A plane is travelling at an average speed of 325 km/h. How far does the plane travel (km) in 30.0 minutes?

Answer:

Converting to and from scientific notation, as well as performing calculations with numbers in scientific notation is therefore a useful skill in many scientific and engineering disciplines. One of the advantages of scientific notation is that it allows you to be precise with your numbers, which is crucial in those industries.

The object will move at a constant speed to the left.

The net force on the object is calculated as follows;

According to Newton's second law of motion, when the net force on an object is greater than 0, the object tends to move in the direction of the net force.

Thus, the object will move at a constant speed to the left.

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The individual masses are 4.70 kg and 0.30 kg respectively.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Let the individual masses are m kg and (5-m) kg.

According to the question:

m(5-m) = (2.2 × 10⁻¹⁰ × (0.65)²) ÷ (6.67×10⁻¹¹)

m² - 5m + 1.40 = 0

Hence, m = 4.70 and 5 -m = 0.30

The individual  masses are 4.70 kg and 0.30 kg respectively.

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Answer:

D. 1.17 J

Explanation:

The potential energy stored in a spring is given by the following:

U = (K•x²)/2

U -> elastic Potential energy

K -> spring constant

x -> compression

So:

U = (53•0.21²)/2

U = 1.17

Answer1.17:

Explanation:

Answer:25N/

Explanation:

With a 25.1 m/s2 acceleration, 2,946.19 N of horizontal force is required to push the trunk across the floor to the left.

Usually, the Greek letter mu is used to indicate it (). is mathematically equivalent to F/N, where F denotes frictional force and N is normal force. Due to the fact that F and N are both measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds).

An object's mass times its acceleration equals the object's net force:

F_net = m * a

The applied force less the frictional force equals the net force acting on the trunk:

F_net = F_applied - F_friction

The force of friction is given by:

F_friction = μ * N

As there is no vertical acceleration of the trunk, its weight is equal to the normal force:

N = m * g

where g is the gravitational acceleration.

When you combine everything, you get:

F_net = F_applied - μ * m * g = m * a

With the applied force factored in, we obtain:

F_applied = m * (a + μ * g)

Plugging in the given values, we get:

F_applied = 105 N * (25.1 m/s^2 + 0.63 * 9.81 m/s^2) = 2,946.19 N

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The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

Atomic mass is defined as the number of protons and neutrons in an atom, where each proton and neutron has a mass of approximately 1 amu (1.0073 and 1.0087, respectively). The electrons within an atom are so miniscule compared to protons and neutrons that their mass is negligible.

Explanation:

The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N

The following data were obtained from the question:

The centripetal force can be obtained as illustrated below:

F = mv²/r

= (50 × 7²) / 5

= (50 × 49) / 5

= 2450 / 5

= 490 N

Thus, we can concluded that the centripetal force is 490 N

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Answer:

Magnitude of electric field is 1.06 x \(10^5\) V/m along negative X-direction

Explanation:

Given: initial velocity of proton = u = 3.5 x \(10^6\) m/s

final velocity of proton = v = 0 m/s

initial point \(l_i\) = 0.2 m and final point is \(l_f\) = 0.8 m

According to conservation of energy:

change in in kinetic energy = change in potential energy of proton

⇒\(\frac{m}{2}(v^2-u^2 ) = qE(l_i - l_f)\)

where q and m is the charge and mass of proton E is the electric field , \(l_i\) and \(l_f\) is the initial and final position of proton

on substituting the respected values we get,

1.023 x \(10^-^1^4\) = 9.6 x \(10^-^2^0\) x E

⇒ E = 1.06 x \(10^5\) V/m

external force is opposite to the motion as velocity of proton decreases with distance.

Therefore, magnitude of electric field is 1.06 x \(10^5\) V/m along negative X-direction

Answer:

Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy that, through cellular respiration, can later be released to fuel the organism's activities.

Explanation:

The distance of the image formed by the lens is at 10.7 cm on the ruler.

option C.

The distance of the image is calculated by applying lens formula as shown below;

1/f = -1/u + 1/v'

where;

From the diagram, the focal length of the lens = 8.5 cm

the object distance = 3 cm

The image distance is calculated as follows;

1/v' = 1/f + 1/u

1/v' = 1/8.5 + 1/3

1/v' = 0.45

v' = 1/0.45

v' = 2.21 cm

The position of the image on the rule is calculated as follows;

v = v'  +  8.5 cm

v = 2.21 cm + 8.5 cm

v = 10.71 cm

Thus, the ray - diagram shows the position or distance of the image formed.

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Answer:

Q=cmΔT

Q1(steel)=Q2(water)

c1•m1• (t1-t) = c2•m2• (t-t2)

628•0.1•(80-t) = 4180•0.2• (t-10)

5024-62.8t = 836t -8360

5024+8360=(836+62.8)t

t=14.9°C

The lengths of the other bars on the set of they have frequencies of 220 Hz, 264 Hz, 330 Hz, 396 Hz, and 440 Hz would be 27.0 cm, 22.7 cm, 18.2 cm, 15.0 cm,  and 13.6 cm. respectively.

The fundamental frequency of a vibrating bar is inversely proportional to its length, so we can use the following formula to calculate the length of each bar in the set:

L = L₀ × f₀ / f

where L₀ is the length of the longest bar (30.0 cm), f₀ is its fundamental frequency (198 Hz), f is the frequency of the bar we want to find, and L is the length of that bar.

(a) For a frequency of 220 Hz:

L = L₀ × f₀ / f = 30.0 cm × 198 Hz / 220 Hz ≈ 27.0 cm

So the length of the bar that produces a frequency of 220 Hz is approximately 27.0 cm.

(b) For a frequency of 264 Hz:

L = L₀ × f₀ / f = 30.0 cm × 198 Hz / 264 Hz ≈ 22.7 cm

So the length of the bar that produces a frequency of 264 Hz is approximately 22.7 cm.

(c) For a frequency of 330 Hz:

L = L₀ × f₀ / f = 30.0 cm × 198 Hz / 330 Hz ≈ 18.2 cm

(d) For a frequency of 396 Hz:

L = L₀ × f₀ / f = 30.0 cm × 198 Hz / 396 Hz ≈ 15.0 cm

(e) For a frequency of 440 Hz:

L = L₀ × f₀ / f = 30.0 cm × 198 Hz / 440 Hz ≈ 13.6 cm

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Heya!!

For calculate aceleration, lets applicate formula:

                                                   \(\boxed{a=\frac{V-V_o}{t} }\)

                                                   Δ   Being   Δ

                                          V = Final Velocity = 5 m/s

                                         Vo = Initial Velocity = 2 m/s

                                          a = Aceleration = ? m/s²

                                                   t = Time = 7 s

⇒ Let's replace according the formula:

\(\boxed{a=\frac{5\ m/s - 2 \ m/s}{7\ s} }\)

⇒ Resolving

\(\boxed{ a=0,428\ m/s^{2}}\)

Result:

The aceleration of the object is 0,428 m/s²

Good Luck!!

Answer:

Ksasdasd

Explanation:

The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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For the roller coaster on a frictionless track:

a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.

Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.

Answer: A. 5.0 m/s

b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.

At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:

Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A

At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."

Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B

Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.

Equating the mechanical energy at Point A to the mechanical energy at Point B:

Initial mechanical energy at Point A = Mechanical energy at Point B

Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B

Since the kinetic energy is the same at both points, simplify the equation:

Potential energy at Point A = Potential energy at Point B

The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:

mgh = mghA

Since the mass and acceleration due to gravity are the same, cancel them out:

h = hA

This means that the height where kinetic energy equals potential energy is the same as the height at Point A.

Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.

c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.

Potential energy at Point B = mghB

Potential energy at Point C = mghC

Given that the height at Point C is 8.0 m, compare the potential energies:

Potential energy at Point B ≥ Potential energy at Point C

mghB ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hB ≥ hC

Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.

d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.

Potential energy at Point A = mghA

Potential energy at Point C = mghC

Given that the height at Point A is 5.0 m, compare the potential energies:

Potential energy at Point A ≥ Potential energy at Point C

mghA ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hA ≥ hC

Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.

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C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

Answer:

c) A soccer ball bouncing off a wall should be the correct answer :)

Answer:

D) all of the above

Explanation:

The net rate of radiation emitted by the pot at 49.1°C placed in a -19.3°C freezer can be calculated using the Stefan-Boltzmann Law and the equation for net radiation.

1. Convert the temperatures to Kelvin:

  Freezer temperature = -19.3°C + 273.15 = 253.85 K

  Pot temperature = 49.1°C + 273.15 = 322.25 K

2. Apply the Stefan-Boltzmann Law:

  The Stefan-Boltzmann Law states that the power radiated per unit area by an object is proportional to the fourth power of its temperature:

  P = εσA(T₁⁴ - T₂⁴)

  Where:

  P = Net rate of radiation (in watts)

  ε = Emissivity of the object (given as 0.657)

  σ = Stefan-Boltzmann constant (σ = 5.67 x \(10^{-8\) W/m²K⁴)

  A = Surface area of the pot (given as 0.127 m²)

  T₁ = Pot temperature in Kelvin (322.25 K)

  T₂ = Freezer temperature in Kelvin (253.85 K)

3. Calculate the net rate of radiation:

  P = 0.657 x 5.67 x \(10^-^8\) x 0.127 x (322.25⁴ - 253.85⁴)

  After performing the calculation, you will get the net rate of radiation emitted by the pot.

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B. The hormone erythropoeitin increases the production of red blood cells when oxygen levels are low.

A free body diagram is a visual representation of all the forces acting on an object.

A free body diagram is a visual representation of all the forces acting on an object. It is a tool commonly used in physics to help analyze the motion of an object.

In the case of an air cart, the forces acting on the cart might include the force of gravity pulling the cart downward, the normal force of the surface supporting the cart pushing upward, and the force of air resistance acting against the cart as it moves through the air. There may also be other forces at play, depending on the specific situation, such as an applied force from a fan or a motor driving the cart forward.

If there is an extra force causing a discrepancy between your numbers, you would also include this force on the free body diagram, with an arrow representing the magnitude and direction of the force

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Answer:

The quartering act of 1765 required the colonies to house British soldiers in barracks provided by the colonies.

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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Answer:

Explanation:

In this problem, we are required to solve for the total distance that the car travelled. and the displacement

A) the distance travelled by car

this can be gotten by summing all the distances the car has travelled.

i,e total distance= 60 miles+120 miles

total distance= 180 miles

B) the displacement of the car

the displacement can be gotten by  subtracting the final distance from the initial distance

final distance = 120 miles

initial distance= 60 miles

displacement= 120-60= 60 miles

Answer:

20.8 N*s

Explanation:

Brainly is being odd so I can't give a good explanation. But the impulse is the average force multiplied by the time the force acts on the object. impulse is basically just the total force

Impulse=Force * time=8*2.6=20.8