a pita ya or dragon fruit is a tropical fruit with pink skin and pulp filled with tiny black seeds the weight of a pitaya is 1x10~3 ounces what is the weight of the pitaya seed in standard form

Based on the information given, let's find the probability that you will not exceed the $50 reimbursement limit for all three dinners.

1. First, identify the number of restaurants that exceed the $50 limit:
One-third of 18 restaurants is (1/3) * 18 = 6 restaurants.

2. Calculate the probability of selecting a restaurant that does not exceed the $50 limit:
There are 12 restaurants (18 total - 6 expensive ones) that meet the criteria. So, the probability of choosing one of them is 12/18 = 2/3.

3. Determine the probability of choosing three restaurants that do not exceed the $50 limit:
Since you're choosing three restaurants, we'll multiply the individual probabilities: (2/3) * (2/3) * (2/3) = 8/27.

4. Round the answer to four decimal places:
The probability is approximately 0.2963, or 29.63%.

So, if you randomly select three of these restaurants for dinner, there is a 29.63% chance that you will not exceed the $50 reimbursement limit for all three dinners.

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Answer:

The slope is -3/7 so B

Step-by-step explanation:

Just turn this into slope-intercept form.

what you do is subtract 3x so that it's moved to the right side.

It should look like this -7y = 12 - 3x

Then just divide all numbers by 7 so everything is simplified

It should look like this y = -3/7x - 12/7

pls mark brainliest because i didn't waste you time lol

Answer:

m = 132

Step-by-step explanation:

(m / 4) + 8 = 41

(m / 4) = 33

m = 132

Step-by-step explanation:

m/4=33

m=33×4=132

,,,,,,,

Answer:

(-3 ÷ 4)x^2 + 6x

Step-by-step explanation:

Data mentioned in the question

Maximum height = 12m

Number of seconds = 8

Height = 3m

Depend on the above information, the quadratic equation is shown below:

As it took 8 seconds to hit the maximum altitude and it reverted to the ground floor, this graph also reflects the motion in parabola after 4 seconds, so that the a must be negative

Now it is given that

a × x ^ 2 + bx + c =0

We can considered that

x = 0

x = 8

As {0.8} are intercepts of x

When x = 0, then it is

a × 0 ^ 2 + b(0)  + c = 0 .................... (i)

Hence 0 = 0

Now x = 8, it is

a × 8 ^ 2 + b(8)  + c = 0

Hence a(8)^2 + b(8) + c =  0 ..................(ii)

As it can be seen that in the first equation c must be zero

Whereas the second equation is

64a + 8b = 0

i.e.

8a = -b or a = -b ÷ 8

Now according to the quadratic function, it presented

(-b ÷8)x^2 + bx + 0

So, the parabola vertex is (4, 12)

Now place this in the place of a

(-b ÷ 8)(4)^2 + b(4) = 12

And for calculating this b, all terms must be multiplied by 8

That appears

-b(16) + 32b = 96

16b = 96

So, b = 6.  

As a = -b ÷8

a = -6 ÷ 8

a = -3 ÷4

So, the equation is

= (-3 ÷ 4)x^2 + 6x

Hence, this is the equation

Given:

\(QP=2x+9,QM=5x-3\)

To find:

The value of QN.

Solution:

From the figure it is clear that, point Q is the intersection point of angle bisectors. So, point Q is the incenter.

\(QP=QM=QN\)    ...(i)  [Incenter is equidistant from each side of triangle]

Using (i), we get

\(QP=QM\)

\(2x+9=5x-3\)

\(2x-5x=-9-3\)

\(-3x=-12\)

Divide both sides by -3.

\(x=4\)

Now,

\(QP=2x+9\)

\(QP=2(4)+9\)

\(QP=8+9\)

\(QP=17\)

Using (i), we get

\(QN=17\)

Therefore, the value of QN is 17.

A skewed right distribution is most likely to result in the mean being substantially smaller than the median.

The mean and median are measures of central tendency used to describe the center of a distribution. In a skewed right distribution, the tail of the distribution extends towards the right, indicating a larger number of smaller values and a few extremely large values. This distribution shape is also known as positively skewed.

When a distribution is skewed right, the mean is typically pulled towards the larger values in the tail, making it larger than the median. However, there are scenarios where the mean can be substantially smaller than the median in a skewed right distribution.

This occurs when there are extremely large values in the tail that significantly affect the mean, but the bulk of the distribution remains concentrated on the smaller side. As a result, the mean can be pulled downward, making it smaller than the median.

On the other hand, in a symmetric distribution or a skewed left distribution (negatively skewed), where the tail extends towards the left with a larger number of larger values and a few extremely small values, it is less likely for the mean to be substantially smaller than the median. In these cases, the mean is typically closer to or larger than the median.

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Use the equation formula to find the area of a circle

The radius is given on the question, replace this value on the equation and find the area.

The area of the circle is 201.06 mm^2

Answer:

1/4 = 0.25

Step-by-step explanation:

Answer:

2/8

Step-by-step explanation:

i don't know what to put here but 1/4 is = to 2/8

Answer: $6.75

Step-by-step explanation:

25 hours times $9= $225/week

3% increase from $9.00= $0.27

$9.27 times 25 hours= $231.75

$231.75-$225= $6.75 more per week

Answer:

\(39.8^{\circ} C\)

Step-by-step explanation:

We are given that the temperature each hour in Elma Texas on October 1 is modelled by the equation

\(t(h)=10cos(15h-10)^{\circ}+30\)

Where h=Hour of the day with 0 meaning midnight

t=Temperature in degree Celsius

We have to find the temperature on October 1.

Substitute h=0

\(t(0)=10cos(15(0)-10)+30\)

\(t(0)=10cos(-10)+30\)

\(t(0)=39.8^{\circ} C\)

Hence, the temperature in Elma on October 1=\(39.8^{\circ} C\)

Answer:

x = 0, 6, -1

Step-by-step explanation:

To solve for x, first get rid of the negative x^3 by making it positive.

x^3 - 5x^2 - 6x = 0

Now you can start by finding the possible zeros. To do so take the factors of p (in this case the 6 in 6x) and the factors of q (in this case 1 in -x^3) and divide p by q.

P = ±1, ±2, ±3, ±6

Q = 1

possible zeros = ±1, ±2, ±3, ±6

Go through your equation x^3 - 5x^2 - 6x = 0 and check each possible zero until you find one that gets the equation to equal zero.

You could either continue to try each number and the ones that work would be your answer, or you can find one that works, factor it out, then factor your new equation. The second method is faster so that's what I'll use

Check each possible zero. For example:

(1)^3 - 5(1)^2 - 6(1) = 0

-10=0 This will not work

(-1)^3 - 5(-1)^2 - 6(-1) = 0

0 = 0

-1 Works, so now you will factor out -1 using synthetic division.

-1 |            | 1    -5   -6   0

                |      -1     6   0

                 1    -6    0   0

Your new equation is x^2 - 6x = 0

Now factor your new equation:

x(x - 6) = 0

x = 0, 6, -1

I hope this all made sense, have a good day :)

Answer:

513.247

Step-by-step explanation:

Answer:

A.

bc if you have the answer 16 you look at 6 and see that 6 is a even number so the whole thing's even lol

Answer:

I think the answer is A

Step-by-step explanation

The statement the most frequently used graphic in reports is the table is false because tables are not typically the most frequently used graphic in reports.

While tables are commonly used in reports to present structured and detailed information, they are not typically the most frequently used graphic. Instead, other types of visuals such as charts, graphs, and diagrams are often employed to present data and communicate information more effectively.

Graphical representations like bar charts, line charts, pie charts, and scatter plots are widely used in reports to visualize patterns, trends, comparisons, and relationships in the data. These visualizations offer a concise and visually appealing way to convey information, making it easier for readers to understand complex data.

Tables, on the other hand, are more suitable for presenting precise numerical values, categorical information, or detailed breakdowns. They are useful for displaying large datasets or providing specific values for reference. However, their format can be dense and may require closer scrutiny, making them less visually impactful compared to graphical representations.

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In this question, we were given five relations and asked to determine if they are reflexive, symmetric, and/or transitive.

(a) The relation Ri on R is reflexive, symmetric, and transitive.

(b) The relation R on A is not reflexive, not symmetric, and transitive.

(c) The relation Rs on Z is not reflexive, not symmetric, and transitive.

(d) The relation R, on Z is not reflexive, not symmetric, and not transitive.

(e) The relation Rs on Z is reflexive, not symmetric, and transitive.

A reflexive connection is a relationship between items of a set A in which each element is related to itself. As the name implies, the image of each element of the set is its own reflection. In set theory, a reflexive relation is an essential concept.

(a) Ri is reflexive, symmetric, and transitive.

- Reflexive: For any x ∈ R, (x, x) ∈ Ri since |x - x| = 0 < 1.

- Symmetric: For any (x, y) ∈ Ri, we have |x - y| < 1, which implies |y - x| < 1. Therefore, (y, x) ∈ Ri.

- Transitive: For any (x, y), (y, z) ∈ Ri, we have |x - y| < 1 and |y - z| < 1. Adding these inequalities, we get |x - z| < 2, which implies (x, z) ∈ Ri.

(b) R is not reflexive, symmetric, or transitive.

- Not reflexive: For any x ∈ A, (x, x) ∉ R since x - x = 0 is not a positive integer.

- Not symmetric: For any distinct x, y ∈ A, if (x, y) ∈ R, then x - y = 1, which implies y - x = -1 is not a positive integer. Therefore, (y, x) ∉ R.

- Not transitive: Let A = {1, 2, 3} and R = {(1, 2), (2, 3)}. Then (1, 3) is not in R since 3 - 1 = 2 is not a positive integer.

(c) R3 is not reflexive, symmetric, or transitive.

- Not reflexive: For any x ∈ Z, (x, x) ∉ R3 since x * x = x^2 is not greater than 0.

- Symmetric: For any (x, y) ∈ R3, we have xy > 0, which implies yx > 0. Therefore, (y, x) ∈ R3.

- Not transitive: Let x = -1, y = 2, and z = -1. Then (x, y) ∈ R3 and (y, z) ∈ R3, but (x, z) = (-1, -1) ∉ R3 since xz = 1 is not greater than 0.

(d) R, is not reflexive, symmetric, or transitive.

- Not reflexive: For any y ∈ Z, (y, y) ∉ R, since 3 does not divide y + 2y = 3y.

- Not symmetric: For y = 1 and z = 2, we have (2, 1) ∉ R, but (1, 2) ∈ R since 3 divides 1 + 4 = 5.

- Not transitive: Let x = 2, y = 1, and z = 5. Then (x, y) ∈ R, (y, z) ∈ R, but (x, z) = (2, 5) ∉ R since 3 does not divide 2 + 10 = 12.

(e) Rs is the relation on Z given by Rs = {(x,y) ⬠Zx Z: there exists k ⬠N such that elyk and yak).

- Reflexive: This relation is not reflexive because (1, 1) ∉ Rs as there does not exist k such that 1 x k = 1.

- Symmetric: This relation is not symmetric because, for example, (1, 2) ∈ Rs but (2, 1) ∉ Rs since there does not exist k such that 2 x k = 1.

- Transitive: This relation is not transitive. For example, let x = 1, y = 2, and z = 4. Then (x, y) ∈ Rs and (y, z) ∈ Rs, but (x, z) ∉ Rs since there does not exist k such that 1 x k = 4.

In short, in this question, we were given five relations and asked to determine if they are reflexive, symmetric, and/or transitive.

(a) The relation Ri on R is reflexive, symmetric, and transitive.

(b) The relation R on A is not reflexive, not symmetric, and transitive.

(c) The relation Rs on Z is not reflexive, not symmetric, and transitive.

(d) The relation R, on Z is not reflexive, not symmetric, and not transitive.

(e) The relation Rs on Z is reflexive, not symmetric, and transitive.

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Using the Chain Rule to find dw/dt:

We have w = xey/z, where x = t^3, y = 3 - t, and z = 7 + 3t. To find dw/dt, we can use the Chain Rule:

dw/dt = (∂w/∂x)(dx/dt) + (∂w/∂y)(dy/dt) + (∂w/∂z)(dz/dt)

Taking the partial derivatives of w with respect to x, y, and z, we get:

∂w/∂x = ey/z * 3t^2

∂w/∂y = ex/z * (-1)

∂w/∂z = -exy/z^2

Substituting in the values for x, y, and z, we get:

∂w/∂x = (3t^2)(3-t)/(7+3t)

∂w/∂y = -(t^3)(3-t)/(7+3t)

∂w/∂z = -(t^3)(3-t)(3+7t)/(7+3t)^2

Taking the derivatives of x, y, and z with respect to t, we get:

dx/dt = 3t^2

dy/dt = -1

dz/dt = 3

Substituting in all the values, we get:

dw/dt = (3t^2)(3-t)/(7+3t) + -(t^3)(3-t)/(7+3t) + -(t^3)(3-t)(3+7t)/(7+3t)^2

Simplifying this expression, we get:

dw/dt = (-3t^4 + 9t^3 + 3t^2 - 9t)/(7+3t)^2

Using the Chain Rule to find dw/dt:

We have w = ln(vx^2 + y^2 + z^2), where x = 2sin(t), y = 4cos(t), and z = 5tan(t). To find dw/dt, we can use the Chain Rule:

dw/dt = (∂w/∂x)(dx/dt) + (∂w/∂y)(dy/dt) + (∂w/∂z)(dz/dt)

Taking the partial derivatives of w with respect to x, y, and z, we get:

∂w/∂x = 2vx^2/(vx^2 + y^2 + z^2)

∂w/∂y = 2vy/(vx^2 + y^2 + z^2)

∂w/∂z = 2vz/(vx^2 + y^2 + z^2)

Substituting in the values for x, y, and z, we get:

∂w/∂x = 4vsin(t)^2/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

∂w/∂y = 8vcos(t)/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

∂w/∂z = 10vtan(t)/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

Taking the derivatives of x, y, and z with respect to t, we get:

dx/dt = 4cos(t)

dy/dt = -4sin(t)

dz/dt = 5sec^2(t)

Substituting in all the values, we get:

dw/dt = (4vsin(t)^2)/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2)) + (8vcos(t))/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2)) + (10vtan(t))/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

Simplifying this expression, we get:

dw/dt = (16vsin(t)cos(t) - 32vcos(t)sin(t) + 50vtan(t)sec^2(t))/(sin(t)^2 + cos(t)^2 + 25tan(t)^2)^2

Using the Chain Rule to find az/as and az/at:

We have z = tan(u/v), where u = 7s + 9t and v = 9s - 7t. To find az/as and az/at, we can use the Chain Rule:

az/as = (∂z/∂u)(du/ds) + (∂z/∂v)(dv/ds)

az/at = (∂z/∂u)(du/dt) + (∂z/∂v)(dv/dt)

Taking the partial derivatives of z with respect to u and v, we get:

∂z/∂u = sec^2(u/v)(1/v)

∂z/∂v = -sec^2(u/v)(u/v^2)

Taking the derivatives of u and v with respect to s and t, we get:

du/ds = 7

dv/ds = 9

du/dt = 9

dv/dt = -7

Substituting in all the values, we get:

az/as = (sec^2(u/v)(1/v))(7) + (-sec^2(u/v)(u/v^2))(9)

az/at = (sec^2(u/v)(1/v))(9) + (-sec^2(u/v)(u/v^2))(-7)

Substituting in the expression for u and v, we get:

az/as = (sec^2((7s+9t)/(9s-7t))(1/(9s-7t)))(7) + (-sec^2((7s+9t)/(9s-7t))((7s+9t)/(9s-7t)^2))(9)

az/at = (sec^2((7s+9t)/(9s-7t))(1/(9s-7t)))(9) + (-sec^2((7s+9t)/(9s-7t))((7s+9t)/(9s-7t)^2))(-7)

Finding the rates of change of volume, surface area, and length of diagonal of a box:

At a certain instant, the dimensions of the box are l = 9 m, w = h = 5 m, and l and w are increasing at a rate of 7 m/s while h is decreasing at a rate of 4 m/s.

(a) To find the rate at which the volume is changing, we can use the formula for the volume of a box:

V = lwh

Taking the derivative of V with respect to time, we get:

dV/dt = (dh/dt)lwh + (dl/dt)wh + (dw/dt)lh

Substituting in the values for l, w, and h, as well as the rates of change for l, w, and h, we get:

dV/dt = (-4)(9)(5)(5) + (7)(5)(5)(9) + (7)(9)(5)(5)

Simplifying this expression, we get:

dV/dt = 385 m^3/s

Therefore, the volume of the box is increasing at a rate of 385 m^3/s at that instant.

(b) To find the rate at which the surface area is changing, we can use the formula for the surface area of a box:

S = 2lw + 2lh + 2wh

Taking the derivative of S with respect to time, we get:

dS/dt = (dl/dt)(2w + 2h) + (dh/dt)(2l + 2w) + (dw/dt)(2l + 2h)

Substituting in the values for l, w, and h, as well as the rates of change for l, w, and h, we get:

dS/dt = (7)(2(5) + 2(5)) + (-4)(2(9) + 2(5)) + (7)(2(9) + 2(5))

Simplifying this expression, we get:

dS/dt = 164 m^2/s

Therefore, the surface area of the box is increasing at a rate of 164 m^2/s at that instant.

(c) To find the rate at which the length of the diagonal is changing, we can use the formula for the length of the diagonal of a box:

D = sqrt(l^2 + w^2 + h^2)

Taking the derivative of D with respect to time, we get:

dD/dt = (1/2)(l^2 + w^2 + h^2)^(-1/2)(2l(dl/dt) + 2w(dw/dt) + 2h(dh/dt))

Substituting in the values for l, w, and h, as well as the rates of change for l, w, and h, we get:

dD/dt = (1/2)(9^2 + 5^2 + 5^2)^(-1/2)(2(9)(7) + 2(5)(7) + 2(5)(-4))

Simplifying this expression, we get:

dD/dt = 3.08 m/s

Therefore, the length of the diagonal of the box is increasing at a rate of 3.08 m/s at that instant.

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Answer:

11

Step-by-step explanation:

Consider 10's factors: 1, 2, 5, 10, this is more than 2.

11's factors: 1, 11 (!)

Answer:

I think11 js the smallest 2 digit number that only has 2 factors

If Howard, in his new lightweight running shoes, was able to walk at the rate of 0.83 meters per second in which his coach timed his walking at this steady pace for seconds. . The distance he walk during that time is 10.126.

Given data:

Distance walk in 1 second = 0.83 meters per second

Walk at steady pace = 12.2 seconds

Now let find the distance that Howard have to walked in 12.2 seconds

Distance walked in 12.2 seconds =  0.83 meters per second × 12.2 seconds

Distance walked in 12.2 seconds = 10.126

Therefore the distance is 10.126.

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The complete question is:

Howard, in his new lightweight running shoes, was able to walk at the rate of 0.83 meters per second. His coach timed his walking at this steady pace for 12.2 seconds. How far did he walk during that time? Use paper and a pencil to show your work, and then check your answer with a calculator.

Answer:

x = 7, -6

Step-by-step explanation:

Since they already give you the binomial factors, all you need to do is set them equal to 0 to find your roots:

x - 7 = 0

x = 7

x + 6 = 0

x = -6

Answer:

Step-by-step explanation:

(x-7)(x+6)=0

x-7=0/(x+6)

x cannot be -6

x-7=0

x=7

x+6=0/(x-7)

x+6=0

x=-6

The zeros are 7 and -6

The equation of the line passing through the points (0, 1) and (2, -3) is y = -2x + 1.

The formula for equation of line is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

First, we determine the slope of the line.

Given the two points are (0, 1) and (2, -3).

We can find the slope of the line by using the slope formula:

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Substituting the values, we get:

m = (-3 - 1) / (2 - 0)

m = -4 / 2

m = -2

Using the point-slope form, plug in one of the given points and slope m = -2 to find the equation of the line.

Let's use the point (0, 1):

y - y₁ = m(x - x₁)

y - 1 = -2(x - 0)

y - 1 = -2x

y = -2x + 1

Therefore, the equation of the line is y = -2x + 1.

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Answer:

y = 3x + 2

Step-by-step explanation:

For this question we have to use the equation y=mx+c

m represents the gradient

c represents where the line crosses the y-axis (the y-intercept)

1) Find the gradient

To find the gradient we have to divide the change in y by change in x

In this question that means we have to divide 3 by 1

3 ÷ 1 = 3

2) Find the y-intercept

We can see that the line crosses the y-axis on the point (0,2) meaning the y-intercept is 2

y = 3x + 2

Hope this helps, have a lovely day! :)

Answer:

Step-by-step explanation:

y=3x+2

Answer:

Randall and the most money. she earned 50 cents more than Stephano did.

Step-by-step explanation:

so it's Randall makes $27.50 on his first day and $25 on a second date and and 32.50 on his third day you would add those up to get $85 in all. now Stefano gets 7.50 22.50 12.50 15.00 and 17.00 dollars , and when you add all those together he gets 84.50 and all. meaning that random made more money by .50 cents.

Answer: (I changed it back to fraction form instead of decimal because it seems that is how you are doing it)

Two possible lengths of ribbon (In inches) are 25 and 133  3/4

Step-by-step explanation:

Okay, so- First, You need to find out how much ribbon is there before the two additional ones are added. Like this:

12 + 14  2/4 + 14  3/4 = 41  1/4

Next, subtract that amount from 200 to get the number of inches of ribbon that are needed to get 200 inches of ribbon. Like this:

(I changed it to a decimal to make it easier, so don't mind that)

200 - 41.25 = 158.75

So, 158.75 inches of ribbon are needed to get 200 inches. You can subtract any number less than 158.75 from that to get two seperate ribbon measurements.

(This might sound confusing so here)

For example:

158.75 - 25 = 133.75 (The bolded numbers are the two measurements)

158.75 - 65 = 93.75

So, Two possible lengths (in inches) of ribbon that kelly could have added are "25" and "133.75 "

Two possible lengths (in inches) of ribbon that kelly could have added are also "65" and "93.75"

Hope this helps! Please tell me if you have any questions!

Answer:

14.

Step-by-step explanation:

this a addition problem since it says "overall".

you simply add them.

Answer:

33 dogs

Step-by-step explanation:

By taking the 22 cats and dividing it by the ratio. Then multiply that quotient by the ratio of dogs.

Thus:

22/2 = 11

11*3 = 33

There will be 33 dogs.

Hope This Helps :)

Answer: 33

Step-by-step explanation:

2cats = 3dogs

22cats = x

Cross multiply

2x = 3×22

2x = 66

x = 66/2

x = 33

The entry in the elementary matrix e, corresponding to the row operation -6R2+R4 -> R4, is located in row number 4 and column number 2, and its value is -6.

To construct the elementary matrix e, we start with the 4 by 4 identity matrix I4 and perform the row operation -6R2+R4 -> R4. The row operation is equivalent to multiplying the second row of I4 by -6 and adding the result to the fourth row. This can be represented by the following matrix:

[1 0 0 0]

[0 1 0 0]

[0 -6 1 0]

[0 0 0 1]

Thus, the entry in row 4 and column 2 is -6, and all other entries in e are identical to those in I4.

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Complete Question:

let e be the 4 by 4 elementary matrix corresponding to the row operation  -6R2+R4  -> R4  then e is identical to I4 at every entry except at the entry on row number_______ and column number_______ where the entry in e is________.

Answer:

x≈-0.0200335+2kπ/5

x≈-0.648352+2kπ/5

Step-by-step explanation:

sin(-5x)=0.1

-sin(5x)=0.1

sin(5x)=-0.1

sin(5x)=1/10

5x=arcsin(- 1/10)

5x=π-arcsin(- 1/10)

5x=π-arcsin(- 1/10)

5x=π-arcsin(- 1/10)+2kπ

5x=π-arcsin(- 1/10)+2kπ

x=arcsin (1/10)/5 + 2kπ/5

x=arcsin (1/10)/5 + 2kπ/5

x≈-0.0200335+2kπ/5

x≈-0.648352+2kπ/5