A particle is moving along a circle of radius r such that it complete 1 rev in 40 sec. What will be the displacement after 2 mint 20sec?

Following the image of the ball that have been shown;

1. Potential energy

2. Kinetic energy

3. Kinetic energy

4. Potential energy

5. Kinetic energy

6. Kinetic energy

7. Kinetic energy

Due to its position or elevation, an object has potential energy while it is at rest or is elevated above the ground. Depending on the circumstances, this potential energy may either be elastic or gravitational.

Kinetic energy, or the energy connected to motion, is present when an item is in motion. An object's kinetic energy is determined by its mass and velocity .

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Answer:

1: Potential and kinetic

2: Potential and kinetic

3: Potential and kinetic

4: potential

5: Potential and kinetic

6: Potential and kinetic

7: NEITHER

Explanation:

4 is potential because its the highest point

7 is neither because the question states "the image shows the path of a ball from the time it's thrown to the time it lands on the ground" so... 7 is when the ball has landed on the ground. therefore it has neither potential nor kinetic because it is resting.

Answer:

The magnetic force disappears

The mass and magnitude of the second particle are calculated below.

The initial velocity of an object is its velocity prior to the effect of acceleration, which causes the change. The velocity will be the final velocity after accelerating the object for some time. When a particle moves at a constant speed, it can be accelerated. When a point object moves in a horizontal circular path at a constant speed, the direction of its velocity vector changes over time. It means that in a uniform circular motion, the object's velocity vector changes over time.

Distance between the charges, r = 3.2 × \(10^{-3}\)m

initial acceleration of first particle, \(a_{1}\) = 7m / \(s^{2}\)

Initial acceleration of second particle, \(a_{2}\) = 9.0m / \(s^{2}\)

Mass of first particle, \(m_{1}\) = 6.3 × \(10^{-7}\)kg

Mas of second particle, m₂ = ?

a) Since, \(F_{1}=F_{2}\)

∴ \(m_{1}a_{1} = m_{2}a_{2}\)

mass of second particle-\(m_{2}\) =\(\frac{m_{1}\times a_{1}}{a_{2}}\)

= \(\frac{6.3\times10^{-7}\times7.0}{9.0}\)

=4.9 × \(10^{-7}\)Kg

b)As, \(F_{1} = F_{2}\)

       = \(\frac{q_{1}q_{2}}{4\pi E_{0}r^{2}}\) = \(m_{1}a_{1}\)

       = 6.3 × \(10^{-7} \times\) 7.0

       = 44.1 × \(10^{-7}\)

∴ q = 7.1 × \(10^{-11}\)C.

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A free-body diagram represents the forces acting on a body. Let's draw a free-body diagram showing the forces acting on an elephant: Here, the force acting downwards is the weight (W) of the elephant, which is balanced by the normal force (N) exerted by the ground.

Weight of the elephant on Earth: The weight of the elephant is equal to the force due to gravity acting on it. On Earth, the acceleration due to gravity (g) is approximately 9.81 m/s².

So, the weight of the elephant on Earth = mass × acceleration due to gravity= 3500 kg × 9.81 m/s²= 34335 N.

Therefore, the weight of the elephant on Earth is 34335 N.

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From the position-time graph, we have the following:

Distance covered Time

0 to 28 m 0 to 20 seconds

28m to 52 m 20 to 60 seconds

At 52 m 60 to 80 seconds

52 to -20m 80 to 110 seconds

Let's find the average speed for the entire trip.

To find the average speed, apply the formula:

Distance at line 1: 28 - 0 = 28m

Distance at line 2: 52 - 28 = 24 m

Distance at line 3: 0 m

Distance at line 4: -20m - 52 = -72 m

Thus, we have the equation:

Where:

d1 = 28 m

d2 = 24 m

d3 = 0 m

d4 = 72 m

t = 110 s

Now substitue values into the equation:

Therefore, the average speed for the trip is 4.4 m/s.

ANSWER:

Equation:

Substitution:

Calculation:

(1) The wavelength of the wave is 1.57 m.

(2) The velocity of the wave is 30 m/s .

(3) The frequency of the wave is 19.10 Hz and the time period of the    wave is 0.052 s.

Note: The given equation seems to be incomplete. Most probably the equation was y=25sin(120t-4x). And the standard system of units (i.e. kg, m, s) is used.

Wavelength: The distance between the consecutive crest or trough of a wave is called the wavelength of a wave.

The equation of a plane wave oscillating in the y direction and traveling in the x direction is given by the equation,

y=A sin(ωt-kx)

where y is the displacement along the y direction, A is the amplitude of the wave, ω is the angular frequency, t is the time, x is the displacement along the x direction, and k is the wave constant.

The given equation is,

y=25sin(120t-4x)

Comparing this equation with the above equation, following values are obtained.

k= 4 m^(-1)

ω =120 rad/s

A=25

The wavelength λ is given by the formula,

λ=2π/k

Here k = 4 m^(-1), so

λ=2π/4

λ=1.57 m.

Velocity: The velocity of a wave is the product of the frequency and the wavelength.

The velocity v is given by the formula,

v=ω*λ/2π

Here ω=120 rad/s and λ=1.57 m, so

v=120*1.57/2π

v=30 m/s

Frequency: The number of oscillations completed in one second is called the frequency of a wave.

The formula of the frequency is,

f=v/λ

Here v=30 m/s and λ=1.57 m, so

f=30/1.57

f=19.10 Hz

Time period: The time taken to complete one cycle of oscillation is called the time period of oscillation.

The formula to calculate the time period T is,

T=2π/ω

Here ω=120 rad/s, so

T=2π/120

T=0.052 s.

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Answer:

burning, cooking, rusting, and rotting.

Explanation:

Answer:

what are the statements so i can help just comment and i will get back to you

Explanation:

Answer:

=>8x+9x+5+3

=>8x+9x+5+3=>17x+8

Answer:

If you try to lift up a weight in a swimming pool and then try to lift the same weight on the edge of the pool, it feels much lighter in the water.

This was supposed to have been first explained by the Greek scientist Archimedes. He said that the water gives an upward force or upthrust on any object in it.

You can weigh an object in air and then in water and actually work out the upthrust, it is the difference between the two readings. For this reason the upthrust is often called the loss in weight of the object.

Answer: the conclusion is that

Explanation:

Answer:

"we both attract each other with the same force but we know that attraction between two bodies depends upon their mass, greater the mass of two bodies is the force of attraction between them"(got this off the internet).

If the dew point of cold outside air is the same as the dew point of warm air indoors, and the door is opened to allow cold air to replace some of the warm inside air, the new relative humidity indoors would be (a) lower than before. Relative humidity is a measure of the amount of moisture in the air compared to the maximum amount of moisture the air can hold at a specific temperature.

When cold air enters a warmer environment, its capacity to hold moisture increases. However, if the dew point of the cold air is the same as the dew point of the warm air indoors, it means that both air masses contain the same amount of moisture relative to their respective temperatures.

When the door is opened, and cold air replaces some of the warm inside air, the overall moisture content remains the same. However, the warmer air indoors has a higher capacity to hold moisture compared to the cold outside air. As a result, the relative humidity decreases as the colder air replaces some of the warm air.

To illustrate this, let's consider an example. Suppose the warm inside air has a temperature of 25°C and a dew point of 15°C. The cold outside air also has a dew point of 15°C but a lower temperature, let's say 10°C. When the door is opened and some of the warm air is replaced by the colder air, the temperature indoors decreases while the moisture content remains the same. As a result, the relative humidity decreases because the cold air has a lower capacity to hold moisture at its lower temperature.

When the dew point of cold outside air is the same as the dew point of warm air indoors, opening the door to let cold air replace some of the warm air will result in a lower relative humidity indoors. This occurs because the colder air has a lower capacity to hold moisture compared to the warmer air, even if the moisture content remains the same.

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The safest option in the lab if one need your vision to be corrected is  wear corrective glasses or lenses under your safety goggles for the whole experiment, but always check with your ta or instructor for your school's policy.

When someone is performing any project in the chemistry lab, he needs to be extra care taken by himself and and the most importantly from the school. The safety goggles are used to protect the eyes from any spiling off the chemical.

One should wear corrective glasses under the safety goggles during the whole experiment.

Thus, wear corrective glasses under the safety goggles during the whole experiment.

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The lover of the princess entered the arena as a door beneath the royal party opened. His looks were tall, lovely, and fair.

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Frequency is perceived by humans as pitch; The sound intensity is the amplitude; Humans can only hear a specific range of sound, usually from 20 Hz to 20,000 Hz; The factors that go into a sound are its intensity, frequency and overtones (which are like interference, or background noises).

It's "Pitch" on edge.

Answer:

A ball is thrown straight up with a speed of 30

m/s. What is the maximum height reached by

the ball?

Answer: The Doppler effect occurs when a source of a wave is moving relative to an observer (or the observer is moving relative to the source). In this case, the apparent frequency of the sound, as heard/seen by the observer, is shifted with respect to the original frequency of the wave.

More specifically, the relationship between the apparent frequency, f', and the original frequency, f, is given by:

where:

is the velocity of the wave

is the velocity of the observer relative to the source, and it is positive if the observer is moving towards the source, and negative if the observer is moving away from the source

is the velocity of the source relative to the observer, and it is positive if the source is moving away from the observer, and negative if the source is moving towards the observer

The doppler effect occurs in many daily-life situations: for instance, when an ambulance approaches you, you hear an increase in the apparent frequency of the siren due to the Doppler effect. Another example is the movements of distant galaxies from us: when they move away from us, the apparent frequency of the light they emit decreases, so their wavelengths appear to increase towards the red color (red-shift); on the contrary, when they are moving towards us, the apparent frequency seems to increase, so the wavelength seems to decrease towards the blue color (blue-shift).

Explanation:

The distance between the central axis and the first dark fringe in the given single-slit diffraction experiment is approximately 4221.75 mm.

The distance between the central axis and the first dark fringe in a single-slit diffraction experiment can be determined using the formula:

y = (λL) / w

where:

y is the distance between the central axis and the first dark fringe,

λ is the wavelength of light,

L is the distance between the slit and the screen,

and w is the width of the slit.

λ = 573 nm

λ= 573 × 10⁻³m

w = 0.312 mm

w = 0.312 × 10⁻³ m

L = 2.30 m

Now, let's calculate the distance between the central axis and the first dark fringe (y):

y = (λL) / w

y = (573 × 10⁻⁹ m) × (2.30 m) / (0.312 × 10⁻³ m)

y  = 4.22175 m

We need to convert this result to millimeters (mm) since the question asks for the answer in that unit:

y = 4.22175 m × 1000 mm/m

y  ≈ 4221.75 mm

Therefore, the distance between the central axis and the first dark fringe is approximately 4221.75 mm.

In conclusion, the distance between the central axis and the first dark fringe in the given single-slit diffraction experiment is approximately 4221.75 mm.

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Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era.

Kepler's laws of planetary motion are fundamental principles that describe the motion of planets around the Sun and were derived based on observational data available to Johannes Kepler during the 16th and 17th centuries. However, these laws are not limited to the six planets known in Kepler's time.

Kepler formulated three laws of planetary motion:

1. Kepler's First Law (Law of Ellipses): Planets orbit the Sun in elliptical paths, with the Sun located at one of the two foci of the ellipse. This law applies to all planets, including those discovered after Kepler's time.

2. Kepler's Second Law (Law of Equal Areas): An imaginary line connecting a planet to the Sun sweeps out equal areas in equal time intervals. This law holds for all planets, regardless of when they were discovered.

3. Kepler's Third Law (Harmonic Law): The square of a planet's orbital period is proportional to the cube of its average distance from the Sun. This law applies to all planets, both the ones known in Kepler's time and the ones discovered later.

Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era. They provide important insights into the motion and behavior of celestial bodies.

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The owl eats 42 prey in a week and 180 prey in a month.

To calculate how much the owl eats in a week and a month, we need to determine the number of prey consumed in each time period.

In a week:

The owl produces two pellets every 24 hours. So, in one day, it consumes 2 * 3 = 6 prey (since each pellet contains the remains of 3 prey).

In a week (7 days), the owl consumes 6 * 7 = 42 prey.

In a month:

Assuming a month has 30 days (though some months have 31 days or 28/29 days), we can calculate the number of prey consumed in a month.

In a day: 6 prey

In a month (30 days): 6 * 30 = 180 prey.

Hence, the owl eats 42 prey in a week and 180 prey in a month.

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The de Broglie wavelength, λ, can be calculated using the formula:

λ = h / p

where h is Planck's constant and p is the momentum of the particle.

In the case of an electron, the momentum can be calculated using the formula:

p = mv

where m is the mass of the electron and v is its velocity.

The velocity of the electron can be calculated using the formula:

v = sqrt(2 * KE / m)where KE is the kinetic energy of the electron.

In this case, the electron has a kinetic energy of 500 eV. The mass of an electron is 9.11 x 10^-31 kg. Therefore, the velocity of the electron is:

v = sqrt(2 * 500 eV * 1.6 x 10^-19 J/eV / 9.11 x 10^-31 kg) = 2.19 x 10^6 m/s

The momentum of the electron is:

p = mv = 9.11 x 10^-31 kg * 2.19 x 10^6 m/s = 1.99 x 10^-24 kg m/s

The de Broglie wavelength of the electron is:

λ = h / p = 6.63 x 10^-34 J s / 1.99 x 10^-24 kg m/s = 3.33 x 10^-10 m = 3.33 Å

The spacing between the sheets of atoms is d = 1.70 Å, which is smaller than the de Broglie wavelength of the electron. This means that the electron will diffract and interfere with itself as it passes through the slits.

This will result in an interference pattern on the screen behind the slits. The interference pattern will consist of bright and dark fringes, where the bright fringes correspond to constructive interference and the dark fringes correspond to destructive interference .The distance between the slits and the screen is not given, so the exact pattern of the interference fringes cannot be calculated.

However, the general pattern will consist of a central maximum flanked by secondary maxima and minima. The width of the central maximum will depend on the width of the slits and the wavelength of the electron. The width of the secondary maxima and minima will depend on the spacing between the slits and the wavelength of the electron.

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Explanation:

Distance travelled (d) = 56 metres

Time taken (t) = 7 seconds

velocity of the object (V)

= d / t

= 56 / 7

= 8 m/s

The velocity of the object is 8 m/s.

Hope it will help :)

Answer

C

hope this helps!!

*please mark brainliest if correct!! Trying to level up!!

The acceleration experienced by the crate is approximately 0.844 m/s

Weight of the crate:

Weight = mass × acceleration due to gravity

Weight = 114 kg × 10 m/s^2

Weight = 1140 N

Force of friction:

Force of Friction = coefficient of friction × normal force

Force of Friction = 0.541 × 1140 N

Force of Friction ≈ 616.74 N

Net force:

Net Force = Applied Force - Force of Friction

Net Force = 713 N - 616.74 N

Net Force ≈ 96.26 N

Acceleration:

Acceleration = Net Force / mass

Acceleration = 96.26 N / 114 kg

Acceleration ≈ 0.844 m/s

Therefore, the acceleration experienced by the crate is approximately 0.844 m/s

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Answer:

Matter is matter. Particles are particles. Atoms are atoms. You can explain matter using particles and atoms.

JK!

Real Answer:

The term matter refers to anything that occupies space and has mass—in other words, the “stuff” that the universe is made of. An atom is the smallest unit of matter that retains all of the chemical properties of an element. Most atoms contain all three of these types of subatomic particles—protons, electrons, and neutrons.

Hope this helps!

Answer:

there is no graphic

Explanation:

No, they will not be able to clear the hurdle from the given distance of their leap.

Projectile motion includes vertical and horizontal velocity components. It's important to understand that the two are independent of each other. But what is a projectile and what is a good example. Well, a projectile is an object that is thrown by applying a force that falls under gravity and is subject to the resistance of the medium in which it travels. It can be thrown into the air and fall under the influence of gravity.

First of all the time required to reach the hurdle is:

by using horizontal velocity we have time = \(\frac{distance}{speed}\)

t = \(\frac{0.400}{4}\)

t = 0.100s

Now for the vertical distance covered by student:

S = ut + \(\frac{1}{2}\) gt²

S = 9 × 0.100 +  \(\frac{1}{2}\) 9.8 × 0.100²

S = 0.851m or 85.1cm

Since the distance calculated is less than the height of hurdles which is 91.4 cm so the student may not be able to clear the hurdle.

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The acceleration of the object is equal to the net force exerted on it divide by its masses, or a = F m, in accordance with Newton's second rule of motion.

Whenever a forces is applied to a body, numerous other forces, such as gravitational force Field goal, frictional force Ff, and the normal force, also work to balance the imposed force. Therefore, FNet Equals Fa Plus Fg Plus Ff + FN is the formula for net force.

The effects (the total) of all push and pull forces that are really operating on a thing is known as the net force. An object will accelerates in the net force if the pushing and pulling forces acting on it are not equal (a net force acts).

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The type of mass movement that is associated with bowed out tree trunks and misaligned fences is creep.

Creep is a slow form of mass wasting, which is the gradual movement of soil, rock, or debris downhill under the influence of gravity.

Creep is characterized by the gradual downward movement of soil or rock, resulting in the distortion of trees, fences, and other structures on the slope. The movement can be imperceptible, taking place over months or even years.

Bowed out tree trunks and misaligned fences are common signs of creep, indicating that the ground beneath them is gradually moving downhill.

This type of mass movement is typically caused by the expansion and contraction of soil due to changes in temperature and moisture content, as well as the effects of gravity.

In contrast, rock fall, mudflow, and debris slide are all examples of more rapid and destructive forms of mass wasting, each with their own unique characteristics and causes.

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