The actual volume of water measured out is 10.01 ml.
Volume of water measured out=10ml ,Mass of this volume of water=9.990g, Density of water=0.9978g/ml.
Density (volumetric mass density or specific mass) is the substance's mass per unit of volume. The density of a material varies with temperature and pressure. This variation is typically small for solids and liquids but much greater for gases.
Density = Mass / Volume
Volume = Mass / Density
Volume = 9.990 g / 0.9978 g/ml=10.01 ml
Thus, the actual volume of water measured out is 10.01 ml.
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please Help and Thanks!
1 gallon = 4 q
1 quart = 946
27 g/l to lb/grams
We are asked to convert 1 quart from grams/liters to pounds/grams. Given that 1 gallon is equal to 4 quarts, we can start by determining the equivalent value of 1 gallon.
To do this, we multiply 4 quarts by the conversion factor of 946.27 grams/liter as follows:
1 gallon = 4 quarts
1 gallon = 4 x 946.27 g/l
1 gallon = 3,784.08 g/l
Next, we can convert this value from grams/liter to pounds/grams. To do this, we need to use the conversion factor of 0.00220462 pounds/gram.
Therefore: 1 gallon = 3,784.08 g/l
1 gallon = 3,784.08 x 0.00220462 lbs/g
1 gallon = 8.3454 lbs
Therefore, 1 gallon is equal to 8.3454 pounds.
Now, we can determine the equivalent value of 1 quart by dividing 1 gallon by 4.1 quart = 1/4 gallon1 quart
= 1/4 x 8.3454 lbs
1 quart = 2.08635 lbs
Finally, we can convert this value from pounds to grams using the conversion factor of 453.592 grams/pound.
1 quart = 2.08635 lbs
1 quart = 2.08635 x 453.592 g/l
1 quart = 944.19 g
Therefore, 1 quart is equal to 944.19 grams.
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Fill in the words to complete each step in liquid spill cleanup. 1 cover the spill. 1. Surround the area with ____ absorbent material 2. Scoop up the material and place in a ____ 3. Place the bagged waste in a ____ 4. Wipe down the area with _____
The words to complete the sentence are :
1) he Absorbent material
2) The Plastic bag
3) The solid waste container
4) The Detergent and the water
The complete sentences in the spill cleanup are :
1) The step in liquid spill cleanup.
Surround the area with "Absorbent material", then cover the spill.
2) The step in liquid spill cleanup.
Scoop up the material and place in a "plastic bag".
3) The step in liquid spill cleanup.
Place the bagged waste in a "solid waste container".
4) The step in liquid spill cleanup.
Wipe down the area with "detergent and the water".
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How many molecules are present in a sample that is 89 g of H2O?
\(\qquad\)\( \pink{\bf\longrightarrow { Molar \:mass \:of \:H₂O:-} }\)
\(\qquad\)\( \sf \longrightarrow 1\times +16\)
\(\qquad\)\( \sf \longrightarrow 18g\)
\(\qquad\)____________________
Let's calculate the number of moles present in 89g of H₂O.
\(\qquad\)\( \purple{\bf\longrightarrow { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}\)
\(\qquad\)\( \sf \longrightarrow \dfrac{89}{18}\)
\(\qquad\)\( \sf \longrightarrow 4.94\: moles\)
We know –
Avogadro number = 6.022×10²³Number of molecules:-
\(\qquad\)\( \purple{\bf \longrightarrow No \: of \: moles \times Avogadro \: number}\)
\(\qquad\)\( \sf \longrightarrow 4.94×6.022×10²³\)
\(\qquad\)\( \sf \longrightarrow 2.98 ×10²⁴\)
\(\qquad\)\(\purple{ \bf \longrightarrow 2.98×10²⁴ molecules}\)
Thus, 2.98×10²⁴ molecules are there in 89g of H₂O.\(\qquad\)____________________
A student accurately measured the volume of a solution, but spilled some before measuring solution mass. What is the effect on calculated solution density?
The calculated solution density is lower than the actual density
The predicted mass of the solution will fall short of the actual mass of the solution if the student spilled part of the solutions prior to taking the mass measurement.
What is the solution's total mass?After we have the masses of the solute and solvent, we may add them to determine the mass of both the solution. Masses are always additive. Hence, we may determine the solution's density by knowing its mass and volume.
What are the meanings of the terms "solute" and "solution mass"?Mass or moles are used to describe the solute's concentration. A solution's mass percent is computed by dividing the grams of component per grams of solutions by 100 to arrive at the percentage. The mass of each element in a mole of the compound as well as its molar mass are both solved by using the Mass Percent formula.
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Which of the following statements correctly describe the procedure for drawing a Lewis structure? (Select all that apply.)
a. A single bond, which represents 2 electrons, should be placed between every two atoms.
b. Nonbonding electrons should be excluded from the Lewis structure.
c. For a neutral molecule the sum of the number of valence electrons for each atom gives the number of electrons used in the Lewis structure. d. Halogen atoms are usually places at the center of the structure.
e. An electron is added to the total count for each negative charge on the species
The correct statements that describe the procedure for drawing a Lewis structure are:
c. For a neutral molecule, the sum of the number of valence electrons for each atom gives the number of electrons used in the Lewis structure.
e. An electron is added to the total count for each negative charge on the species.
a. This assertion is untrue. If two atoms are joined by a bond, a single bond representing two electrons should be placed between them; however, not every pair of atoms in the Lewis structure must be linked by a connection.
b. This assertion is untrue. Since they increase the number of valence electrons and have an impact on the overall structure, nonbonding electrons, sometimes referred to as lone pairs, should be included in the Lewis structure.
d. This assertion is untrue. Halogen atoms are typically not positioned in the structure's center. The arrangement of formal charges of the atoms in a molecule and their overall electronegativity determine where they are placed in a Lewis structure.
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To draw a Lewis structure, you should place single bonds between atoms, include nonbonding electrons, and use the sum of the valence electrons for a neutral molecule.
Explanation:The correct statements that describe the procedure for drawing a Lewis structure are:
A single bond, which represents 2 electrons, should be placed between every two atoms. This follows the octet rule, where each atom tries to acquire 8 valence electrons. Nonbonding electrons should be included in the Lewis structure. These are the lone pairs of electrons that are not involved in bonding with other atoms. For a neutral molecule, the sum of the number of valence electrons for each atom gives the number of electrons used in the Lewis structure. This ensures that all valence electrons are accounted for.Learn more about Lewis structure here:https://brainly.com/question/34631490
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There are several different models that represent compounds. One type of model is shown.
3 C's connected in a line by 2 black lines. The first and third C's each have 3 H's connected to them by a single black line each. The middle C has 2 H's connected to it by a single black line each.
What type of model is shown?
A) structural formula
On edge
Answer:
A
Explanation:
Uranium-233 decays to thorium-229 by α decay, but the emissions have different energies and products: 83% emit an α particle with an energy of 4.816 MeV and give ²²⁹Th in its ground state; 15% emit an a particle of 4.773 MeV and give ²²⁹Th in excited state I; and 2% emit a lower energy α particle and give ²²⁹Th in the higher excited state II. Excited state II emits a γ ray of 0.060 MeV to reach excited state I.(a) Find the γ-ray energy and wavelength that would convert excited state I to the ground state.
That would give us the total amount of energy released during the process, or 7.85 x 10^-13 Jules.
HOW IS THIS POSSIBLE ?Radioactive new Clydes release energy, which can be in the form of particles or energy, as they decay to create more stable nuclei. In nuclear notation, the high mass number is the main script and the atomic number is used as the subscript to represent the plutonium isotope P u 2 42, for example. The atomic number is displayed in the periodic table.
We are informed that this breaks down into two elements from the periodic table: uranium 238 (which has a mass number of 92) and an alpha particle, which has the symbol of a helium and a mass of four. It breaks down with a release of energy of 4.85 three mega electron volts.
Through gamma decay, the nucleus that makes up the uranium nucleus degrades even further. Given that decay creates the same exact nucleus and does not alter the particle's mass or atomic number, it emits gamma radiation.
The Greek letter gamma appears in the symbol for gamma. We can find the energy that is released in the form of electromagnetic radiation from this, more precisely radiation with a wavelength between 0 and 7 5 7 nanometers. utilizing the formula e = h time. See above Lambda, where H is 6.626 times 10 to the minus 34 meter squared times kilograms, also known as Planck's Constant.
The speed of light must be three times 10 to the eighth meters per second on our wavelength for me to believe it to be in meters per second. As a result, we measure wavelength in nanometers and know that there are 10 to 9 nanometers in a meter. Therefore, this is equal to two point 757 multiplied by 10 minus 11 meters. Therefore, given those figures or our energy and Jules, we can determine the energy of the wavelength in Jules.
Jules, this is 7.21 times 10 to the minus 15. Therefore, the gamma radiation released is equal to that amount. Because the initial step is given in mega electron volts, we first convert this to electron volts and then use the relationship that every 11 every Jules is equivalent to 6.24 times 10 to the 18 electron bowls to calculate the value of the energy released going directly from the plutonium directly to the stable nucleus.
In other words, the first phase generates energy that is 7.78 x 10 13 Jules. Therefore, if we combine these two figures together, the total amount of energy released would be 7.85 times 10 to the minus 13 Jules.
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What is an ecosystem. A.It is a single plant and a single animal that live in given area B. it is a community of plants, animals and their physical surrounding. C it is the members of the same species in an area. D it is one species that lives in a given area GIVE BRANLIYST
Answer:
B. it is a community of plants,animals and there physical surrounding.
Draw the two planes indicated by the Miller indices (121) and (212) in a unit cell of a cubic lattice with a lattice constant parameter a=3.42
A
˚
. Then determine the perpendicular distance between the origin and each of them.
To draw the planes indicated by the Miller indices (121) and (212) in a unit cell of a cubic lattice, we follow these steps:
To find the perpendicular distance between the origin and each plane, we can use the formula:
Distance = sqrt((x-intercept)^2 + (y-intercept)^2 + (z-intercept)^2)
1. Determine the intercepts:
For the Miller indices (hkl), the intercepts on the x, y, and z axes are determined by taking the reciprocals of the indices:
Intercept on x-axis = 1/h
Intercept on y-axis = 1/k
Intercept on z-axis = 1/l
2. Scale the intercepts:
Multiply the intercepts by the lattice constant parameter (a) to scale them to the appropriate size.
Scaled intercept on x-axis = (1/h) * a
Scaled intercept on y-axis = (1/k) * a
Scaled intercept on z-axis = (1/l) * a
3. Draw the planes:
Place the plane on each axis by drawing lines perpendicular to the axes at the scaled intercepts. The points where the lines intersect will determine the position of the plane in the unit cell.
4. Determine the perpendicular distance:
To find the perpendicular distance between the origin and each plane, we can use the formula:
Distance = sqrt((x-intercept)^2 + (y-intercept)^2 + (z-intercept)^2)
By following these steps, you can draw the planes and calculate the perpendicular distances between the origin and each of them in the given unit cell.
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H 0
:p A
=0.40,p B
=0.40, and p C
=0.20 H a
: The population proportions are not p A
=0.40,p B
=0.40, and p C
=0.20. sample of size 200 yielded 140 in category A, 20 in category B, and 40 in category C. Use α=0.01 and test to see whether the proportions are as stated in H 0
. (a) Use the p-value approach. Find the value of the test statistic. Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Reject H 0
. We conclude that the proportions differ from 0.40,0.40, and 0.20. Do not reject H 0
. We cannot conclude that the proportions are equal to 0.40,0.40, and 0.20. Do not reject H 0
. We cannot conclude that the proportions differ from 0.40, 0.40, and 0.20. Reject H 0
. We conclude that the proportions are equal to 0.40,0.40, and 0.20. (b) Repeat the test using the critical value approach. Find the value of the test statistic. State the critical values for the rejection rule. (If the test is one-tailed, enter NONE for the unused tail. Round your answers to three decimal places.) test statistic ≤ test statistic ≥ State your conclusion. Reject H 0
. We conclude that the proportions differ from 0.40,0.40, and 0.20. Do not reject H 0
. We cannot conclude that the proportions differ from 0.40, 0.40, and 0.20. Do not reject H 0
. We cannot conclude that the proportions are equal to 0.40,0.40, and 0.20. Reject H 0
. We conclude that the proportions are equal to 0.40,0.40, and 0.20.
The test results indicate that we reject the null hypothesis (H0) and conclude that the proportions are not equal to 0.40, 0.40, and 0.20.
What is the value of the test statistic and the p-value for the given hypothesis test?To test the hypothesis, we can use the p-value approach. The test statistic for comparing proportions is the chi-square statistic (χ²). In this case, we have three categories (A, B, and C) and their respective observed frequencies (140, 20, and 40) in a sample of size 200.
The expected frequencies under the null hypothesis can be calculated by multiplying the sample size by the hypothesized proportions. Thus, the expected frequencies are 80 for category A, 80 for category B, and 40 for category C.
Using these observed and expected frequencies, we can calculate the chi-square test statistic:
χ² = Σ[(observed - expected)² / expected]
After calculating the test statistic, we can find the p-value associated with it using the chi-square distribution with degrees of freedom equal to the number of categories minus 1.
Comparing the p-value to the significance level (α = 0.01), if the p-value is less than α, we reject the null hypothesis; otherwise, we fail to reject it.
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36.512 ml of aqueous solution containing 0.111 moles of reactant a in a calorimeter at 25.0oc undergoes the following reaction: a(aq) --> b(aq). (the solution and the calorimeter are initially both at 25oc) when the reaction is complete, the temperature of the solution and the calorimeter is 46.84 oc. what is the enthalpy of the reaction in units of kj/mole of a? assume that the density of the solution is 1.000 g/ml, the specific heat of the solution is 4.186 j/goc, and the calorimeter has a heat capacity of 15.558 j/oc.
The enthalpy of the reaction is -58.7928 kJ/mol of A. Note that the negative sign indicates that the reaction is exothermic (heat is released).
To calculate the enthalpy of the reaction (ΔH) in units of kJ/mole of A, we can use the following equation; ΔH = -q/n
where q is the heat absorbed or released by the reaction, and n is the number of moles of reactant A.
First, we need to calculate the heat absorbed or released by the reaction (q). We can use the following equation to calculate q:
q = m × c × ΔT + C_cal × ΔT
where m is the mass of the solution, c is the specific heat of the solution, ΔT is the change in temperature (T_final - T_initial), and C_cal is the heat capacity of the calorimeter.
The mass of the solution can be calculated using the density of the solution;
mass = volume × density = 36.512 mL × 1.000 g/mL = 36.512 g
Substituting the given values, we get;
q = 36.512 g × 4.186 J/g°C × (46.84°C - 25.0°C) + 15.558 J/°C × (46.84°C - 25.0°C)
= 6524.1 J
Next, we need to calculate the number of moles of reactant A
n = 0.111 moles
Now we can calculate the enthalpy of the reaction:
ΔH = -q/n = -(6524.1 J)/(0.111 moles) = -58792.8 J/mol
Finally, we convert the result to kJ/mol
ΔH = -58.7928 kJ/mol
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Which of the following is not a reason childhood friendships are important to development? a. positive relationships provide positive psychological support. b. friends are a child's first chance in learning how to be social with siblings. c. adolescents can use friendships as a way to work out personal problems. d. children can learn what it means to be loyal through their friendships. please select the best answer from the choices provided a b c d
Reactions review please help
PLS HELP ME I HAVE TILL 12
A student collects oxygen gas by displacing water in a test tube. The gas in the tube has a total pressure of 92.3kPa. If the water has a vapor
pressure of 1.82kPa, what is the pressure of oxygen?
a 90.5kPa
b 94.1kPa
c 168.0kPa
d 50.7kPa
Answer:
alright bud lets see hmm.... the answer is a. 90.5kpa
Explanation:
92.3 kPa - 1.82 kPa = 90.5 kPa
keep up your hope also corrected me if a am wrong in anyway! :)
Pellets of calcium chloride are spread on a sidewalk covered in water that is 36°C. Under which circumstance will the calcium chloride dissolve faster?
a. It rains, increasing the amount of water on the sidewalk.
b. Sand is sprinkled on the sidewalk.
c. The water cools to a temperature of 33°C.
d. People walking on the sidewalk crush the calcium chloride pellets.
The calcium chloride pellets will dissolve faster under option C, where the water cools to a temperature of 33°C.
Calcium chloride (CaCl2) is a hygroscopic compound that readily absorbs moisture from the air. When spread on a wet sidewalk, the calcium chloride can dissolve in the water, forming a solution. It dissolves faster when water cools to a temperature of 33 degree celsius. This is because the solubility of calcium chloride in water decreases as the temperature increases. So, with a lower temperature, the calcium chloride will dissolve faster. The other options (a, b, and d) do not have a significant effect on the rate of dissolution of the calcium chloride pellets.
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Which statement best describes the effects chemicals may have on the
environment?
A. The effects of chemicals on the environment are easy to observe.
B. Some chemicals may help the environment.
C. All chemicals harm the environment.
D. Chemicals must be released in large amounts to affect the
environment.
SOMEONE HELP ME PLEASE ILL GIVE BRAINLY
Snapping an instant cold pack is a
Change in temperature
Formation of gas/bubbles
Formation of precipitate
Release of energy (fire/light)
Change in color
Answer:
Answer
Change in temperature
It is an example of an endothermic reaction. It is absorbing heat.
Two out of the three domain groups include prokaryotic organisms true or false
Group of answer choices
Answer:
True, there’s Prokaryotic and Eukaryotic
Explanation:
Eukaryotic are more complex and HAVE a nucleus, Prokaryotic are less complex and don’t have a nucleus
True or False?
Nuclear fusion releases less energy than nuclear fission does.
Which argument is supported by the information? A. This gene therapy method should be used to improve other senses such as hearing. B. This gene therapy method should be used to prevent blindness that is caused by sun damage. C. This gene therapy method can help improve vision in some patients with the defective gene. D. This gene therapy method can help improve the eyesight of people without an inherited disease
Based on the information provided, the argument that is supported is:
C. This gene therapy method can help improve vision in some patients with the defective gene.
Gene therapy is a medical approach aimed at treating or preventing genetic disorders by modifying the genetic material of an individual's cells. It involves introducing functional genes or altering existing genes within the cells of a patient to correct or compensate for a genetic mutation or abnormality.
The given information implies that the gene therapy method discussed is effective in addressing a defective gene that impacts vision. Therefore, it suggests that the gene therapy method has the potential to improve vision in individuals with the specific genetic condition.
Hence, C. This gene therapy method can help improve vision in some patients with the defective gene is correct.
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27.5 cm³ of a solution of NaOH neutralizes 25.0cm³ of 0.5 MHCL solution. Calculate the
concentration of NaOH in
b. gdm
a. Moldm-3
a)The concentration of NaOH in g/dm³ is approximately 18.18 g/dm³, and b)The concentration in mol/dm³ is approximately 0.4545 mol/dm³.
a)To calculate the concentration of NaOH in g/dm³ (grams per cubic decimeter) and mol/dm³ (moles per cubic decimeter), we need to know the amount of NaOH used in the reaction and the volume of the NaOH solution.
From the given information, we have:
Volume of NaOH solution = 27.5 cm³
Volume of HCl solution = 25.0 cm³
Molarity of HCl solution = 0.5 M
Since the reaction between NaOH and HCl is a 1:1 stoichiometric ratio, the moles of NaOH used can be determined from the moles of HCl used:
Moles of HCl = Molarity × Volume = 0.5 M × 25.0 cm³ = 12.5 mmol (millimoles)
Since the moles of NaOH used is also equal to the moles of HCl, we have:
Moles of NaOH = 12.5 mmol
b)To calculate the concentration of NaOH in g/dm³, we need to convert moles to grams using the molar mass of NaOH, which is approximately 40 g/mol:
Mass of NaOH = Moles × Molar mass = 12.5 mmol × 40 g/mol = 500 g
Now, we can calculate the concentration in g/dm³:
Concentration of NaOH (g/dm³) = Mass of NaOH / Volume of NaOH solution
= 500 g / 27.5 cm³
≈ 18.18 g/dm³
To calculate the concentration of NaOH in mol/dm³, we can use the same approach:
Concentration of NaOH (mol/dm³) = Moles of NaOH / Volume of NaOH solution
= 12.5 mmol / 27.5 cm³
≈ 0.4545 mol/dm³
Therefore, the concentration of NaOH in g/dm³ is approximately 18.18 g/dm³, and the concentration in mol/dm³ is approximately 0.4545 mol/dm³.
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Power is measured in which unit?
Answer:
joules or watts
Explanation:
Answer:
the answer is B: watts
Explanation:
edge
Give one example of each of the following, that happens to us in our everyday life: Explain a bit about the science behind it, so for example, for melting you can say ice cream melting in your hand, which turns from a solid to a liquid, which is melting. If you are unsure please do not answer, though if you are confident please be free to do so! Have a wonderful day or night!
a) Melting:
b) Freezing:
c) Condensation:
d) Evaporation:
e) Sublimation.
a) Melting: An example of melting that occurs in our everyday life is when we heat butter on a stovetop.
b) Freezing: Freezing is the process in which a liquid transforms into a solid upon cooling.
c) Condensation: One example of condensation that we encounter regularly is when water droplets form on the surface of a cold drink on a hot day.
d) Evaporation: Evaporation is the process by which a liquid transforms into a gas or vapor.
e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state.
a) Melting: Butter is a solid at room temperature, but when heat is applied, it melts into a liquid. This change is a result of the increase in temperature, which provides enough energy to overcome the intermolecular forces holding the butter molecules together.
b) Freezing:Eventually, the temperature reaches the freezing point of water (0°C or 32°F), at which the water molecules slow down and arrange themselves into a regular, crystalline structure. This transformation from a liquid to a solid state is accompanied by the release of heat energy.
c) Condensation: As the temperature decreases, the air's capacity to hold moisture decreases, causing the water vapor in the air to condense into liquid water droplets. This process occurs due to the transfer of heat energy from the warm air to the cold surface, leading to the saturation of the air and the conversion of water vapor into liquid form.
d) Evaporation: As the sun's heat energy is absorbed by the water molecules on the clothes' surface, their kinetic energy increases, causing them to break free from the liquid phase and escape into the surrounding air as water vapor. This process occurs because the molecules at the liquid surface with sufficient energy can overcome the attractive forces within the liquid and enter the gas phase.
e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state. An example of sublimation is the process of dry ice (solid carbon dioxide) converting into carbon dioxide gas.
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________ occurs when gravity is the only force acting on an object. Select the best answer from the choices below.
how many valence electrons does silicon have
Answer:
As in silicon, four electrons are present in the outermost shell, so silicon has Four valence electrons.
Which substance cannot be separated or broken down into simpler substances by chemical means?
table salt
gold wire
candle wax
water vapor
Answer: Gold Wire
Explanation:
Out of all of these options only gold wire is an element, elements are pure and cannot be broken down by any chemical means
hope it helped, good luck :)
I need helppppp!!!!!!!
Answer:
1. Endothermic
2. Exothermic
3. Exothermic
4. Endothermic
Explanation:
Just the laws of thermodynamics. I always like to remember exothermic as heat exiting or releasing by the phrase "exo" for exit.
I need help with this if you do it you will be marked brainlyist and plz do it like this
-Claim
- Evidence
- Reasoning
Answer:
Explanation:
Claim: Earth's atmospheric CO2 levels were measured over the past 1000 years and correlated with average world temperatures. The data demostrate that Earth's temperature did not change during the period CO2 levels were steady. But the past 100 years show a dramatic rise in CO2 levels, with a corresponding rise in world temperatures. The CO2 rise can be traced back to the start of the industrial revolution, when machines began doing much of the work. These machine burn fossil fuels and the increased CO2 levels have led to a dramatic rise in world temperatures. The data clearly show the importance of reducing fossil fuel useage, as well as other CO2 emitters. A world of incresing temperatures will lead to greater natural disasters, such as storms, flooding, hurricanes, and drought - all of which upset the ecological balance of the planet.
Where did you walk? what did you find most enjoyable while walking: listening to music, listening to an audio book, or nothing? how did your body react to this introductory amount of exercise? was it more exercise or less exercise than you are used to? if you did not walk, what other type of physical movement did you do?
Answer: walked from school few blocks before arriving .found charting and laughing with my pals most enjoyable while I was walking .my body reacted by tiredness, it is less exercise than I am capable of doing.
Explanation: did that help?