a pointy pony can work at the rate of 0.5 hp if the pony pulls a load with a steady force of 170 n how fast can she go

The acceleration of an object can be split into two components: the tangential and normal components. The tangential component points along the direction of motion and is responsible for changing the speed of the object. The normal component is perpendicular to the direction of motion and is responsible for changing the direction of motion.

In your skiing example, the direction of your acceleration will change as you move uphill, downhill, up a ramp, and make a turn. Therefore, the tangential and normal components of your acceleration will also change in direction and magnitude.

As you ski uphill, your acceleration will be pointing in the opposite direction of your motion, resulting in a negative tangential acceleration. Since your motion is mostly vertical, your normal acceleration will be pointing upwards.

As you ski downhill, your acceleration will be in the same direction as your motion, resulting in a positive tangential acceleration. Your normal acceleration will still be pointing upwards.

When you go up a ramp, your acceleration will be a combination of tangential and normal components. The tangential component will be pointing upwards to match your velocity, and the normal component will be pointing perpendicular to the ramp.

When you land, your acceleration will be mostly normal, as you decelerate your downward motion and start to move horizontally.

Finally, when you make a turn, your tangential acceleration will be pointing in the direction of the turn, while your normal acceleration will be perpendicular to the turn.

Overall, the direction and magnitude of the tangential and normal components of your acceleration will depend on the direction and magnitude of your velocity and the curvature of your path.

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The height above the earth where the balloon has a speed of 7.40 m/s is 1587.4 m, calculated as m = 4.90  102 kg, W = 9.70  104 J, initial velocity = 0, final velocity = 7.40 m/s.

The height above the earth where the balloon has a speed of 7.40 m/s can be calculated as follows: Mass of the balloon, m = 4.90 × 102 kg Work done by the nonconservative forces, W = 9.70 × 104 J Initial velocity, u = 0Final velocity, v = 7.40 m/s Let the height above the earth where the balloon has a speed of 7.40 m/s be h. Kinetic energy at height h = Work done by nonconservative forces at height h i.e.,12mv2 = W Here, m = mass of the balloon, v = velocity of the balloon at height h Putting the given values, we get1/2 × 4.9 × 102 × (7.4)2 = 9.7 × 104We get h as, h = 1587.4 m Hence, the height above the earth where the balloon has a speed of 7.40 m/s is 1587.4 m.

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The VRIO analysis will provide valuable insights into the internal factors that contribute to Mercedes Benz's competitive position in the automotive industry.

VRIO Analysis

In addition to the Strategy Diamond, the group will also conduct a VRIO analysis as part of their collective analysis of Mercedes Benz.

VRIO stands for Value, Rarity, Imitability, and Organization, and it is a framework used to evaluate the resources and capabilities of a company.

The VRIO analysis helps assess the competitive advantage of a company by examining whether its resources and capabilities are valuable, rare, difficult to imitate, and well-organized.

This analysis allows the group to identify the company's key strengths and weaknesses and understand how they contribute to its overall strategy.

By applying the VRIO framework to Mercedes Benz, the group can determine which aspects of the company's operations and resources provide a sustainable competitive advantage.

They will evaluate the value of Mercedes Benz's brand reputation, technological innovation, manufacturing capabilities, and distribution network.

They will also assess the rarity of these resources and capabilities and analyze whether competitors can easily imitate or replicate them. Lastly, the group will examine how well Mercedes Benz's organization and management effectively leverage these resources to create value for the company.

The VRIO analysis will provide valuable insights into the internal factors that contribute to Mercedes Benz's competitive position in the automotive industry.

It will help the group understand the unique aspects of the company's operations and guide their analysis of the broader strategic context outlined in the Strategy Diamond.

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Two small plastic spheres are given positive electric charges. When they are 15.0 cm apart, the repulsive force between them has a magnitude of 0.72.

How many electrons had to be removed from one sphere and added to the other to cause an attractive force between the spheres?The answer is given below:Concept:Charge on an electron, e = 1.6 × 10^-19 C. Coulomb’s law gives the magnitude of the electrostatic force, F, between two charges, q1 and q2, separated by a distance, d. It is given by:F = kq1q2/d2where, k = Coulomb’s constant = 9 × 10^9 Nm^2/C^2.Force, F = 0.72 N, distance, d = 15 cm = 0.15 m. We know that the repulsive force is due to the fact that both charges are positive, meaning both are deficient in electrons. To create an attractive force, electrons from one sphere must be transferred to the other sphere. Let x be the number of electrons transferred, then each sphere acquires an additional charge of -xe.Since the force is attractive, the charges on the spheres are of opposite polarity. Let the charges on the spheres after transferring electrons be q1 and q2 with q1 < 0 and q2 > 0. Then we have:k|q1q2|/d2 = k|(-xe) - (xe)|/d2 = kx2e2/d2 = 0.72 NThe number of electrons transferred to create an attractive force between the spheres is given by:|x| = 1.2 × 10^13

First, we determine the total charge on each sphere.The magnitude of the repulsive force between the spheres is given by:Coulomb's law:$$F=\frac{k q_1 q_2}{d^2}$$$$0.72=\frac{(9\times 10^9)q_1q_2}{(0.15)^2}$$Simplifying the equation:$$q_1q_2=\frac{(0.72)(0.15)^2}{9\times 10^9}$$$$q_1q_2=1.08\times 10^{-11}$$Let the charges on the spheres be $q_1$ and $q_2$ such that $q_1<0$ and $q_2>0$. The difference in charges between the two spheres is given by:$$q_2-q_1=\frac{(0.72)(0.15)^2}{9\times 10^9}$$$$q_2-q_1=1.08\times 10^{-11}$$Add the same number, $x$, of electrons to one sphere and remove $x$ electrons from the other sphere, so the charges on the two spheres become $q_1-xe$ and $q_2+xe$, where $e=1.6\times 10^{-19}$ C is the charge of an electron. The difference in charges between the two spheres after the electrons have been transferred is:$$q_2+xe-(q_1-xe)=q_2-q_1+2xe=1.08\times 10^{-11}+2xe$$The electrostatic force between the spheres after the transfer of electrons is:$$F=\frac{k(q_1-xe)(q_2+xe)}{d^2}$$$$=\frac{(9\times 10^9)(q_1q_2+(q_2-q_1)xe+x^2e^2)}{(0.15)^2}$$Substituting the value of $q_1q_2$ and the difference in charges, $q_2-q_1$:$$0.72=\frac{(9\times 10^9)(1.08\times 10^{-11}+2xe+x^2e^2)}{(0.15)^2}$$Simplifying the equation:$$x^2=3.6\times 10^{22}-2.0\times 10^{13}x$$$$x^2+2.0\times 10^{13}x-3.6\times 10^{22}=0$$Using the quadratic formula:$$x=\frac{-2.0\times 10^{13}\pm \sqrt{(2.0\times 10^{13})^2+4(3.6\times 10^{22})}}{2}$$$$x=-1.0\times 10^{13}\ \text{or}\ x=3.6\times 10^{9}$$The number of electrons transferred to create an attractive force between the spheres is:$|x|=3.6\times 10^{9}$

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Answer:

An 8 kg sled mass moves in a straight line on a surface without horizontal friction at a certain point its speed is 4 m / s 2.50 m later its speed is 6 m / s using the work and energy theorem, determine the force acting on the sled assuming it is constant and acts in the direction of the sled movement

The force acting on the 8 kg sled has a value of 32 N.

Explanation:

We have initially look for the work that is applied to the sled, and this will be nothing more than the difference in kinetic energy from the end point to the initial, then:

ΔEc = Ec₂ - Ec₁

ΔEc = 0.5 * m * [V₂² - V₁²]

ΔEc = 0.5* 8 kg * [(6m / s) ² - (4m / s) ²]

ΔEc = 80 J

So, the work is 80 J, now we know that work is a relation distance and force , such that:

W = F * d

F = W / d

F = (80 J) / (2.50 m)

F = 32 N

Therefore, the force acting on the sled is 32 N.

The coefficient of kinetic friction μk relates the frictional force between two surfaces to the normal force pressing the surfaces together, and it depends on the nature of the surfaces in contact.

If an object of mass m is moving on a horizontal surface with a constant velocity v, the frictional force f_k acting on the object is given by:

f_k = μ_k * N

where N is the normal force, which is equal in magnitude to the weight of the object when it is on a horizontal surface. Thus, we have:

N = m * g

where g is the acceleration due to gravity.

In the situation where an object of mass m is sliding down an inclined plane with an angle of inclination θ, the gravitational force acting on the object can be resolved into two components:

A component mg * sin(θ) parallel to the plane, which causes the object to slide down.

A component mg * cos(θ) perpendicular to the plane, which is balanced by the normal force N.

The kinetic frictional force f_k acting on the object is then given by:

f_k = μ_k * N

Substituting for N, we get:

f_k = μ_k * m * g * cos(θ)

Since the object is sliding down the inclined plane with a constant velocity, the kinetic energy is constant, and the work done by the kinetic friction force must equal the loss in potential energy of the object.

Thus, we have:

f_k * d_1 = m * g * (h_1 - h_2)

where d_1 is the distance traveled along the incline, h_1 is the initial height of the object, and h_2 is the final height of the object. Solving for μ_k, we get:

\(μ_k = (m * g * (h_1 - h_2)) / (f_k * d_1)μ_k = (m * g * (h_1 - h_2)) / (μ_k * m * g * cos(θ) * d_1)μ_k = (h_1 - h_2) / (cos(θ) * d_1)\)

Therefore, the coefficient of kinetic friction μ_k can be expressed in terms of the variables d_1, h_1, h_2, and θ as:

μ_k = (h_1 - h_2) / (cos(θ) * d_1)

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The image of the 12-inch object produced by a plane mirror placed 30 inches in front of it is 12 inches high. This is because the image is the same size as the object and is located at the same distance behind the mirror as the object is in front of it.

The angle of incidence of the ray of light striking the mirror is not relevant to the size or position of the image produced by the mirror.In a plane mirror, the angle of incidence is equal to the angle of reflection. This means that the angle between the incident ray and the mirror is equal to the angle between the reflected ray and the mirror.

If the incident ray strikes the mirror at a 45-degree angle, then the reflected ray will also be at a 45-degree angle with respect to the mirror. This will not affect the size or position of the image produced by the mirror. Therefore, the image of the 12-inch object produced by the plane mirror is also 12 inches high and is located 30 inches behind the mirror, as if it were a real object.

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Answer:

t = 11.1 hours

Explanation:

The question says that, "A mobile advances at 20 m / s and travels a distance of 800 km. Determine the time in hours you use".

Given that,

Speed of a mobile, v = 20 m/s = 72 km/h

Distance, d = 800 km

We know that,

Speed = distance/time

So,

\(t=\dfrac{d}{v}\\\\t=\dfrac{800}{72}\\\\t=11.1\ h\)

So, it will take 11.1 hours.

Answer:

Explanation:

brash this so hard

Answer:

Dietary carbohydrates provide the body with energy for tough workouts and replenish energy stores in muscles in the form of glycogen.

Explanation:

Answer:

The answer is B) Lourdes>Jameson= Katherine >Montel

Explanation:

Use: W= mgs

Answer:

Explanation:

We shall apply law of conservation of momentum .

Momentum before impact = momentum after impact

Since they are moving towards the same direction , their momentum will add up .

Total momentum before impact

= 136 x 6 + 100 x 1 = 916 kg m/s .

Total mass of lineman and quarterback = 236 kg , if their velocity after impact be v

their momentum = 236 v

According to law of conservation of momentum

236 v = 916

v = 3.88 m /s

Both of them will move with velocity of 3.88 towards the north .

The camp has provided cadets with a greater understanding of opportunities within the STEM field and how to get there in several ways:

1. Exposure to different STEM career paths: The camp has likely exposed cadets to a variety of STEM career paths. Through workshops, presentations, and possibly guest speakers, cadets would have learned about different job opportunities within the STEM field. This exposure helps them understand the range of possibilities available to them and allows them to explore various interests within STEM.

2. Hands-on activities and projects: The camp may have included hands-on activities and projects related to STEM fields. These activities give cadets the opportunity to apply their knowledge, develop practical skills, and gain a deeper understanding of the real-world applications of STEM concepts. By engaging in these activities, cadets can see the direct link between their academic learning and potential career paths in STEM.

3. Mentoring and networking: The camp may have provided opportunities for cadets to interact with professionals working in STEM fields. This could include mentorship programs or networking events where cadets can ask questions, seek guidance, and gain insights from professionals who have already established themselves in their respective careers. By connecting with these mentors and professionals, cadets can learn about the paths they took to get to where they are and receive valuable advice on how to achieve their own career goals in the STEM field.

4. Career planning and goal-setting: The camp likely included sessions on career planning and goal-setting. Cadets may have been introduced to resources and tools to help them develop a plan for their educational and career journeys. This could involve identifying the educational requirements, internships or research opportunities, and additional skills or certifications needed to pursue specific STEM careers. By setting clear goals and understanding the steps necessary to achieve them, cadets are better equipped to navigate their way through the STEM field.

Overall, this camp has provided cadets with a greater understanding of opportunities within the STEM field by exposing them to different career paths, providing hands-on experiences, facilitating mentorship and networking, and assisting in career planning and goal-setting. These opportunities help cadets explore their interests, gain practical skills, and develop a roadmap for their future STEM careers.

The static friction is 11N and kinetic friction is 8N  between a block of wood and a laboratory bench.

Static friction is a force opposing relative movement and it happens at the connection point between the bodies, yet additionally inside the bodies, as in the event of liquids. The idea of friction coefficient was first formed by Leonardo da Vinci. The extent of the coefficient of still up in the air by the properties of the surfaces, environmental elements, surface highlights, presence of the oil, and so on.

Kinetic friction is characterized as a force that demonstrations between moving surfaces. A body continuing on a superficial level encounters a force the other way of its development. The extent of the force will rely upon the coefficient of motor grinding between the two materials.

We know that static friction is the maximum force applied by the body,so here 11N is the maximum force,so static friction value will be 11N and kinetic friction value will be 8N.

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The total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).

To find the work done in lifting the bucket and rope, we need to consider two parts:

Part 1: Work done lifting the bucket (without the rope) 24 ft:

The work done in lifting the bucket can be calculated by multiplying the weight of the bucket by the distance it is lifted.

Given:

Weight of the bucket = 7 lb

Distance lifted = 24 ft

Work done lifting the bucket = Weight of the bucket x Distance lifted

Work done lifting the bucket = 7 lb x 24 ft

Please note that the units need to be consistent for the calculation. In this case, we have pounds (lb) and feet (ft).

Part 2: Work done lifting the rope:

Assuming the force required to lift the rope is equal to its weight, we can calculate the work done lifting the rope by multiplying the weight of the rope by the distance it is lifted.

Given:

Weight of the rope = 0.8 lb

Distance lifted = 24 ft

Work done lifting the rope = Weight of the rope x Distance lifted

Work done lifting the rope = 0.8 lb x 24 ft

Now, we can calculate the total work done in lifting the bucket and rope by summing up the work done in both parts:

Total work done = Work done lifting the bucket + Work done lifting the rope

Please note that the units of work are in foot-pounds (ft-lb).

Now, we can calculate the values:

Work done lifting the bucket = 7 lb x 24 ft = 168 ft-lb

Work done lifting the rope = 0.8 lb x 24 ft = 19.2 ft-lb

Total work done = 168 ft-lb + 19.2 ft-lb = 187.2 ft-lb

Therefore, the total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).

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The complete question is:

Find the work done In lifting the bucket A 7 Ib bucket attached to a rope is lifted from the ground Into the air by puling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work done lifting the bucket and rope? Part1 -1 Find the work done lifting the bucket (without the rope) 24 ft . ft-Ib Part-2. Assuming the force required to lift the rope is equal to its weight; find the force function, F(x), that acts on the rope when the bucket is at height of x Ft. Part- 3 Setup the Integral that will give the work required to lift the rope 24 ft. Part -4 The total amount of work done lifting the bucket and ft-Ib.

Answer:True

The number of molecules hitting the unit surface per unit time increasethe gas pressure increases.

Answer:

c. may be accompanied by the sound of explosively expanding hot air, called thunder.

Explanation:

Lightning is a discharge which is due to the reaction between oppositely charged charges in the clouds, or between clouds base and the Earth surface.

The motion of the cloud causes charging of clouds by friction, thus the reaction between opposite charges (jumping of charges from one cloud to another) in the cloud can lead to lightning. Also, oftentimes the bottom of a cloud is negatively charged so that this is attracted to the positive charge on the earth surface. Thus leading to a discharge called lightning.

Thus in the given question, the appropriate option is C. This implies that, lightning may be accompanied by the sound of explosively expanding hot air, called thunder.

The bullet's undetermined mass is m1 = 1.458 x 103. Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.

Newton's equations of motion state that when a body of mass m is subject to a net external force, the body's momentum changes and is represented by:

f = p/dt

Where:

P is the body's linear momentum.

m2 = m3 = 4.5 x 10-3 kg

v2 = v3 =  575 m/s

The equal masses must move at angles of to each other in order for momentum to be zero in the y-direction.

θ1=180°, θ2=60°, θ3=-60°

m₁ ₓ v₁ ₓ cos180° + m₂ ₓ v₂ ₓ cos60° + m₃ ₓ v₃ ₓ cos(-60°) = 0

m₁ ₓ 575m/s ₓ cos180° + 4.5 x 10-3 kg ₓ 324 m/s ₓ cos60° + 4.5 x 10-3 kg ₓ 324 m/s ₓ cos(-60°) = 0

-m1 ₓ 575m/s + 1.458 ₓ 0.5 + 1.458 ₓ 0.5 = 0

-m1 ₓ 575m/s + 0.729 + 0.729 = 0

-m1 ₓ 575m/s + 1.458 = 0

m1 = 1.458 ₓ 10⁻³

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Answer:

a) Pascal is a derived unit because it is derived from the unit of force and area

b)Mass is a fundamental quantity because it doesn't depends upon others physical quantity and made up of only one unit

c) unit of power is a derived unit because they are dependent quantities

D) unit of length is a fundamental unit because it cannot be expressed in terms of another quantity.

The power required to change a sport utility vehicle's speed is 2725 Watt.

A measure of how quickly an object's location can shift in any direction. Speed is defined as the distance traveled divided by the time required to cover that distance. It is a scalar because speed only has a directions and no magnitude. In common usage and kinematics, the speed of an object is a scalar quantity and is defined as the amount of the change within this object's motion per unit of time or over time.

Speed is calculated as follows: speed = distance * time. Knowing the units for distance and time is necessary to calculate the units for speed. The units will be in metres per second (m/s) in this example since the distance is measured in metres (m) and the time is measured in seconds (s).

Speed is a unit of measurement for how quickly something is moving. The most popular speed measurements are miles per hour (mph), kilometers per hour (km/h), and metres per second (m/s).

Mass of the sport utility = 1600kg

Initial velocity (v1) - 15m/s, (152 = 225)

Final velocity (v2) - 40m/s, ( 402 = 1600)

To find the energy required, Kinetic energy (K.E) = 1/2 mv2

K.E = final K.E - initial K.E

= 1/2(v2-v1)

= 1/2×1600×(1600-225)

= 80 × 1375

= 11000 J

Power = Energy (E)/Time (t) = 1100joule/4sec

= 2725Watt.

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From the first floor to the fourth floor, the elevator's net work during the entire trip is -3mgh.

Given,

On the first floor of a building, an elevator with mass m is initially at rest. It ascends at a constant speed, passing second and third floors before coming to a stop at the fourth floor.

the separation between the floors is h

The distance from the first floor to the fourth floor Equals 3 hours of work = -mg(3 hours)

= -3mgh

Work Done = -3mgh

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Answer:

traveling at a constant acceleration

The maximum energy gain of the boy can be calculated by multiplying his mass (70kg) by the gravitational acceleration (9.81 m/s^2) and the height of the hill (1000m), which gives a value of 686700 J or 686.7 kJ.

The formula E = mgh, where E is the energy gain, m is the boy's mass, g is the acceleration from gravity, and h is the height of the hill, may be used to determine the boy's maximum energy gain. In this instance, the youngster weighs 70 kg, the acceleration caused by gravity is 9.81 m/s^2, and the slope is 1000 metres high. The formula yields E = 70 kg x 9.81 m/s^2 x 1000 m = 686700 J or 686.7 kJ when we insert these numbers. This indicates that throughout his ascent of the hill, the youngster expended a total of 686.7 kilojoules of energy.

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1.  a) no charge

2. a) a transverse wave

3. d) all of the above.

4. a) greater than that of radio waves.

5. b) lower than that of radio waves.

6. d) all of the above.

7. d) all of the above.

8. d) all of the above

9. a) exist for all particles

10. a) modifies classical results

11.  b) the returnee is younger

12. d) all of the above statements are correct.

1. An electromagnetic wave consists of oscillating electric and magnetic fields that propagate through space. It does not carry any net charge.

2. Electromagnetic waves are transverse waves, meaning that the direction of the electric and magnetic fields is perpendicular to the direction of wave propagation.

3. Light exhibits both wave-like and particle-like behavior, as described by the wave-particle duality principle in quantum mechanics.

4. Gamma rays have a higher frequency than radio waves, which means they have more oscillations per unit of time.

5. Gamma rays have a shorter wavelength than radio waves, indicating that the distance between successive wave crests is smaller.

6. When a tree is located 20 meters from a convex lens with a focal length of 10 cm, the image formed is inverted (upside down), diminished (smaller in size compared to the object), and real (can be projected on a screen).

7. An arrow placed 2 cm from a convex lens with a focal length of 5 cm will produce an erect (upright), virtual (cannot be projected on a screen), and magnified (larger in size compared to the object) image.

8. A parabolic mirror, such as a parabolic reflector or a parabolic antenna, has the property of focusing all parallel rays of light (or electromagnetic waves) to a single point called the focus. It also reflects rays originating from the focus in a parallel direction, which is useful for applications like satellite dish antennas. Furthermore, parabolic mirrors can work for a wide range of electromagnetic waves, including radio waves.

9. De Broglie waves, proposed by Louis de Broglie, suggest that particles, such as electrons and protons, exhibit wave-like properties. They are not limited to sound waves or specific particles like hydrogen. De Broglie waves play a crucial role in understanding the wave-particle duality of matter.

10. The Lorentz factor, denoted as γ (gamma), is a term in special relativity. It modifies classical results as objects approach the speed of light, accounting for time dilation, length contraction, and relativistic mass increase. It is a key factor in understanding the effects of high-speed motion and is not limited to geometric optics.

11. In the Twin Paradox scenario, the traveling twin experiences time dilation due to their high velocity, causing them to age slower compared to the twin who stays at home. Thus, when they reunite, (b) the returnee is younger. This phenomenon is a consequence of special relativity and has been confirmed by experiments and observations.

12. Bohr's atomic model describes electrons in discrete energy levels or orbits. According to the model, electrons can jump to lower orbits, emitting photons in the process. They can also spontaneously jump to higher orbits. Additionally, the model suggests that the electron orbit would eventually decay, resulting in the electron spiraling into the proton. However, this aspect is not consistent with modern understanding and is considered a limitation of Bohr's model.

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Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

The team of engineers must first define the problem, Option A.

The term air quality has to do with the overall purity of the air in a certain locality. We know that the air in an area is affected by the activities of the people that reside in that vicinity.

In this case, the team of engineers must first define the problem before they can  improve local air quality in the community.

Missing parts;

A team of engineers is asked to help a community improve local air quality. What must the team do before it can begin to identify possible solutions?

answer choices

Iterate to improve the solution.

Define the problem.

Select one solution.

Model the solution.

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The black car has a speed of 10 m/s

The red car has a speed of - 7.9 m/s

The both cars meet at time = 4s

The position time graph shows the rate at which the position of a body is changing with time. The position of the body is plotted on the vertical axis and the time taken is plotted on the horizontal axis.

We can know how fast the object is going by taking the slope of the position time graph. This is known as the speed of the object. If we look keenly as the graph as we have it we can see that;

1) Speed of the black car = 10 - 0/ 1 - 0 = 10 m/s

2) Speed of the red car = 25 - 80/ 7 - 0 = -7.9 m/s

3 ) The both cars meet at time = 4s

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If the mass attached to the horizontal spring is increased from 0.050 kg to 0.100 kg, the period of oscillation will increase.

This is because the period of an oscillating mass-spring system is inversely proportional to the square root of the mass. As the mass increases, the restoring force provided by the spring becomes stronger, resulting in a slower oscillation and a longer period.

If the mass of the bob in a pendulum is increased from 0.100 kg to 0.300 kg, the period of oscillation will also increase. The period of a pendulum is directly proportional to the square root of the length and inversely proportional to the square root of the acceleration due to gravity. Increasing the mass of the bob without changing the other parameters increases the effective length of the pendulum, which leads to a longer period.

In a swinging pendulum, the bob temporarily stops its motion at the extreme points of its swing, known as the endpoints or the highest and lowest points. This happens because at these positions, the gravitational force acting on the bob is balanced by the tension in the pendulum string or rod, resulting in a net force of zero. As a result, the bob momentarily comes to a stop before changing direction and starting its swing back. This is similar to an object momentarily pausing at the highest point of its trajectory in a projectile motion due to zero vertical velocity.

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Answer:

36 ml

Explanation:

The volume of the water was 50 ml without anything in it. When you put something in water, the amount of volume that it rises is the volume of the object put into it. It rose up to 86 ml.

86-50=36

36 ml