a pebble is dropped from rest from the top of a tall cliff and falls 122.5 m after 5.0 s has elapsed. how much farther does it drop in the next 10.0 s?

So, 2200 metres were travelled, and 200 metres were moved.

The athlete will be in the exact opposite posture after his motion is finished. That is, 200 m equals 200 x diameter.

Multiplying the circle's diameter by (pi) yields the circumference of the circle. Additionally, the circumference may be determined by multiplying the 2radius by pi (=3.14).

Simply draw a vector from your beginning point to your destination location, solve for the length of this line, and you can determine displacement. If your beginning and finishing positions are identical, as they are if you are running a circular 5K course, your displacement is 0. Displacement in physics is symbolised by the symbol s.

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If the electronic configuration of an atom is 1s2 2s2 2p2 then it has 6 electrons.

This electronic configuration corresponds to carbon, whose atomic number is 6.

The electronic configuration is a form of organization by layers that the electrons have.

Its importance is based on the ability to determine through it the total properties of chemical combination of atoms, which is equivalent to their location on the periodic table of elements.

Furthermore, the electronic configuration of an element defines its binding energy and thus its state at room temperature.

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Answer: a bridge suspended by cables

Answer:

sound is made up of vibrations or sound waves that we can hear these sound waves are formed by objects

Answer:

Sound wave consists to vibrating particles.These knock into other particles causing them to vibrate,and so the sound can travel away from the source.You can hear sound because the vibration in the air cause your ear drums to vibrate this vibration is converted into signals which travel down a nerve to your brain.

Explanation:

hpe its help

The property of a system that enables it to do something or make something happen, including the capacity to do work is called energy.

Energy is the ability of a system to perform work or bring about change is represented by the fundamental idea of energy in physics. It has magnitude but no direction because it is a scalar quantity.

The principle of energy conservation states that energy can be changed from one form to another and that the overall energy of a closed system stays constant. Energy can, however, be converted or transported across various systems or objects, enabling movement or changes to take place.

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The wavelength and energy of light that has a frequency of 1.6 x 10¹⁵ Hz is 1.875 x 10⁻⁷ m and 10.6 x 10⁻¹⁹ J.

The distance between the adjacent crest or trough of the sinusoidal wave.

Given is the frequency f = 1.6 x 10¹⁵ Hz, the speed of the light c = 3 x 10⁸ m/s, then the wavelength will be

λ = c/f

Substitute the values, we get

λ =3 x 10⁸ /  1.6 x 10¹⁵

λ = 1.875 x 10⁻⁷ m

Energy of light E = hc /λ

Where h is the Planck's constant = 6.626 x 10⁻³⁴ J.s

Substitute the values in the energy expression, we get

E =(6.626 x 10⁻³⁴ x 3 x 10⁸) / 1.875 x 10⁻⁷

E =10.6 x 10⁻¹⁹ J

Thus, the wavelength and energy of the light of given frequency is 1.875 x 10⁻⁷ m and 10.6 x 10⁻¹⁹ J.

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Answer: Green Light

Explanation:

The color green has a higher frequency than the color red and the higher the frequency the more energy. If you looks at a rainbow you'll see red on one end and violet on the other. Red has the least energy Violet has the most.

Answer:

See below

Explanation:

I will assume each resistor is 120 ohms

  in series , the resistance just sums.... to 120 + 120 + 120 = 360 ohms

  in parallel they are   1 / (1/120 + 1/120 + 1/120) = 1/ (3/120) = 40 ohms

(a)The hydrostatic pressure on the bottom of the tank is 35,910 Pa

(b)The hydrostatic force on the bottom of the tank is 913,104 N

(c)The hydrostatic force on one end of the tank is 117.6 N

(a) Hydrostatic pressure on the bottom of the tank. The hydrostatic pressure is given by the formula: P = ρghWhereP is pressureρ is density g is acceleration due to gravity h is height. We are given: Length of the tank, l = 6 m Width of the tank, w = 4 m. Height of the tank, h = 5 m. Density of kerosene, ρ = 820 kg/m3Depth of kerosene, d = 4.5 m Acceleration due to gravity, g = 9.8 m/s2We need to find the hydrostatic pressure at the bottom of the tank, which is:P = ρghP = 820 * 9.8 * 4.5P = 35,910 Pa. Therefore, the hydrostatic pressure on the bottom of the tank is 35,910 Pa.

(b) Hydrostatic force on the bottom of the tank .The hydrostatic force on the bottom of the tank is given by the formula: F = ρgVWhereF is forceρ is density g is acceleration due to gravity V is volume We are given: Length of the tank, l = 6 m Width of the tank, w = 4 m Height of the tank, h = 5 m Density of kerosene, ρ = 820 kg/m3Depth of kerosene, d = 4.5 m Acceleration due to gravity, g = 9.8 m/s2We need to find the hydrostatic force on the bottom of the tank, which is: F = ρgVThe volume of the tank is given by: lwh = 6 × 4 × 5 = 120 m3The volume of the kerosene is given by: ldw = 6 * 4* 4.5 = 108 m3.The volume of the kerosene is less than the volume of the tank. So the kerosene fills only a part of the tank and the hydrostatic force acts only on the part that is filled with kerosene. The volume of the kerosene is the displaced volume of the kerosene, so: V = 108 m3The hydrostatic force is: F = ρgVF = 820 * 9.8 * 108F = 913,104 N. Therefore, the hydrostatic force on the bottom of the tank is 913,104 N.

(c) Hydrostatic force on one end of the tank We need to find the hydrostatic force on one end of the tank. The end that has dimensions of 4 m x 5 m. Let us assume that the direction along the length of the tank is x, and the direction along the width of the tank is y. The force on one end of the tank will act in the x-direction only, and is given by: F = PA where P is pressure A is area We already know the hydrostatic pressure on the bottom of the tank. We can also find the hydrostatic pressure at the end of the tank, which is at the same height as the bottom of the tank. The depth of kerosene at this end of the tank is given by:4.5 - 5 = -0.5 m. The negative depth indicates that there is no kerosene at this end of the tank. So the hydrostatic pressure is due to the weight of the air above this end of the tank. The hydrostatic pressure at this end of the tank is given by: P = ρghP = 1.2 * 9.8 * 0.5P = 5.88 Pa. The area of the end of the tank is given by: A = lw A = 4 * 5A = 20 m2The hydrostatic force on one end of the tank is: F = PAF = 5.88 * 20F = 117.6 N. Therefore, the hydrostatic force on one end of the tank is 117.6 N.

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The electromagnetic force and gravitational force are two of the four fundamental forces of nature. While the electromagnetic force is much stronger than the gravitational force on a small scale, it appears that gravity dominates on larger scales.

The electromagnetic force is strongest between electrically charged particles, while the gravitational force is proportional to the mass of objects. The electromagnetic force is approximately 10^36 times stronger than the gravitational force on the scale of single atoms and molecules. However, on larger scales, the gravitational force begins to dominate.

This is because the electromagnetic force is a long-range force that decreases rapidly with distance, while the gravitational force is a long-range force that decreases more slowly with distance. As a result, the total amount of gravitational force between two large objects like stars or planets is much greater than the total amount of electromagnetic force.

In summary, the electromagnetic force is much stronger than the gravitational force on a small scale, but it is overpowered by gravity on large scales due to the long-range nature of the gravitational force and its relatively slower decrease with distance.

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Where the angle of incidence equals the angle of reflection, resulting in a mirror image that is flipped both horizontally and vertically.

Correct answer is, all of the above

When an image is reflected in a plane mirror, it undergoes a complete inversion. This means that not only is the left side of the object reflected to the right side in the image, but the top side is reflected to the bottom side, and the front side is reflected to the back side.

A plane mirror creates a virtual image that appears to be the same distance behind the mirror as the object is in front of it. In this virtual image, the left and right sides are inverted, while the up-down and front-back orientations remain the same.

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Answer:

no

Explanation:

ans should be correct

The total distance traveled by the cyclist between 0 and 6.0 s is 37.435 m.

A motorcyclist who is moving along an x axis directed toward the east has an acceleration given by a = (6.1 - 2.0t) m/s2 for 0 t 6.0 s. At t = 0, the velocity and position of the cyclist are 3.1 m/s and 7.3 m. We can use the following kinematic equations of motion to solve the problem: v = u + at

Here, v, u, a and t represent final velocity, initial velocity, acceleration, and time, respectively. s = ut + 0.5 at²Here, s, u, a, and t represent displacement, initial velocity, acceleration, and time, respectively.

(a)To find the maximum speed of the cyclist, we first need to find the time at which the acceleration becomes zero. Therefore, 6.1 - 2.0t = 0⇒ t = 3.05s

Now, we can find the maximum speed using the kinematic equation: v = u + at= 3.1 + (-2.0 × 3.05)= -3.8 m/s

Therefore, the maximum speed achieved by the cyclist is 3.8 m/s.(b)Total distance covered by the cyclist between 0 and 6.0 s is given by the area under the velocity-time graph in the given interval.

The velocity of the cyclist as a function of time is given by the following equation: v = 3.1 + (6.1 - 2.0t)⇒ v = 3.1 + 6.1 - 2.0t⇒ v = 9.2 - 2.0t

So, we can draw a velocity-time graph using the above expression. We have, Taking the area under the curve between 0 to 6.0 s, we get the total distance traveled by the cyclist between the time interval of 0 to 6.0s. We can find this area by breaking it down into two areas.

Area 1: It is a rectangle of width 3.05 s and height 3.8 m/s.

Area 2: It is a trapezium with the following parameters: Height = (9.2 - (-3.8)) m/s = 13 m/s Width = (6 - 3.05) s = 2.95 s Area of trapezium = 0.5 × (3.8 + 13) × 2.95= 25.575 m²

Total distance traveled = area of rectangle + area of trapezium= 3.05 × 3.8 + 25.575= 37.435 m

Therefore, the total distance traveled by the cyclist between 0 and 6.0 s is 37.435 m.

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Answer:

It’s fun

Explanation:

If a person sitting on the outer edge of a merry-go-round travels at a greater speed than a person sitting near the center because the linear velocity is a product of the angular velocity and the perpendicular distance from the center .

It is defined as motion when the object is moving in a circle with a constant speed and its velocity is changing with every moment because of the change of direction but the speed of the object is constant in a uniform circular motion .

Because the linear velocity is a function of the angular velocity and the perpendicular distance from the center .

Thus, the person seated on the outside edge of a merry-go-round will move more quickly than a person seated near the center .

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The bucket is 0.8 meters away from the older child.

In this scenario, we have two children carrying a 2.4-meter long horizontal pole with a water bucket hanging from it. The older child supports twice the weight of the younger child. Let's denote the distance of the bucket from the older child as 'x' and the distance from the younger child as '2.4 - x'.

Since the older child is supporting twice the weight of the younger child, we can relate the forces using a balance of torques. Torque is the force applied at a distance from the pivot point. In this case, the pivot point is where the younger child is holding the pole.

The torque applied by the older child is equal to the weight supported by the older child multiplied by the distance 'x'. Similarly, the torque applied by the younger child is equal to half the weight supported by the older child multiplied by the distance '2.4 - x'. For the pole to be in equilibrium, these two torques must be equal. Therefore:

Older child's torque = Younger child's torque
(weight supported by older child) * x = (1/2 * weight supported by older child) * (2.4 - x)

Since we only need to find 'x', we can cancel out the weight supported by the older child from both sides of the equation:

x = (1/2) * (2.4 - x)

Solving for 'x', we get:

x = 0.8 meters

So, the bucket is 0.8 meters away from the older child.

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Answer:

A - energy is absorbed in the reaction

Explanation:

Answer:

50 x 3000 = 150000/4000 = 37.5

37.5 I think.

Explanation:

Hope this helps!

A 3000 kg truck travelling at 50km/hr strikes a stationary 1000 kg car, locking the two vehicles together, the final velocity of the two vehicles after the collision is approximately 10.43 m/s.

We may use the concept of conservation of momentum to calculate the final velocity of the two vehicles after the collision.

The total initial momentum (P_initial) is given by:

P_initial = (mass of truck) * (initial velocity of truck) + (mass of car) * (initial velocity of car)

P_initial = (3000) * (50) + (1000) * (0)

The velocity:

Vt = 50 * (1000/3600) = 13.9 m/s

Vc = 0 = 0 m/s

P_initial = (3000) * (13.9) + (1000) * (0 )

P_initial = 41700 kg·m/s

P_initial = P_final

41700 kg·m/s = (3000 kg + 1000 kg) * Vf

41700 kg·m/s = 4000 kg * Vf

Now Vf:

Vf = 41700 kg·m/s / 4000 kg

Vf ≈ 10.43 m/s

Therefore, the final velocity of the two vehicles after the collision is approximately 10.43 m/s.

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The compression of the spring when the mass is placed on it and doesn't move is \(\frac{{M \cdot g}}{{k}}\). The maximum compression when the mass is released is \(\frac{{2 \cdot M \cdot g}}{{k}}\). The speed of the mass when it reaches a height of 2L is sqrt(4 * g * L).

Assumptions: neglecting air resistance, ideal linear spring, one-dimensional motion.

(a) To determine the compression of the spring when the mass is placed on it and doesn't move, we can equate the gravitational force acting on the mass (M * g) to the force exerted by the spring (k * s), where s is the compression of the spring. Therefore, we have:

M * g = k * s

Rearranging the equation to solve for s:

\(s = \frac{{M \cdot g}}{{k}}\)

The correct answer for the compression of the spring is indeed \(s = \frac{{M \cdot g}}{{k}}\).

(b) When the mass is released from being barely touching the top of the spring, it will experience a maximum compression. This maximum compression occurs when all the potential energy of the mass is converted into elastic potential energy of the spring. Therefore, we can equate the potential energy of the mass (M * g * s) to the elastic potential energy of the spring (0.5 * k * s²), where s is the maximum compression of the spring. Solving this equation:

M * g * s = 0.5 * k * s²

Simplifying and solving for s:

\(s = \frac{{2 \cdot M \cdot g}}{{k}}\)

The correct answer for the maximum compression of the spring is \(s = \frac{{2 \cdot M \cdot g}}{{k}}\).

(c) To find the speed of the mass when it reaches a height of 2L above the table, we can apply the principle of conservation of mechanical energy. The initial mechanical energy of the system is the sum of the potential energy (M * g * s) and the elastic potential energy of the compressed spring (0.5 * k * s²). When the mass reaches a height of 2L, all the initial potential energy is converted into kinetic energy (0.5 * M * v²), where v is the speed of the mass.

M * g * s + 0.5 * k * s² = 0.5 * M * v²

Substituting the expression for s from part (c):

\((M \cdot g \cdot \frac{{2 \cdot M \cdot g}}{{k}}) + 0.5 \cdot k \cdot \left(\frac{{2 \cdot M \cdot g}}{{k}}\right)^2 = 0.5 \cdot M \cdot v^2\)

Simplifying and solving for v:

|v| = sqrt(4 * g * L)

The correct answer for the speed of the mass when it reaches a height of 2L above the table is |v| = sqrt(4 * g * L).

Approximations and simplifying assumptions made in this problem may include:

- Assuming negligible effects of air resistance or friction.

- Assuming an ideal spring with linear behavior (Hooke's Law) throughout its range of compression.

- Treating the spring as massless and neglecting its own gravitational potential energy.

- Assuming a one-dimensional motion without any lateral or rotational effects.

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The existence of black holes is supported by a significant body of scientific evidence and observations like, stellar observations, gravitational waves, accretion disks, galactic centers, and general relativity.

1. Stellar observations: Astronomers have observed the behavior of stars within galaxies, particularly in binary star systems. They have noticed anomalies in the orbital motion and energy output of these systems that can be best explained by the presence of a black hole.

2. Gravitational waves: In 2015, the Laser Interferometer Gravitational-Wave Observatory (LIGO) made the first direct detection of gravitational waves, which are ripples in the fabric of spacetime caused by the acceleration of massive objects. LIGO has detected gravitational waves originating from the merger of black holes, providing strong evidence for their existence.

3. Accretion disks: When matter falls into a black hole, it forms an accretion disk, which is a swirling disk of superheated gas and dust. The intense X-ray emissions detected from these accretion disks provide further evidence for the presence of black holes.

4. Galactic centers: Observations of galactic centers, including our own Milky Way galaxy, have revealed the presence of extremely massive and compact objects. These objects, known as supermassive black holes, can explain the observed gravitational effects and energy emissions from these regions.

5. General relativity: The theory of general relativity, proposed by Albert Einstein, provides a mathematical framework for understanding the behavior of gravity and the existence of black holes. General relativity has been extensively tested and has successfully predicted various phenomena related to black holes.

While the direct observation of black holes remains challenging due to their nature as objects that trap all light, the evidence from these various lines of inquiry strongly supports their existence. Scientists continue to study and explore black holes to deepen our understanding of the universe.

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Detection methods to measure the gravitational tug of a planet on its star that is allowing us to estimate planetary mass is : (c) the astrometric and doppler methods.

Method for finding extrasolar planets and brown dwarfs from radial-velocity measurements through observation of doppler shifts in the spectrum of the planet's parent star is called doppler spectroscopy.

It is also known as the radial-velocity method or the wobble method.

Method that detects the motion of a star by making precise measurements of its position on the sky is called astrometry. This technique can be used to identify the planets around a star by measuring small changes in the position of the stars.

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The direction of the acceleration of the crate is in the southwest direction.

To determine the direction of acceleration, we can use vector addition. The force of 6.0 N to the north can be represented as (0, 6.0) N (with the y-axis pointing north), and the force of 8.0 N to the west can be represented as (-8.0, 0) N (with the x-axis pointing east). We can add these two vectors to find the net force acting on the crate.

Adding the x-components (-8.0) and the y-components (6.0), we get a resultant force of (-8.0, 6.0) N. This means the crate will experience an acceleration in the southwest direction, which can be described as the resultant force pointing towards the southwest relative to the initial position of the crate.

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Answer:

C. 199.9 s

Explanation:

3 minutes = 3×60 = 180 seconds.

the turtle moves in that time 180×10 = 1800 cm.

in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).

the rabbit moves with 10×10cm/s = 100cm/s.

the rabbit needs therefore 1800/100 = 18 seconds for the

1800 cm.

at that time the turtle has added another 18×10 = 180 cm.

for which the rabbit needs 180/100 = 1.8 seconds.

during that time the turtle has added 1.8×10 = 18 cm.

and so on.

in formal mathematics this looks like this :

1800 + 10x = 100x

after x seconds of the rabbit running both will have run the same distance, and it is a tie.

1800 = 90x

x = 20 seconds

so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm

and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.

but our question tells us that the turtle won by 10 cm.

so, the race was over a little bit before these 200 seconds (for a tie).

this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).

the rabbit would have needed 10/100 seconds for these 10 cm.

as speed = distance/time

we need to divide distance by speed

distance/1 / distance/time

to get time.

so,

10cm/1 / 100cm/s = 10s/100 = 1/10 s

so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).

the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).

and so, the race was 199.9 s long.

Answer:

Explanation:

l etme y lo saoc apr aotarsy  r dealkten dpo

The stretch in a spring can be calculated using the formula:

where delta_x is the stretch, F_spring is the force applied on the spring and k is the spring constant.

The force applied on the spring is equal to the weight of the mass, which is 7.3 kg, multiplied by the acceleration due to gravity (9.8 m/s^2):

So the stretch in the spring can be calculated as follows:

The Stretch of a spring is analogous to the vibration of a pendulum. This is because there is an alternating movement of the spring past the balance point. Stretch on the spring also has a tension restoring force according to Hooke's law: Fs = -K.X Where K is the spring constant, and X is the stretch length.

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Answer:

8000J

Explanation:

The kinetic energy of the car lost during breaking are converted to thermal energy and are gained by the brakes.

Kinetic energy loss by car = thermal energy gained by brakes.

∆K.E = ∆T.E ....1

The Kinetic energy loss by car can be expressed as;

∆K.E = K.E1 - K.E2

Initial K.E = K.E1 = 10000J

Final K.E = K.E2 = 2000J

∆K.E= 10000J - 2000J = 8000J

From equation 1,

∆K.E = ∆T.E

∆T.E = 8,000J

thermal energy gain by brakes = 8,000J

Answer:

6.58×10⁻¹⁸ J

Explanation:

Applying

E = kq²/r.................. Equation 1

Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.

From the question,

Given: r = 3.5×10⁻¹¹ m,

Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)

E = 6.58×10⁻¹⁸ J

If the coefficient of static friction is 0.3, then the minimum force required to get it moving is equal in magnitude to the maximum static friction that can hold the body in place.

By Newton's second law,

• the net vertical force is 0, since the body doesn't move up or down, and in particular

∑ F = n - mg = n - 50 N = 0   ==>   n = 50 N

where n is the magnitude of the normal force; and

• the net horizontal force is also 0, since static friction keeps the body from moving, with

∑ F = F' - f = F' - µn = F' - 0.3 (50 N) = 0   ==>   F' = 15 N

where F' is the magnitude of the applied force, f is the magnitude of static friction, and µ is the friction coefficient.

Answer:

Explanation:

The PE equation for a mass/spring system is

\(PE=\frac{1}{2}k\)Δx² and filling in:

\(130=\frac{1}{2}k(.10)^2\) and

\(k=\frac{2(130)}{(.10)^2}\) so

k = 26000 N/m

If the displacement from equilibrium changes more, the PE needed to compress it will also change.

\(PE=\frac{1}{2}(26000)(.20)^2\) gives us that

PE = 520J