The minimum sample size would be 953.
What is the confidence interval?
A confidence interval is a range of estimates for an unknown parameter in frequentist statistics. A confidence interval is calculated at a specified confidence level; the 95% confidence level is most commonly used, but other levels, such as 90% or 99%, are occasionally used.
The given sample space is n = 300.
x = 101 plan to vote
P = x/n = 101/300 = 0.3367
95% confidence = \(P\pm Z_\frac{\alpha}{2}=1.96\)
Confidence Interval:
\(CI=P\pm Z_\frac{\alpha}{2}\sqrt{\frac{P(1-P)}{n}}\\\\CI=0.3367\pm 1.96 \times \sqrt{\frac{0.3367(1-0.3367)}{300}}\\\\CI=(0.2832, 0,3902)\)
Margin of error = 3%
The margin of Error = \(Z_\frac{\alpha}{2}\sqrt{\frac{P(1-P)}{n}}\)
\(3 \% = P\pm Z_\frac{\alpha}{2}\sqrt{\frac{P(1-P)}{n}}\)
\(\frac{1}{\sqrt{n}}=\frac{0.03}{1.96\sqrt{(0.3367)(1-0.3367)}}\\\\\sqrt{n} = 30.875\\\\n = 953\)
Hence the minimum sample size = 953.
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Can u do these for me
Answer:
Step-by-step explanation:
Compare the decimals using >, <, or =
2.95 > 2.949 (2.95 can be written as 2.950, which is > 2.949)3.75 < 3.8 (3.8 can be written as 3.80, which is > 3.75)0.98 = 0.980 (0.98 can be written as 0.980, which is = 0.980)0.86 < 0.861 (0.86 can be written as 0.860, which is < 0.861)1.76 < 2 (2 can be written as 2.00, which is > 1.76)3.15 < 3.2 ( 3.2 can be written as 3.20, which is > 3.15)Name two equivalent fractions for each fraction listed below.
2/4 = 1/2 = 4/81/3 = 2/6 = 3/91/10 = 2/20 = 3/30If there are 16 cups in one gallon, how many cups are in 3 gallons?
16 cups = 1 gal.
? cups = 3 gals.
3 * 16 = 48 cups
How many cups are in 5 gallons?
5 * 16 = 80 cups
Compare and contrast squares are rectangles
Squares: have four sides and four equal sides
Rectangles: have four sides and have 2 parallel sides, meaning that they have 2 opposite sides that are equal.
Hope this helps!
Help please and thank you !! ill give brainle and 20 points !
Answer:
G 33%
Step-by-step explanation:
17/52 = 0.32692307692
0.32692307692 is about 33 %
Have a nice day! :)
Write these numbers in order of size.
Start with the smallest number.
9
-3
2.
-2
Smallest
Answer:
smallest -3,-2,2,9 biggest
Answer:
-3, -2, 2, 9
Step-by-step explanation:
-3 is the smallest (it is below 0), -2 is second because it is closer to 0 than -3 but still below it, 2 follows, and then 9
The water in Earth’s oceans has a volume of about 3.2x10^8 cubic miles. There are about 1.1 x10^12 gallons in 1 cubic mile. How many gallon jugs would it take to hold all the ocean water on Earth? Show your work. Write your answer using scientific notation
If he water in Earth’s oceans has a volume of about 3.2x10⁸ cubic miles, it would take 3.52x10²⁰ gallon jugs to hold all the water in Earth's oceans.
To calculate how many gallon jugs it would take to hold all the ocean water on Earth, we need to multiply the volume of the water by the conversion factor from cubic miles to gallons.
Given that the water in Earth's oceans has a volume of about 3.2x10⁸ cubic miles and there are about 1.1x10¹² gallons in 1 cubic mile, we can calculate the total number of gallons using the following equation:
Total gallons = (Volume in cubic miles) x (Gallons per cubic mile)
Substituting the given values, we get:
Total gallons = (3.2x10⁸) x (1.1x10¹²) = 3.52x10²⁰
This number is very large and is written in scientific notation to make it more manageable. Scientific notation is a compact way of writing very large or very small numbers using a power of ten. In this case, the number is expressed as a coefficient (3.52) multiplied by 10 raised to the power of 20 (10²⁰).
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a data set has its first and third quartiles as 9 and 17 respectively. Which of the following data points would be considered an outlier for the data set
A. 27
B. 17
C. 3
D. 41
In which of these cases should the mean be used?
A. When the data is left-skewed
B. When the data is symmetric
C. When the data is right-skewed
D. When the data has extreme values
To determine if a data point is considered an outlier for a data set, we need to calculate the interquartile range (IQR) and use it to define the outlier boundaries. The IQR is the difference between the third quartile (Q3) and the first quartile (Q1). The correct option is (B).
We have that Q1 = 9 and Q3 = 17, we can calculate the IQR as follows:
IQR = Q3 - Q1 = 17 - 9 = 8
To identify outliers, we can use the following rule:
- Any data point that is less than Q1 - 1.5 * IQR or greater than Q3 + 1.5 * IQR is considered an outlier.
Using this rule, we can evaluate each data point:
A. 27: This data point is greater than Q3 + 1.5 * IQR = 17 + 1.5 * 8 = 29. It is considered an outlier.
B. 17: This data point is not an outlier because it is equal to the third quartile (Q3).
C. 3: This data point is less than Q1 - 1.5 * IQR = 9 - 1.5 * 8 = -3. It is considered an outlier.
D. 41: This data point is greater than Q3 + 1.5 * IQR = 17 + 1.5 * 8 = 29. It is considered an outlier.
Therefore, the outliers in the data set are A (27) and D (41).
As for when to use the mean, it is generally recommended to use the mean as a measure of central tendency when the data is symmetric and does not have extreme values.
Therefore, the correct option would be B. When the data is symmetric.
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Find the volume of the given solid over the indicated region of integration. f(x,y) = 2x +2y ? 5; R = {(x,y): - 4 leq x leq 1, 3 leq y leq 6} What is the volume of the region? Units^3
The volume of the given solid over the indicated region of integration, f(x,y) = 2x + 2y - 5 and R = {(x,y): -4 ≤ x ≤ 1, 3 ≤ y ≤ 6}, is 63 units³.
To find the volume, we will integrate the function f(x,y) over the region R. Follow these steps:
1. Set up the double integral: ∬R (2x + 2y - 5) dA
2. Set up the limits of integration: ∫(from -4 to 1) ∫(from 3 to 6) (2x + 2y - 5) dy dx
3. Integrate with respect to y: ∫(from -4 to 1) [(2xy + 2y²/2 - 5y)] (evaluated from 3 to 6) dx
4. Simplify and evaluate: ∫(from -4 to 1) [6x + 18 - 5(6-3)] dx
5. Integrate with respect to x: [3x² + 18x - 15x] (evaluated from -4 to 1)
6. Simplify and evaluate: (3 + 18 - 15) - (-12 + 72 + 60)
7. Calculate the final result: 6 - (-30) = 36
The volume of the region is 63 units³.
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HELP ME I NEED THIS DONE
h(x) = 4x +3. What is
the coordinate pair for h (1)?
9514 1404 393
Answer:
(1, 7)
Step-by-step explanation:
Fill in x=1 and do the arithmetic.
h(1) = 4(1) +3 = 7
The coordinate pair is ...
(x, h(x)) = (1, h(1)) = (1, 7)
HELP MEEEE PLEAS!!???
Which expression is equivalent to -6(-2/3+2x)?
Answer:
4+(-12x)
Step-by-step explanation: Hope this helped!
que es una organizacion
por favor es urgente
Step-by-step explanation:
Las organizaciones son estructuras administrativas y sistemas administrativos creadas para lograr metas u objetivos con el apoyo de las propias personas, o con apoyo del talento humano o de otras características similares.
A steel shop has three plasma machines to shear steel sheets and produce various part types automatically using information from a CAD/CAM database. Although the machines are relatively new, each machine breaks down at an average rate of 2 times per week. Two repairmen is available to repair the machines that break down. When a machine breaks down, and the other two are working, it is served immediately by one repairman. If a second machine breaks down (when one machine is down and the other one is working), the idle repairman serves the machine. When the third machine breaks down, and the other two are also down, it waits for service. Each repairman can repair plasma machines at an average rate of 5 machines per week. Machine breakdown times and machine repair times are continuous random variables which distributions possess the memoryless property. Thus, the system can be modeled as a continuous-time Markov chain. (a) Define the states of the Markov chain and draw the state transition diagram including the transition rates. (b) Compute the steady-state probabilities. (c) Determine the average number of working machines.
Steel shop's plasma machine system can be modeled as a continuous-time Markov chain. The states of Markov chain represent the different configurations of machines, repairmen, and number of working machines.
The state transition diagram illustrates the transitions between these states and includes the corresponding transition rates. In this system, there are three main states: (1) all three machines working, (2) one machine down and two working, and (3) two or more machines down. The transition rates depend on the average breakdown rate of the machines and the repair rate of the repairmen. By analyzing the steady-state probabilities and the average number of working machines, we can gain insights into the system's performance and efficiency.
To compute the steady-state probabilities, we can set up a set of equations based on the transition rates and solve for the probabilities of each state. These probabilities represent the long-term behavior of the system, indicating the likelihood of the system being in a particular state at any given time. The steady-state probabilities provide valuable information about the system's reliability and downtime.
Additionally, by determining the average number of working machines, we can assess the overall productivity of the system. This metric takes into account the probabilities of the different states and provides an estimate of the average number of machines that are operational at any given time. By understanding the system's steady-state probabilities and average number of working machines, the steel shop can make informed decisions to optimize maintenance schedules and ensure efficient operation of their plasma machine system.
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Consider the following IVP: y' = ty +t^2, 0<= t<= 2, y(0) = 1 The exact solution of this IVP is y(t) = y = -t^2 – 2(t + 1) + 3et Use Euler's method with step size h = 0.1 to approximate y(1).
The approximate value of y(1) using Euler's method with a step size of h = 0.1 is 1.
Using Euler's method and a step size of h = 0.1, we can use the given initial value problem (IVP) and iterate through the interval [0, 1] in steps of size h to approximate the value of y(1). Let's begin by determining the number of steps required: n = (1-0) / 0.1 = 10.
Utilizing the accompanying recipe, we can repeat through the span beginning with the underlying condition y(0) = 1.
y(i+1) is equivalent to y(i) + h * (t(i) * y(i) + t(i)2), where I is among 0 and n-1, t(i) is equivalent to I * h, and y(i) is the surmised worth of y at t(i).
At each step, we can inexact the upsides of y utilizing the recipe gave:
The approximate value of y(1) is 1, assuming Euler's method and a step size of h = 0.1. y(0) = 1 y(1) y(0) + 0.1 * (0 * y(0) + 02) = 1 + 0.1 * (0 + 0) = 1.
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I think the pic is attached to this
The y-intercept of a line in the xy-plane is (0,1) as shown in attached graph given int the question.
To find the y-intercept of a line in the xy-plane, we need to find the point where the line intersects the y-axis. The y-axis is the vertical axis that runs through the origin and is perpendicular to the x-axis. This means that the y-intercept is the value of y when x is equal to zero. Therefore, we can read off the y-intercept directly from the equation of the line. To find the y-intercept of a line in the xy-plane, we need to find the point where the line intersects the y-axis. The y-axis is the vertical axis that runs through the origin and is perpendicular to the x-axis.
In the given graph we can see that the line intersects the point 1 on y axis.
Therefore, y-intercept of a line in the xy-plane is (0,1).
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The following table shows the number of pieces of junk mail that arrives in my mailbox each day. What is the probability that 3 or fewer pieces of junk mail will be received today? Please show steps with the formula used.Number of Pieces of Junk Mail Frequency
2 2
3 14
4 6
5 16
6 12
The probability of receiving 3 or fewer pieces of junk mail is 0.44 or 44%.
Probability is a measure of how likely an event is to occur.
Total number of pieces of junk mail that could be received = 2 + 14 + 6 + 16 + 12 = 50
Total number of pieces of junk mail that correspond to receiving 3 or fewer pieces = 2 + 14 + 6 = 22
Now calculate the probability by dividing the number of pieces of junk mail that correspond to receiving 3 or fewer pieces by the total number of pieces of junk mail:
P(3 or fewer pieces) = 22/50 = 0.44
So the probability of receiving 3 or fewer pieces of junk mail is 0.44 or 44%.
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what is the length of the missing leg? If necessary, round to the nearest tenth.
Answer:
48 yards
Step-by-step explanation:
Use the Pythagorean theorem:
\( {a}^{2} = {52}^{2} - {20}^{2} = 2704 - 400 = 2304\)
\(a > 0\)
\(a = \sqrt{2304} = 48 \: yd\)
Find the derivative, if it exists, of the function at the specified point.() = ^2 − 4 + 3 at = 1
Find the derivate of the expression using the general procedure to find the derivative of a polynomial function. To do it, multiply the term times the exponent of the variable and raise the variable to the original exponent minus 1:
\(\begin{gathered} f(x)=x^2-4x+3 \\ f^{\prime}(x)=2x^{2-1}-4x^{1-1}-0\cdot3 \\ f^{\prime}(x)=2x-4 \end{gathered}\)Now that we have the expression for the derivative of the function, evaluate it at the value of x that is in the question statement, which is 1:
\(f^{\prime}(1)=2(1)-4=2-4=-2\)The derivative of the function is -2 at x=1.
Saumya read one third of book on Monday, two fifth of the remaining book on Tuesday, and still 60 pages were left to read. Find the total number of pages she read on Monday and Tuesday.(1) 90(2) 50(3) 40(4) 60
Fraction : Word problems may involve fractions if we are dealing with partial values coming from a whole.
Total number of pages she read on Monday are 50 pages .
Total number of pages she read on Tuesday are 40 pages .
Operations with Fractions:
we have to remeber some important rules, making fractions similar for addition and subtraction, and applying the reciprocal for the divisor in division. The operations would depend on the analysis of the problem.
We have given in the problem that on Monday, Saumya read 1/3 of a book and on Tuesday, she read 2/5 of the remaining pages. After those, the remaining number of pages is 60
Firstly, we have to find the total number of pages the book has.
We will begin by finding the remaining fraction of pages after Saumya read on Monday. We will subtract 1/3 from 1 whole since she read from the beginning of the book.
1 − 1/3 = 2/3
Now, we know that on Tuesday, Saumya began reading with 2/3 remaining in the book. We will now find the fraction of the pages Saumya read on Tuesday. We know that it's 2/5 of the remaining pages, so it's 2/5 of 2/3
=> 2/5× 2/3 = 4/15 of the total number of pages of the book on Tuesday. So now, we will find the total fraction of the number of pages of the book that Samuya has read so far. This is so we can compare this fraction with the number of pages remaining. For this, we will add
1/3 + 4/15 = (5 + 4)/15 = 9/15
then 1 - 9/15 = (15-9)/15 = 6/15
This means that there would be another 6/15
= 2/5 of the book remaining and
that the remaining 2/5 of the book = 60 pages the total number of pages = 60/2/5
= 60×5/2 = 150
Therefore, the book has a total of 150 pages.
Total number of pages she read on Monday
= 1/3 of 150 = 50 pages
Total number of pages she read on Tuesday
= 4/15 of 150 = 40 pages
Hence, the total number of pages she read on Monday and Tuesday are 50 pages and 40 pages respectively.
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Which of the following functions exhibit the end behavior f(x) —>infinite as x—> -infinite and f(x) —> -infinite as x—>infinite? Select all that apply. Please help me out! Nobody wants to help :(
The end behavior f(x) → ∞ as x → -∞ means that x-value is negative and y-value is positive. If this is the case, the other end part of the function is located in the 2nd quadrant.
The end behavior f(x) → -∞ as x → ∞ means that the x-value is positive and the y-value is negative. The other end part of the function is located in the 4th quadrant.
Looking at the choices, Option 1 and 4 exhibits these characteristics.
Given the speeds of each runner below, determine who runs the fastest. Stephanie runs 10 feet per second. Brooke runs 192 feet in 24 seconds. Frank runs 1 mile in 449 seconds. Zach runs 817 feet in 1 minute.
Answer:
Step-by-step explanation:
speed of
Stephanie=10 ft/s
Brooke= 192/24=8 ft/s
Frank= (1×1760×3)/449≈11.76 ft/s
Zach=817/(1×60)≈13.62 ft/s
Zach runs fast.
If M=1,000,P=2.25, and Y=2,000, what is velocity? a. 2.25 b. 4.5 c. 2 d. None of the above is true
Answer:d
Step-by-step explanation:
The answer is d. None of the above is true.
To calculate velocity, we need to use the equation:
Velocity = M * P / Y
Given:
M = 1,000
P = 2.25
Y = 2,000
Plugging in the values:
Velocity = 1,000 * 2.25 / 2,000
Simplifying:
Velocity = 2.25 / 2
The result is:
Velocity = 1.125
Therefore, the correct answer is: d. None of the above is true.
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Sarah ran 4 7/8miles, then walked 1 11/12 miles.
Find the total distance she traveled.
Answer:
6 19 /24
Step-by-step explanation:
find the lcd and add
pls help me plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss plssssssssssssssss
Answer:
Step-by-step explanation:
Answer:
4 x 1/4
Step-by-step explanation:
The box is split into 4 representing the 1/4 and it goes to the 4 on the number line representing the.
Part #1: find the solution of the inequality.\(10 \geqslant p - 4\)Part #2: describe the solution
Part 2
The solution is described as p is less than or equal or equal to 14
Which planet is more than one astronomical unit from the Sun? A. Mars B. Earth C. Venus D. Mercury
Answer: Earth
Step-by-step explanation:
Planet (or Dwarf Planet) Distance from the Sun (Astronomical Units miles km) Number of Moons
Mercury 0.39 AU, 36 million miles 57.9 million km 0
Venus 0.723 AU 67.2 million miles 108.2 million km 0
Earth 1 AU 93 million miles 149.6 million km 1
Mars 1.524 AU 141.6 million miles 227.9 million km 2
. Assume that the annual percentage rate increases by 5%, 10%, 20%, 40%, and 60%. [30 marks] a. Calculate the approximate doubling time (Dappx) b. Calculate the exact doubling time (Dexact) c. Calculate the percentage error in calculating the doubling time for each case.
a) Approximate Doubling Time Dappx = 70/r, where r is the annual interest rate in percentage terms.Assuming that r = 5%, 10%, 20%, 40%, and 60%Doubling time for 5% = 70/5 = 14 yearsDoubling time for 10% = 70/10 = 7 yearsDoubling time for 20% = 70/20 = 3.5 yearsDoubling time for 40% = 70/40 = 1.75 yearsDoubling time for 60% = 70/60 = 1.1667 yearsb) Exact Doubling Time Dexact = ln2/r where r is the annual interest rate in decimal terms.
Assuming that r = 5%, 10%, 20%, 40%, and 60%For 5%: ln2/0.05 ≈ 13.86 yearsFor 10%: ln2/0.1 ≈ 6.93 yearsFor 20%: ln2/0.2 ≈ 3.47 yearsFor 40%: ln2/0.4 ≈ 1.73 yearsFor 60%: ln2/0.6 ≈ 1.16 yearsc)
The percentage error is given by:(Dexact − Dappx)/Dexact × 100%For 5%: (13.86 - 14)/13.86 x 100% ≈ 1.18%For 10%: (6.93 - 7)/6.93 x 100%
≈ 1.15%For 20%: (3.47 - 3.5)/3.47 x 100%
≈ -0.86%For 40%: (1.73 - 1.75)/1.73 x 100%
≈ -1.15%For 60%: (1.16 - 1.1667)/1.16 x 100%
≈ -0.60%Note that the percentage error is small for lower values of interest rates but increases as the interest rate increases.
Also, the percentage error is negative for 20%, 40%, and 60%, which means that the approximate doubling time is actually larger than the exact doubling time.
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what is the scale factor of dilation
Answer:
The center of a dilation is a fixed point in the plane about which all points are expanded.
Linear Algebra and Differential Equation Question 1 Choose the correct solution of the given linear differential equation by separating the variables. Not yet answered dy dx xy² Marked out of 2.00 -y = =+ c Pag question y=+C 11. iii. y = -- iv. 3-54
The correct solution of the linear differential equation dy/dx = xy^2, obtained by separating the variables, is y = -1/(c - x^2), where c is a constant.
To solve the given linear differential equation, we can separate the variables by writing it as dy/y^2 = xdx. Integrating both sides, we get ∫(1/y^2)dy = ∫xdx.
The integral of 1/y^2 with respect to y is -1/y, and the integral of x with respect to x is (1/2)x^2. Applying the antiderivatives, we have -1/y = (1/2)x^2 + c, where c is the constant of integration.
To isolate y, we can take the reciprocal of both sides, resulting in y = -1/(c - x^2), where c represents the constant of integration.
Therefore, the correct solution of the linear differential equation dy/dx = xy^2, obtained by separating the variables, is y = -1/(c - x^2), where c is a constant.
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Simplify the following expression.
The simplification of the expression ½(18t) + 2t(9) -12 is 27t-12
What is simplification of expression?Simplifying an expression is just another way to say solving a math problem. When you simplify an expression, you're basically trying to write it in the simplest way possible.
For example, 3a²+9a+12 can be simplified by bring out the common factors between the terms
= 3(a²+3a+4).
Similarly, 1/2(18t) + 2t(9) -12 can be simplified as;
9t + 18t -12
= 27t -12
therefore the simplification of ½(18t) + 2t(9) -12 is 27t-12
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ASAP plz!
If MO = 210, find the value of x. Then find MN and NO.
Answer:
x = 40
MN = 140
NO = 70
Step-by-step explanation:
MN + NO = MO
4x-20 + 2x -10 = 210
6x-30 = 210
6x = 240
x = 240/6
x = 40
4x-20
4 * 40 -20 =
160-20 =
140
MN = 140
2x-10 =
2 * 40 -10=
80 - 10=
70
NO = 70
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It would help me a lot!
Thank you!