A particle in a magnetic field is found to has zero magnetic force on it. Which situation is impossible to happen?​

Answer:

d.solid to liquid cause they were once on a fixed and started to slide.liquid particles slide along a container so it is a solid to liquid

Answer: B

Explanation: just did it on a p e x

Answer:

solution given:

acceleration (a)=?

initial velocity (u)=3m/s

final velocity (v)=6m/s

distance (s)=90m

we have

v²=u²+2as

substituting value

6²=3²+2*a*90

36=9+180a

36-9=180a

a=25/180

a=0.1388m/s²

Answer:

The acceleration of dog is 0.15 m/s².

Step-by-step explanation:

Given :

To Find :

Using Formula :

\(\star{\underline{\boxed{\sf{\purple{{v}^{2} = {u}^{2} + 2as}}}}}\)

Solution :

Substituting all the given values in the formula to find acceleration :

\({\longrightarrow{\sf{{v}^{2} = {u}^{2} + 2as}}}\)

\({\longrightarrow{\sf{{6}^{2} = {3}^{2} + 2 \times a \times 90}}}\)

\({\longrightarrow{\sf{{6 \times 6}= {3 \times 3} + 2 a \times 90}}}\)

\({\longrightarrow{\sf{36=9 + 180a}}}\)

\({\longrightarrow{\sf{36 - 9 = 180a}}}\)

\({\longrightarrow{\sf{27 = 180a}}}\)

\({\longrightarrow{\sf{a = \dfrac{27}{180}}}}\)

\({\longrightarrow{\sf{a \approx 0.15}}}\)

\(\star{\underline{\boxed{\tt{\red{a \approx 0.15 \: m/s^{2} }}}}}\)

Hence, the acceleration of dog is 0.15 m/s².

\(\rule{300}{1.5}\)

Answer:

5.0 kg

Explanation:

use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)

F12 = k • q1 • q2 / r12²

F12 = (9 × 10⁹) • (7.5 × 10⁻⁶)² / (0.25)²

F12 = 8.1 N

F13 = k • q1 • q2 / r12²

F12 = (9 × 10⁹) • (7.5 × 10⁻⁶)² / (0.25² + 0.25²)

F12 = 4.05 N

F² = F12² + F13² + 2(F12)(F13) cos θ

F² = (8.1)² + (4.05)² + 2(8.1)(4.05) cos 45°

F = 11.33 N

Work  done on the crate by the tension force is -1.8125 J

The work that the tension force during the motion did on the container can be calculated using the work-energy theorem. According to the work-energy theorem, an object's change in kinetic energy equals the net work that is performed on it.

The crate has initial kinetic energy of: because it is initially moving at a speed of 0.500 m/s,

K1 = (1/2)mv1² = (1/2)14.5 kg*0.500 m/s*² = 1.8125 J

The crate encounters an additional upward force of when the rope's tension is increased to 160 N.

\(F=mg+T=14.5 kg* 9.81 m/s 2 +160 N=301.245 N\)

The final height of the crate above the ground after an additional 1.35 m of lifting is:

h2 = 1.35 m

The crate has stopped moving at this stage, leaving it with zero final kinetic energy.

As a result, the change in the crate's kinetic energy equals the work done on it by the tension force:

W = K2 - K1 = 0 - 1.8125 J \s= -1.8125 J

Due to the fact that the tension force's work is negative, the crate is being pulled downward by the gravitational force, which is equivalent to the tension force's negative work. This makes sense given that the tension force is working against gravity when the cargo is being hoisted.

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Answer:

1/f = 1/i + 1/o      thin lens equation

1/i = 1/f - 1/o

i =  o * f / ( o - f) = 50 * (-20) / (50 - (-20)) = -14.3 cm

The final image is  erect and 14.3 cm behind the curved surface

M = -o / i = 14.3 / 50 = .29      magnificaton of object

S = .29 * 25 cm = 7.1 cm       appearance of bird in mirror (height)

It is not possible to observe all of the stars during a year from a single location on Earth. This is because the Earth rotates on its axis and orbits the Sun, causing the positions of the stars to change relative to an observer on the surface.

From the North Pole, an observer can see approximately half of the sky. This is because the North Pole is located at the axis of rotation of the Earth, and therefore the observer can see half of the sky in all directions.

Yes, you can see stars at the North Pole, but the availability of stars to be seen depends on the time of year. During the summer months, the North Pole experiences 24 hours of daylight and the Sun never sets, so the stars are not visible.

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Answer:

d = 100 m

Explanation:

Given that,

Initial speed of a car, u = 10 m/s

Final speed of a car, v = 40 m/s

Time, t = 4 seconds

We need to find how far does it travel during that time. Let the car travel d distance. We can find it using third equation of motion as follows :

\(v^2-u^2=2ad\) ...(1)

a is acceleration and d is the distance

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{40-10}{4}\\\\a=7.5\ m/s^2\)

So, equation (1) becomes,

\(d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(40)^2-(10)^2}{2\times 7.5}\\\\d=100\ m\)

So, it will travel 100 m during that time.

The statement, "The Voyager 1 space probe can't change its own motion" is correct and true. The Voyager 1 space probe was launched by NASA in 1977, and since then it has traveled over 14 billion miles away from Earth. It's the most distant spacecraft from Earth.

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Answer:

B

Explanation:

Answer:

A. 12,240.

Explanation:

1,530 times 8.0 = 12,240.

hope this helped :)

Explanation:

q1 = -6

q2 = -8

d^2 = (6/100)^2 = 0.0036

k = 1/4*(pi*E) where E js the permittivity of free space

F = (k*q1*q2)/(d^2)

Substitute your values into this equation and solve

To maximize the objective function p with the given constraints, we use linear programming by identifying the feasible region.

Finding corner points, evaluating p at each point, and selecting the point with the maximum value of p.In this case, the given constraints are x = 0, y = 0, 2x + 2y = 4, and x + y = 8. To maximize the objective function p, we follow these steps:Identify the feasible region by graphing the constraints on a coordinate plane.

The corner points, which represent the vertices of the feasible region.Evaluate the objective function p at each corner point.Select the point with the maximum value of p as the optimal solution that maximizes p while satisfying the given constraints.

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The power required to move the automobile to the top of the hill is 130,666.67 watts or 175.41 horsepower.

The power required to move an object can be calculated using the formula: power = work / time.

First, let's calculate the work done in lifting the automobile to the top of the hill. The work done against gravity is given by the formula: work = force × distance.

The force required to lift the automobile is equal to its weight. The weight of an object is given by the formula: weight = mass × acceleration due to gravity.

Substituting the given values, we have: weight = 2,000 kg × 9.8 m/s^2 (acceleration due to gravity) = 19,600 N.

The distance the automobile is lifted is 100 meters.

Therefore, the work done against gravity is: work = 19,600 N × 100 m = 1,960,000 J (joules).

The time taken to reach the top of the hill is given as 15.0 seconds.

Now, we can calculate the power using the formula: power = work / time.

power = 1,960,000 J / 15.0 s = 130,666.67 W (watts).

To convert watts to horsepower, divide the power in watts by 746 (1 horsepower = 746 watts).

power in horsepower = 130,666.67 W / 746 = 175.41 hp (horsepower).

Rounding to two decimal places, the power required to move the automobile to the top of the hill is approximately 130,666.67 watts or 175.41 horsepower.

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The  to problem of calculating the power required to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is given

Given, Mass of the automobile, m = 2000 knight of the hill, h = 100 time, t = 15.0 the gravitational potential energy of the automobile when at the bottom of the hill is equal to the work done in lifting it up the hill

.W = mgh= (2000 kg) (9.81 m/s²)

(100 m)= 1,962,000 J

Power is defined as the rate at which work is done, or the work per unit time. Therefore,

Power = Work / Time= 1,962,000 J / 15.0 s

= 130,800 WIn horsepower, Power = (130,800 W) / (746 W/hp)

= 175.3 hp

Therefore, the required power to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is 130,800 W or 175.3 hp.

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Answer:

Opción A - Difracción

Explanation:

Mirando las opciones, la respuesta correcta es la difracción.

Esto se debe a que la difracción es simplemente la propagación de las olas alrededor de los obstáculos.

Por ejemplo, si estuviera afuera de una puerta abierta, aún podría escuchar porque la arena se extenderá desde la pequeña abertura como si fuera una fuente localizada de arena.

Esto es posible debido al fenómeno llamado difracción.

Acceleration will increase as the angle of incline does, and as a result, force will as well.

The gravitational force acting on the cart increases as the slope of the incline increases, causing it to accelerate more quickly.The ramp's steepness will cause an increase in inclination. As a result, the acceleration increases as the inclination angle increases. This acceleration causes the object to descend with greater speed.

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The most distant star for which Jill can measure parallax from the asteroid orbiting the Sun at a distance of 3 AU is approximately 224,620 AU.

To determine the maximum distance at which Jill can measure parallax from the asteroid orbiting the Sun, we need to calculate the corresponding parallax angle for that distance.

The parallax angle (θ) is related to the distance to the star (d) and the baseline distance (B) between two observations by the following formula:

θ = atan(B / d)

Given that Jill can determine parallax to 0.2 arcseconds, which corresponds to a distance of 16 light years, we can write:

0.2 arcseconds = atan(B / 16 ly)

To convert the distance from light years to astronomical units (AU), we can use the conversion factor that 1 light year is approximately equal to 63,241 AU. Therefore:

0.2 arcseconds = atan(B / (16 * 63,241 AU))

Now, let's consider the new observation from the asteroid, which orbits the Sun at a distance of 3 AU. The baseline distance (B) for Jill's observations will be twice the distance of the asteroid from the Sun (6 AU) because she will observe the star from opposite sides of the Sun's orbit. Substituting B = 6 AU into the equation:

0.2 arcseconds = atan(6 AU / (16 * 63,241 AU))

Simplifying the equation:

0.2 arcseconds = atan(6 / (16 * 63,241))

Now, we can solve for the distance (d) using the inverse tangent (atan) function:

d = (6 / (16 * 63,241)) / atan(0.2 arcseconds)

Calculating this expression:

d ≈ 2.2462 × 10^5 AU

Therefore, the most distant star for which Jill can measure parallax from the asteroid orbiting the Sun at a distance of 3 AU is approximately 224,620 AU.

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The product of the charges and the distance have a direct relationship with the electrical force, F, between two point charges.

The square of the distance between the two charges and the strength of the force are inversely related. As a result, if the gap between the two charges is increased, the attraction or repulsion is reduced.

Coulomb's law states that the force of attraction or repulsion between two charged bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their charges.

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Answer:

By applying an unbalanced force, you can change the motion of an object. Unbalanced forces can make an object at rest start moving, make a moving object stop, or change the direction and speed of the object.

Explanation:

Any functional group that contributes negative charge must have a lone pair of electrons.

The term functional group refers to an atom, group of atoms or a bond that is responsible for the chemical reactivity of the homologous series. A homologous series is any family of compounds.

The question is incomplete. However, any functional group that contributes negative charge must have a lone pair of electrons like amines.

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Explanation:

1. the potential difference of each capacitors is the same.

Hi there!

We know that:

Ei = Ef

At the bottom of the incline, we have both rotational and translational kinetic energy. Recall:

Translational KE  = 1/2mv²

Rotational KE = 1/2Iw²

We can begin by deriving an equation for the final energy of the sphere.

Moment of Inertia of a hollow sphere= 2/3mR²

\(KE_{total} = \frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{3}mR^2(\frac{v^2}{R^2}))\)

Simplify:

\(KE_{total} = \frac{1}{2}mv^2 + \frac{1}{3}mv^2 = \frac{5}{6}mv^2\)

Since Ei = Ef, and the initial energy is simply PE = mgh, thus:

mgh = 5/6mv²

Cancel out 'm':

gh = 5/6v²

We are given the angular velocity, so we can convert to velocity using:

v = ωr

v = 5.88(.68) ≈ 4.00 m/s

h = (5/6v²)/g

h = (5/6(4²))/g = 1.359 m

Answer:

the correct one is 3

Explanation:

The magnetic force is described by the expression

         F = q v x B

The bold indicate vectors, q is the charge, v the velocity and B the magnetic induction

This expression can be written in scalar form

        F = q v B sin θ

where θ is the angle between velocity and induction.

The direction of the force is perpendicular to the vectors.

When revising this expression the force depends on the electric charge, the speed of the particle and the induction of the magnetic field

therefore, checking the possible answers, the correct one is 3

Answer:

convection: heat transfer by movement of currents inside a liquid, currents in the mantle, temp inside the house, red dye rises blue dye sinks,

radiation: heat from a bonfire, transfer of energy through space,

conduction: frying pan to cooking egg, candle heating up foil to chocolate chips

Explanation:

a. By the work-energy theorem, the total work required to stop the car is equal to the change in its kinetic energy,

W = 0 - 1/2 (750 kg) (25 m/s)² ≈ -230 kJ

b. The car covers a distance x as it stops such that

W = (-725 N) x   ==>   x ≈ 320 m

The two waves of equal frequency interfere constructively at a listener's location, and interference increases amplitude.

There won't be interference if the amplitudes of two sources with the same frequency are not identical. All points will have the same level of sound intensity. Any given time, the volume of the sound will fluctuate in intensity. Even though there will be interruption, it won't be completely absent.

Interference in physics is a phenomena when two waves merge by adding their displacements at each and every point in space and time to produce a new wave that has a higher, lower, or identical amplitude. The interaction of waves that are coherent or correlated with one another, either because they originate from the same source or because their frequencies are similar or almost identical, leads to both constructive and destructive interference. All sorts of waves, including light, radio, acoustic, surface water waves, gravity waves, and matter waves, can exhibit interference effects.

Hence, amplitude increases when equal frequency combined.

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Answer:

Passive solar heating uses building design to utilize sunlight, while active solar heating uses technology.

Explanation:

lol