreasing the induced magnetic field will be clockwise.
According to Faraday's law of electromagnetic induction, a changing electric field induces a magnetic field. The direction of the induced magnetic field can be determined using Lenz's law, which states that the direction of the induced magnetic field is such that it opposes the change that produced it.
In the first scenario, the electric field E points toward you, and its magnitude is increasing. This means that the flux through a hypothetical loop perpendicular to the electric field and with an area vector pointing in the direction of the electric field is increasing. According to Lenz's law, the induced magnetic field will be in a direction such that it opposes the increase in the flux. Therefore, the induced magnetic field will be clockwise.In the second scenario, the electric field E points away from you and its magnitude is decreasing. This means that the flux through a hypothetical loop perpendicular to the electric field and with an area vector pointing in the direction opposite to the electric field is decreasing. According to Lenz's law, the induced magnetic field will be in a direction such that it opposes the decrease in the flux. Therefore, the induced magnetic field will be clockwise.In summary, when an electric field is changing, the direction of the induced magnetic field is such that it opposes the change that produced it, regardless of the direction of the electric field.
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The colorado river still has water after it leaves the desert southwest region and enters the gulf of california because ________.
The Colorado river began somewhere than in the desert, which is often the only way streams leaving the desert have water, therefore the river still has water after leaving the arid southwest region and entering the gulf of California.
The Colorado River and its tributaries travel through seven different states in the United States as well as Mexico on their way from their source in Colorado and Wyoming to where they flow into the Gulf of California. However, there were drawbacks; over a number of decades, river flows fell. Between 1960 and 1980, as Lake Powell developed behind Glen Canyon Dam, the Colorado River gradually ceased to flow steadily in the direction of the ocean.
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A complete electric circuit includes a voltage source, current, wires, and something to _________ the flow of current.
Answer:
If you ground the flow of current like the last part of your question states you will not have a complete circuit as the circuit will open on a short circuit. To make a complete circuit operate you need a power source, an overload device to protect the conductors of the circuit, conductors to carry the current and a load across the power source which causes the current to flow in the circuit.
Explanation:
Leave any one of these things out and you will not have a complete circuit.
A complete electric circuit includes a voltage source, current, wires, and load to flow the current.
What is load in an electric circuit?An electrical load can be described as an electrical component of a circuit that consumes electrical power such as electrical appliances, bulbs, and lights. The electrical load may also refer to the power consumed by a circuit. An electrical load is opposed to a power source, such as a battery, which produces power.
If an electric circuit contains an output port, a pair of terminals that generates an electrical signal, the circuit connected to this terminal is the load. Load influences the performance of circuits according to the output voltages or currents, such as voltage sources, and amplifiers.
Mains power outlets supply power at constant voltage, with electrical appliances connected to the power circuit making up the load. When a high-power device switches on, it drastically reduces the load impedance.
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determine the maximum intensity w of the uniform distributed load that can be applied to the beam without risk of causing the strut to buckle. take f.s.
The maximum intensity "w" of the uniform distributed load that can be applied to the beam without risking strut buckle depends on the factor of safety (f.s.) used.
Determining the maximum intensity of the load that a beam can withstand without causing strut buckling requires considering the factor of safety. The factor of safety is a design parameter used to ensure that a structure can handle loads safely without failure.
To calculate the maximum intensity "w," we need to determine the critical load that causes buckling and then divide it by the factor of safety. Buckling occurs when a slender strut subjected to compressive forces becomes unstable and fails under the applied load.
The specific calculation to determine the maximum load will depend on the beam's geometry, material properties, and the boundary conditions. It involves analyzing the Euler buckling equation, which relates the critical buckling load to the beam's length, area moment of inertia, and material properties.
By dividing the critical load by the factor of safety, we ensure that the load applied to the beam remains within a safe range, reducing the risk of buckling or structural failure.
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Where is the potential energy highest on a marble roller coaster?
The potential energy is highest on a marble roller coaster at the highest point of the track.
The potential energy of an object is directly related to its height and its position relative to the reference point. In the case of a marble roller coaster, as the marble climbs up the track, it gains potential energy due to its increased height.
At the highest point of the roller coaster track, the marble reaches its maximum elevation, and thus, its potential energy is at its highest point.
As the marble moves downhill from the highest point, its potential energy decreases and is converted into kinetic energy, which is the energy of motion.
At the bottom of the track, where the marble reaches its lowest point, the potential energy is at its minimum because the height is at its lowest and the marble has converted most of its potential energy into kinetic energy.
The potential energy is highest on a marble roller coaster at the highest point of the track. This is where the marble reaches its maximum elevation and has the greatest amount of potential energy due to its height. As the marble moves downhill, its potential energy decreases and is converted into kinetic energy.
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Consider the vector field F(x, y) = (-2xy, x² ) and the region R bounded by y = 0 and y = x(2-x) (a) Compute the two-dimensional curl of the field. (b) Sketch the region (c) Evaluate BOTH integrals in Green's Theorem (Circulation Form) and verify that both computations match.
The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.
(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:
\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)
Simplifying this expression yields:
\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)
(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).
(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.
Using the circulation form of Green's Theorem, the line integral becomes:
\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)
The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:
\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)
Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.
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A swimmer push water backward give reason
To move forward he has to push the water back and because of Newtons third law of motion, every action has a equal and opposite reaction, so the force he uses to push the water is how much he moves forward.
3.) using calories, calculate the how much heat 32.0 g of water absorbs when it is heated from 25.0oc to 80.0oc. how many joules is this?
The specific heat capacity of water is 1 calorie per gram per degree Celsius. This means that 1 gram of water will absorb 1 calorie of heat for every 1 degree Celsius increase in temperature.
In this case, we have 32.0 grams of water that is heated from 25.0 degrees Celsius to 80.0 degrees Celsius. The change in temperature is therefore 80.0 - 25.0 = 55.0 degrees Celsius.
The amount of heat absorbed by the water is therefore 32.0 x 55.0 = 1760 calories.
To convert calories to joules, we can use the following conversion factor:
1 calorie = 4.184 joules
Therefore, the amount of heat absorbed by the water in joules is 1760 x 4.184 = 7374 joules.
Therefore, the answer to your question is that 32.0 grams of water absorbs 7374 joules of heat when it is heated from 25.0 degrees Celsius to 80.0 degrees Celsius.
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A car traveling at 7.5 m/s accelerates 2.9 m/s2
to reach a speed of 12.0 m/s.
How long does it take for this acceleration
to occur?
Answer in units of s.
Answer:
6.5/3.8 seconds
Explanation:
u=7.5
a=3.8
v=14
find t
The first formula has u,a v and t
so use that one
14=7.5+3.8t
6.5=3.8t
t=6.5/3.8 seconds
Please
help
me
with this problem
Answer:
speeding up
Explanation:
because its speeding up, theres going to be more newtons in the back
i really hope this is right, tell me if so
The electric force between two or more charged objects depends on which of the following quantities?
a. charge and distance between the charged objects
b. quantity of charges and their masses
c. charge and mass of charged objects
d. mass and distance between the charged objects
The electric force between two or more charged objects depends on the charge and the distance between the charged objects
What is Coulomb's law?Coulomb's law states that the force of attraction or repulsion between two charged bodies is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Coulomb's law shows the relationship between the force , charge and the distance between the bodies
therefore F= kq1q2/r²
where q1 is the charge of body 1 and q2 is the charge of body 2. r is the distance between them and k is called electrostatics constant which have a value of 9,×10⁹ Nm²/C²
Therefore what can affect the force between two charges are the product of the charge of the two bodies and the distance between the two charge.
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A capacitor has a peak current of 330 μA when the peak voltage at 350 kHz is 2.8 V .Part AWhat is the capacitance?Part BIf the peak voltage is held constant, what is the peak current at 700 kHz ?
The capacitance is approximately 1.54 nanofarads and the peak current at 700 kHz is 5.21 μA
Part A:
To calculate the capacitance (C), we can use the formula:
I = C * ω * V
where I is the peak current, ω is the angular frequency (2πf), and V is the peak voltage.
Given that the peak current is 330 μA (microamperes), the peak voltage is 2.8 V, and the frequency is 350 kHz (kilohertz), we can convert the units:
I = 330 μA = 330 * 10^(-6) A
V = 2.8 V
f = 350 kHz = 350 * 10^(3) Hz
ω = 2πf = 2π * 350 * 10^(3) rad/s
Now, we can rearrange the formula to solve for C:
C = I / (ω * V)
C = (330 * 10^(-6) A) / (2π * 350 * 10^(3) rad/s * 2.8 V)
C ≈ 1.54 * 10^(-9) F
Therefore, the capacitance is approximately 1.54 nanofarads (nF).
Part B:
To find the peak current at 700 kHz while keeping the peak voltage constant, we can use the same formula:
I = C * ω * V
Given that the peak voltage is constant at 2.8 V and the frequency is now 700 kHz (700 * 10^(3) Hz), we can calculate the new angular frequency:
ω = 2πf = 2π * 700 * 10^(3) rad/s
Substituting the values into the formula, we can calculate the new peak current:
I = (1.54 * 10^(-9) F) * (2π * 700 * 10^(3) rad/s) * (2.8 V)
I ≈ 5.21 μA
Therefore, the peak current at 700 kHz while keeping the peak voltage constant is approximately 5.21 μA (microamperes).
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You've got a flat tire. To lift your car, you make a homemade lever (see the figure (Figure 1)). A very light 1.6-m-long handle part is pushed down on the right side of the fulcrum and a 0.050-m-long part on the left side supports the back of the car.
How hard must you push down on the handle so that the lever exerts an 6900- N force to lift the back of the car?
How hard you must push down on the handle is by applying a force of 215.63 N
Moment of a forceThe moment of a force about a point is the turning effect of the force about that point.
The moment of a force M = Fd where
F = force and d = perpendicular distance of force from pivot point.Now, for you to lift up the car, the moment due to your force about the fulcrum, M equals the moment due to the force on back of car. M'
M = M'
FD = F'd where
F = Force applied, D = distance of force from fulcrum = 1.6 m, F' = force applied on back of car = 6900 N and d = distance of force on back of car from fulcrum = 0.050 mMaking F subject of the formula,we have
F = F'd/D
Substituting the values of the variables into the equation,we have
F = F'd/D
F = 6900 N × 0.050 m/1.6 m
F = 345 Nm/1.6 m
F = 215.625 N
F ≅ 215.63 N
So, how hard you must push down on the handle is by applying a force of 215.63 N
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which of the following is incorrect for nuclear forces
a) they are attractive in nature
b) they are short range forces
c) they obey inverse square law
d) they are non conservative in nature
Answer:
c they obey inverse square law
The color of light emitted is determined by the amount of energy released by the atom when electrons within it relax.
Answer:
As electrons move from higher energy levels to lower energy levels a photon (particle of light) will be given off. This is the process of emission.
Explanation:
electrons and photons also do this
PLEASE HELP—ITS PHYSICS AND I NEED ANSWERS ASAP
If a train is going 24 m/s and comes to a stop, what is the distance it covers if the acceleration
is -0.29 m/s??
Explanation:
u=24
v=0
a=-0.29
s=
v^2=u^2+2as
s=(v^2-u^2)/2a
s=(0-576)/0.58
s=-575.42
The 200-mm test tube also contained some water (besides the metal) that was subsequently added to the calorimeter (in Part A.4.). Considering a higher specific heat for water, will the temperature change in the calorimeter be higher, lower, or unaffected by this technique error?
Answer:
The temperature change in the calorimeter will be lower
Explanation:
Water is an example of a molecular substance. They have relatively low melting points and boiling points usually below 300° C . Water reacts with metals to a degree varying with their position in the electrochemical series.
The specific heat of water is 4179.6 Joules which is relatively high . This typically implies that water absorbs a larger amount of heat but the increase in temperature of its boiling points is relatively low. Thus; in the 200-mm test tube that contains water and was subsequently added to the calorimeter , the heat present was initially absorbed by the water and that does not result to an increase in the temperature change in the calorimeter. Thus the temperature change in the calorimeter will be lower.
you are driving a car. as you prepare to turn, you see a motorcycle coming toward you. the motorcycle is likely to appear farther away than it is because it is ______.
The motorcycle is likely to appear farther away than it actually is because it is smaller in size than your car. This phenomenon is known as the size-distance illusion, where our brains tend to perceive smaller objects as farther away, even if they are not. This is because our brain assumes that larger objects are closer and smaller objects are farther away.
Moreover, the visual angle of the motorcycle, which is the angle that the motorcycle subtends on your eye, is smaller than that of your car due to its smaller size. Hence, our brain interprets this smaller visual angle as an indication that the motorcycle is farther away than it actually is.
As a driver, it is crucial to be aware of this illusion and take necessary precautions while turning or changing lanes to avoid accidents with smaller vehicles such as motorcycles. One should always check their surroundings thoroughly and double-check before making a move.
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Elmo finds himself at a Coke machine on a hot and dusty Sunday. The Coke machine requires exact change—two quarters and a dime. No other combination of coins will make anything come out of the machine. No stores are open; no one is in sight. Elmo is so thirsty that the only thing he cares about is how many soft drinks he will be able to buy with the change in his pocket; the more he can buy, the better. While Elmo searches his pockets, your task is to draw some indifference curves that describe Elmo’s preferences about what he finds.
(a) If Elmo has 2 quarters and a dime in his pockets, he can buy 1 soft drink. How many soft drinks can he buy if he has 4 quarters and 2 dimes? 1
(b) Does Elmo have convex preferences between dimes and quarters?
(c) Does Elmo always prefer more of both kinds of money to less?
(d) Does Elmo have a bliss point?
(e) If Elmo had arrived at the Coke machine on a Saturday, the drugstore across the street would have been open. This drugstore has a soda fountain that will sell you as much Coke as you want at a price of 4 cents an ounce. The salesperson will take any combination of dimes and quarters in payment. Suppose that Elmo plans to spend all of the money in his pocket on Coke at the drugstore on Saturday. Draw one or two of Elmo’s indifference curves between quarters and dimes in his pocket. Describe these new indifference curves in words.
The answers are- (a) 2 soft drinks. (b) Uncertain. (c) Not necessarily.
(d) No bliss point. and, (e) Steeper indifference curves.
(a) If Elmo has 4 quarters and 2 dimes in his pockets, he can buy 2 soft drinks. Since each soft drink requires two quarters and a dime, having double the amount of each coin allows him to make two purchases.
(b) Elmo's preferences between dimes and quarters may or may not be convex. Convex preferences imply that as Elmo increases the quantity of one type of money (quarters or dimes), the marginal utility he derives from each additional unit of that money diminishes. If Elmo's preference for soft drinks is based solely on the ability to purchase them and not on any diminishing marginal utility of the coins themselves, then his preferences may not exhibit convexity.
(c) Elmo does not necessarily always prefer more of both kinds of money to less. Given the specific context of the Coke machine, Elmo's only concern is to have the exact change required to obtain a soft drink. As long as he has the necessary combination of two quarters and a dime, having additional coins does not increase his utility further.
(d) Elmo does not have a bliss point in this scenario. A bliss point refers to the combination of goods or factors that maximizes an individual's utility or satisfaction. Since Elmo's sole objective is to purchase soft drinks from the Coke machine, his utility is maximized when he has the exact change required (two quarters and a dime). Having more coins does not enhance his utility beyond being able to buy a single soft drink.
(e) If Elmo had arrived at the Coke machine on a Saturday, with the drugstore across the street open, his preferences would change. Instead of being limited to the specific combination of two quarters and a dime, he could now use any combination of quarters and dimes to purchase as much Coke as he wants at a price of 4 cents per ounce.
In this case, Elmo's indifference curves between quarters and dimes would exhibit a downward slope, indicating that he is willing to trade off some quantity of one coin for a corresponding increase in the other, while still maintaining the same level of utility. The indifference curves would be steeper than the ones in the previous scenario, as Elmo can now acquire more soft drinks by having a larger combination of quarters and dimes.
These new indifference curves reflect Elmo's preference for more quarters and dimes, as they enable him to buy more Coke at the drugstore. The curves demonstrate that Elmo is willing to sacrifice some quantity of quarters to obtain additional dimes or vice versa, as long as the overall combination allows him to maximize the quantity of Coke he can purchase.
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A voltage signal is in the form, 5(ω)+7(2ω)+9(3ω). You decided to improve the THDR of the signal by amplifying it. What is the minimum voltage amplification required to bring the THDR of the output signal below 0.5. Assume that due to the frequency response of the voltage amplifier only the fundamental harmonic signal voltage gets amplified while higher harmonics signal voltages get reduced by half of their original value. Approximate your answer to 2 decimal points.
The minimum voltage amplification required to bring the THDR of the output signal below 0.5 is 3.2.The given voltage signal is in the form of 5(ω) + 7(2ω) + 9(3ω).
To improve the THDR (Total Harmonic Distortion Ratio) of the signal, we need to amplify it. Let's find the THDR of the original signal first. The THDR is calculated by dividing the sum of the amplitudes of all harmonic frequencies by the amplitude of the fundamental frequency. In this case, the fundamental frequency is ω, and the harmonic frequencies are 2ω and 3ω.
The amplitude of the fundamental frequency is 5, and the sum of the amplitudes of the harmonic frequencies is 7 + 9 = 16. So, the THDR of the original signal is 16/5 = 3.2.
To bring the THDR of the output signal below 0.5, we need to reduce it by more than 3.2/0.5 = 6.4 times. Since the higher harmonic signals get reduced by half of their original value, we can calculate the minimum voltage amplification required to achieve this.
Let's assume the amplification factor for the fundamental frequency is x. Then the amplitude of the fundamental frequency in the output signal will be 5x. For the harmonic frequencies, their original amplitudes are 7 and 9. Since they get reduced by half, their amplitudes in the output signal will be 7/2 and 9/2, respectively.
Now, let's calculate the THDR of the output signal using these values.
The sum of the amplitudes of the harmonic frequencies in the output signal is (7/2) + (9/2) = 8.
To bring the THDR below 0.5, the sum of the amplitudes of the harmonic frequencies should be less than 0.5 times the amplitude of the fundamental frequency.
In this case, that would be 0.5 * 5x = 2.5x. So, 8 < 2.5x.
To find the minimum value of x, we divide both sides of the inequality by
2.5. 8/2.5 < x. x > 3.2.
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an object has a kinetic energy of 36.0 j. an object with three times the mass moving at the same speed will have a kinetic energy of
The kinetic energy of another body having three times the mass of the given object will be 108 J
Kinetic energy-In physics, the kinetic energy of an object is the energy it has due to motion. It is defined as the work required to accelerate a body from a given mass from rest to a specified speed.
The kinetic energy of a body is given by \(K.E= \frac{1}{2}Mv^{2}\) (first equation)
Given K.E= 36J
Now the mass of second body is m=3M
also the second body is moving with the same speed v
So kinetic energy of second body K.E₂= \(\frac{1}{2}mv^{2} =\frac{1}{2}(3M)v^{2}\)=36×3
=108J (from first equation)
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What is the acceleration of car if it goes from 60 m/s to a stop in 6 seconds?
Answer:
\(\boxed {\boxed {\sf a= -10 \ m/s^2}}\)
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
\(a=\frac{v_f-v_i}{t}\)
The car came to a stop, so it's final velocity is 0 m/s.
The initial velocity of the car is 60 m/s.
The time is 6 seconds.
\(v_f=0 \ m/s\\v_i=60 \ m/s\\t= 6 \ s\)
Substitute the values into the formula.
\(a=\frac{0 \ m/s-60 \ m/s}{6 \ s }\)
Solve the numerator.
0 m/s-60 m/s= -60 m/s\(a\frac{-60 \ m/s}{ 6 \ s }\)
Divide.
\(a= -10 \ m/s^2\)
The acceleration of the car is-10 meters per square second. The negative acceleration indicates it is slowing down/stopping.
an electrically charged object can be used to attract:
An electrically charged object can be used to attract any object with an opposite charge.
This is due to the fundamental principle that opposites attract and repel in physics.
Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.
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what is the demand for resources, such as food, water, and shelter.
the magnetic field at the center of a 0.700-cm-diameter loop is 3.00 mt . part a what is the current in the loop? express your answer with the appropriate units.
The magnetic field at the center of a current-carrying loop is given by the formula: B = (μ₀/4π) * (2I/ r)
where B is the magnetic field at the center of the loop, I is the current in the loop, r is the radius of the loop, and μ₀ is the permeability of free space. In this case, we are given the magnetic field B = 3.00 mT = 3.00 × 10^(-3) T and the radius r = 0.700 cm = 0.00700 m.Substituting these values into the above formula, we can solve for the current I: I = (B * r * 4π)/ (2 * μ₀)
I = (3.00 × 10^(-3) T * 0.00700 m * 4π)/ (2 * 4π × 10^(-7) T·m/A)
I = 0.0133 A
Therefore, the current in the loop is 0.0133 A (amperes).
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