A projectile is launched at an angle of 60 degrees above the horizontal. Compared to the vertical component of the initial velocity of the projectile, the vertical component of the projectile's velocity when it has reached its maximum height is
(1) smaller
(2) larger
(3) the same

The acceleration of the mass in terms of {m} is -

a = 2F/m.

The force acting on a body is given by -

Force {F} = mass {m} x acceleration {a}

Given is that a net force of {F} is applied to half the mass {m/2}.

We know that -

Force {F} = mass {m} x acceleration {a}

F = {m/2} x a

a = 2F/m

Therefore, the acceleration of the mass in terms of {m} is -

a = 2F/m.

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Answer:

Given :  

m 1 =0.5 kg        

u 1 =0 m/s                    

m 2=0.005 kg      

u 2=200 m/s              

Let the velocity acquired by the block after the collision be V.

Using conservation of linear momentum before and after the collision :    P i =P f

​∴    m1u 1 +m 2u 2=(m 1+m 2 )V

OR    

0.5×0+0.005×200=(0.5+0.005)V              

⟹V≈1.9  m/s

Answer:

V= 1.9  m/s

Explanation:

I did the test

Hope this helps :)

oh ok where is it bring it

The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

Electric field is the physical field that surrounds a charge.

a=F/m=qE/m

E= electric field

m= mass of electron

=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)

=10¹⁵×0.526m/s²

v0=initial velocity of the electron =5×10⁶m/s

a=acceleration of the electron =10¹⁵×0.526m/s²

Δx=distance moved by the electron in east direction =1cm=10^-2m

=25×10¹²+10.52×10¹²

=35.52×10¹²

Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

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It is C) doing work because he is moving the bale of cotton.It only makes sense he is still doing work the pulley is just making it easier.

Answer:

F= 3.56e22N

Explanation:

Using the force of radiation acting on the earth which is

force = radiation pressure x area = (intensity/c)xpi R^2

force = 1370W/m^2 x pi x( 6.37x10^6m)^2/3x10^8m/s

force = 5.82x10^8 N

But the sun's gravitational attraction means the magnitude of the solar gravitational force on earth: If that's the case, the answer is approx 10^22 N:

F=GMm/r^2

G=6.67x10^(-11)=6.67e-11

M=mass sun = 2x10^30kg=2e30

m=mass earth = 6x10^24kg

r=earth sun distance = 1.5x10^11m

F=(6.6e-11)(2e30)(6e24)/(1.5e11)^2 =

F= 3.56e22N

The probability of getting a prime number ( 2, 3, 5, 7) between 1 to 8 is 1/2. The total outcomes possible for spinning the spinner and tossing the coin is 16.

Branch of mathematics concerning numerical descriptions of how likely an event is to occur is called probability.

Total number of outcomes = 8.

Let, the probability of getting a prime number ( 2, 3, 5, 7) between 1 to 8

P(E) = (no. of outcomes) /( total no. of outcomes)

=4/8

=1/2

When a coin is tossed,  there are two possible outcomes that are H(head), and T(tail).

If you spin the spinner , there are 8 possibilities.

Total outcomes = 8 * 2

=16

There are 16 outcomes, when spinning a spinner numbered from 1 to 8 and tossing a coin.

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Answer:

Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8m s2 = 9800N To draw a Free Body Diagram, draw an elevator cage (I am sure you would get lots of points for drawing it with intricate detail) with a downward force of 9800 N. I hope this helps,

Explanation:

Explanation:

❀ \( \underline {{\underline{ \text{Given} }}}: \)

❀ \( \underline{ \underline{ \text{To \: find}}} : \)

❀ \( \underline{ \underline{ \text{Solution}}} : \)

\( \boxed{ \sf{force = mass \times acceleration}}\)

Plug the known values :

⟶\( \sf{1000 \times 9.8}\)

⟶ \( \sf{9800 \: N}\)

\( \red{\boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 9800 \: N}}}}\)

Hope I helped !♡

Have a wonderful day / night ! ツ

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Answer:5

Explanation:

You do change in y over change in X

Answer:

a)    I= I₀ (cos²θ - cos⁴θ)    b) 75.5º

Explanation:

a) For this exercise we must use Malus's law

         I = I₀ cos² θ

where tea is the angle between the two polarizers.

We apply this expression to our case

* Polarizer 1 suppose that it is vertical and polarizer 2 (intermediate) is at an angle θ with respect to the vertical

         I₁ = I₀ cos² θ

* We analyze for the polarity 2 and the last polarizer 3 which indicate that it must be at 90º from the first one, therefore it must be horizontal.

The angle of polarizers 2 and 3 is θ' measured from the horizontal, if we measure with respect to the vertical

              θ₂ = 90- θ’ = θ

fiate that in the exercise we must take a reference system and measure everything with respect to this system.

          I = I₁ cos² θ'

we substitute

         I = (I₀ cos² tea) cos² (θ - 90)

        cos (θ -90) = cos θ cos 90 + sin θ sin 90 = sin θ

         I = Io cos² θ sin² θ

        1= cos²θ+ sin²θ

       sin²θ = 1 - cos²θ

        I= I₀ (cos²θ - cos⁴θ)

b) to find when the intensity is maximum,

we can use that we have an extreme point when the drift is zero

          \(\frac{dI}{d \theta}\) = 0

          \frac{dI}{d \theta}= Io (2 cos θ - 4 cos³θ) = 0

whereby

            cos θ - 2 cos³ θ = 0

            cos θ ( 1 - 2 cos² θ) = 0  

The zeros of this function are in

           θ = 90º

           1-2cos²θ =0       cos θ = 0.25  θ =  75.5º

Let's analyze this two results for the angle of 90º the intnesidd is zero with respect to the first polarizer, so it is not an acceptable solution.

Consequently, the angle that allows the maximum intensity to pass is 75.5º

The term "internal energy" describes the combined potential and kinetic energy of a system or substance. It is the potential energy held inside the bonds between those particles as well as the energy that results from the motion and interactions of the molecules and atoms within a substance.

The chaotic, random motion of molecules is known as a system's internal energy; a system's total (internal) energy is made up of both potential and kinetic energy.

The sum of the random internal kinetic energies of the atoms and the total internal potential is known as a system's internal energy.energies due to the bonds between atoms. Internal energy is not a new concept or form of energy. On the other hand, heat is a new concept that is central to thermodynamics.

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Given:

The proper length of the sports car is: L₀ = 5.9 m

The contracted length of the sports car is: L = 5.4 m

To find:

The speed of the car.

Explanation:

The length contraction is the shortening of the length of the moving object as measured relative to the observer's frame of reference.

The expression for length contraction is given as:

Here, L is the contracted length, L₀ is the proper length, v is the speed of the object and c is the speed of light having a value 3 × 10⁸ m/s.

Substituting the values in the above equation, we get:

Final answer:

The sports car should travel with a speed of 0.40c so that the length of the car appears to be 5.4 m.

To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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Based on the densities of the two liquids, the height of the light liquid in the right arm of the U-tube is 0.203 cm.

Let's first consider the situation before the light liquid is added. At this point, the heavy liquid fills both arms of the U-tube to the same height, h.

The pressure at point A is equal to the pressure at point B

Therefore:

P₀ + ρgh = P₀ + ρgh

where P₀ is the atmospheric pressure, ρ is the density of the heavy liquid, and g is the acceleration due to gravity.

Simplifying this equation, we get:

ρgh = ρgh

Canceling out the ρ and solving for h, we get:

h = h

In other words, the height of the heavy liquid is the same in both arms of the U-tube.

Now let's consider the situation after the light liquid is added to the right arm of the U-tube. We want to find the height, L, of the light liquid in the right arm.

Since the pressure at any two points in a connected vessel is the same, the pressure at point B (the top of the heavy liquid in the right arm) must be equal to the pressure at point C (the top of the light liquid in the right arm).

Therefore, we can write:

P₀ + ρgh = P₀ + ρg(L+h)

where L is the height of the light liquid in the right arm.

Simplifying this equation, we get:

ρgh = ρgL + ρgh

Canceling out the ρgh and solving for L, we get:

L = (ρ/ρ₀)h

where ρ₀ is the density of the light liquid.

Substituting the given values, we get:

L = (0.92 g/cm³ / 13 g/cm³)h

L = 0.070769h

Now we need to find h. We can use the fact that the volume of the heavy liquid in the left arm is equal to the volume of the heavy liquid plus the light liquid in the right arm.

The volume of the heavy liquid in the left arm is:

V₁ = Ah = (13.2 cm²)(h cm)

V₁ = 13.2h cm³

The volume of the heavy liquid plus the light liquid in the right arm is:

V₂ = A(L+h) = (2.11 cm²)(L+h cm)

V₂ = 2.11(L+h) cm³

Since these volumes are equal, we can set them equal to each other and solve for h:

13.2h = 2.11(L+h)

13.2h = 2.11L + 2.11h

11.09h = 2.11L

h = (2.11/11.09)L

Substituting this into our expression for L, we get:

L = 0.070769(2.11/11.09)L

L = 0.01345L

L = 0.01444h

Substituting the given value for the density of the heavy liquid, we get:

L = 0.01444h = 0.01444(13 g/cm³)/(0.92 g/cm³)

L = 0.203 cm

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Complete question:

A heavy liquid with a density 13 g/cm³ is poured into a U-tube as shown in the left- hand figure below. The left-hand arm of the tube has a cross-sectional area of 13.2 cm², and the right-hand arm has a cross-sectional area of 2.11 cm². A quantity of 90.2 g of a light liquid with a density 0.92 g/cm³ is then poured into the right-hand arm as shown in the right-hand figure below.

Determine the height L of the light liquid in the column in the right arm of the U-tube, as shown in the second figure above. Answer in units of cm.

Answer:

T = 34.54 N

Explanation:

First we find the buoyant force acting on the sphere, due to displaced water. For that purpose, we need to find the volume of water displaced by the sphere.

Volume of Water Displaced = V = (Mass of Sphere)/(Density of metal)

V = 4.7 kg/(4000 kg/m³)

V = 0.001175 m³

Now, the buoyant force is given as:

F = (Density of Water)(V)(g)

F = (1000 kg/m³)(0.001175 m³)(9.8 m/s²)

F = 11.52 N

Now, we find the weight of the sphere:

W = mg = (4.7 kg)(9.8 m/s²)

W = 46.06 N

Since, both the tension force (T) and buoyant force act in upward direction, while the weight of sphere act in downward direction. Therefore,

W = T + F

T = W - F

T = 46.06 N - 11.52 N

T = 34.54 N

The tension in the chord when sphere emmerged out of the water is 34.54 N.

Volume of Water Displaced,

\(\bold { V = \dfrac m\rho}\)

Where,

m -Mass of Sphere = 4.7 kg

\(\bold {\bold { \rho}}\) - Density of metal = 4000 kg/m³

Thus,

\(\bold {\bold { V = \dfrac {4.7\ kg}{4000\ kg/m^3}}}\\\\\bold {\bold { V = 0.001175 m^3}}\)

The buoyant force on sphere,

F = (Density of Water) (V) (g)  

F = (1000 kg/m³) (0.001175 m³) (9.8 m/s²)  

F = 11.52 N

So, weight of the sphere,  

W = mg

w = (4.7 kg) (9.8 m/s²)  

w = 46.06 N

Since, both the tension force and buoyant force act in upward direction, while the weight of sphere act in opposite direction.  

T = W - F  

T = 46.06 N - 11.52 N  

T = 34.54 N

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The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

The intensity of the force F is calculated to be approximately 2.83 N.

Coefficient of sliding friction is a value that measures force of sliding friction for particular surface type.

Weight = mg = 1 kg x 10 m/s² = 10 N (acting downwards)

F_vertical - Weight = 0

F_vertical = 10 N

As Frictional force = coefficient of friction x normal force

Frictional force = 0.2 x 10 N = 2 N (acting to the left)

F_horizontal = F x cos(45) = F / √2

F_horizontal - frictional force = 0

F_horizontal = frictional force = 2 N

F / √2 = 2 N

F = 2 N x √2

F ≈ 2.83 N

Therefore, the intensity of the force F is approximately 2.83 N.

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Answer:

10.20meters

Explanation:

Answer:

10.2 m

Explanation:

The formula for potential energy is

PE=mgh

Let's plug in the given values into the equation

300 J = 3.00 kg*9.8m/s²*h

We're assuming that the object is on Earth and has a gravitational acceleration of 9.8m/s²

300J = 29.4 N * h

h = 10.2 m

The following theories contributed significantly to a more full knowledge of black body radiation. Light is made up of separate pieces that must be absorbed together.

A black body is an object that absorbed all radiation falling on it at all wavelengths. When a black body is at a constant temperature, its emission exhibits a temperature-dependent frequency distribution. It emits what is known as black-body radiation.

One of the first experiments that led to quantum mechanics was blackbody radiation. It all started with the basic observation that when you heat a metal, it first turns red, then yellow, and finally white hot as the temperature rises.

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Answer-

mk thats kool.

Answer:

Force Friction

Explanation:

The size of the nail if increased, there will be more surface to attract more number of sewing pins. Thus by using a nail larger than the one shown, the number of pins picked up by the nail is increased.

An electromagnet is a magnetic material or metal that produce an electromagnetic field on to which the magnetically susceptible particles can be attracted.

An electromagnetic field is a combination of electric field and magnetic field. The direction of both will be perpendicular for an object. A magnet is usually made of iron and iron containing alloys.

If the surface of the magnetic nail has more space to attract, then more pins can be picked up using this. We cannot increase the attracted pins by increasing the coils around the nails. Thus option A is correct.

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Answer:

Mass of Exoplanet =  0.58 kg

Explanation:

First, we will calculate the speed of the forest moon:

\(speed = v = \frac{Circumference}{time}\\\)

circumference = 2πr = 2π(14441566 m) = 90739035.3 m

time = 6 days 10 hr = (6 days)(24 h/1 day)(3600 s/1 h) + (10 h)(3600 s/1 h)

time = 554400 s

Therefore,

\(v = \frac{90739035.3\ m}{554400\ s}\\\\v = 163.67\ m/s\)

We know that the centripetal force on forest moon will be equal to the gravitational force given by Newton's Gravitational Law, as follows:

\(Centripetal\ Force = Gravitational\ Force\\\frac{m_{moon}v^2}{r} = \frac{Gm_{moon}m_{exoplanet}}{r^2}\\\\m_{exoplanet} = \frac{v^2r}{G}\\\\m_{exoplanet} = \frac{(163.67\ m/s)^2(14441566)}{6.67\ x\ 10^{-11}\ N.m^2/kg^2}\)

Mass of Exoplanet =  0.58 kg

Answer:

Explanation:

v = 50 km / h

= 13.89 m /s

When a vehicle runs on a circular path , it is static friction which prevents it from getting overturned .

static friction = μs mg

centripetal force = m v² / R

m v² / R = μs mg

R = v² / μs x g

= 13.89² / .7 x 9.8

= 28.12 m .

The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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Answer:

37.85 Liters in 10 US gallons

Explanation:

if asking for volume: volume = 3.785liters

Answer:  arrows

Explanation:

A vector quantity is usually represented by an arrow, with the direction of the vector being the direction in which the arrow points and the length of the arrow representing the vector's magnitude.

What is the vector quantity unit?

The meter is the only fundamental SI unit that is a vector. The rest are all scalars. Derived quantities might be scalar or vector, but all vector quantities require meters as part of their definition and measurement.

The term "vector quantities" refers to physical quantities whose magnitude and direction are well specified.

Arrows are used to depict vectors. An arrow has a direction and a magnitude (how long it is) (the direction in which it points).

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Answer: With no friction, the box will accelerate down the ramp

Explanation:

The amount of energy needed to boil away the water at the initial temperature  is 301,248 J.

The amount of energy needed to boil the water at the given is calculated as follows;

Q = mcΔθ

where;

density of water = 1000 g/L

mass = density x volume

mass of water = 1000 g/L x 1.6 L = 1,600 g

Q = 1600 g x 4.184 J/g⁰C x (100⁰C - 55 ⁰C)

Q = 301,248 J

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