Pipe of constant radius, we can use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at two points in a flow system.the pressure of water in the pipe is approximately 105,142 Pa.
What is a system?System refers to a collection of related components or parts that work together to achieve a specific goal or purpose. The concept of a system can be applied to a wide range of fields and disciplines, including science, engineering, economics, and social sciences.
In science, a system is often defined as a portion of the universe that is being studied or analyzed. This can include anything from a single atom or molecule to an entire ecosystem or planet. By defining the boundaries of a system, scientists can focus their attention on understanding the interactions and relationships between the various components within that system.
In engineering, a system refers to a collection of components that are designed to work together to perform a specific function or task. This can include everything from simple mechanical systems like gears and pulleys to complex electrical or computer systems.
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what are the factors affecting center of mass in an object
A 3.5 kilogram cannon is loaded with a 0.52-kilogram ball. The cannon and ball are initially rolling forward with a speed of 1.27 m/s. The cannon is fired and launches the ball forward with a total speed of 75 m/s. Determine the post-explosion velocity of the cannon.
As a result, the cannon's post explosion velocity is -0.68 m/s, which indicates that it is moving backwards at a rate of 0.68 m/s.
What is the formula for the cannon ball's range?y(t)=−12gt2+sin(θ)stx(t)=cos(θ)st. Thus, the ball's range, or the value of x when y=0, is the horizontal distance it travels before contacting the ground.
Utilizing momentum conservation, we can find a solution to this issue. Prior to the explosion, the system's (cannon and ball) momentum is:
p_before = (m_cannon + m_ball) * v_before
Following the explosion, the system's momentum is:
p_after = m_cannon * v_cannon + m_ball * v_ball
Because momentum is conserved, we can state:
p_before = p_after
Substituting the expressions for p_before and p_after, we get:
(m_cannon + m_ball) * v_before = m_cannon * v_cannon + m_ball * v_ball
Now, we can solve for v_cannon:
v_cannon = (m_cannon + m_ball) / m_cannon * v_before - m_ball / m_cannon * v_ball
Substituting the given values, we get:
v_cannon = (3.5 + 0.52) / 3.5 * 1.27 - 0.52 / 3.5 * 75
v_cannon = -0.68 m/s
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2. A 6.0 kg mass is pulled along a horizontal surface where the coefficient of friction is 0.20.
a) What is the friction force acting on the mass?
b) What force is needed to accelerate it at 0.68 m/s^(2)?
Answer:
Below
Explanation:
a) To find the force of friction acting on the mass we can use this formula :
friction = coefficientoffriction x normal force
First we need to find the normal force of this object :
Fn = mg
= (6.0)(9.8)
= 58.8 N
Now we can find the force of friction acting on the object :
friction = (0.20)(58.8N)
= 11.76 N
= 12 N (we round this to 2 sig figs)
b) To find the force needed to accelerate this object at 0.68 m/s^2 use this :
F = ma
0.68 = x - 11.76 / 6
x = 15.84
x = 16 N
Hope this helps! Best of luck <3
Find the magnitude of the resultant of forces 6N and 8N acting at 240° to each other
Answer:
magnitude of the resultant of forces is 11.45 N
Explanation:
given data
force F1 = 6N
force F2 = 8N
angle = 240°
solution
we get here resultant force that is express as
F(r) = \(\sqrt{F_1^2+F_2^2+2F_1F_2cos\ \theta}\) ..............1
put here value and we get
F(r) = \(\sqrt{6^2+8^2+2\times 6\times 8 \times cos240}\)
F(r) = 11.45 N
so magnitude of the resultant of forces is 11.45 N
What did Hubble discover about the universe?
A. That it is expanding.
B. None of these
C. That it is smaller than previously thought.
D. That it is shrinking.
Answer:
A. That it is expanding.
A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slowing down at 2.0 m/s2?
Answer:
360 N
Explanation:
m = 30kg u = 2 m/s a = -2m/s/s
Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s
the object will come to rest in 1 second but the force applied in that one second can be calculated by:
F = ma
F = 30 * -2
F = -60 N (the negative sign tells us that the force is acting downwards)
Now, calculating the force applied on the box due to gravity
letting g = -10m/s/s
F = ma
F = 30 * -10
F = -300 N (the negative sign tells us that the force is acting downwards)
Now, calculating the total downward force:
-300 + (-60) = -360 N
Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction
Therefore tension on the force = 360 N
A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.
The acceleration of this sled can be calculated by doing: option A, B, E and F.
How to calculate the acceleration?The acceleration of this sled can be calculated by using Newton's Second law of motion. Mathematically, the acceleration of an object is given by this formula:
Net force = Mass × acceleration
Deductively, the acceleration of this sled can be calculated by doing the following:
The force of gravity must be broken into its parallel and perpendicular components.Acceleration can be found by dividing the net force by mass.Trigonometry can be used to solve for the magnitude of the force components.Net force must be found before acceleration can be found.Read more on acceleration here: brainly.com/question/14344386
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Complete Question:
A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.
A. The force of gravity must be broken into its parallel and perpendicular components.
B. Acceleration can be found by dividing the net force by mass.
C. Acceleration can be found by multiplying the net force by mass.
D. The magnitude of the force components must be multiplied by gravity.
E. Trigonometry can be used to solve for the magnitude of the force components.
F. Net force must be found before acceleration can be found.
Answer:
To find the acceleration, you do 20N/50kg = 0.4 m/s^2
Explanation:
example: a = F/m = 10/2 = 5 m/s2
5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?
The traffic cop needs 23.3 seconds to pass the automobile.
What is the acceleration of a car moving in a straight line at a constant speed?When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.
\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)
\(d = d1 = 35.0 m\)
\(d2 = v2*t + (1/2)at^2\)
\(d2 = (1/2)at^2\)
\(v2*t + (1/2)at^2 = (1/2)at^2\)
\(v2*t = (1/2)at^2\)
Solving for t, we get:
\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)
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If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial speed of 5 m/s, the snowboarder is moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on planet Epsilon, where gravity is less than gravity on earth.
A. Would the height of the hill on Epsilon cause a reduction in speed from 4 m/s to 0 greater than, less than, or equal to the height of the corresponding hill on earth? Explain.
B. Consider the hill on Epsilon discussed in part A. If the initial speed at the bottom of the hill is 5 m/s, will the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain.
(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
Conservation of mechanical energy
The effect of height and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;
ΔK.E = ΔP.E
¹/₂m(v²- u²) = mg(hi - hf)
¹/₂(v²- u²) = g(0 - hf)
v² - u² = -2ghf
v² = u² - 2ghf
where;
v is the final velocity at upper levelu is the initial velocityhf is final heightg is acceleration due to gravitywhen u² = 2gh, then v² = 0,
when gravity reduces, u² > 2gh, and v² > 0
Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
Final speedv² = u² - 2ghf
where;
u is the initial speed = 5 m/sg is acceleration due to gravity and its less than 9.8 m/s²v is final speedhf is equal heightSince g on Epislon is less than 9.8 m/s² of Earth;
5² - 2ghf > 3 m/s
Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
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How does the comet's energy change as it moves from point B to point C?
A. KE increases, GPE increases
B. KE increases, GPE decreases
C. KE decreases, GPE increases
D. KE decreases, GPE decreases
Need it asap please help me thanks in advance just trying to pass my senior year :)
Option C. KE decreases, GPE increases
What is the GPE of the comet?The GPE of the comet is given by, U(r) = -GMm/r, where M is the mass of the sun, and m is the mass of the comet.
The total energy E of the comet remains constant.
We know, E = K + U ⇒ K = E - U. So, if U increases K decreases.
As the comet moves from B to C, the distance r between the comet and the sun increases.
When r increases U(r) increases according to the above equation, it becomes more positive. So, the GPE of the comet increases as it moves from B to C. KE, according to the energy relation, thus, decreasing during the same course of motion.
Therefore, as the comet moves from B to C, its KE decreases, and its GPE increases.
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Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2
The molecules of O2 that are present in 3.90 L flask at a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules of O2
Step 1: used the ideal gas equation to calculate the moles of O2
that is Pv=n RT where;
P(pressure)= 1.00 atm
V(volume) =3.90 L
n(number of moles)=?
R(gas constant) = 0.0821 L.atm/mol.K
T(temperature) = 273 k
by making n the subject of the formula by dividing both side by RT
n= Pv/RT
n=[( 1.00 atm x 3.90 L) /(0.0821 L.atm/mol.k x273)]=0.174 moles
Step 2: use the Avogadro's law constant to calculate the number of molecules
that is according to Avogadro's law
1 mole = 6.02 x10^23 molecules
0.174 moles=? molecules
by cross multiplication
the number of molecules
= (0.174 moles x 6.02 x10^23 molecules)/ 1 mole =1.047 x 10^23 molecules of O2
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A football is kicked from the ground with a speed of 30 m/s at an angle of 60º with the ground. What is the horizontal component of the football immediately after it is kicked?
a
30 m/s
b
30 tan(60º) m/s
c
30 sin(60º) m/s
d
30 cos(60º) m/s
Answer:
D
Explanation:
30 m/s is the hypothenuse. The horizontal component will be x. Using trig, you can see that
\(cos(angle) = \frac{x}{hypotenuse} \)
Hello, please help!
Physics teacher asked us to answer and give explanation to why:
Can light bend around corners?
THNX SO MUCH
Answer:
Yes, light can bend around corners.
Explanation: In fact, light always bends around corners to some extent. This is a basic property of light and all other waves. The amount of light that bends around a corner depends on the exact situation.
Thanks for asking the question!!
how would you define an ocean current?
Answer:
i would describe an ocean current like a pull of the water
Explanation:
water
write an expression whose value is the character at index 3 of the str associated with s.
s[3] is an expression whose value is the character at index 3 of the str associated with s.
What string method can be used to check whether the text variable's string only contains letters?
Checking whether a string only contains alphabetical characters requires the use of the Python isalpha() string method. I.e., isalpha() determines whether a string is composed entirely of letters.
The indexOf() method searches the entire calling string for the specified substring with such a single argument of a substring to look for and returns the index of the first occurrence.
Therefore, The value of the expression s[3] is the character found at index 3 of the str linked to s.
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Solar____is the energy output from the sun
Answer:
Solar energy? Solar rays? Solar Power?
Explanation:
not too sure what you mean, its kinda in the sentence. lmk if you need any help however
Answer:
Solar system is the energy output from the sun
When an element ejects an alpha particle, the mass number of that element
A.reduce by 4.
B.remains unchanged.
C.increase by 1.
D. reduce by 1.
Answer:
A.reduce by 4.
Explanation:
In Chemistry, an alpha particle which is typically a helium nucleus has an atomic mass (number of nucleons) of four (4). Therefore, the ejection of an alpha particle by any chemical element simply means that, the mass number of that particular chemical element would be reduced by four (4).
Basically, this process is referred to as an alpha decay and can be defined as a radioactive disintegration of a chemical element that causes it to emit an alpha particle and as a result reducing its mass number by four (4).
Hence, when an element ejects an alpha particle, the mass number of that element reduces by 4.
You have two contentious friends, Chris and Pat, and you’ve quickly discovered that they need you to resolve arguments they have about physics concepts. Chris says, "The spacing between two dots tells you the speed at the time of the first dot," but Pat says, "The spacing tells you the speed at the time of the second dot. How do you resolve this debate?"
Answer:
v_average = (d₂-d₁) / Δt
this average velocity is not necessarily the velocity of the extreme points,
Explanation:
To resolve the debate, it must be shown that the two have part of the reason, the space or distance between the two points divided by time is the average speed between the points.
v_average = (d₂-d₁) / Δt
this average velocity is not necessarily the velocity of the extreme points, in the only case that it is so is when there is no acceleration.
Therefore neither of them is right.
A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 60 m/s and 80 m/s, respectively. (a) Determine the initial speed of the projectile. (b) At what angle is the projectile fired (measured with respect to the horizontal)
This question involves the concepts of projectile motion and launch speed.
(a) The initial launch speed of the projectile is "100 m/s".
(b) The launch angle of the projectile is "53.13°".
(a) LAUNCH SPEEDA projectile motion is a motion that takes place on both x and y axes, simultaneously. In this motion the initial launch speed is given by the following formula:
\(v_o=\sqrt{v_{ox}^2+v_{oy}^2}\)
where,
\(v_o\) = initial launch speed = ?\(v_{ox}\) = horizontal component of initial launch speed = 60 m/s\(v_{oy}\) = vertical component of initial launch speed = 80 m/sTherefore,
\(v_o = \sqrt{(60\ m/s)^2+(80\ m/s)^2}\\\\v_o = 100 m/s\)
(b) LAUNCH ANGLELaunch angle is given by th following formula:
\(\theta = tan^{-1}(\frac{v_{oy}}{v_{ox}})=tan^{-1}(\frac{80\ m/s}{60\ m/s})\\\\\theta=53.13^o\)
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Which description accurately describes the tide represented by the image below? (4 points)
Image of the sun and moon at a 90 degree angle to Earth. An oval is around Earth that points toward and away from the moon to show the tidal bulges.
High tides occur when the sun and moon are at right angles to one another.
Low tides occur when the sun and moon are at right angles to one another.
The gravitational pull of the sun and moon combined creates larger than normal tides.
The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides.
High tides occur when the sun and moon are at right angles to one another. This is because the gravitational pull of the moon and the sun combine to create larger-than-normal tides, known as spring tides. The correct option is A.
Gravitational pull is the force of attraction that exists between two objects with mass. The greater the mass of an object, the greater its gravitational pull.
Option B, "Low tides occur when the sun and moon are at right angles to one another," is incorrect. Low tides occur when the sun and moon are at a 90-degree angle (or "quarter moon") to each other, but this position also results in high tides on the opposite side of the Earth.
Option C, "The gravitational pull of the sun and moon combined creates larger than normal tides," is partially correct. The gravitational pull of both the sun and moon does contribute to the tides, but the specific position depicted in the image (sun and moon at right angles to each other) does not necessarily create larger than normal tides.
Option D, "The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides," is also incorrect. The sun's gravitational pull does have an effect on the tides, but it does not reduce the moon's gravitational pull. Rather, the combined gravitational pull of the sun and moon creates the tides we observe.
Therefore,The accurate description of the tide represented by the image below is option A: "High tides occur when the sun and moon are at right angles to one another."
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a ball is thrown horizontally from a height of 1 m and lands 5 m away
Answer:
it's from gravity because when you throw something up it goes forward a certain distance
Season and date for this person
Answer:
summer June 21 is the answer
A sprinter starting to run from rest, reaches a speed of 8m/s in 2 second, what is the average power needed to accelerate like this ?
Answer:
okay
Explanation:
power is rate of doing work
power is workdone over time taken
but you don't have information concerning the force
Power = work/time
Work = force x distance
Force = mass x acceleration
So Power = (mass x acceleration x distance) / (time)
acceleration = 8m/s / 2sec = 4 m/s²
distance = (avg speed) x (time) = 8 m
time = 2 sec
we don't know the runner's mass
Power = (mass) x (4 m/s²) x (8 m) / (2 sec)
Power = (16 x mass in kg) watts
=============================================
Slightly easier way to do it:
Power = (runner's kinetic energy at the end) / (time)
Power = (1/2 m v²) / (time)
Power = (1/2 mass) (64 m²/s²) / (2 sec)
Power = (16 x runner's mass in kg) watts
I WILL GIVE BRAINLIEST Identify two types of motion where an object's speed remains the same while it continues to change direction
Answer:
velocity and acceleration
Answer:
Hey there!
Centripetal (Circular Motion) and Oscillating Motion.
Let me know if this helps :)
a 250 mH coil of negligible resistance is connected to an AC circuit in which as effective current of 5 mA is flowing. if the frequency is 850Hz, find the inductive reactance
Answer:
the inductive reactance of the coil is 1335.35 Ω
Explanation:
Given;
inductance of the coil, L = 250 mH = 0.25 H
effective current through the coil, I = 5 mA
frequency of the coil, f = 850 Hz
The inductive reactance of the coil is calculated as;
\(X_l = \omega L = 2\pi f L\\\\X_l = 2\pi \times 850 \times 0.25\\\\X_l = 1335.35 \ ohms\)
Therefore, the inductive reactance of the coil is 1335.35 Ω
Two blocks of masses 1.0 kg and 2.0 kg, respectively, are pushed by a constant applied force F across a horizontal frictionless table with constant acceleration such that the blocks remain in contact with each other, as shown above. The 1.0 kg block pushes the 2.0 kg block with a force of 2.0 N. The acceleration of the two blocks is
0
1.0 m/s2
1.5 m/s2
2.0 m/s2
3.0 m/s2
Answer:
1.0 m/s^2
Explanation: happy to help :)
Answer: \(1\ m/s^2\)
Explanation:
Given
Masses of the block are \(m_1=1\ kg\) and
\(m_2=2\ kg\)
Force applied by \(1\ kg\) block on \(2\ kg\) block is \(2\ N\)
From the free body diagram of \(2\ kg\) block, the net force on
\(\therefore m_2a=2\\\\\Rightarrow 2\times a=2\\\\\Rightarrow a=\dfrac{2}{2}\\\\\Rightarrow a=1\ m/s^2\)
Thus, the acceleration of two blocks is \(1\ m/s^2\)
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3. Find the weight of ethanol that is inside a cylindrical can of diameter 5cm and a height of 50mm. The density of ethanol is 0.81 x 10 kg/m³
To convert this computed volume from mL to L, simply divide the provided quantity of ethanol by its density: 500g(mL0.789g)(L1000mL)=0.633L. 500g(mL0.789g)(L1000mL) = 0.633L.
Is ethanol bad for people?Ingestion, inhalation, and skin absorption of ethanol are all dangerous. Frequent contact can cause the skin to become dry, which can cause it to become itchy, crack, and peel. The central nervous system, the eyes, and the upper respiratory tract can all be affected by ethanol.
Is ethanol a synonym for alcohol?The term "alcohol" refers to a wide variety of compounds that are created when one atom of carbon interacts with oxygen, hydrogen, and other atoms. Yet, all alcohol in alcoholic beverages is a particular little molecule known as ethanol.
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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A person throws a 0.21-kg ball straight up into the air. It reaches a height of
10 m. What is the force on the ball as it begins to fall? (The acceleration due
to gravity is 9.81 m/s².)
A. 2.06 N
B. 4.32 N
C. 1.18 N
OD. 4.67 N
Answer:
A
Explanation:
As it begins to fall
F = ma a = 9.81
F = .21 * 9.81 = 2.06 N
The definition of force in physics is the push or pull on a massed object that changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. The correct option is A.
Force is a physical factor that alters or has the potential to alter an object's state of rest or motion as well as its shape. Newton is the SI unit of force.
One of the most fundamental types of physical entities is the force. Due to the fact that force is a vector quantity, it possesses both a magnitude and a direction. Frictional force and contact force are the two categories under which all forces can be classified.
F = m × a
F = 0.21 × 9.81
F = 2.06 N
Thus the correct option is A.
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I need help
Pls for me