a probability experiment consists of rolling a fair 10-sided die. Find the probability of the event below.

rolling a number greater than 3

Answer:

f(x)=x^3-13x-12

Step-by-step explanation:

Answer:

60 ?

Step-by-step explanation:

Student's mean score of the class is 80.6.

Mean:

Mean or the average of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set.

Given,

A student receives test scores of 62, 83, and 91. the student's term project score is 88 and her homework score is 76. each test is worth 20% of the final grade, the term project is 25% of the final grade, and the homework grade is 15% of the final grade.

Here we need to find the student's mean score in the class.

First, we have to convert the percentage into decimal,

Then

=> 20% = 0.20

=> 25% = 0.25

=> 15% = 0.15

Then we have to find the scores from it,

Test A is 0.20 of the total and scores 62.

Test B is 0.20 of the total and scores 83.

Test C is 0.20 of the total and scores 91.

Project F is 0.25 of the total and scores 88.

Work H is 0.15 of the total and scores 76.

Multiply across:

=> A = (0.2 * 62) = 12.4

=> B = (0.2 * 83) = 16.6

=> C = (0.2 * 91) = 18.2

=> F = (0.25 * 88) = 22

=> H = (0.15 * 76) = 11.4

Now we have to add all these values to find the mean,

=> A + B + C + F + H

=> 12.4 + 16.6 + 18.2 + 22 + 11.4

=> 80.6

Therefore, the mean of that student is 80.6

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Based on the arithmetic sequence with the first term −5 and the common difference 4 is 660, we could find m = 20.

To find the sum of the first m terms of an arithmetic sequence, we can use the formula:

sum = (m/2)(2a + (m-1)d),

where a is the first term,

d is the common difference,

and m is the number of terms.

In this case, we are given a = −5, d = 4, and sum = 660. We can plug these values into the formula and solve for m:
660 = (m/2)(2(-5) + (m-1)(4))
660 = (m/2)(-10 + 4m - 4)
660 = (m/2)(4m - 14)
1320 = m(4m - 14)
0 = 4m^2 - 14m - 1320

Now we can use the quadratic formula to solve for m:
m = (-b ± √(b^2 - 4ac))/(2a)
m = (-(−14) ± √((−14)^2 - 4(4)(-1320)))/(2(4))
m = (14 ± √(196 + 21120))/8
m = (14 ± √21316)/8
m = (14 ± 146)/8

Now we have two possible values for m:
m = (14 + 146)/8 = 160/8 = 20
m = (14 - 146)/8 = -132/8 = -16.5

Since m must be a positive integer, we can conclude that m = 20. Therefore, the sum of the first 20 terms of the arithmetic sequence is 660.

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The complete statements are as follows;

The variable is represented by one orange x tiles.

Subtract three is represented by three blue - tiles.

The tiles represent subtraction 3 from an unknown number.

Algebra tiles are square and rectangle shaped tiles or tiles that represent numbers and variables.

Given

Use the algebra tiles to model x -3.

The complete statements are as follows;

The variable is represented by one orange x tiles.

Subtract three is represented by three blue - tiles.

The tiles represent subtraction 3 from an unknown number.

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Answer:

Use the algebra tiles to model x – 3.

Then complete the statements.

The variable is represented by

✔ one orange x tile

Subtracting three is represented by

✔ three blue – tiles

.

The tiles represent

✔ subtracting 3 from

an unknown number.

Step-by-step explanation:

Answer:

values in range

Step-by-step explanation:

Answer:

Step-by-step explanation:

_____________________________________________________

\(4+2\times (-4)+8\times (-1)\)

_____________________________________________________

\(4-2\times 4+8\times (-1)\)

\(4-2\times 4-8\)

______________________________________________________

\(4-8-8\)

______________________________________________________

\(-4-8\)

\(-12\)

I hope this helps you

:)

Answer: X = 8.5

Step-by-step explanation:

2x = 17

divide by 2

x = 8.5

By solving the value we get the value of x that is equal to 8.5.

\(\to\) 2x=17

\(\to\)  x=\(\frac{17}{2}\)

\(\to\) x=8.5

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Situation in which dentist use the hypothesis test for a difference in two population is each patient uses non-fluoride toothpaste for one year, then the new fluoride toothpaste for one year. After each year, the dentist examines all 100 patients. The dentist calculates the change in number of cavities for all 100 patients.

After one year, the dentist examines all 100 patients. The dentist compares the change in number of cavities  in the two groups.  The dentist records whether each patient has less cavities, no difference, or more cavities after one year.

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The factored form of the equation are as follows;

Converting a quadratic function to factored form is called factoring.

Therefore,

let's factor the equation,

a.

d² - 7d + 6 = 0

d² - d - 6d + 6 = 0

d(d - 1) - 6(d - 1) = 0

(d - 6)(d - 1) = 0

b.

x² + 18x + 81 = 0

x² + 9x + 9x + 81 = 0

x(x + 9) + 9(x + 9) = 0

(x + 9)(x + 9) = 0

c.

u² + 7u - 60 = 0

u² - 5u + 12u - 60 = 0

u(u - 5) 12(u - 5) = 0

(u + 12)(u - 5) = 0

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Answer:

3

Explanation:

For every 3 cupcakes that Edgar gets, Fred gets 1. So, if Edgar gets 9, Fred gets 3.

The slope of the line is \(\frac{2-0}{0-(-4)}=\frac{1}{2}\).

Substituting into point-slope form, the equation is \(\boxed{y=\frac{1}{2}x+2}\).

Answer: 36,290,000

Step-by-step explanation:

Let's define two sequences, one representing the number of ways to order lunch on the "n"th day if Angela ate chicken salad on the (n-1)th day, and another representing the number of ways if she didn't.
If Angela ate chicken salad on the (n-1)th day, then she cannot eat it on the n-th day. Therefore, the number of ways for the "n"th day is equal to the number of ways for the (n-1)th day when Angela didn't eat chicken salad.
If Angela didn't eat chicken salad on the (n-1)th day, then she has two options for the n-th day: either eat chicken salad or not. If she doesn't eat chicken salad, the number of ways for the "n"th day is equal to the number of ways for the (n-1)th day when she didn't eat chicken salad. If she does eat chicken salad, the number of ways for the "n"th day is equal to the number of ways for the (n-2)th day when she didn't eat chicken salad.
Therefore, the recurrence relation is:
f(n) = f(n-1) + g(n-1)
g(n) = f(n-1) if Angela didn't eat chicken salad on the (n-1)th day
g(n) = f(n-2) if Angela ate chicken salad on the (n-1)th day.

To find the recurrence relation for the number of ways for Angela to order lunch for the "n" days, we need to consider two cases: when Angela ate chicken salad on the (n-1)th day and when she didn't.

If Angela ate chicken salad on the (n-1)th day, then she cannot eat it on the n-th day, as she cannot eat chicken salad three days in a row. Therefore, the number of ways for the "n"th day is equal to the number of ways for the (n-1)th day when Angela didn't eat chicken salad.

If Angela didn't eat chicken salad on the (n-1)th day, then she has two options for the n-th day: either eat chicken salad or not. If she doesn't eat chicken salad, the number of ways for the "n"th day is equal to the number of ways for the (n-1)th day when she didn't eat chicken salad. If she does eat chicken salad, the number of ways for the "n"th day is equal to the number of ways for the (n-2)th day when she didn't eat chicken salad.

Therefore, we can define two sequences, f(n) representing the number of ways to order lunch on the "n"th day if Angela didn't eat chicken salad on the (n-1)th day, and g(n) representing the number of ways if she did. Then, the recurrence relation can be written as:

f(n) = f(n-1) + g(n-1)

g(n) = f(n-1) if Angela didn't eat chicken salad on the (n-1)th day

g(n) = f(n-2) if Angela ate chicken salad on the (n-1)th day.

In conclusion, we can use the recurrence relation f(n) = f(n-1) + g(n-1) and g(n) = f(n-1) if Angela didn't eat chicken salad on the (n-1)th day, and g(n) = f(n-2) if she did, to calculate the number of ways for Angela to order lunch for the "n" days if she never orders chicken salad three days in a row.

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Answer:

(8+2) + (8+2) + (8+2) + (8+2) + (8+2)

Step-by-step explanation:

The distributive property of multiplication allows you to show multiplication as addition.

The average of y is given x in the simple regression model. The correct answer is OC. Hyjx = Bo +Byx.

A regression model is a statistical method for estimating the relationship between one or more independent variables and a dependent variable (also known as the response variable) (also called the explanatory variables or predictors). The primary goal of regression analysis is to forecast the value of the dependent variable based on the independent variables' values.

In a simple linear regression model, the equation is y = Bo + B1x + e, where Bo is the intercept and B1 is the slope. The average of y given x is represented by the expected value of y given x, which is E(y|x) = Bo + B1x. This equation represents the regression line, which is a line that best fits the data points in the scatter plot.

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Answer:

The last option

Step-by-step explanation:

SSS means that all the sides are congruent

Line RS is conected so you know its congruent.

RU and RT is the last sides left

also the last option is the only one that includes an two congruent lines

Answer:

between 222 and 223 days

Step-by-step explanation:

This relation includes the point (0, 2).

A proportional relation must include the point (0, 0).

This is not proportional, but it may be linear.

Points: (0, 2), (2, 20)

y = mx + b

20 = (20 - 2)/(2 - 0) × 2 + b

20 = 18/2 × 2 + b

b = 2

y = 18x + 2

When 4000 people know, y = 4000.

y = 18x + 2

4000 = 18x + 2

3998 = 18x

x = 3998/18

x = 222.111...

Answer: between 222 and 223 days

Observational data that contains a numerical value or amount is called quantitative observation.

Quantitative observation is an objective data gathering that is primarily concerned with numbers and values and is "related to, of or expressed in terms of a quantity." The outcomes of a quantitative observation are derived using statistical and numerical analytic techniques. Thus, quantitative observation refers to observational data that includes a numerical value or amount.

An objective gathering of facts, quantitative observation refers to "related to, of or depicted in terms of a quantity" and is generally focused on numbers and values. Methods of statistical and numerical analysis are used to derive the results of quantitative observation.

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Answer:

NL is congruent to US.

Answer:

d. NL ≅US

Step-by-step explanation:

ΔMNL ≅ ΔTUS

follow the order in ≅ statement meaning that MN ≅ TU,NL ≅US, ML ≅ TS

Answer:

The new interest rate is about 0.1038.

As a percent, this is about 10.4%.

Step-by-step explanation:

We are given:

\(\displaystyle A=250(1.1)^t\)

From this, we can determine that the interest rate is compounded annually at 10%.

We want a new equation that keeps A and P but the interest rate is compounded quarterly.

Compound interest is given by:

\(\displaystyle A=P(1+\frac{r}{n})^{nt}\)

Since we are compounding quarterly, n = 4. Since the rate is 10%, r = 0.1. P stays at 250. Therefore:

\(\displaystyle A=250(1+\frac{0.1}{4})^{4t}\)

Add:

\(\displaystyle A=250(1.025)^{4t}\)

Rewrite:

\(A=250((1.025)^4)^t\)

So:

\(A\approx 250(1.1038)^t\)

Therefore, the approximate new interest rate is 1.1038 - 1 or about 0.1038.

As a percent, this will be 0.1038 or about 10.4%.

Answer:

-12 and 4

Step-by-step explanation:

-12 x 4 = 48

and

-12 + 4 = -8

Answer:

-12 and +4

Step-by-step explanation:

-12 * 4 = - 48

-12 + 4 = - 8

Answer:

the answer is jesus asdlkfjsfs

Answer:

Step-by-step explanation:

lo siento, pero su pregunta no tiene sentido.

Answer:

\(w = 13500\) --- real windscreen

\(v = 408\) --- scale volume

Step-by-step explanation:

Given

\(k = \frac{1}{10}\) --- scale factor

See attachment

Required

Complete the table

To get the windscreen (w) of the real car, we do the following computation

\(w = \frac{w_{scale}}{k^2}\)

This gives:

\(w = \frac{135}{(1/10)^2}\)

\(w = \frac{135}{1/100}\)

\(w = 13500\)

Next, the volume (v) of the scale mode

We make use of the following computation

\(v = v_{real} * k^3\)

So, we have:

\(v = 408000 * (1/10)^3\)

\(v = 408000 * 1/1000\)

\(v = 408\)

The probability that 115 or fewer of the 250 homes were partially financed by the seller is approximately 0.9733.

This problem can be solved using the binomial distribution, where

n = 250 is the total number of home sales in the sample.

p = 0.4 is the probability that any given home sale is partially financed by the seller.

X is the number of home sales in the sample that are partially financed by the seller, which we are interested in.

The probability of X successes in n independent Bernoulli trials, each with success probability p, is given by the probability mass function of the binomial distribution

P(X = k) = (n choose k) * p^k * (1-p)^(n-k)

where (n choose k) is the binomial coefficient, which represents the number of ways to choose k items out of n without regard to order.

To solve this problem, we need to calculate the cumulative probability of 115 or fewer home sales being partially financed by the seller

P(X ≤ 115) = P(X = 0) + P(X = 1) + ... + P(X = 115)

We can use a statistical software or calculator to calculate this probability directly, or we can use the normal approximation to the binomial distribution, which is valid when n is large and p is not too close to 0 or 1.

The mean of the binomial distribution is μ = np = 250 * 0.4 = 100, and the standard deviation is σ = sqrt(np(1-p)) = sqrt(60) ≈ 7.746.

To use the normal approximation, we standardize the random variable X as follows

Z = (X - μ) / σ

Then, we can use the standard normal distribution to calculate the probability

P(X ≤ 115) ≈ P(Z ≤ (115 - μ) / σ)

P(Z ≤ (115 - μ) / σ) = P(Z ≤ (115 - 100) / 7.746) ≈ P(Z ≤ 1.934)

Using a standard normal table or calculator, we find that P(Z ≤ 1.934) ≈ 0.9733.

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The number of games in her phone is 10

An algebraic expression can simply be defined as an expression that is composed of terms, factors, some variables, coefficients and then constants.

They are also known to consist of some mathematical operations, which may include;

Based on the information given, we have;

Let the number of games in her phone be s

s + 3s - 7 = 33

collect like terms

4s = 40

Make 's' the subject

s = 40/4

s = 10 games

Hence. the number is 10

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The number of students admissions office should accept to maximize the total tuition while limiting the total attrition to 600 first-year students are 2,800 in-state and 700 out-of-state.

We are to determine how many in-state and out-of-state students to accept while maximizing the total tuition and limiting the total attrition to 600 students.

Let us suppose that x students from in-state will be accepted and y students from out-of-state will be accepted.

So the total number of students that will be accepted will be:

x + y ≤ 3500

From past experiences, the admissions office knows that 12% of in-state students and 24% of out-of-state students will drop out in their first year.

Therefore, the number of students that will drop out in their first year will be:

0.12x + 0.24y ≤ 600

Also, we know that Tech is a state institution, so the number of out-of-state students should not exceed 40% of the total number of students, which is:

0.4(x + y) ≥ y

Also, we can find the tuition fees by multiplying the number of students accepted from each state by their respective tuition fees.

The tuition for an in-state student is $7600 per year, while the tuition for an out-of-state student is $22,500 per year.

So, the total tuition is:

7600x + 22500y

In order to maximize the total tuition, we will have to solve this linear programming problem:

Maximize Z = 7600x + 22500y

Subject to:

x + y ≤ 35000.

12x + 0.24y ≤ 6000.

4(x + y) ≥ y

x ≥ 0, y ≥ 0

The graphical representation of the constraints is shown below:

The region enclosed by the feasible region is shown by A B C D. Each point on the line AB represents the combination of x and y which satisfies x + y = 3500.

Each point on the line BD represents the combination of x and y which satisfies 0.4(x + y) = y, which represents the point where 40% of the students are out-of-state.

Each point on the line CD represents the combination of x and y which satisfies 0.12x + 0.24y = 600, which represents the point where the attrition is limited to 600 students.

The optimal solution is (x, y) = (2800, 700), which gives the maximum tuition fees as follows:

$7600(2800) + $22,500(700) = $58,820,000

Therefore, the admissions office should accept 2,800 in-state and 700 out-of-state students to maximize the total tuition while limiting the total attrition to 600 first-year students.

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