a person standing a certain distance from twelve identical loudspeakers is hearing a sound level intensity of 120db. what sound level intensity would this person hear if six are turned off?

Work is equal to energy. Since your braking distance is 10.8 m. you will not stop before you hit the oil spill

Energy is the ability to do work. The work done on an object is tantamount to energy used on the object.

If you are first place in Mario Kart at the moment. Your 5.0 kg Mario Kart is moving at 5.5 m/s when you see an oil spill 10 m ahead. If your maximum braking force is 7.0 N, will you stop before you hit the oil spill? What is your braking distance?

By using the concepts of work and energy, that is,

1/2mv² = F × s

Where

Substitute all the parameters into the formula

1/2 × 5 × 5.5² = 7 × s

75.625 = 7s

s = 75.625/7

s = 10.8 m

Since the calculated distance is greater than the given distance (10 m), you will not stop before you hit the oil spill. And your braking distance will be 10.8 m

Therefore,  you will not stop before you hit the oil spill.

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Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=\(\frac{1}{2}m(v^2-u^2)\)

Using the formula

Work done, W\(=\frac{1}{2}(0.145)((25)^2-0)\)

Work done=\(\frac{1}{2}(0.145)(625)\)

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

The marginal revenue of the 7th unit of output is the additional revenue generated from producing and selling that unit. The marginal cost of the 7th unit of output is the additional cost incurred in producing that unit.

To determine the marginal revenue and marginal cost for the 7th unit, we would need more specific information about the revenue and cost functions or data associated with the production and sale of the units. Marginal revenue is typically calculated as the change in total revenue divided by the change in quantity, while marginal cost is calculated as the change in total cost divided by the change in quantity.

Without further information, it is not possible to provide an exact numerical answer for the marginal revenue and marginal cost of the 7th unit.

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Answer:

Density = 3 x 10⁻⁵ kg/m³

Explanation:

First, we will find the volume of the planet:

\(V = \frac{4}{3}\pi r^3\ (radius\ of\ sphere)\\\\V = \frac{4}{3}\pi (8000\ m)^3\\\\V = 2.14\ x\ 10^{12}\ m^3\)

Now, we will use the expression for gravitational force to find the mass of the planet:

\(g = \frac{Gm}{r^2}\\\\m = \frac{gr^2}{G}\)

where,

m = mass = ?

g = acceleration due to gravity = 6.67 x 10⁻¹¹ m/s²

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

r = radius = 8000 m

Therefore,

\(m = \frac{(6.67\ x\ 10^{-11}\ m/s^2)(8000\ m)^2}{6.67\ x\ 10^{-11}\ Nm^/kg^2}\\\\m = 6.4\ x\ 10^7\ kg\)

Therefore, the density will be:

\(Density = \frac{m}{V} = \frac{6.4\ x\ 10^7\ kg}{2.14\ x\ 10^{12}\ m^3}\)

Density = 3 x 10⁻⁵ kg/m³

Answer:

Explanation:

The equation for work is

W = FΔx

We are looking for work, so that means we have to be able to fill in the Force and the displacement. We have Force, but we don't have displacement. But the thing we need to do first is change the 45 minutes to seconds because the velocity is in m/s, not m/min.

45 minutes is 2700 seconds.

That means that  the displacement is

Δx = (.90)(2700) so

Δx = 2430 m

Now we plug that in to find work, along with the given Force:

W = 40(2430) so

W = 97200 J (and that is not the correct number of sig fig's but I have a feeling you're not too into that in class, because if you were, the 40 N would be expressed as 40.0 or 4.0 × 10¹)

One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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The speed of the  Toyota Corolla would have  been 143.9 mph.

The acceleration of the F-15 can be calculated as follows:

Acceleration = Velocity Change / Time = (Take-off Speed) / Time

where;

Take-off Speed = √(2dg /t²)

Take-off Speed = √(2 x  (270 ft)  x 32.2 ft/s² / (2 s)²)

T  = √(17496) = 131.6 ft/s

Acceleration = Velocity Change / Time

= (131.6 ft/s) / (2 s) = 65.8 ft/s²

We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:

Final Velocity = Initial Velocity + Acceleration x Time

where;

Final Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s

Finally, we can convert the velocity from feet per second to miles per hour:

Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)

= 131.6 ft/s x  (1 hour/3600 s)  x (5280 ft/mile)

= 143.9 mph

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The phenomenon is the term that best describes the phrase "something that happens", therefore the correct answer is option D.

The deliberate, scientifically justified quest and utilization of knowledge and comprehending of the natural and improvements in living standards are what is known as science.

As given in the problem,

Which term best describes the phrase "something that happens"?

A. Experiment

B. Observation

C. Hypothesis

D. Phenomenon

The phenomenon is the term used to define the process of happening things that may be natural or anthropologic.

Thus, The phrase "something that happens" is best described by the word "phenomenon," hence option D is the appropriate response.

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Answer:

Dude this is based on some egg you have

Explanation:

The force due to hydrostatic pressure on the dam when the water is 75% of the way up the wall is 735,750 N

The force due to hydrostatic pressure on the dam can be calculated using the formula

P = ρghA

where P is the force, ρ is the density of the water, g is the acceleration due to gravity, h is the height of the water column, and A is the cross-sectional area of the dam.

In this case, the cross-sectional area of the dam is 100 m2 and the height of the water column is 7.5 m (since the water is 75% of the way up the wall, which is a 10m tall wall). Therefore, the force due to hydrostatic pressure on the dam is

P = 1000 kg/m3 x 9.81 m/s2 x 7.5 m x 100 m2

= 735,750 N

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(a) The magnitude of the net gravitational force exerted on the 33.0-kg object is 4.53 x 10^-7 N.

(b) The equilibrium point is 1.89 m from the 530-kg object, toward the 230-kg object.

(a) The magnitude of the net gravitational force exerted by the 230-kg and 530-kg objects on the 33.0-kg object is given by:

F = G(m1m3/r13^2) + G(m2m3/r23^2)

where G is the gravitational constant, m1 and m2 are the masses of the two objects, m3 is the mass of the 33.0-kg object, r13 is the distance between the 230-kg object and the 33.0-kg object, and r23 is the distance between the 530-kg object and the 33.0-kg object.

Plugging in the given values and solving for F, we get:

F = (6.67 x 10^-11 N(m/kg)^2)(230 kg)(33.0 kg)/(2.20 m)^2 + (6.67 x 10^-11 N(m/kg)^2)(530 kg)(33.0 kg)/(2.20 m)^2

F = 1.37 x 10^-7 N + 3.16 x 10^-7 N

F = 4.53 x 10^-7 N

Therefore, the magnitude of the net gravitational force exerted on the 33.0-kg object is 4.53 x 10^-7 N.

(b) To find the position where the net force on the 33.0-kg object is zero, we can use the concept of gravitational equilibrium. At this point, the gravitational forces from the two larger objects will cancel out, resulting in zero net force on the 33.0-kg object.

Let x be the distance from the 530-kg object to the equilibrium point. Then, the distance from the 230-kg object to the equilibrium point is 4.40 m - x.

Setting the gravitational forces from the two larger objects equal to each other, we have:

G(m1m3/(4.40 - x)^2) = G(m2m3/x^2)

Simplifying and solving for x, we get:

x = 1.89 m

Therefore, the equilibrium point is 1.89 m from the 530-kg object, toward the 230-kg object.

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The spring on the left will oscillate faster than spring on the right. This is the true statement.

A simple harmonic oscillator is a kind of oscillator that is either damped or driven. It generally has a mass' m', where a single force 'F' pulls the mass in the trajectory of the point x = 0, and depends only on the position 'x' of the body and a constant k.

The particle's acceleration in simple harmonic motion is directly proportional to its displacement and it is directed towards its mean location.

Since the force constant for the left spring is more than the right spring, The left will oscillate faster. It has the direct relation with force constant.

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The type of model of the universe in which many of the ancient Greeks believed that the earth was the stationary center of the universe is called geocentric model.

In this model, the Earth is considered to be at the center, with the Sun, Moon, planets, and stars orbiting around it. This geocentric view of the Universe was prevalent in ancient Greek cosmology and was also adopted by other civilizations, such as ancient Babylonian and medieval European societies. One of the most influential proponents of the geocentric model was the Greek philosopher Aristotle. It was not until the 16th century when the heliocentric model, with the Sun at the center of the Solar System, was proposed by astronomers such as Nicolaus Copernicus and later confirmed by observations and discoveries made by Galileo Galilei and others.

The question should be:

Many of the ancient Greeks believed that the Earth was the stationary center of the Universe. What type of model of the Universe is this?

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As per the problem, the charge is of 2.5μC, moving in magnetic field \(3\times10^{2}\) T and having velocity \(5\times 10^{3}\) m/s, the force comes out to be 3.75N

Magnetic force is the force experienced by the object inside the magnetic field or flowing current across the conductor. This force is caused due to the movement of charges.

The force exerted is magnetic force which is given as,

\(F= QVBsin\theta\)

here,

Q= charge

v= velocity

B= Magnetic field and

\(\theta\)=Angle of object from magnetic field

\(F=2.5\times10^{-6} \times 5\times10^{3} \times3\times10^{2}\times sin90\)

\(F=3.75N\)

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The work was done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.

When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.

To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.

Given:

The mass, m = 2 kg,

The acceleration, g = 9.81 \(m/s^2\),

θ = angle between block and surface kinetic friction = μ

Calculate the work done by the formula given below,

\(W_{fy}\) = F sinθ

\(W_{fy}\) =  (\(mgsin\)θ)/ (sinθ -  μ * cosθ)

Substitute the values

\(W_{fy}\)  = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)

\(W_{fy}\)  = 42.83 J

Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.

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The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

This is defined as  sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

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Answer:In geometric optics, the angle of incidence is the angle between a ray incident on a surface and the line perpendicular to the surface at the point of incidence, called the normal. The ray can be formed by any wave: optical, acoustic, microwave, X-ray and so on. In the figure below, the line representing a ray makes an angle θ with the normal. The angle of incidence at which light is first totally internally reflected is known as the critical angle. The angle of reflection and angle of refraction are other angles related to beams.

Explanation:tik tok: Uh.amy07

Answer:

The angle between a ray incident on a surface and the line perpendicular to the surface at the point of incidence.

Explanation

Answer:

I know someone anwsered but it would be 400M

Explanation:

i initial velocity (u)=10m/s

acceleration (a)=0

time taken (t) =40s

then distance (s)=u t +1/2 a t^2

s= u t +0 (as a is 0)

s= 10 x 40

s= 400M

If the pressure of a gas collected over water was measured to be 453.0 mm Hg. The pressure of the pure gas is 0.573 atm.

Dalton's Law of Partial Pressure, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases, must be used to solve the problem.

The total pressure in this situation, which involves a gas and water vapor mixture, is expressed as 453.0 mmHg. The vapor pressure of water at the specified temperature of 20.0 degrees C, which is 17.5 mmHg, can be used to compute the partial pressure of water vapor.

The partial pressure of the gas can be obtained by subtracting the partial pressure of water vapor from the total pressure:

Partial pressure of gas = Total pressure - Partial pressure of water vapor

= 453.0 mmHg - 17.5 mmHg

= 435.5 mmHg

To convert the pressure from mmHg to atm, we can divide by the conversion factor of 760 mmHg/atm:

Partial pressure of gas = 435.5 mmHg / 760 mmHg/atm

= 0.573 atm

Therefore, the pressure of the pure gas is 0.573 atm.

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Answer:

methylated spirit is in fact methanol added to ethanol (usually 10% methanol is used). The liquid evaporates which means that the liquid converts to a gaseous state. This process requires energy which it extracts from your body in the form of heat.

Explanation:

Answer:

nothing you let it go be a good human being

or syrup... sugary food ig orrrr just straight up sugar

Answer:

an elevator we can use a counterweight that has the same mass as the empty box,

Explanation:

An Atwood machine consists of two masses connected by a rope through a pulley, in this case the acceleration of the system is proportional to the difference in masses, in the case of equal masses the acceleration is zero.

In the design of an elevator we can use a counterweight that has the same mass as the empty box, in that case when there are no people in the elevator, the natural acceleration is zero and there is no need to apply any force and therefore no power is needed. the motor.

When you have people inside, the power of the motor is what you need to lift the people, not the box, this reduces the power needed by the elevator motor by a high factor.

Using Atwood machine concept, we can state that the elevator can use a system of counterweights that balance the weight inside the box and minimize the force required to move the elevator up and down.

We can arrive at this answer because:

With that, we can say that an elevator can act as an Atwood machine.

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The elastic potential energy of the block at point D is 0.28J, the velocity of the block at point C is 1.21 m/s, the velocity of the block at the top of the loop at point B is 2.19 m/s, the height of point A is 0.51m and no work is done by the block.

a. The elastic potential energy of the block at point D can be found using the equation:

Elastic potential energy = \((1/2) \times k \times x^2\)

where k is the spring constant and x is the distance the spring is compressed. Substituting the given values, we get:

Elastic potential energy \(= (1/2) \times 350 N/m \times (0.04 m)^2\) = 0.28 J

b. The velocity of the block at point C can be found using the principle of conservation of mechanical energy, which states that the total mechanical energy (kinetic + potential) of a system is constant if no external forces act on it.

The mechanical energy at point D is equal to the elastic potential energy, and at point C it is equal to the sum of the elastic potential energy and the gravitational potential energy:

\((1/2) \times m \times v^2 = (1/2) \times k \times x^2 + m \times g \times h\)

where v is the velocity, h is the height above point D, and g is the acceleration due to gravity. Substituting the given values, we get:

\((1/2) \times 0.05 kg \times v^2\)

\(= (1/2) \times 350 N/m \times (0.04 m)^2 + 0.05 kg \times 9.8 m/s^2 \times (0.1 m - 0.04 m)\)

Solving for v, we get:

v = 1.21 m/s

c. The velocity of the block at the top of the loop at point B can be found using the principle of conservation of mechanical energy again. The mechanical energy at point C is equal to the mechanical energy at point B:

\((1/2) \times m \times v^2 = m \times g \times h\)

where h is the height above point C.

Substituting the given values, we get:

\((1/2) \times 0.05 kg \times (1.21 m/s)^2\)

\(= 0.05 kg \times 9.8 m/s^2 \times (0.1 m + 0.04 m)\)

Solving for v, we get:

v = 2.19 m/s

d. The height of point A can be found using the conservation of mechanical energy again. The mechanical energy at point B is equal to the mechanical energy at point A:

\((1/2) \times m \times v^2 = m \times g \times h\)

where h is the height above point B. Substituting the given values, we get:

\((1/2) \times 0.05 kg \times (2.19 m/s)^2 = 0.05 kg \times 9.8 m/s^2 \times h\)

Solving for h, we get:

h = 0.51 m

e. No work is done by the block because the only force acting on it is the gravitational force, which is a conservative force. Conservative forces do not dissipate energy as heat or sound, so the total mechanical energy of the block is conserved.

In summary, the elastic potential energy of the block at point D can be found using the spring constant and distance compressed. The velocity of the block at point C and the top of the loop at point B can be found using the conservation of mechanical energy.

The height of point A can also be found using the conservation of mechanical energy. No work is done by the block because the gravitational force is a conservative force.

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By solving the given equation on [² f(u)du = t_ -L₁ €² 2 f(u)du is obtained, we can find t.= J 1+e²t / 1 + e2t / 1-e²tdt. Now, we need to solve the integral,∫ 1+e²t / (1 + e2t)(1-e²t) dt.

For this integral, let u = 1+ e²tSo, du/dt = 2e²And, dt = du/2e²= 1/2e² ∫1+e²t / (u)(1-e²t) du= 1/2e² ∫ (1/u) - (e²/(1-e²t)) du= 1/2e² [ln|u| - ln|1-e²t|] + c.

Now, substituting back the value of u,= 1/2e² [ln|1+ e²t| - ln|1-e²t|] + c= 1/2e² ln|1+ e²t / 1-e²t| + c.

Now, putting the limits in the above expression and solving it, we get the value of t.= [1/2e² ln|1+ e²t / 1-e²t|] t = 1 2t / [1 + e²t] - L₁ 2t / [1-e²t].

Hence, the answer is D) f(t)= 2t / [1 + e²t] - L₁ 2t / [1-e²t].

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The recoil speed of the shooter and the rifle would both be zero.

Let's assume the recoil speed of the marksman and rifle to be v (in m/s), and the combined mass of the marksman and rifle to be M.

According to the conservation of momentum:

Initial momentum = Final momentum

0 = (mass of the marksman) * (recoil speed of the marksman) + (mass of the rifle) * (recoil speed of the rifle)

Since the marksman and rifle are together during the shot and have the same recoil speed:

0 = (mass of the marksman + mass of the rifle) * (recoil speed)

Given:

Weight of the marksman = 600 N

Using the equation weight = mass * acceleration due to gravity (weight = mass * g), we can calculate the mass of the marksman:

mass of the marksman = weight / g

mass of the marksman = 600 N / 9.8 m/s^2

mass of the marksman = 61.22 kg

Assuming the mass of the rifle to be negligible compared to the marksman:

mass of the marksman + mass of the rifle ≈ mass of the marksman

Using the conservation of momentum equation:

0 = (mass of the marksman) * v + (mass of the rifle) * v

0 = (61.22 kg) * v + (mass of the rifle) * v

0 = (61.22 kg + mass of the rifle) * v

Since the combined mass of the marksman and rifle is approximately equal to the mass of the marksman, we can simplify the equation:

0 = (61.22 kg) * v

Therefore, the recoil speed of the shooter and rifle is zero. The marksman and rifle will remain at rest after firing.

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Answer:

A

Explanation:

Answer:

W = 0 J

Explanation:

Formula for work done is;

W = F × d

Where;

W is work done

F is Force

d is distance covered

What this means is that we will calculate the area under which the given times in the graph pass.

Thus;

At constant force of F = 40 N which falls in between distance of 0 m and 2m,

W1 = 40 × 2 = 80 J

At constant force of -20 n which will fall between distance of 2 m and 6 m which is 4m, we have;

W2 = -20 × 4

W2 = -80 J

Thus, total workdone is;

W = W1 + W2

W = 80 - 80

W = 0 J

Answer:

20 J

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