Answer:
\(Power = 360W\)
Explanation:
Given
\(Force = 600N\)
\(Time = 10s\)
\(Height = 6m\)
Required
Determine the power used
First, we need to calculate the work done to climb the stairs.
\(Word = Force * Distance\)
In this case, the distance represents the height of the stairs.
So:
\(Work = 600N * 6m\)
\(Work = 3600J\)
Next, we calculate the power using:
\(Power = \frac{Work}{Time}\)
Substitute values for Work and Time
\(Power = \frac{3600J}{10s}\)
\(Power = 360W\)
Hence, the power used by the person is 360 watts
if i weigh 100 ibs on earth how much do i weight on uranus
Gravity on Uranus is 86% of Earths.
100 pounds x 86% = 86 pounds
You would weigh 86 pounds.
I NEED HELP ASAP
A green filter...
Select one:
a. transmits all other colors except green light.
b. reflects only green light.
c. absorbs only green light.
d. transmits only green light.
Answer:
ig d. transmits only green light.....
What is the low end of the range of surface temperature for blue white stars
B 10,000 - 30,000 K Blue-white stars
A 7,500 - 10,000 K White stars
F 6,000 - 7,500 K Yellow-white stars
G 5,000 - 6,000 K Yellow stars (like the Sun)
The lowest temperature stars are red while the hottest stars are blue. Astronomers are able to measure the temperatures of the surfaces of stars by comparing their spectra to the spectrum of a black body.
During a phase change, a substance undergoes a(n) *
HELP
reversible change from one state to another.
irreversible change to a different substance
irreversible change from one state to another.
reversible change to a different substance.
Answer:
Reversible change from one state to another
Hope this helps
:)
What is required for the heat to flow from one object to another?
Uniform temperature
Uniform density
Temperature difference
Density difference
Answer:
Explanation:
The answer is Temperature difference
Answer:
C
Explanation:
is the answer ,..........................
PLs HELP
The gravity in space is the same as the gravity on Earth
True
False
Answer:
false
Explanation:
The gravity in space is not the same as the gravity on Earth
What is the most common source of pollution?
gas
nuclear
coal
oil
Answer:
oil
Explanation:
Hope I helped! Brainiest plz! Hope you make an 100% and have a wonderful day! -Amelia♥
Answer:
Gas
Explanation:
Hope this helps!
What is the name of the process on a neuron that carries electrical impulses toward the cell to be stimulated?.
Answer:
axon
Explanation:
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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(b) What is the probability that the electron can be detected in the middle one third of well, region (b)
In order to determine the probability that an electron can be detected in the middle one-third of a well region, we need to take into account the wave function and the boundary conditions.The wave function represents the probability density of finding the electron in a particular location within the well. The boundary conditions are determined by the geometry of the well, which can be rectangular, triangular, or other shapes.
The Schrodinger equation is used to calculate the wave function and determine the probability density of finding the electron in a particular location. The wave function is a complex function that describes the position and momentum of the electron. It is also used to calculate the energy of the electron in the well.The probability of finding the electron in the middle one-third of the well can be determined by integrating the probability density over the middle one-third of the well region. This will give us the probability of finding the electron in that region. The integral can be evaluated using numerical methods or analytical methods, depending on the complexity of the wave function and the boundary conditions.In general, the probability of finding the electron in the middle one-third of the well will depend on the shape of the well, the energy of the electron, and the boundary conditions. For example, if the well is rectangular and the electron is in the ground state, then the probability of finding the electron in the middle one-third of the well will be high. However, if the well is triangular and the electron is in an excited state, then the probability of finding the electron in the middle one-third of the well will be lower.For such more question on probability
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The shear formula is given as τ=vqit. which of the following is a proper unit of q?a. m^2b. m^4c. dimensionsd. me. m^2f. None of these
the correct answer is option a. m^2, as it is the proper unit for the second moment of area (q) in the shear formula.
In the shear formula, τ=vqit, q represents the area over which the shear force is applied. The units of q should be in square meters (m^2) to ensure that the overall unit of the formula is in Newtons per square meter (N/m^2) or Pascals (Pa). Therefore, option (e) m^2 is the proper unit of q. Option (a) m^2 is also correct but it is not specifically labeled as a unit.
Option (b) m^4 is incorrect because it is a unit of volume. Option (c) dimensions and option (d) me are not valid units of area. Lastly, option (f) None of these is incorrect since option (e) m^2 is the correct answer. The proper unit of q in the shear formula τ = vqit is "m^2".
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A light spring with force constant 3.70 N/m is compressed by 8.64 cm as it is held between a 0.261-kg block on the left and a 0.522-kg block on the right, both resting on a horizontal surface. The spring exerts a force on each block, tending to push them apart. The blocks are simultaneously released from rest. Find the acceleration with which each block starts to move, given that the coefficient of kinetic friction between each block and the surface is the following. (Let the coordinate system be positive to the right and negative to the left. Be sure to include the sign to indicate the direction of the acceleration.) (a) μ = 0 heavier block lighter block (b) μ = 0.110 heavier block lighter block (c) μ = 0.480 heavier block lighter block m/s² m/s² m/s² m/s² m/s² m/s²
The lighter block will also accelerate to the right with an acceleration of -0.82 m/s².
(a) μ = 0
The heavier block will accelerate to the right with an acceleration of:
a = F / m = k x / m = (3.70 N/m) (0.0864 m) / 0.261 kg = 1.22 m/s²
The lighter block will also accelerate to the right with an acceleration of 1.22 m/s².
(b) μ = 0.110
The heavier block will accelerate to the right with an acceleration of:
a = F - μk / m = k x / m - μk / m = (3.70 N/m) (0.0864 m) / 0.261 kg - (0.110)(0.261 kg)(9.80 m/s²) = 0.68 m/s²
The lighter block will not accelerate because the force of friction is greater than the force of the spring.
(c) μ = 0.480
The heavier block will accelerate to the right with an acceleration of:
a = F - μk / m = k x / m - μk / m = (3.70 N/m)(0.0864 m) / 0.261 kg - (0.480)(0.261 kg) (9.80 m/s²) = -0.82 m/s²
Therefore, the lighter block will also accelerate to the right with an acceleration of -0.82 m/s².
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Find the efficiency of a machine that does 800J of work if the input work is 2,000J
Answer:
Efficiency: 0.4 (40%)
Explanation:
The efficiency of a simple machine is given by the ratio
n = w¹/w²
where
w² is the input work of the machine
w¹ is the output work of the machine
For the machine in this problem, we have:
w¹ = 800j is the output work
w² = 2000j is the input work
Therefore, the efficiency of the machine is
n = 800/2000 = 0.4
Which can be also written as percentage:
n = 0.4 × 100 = 40%
hope it helps you
You have recently been called to troubleshoot network connectivity problems at a user's workstation. You have found that the network cable runs across high-traffic areas on the floor, causing the cable to wear through and break. You have replaced the cable with a plenum-rated and shielded twisted pair cable. You would like to minimize the problem and prevent it from happening again.Which of the following will BEST protect the cable from further damage?A. Encase the cable in a protective shield and secure the cable to prevent it from slipping.B. Periodically check the cable for kinks and wear. Replace the cable when necessary.C. Run the cable through the ceiling area instead of across the floor.D. Run the cable under the carpet.
Answer:
C
Explanation:
Prevents further damage to the network cable.
By solving the equation A) f(t)= = B) f(t): C) f(t) D) f(t)= = on [² f(u)du = t_ -L₁ €² 2 f(u)du is obtained: Jo 1+e²t 1 1+ e2t t = 1 1 2t 1-e²t
By solving the given equation on [² f(u)du = t_ -L₁ €² 2 f(u)du is obtained, we can find t.= J 1+e²t / 1 + e2t / 1-e²tdt. Now, we need to solve the integral,∫ 1+e²t / (1 + e2t)(1-e²t) dt.
For this integral, let u = 1+ e²tSo, du/dt = 2e²And, dt = du/2e²= 1/2e² ∫1+e²t / (u)(1-e²t) du= 1/2e² ∫ (1/u) - (e²/(1-e²t)) du= 1/2e² [ln|u| - ln|1-e²t|] + c.
Now, substituting back the value of u,= 1/2e² [ln|1+ e²t| - ln|1-e²t|] + c= 1/2e² ln|1+ e²t / 1-e²t| + c.
Now, putting the limits in the above expression and solving it, we get the value of t.= [1/2e² ln|1+ e²t / 1-e²t|] t = 1 2t / [1 + e²t] - L₁ 2t / [1-e²t].
Hence, the answer is D) f(t)= 2t / [1 + e²t] - L₁ 2t / [1-e²t].
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If one were to stack thick fabric fabric on top of one another, then push the opposite ends towards one another, resulting and bending and rumpling, this would illustrate what physical process?
Answer:
The answer is "folding".
Explanation:
It is a physical reconfiguring of the process, which gives a fabric a softer, lightweight shape. It is achieved in a far less simple space to carry or store products.
When one places effect sizes on each other, instead move the different ends to each other and fold and roll it, its linear function of Folding would be illustrated. Except in geography, the piling process naturally creates space to makes the surface clearer and lighter.Moving a spring toy up and down will create what kind of disturbance?
parallel to the wave motion
in a circular motion
in the same direction as the wave motion
perpedicular to the wave motion
Answer:
Perpindicular to the wave motion.
Explanation:
Moving a spring toy up and down will create a disturbance in the same direction as the wave motion.
We can classify waves by the direction of wave motion in which case waves are classified into;
Transverse wavesLongitudinal wavesLongitudinal waves are waves in which the direction of disturbance is in the same direction as the wave motion. The wave along a spring is a longitudinal wave therefore; moving a spring toy up and down will create a disturbance in the same direction as the wave motion.
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if a velocity time graph is hortizontal then velocity is
Answer: If a velocity time graph is horizontal then the velocity is constant and there is no acceleration.
Which of the following statements is consistent with Thomson’s and Millikan’s work with cathode rays and electrons? (A) Cathode rays from helium atoms are heavier than cathode rays from hydrogen atoms. (B) Cathode rays are attracted toward a negatively charged electric plate. (C) The mass of an electron is about 2000 times lighter than the mass of a hydrogen atom. (D) The plum pudding model of the atom consists of a uniform sphere of negative charge in which the protons are embedded, like raisins in a pudding.
Answer:
Dalton's ideas proved foundational to modern atomic theory. However, one of his underlying assumptions was later shown to be incorrect. Dalton thought that atoms were the smallest units of matter-−minustiny, hard spheres that could not be broken down any further. This assumption persisted until experiments in physics showed that the atom was composed of even smaller particles. In this article, we will discuss some of the key experiments that led to the discovery of the electron and the nucleus.
J.J. Thomson and the discovery of the electron
In the late 19^{\text{th}}19
th
19, start superscript, start text, t, h, end text, end superscript century, physicist J.J. Thomson began experimenting with cathode ray tubes. Cathode ray tubes are sealed glass tubes from which most of the air has been evacuated. A high voltage is applied across two electrodes at one end of the tube, which causes a beam of particles to flow from the cathode (the negatively-charged electrode) to the anode (the positively-charged electrode). The tubes are called cathode ray tubes because the particle beam or "cathode ray" originates at the cathode. The ray can be detected by painting a material known as phosphors onto the far end of the tube beyond the anode. The phosphors spark, or emit light, when impacted by the cathode ray.
A diagram of a cathode ray tube.
A diagram of a cathode ray tube.
A diagram of J.J. Thomson's cathode ray tube. The ray originates at the cathode and passes through a slit in the anode. The cathode ray is deflected away from the negatively-charged electric plate, and towards the positively-charged electric plate. The amount by which the ray was deflected by a magnetic field helped Thomson determine the mass-to-charge ratio of the particles. Image from Openstax, CC BY 4.0.
To test the properties of the particles, Thomson placed two oppositely-charged electric plates around the cathode ray. The cathode ray was deflected away from the negatively-charged electric plate and towards the positively-charged plate. This indicated that the cathode ray was composed of negatively-charged particles.
Thomson also placed two magnets on either side of the tube, and obser
Explanation:
Most of the galaxies in the universe are observed to be moving away from Earth. Suppose a particular galaxy emits orange light with a frequency of 5.000 x 10 Hz. Part A If the galaxy is receding from Earth with a speed of 4500 km/s, what is the frequency of the light when it reaches Earth? Express your answer to four significant figures and include appropriate units.
The frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.
Explanation:-
Given:
Emitted frequency of light, f = 5.000 x 10^14 Hz,
Speed of the galaxy receding from Earth, v_src = 4500 km/s.
We need to convert the speed of the galaxy from km/s to m/s:
v_src = 4500 km/s * (1000 m/km)
v_src = 4.5 x 10^6 m/s
Plugging the given values into the Doppler effect formula:
f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s + 0 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)
Simplifying the expression:
f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)
f' ≈ 4.988 x 10^14 Hz
Therefore, the frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.
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A ball rolls of a building that is 100 m high. Calculate the time it takes to hit the ground.
Answer:
2as=v2-u2
2000=v2
V=44
V=u+at
44/10=t
T=4.4seconds
Explanation:
The vector product of vectors and has magnitude and is in the direction. If vector has magnitude 8. 0 m and is in the direction, what are the magnitude and direction of vector if it has no component?.
The magnitude and direction of vector B if it has no X-component is 2m along negative y direction.
Given the magnitude of vector A is 8m
The direction of vector A is negative x-axis = -8i
The magnitude of vector product of two vectors A and B is = 16m
The direction of vector (A x B) is along z-axis = (A X B) = 16k
We know that from product of vectors i x j = k
So, B must be pointing in the -y direction which means:
B = -lBlj
Then, A X B = (8 x B)(i x j) = 16k
B = 2m
Hence the magnitude and direction of vector B if it has no X-component is 2m along negative y direction.
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complete question: The vector product of vectors and B has magnitude 16.0 m? and is in the +z-direction. If vector A has magnitude 8.0 m and is in the -x-direction, what are the magnitude and direction of vector B if it has no X-component?
Question 2
A wave with a frequency of 10 Hz and a wavelength of 4 m would have what speed?
m/s
Answer:
speed = 40 m/s
Explanation:
speed = frequency x wavelength
speed = 10 Hz x 4 m
speed = 40 m/s
if a walker travels at 45.0 east of north (north east) for 10.0 km and then due east for another 10.0 km, what is the final distance from the starting point?a. 10.4 kmb. 11.4 kmc. 12.4 kmd. 13.4 km
The final distance from the starting point is approximately 14.1 km, which is closest to answer choice 13.4 km.
The final distance from the starting point can be found by using the Pythagorean theorem, which states that the square of the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is the final distance from the starting point, and the other two sides are the distances traveled in the two different directions. The equation for the Pythagorean theorem is:
c² = a² + b²
Where c is the hypotenuse, and a and b are the other two sides. In this case, a = 10.0 km (the distance traveled due east) and b = 10.0 km (the distance traveled 45.0 east of north). Plugging in these values gives:
c² = 10.0² + 10.0²
c² = 100 + 100
c² = 200
c = √200
c ≈ 14.1 km
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saturn has a satellite called enceladus. enceladus is just a little over 500 km in diameter. what shape do you expect enceladus to be?\
Saturn has a satellite called enceladus, enceladus is just a little over 500 km in diameter, the shape enceladus to be round or spherical shape
Saturn is one of the most fascinating planets in our solar system, and it has many satellites. Enceladus is one of these satellites, and it has a diameter of just over 500 km. Based on this information, it is reasonable to assume that Enceladus is a round or spherical shape. However, it's not quite as simple as that. Enceladus is indeed round, but it has not formed into a perfectly spherical shape, it has some noticeable irregularities, which is due to its composition.
Enceladus is made up of a rocky core with a water ice crust and an icy mantle, because of this, it has different densities, which have resulted in some significant variations in its shape. Enceladus is a very intriguing satellite because of its many peculiar features, it has active water geysers that have been observed shooting out from its south pole, and it has a subsurface ocean that may contain the necessary conditions to support life. This makes Enceladus an excellent target for further study and exploration. So therefore Enceladus shape is a round or spherical shape.
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a stone is thrown vertically upwards with an initial velocity of 20 metre per second find the maximum height it reaches and the time taken by to reach the height( g =10m/s)
Answer:
y = 20 [m]
Explanation:
To solve this type of problem we must use the following equation of kinematics.
\(v_{f}^{2} =v_{o}^{2}-2*g*y\)
where:
Vf = final velocity = 0
Vo = initial velocity = 20 [m/s]
g = gravity acceleration = 10 [m/s²]
y = elevation [m]
Now the key to solving this problem is to know that when the stone reaches the maximum height its speed is zero. Therefore the final velocity term is zero.
\(0 = (20)^{2}-2*10*y\\20*y=400\\y=20 [m]\)
Another important fact is that the sign of gravitational acceleration was taken as negative, since it acts in the opposite direction to the movement of the stone.
3.) using calories, calculate the how much heat 32.0 g of water absorbs when it is heated from 25.0oc to 80.0oc. how many joules is this?
The specific heat capacity of water is 1 calorie per gram per degree Celsius. This means that 1 gram of water will absorb 1 calorie of heat for every 1 degree Celsius increase in temperature.
In this case, we have 32.0 grams of water that is heated from 25.0 degrees Celsius to 80.0 degrees Celsius. The change in temperature is therefore 80.0 - 25.0 = 55.0 degrees Celsius.
The amount of heat absorbed by the water is therefore 32.0 x 55.0 = 1760 calories.
To convert calories to joules, we can use the following conversion factor:
1 calorie = 4.184 joules
Therefore, the amount of heat absorbed by the water in joules is 1760 x 4.184 = 7374 joules.
Therefore, the answer to your question is that 32.0 grams of water absorbs 7374 joules of heat when it is heated from 25.0 degrees Celsius to 80.0 degrees Celsius.
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In order to reduce the sting in catching a hard ball one usuallyA. increases momentum changeB. increases the contact forceC. increases the impulseD. increases the contact time
D. increases the contact time is In order to reduce the sting in catching a hard ball one usually
By increasing the contact time, the force of the impact is spread out over a longer period, reducing the overall force felt and thus reducing the sting. This can be achieved by using softer gloves, catching the ball with both hands, or using proper technique to absorb the impact.
In order to reduce the sting in catching a hard ball, one usually D. increases the contact time. By increasing the contact time, the force exerted on the hand is distributed over a longer period, resulting in a decreased impact and reduced sting.
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I am listening to a radio station at 95.5 MHz. I live near a radio station that puts out a frequency of 98.5 MHz and it is interfering with my reception. What kind of filter do I add to my receiver circuit to block this other station
The kind of filter you need to add to your receiver circuit to block another radio station that is interfering with your reception is a band-stop filter.
A band-stop filter is an electronic filter that enables signals to pass through all frequencies except for those in a specific range. The filter’s purpose is to avoid signals from interfering with one another. As a result, when using multiple signals, a band-stop filter can reduce interference from other signals or sources, providing a better sound quality.
A band-stop filter is used to attenuate or remove a specific frequency band from a signal path. This type of filter is also known as a notch filter since it produces a notch, or a dip in the frequency response curve, at the desired frequency or range of frequencies.
Band-stop filters are used in applications where it is necessary to reduce the impact of a specific frequency band.
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The milky way galaxy contains about _____ stars. most of theses stars are probably _____.
The Milky Way galaxy contains about 100 to 400 billion stars. Most of these stars are probably similar to our Sun. While this estimation provides a rough idea of the stellar population, the actual number may vary. Additionally, it is reasonable to assume that the majority of these stars are similar to our Sun, as G-type stars are prevalent in the galaxy.
The exact number of stars in the Milky Way galaxy is difficult to determine precisely due to its vast size and the challenges of counting individual stars. Estimates suggest that there are approximately 100 to 400 billion stars in our galaxy.
As for the type of stars, most of them are likely similar to our Sun, which is classified as a G-type main-sequence star. G-type stars like the Sun are relatively common and make up a significant portion of the stellar population in the Milky Way.
The Milky Way galaxy is home to a staggering number of stars, ranging from 100 to 400 billion. While this estimation provides a rough idea of the stellar population, the actual number may vary. Additionally, it is reasonable to assume that the majority of these stars are similar to our Sun, as G-type stars are prevalent in the galaxy.
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