The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Force is the amount _____ or _____ on an object
Motion is the action of _____ from one place to another place.
Answer:
force is the amount of work or pressure given to an object
motion is the action of moving one place to another place
If the water start at a height of 45 metered and has a mass of 250 kg what is the potential energy of the water
The potential energy of the water having height of 45 m and has a mass of 250 kg is 110,250 Joule.
The force acting on the two objects affects the potential energy formula. The formula for gravitational force is P.E. = mgh, where g is the acceleration caused by gravity (9.8 m/s2 at the earth's surface) and h is the height in meters.
Substituting the value of mass (m), height(h) and g in the formula of potential energy
P.E = mgh
P.E. = 250*9.8*45
P.E.= 110,250 J
What is potential energy?Potential energy is the power that a thing possesses as a result of where it is in relation to other objects. Because the earth can pull you down through the force of gravity while doing work in the process, being at the top of a stairwell gives you more potential energy than standing at the bottom.
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24. What are the three factors Gore says are causing a collision between our civilization and the Earth? Explain each one.
Gore argues that the combination of population growth, a globalized economy, and technological impact is driving our civilization towards a collision with the Earth, jeopardizing the well-being of future generations.
1. Population Growth: Gore argues that the rapid growth of the global population is straining the Earth's resources and ecosystems. As the population increases, so does the demand for food, water, energy, and other resources, leading to overconsumption and environmental degradation. This places a significant burden on the planet's capacity to sustain life and maintain a healthy balance.
2. Globalized Economy: The expansion of the globalized economy has resulted in increased production, consumption, and trade on a massive scale. While this has brought economic benefits and improved living standards for many, it has also contributed to environmental problems. The pursuit of economic growth often prioritizes short-term profits over long-term sustainability, leading to resource depletion, pollution, and climate change.
3. Technological Impact: Advances in technology have brought numerous benefits to society, but they have also come with unintended consequences. Industrial processes, transportation systems, and energy production have increasingly relied on fossil fuels, leading to greenhouse gas emissions and climate change. Additionally, technological advancements have accelerated the extraction and exploitation of natural resources, further straining the planet's ecosystems.
He advocates for sustainable solutions that prioritize environmental conservation, renewable energy, and responsible resource management to mitigate these challenges.
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a rough block slides down the entire length of a smooth inclined plane (angle theta). A similar but smooth block would take half the time to slide the entire length. Find the coefficient of kinetic frictions between the rough block and the incline in terms of the angle theta
Answer:
The value is \(\mu_k = \frac{3}{4} * tan(\theta )\)
Explanation:
Generally the net force acting on the smooth block is mathematically represented as
\(F = mgsin (\theta )\)
Here this force also represented as
\(F = ma\)
So
\(ma = mgsin (\theta )\)
=> \(a = g sin(\theta )\)
Generally from kinematic equation
\(s = ut + \frac{1}{2} a t_1^2\)
before the sliding the block was at rest so u = 0 m/s
\(s = \frac{1}{2} a t_1^2\)
=> \(s = \frac{1}{2} (g sin(\theta )) t^2\)
=> \(t_1 = \sqrt{\frac{2s}{gsin(\theta )} }\)
Generally the net force acting on the rough block is mathematically represented as
\(F = mgsin(\theta ) - F_f\)
Here \(F_f\) is the frictional force acting on the block which is mathematically represented as
\(F_f = \mu_k * mg * cos (\theta)\)
So
\(F = mgsin(\theta ) - \mu_k * mg * cos (\theta) \)
generally this net force is mathematically represented as
\(F = ma\)
=> \( ma = mgsin(\theta ) - \mu_k * mg * cos (\theta) \)
=> \(a = gsin(\theta ) - \mu_k * cos (\theta )\)
Generally from kinematic equation
\(s = ut + \frac{1}{2} a t_2^2\)
before the sliding the block was at rest so u = 0 m/s
\(s = \frac{1}{2} a t_2^2\)
=> \(s = \frac{1}{2} [gsin(\theta ) - \mu_k * cos (\theta )} t^2\)
= > \(t_2 = \sqrt{\frac{2s}{gsin(\theta ) - \mu_k cos(\theta )} }\)
From the question we are told that
\(t_2 = 2 t_1\)
\(\sqrt{\frac{2s}{gsin(\theta ) - \mu_k cos(\theta )} } = 2 * \sqrt{\frac{2s}{gsin(\theta )} }\)
Squaring both sides
\(\frac{1}{sin(\theta ) - \mu_k cos(\theta )} = \frac{2}{sin(\theta)}\)
=> \(sin(\theta) = 4sin(\theta ) - 4\mu_k cos(\theta )\)
=> \(4\mu_k cos(\theta ) = 3sin(\theta )\)
=> \(\mu_k = \frac{3}{4} * \frac{sin(\theta )}{ cos(\theta )}\)
=> \(\mu_k = \frac{3}{4} * tan(\theta )\)
How to do projects on newton’s law
Write a short essay describing the six key features of Mesopotamia. Be sure to include how it advanced human society as a whole.
Mesopotamia, with its key features of specialization, government, cities, religion, trade, and written records, advanced human society by fostering economic growth, establishing governance structures, creating urban centers, facilitating cultural exchange, promoting trade networks, and revolutionizing communication and knowledge preservation through writing.
Mesopotamia, often referred to as the "cradle of civilization," possessed several key features that contributed to its advancement and influenced human society as a whole. These features include specialization, government, cities, religion, trade, and written records. Let's explore each of these key features and their significance.
Specialization: Mesopotamian society developed specialization, where individuals began to focus on specific occupations and trades. This led to the emergence of skilled craftsmen, farmers, priests, scribes, and merchants. Specialization allowed for the production of surplus goods, leading to economic growth and the establishment of a more complex society.
Government: Mesopotamia witnessed the development of early forms of government. Initially, city-states were governed by religious leaders known as priest-kings. Over time, as society grew more complex, secular leaders, such as kings, emerged to rule the city-states. These early forms of governance laid the foundation for later systems of government and administration.
Cities: Mesopotamia was characterized by the rise of urban centers. These cities served as political, economic, and cultural hubs. They were densely populated, with advanced infrastructure, including defensive walls, temples, markets, and residential areas. The cities of Mesopotamia, such as Ur, Uruk, and Babylon, provided the framework for the organization and development of early urban societies.
Religion: Religion played a central role in Mesopotamian society. The people of Mesopotamia believed in a pantheon of gods and goddesses and practiced polytheism. Temples were constructed as sacred spaces to honor and worship deities. Priests held significant influence, serving as intermediaries between the people and the divine. Religious beliefs and rituals provided a sense of identity, social cohesion, and moral guidance to the Mesopotamian community.
Trade: Mesopotamia's strategic location between major rivers, the Tigris and Euphrates, facilitated extensive trade networks. The abundance of resources, such as fertile land for agriculture, allowed for surplus production. This surplus was exchanged with neighboring regions, fostering trade and the establishment of commercial relationships. The exchange of goods and ideas through trade networks promoted cultural diffusion and contributed to the overall prosperity and interconnectedness of Mesopotamia.
Written Records: Mesopotamia is credited with the invention of writing, making it one of the earliest literate civilizations. Scribes used wedge-shaped marks known as cuneiform to record important information on clay tablets. The development of writing enabled the recording of laws, contracts, administrative documents, literature, and historical accounts. Written records not only facilitated communication and administration but also served as a means of preserving knowledge and passing it down through generations.
Collectively, these key features of Mesopotamia played a pivotal role in advancing human society as a whole. Specialization allowed for the efficient allocation of resources and the growth of economies. The establishment of early forms of government provided organization and stability to communities. Urbanization transformed social structures and fostered cultural and intellectual exchange. Religion served as a unifying force and provided a moral framework. Trade networks expanded horizons and facilitated the exchange of goods and ideas. Finally, the invention of writing revolutionized communication, education, and the preservation of knowledge.
Therefore, Mesopotamia's legacy as a cradle of civilization lies in its ability to establish foundations for complex societies, laying the groundwork for subsequent advancements in various aspects of human life.
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What is the acceleration of the object?
m/s2
Answer:
nice app is brainly heheh........
Answer:
The acceleration is 100m
Explanation:
To practice Problem-Solving Strategy 22.1 for electric force problems. Two charged particles, with charges q1=qq1=q and q2=4qq2=4q, are located on the x axis separated by a distance of 2.00cm2.00cm . A third charged particle, with charge q3=qq3=q, is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3.Find the position of charge 3 when qqq = 2.00 nCnC .
Answer:
x₂ = 0.01336
Explanation:
In this exercise we use the translational equilibrium equation
F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
at the point where charge 3 is placed the two electric forces have the same magnitude
let us use the expression of Coulomb's law for the electric force
F₁₃ = ka q₁ q₃ / r₁₃²
F₂₃ = ka q₂ q₃ / r₂₃²
we substitute
k q₁ q₃ / r₁₃² = k q₂ q₃ / r₂₃²
now imprescriptibility suppose that particle 1 is at the origin of the coordinate system, particle 2 is at a distance d = 2.00cm = 2 10-2 m, therefore let's call the distance from particle 1 to particle 3 as x
r₁₃ = x
R₂₃ = d-x
In the exercise we are given the charges for the particle1 q1 = q, for the particle 2 the charge is q2 = 4q the distance between them is d = 2.00cm = 0.0200 m, the value of q = 2.00 nC = 2.00 10⁻⁹ C
let's substitute these values
q₁ / x₂ = q₂ / (d-x)²
let's clear x
(d-x)² = q₂ / q₁ x²
d² - 2dx + x₂ = q₂ /q₁ x²
x² (1-q₂ / q₁) - 2d x + d² = 0
let's substitute the values and solve the quadratic equation
x² (1 - 4q / q) - 2 0.02 x + 0.02² = 0
-3 x² - 0.04 x + 0.0004 = 0
x² + 0.0133 x - 0.0001333 = 0
x = [-0.0133 ±√(0.0133² + 4 0.00013333)] / 2
x = [-0.0133 + - 0.026664] /2
x₁ = -0.01998 m
x₂ = 0.01336 m
Since load 3 must be between charged 1 and 2 the correct answer is
x₂ = 0.01336
Description
1) Consider a 10kg block resting on a spring. The
spring is compressed a distance of 0.25m from
its natural length.
a. Construct a free body diagram for the block
on the spring.
b. Calculate the spring constant for
this particular spring.
Suppose the spring-block apparatus is placed in
an elevator which accelerates downward at 3.0
m/s².
c. Would the compression of the spring be...
Less than 0.25m
Equal
Greater than 0.25m
to 0.25m
Justify your choice based on the forces acting on
the system.
The spring constant for this particular spring is 400 N / m. If the spring-block apparatus is placed in an elevator which accelerates downward at 3.0 m/s², the compression of spring would be less than 0.25 m
F = - k x
F = m g
F = Force
k = Spring constant
x = Displacement of spring
m = Mass
g = Acceleration due to gravity
m = 10 kg
x = - 0.25 m ( Since it is compressed )
g = - 10 m / s²
F = 10 * - 10
F = - 100 N ( Negative because it is acting downwards )
- 100 = k * - 0.25
k = 400 N / m
Since the elevator moves in y direction,
F = m a + m g
a = - 3 m / s²
F = m ( a + g )
F = 10 ( - 3 - 10 )
F = - 130 N ( Negative because it is acting downwards )
F = - k x
- 130 = - 400 * x
x = 0.325 m
Since x is positive, the spring is extended a distance of 0.325 m. So the compression of spring would be less than 0.25 m
Therefore,
The spring constant for this particular spring is 400 N / m. The compression of spring would be less than 0.25 m.To know more about spring constant
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Find the current flowing out of the battery.
Answer:
5A
Explanation:
PLEASE HELP ASAP! WILL GIVE BRAINLIEST TO CORRECT ANSWER! HELP!! HELP!!
The diagram shows the structure of an animal cell.
The image of an animal cell is shown with some organelles labeled numerically from 1 to 6. The outer double layer boundary of the cell is labeled 1. A stacked disc like structure is labeled 2. A broad rod shaped structure with an irregular shape inside it is labeled 3. The entire plain section that forms the background of the cell and is within the outer boundary is labeled 4. A small circular shape within the large circular shape is labeled 5. The large central circular shape is labeled 6.
Which number label represents the cell membrane?
1
2
4
6
(this is middle school science)
Answer:
1. cell membrane
2. golgi body
3. mitochondrion
4. cytoplasm
5. nucleolus
6. nucleus
Explanation:
The correct answer to this question is Option A; 6.
Why?
In a plant cell, the nucleus surrounds the nucleolous, which would be number 5. Therefore, number 6 would be your correct answer.
~Thank you~
If a wave has a frequency of say 10 Hz, that means something is oscillating times per second. What is this property that is oscillating for light, described by its frequency?
The property that is oscillating would be the electric and magnetic fields.
Oscillating properties of lightFor light, the property that is oscillating or vibrating at a particular frequency is the electric and magnetic fields.
Light is an electromagnetic wave, which means that it consists of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of wave propagation.
The frequency of the wave corresponds to the number of complete oscillations of the electric and magnetic fields that occur per second, and is measured in hertz (Hz).
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A boat, whose speed in still water is 1.75 m/s, must aim upstream at an angle of 26.3° (with respect to a line perpendicular to the shore) in order to travel directly across the stream.
(a) Determine the speed of the current.
(b) Determine the resultant speed of the boat with respect to the shore.
(a) should be 0.7775 m/s
(b) should be 1.57 m/s (i’m looking for the explanation)
A boat must aim upstream at an angle of 26.3° (with respect to a line perpendicular to the coast) with respect to a line should be 1.57 m/s for a boat moving at 1.75 m/s in still water.
How come a line is perpendicular?Perpendicular lines are two different lines that cross at a right angle of 90 degrees. Here, AB and XY connect at a 90-degree angle, making AB perpendicular to XY. The two lines do not intersect and run parallel to one another. They can't possible be compared side by side.
What is a perpendicular's form?A form is considered perpendicular if at least two of its sides are 90 degrees from one another. Shapes with perpendicular sides include the following: Square. Rectangle.
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How to find the angle in a projectile motion when displacement and heigh are the same
projectile's vertical speed v yv y v, start , y, drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward
.
At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.
In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.
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The world’s largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds.
What is the velocity for one of the blades?
(THIS IS PHYSICS, CIRCULAR MOTION)
Answer:
88.14 m/s
Explanation:
From the question given above, the following data were obtained:
Radius (r) = length of blade = 80 m
Revolution (rev) = 1
Time (t) = 5.7 s
Velocity (v) =?
The velocity of the blade can be obtained by using the following formula:
v = (rev × 2πr) / t
NOTE: Pi (π) = 3.14
v = (1 × 2 × 3.14 × 80) / 5.7
v = 502.4 / 5.7
v = 88.14 m/s
Therefore, the velocity of the blade is 88.14 m/s
When an object is in free fall, ____________________.
Answer:
Objects that are said to be undergoing free fall, are not encountering a significant force of air resistance; they are falling under the sole influence of gravity.
Explanation:
Under such conditions, all objects will fall with the same rate of acceleration, regardless of their mass.
What are two types of forces exerted by magnets?
Answer:
The other two forces are electrostatic and gravitational
Explanation:
N
Using the graph below, how many adults do NOT carpool to work?
Transportation to Work
Account
80
ashboard
70
60
50
Dunes
Number of Adults
40
30
Hondar
20
10
DOK
0
Bus
Walk
Car
Carpool
Method of Transportation
cory
2
160
O 15
50
130
Answer:130
Explanation:just answered it
A model rocket accelerated upwards at 3.80 m / s² from the ground. The small motor runs for 9.40s before breaking down.The rocket continues in a free fall motion until it collides with the ground.1)What is the speed of the rocket when it breaks down.2)What is its maximum altitude3)What is the total flight time
1) In order to determine the speed of the rocket when it breaks down, use the following formula:
\(v=v_o+at\)where,
vo: initial speed = 0m/s
a: acceleration = 3.80 m/s^2
t: time = 9.40s
Replace the previous values of the parameters into the formula for v:
\(v=\frac{0m}{s}+(\frac{3.80m}{s^2})(9.40s)=\frac{35.72m}{s}\)Hence, when the rocket breaks down it speed is 35.72 m/s
2)
Use the following formula to determine the vertical distance traveled by the rocket after it breaks down:
\(y=\frac{v^2_0-v^2}{2g}=\frac{(\frac{35.72m}{s})^2-(\frac{0m}{s})^2}{2(\frac{9.8m}{s^2})}=65.1m\)where the intial speed vo , in this case, is the final speed of the first trajectory.
Now, consider the distance traveled by the rocket before it breaks down. Us the following formula:
\(v^2=v^2_o+2ay_o\)where v is the final speed of the rocket in the first trajectory (35.72m/s), vo is the initial speed of the rocket in the first trajectory (vo = 0m/s becasue it started its motion from rest on the ground) and a is 3.80m/s^2.
Solve the previous equation for yo and replace the rest of the parameters:
\(y_o=\frac{v^2-v^2_0}{2a}=\frac{(\frac{35.72m}{s})^2-(\frac{0m}{s})^2}{2(\frac{3.80m}{s^2})}=167.88m\)The maximum height of the rocket is:
hmax = yo + y = 167.88m + 65.1m = 232.98 m
3) Take into account that when the rocket breaks down it keeps going up until its speed is 0 m/s. in this case, use the following formula:
\(v=v_o-gt\)to get the time at which the speed of the rocket is zero. In this case, you have:
vo = 35.72 m/s (the initial speed is the final speed of the first trajectory)
g: gravitational acceleration constant = 9.8m/s^2
v = 0 m/s
\(t=\frac{v_o-v}{g}=\frac{\frac{35.72m}{s}-\frac{0m}{s}}{\frac{9.8m}{s^2}}=3.64s\)Furthermore, consider that the rocke falls down in free fall when it reachs the maximum height. To determine the time it takes to reach the ground, use the following formula:
\(h_{\max }=\frac{1}{2}gt^2\)Solve the previous equation for t and resplace the values of g and hmax:
\(t=\sqrt{\frac{2h_{\max}}{g}}=\sqrt[]{\frac{2(232.98m)}{\frac{9.8m}{s^2}}}=6.89s\)Finally, consider that you have to consider the time before the rocket breaks down, the time before the rocket speed becomes zero and the time the rocket takes to reach the ground in freee fall.
Then, the total flight time is:
total time = 9.40s + 3.64s + 6.89s = 19.93s
HELP ME !!!Question 4 of 10
A pot of water is heated on an electric stove top and begins to boil. Which
two transfers of thermal energy involved in this system are examples of
convection?
A. From the rising warmed water to cooler water at the top
B. In the surrounding air as air currents develop
C. From the pot to the water
O D. From the burner to the bottom of the pot
Convection currents are set up in the boiling water and in the surrounding air.
Convection is the transfer of thermal energy by the actual movement of the molecules of a substance. A convection current is set up when the molecules of a fluid is heated, rises and is replaced by cooler molecules from below.
The two transfers of energy in this system are;
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Answer:
Explanation:
ill try to help
A skier accelerates downhill on their skis. Is TME conserved? Explain.
I do not see a pick an awsnser bAr
You launch a ball at a target with a speed v0 = 10.84 m/s at an angle θ above the horizontal. The target is at a height h = 5.22 m above the level at which you release the ball. You want the ball’s velocity to be horizontal (i.e. vy= 0 m/s) at the instant it reaches the target.
What is the value of the horizontal velocity v0x in m/s?
Enter your value with two (2) decimal places and no units. For example if your answer is 1.276, then enter 1.28.
Answer:
Explanation:
We can use the kinematic equation for vertical motion to find the value of the initial vertical velocity, v0y:
v0y = v0 * sin(θ)
Next, we can use the equation for vertical motion with constant acceleration (g = 9.8 m/s^2 is the acceleration due to gravity) to find the time it takes for the ball to reach the target:
v0y * t - 0.5 * g * t^2 = h
Solving for t:
t = sqrt(2 * h / g)
Finally, we can use the kinematic equation for horizontal motion (no acceleration in the horizontal direction) to find the horizontal velocity:
v0x = v0 * cos(θ)
So,
v0x = 10.84 * cos(θ) = 10.84 * cos(θ)
v0x = 10.84 * cos(θ) = 10.84 * cos(θ)
We do not have the value of θ, so we cannot determine the exact value of v0x.
The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the instantaneous velocity of the particle when t=1.0 s?
Answer:
pls first attach the fig.
The graph in the figure shows the position of a particle as it travels along the x-axis. The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s. Therefore, option B is correct.
What do you mean by average speed ?The term average speed is defined as the total distance traveled by the object in a particular time interval.
In the kinematics studies the movement of bodies, give the relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is known as uniform motion.
v = Δ x / Δt
Where v is the velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.
Therefore,
v = 2.0 - ( - 2.0 ) / 4.0 - 1.0
v = 1.33 m / s
Thus, The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s, option B is correct.
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Your question is incomplete, most probably your question was
The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s?
Please help!! The graph in the figure shows the position - 1, Graph is attache below in image.
Excepting a dare to do something physically dangerous is an example of this kind of influence is it (A Direct negative (B Indirect negative (C Direct post ( indirect post
Answer:
a
Explanation:
given that you know the risks it is directly negative
A ball is moving up a hill at 20 meters per second, and is decelerating at a uniform rate of 2 meters per second squared. What is its velocity after 5 seconds? Assume the direction up the hill is positive.
Answer:
-12meters per secondExplanation:
2^5=32-20=-12 meters per sec (going backwards).
If this is correct pls mark me. brainly to let me know, tyy C:
The higher something is off the ground, the more
potential energy it has.
True
False
Weight is best defined as _____. A the amount of space an object takes up B the speed of an object C the force of gravity on an object D the amount of energy in an object
Weight is best defined as C) the force of gravity on an object.
In one of the classic nuclear physics experiments at the beginning of the 20th century, alpha particles were accelerated toward stationary gold nuclei. Some alpha particles were reflected straight back due to the Coulomb interaction between the alpha particle and the nucleus. If the kinetic energy of a doubly charged alpha nucleus was 3.83 MeV when it was a large distance away from the nucleus, how close to the gold nucleus (79 protons) could it come before being reflected
Answer:
Explanation:
In the whole process , electric potential energy is converted into kinetic energy .
Kinetic energy = 3.83 MeV
= 3.83 x 1.6 x 10⁻¹⁶ J
= 6.128 x 10⁻¹⁶ J .
Let the closest distance of approach be r .
Electric potential energy = k Q q / r , Q is charge on nucleus , q is charge on alpha particle , r is closest distance .
Electric potential energy = 9 x 10⁹ x 79 x 1.6 x 10⁻¹⁹ x 2 x 1.6 x 10⁻¹⁹ / r
= 3640.32 x 10⁻²⁹ / r
So,
6.128 x 10⁻¹⁶= 3640.32 x 10⁻²⁹ / r
r = 3640.32 x 10⁻²⁹ / 6.128 x 10⁻¹⁶
= 594.05 x 10⁻¹³
= 59.405 x 10⁻¹²
= 59.405 pm .
If a wave is traveling at 60 cm/second and has a wavelength of 15 cm, what is the frequency?
A. 900 Hz
B. 60 Hz
C. 8 Hz
D. 4 Hz
Answer: B
G v = 60 cm/s λ = 15 cm E f = V / λ S f = 4 Hz U f = ? S f = (60 cm/s) / 15 cm 5.
Explanation: