A person who weighs 715 N is riding a 98-N mountain bike. Suppose the entire weight of the rider and bike is supported equally by the two tires. If the gauge pressure in each tire is 6. 20 105 Pa, what is the area of contact between each tire and the ground?
Answers
The magnitude of the magnetic field is \(2.56 * 10^{-4} T.\)
The force on a charged particle moving in a magnetic field is given by the equation:
F = q v B sin θ
where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field, and θ is the angle between the velocity of the particle and the magnetic field.
The acceleration of the particle is related to the force on the particle by the equation:
F = m a
where m is the mass of the particle and a is the acceleration of the particle.
In this problem, the velocity of the particle is given as 2.0 km/s at an angle of 50° to the magnetic field.
We can resolve this velocity vector into components parallel and perpendicular to the magnetic field.
The component of the velocity parallel to the magnetic field does not experience any force, so we can ignore it.
The component of the velocity perpendicular to the magnetic field experiences a force that causes the particle to move in a circular path.
The magnitude of the velocity component perpendicular to the magnetic field is:
v_perp = v sin θ
v_perp = 2.0 km/s × sin 50°
v_perp = 1.53 km/s
We can convert this to meters per second:
v_perp = 1.53 km/s × 1000 m/km
v_perp = 1530 m/s
The force on the particle due to the magnetic field is:
F = q v_perp B
The mass of the particle is given as 5.0 mg. We can convert this to kilograms:
\(m = 5.0 mg *1 kg / (1000 mg) = 5.0 * 10^{-6} kg\)
The acceleration of the particle is given as \(5.8 m/s^2\). We can substitute these values into the equation F = m a and solve for the magnetic field B:
F = m a
q v_perp B = m a
B = m a / (q v_perp)
Substituting the values we know, we get:
\(B = (5.0 * 10^{-6} kg) *(5.8 m/s^2) / (-4.0 C * 1530 m/s) = 2.56 * 10^{-4} T\)
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Related Questions
The measurement of the work in the English system is in units of
Answers
Answer:
Force is in lbs and distance is in ft.
W = F * d = ft-lbs units of work
(Note - torque = F * R normally torque is specified in "lbs-ft" to distinguish work from torque)
a 500-kg car is parked 20 M away from a 600 kg truck. what is the gravitational force between the two cars? Show the 4 steps.
Answers
Answer:
600 kg
Explanation:
Answer: 5.0025 * 10^-8 N
Explanation:
\(F = \frac{Gm_1m_2}{r^{2} }\)
F = gravitational force
G (is a constant) = 6.67×\(10^{-11}\) N(m/kg)^2
m1 = mass of first object = 500 kg
m2 = mass of second object = 600 kg
r = distance between them = 20 M
\(6.67*10^{-11}N(m/kg)^2* \frac{500 kg*600 kg}{(20m)^2}\\6.67*10^{-11}N*\frac{m^2}{kg^2} * \frac{300000kg^2}{400m^2}\\6.67*10^{-11} N * 750\\5002.5 * 10^{-11} N \\5.0025 * 10^{-8} N\)
a car is traveling at a constant speed of 26 m/s on a highway. at the instant this car passes an entrance ramp, a second car enters the highway from the ramp. the second car starts from rest and has a constant acceleration. what acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.2 km away?
Answers
The second car must maintain an acceleration of approximately -5.68 m/s² (negative sign indicating deceleration) to meet the first car at the next exit.
To determine the acceleration the second car must maintain in order to meet the first car at the next exit, we can use the equations of motion.
Let's define the following variables:
u1: Initial velocity of the first car = 26 m/s
u2: Initial velocity of the second car = 0 m/s (since it starts from rest)
a2: Acceleration of the second car (what we need to find)
s: Distance between the entrance ramp and the next exit = 2.2 km = 2,200 m
We can use the equation of motion to calculate the distance traveled by each car:
For the first car:
s1 = u1 * t
For the second car:
s2 = u2 * t + (1/2) * a2 * \(t^{2}\)
Since we want the two cars to meet at the same time, we can set s1 = s2:
u1 * t = u2 * t + (1/2) * a2 * \(t^{2}\)
Simplifying and rearranging the equation, we have:
(1/2) * a2 * \(t^{2}\) + u2 * t - u1 * t = 0
Now we can solve for the acceleration a2:
(1/2) * a2 * \(t^{2}\) + (u2 - u1) * t = 0
Since the cars meet at the next exit, we can assume they meet after the same time interval t. Therefore, we can cancel out t from the equation:
(1/2) * a2 * t + (u2 - u1) = 0
Solving for a2:
a2 = -2 * (u2 - u1) / t
Plugging in the known values:
a2 = -2 * (0 m/s - 26 m/s) / t
The distance s is covered at a constant speed of 26 m/s, so we can calculate the time t:
t = s / u1
Plugging in the values of s and u1:
t = 2,200 m / 26 m/s
Now we can substitute the value of t back into the equation for a2:
a2 = -2 * (0 m/s - 26 m/s) / (2,200 m / 26 m/s)
Simplifying:
a2 = -2 * (26 m/s)² / (2,200 m)
a2 ≈ -5.68 m/s²
Therefore, the second car must maintain an acceleration of approximately -5.68 m/s² (negative sign indicating deceleration) to meet the first car at the next exit.
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Question 18 of 25 What is the current model of the atom called? O A. Electron cloud model B. Plum pudding model OC. Planetary model O D. Nuclear model
Answers
The current model of the atom is called the electron cloud model or the quantum mechanical mode.
Current model of an atom explained.The current model of the atom is called the electron cloud model or the quantum mechanical model. This model describes electrons as existing in a three-dimensional region around the nucleus called the electron cloud, where the electrons are most likely to be found at any given time. This model incorporates principles of quantum mechanics, which recognizes the wave-particle duality of electrons and the probabilistic nature of their behavior, in contrast to the earlier classical models like the planetary model or the plum pudding model.
Therefore, the nuclear model, which describes the atom as consisting of a central nucleus surrounded by electrons, is a precursor to the modern quantum mechanical model.
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Can someone please answer this, ill give you brainliest Would be very appreciated.
Answers
Answer:
See below ~
Explanation:
ice wedging : mechanical weathering
oxidation : chemical weathering
abrasion : mechanical weathering
plant roots : biological weathering
hydrolysis : chemical weathering
Two Physics professors challenge each other to a 100 m race across the football field. Dr. Rice runs the race in 10.40 seconds. Dr. Lopez runs the first 25 2nd m with an average speed of 10 m/s, the next 50 m with an average speed of 9.50 m/s and the last 25 m with an average speed of 11.1 m/s.
Answers
Answer:
Dr. Rice
Explanation:
For determining who is stuck grading physics labs for the coming month first determine the Dr. De La Paz time taken
= (25 ÷ 10) + (50 ÷ 9.5) + (25 ÷ 11.1)
= 2.5 + 5.26 + 2.25
= 9.51 seconds
And, the Dr Rice runs the race is 10.40 seconds that means he takes more time as compared with the Dr. De La Paz
We simply applied the distance by speed formula so that the time could come
Therefore the Dr. Rice gots stuck
How much work is done by a 10 N frictional force which slows a moving block to a stop after a displace ment of 5.0m to the right?
a) 50J
b) -50J
c) 25J
d) -25J
Answers
Answer:
a)
Explanation:
work done = Fscosθ
=(10)(5)(cos0⁰)
=50J
Perdue Company purchased equipment on October 1 for $54,880. The equipment was expected to have a useful life of three years, or 7,600 operating hours, and a residual value of $1,680. The equipment was used for 1,400 hours during Year 1, 2,700 hours in Year 2, 2,300 hours in Year 3, and 1,200 hours in Year 4. Required: Determine the amount of depreciation expense for the years ended December 31, Year 1, Year 2, Year 3, and Year 4, by (a) the straight-line method, (b) the units-of-activity method, and (c) the double-declining-balance method.
Answers
Depreciation Expense:
(a) Straight-line method:
Year 1: $16,400
Year 2: $16,400
Year 3: $16,400
Year 4: $0
(b) Units-of-activity method:
Year 1: $9,700
Year 2: $19,040
Year 3: $16,320
Year 4: $8,820
(c) Double-declining-balance method:
Year 1: $24,352
Year 2: $14,611
Year 3: $8,767
Year 4: $5,261
(a) Straight-line method:
Determine the straight-line method?In the straight-line method, the depreciable cost is calculated by subtracting the residual value from the initial cost.
The depreciable cost is then divided by the useful life to determine the annual depreciation expense.
In this case, the depreciable cost is $53,200 ($54,880 - $1,680), and since the useful life is three years, the annual depreciation expense is $16,400 ($53,200 ÷ 3).
The same amount is charged as depreciation expense in each year until the residual value is reached.
(b) Units-of-activity method:
Determine the units-of-activity method?The units-of-activity method calculates depreciation based on the actual usage of the equipment.
First, the depreciable cost is determined by subtracting the residual value from the initial cost.
Then, the depreciation cost per unit is calculated by dividing the depreciable cost by the total expected operating hours.
Finally, the depreciation expense for each year is calculated by multiplying the depreciation cost per unit by the actual hours of usage. In this case, the depreciable cost is $53,200, and the total expected operating hours are 7,600.
The depreciation cost per unit is approximately $7 ($53,200 ÷ 7,600). Multiplying this by the actual hours of usage for each year gives the respective depreciation expenses.
(c) Double-declining-balance method:
Determine the double-declining-balance method?The double-declining-balance method uses a fixed percentage that is double the straight-line rate to calculate depreciation.
First, the straight-line rate is determined by dividing 100% by the useful life in years. Then, the double-declining-balance rate is calculated by multiplying the straight-line rate by 2.
The depreciation expense for each year is calculated by applying the double-declining-balance rate to the net book value (initial cost minus accumulated depreciation) at the beginning of the year.
In this case, the straight-line rate is 33.33% (100% ÷ 3), and the double-declining-balance rate is 66.67% (33.33% × 2).
The depreciation expense for each year is determined accordingly.
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a sample of radioactive material emits 400000 particles over a period of 20 minutes calculate the activity of the source in Becquerel
Answers
The activity of the source in Becquerel is 333.3Bq
What is Activity ?The number of nuclei that disintegrate or decay per unit time is known as Activity.
Given that a sample of radioactive material emits 400000 particles over a period of 20 minutes.
N = 400000 particlest = 20 min = 20 x 60 = 1200 sActivity A = dN/dt
A = 400000 / 1200
A = 333.3 particles / s
A = 333.3 Bq
Therefore,
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PLS HELP WILL GIVE BRAINLIEST PLSSSS The equation for the reaction is: Mg(s) magnesium + 2 HCl(aq) hydrochloric acid MgCl2(aq) magnesium chloride + H2(g) hydrogen The student investigated how the rate of this reaction changed when the concentration of hydrochloric acid was changed. Write a plan the student could use. In your plan you should: • describe how you would carry out the investigation and make it a fair test • describe the measurements you would make.
Answers
Answer:
50 cm3 of 1M hydrochloric acid is a six-fold excess of acid. In this reaction, the magnesium and acid are gradually used up. However the acid is in excess, so it is mainly the loss of magnesium (surface area becomes smaller) that causes the change in the rate.
Explanation:
The equation for the reaction is: magnesium + hydrochloric acid → magnesium chloride + hydrogen
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
Students follow the rate of reaction between magnesium and the acid, by measuring the amount of gas produced at 10 second intervals.
3 cm of magnesium ribbon typically has a mass of 0.04 g and yields 40 cm3 of hydrogen when reacted with excess acid. 50 cm3 of 1M hydrochloric acid is a six-fold excess of acid.
In this reaction, the magnesium and acid are gradually used up. However the acid is in excess, so it is mainly the loss of magnesium (surface area becomes smaller) that causes the change in the rate.
If a graph of volume (y-axis) against time (x-axis) is drawn, the slope of the graph is steepest at the beginning. This shows that the reaction is fastest at the start. As the magnesium is used up, the rate falls. This can be seen on the graph, as the slope becomes less steep and then levels out when the reaction has stopped (when no more gas is produced).
The reaction is exothermic, but the dilute acid is in excess and the rise in temperature is only of the order of 3.5˚C. There is some acceleration of the reaction rate due to the rise in temperature. Some students might notice the flask becoming slightly warm and they could be asked how this would affect the rate of reaction, and how they might adapt the experiment to make it a ‘fair test’.
Additional information
This is a resource from the Practical Chemistry project, developed by the Nuffield Foundation and the Royal Society of Chemistry. This collection of over 200 practical activities demonstrates a wide range of chemical concepts and processes. Each activity contains comprehensive information for teachers and technicians, including full technical notes and step-by-step procedures. Practical Chemistry activities accompany Practical Physics and Practical Biology.
To solve this we must be knowing each and every concept related to Le Chatelier′s Principle. Therefore, when concentration of hydrochloric acid was changed. the concentration of product will also change.
What is Le Chatelier′s Principle?When a stress is given to a chemical system in equilibrium, the equilibrium shifts to alleviate the tension, according to Le Chatelier′s Principle. In other words, it can anticipate the outcome of a chemical reaction with response to changes in temperature, concentration, quantity, or pressure.
While Le Chatelier's concept can be used to anticipate the reaction to a change from equilibrium, it doesn't explain why the system behaves as it does (at the molecular level).
Mg(s) + 2 HCl(aq) \(\rightarrow\) MgCl\(_2\)(aq) + H\(_2\)(g)
According to Le Chatelier′s Principle, when concentration of hydrochloric acid was changed. the concentration of product will also change.
Therefore, when concentration of hydrochloric acid was changed. the concentration of product will also change.
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Suppose the airplane in the preceding problem fires a projectile horizontally in its direction of motion at a speed of 300 m/s relative to the plane. (a) How far in front of the release point does the projectile hit the ground? (b) What is its speed when it hits the ground?
Answers
Answer:
a) s = 5619.2 m
b) v = 456.5 m/s
Note: The preceding question is given below:
An airplane flying horizontally with a speed of 500 km/h at a height of 800 m drops a crate of supplies (see the following figure). If the parachute fails to open, how far in front of the release point does the crate hit the ground?
Explanation:
From the preceding question;
height, h = 800 m,
speed of plane = 500 km/h = 500000 m / 3600 s = 139 m/s
Speed of projectile = 139 m/s + 300 m/s = 439 m/s
a) using h = ut + 1/2 * gt² = 1/2 gt² (sice u = 0)
t = √(2h/g) where g = 9.8 m/s²
t = √(2 * 800/9.8)
t = 12. 8 s
horizontal distance, s = horizontal velocity * time
s = 439 * 12.8
s = 5619.2 m
b) Final vertical velocity v₂ = u - gt
v₂ = 0 - 9.8 * 12.8 = 125.4 m/s
horizontal velocity, vₓ = 439.0 m/s
resultant velocity, v = √(v₁² + vₓ²)
v = √{(125.4)² + (439.0)²}
v = 456.5 m/s
HELP!!
8. The speed that the car is going at an instant of time is called the (5 points)
average speed
final speed
initial speed
instantaneous speed
Answers
Answer:
the speed that the car is going at an instant of time is called the instantaneous speed.
Hope this helps.
The body can get water from milk, juices, fruits, and vegetables.
Answers
Answer: yes it can but not enough to stay hydrated and keep your body going but you cant get water from milk lol
Explanation: hope this helpes
Answer:
Yes This would be True hope this helps
Explanation:
What process involves heavier atoms breaking down into lighter atoms?
Answers
Answer:
Fission occurs when a neutron slams into a larger atom, forcing it to excite and split into two smaller atoms—also known as fission products. Additional neutrons are also released that can initiate a chain reaction. When each atom splits, a tremendous amount of energy is released.
Explanation:
Answer:
Fission
Explanation:
this happens when the neutrons an atoms slams into a larger atom, forcing it to split into two smaller atoms
CA-Common Core English Language Arts 9 A
Answers
Answer:
The standards establish guidelines for English language arts (ELA) as well as for literacy in history/social studies, science, and technical subjects.
Explanation:
Answer:
A
Explanation:
PLEASE HELP ASAP I AM GIVING 30 POINTS PLEASE HELP
Answers
conservation of momentum: you are standing on a skateboard, initially at rest. a friend throws a very heavy ball towards you. you can either catch the object or deflect the object back towards your friend (such that it moves away from you with the same speed as it was originally thrown). what should you do in order to minimize your speed on the skateboard?
Answers
Conservation of momentum is a fundamental law in physics, which states that in a closed system, the total momentum remains constant. In the given scenario, if you catch the ball, the momentum of the system will change as you and the skateboard will start moving in the opposite direction to compensate for the momentum of the ball. On the other hand, if you deflect the ball back towards your friend, the momentum of the system will remain constant, but the direction of the momentum will change. In order to minimize your speed on the skateboard, it is recommended to deflect the ball back towards your friend. By doing so, the momentum of the system will remain constant, and the skateboard's speed will not increase. However, it is essential to ensure your safety and take precautions while performing such an experiment.
Hi there! To minimize your speed on the skateboard, you should deflect the object back towards your friend. Let me explain using conservation of momentum:
1. Initially, both you and the skateboard are at rest, so your total momentum is 0.
2. When the heavy ball is thrown towards you, it has a certain momentum (mass of ball × speed).
3. Conservation of momentum states that the total momentum before and after an interaction must be equal.
If you catch the ball, the momentum of the ball will be transferred to you, causing you and the skateboard to move at a higher speed. On the other hand, if you deflect the ball back with the same speed, the ball's momentum will be reversed in direction but maintain the same magnitude.
In this case, your final momentum will be the opposite of the ball's momentum, making the total momentum still 0. Therefore, deflecting the ball back towards your friend will minimize your speed on the skateboard.
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A table exerts a force on the ground. The ground exerts
A. no force on the table
B. a greater and opposite force on the table
C. an equal and opposite force on the table
D. a lesser an opposite force on the table
Answers
Answer:
hey from what I know the answer is C
Explanation:
When a book is kept on a table , weight (gravitational force) of book acts on table vertically downwards and as a reaction of weight , table also exerts an equal and opposite ( upward) force on book .
When using presentation aids, you should always remember __________; if something can go wrong, it will. Group of answer choices
Answers
When using presentation aids, you should always remember Murphy's Law what: if something ca go wrong with it, option B.
You are now in the realm of Murphy's Law. The law is extremely optimistic, stating that anything that can go wrong will. In any case, on the off chance that it can't turn out badly, it will turn out badly. Murphy's Law is based on this fundamental idea. "Anything that can go wrong will go wrong," says Murphy's Law.
Another supposedly original and accurate interpretation of Murphy's Law holds that if there are two or more ways to do something and one of them could lead to disaster, someone will do it. Yet, the explanation that best communicates the touchy idea of Murphy's Regulation is without a doubt the possibility that you will definitely pursue some unacceptable decision anything you choose, and it might simply be correct. This is not due to some enigmatic power that the law possesses.
As a general rule, we can give significance to Murphy's Regulation in our everyday life. The good times are rarely talked about. After all, we hope that everything will go our way. However, when things go wrong, we look for reasons. Thoughtful though it may be, Murphy's Law as a whole is based solely on perception, and there is no evidence to support it. We are captivated by the law.
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Complete question:
when using presentation aids, you should always remember ______ what: if something ca go wrong with it.
Logos
Murphy's Law
physiological
dynamism
What is the mechanical advantage of a wedge, with input force of 2.4 N and output force of 5.3 N
Answers
Answer:
approx. 2.21
Explanation:
5.3/2.4 = 2.208
Cedric and Insha solved the same equation using the calculations below.
Cedric’s Work
Insha’s Work
z minus 4.5 = negative 1.5. z minus 4.5 + 4.5 = negative 1.5 + 4.5. z = 3.
z minus 4.5 = negative 1.5. z minus 4.5 + (negative 4.5) = negative 1.5 + (negative 4.5). z = negative 6.
Which statement is true about their work?
Cedric is correct because he used the inverse of subtraction and added 4.5.
Cedric is incorrect because he should have subtracted 4.5 from both sides instead of adding.
Insha is correct because she added the opposite if 4.5, which is Negative 4.5, to both sides.
Insha is incorrect because she did not add Negative 1.5 + (negative 4.5) correctly.
Answers
Answer:
Explanation:
Cedric is correct because he used the inverse of subtraction and added 4.5
How is the speed trap gun used to measure speed?
Answers
Answer:
the speed of light, the difference in frequency between the radio waves that receive back by the gun.
Explanation:
Jason throws a ball horizontally off a 300 meter cliff at 15.0 m/s. How far will it travel before it hits the
ground? Use significant figures, and estimate g to be equal to 9.81 m/s2. Round the answer to the nearest
hundredth.
117.30 m
B
130.80 m
с
51.80 m
D
101.70 m
Answers
Answer:
117,30m
Explanation:
I think the situation here is a horizontal projection to the ground. So in order to find the distance the formula = Ut, where U is the initial speed and t is the Time of flight. To get the time of flight in this case =√2h/g where h is the height and g is gravity. so to get the time = √2×300÷9.81 =7.821 .so range =ut which is equal to the time multiplied by 15m/s =117.30m
Hi there!
To find the total distance traveled, we must find the time taken to fall down.
Ignore the horizontal velocity when dealing with the vertical direction. We can use the simplified equation:
\(t = \sqrt{\frac{2h}{g}{}}\)
Plug in the given values:
\(t = \sqrt{\frac{2(300)}{9.81}} = 7.821 sec\)
Use the equation:
Δd = vt
Plug in the time and horizontal velocity:
Δd = (15)(7.821) = 117.30m
Write AT LEAST 10 SENTENCES based on ONE event that has happened in your life.
Please do it am so tired
Answers
Sorry your tired, ill try to make it worth reading.
One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.
If a force is exerted on an object, which statement is true?
A. A large force always produces a large change in the object’s momentum.
B. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval
C. A small force applied over a long-time interval can produce a large change in the object’s momentum
D. A small force produces a large change in an object’s momentum.
Answers
Answer:
B. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.
Explanation:
This statement aligns with Newton's second law of motion, which states that the change in momentum of an object is directly proportional to the force applied and occurs in the direction of the force, and is inversely proportional to the time over which the force is applied. Therefore, a large force applied over a very short time interval can result in a large change in the object's momentum, while a small force applied over a long time interval may not produce a significant change in the object's momentum.
Derive a relation for time period of simple pendulum from dimensional method
Answers
The time period of simple pendulum is 2xpi x (l/g)^1/2 when derived by dimensional method.
What is dimensional method and time period of simple pendulum?Dimensional method is a phenomena we use to derive by using the dimensions of the components given.Here the relation of the time period is 2 pi (l/g)^1/2 where l is the length of the pendulum , g is the gravity.Let 't' the time period be directly proportional to m^a l^b g^c where a, b , c are dimensions.We will us the principle of homogeneity of dimensions to solve this.a= 0b + c = 0 , using this method we calculate the value of dimensionless constant k = 2 pi , t= 2 pi (l/g)^1/2.To know more about dimension visit:
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In the the table there is 20 kj of coal, how much energy in joules is 1g of coal?
Answers
Answer:
what do u meN by this i really don't know
TRUE/FALSE. thomas edison was not motivated by profits: his inventions were for pure scientific understanding only.
Answers
Answer:
false
Explanation:
questions with the words "all/only" are usually too generalized
A. Which law is being demonstrated?
Answers
Answer:
There is no law being shown for us to see.
Explanation:
Can you attach something for us to see?
Please help me please I need someone to help me with all this question 1) How do we calculate the momentum of a race car? What part of this changes during a collision? 2) What happening to the momentum of the car when they crash? 3) how does impulse factor into this? 4) what type of collision is it ( ideally) when cars crash into this SAFER barrier?
Answers
Answer:
Explanation:
1 ) Momentum of a race car = mass of car x velocity of car . During a collision , an external force acts on the car which changes the momentum of the car in the direction in which force acts .
2 )
The momentum of the car decreases as external force acts against the momentum . Sometimes when external force is very high , direction of momentum is reversed .
3 ) Impulse is force x time of action of force . Generally time of action of force in large collision is very small . so it is calculated very carefully .
Impulse = change in momentum .
4 ) The type of collision is inelastic . In this type of collision , car crashes into safer barrier , sticks to it . It does not rebound from the barrier . In case of elastic collision , rebound creates large impulse creating huge damage to the car .