A particle starts from rest and moves with a constant acceleration of 0.5m/s . Calculate the time taken by the particle to cover a distance of 25m
Answers
Answer:
t=10s
Explanation:
Use equation d=v1*t + 1/2a*t^2
Now rearrange for t
We also know that v1 is zero so that part v1*t will be canceled since its zero
d= 1/2 *a*t^2
dx2=at^2
d*2/a=t^2
^1/2 means square root
(d*2/a)^1/2 = t
Now plug in values
(2x25m/0.5m/s^2) ^1/2= t
(50/0.5)^1/2=t
(100)^1/2=t
+10s, -10=t
we will take +10s ofc.
Related Questions
Net Force (N) = 5. 0
Mass (kg) = 2. 5
What is acceleration?
Answers
The acceleration of the object is 2.0 m/s². This means that for every second the object is in motion, its velocity will increase by 2.0 meters per second.
The given information is the net force (N) = 5.0 and the mass (kg) = 2.5. We need to determine the acceleration.
Acceleration is the rate at which an object's velocity changes over time.
It is directly proportional to the net force applied to the object and inversely proportional to its mass.
The formula to calculate acceleration is:
Acceleration = Net Force / Mass
Now, let's substitute the given values into the formula:
Acceleration = 5.0 N / 2.5 kg
Simplifying the equation:
Acceleration = 2.0 m/s²
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You would like to confirm Netwon's second law by running an experiment. You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude?
Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
There is some other force present. This additional force is different for the two objects and accounts for the fact that the objects land at different times.
Newton's second law is not relevant in determining when an object will land on the ground.
One object must be heavier than the other and must therefore experience a greater gravitational acceleration.
Answers
Answer:
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
Explanation:
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
I do not understand it or even where to start
Answers
a) The speed of the Santa Claus is 0.056 m/s
b) The percentage of the speed of the Santa Claus to the speed of the light is 1.9 * 10^ -8 %.
What is the speed?We know that the speed has to do with the ratio of the distance to the time that has been taken. It is worthy of mention that the speed that we are talking about here is a scalar quantity and the implication of this is that the direction of the quantity does not need to be mentioned as we are trying to solve the problem that we have at hand in the question that has been asked to us here.
We know that;
Distance covered by the Santa Claus = 4850 m/ 24 * 60 * 60
= 4850 m /86,400
= 0.056 m/s
We already know that the speed of light as we have it would be 3 * 10^8 m/s
The ratio of the speed of the Santa Claus to the speed of light is;
0.056 m/s/3 * 10^8 m/s * 100/1
= 1.9 * 10^ -8 %
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54. the current in the rl circuit shown here increases to 40% of its steady-state value in 2.0 s. what is the time constant of the circuit?
Answers
The time constant of the circuit is 3.92s.
In a circuit, what is RL?A type of circuit known as an RL Circuit (resistor-inductor circuit), also known as an RL Network or an RL Filter, consists of a pair of inductors and resistors and is typically powered by an external source. As a result, an RL circuit consists of an inductor and a resistor connected in either series or parallel fashion.
During charging, the expression of current through the resistor in the RL-circuit shows that
I(t) = I₀ (1-\(e^{1/t}\))
10=4(1-0²)
Here I₀ is maximum current through resistor,τis time constant and t is time.
Time constant of the circuit is calculated as follows,
Substitute 0.40I₀, for I (t) and 2.0 s for t in above current equation,
0.40I₀= I₀ (1-\(e^{-2.0x/r}\))
0.40 = 1-\(e^{-2.0x/r}\)
\(e^{-2.0x/r}\) = 0.60
Take natural log both side
-2.0 s/τ = In (0.60)
-2.0 s/τ = -0.51
τ = 3.92 s
Hence time constant of the circuit is 3.92s.
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Which practice is an unsustainable way of managing resources?
Please help
Answers
Answer:
I would say it is recycling nonrenewable minerals instead of throwing them away.
Explanation:
using grocery bags only once before disposing them is also bad, but plastic is not really a resource compared to how minerals are resources.
if we recycle nonrenewable resources instead of throwing them away we would damage true resources.
The mass of the Sikorsky UH-60 helicopter is 9300 kg. It takes off vertically at t = 0. The pilot advances the throttle so that the upward thrust of its engine (in kN) is given as a function of time in seconds by T=100+t2.
A.) How fast is the helicopter rising 3 s after it takes off?
B.) How high has it risen 3 s after it takes off?
Answers
The helicopter is rising at a rate of 0.0192 m/s after 3 seconds.
The helicopter has risen to a height of 43.9 m after 3 seconds.
A) To find the rate at which the helicopter is rising after 3 seconds, we need to calculate its acceleration using the formula:
a = F_net / m
where F_net is the net force acting on the helicopter, and m is its mass.
The net force is the difference between the upward thrust and the weight of the helicopter:
F_net = T - mg
where T is the upward thrust, g is the acceleration due to gravity (9.81 m/\(s^2\)), and m is the mass of the helicopter.
Substituting the given values, we get:
F_net = (100 + \(3^2\)) kN - 9300 kg x 9.81 m/\(s^2\) = 178.7 kN
a = F_net / m = 178.7 kN / 9300 kg = 0.0192 m/\(s^2\)
Therefore, the helicopter is rising at a rate of 0.0192 m/s after 3 seconds.
B) To find the height the helicopter has risen after 3 seconds, we need to integrate its velocity from t=0 to t=3, and add the initial height (which is zero):
v = ∫ a dt = ∫ (100 + \(t^2\)) / m - g dt
v = (100/9300)t + (1/3)(1/9300)\(t^3\) - 9.81t + C
At t=0, v=0, so C=0.
Substituting the given values, we get:
v = (100/9300)t + (1/3)(1/9300)\(t^3\) - 9.81t
∫v dt = h = ∫ [(100/9300)t + (1/3)(1/9300)\(t^3\) - 9.81t] dt
h = (50/9300)\(t^2\) + (1/12)(1/9300)\(t^4\) - 4.905\(t^2\) + C
At t=0, h=0, so C=0.
Substituting t=3 seconds, we get:
h = (50/9300)(\(3^2\)) + (1/12)(1/9300)(\(3^4\)) - 4.905(\(3^2\)) = 43.9 m
Therefore, the helicopter has risen to a height of 43.9 m after 3 seconds.
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a car has a mass of 200kg. It is on a hill 1000m high. How much gravitational potential energy does the car have?
Answers
Answer:
Explanation:
PE = m * g * h
m = 200 kg
h = 1000 m
g = 9.81
PE = 200 * 9.81 * 1000
PE = 1962000 Joules
What is the main advantage multistage
rockets have over conventional rockets?
A. They collect additional fuel cells as they increase inaltitude.
B. They are less complex.
C. They are easier to build.
D. They get lighter by dropping empty sections that held fuel.
Answers
The main advantage multistage rockets have over conventional rockets is they get lighter by dropping empty sections that held fuel. So, option D is the correct answer.
Multistage rockets have an advantage over conventional rockets since they are outlined to drop off empty segments that held fuel as the rocket gains height. This diminishes the weight of the rocket, making it less demanding to realize elude speed and reach the circle. As each organizes is utilized, it is discarded, diminishing the general weight of the rocket and making it more effective.
Multistage rockets are more flexible and can be utilized for a more extensive extend of missions. They can be custom fitted to meet the particular necessities of a mission by including or evacuating stages, which permits them to carry payloads to diverse heights and speeds. In differentiation, conventional rockets carry all of their fuel and engines with them through the complete mission, making them heavier and less proficient.
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Discovering outer space had been an ancient goal of humanity. The first rocket launched ever was by the
American college professor and scientist Robert Goddard who built and flew the world's first liquid propellant
rocket on March 16, 1926. Its flight, though unimpressive (it climbed only 12.5 meters), was the forerunner of
the Saturn V Moon rocket 43 years later. Answer the following question using your math and science skills.
While launching a rocket into space, the rocket thrust (force) is calculated to be 20,000 N.
OOD
a) The mass of the rocket is approximately 3,000 kg, what would be the acceleration of the launched rocket?
b) The rocket starts from rest, what would be the final speed after 5 min?
Answers
The earliest known observations of the night sky date back to ancient civilizations such as the Babylonians, Egyptians, and Chinese, who recorded the positions of stars, planets, and other celestial bodies.
Explain about goal of humanity:Discovering outer space has been a goal of humanity for centuries. Throughout history, people have looked to the stars with a sense of wonder and curiosity, trying to understand the nature of the universe. a) To calculate the acceleration of the launched rocket, you can use the formula:However, it wasn't until the 20th century that humans were able to physically explore space. With the development of rocket technology, scientists were able to launch spacecrafts beyond Earth's atmosphere, allowing for the study of celestial bodies and the exploration of the Solar System and beyond.a = F / m
where F is the force (thrust) acting on the rocket and m is the mass of the rocket.
In this case, F = 20,000 N and m = 3,000 kg
So, a = 20,000 N / 3,000 kg = 6.67 m/s²
b) To calculate the final speed of the rocket after 5 minutes, you can use the formula:
v = a * t
where v is the final speed, a is the acceleration and t is the time.
In this case, a = 6.67 m/s² and t = 5 minutes = 300 seconds.
So, v = 6.67 m/s² * 300 seconds = 2,001 m/s
It's worth noting that the acceleration and final speed calculations are assuming that the rocket thrust is constant during the entire flight, which is not the case in reality, thrust changes during different stages of the rocket's flight.To learn more about goal of humanity refer to:
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The mass of 50 cm cube milk is 51.5 g find the density of milk in gcm cube
Answers
Answer:1.03 g/cm³
Explanation:To find the density of milk, we need to divide the mass of the milk by its volume.
Given:
Mass of milk = 51.5 g
Volume of milk = 50 cm³
Density = Mass / Volume
Density = 51.5 g / 50 cm³
Density = 1.03 g/cm³
formula for density is d = M/V, where d is density, M is mass, and V is volume, hence if M = 51.5 g and V = 50 cm³
\(d = \frac{m}{v} \\ d = \frac{51.5}{50} = 1.03 \frac{g}{cm³} \)
Un muelle se alarga 5 cm, cuando de él se cuelga una masa de 1000 gr. Colocamos después este muelle unido a una masa de 500 g sobre una mesa horizontal sin rozamiento. La masa se separa 3 cm de su posición de equilibrio y se deja vibrar sobre el eje horizontal. Calcular:
a) La fase inicial y la amplitud del movimiento.
b) La elongación y la velocidad en el instante t = 0,5 s
c) La velocidad angular
d) El periodo
e) la constante de recuperación del resorte;
f) El valor máximo de la velocidad.
g) la energía potencial en el punto de máxima deformación en horizontal;
h) La energía cinética cuando x = 2 cm;
i) La aceleración de la partícula 0,25 s después de iniciado el movimiento
j) la velocidad cuando el tiempo es de 1 seg
Answers
La expresión del movimiento armónico simple permite encontrar los resultados para las preguntas sobre el movimiento de la masa y el resorte son:
a) La fase inicial es cero y la amplitud es 0,05 m
b) La elongación y velocidad para el tiempo dado son:
x = -0,0445 m y v = -0,0229 m/s
c) La velocidad angular es: w = 19,8 rad/s
d) El periodo vale T = 0,317 s
e) La constante de resorte es: k = 196 N/m
f) La velocidad máximas es: v= 0,99 m/s
g) La energia potencial es: Ep = 0,245 J
h) La energía cinética es: K = 0,2058 J
i) La aceleración es: a = -4,61 m/s²
j) La velocidad es: v= -0,806 m/s
.Movimiento armónico simple
El movimiento oscilatorio ocurre cuando hay un fuerza recuperadora en el sistema, si tea fuerza es proporcional al desplazamiento el movimiento se denomina armónico simple y es descrito por la expresión.
x= A cos (wt +Ф)
w² = k/m
Donde x es el desplazamiento, A la amplitud del movimiento, w la velocidad angular, t el tiempo, fi una constante de fase que se determina con los valores iniciales, k la constante del resorte y m la masa.
e) Indican el desplazamiento de x= 5 cm = 0,05 m para una masa de m= 1000 g = 1 kg. Usemos la condición de equilibrio y la ley de Hooke para encontrar la constante del resorte.
W = F
mg = k x
\(k = \frac{mg}{x}\)
Calculemos.
k = \(\frac{1 \ 19.8}{0.05}\)
k = 196 N/m
c) indican la masa aplicada para el movimiento es m= 0,5 kg , podemos buscar la velocidad angular
w= \(\sqrt{ \frac{k}{m}}\)
w = \(\sqrt{ \frac{196}{0.5} }\)
w = 19,8 rad/s
a) La fase y la mplitud.
La amplitud es la elongación máxima del movimiento
A = 0,05 m
para la fase usamos que el bloque se suelta, por lo cual el tiempo es cero t=0 ,desde la posición de máxima elongación v= 0, usemos la relación entre la posición y la velocidad.
v= \(\frac{dx}{dt}\)
v = -A w sin (wt +Ф)
0 = - A w sin Ф
Por lo tanto fi debe ser cero, para que la función seno ea cero.
Ф =0
b) Calculamos para t=0,5 s la elongación y la velocidad.
La ecuación del movimiento queda.
x = A cos wt
Calculamos.
Recuerda que los ángulos están en radianes.
x = 0,05 cos 19,8 0,5
x = -0,0445 m
La velocidad es:
v = 0,05 19,8 sin 19,8 0,05
v = -0,0229 m/s
d) La velocidad angular esta relacionada con el periodo.
W = \(\frac{2\pi}{T}\)
T = \(\frac{2\pi}{w}\)
T = \(\frac{2\pi}{19.8}\)2pi/19,8
T = 0,317 s
f) El valor máximo de la velocidad.
Este valor ocurre cuando la función seno vale 1
v =Aw
v= 0,05 19,8
v= 0,99 m/s
g) La energía mecánica del sistema se mantiene constante porque no hay fuerzas de roce, por lo tanto en el punto de máxima elongación la energía es totalmente potencial.
U = ½ k A²
U = ½ 196 0,05²
U = 0,245 J
h) la energía cinética para x=2 cm = 0,02 m
En todos los puntos la energía mecánica es la suma dela energía cinética mas la enriar potencial
Em₀ = K + U
K = Em₀ – U
K = ½ k ( A² -x² )
K = ½ 196 ( 0,05² – 0,02² )
K = 0,2058 J
i) La aceleracion y la velocidad están relacionadas
a = \(\frac{dv}{dt}\)
a = - A w² cos wt
a = - 0,05 19,8² cos 19,8t
a = -19,6 cos 19,8 t
a = - 19,8cos 19,8 0,25
a = -4,61 m/s²
j) La velocidad para t=1 s.
v= - A w sin wt
v = - 0,05 19,8 sin 19,8 1
v= -0,806 m/s
En conclusión con la expresión del movimiento armónico simple podemos encontrar los resultados para las preguntas sobre el movimiento de la masa y el resorte son:
a) La fase inicial es cero y la amplitud es 0,05 m
b) La elongación y velocidad para el tiempo dado son:
x = -0,0445 m y v = -0,0229 m/s
c) La velocidad angular es: w = 19,8 rad/s
d) El periodo vale T = 0,317 s
e) La constante de resorte es: k = 196 N/m
f) La velocidad máximas es: v= 0,99 m/s
g) La energia potencial es: Ep = 0,245 J
h) La energía cinética es: K = 0,2058 J
i) La aceleración es: a = -4,61 m/s²
j) La velocidad es: v= -0,806 m/s
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Why does the force of gravity increase when one object gets closer to another object?
Answers
Answer:
because the gravity gets stronger as the 2 objects get closer. so the 2 are basicly merging
Explanation:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
hope this helps!
FUN FACT: we achaly all have gravity, its just so weak that we cant feel it.
And PLEASE NO SCAMED WHAT IS WRONG AND WHAT IS RIGHT PLZZ HELP AND DO IT IN YOUR OWN WORDS BECAUSE MY TEACHER WILL KNOW AND HE WILL FLAGGED ME AND YES I AM N FLVS Science 6th grade so my teacher said i made a excellent hypothesis, recorded my data clearly, identified your variables accurately, analyzing how friction changes based on the surface texture. but what was wrong that i needed to add the total distance traveled for all 3 trials on each surface and then divide by 3 to get the average for each surface texture....
Procedures (4 points)
In this section please list ALL materials you used to complete your experiment, summarize the steps you took to complete the experiment and describe any difficulties or errors you encountered.
If an object rolls over (choose one type of material you used), then it will travel (choose one: the farthest distance/the shortest distance).
If the ball rolls over the carpet then It will travels the farthest distance.
For this lab I used the following materials: ball, books, carpet, floor tile, towel, ruler.
Short summary of what I did: (use words like first, next and last) First I stacked my books, Next I put my ruler next to the book last I put my ball on the top of the books and I let it roll down.
I experienced the following errors while doing my experiment: when I rolled the ball on the carpet it stopped at different centimeters per trial.
Test Variable/Independent Variable:
HINT: What was different about your test groups? What did you choose to test?
The difference about the test groups is they flooring, One was Carpet, Other Tile and Table.
I choose to test the ball if it were to stop at the same spot.
Outcome Variable/Dependent Variable:
HINT: What were you measuring? What data did you record?
I measure the ball rolling down the carpet, tile and table which provided me different data for each measuring.
Distance Object Traveled (in centimeters)
Floor Surface
Trial 1
Trial 2
Trial 3
Carpet
30cm
60cm
90cm
Tile floor
13cm
26cm
39cm
table
18cm
18cm
30cm
Floor Surface
Calculation of the Average (show your work)
Average Distance Traveled (answer)
carpet
30+30+30
90
Tile flloor
13+13+13
39
Table
18+18+18
54
Describe in your own words what friction is.
Friction is a force that opposes motion. Friction is basically the resistance of an object rubbing against another, such as a ball rolling down a hill, friction slows it down when rubbed against the grass.
Describe how friction affected the results of your investigation.
Friction slows down the ball if there no friction then it will make the object continue moving without slowing down.
Does an object travel farther on a smooth or slippery surface or on a rough surface? Why?
The object will travel on a slippery surface farther because when it slippery there no friction so it will travel faster.
Propose another experiment that could be used to demonstrate that friction is a contact force.
A hula hoops will twirl around you and it will stay in the air However it will have in upward force on your hips.
Answers
Answer:
just rry
Explanation:
pweese help one more timeeee
pweese look at the image below
Answers
Answer:
increasing; speeding up is my answer
In terms of π, what is the length of an arc
which subtends an angle of 30° at the centre
of a circle of radius 3 cm?
Answers
Answer:
Since 2 pi = 360 deg and pi equals 180 deg, 30 deg = pi / 6.
S = theta * R = pi / 6 * 3 cm = 1.57 cm
Question Based on the following information, which of the following runners has a higher velocity? Runner A: Stride length 3.1 m; Stride rate 2.7 s −1
. Runner B: Stride length 2.3 m; Stride rate 3.5 s −1
Select one: a. There is not enough information to tell b. Runner B had a higher velocity c. Runner A and B are equal in velocity d. Runner A had a higher velocity
Answers
Based on the given information, Runner A has a higher velocity than Runner B.
Velocity is defined as the rate of change of displacement with respect to time. It can be calculated by multiplying the stride length by the stride rate.
For Runner A, the stride length is 3.1 m and the stride rate is 2.7 s^(-1). Therefore, the velocity of Runner A is 3.1 m * 2.7 s^(-1) = 8.37 m/s.
For Runner B, the stride length is 2.3 m and the stride rate is 3.5 s^(-1). Therefore, the velocity of Runner B is 2.3 m * 3.5 s^(-1) = 8.05 m/s.
Comparing the velocities, we can see that Runner A has a higher velocity (8.37 m/s) compared to Runner B (8.05 m/s). Thus, the correct answer is d. Runner A had a higher velocity.
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You performed an experiment in which you measured the amount of water leaking through different types of roofs. For one roof, you measured a volume of 13.2 ounces. What is this measurement in SI units? 1 lb = 16 oz; 1 kg = 2.2 Ibs.
Answers
The measurement of 13.2 ounces is 0.375 kg in SI units.
To convert 13.2 ounces to SI units, we need to convert it to kilograms since the SI unit for mass is kilograms (kg).
Given:
1 lb = 16 oz
1 kg = 2.2 lbs
First, let's convert 13.2 ounces to pounds:
13.2 oz * (1 lb / 16 oz) = 0.825 lbs
Now, let's convert pounds to kilograms:
0.825 lbs * (1 kg / 2.2 lbs) ≈ 0.375 kg
Therefore, the measurement of 13.2 ounces is approximately 0.375 kg in SI units.
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a bearker a with 250ml of water and baker b is with 500ml of water are wermed from 10 degree celsius to 20degree celsius how your work
Answers
beaker B absorbs twice as much heat energy as beaker A due to having twice as much water.
StepsTo calculate the amount of heat energy absorbed by the water in the two beakers, we can use the formula:
Q = mcΔT
where Q is the amount of heat energy absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
For beaker A with 250 mL of water, we first need to convert the volume to mass using the density of water, which is 1 g/mL. So, the mass of water in beaker A is:
m = 250 mL × 1 g/mL = 250 g
The specific heat capacity of water is 4.18 J/g·°C. Therefore, the amount of heat energy absorbed by the water in beaker A is:
Q = 250 g × 4.18 J/g·°C × (20°C - 10°C) = 10,450 J
For beaker B with 500 mL of water, the mass of water is:
m = 500 mL × 1 g/mL = 500 g
Using the same specific heat capacity of water, the amount of heat energy absorbed by the water in beaker B is:
Q = 500 g × 4.18 J/g·°C × (20°C - 10°C) = 20,900 J
Therefore, beaker B absorbs twice as much heat energy as beaker A due to having twice as much water.
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where should the center of gravity of this additional mass be located? express your answer with the appropriate units.
Answers
The center of gravity of the additional mass should be located at the weighted average of the individual centers of mass. This location ensures that the object or system remains in balance and maintains its stability.
Steps to determine the center of gravity of this additional mass
1. Identify the object: First, identify the object or system for which you need to find the center of gravity.
2. Locate the individual masses: Locate the individual masses within the object or system, including the additional mass.
3. Calculate the individual centers of mass: Determine the individual centers of mass for each component of the object, including the additional mass, based on their geometric shapes and density distributions.
4. Calculate the total mass: Add up the masses of all the components, including the additional mass, to obtain the total mass of the object or system.
5. Determine the center of gravity: Calculate the weighted average of the individual centers of mass by multiplying each center of mass by its corresponding mass and then dividing the sum by the total mass.
The center of gravity of the additional mass should be located at the weighted average position calculated in Step 5.
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Fill in the blank to correctly complete the sentence. If n represents any integer, then an expression representing all angles coterminal with 60° is 60° + If n represents any integer, then an expression representing all angles coterminal with 60° is 60° +1° (Type an equation using n as the variable.) Enter your answer in the answer box
Answers
If n represents any integer, then an expression representing all angles coterminal with 60° is 60° + n * 360°.
Coterminal angles are angles that have the same initial and terminal sides when measured in standard position. They differ by a multiple of 360°. In this case, we are looking for angles coterminal with 60°.
To express all angles coterminal with 60°, we can add any integer multiple of 360° to 60°. Since n represents any integer, we can use n as the multiplier of 360°. Therefore, the expression representing all angles coterminal with 60° is 60° + n * 360°.
For example, when n = 0, the expression gives us 60° + 0 * 360° = 60°, which is the original angle. When n = 1, we have 60° + 1 * 360° = 420°, which is coterminal with 60°. Similarly, for any other integer value of n, we can find angles that are coterminal with 60° using this expression.
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Which of the following are double-displacement reactions? multiple answers
A. 2H2(g) + O2(g) -> 2H2O(g)
B. Zn(s) + 2HCI(aq) -> H2(g) + ZnCI2(s)
C. Ba(OH)2(aq) + 2HCIO4(aq) -> Ba(CIO4)2(aq) + 2H2O(I)
D. HNO3 (aq) + KOH (aq) -> H2O(I) + KNO3 (aq)
Answers
Answer:
C and D
Explanation:
A: is a simple composition
B: is a single replacement
C: C is a double displacement
D: is a double replacement
Answer:
The answers are C abd D.
Explanation:
Here,
A no. Is a combination or analysis chemical reaction.
B no.is a single displacement reaction as cl2 goes to zn.
C no. Is double displacement reaction.
D no. Is a double displacement reaction.
Hope it helps.....
Part B Draw a free-body diagram of the car. Suppose that the car is moving to the right. Draw the vectors starting at the black dots. The location and orientation of the vectors will be graded. The length of the vectors will not be graded. O No elements selected f Select the elements from the list and add them to the canvas setting the appropriate attributes. Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining
Answers
Free-body diagram should have four vectors starting at the black dot: forward force (F) to the right, gravitational force (W) downward, normal force (N) upward, and friction force (f) to the left.
A free-body diagram is a visual representation of all the forces acting on an object. In this case, we need to draw a free-body diagram of the car that is moving to the right.
We start by placing a dot in the center of the car, which represents the center of mass of the car. Next, we draw vectors starting from the dot that represent the forces acting on the car. These forces include the force of gravity, which is pulling the car down towards the ground, and the force of friction, which is opposing the motion of the car and acting in the opposite direction to its movement. Additionally, there may be other forces acting on the car depending on the situation, such as air resistance or the force of the engine pushing the car forward.
1. Start with a simple representation of the car as a box.
2. Add a black dot to indicate the point where force vectors will be placed.
3. At the black dot, draw an arrow pointing to the right. This represents the forward force (F) propelling the car.
4. Also, add a downward arrow at the black dot, indicating the force due to gravity (W = mg) acting on the car.
5. Draw an upward arrow to represent the normal force (N) exerted by the ground, which counterbalances the gravitational force.
6. Finally, include a leftward arrow to show the friction force (f) opposing the car's motion.
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Please help, I'm taking a test mlnkhjbgvfgcfgvhb
What is the motion of the particles in this kind of wave?
A) The particles will move up and down over large areas.
B) The particles will move up and down over small areas.
C) The particles will move side to side over small areas.
D) The particles will move side to side over large areas.
Answers
Answer:
I think its A
Explanation:
Not 100 percent sure tho but they do go up and down in big movements.
A 2kg rock is moving at a speed of 6m/s. What constant force is needed to stop the rock in 7 x 10^-4?
Answers
Explanation:
key to this problem is the impulse-momentum theorem which states that the change in the momentum of an object is equal to the impulse applied into it.
J
=
Δ
p
,
where
J
is the impulse and
Δ
p
is the change in momentum. Basically, the impulse is the product of force and time duration, that is,
J
=
F
Δ
t
In this problem, the impulse would be the product of the force stopping the rock and
0.7
s
.
On the other hand, momentum
p
is the product of the mass
m
and velocity
v
. Therefore, the change in momentum is given by
Δ
p
=
m
2
v
2
−
m
1
v
1
.
Starting with the impulse-momentum equation, we have
J
=
Δ
p
F
Δ
t
=
m
2
v
2
−
m
1
v
1
Divide both sides by
Δ
t
,
we get
F
Δ
t
Δ
t
=
m
2
v
2
−
m
1
v
1
Δ
t
F
=
m
2
v
2
−
m
1
v
1
Δ
t
Finally, substitute the values and we get
F
=
(
2
kg
)
(
0
)
−
(
2
kg
)
(
6
m
s
)
(
0.7
s
)
F
≈
−
20
kg
m
s
2
Since
1
N
=
1
kg
m
s
2
,
then
F
≈
−
20
N
Therefore, using the correct significant figures (in this case, we need one significant figure since 2 kg, 6 m/s and 0.7 s all have one) in the final answer, we would need to have approximately
20
N
force to stop the rock in
0.7
s
.
Note: The negative sign is referring to the direction of the force opposite of the direction of the velocity
v
1
.
who was albert einstien describe his contributions???
Answers
Answer:
Albert Einstein was from Germany he was born theoritical physicist, from childhood only he loved mechanical toys, he was highly gifted in Mathematics, He was a world citizen and a scientific genius too. His contribution were:
1) he developed the theory of relativity
2) he also discovered the process of nuclear fission
3)he developed the quantum theory of specific heat
4)theory of stimulated emission, on which laser device technology is based
5) law of photoelectric effect
hope it helped you :)
which is not a general characteristic of starburst galaxies?
Answers
Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.
The starburst galaxy is also regarded as the free quantity of gas with which stars can be formed.They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.
See full question below
Which is not a general characteristic of starburst galaxies?
The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center. The observed features that us to classily a galaxy as a 'starburst" galaxy must be only temporaryphenomena in the galaxy' Supernovae occur so frequently that their effects combine to drive a galactic wind that blows material into intergalactic space. The galaxy's rate of star formation is many times higher than the rate of star formation in the Milky WayLearn more from
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Is the process of science described in this lesson similar to your initial ideas about how science is carried out? Explain why or why not.
Answers
The process of science followed my initial ideas e because it involved experiments.
What is the process of science?The process of science or the scientific method refers to the process which scientists follow in their discovery and explanation of natural phenomena.
The scientific method is given below:
making an observation,develop a hypothesis,making a prediction,conducting an experiment analyzing the resultspropound a lawThe process of science follows my initial ideas about the process of science because I always thought science involved experiments.
In conclusion, the process of science involves making hypothesis and conducting research.
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you are driving a combination vehicel when the trailer breaks away, pulling apart both air lines. you expect the trailer brakes to come on and:
Answers
If the trailer breaks away and pulls apart both air lines, it would result in a loss of air pressure in the trailer's braking system.
As a result, the emergency brakes on the trailer should activate automatically. This is because trailer brakes are typically designed to engage in such situations where there is a sudden loss of air pressure.
When the emergency brakes engage, it helps to bring the trailer to a stop and prevent it from freely rolling away. However, it's important to note that the braking effectiveness may vary depending on the specific design and condition of the trailer's braking system.
Additionally, the actions you should take in response to this situation would depend on various factors, such as the speed of the vehicle, the surrounding traffic conditions, and the availability of safe stopping options. In any case, it is crucial to prioritize safety and take appropriate measures to control the vehicle and ensure the safety of yourself and others on the road.
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PLEASE HELP WILL MARK BRAINLIEST IF YOU EXPLAIN HOW TOU GOT THE ANSWER!!!
A 15kg block is being pushed up a 20 degrees ramp that has a kinetic coefficient of 0.30. What is the pushing force if the acceleration of the block is 2.0m/s^2?
The answer is 121.7 N, I just need to know how to solve it.
Answers
Answer:
this is just and example of how to solve it
Explanation:
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A paved blacktop parking lot was built on what was
once a soil-covered field. This area will now
experience increased runoff when rain occurs because
the paved parking lot has
A) less capillarity B) less permeability
C) greater infiltration D) greater porosity
Answers
Answer:
The answer is B. less permeability.
Explanation: