A particle moves along the x-axis with velocity given by v(t)=8t-20v(t)=8tâ20 for time t\ge 0.tâ¥0. If the particle is at position x=1x=1 at time t=3,t=3, what is the position of the particle at time t=2?t=2?

Answer:

7.61 m/s

Explanation:

Given:

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s

71.6

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s

The time it takes for the car to go from 54 mi/h to 62 mi/h is: Total time = 43.1 s + 6.43 s = 49.53 s.

A car that can accelerate at a rate of 0.56 m/s2 can go from a speed of 54 mi/h to a speed of 62 mi/h within 10.8 seconds. We will use the following formula to solve this problem. vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time interval. Since we are dealing with different units (mi/h and m/s2), we will convert the initial and final velocities into m/s and use the same unit for acceleration.54 mi/h = 24.13 m/s62 mi/h = 27.73 m/sΔv = 27.73 - 24.13 = 3.6 m/st = Δv / a = 3.6 / 0.56 = 6.43 s Since the problem asks for the time interval it takes for the car to go from 54 mi/h to 62 mi/h, we need to find the time it takes for the car to accelerate from 54 mi/h to 62 mi/h.

To do that, we need to subtract the time it takes for the car to go from 0 mi/h to 54 mi/h from the total time it takes for the car to go from 0 mi/h to 62 mi/h. Using the same formula, we can find the time it takes for the car to go from 0 mi/h to 54 mi/h: vi = 0 mi/h = 0 m/svf = 54 mi/h = 24.13 m/sΔv = 24.13 - 0 = 24.13 m/st = Δv / a = 24.13 / 0.56 = 43.1 s Therefore, the time it takes for the car to go from 54 mi/h to 62 mi/h is: Total time = 43.1 s + 6.43 s = 49.53 s.

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Hello!!

For this, use the formula:

\(\boxed{I=V/R}\)

\(\textbf{Being:}\)

\(\sqrt{}\) \(I = Current = ?\)

\(\sqrt{}\) \(V = Voltage = 160 \ V\)

\(\sqrt{}\) \(R = Resistance = 10\ \varOmega\)

\(\textbf{If we replace and resolve it}\)

\(I = 160\ V / 10\ \varOmega\)

\(I = 16\ A\)

\(\text{The current of that circuit is \textbf{16 Amperes}}\)

The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

Where;

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Answer: 1.72J

Just figured this out a while ago

The correct conductor ampacity for a 10-horsepower, 230-volt, single-phase motor is option c. 62.5 A.

The ampacity of a conductor is a measure of the maximum amount of electrical current that can flow through it safely. The ampacity required for a motor is based on the size of the motor and the voltage of the electrical system. There are standard methods for determining the minimum ampacity for a given motor and voltage, such as the National Electric Code (NEC) and the American National Standards Institute (ANSI). The NEC and ANSI both state that the minimum ampacity for a 10-horsepower, 230-volt, single-phase motor is 62.5 amperes. It's important to note that using a conductor with ampacity lower than the recommended one may cause the motor to overheat and fail, leading to damage or even fire hazard.

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Answer:

I'M SO SORRY I SAW THIS TOO LATE :<

Explanation:

im pretty sure it's falseeee, information would probably be accurate

Answer:

it is correct

Explanation:

Though no rounded numbers can be defined as accurate, if we were going by people's discovery, and research, we can define that the number, g = 9.8m/s^2, is accurate

The velocity (v) of a wave set up in a stretched string, caused by plucking it, can be described by the equation \(V = kF^x * l^y * m^z.\)

In this equation, F represents the tension in the string, l represents the length of the string, and m represents the mass of the string.

The exponents x, y, and z represent the respective powers to which the tension, length, and mass are raised. The values of x, y, and z depend on the specific characteristics of the string and the wave being produced.

The constant k represents the proportionality constant that relates the tension, length, and mass to the velocity of the wave. Its value is determined experimentally or can be derived from theoretical considerations.

This equation shows the dependence of the wave velocity on various parameters such as tension, length, and mass. By adjusting these parameters, we can manipulate the wave velocity in the string, thereby affecting the properties of the wave, such as frequency and wavelength.

Therefore, It is important to note that the specific values of x, y, and z, as well as the constant k, would need to be determined through experimentation or derived based on the specific properties of the string and the wave under consideration.

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(a) The charge of the ion is determined as 2.76 x 10⁻¹³C.

(b) The potential difference between the oil droplet’s starting point and end point is 16.28 V.

The charge of the ion is calculated as follows;

W = Fdsinθ

F = W/dsinθ

F = (3.9 × 10⁻¹²)/(0.022 x sin120)

F = 2.046 x 10⁻¹⁰ N

E = F/q

q = F/E

q = (2.046 x 10⁻¹⁰)/(740)

q = 2.76 x 10⁻¹³C

E = V/d

V = Ed

V = 740 x 0.022

V = 16.28 V

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Answer:

We can find out a direction by freely suspending a bar magnet. We will find that freely suspended bar magnet always comes to reset in a North- South direction.

Explanation:

a) Mutual inductance = 0.108 H; Coupling coefficient = 0.482. b) - 4.95 V.


a) Mutual inductance, M between coil A and coil B can be given as:

M = k√(L_AL_B) here, k is the coupling coefficient, L_A and L_B are the inductances of the coil A and coil B respectively. Since 54% of flux produced by coil A links coil B,

So, K = 0.54

L_A = N_A Φ/I_AL_A

= 8120 × 0.02/6

= 27.07 mH

L_B = N_B Φ/I_BL_B

= 11842 × 0.078/6

= 154.63 mH

M = k√(LALB) = 0.482 × √(27.07 × 0.15463) = 0.108 H

b) The emf induced in coil B can be given as:-

ε = M (dI_B/dt)/L_B

ε = 0.108 × (-6/0.015) / 0.15463 = -4.95 V

Thus, the emf induced in coil B when the current is reversed in 0.015 seconds is -4.95 V.

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Given :

A cell of e.m.f  1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.

To Find :

The current in the circuit.

Solution :

We know, resistance of the ammeter is in series with the circuit.

So, total resistance is :

R = 2.5 + 0.5 ohm

R = 3 ohm

Also, e.m.f applied is 1.5 V .

Now, by ohm's law :

\(I = \dfrac{V}{R}\\\\I = \dfrac{1.5}{3}\\\\I = 0.5 \ A\)

Therefore, the current in the circuit is 0.5 A.

What is the SI (metric) unit of FORCE?

with symbol ( N )

All the best !

Answer:

B, Newton,

Explanation:

B.  Newton defined as the Force which when applied to 1 Kg mass produces an acceleration of 1 m/s/s.

F = m * a.

Answer:

According to my calculations it equals to 16 pints

Explanation:

You know that there is a calculator online for this stuff right?

The wavelength of the standing wave at fourth harmonic is; λ = 0.985 m and the frequency of the wave at the calculated wavelength is; f = 36.84 Hz

Given Conditions:

mass of string; m = 0.0133 kg

Force on the string; F = 8.89 N

Length of string; L = 1.97 m

1. To find the wavelength at the fourth normal node.

At the fourth harmonic, there will be 2 nodes.

Thus, the wavelength will be;

λ = L/2

λ = 1.97/2

λ = 0.985 m

2. To find the velocity of the wave from the formula;

v = √(F/(m/L)

Plugging in the relevant values gives;

v = √(8.89/(0.0133/1.97)

v = 36.2876 m/s

Now, formula for frequency here is;

f = v/λ

f = 36.2876/0.985

f = 36.84 Hz

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The acceleration of a counterclockwise-rotating object would be beneficial.

Rotational Kinematics: The angular acceleration units are either rad/s2 or (rad/s)/s. If the value of grows, then is positive. If is negative, then is decreasing. Keep in mind that, by convention, the positive direction is counterclockwise, and the negative direction is clockwise.

As a result, the angular acceleration is positive if a rigid body is rotating counterclockwise and experiences a positive torque. The relationship between torque, moment of inertia, and rotational kinematics is explained by Equation 10.25, which is Newton's second law for rotation. The equation for rotational dynamics is the name given to this.

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Among the reasons for the frequent use of composite measures is that they give a more comprehensive and accurate indication of a given variable. Besides, the researcher is seldom able to develop in advance single indicators of complex concepts. A single data item might not have enough categories to provide a range of variation. And lastly, they are efficient data reduction devices.

So, the correct answer is option (e) all of these choices.

Composite measures are used to combine several variables or scores into a single measurement or index. In other words, they are multidimensional measurement tools. It is useful to make this kind of index because it is possible to calculate the reliability and validity of composite measures, which are statistical measures that indicate whether or not the measurements were conducted accurately or are otherwise legitimate.

For example, if a researcher wants to assess the economic development of a country, he/she could create a composite measure by combining data on GDP per capita, literacy rates, and poverty rates. In this case, each of the three variables reflects a different aspect of economic development.

So, the correct answer is E.

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The surface charge density can be obtained from;

Surface charge density = Charge / Area

The question is incomplete but I can say something about how to calculate the surface chnarege density.

To calculate the surface charge density on a face of a penny, we need to know the charge on that face and the area of the face. Assuming that the penny is uniformly charged, we can calculate the surface charge density using the following formula:

Surface charge density = Charge / Area

To determine the charge on the penny face, we need to know the net charge on the entire penny. Let's assume that the penny has a net charge of Q.

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(a) The motor's line and phase currents:

Given:

Power output, P = 300 Nm × 2π × 1470 rev/min × (1/60) = 21950.6 W

Total losses, PT = 4327 W

Power input, P = Pout + PT = 21950.6 + 4327 = 26277.6 W

Apparent power, S = P/power factor = 26277.6/0.85 = 30856 VA

Supply voltage, V = 6 kV

Line voltage, VL = V/√3 = 6000/√3 = 3464.1 V

Phase voltage, VP = VL/√3 = 3464.1/√3 = 2000 V

The phase current, I = S/VP = 30856/2000 = 15.428 A

Total line current, IL = √3I = √3 × 15.428 = 26.758 A

Line current, I = IL/2 = 26.758/2 = 13.379 A

Therefore, the motor's line current is 13.379 A, and the phase current is 15.428 A.

(b) The rotor winding losses:

Stator winding losses, Ps = 4327 W

Iron losses = Total losses - (Stator winding losses + Rotor winding losses)= 4327 - Rotor winding losses

Rotor winding losses are also called copper losses.

Rotor copper losses, PR = I²RWhere R = Rotor winding resistance (for given conditions)

Rotor current, IR = rotor output/torque= 21950.6/(2π × 1470/60) = 222.06 A

Therefore, PR = 222.06² × R = 49.273R

So, the rotor winding losses are 49.273R.

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The cable will stretch by 4 mm when a 10 kg mass is hung from a 2 m length of the same cable. The answer is E) 4 mm.

Assuming that the cable obeys Hooke's law (i.e., the force required to stretch or compress the cable is proportional to the amount of stretch or compression), we can use the following equation to find the amount by which the cable will stretch when a 10 kg mass is hung from a 2 m length of the same cable:

ΔL = (F * L) / (A * E)

where:

ΔL is the amount of stretch, measured in meters (m)

F is the force applied to the cable, measured in newtons (N)

L is the original length of the cable, measured in meters (m)

A is the cross-sectional area of the cable, measured in square meters (m^2)

E is the Young's modulus of the cable material, measured in pascals (Pa)

We can assume that the cross-sectional area and Young's modulus of the cable are the same in both cases.

In the first case, a 10 kg mass is hung from a 1 m length of the cable, causing it to stretch by 2 mm (0.002 m). The force applied to the cable is:

F = m * g = 10 kg * 9.81 m/\(s^2\) = 98.1 N

Substituting the values into the equation, we get:

0.002 m = (98.1 N * 1 m) / (A * E)

In the second case, a 10 kg mass is hung from a 2 m length of the same cable. The force applied to the cable is still:

F = m * g = 10 kg * 9.81 m\(/s^2\) = 98.1 N

Substituting the values into the equation, we get:

ΔL = (98.1 N * 2 m) / (A * E)

Dividing the second equation by the first equation, we can eliminate the unknowns A and E:

ΔL / 0.002 m = [(98.1 N * 2 m) / (A * E)] / [(98.1 N * 1 m) / (A * E)]

Simplifying, we get:

ΔL / 0.002 m = 2

Multiplying both sides by 0.002 m, we get:

ΔL = 0.004 m = 4 mm

Therefore, the cable will stretch by 4 mm when a 10 kg mass is hung from a 2 m length of the same cable. The answer is E) 4 mm.

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Answer:

1m

Explanation:

The conversion is 1mm = 0.001m. So all we need to do to find how many mm there are in a meter, all we need to do is divide by a 1000;

1000 / 1000 = 1m

Best of Luck!

Answer: 37 Celsius and 310.15 K

Explanation:

C/5 = (F-32)/9 = (98.6-32)/9 = 66.6/9 = 7.4

C = 7.4 * 5 = 37 so the temperature is 37 Celsius

K = C + 273.15 = 37 + 273.15 = 310.15 K

The force of friction acting on him is 122 N. The correct answer is option C

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is  \(F_{r}\) = μN

\(F_{r}\) = 0.15 x 813.4

\(F_{r}\) = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

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The final eqilibrium tempreture of the tin water mixture, given that the was initially at 10 °C is 18.5 °C

The equilibrium temperature of the tin and water mixture can be obtained as follow:

From calorimetry, we understood that:

Heat loss = Heat gain

MC(T - Tₑ) = MᵥᵥC(Tₑ - Tᵥᵥ)

Inputting the various parameters, we have:

0.225 × 230 (97.5 - Tₑ) = 0.115 × 4184(Tₑ - 10)

51.75(97.5 - Tₑ) = 481.16(Tₑ - 10)

Clear bracket

5045.625 - 51.75Tₑ = 481.16Tₑ - 4811.6

Collect like terms

5045.625 + 4811.6 = 481.16Tₑ + 51.75Tₑ

9857.225 = 532.91Tₑ

Divide both side by 532.91

Tₑ = 9857.225 / 532.91

Tₑ = 18.5 °C

Thus, from the above calculation, we can conclude that the equilibrium temperature is 18.5 °C

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Answer:

The force is Centripetal force

Answer:

Conditions under which the belt and pulleys are operating – The friction between the belt and pulley may decrease substantially if the belt happens to be muddy or wet, as it may act as a lubricant between the surfaces.

Explanation:

I hope that this would be helpful

If the truck is moving with the same velocity, if the mass is cut in half then the momentum of the truck will also reduce to half.

The momentum of a body can be described as the function of the object's mass and velocity. Momentum (p) can be determined as kinetic energy and is the product of velocity (v) and mass (m).

The momentum of an object can be determined from the mathematical formula:

p = m×v

The momentum of an object is conserved and can be equal to zero if the object is stationary and its velocity of an object is zero.

Given, the truck has a momentum, p = 5000 units

Given that the mass of the truck is reduced to half. Then the new mass of the truck is equal m/2.  If the truck is still moving with the same velocity then the momentum is equal to:

p' = m' ×v

p' = (m/2) ×v

p' = mv/2

p' = p/2

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