A proton moves perpendicularly to a uniform magnetic field of strength 0.0585 t at a speed of 15,400 m/s. what is the radius of the circle it describes?
Answers
The proton moving perpendicularly to a uniform magnetic field of 0.0585 T and a speed of 15,400 m/s will describe a circular path with a radius of approximately 0.1017 meters. The magnitude of this force is given by the equation F = qvB, where q is the charge of the particle, v is its velocity, and B is the magnetic field strength.
When a charged particle moves through a magnetic field perpendicular to its velocity, it experiences a magnetic force that acts as a centripetal force, causing it to move in a circular path.
Let's calculate the radius of the circular path.
Given:
Charge of the proton, q = \(+1.6 x 10^-^1^9 C\)
Velocity of the proton, v = 15,400 m/s
Magnetic field strength, B = 0.0585 T
The magnetic force acting on the proton can be calculated using the formula F = qvB.
F = \((1.6 x 10^-^1^9 C) * (15,400 m/s) * (0.0585 T)= 1.8776 x 10^-^1^4 N\)
Since the magnetic force is equal to the centripetal force, we can equate them:
F = \(mv^2 / r\)
Here, the mass of the proton, m, is approximately \(1.67 x 10^-^2^7\) kg.
\(1.8776 x 10^-^1^4 N = (1.67 x 10^-^2^7 kg) * (15,400 m/s)^2 / r\)
Simplifying the equation and solving for r:
r = \((1.67 x 10^-^2^7 kg) * (15,400 m/s)^2 / (1.8776 x 10^-^1^4 N)\)
= 0.1017 meters
Therefore, the radius of the circular path is approximately 0.1017 meters.
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Related Questions
How does the electric force between two charges particles charge if the distance between them is increased by a factor of 2?
A. It increased by a factor of 4
B. It increased by a factor of 2
C. It decreased by a factor of 4
D. It decreased by a factor of 2
APEX???
Answers
Answer:
C
Explanation:
The electric force between two charged particles decreases by a factor of 4 if the distance between them is increased by a factor of 2. This is because the electric force is inversely proportional to the square of the distance between the charges. So, if the distance is doubled, the force is 1/4 as strong.
Thus, The answer is C.
a movable bin and its contents have a combined weight of 2.1 kn determine the shortest chain sling acb that can be used to lift the loaded bin if the tension in the chain is not to exceed 5 kn. the shortest chain sling acb that can be used is m.
Answers
The shortest chain sling ACB for a movable bin is 1.228 m.
The question is not complete. A similar question is in the attachment. Use the image in a similar question for this problem. Look at the picture. In the system works
Tension in the chain T₁ and T₂The weight of a movable bin = wTriangle ABC is an isosceles triangle. If ∠ CAB = ∠ CBA = θ.
T₁ = T₂ ≤ 5 kNT₁ = T₂ = 5,000 N AC = BCw = 2.1 kN = 2,100 N
At point C, the direction of the weight is upward.The forces T₁ and T₂ can be described with respect to the y-axes and become T₁y and T₂y. Look at triangle ACO
sin θ = T₁/T₁y
T₁y = T₁ sin θ Look at triangle BCO
sin θ = T₂/T₂y
T₂y = T₂ sin θ
According to Newton's first law, in the y-axis
∑ F = 0
w - T₁y - T₂y = 0
T₁y + T₂y = 2,100
T₁ sin θ + T₂ sin θ = 2,100
5,000 sin θ + 5,000 sin θ = 2,100
10,000 sin θ = 2,100
sin θ = 2,100 ÷ 10,000
sin θ = 0.21
θ = sin⁻¹ (0.21)
θ = 12.12°
Look at AOC
AO = OB = AB ÷ 2 = 1.2 ÷ 2 = 0.6 m cos θ = AO ÷ACcos 12.12° = 0.6 ÷ AC
0.978 = 0.6 ÷ AC
AC = 0.6 ÷ 0.978
AC = 0.614 mACB = AC + BC
ACB = 0.614 + 0.614
ACB = 1.228 m
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What is the resistance of a device if there is a current of 1.50A when a potential difference of 4.00V is placed across it?0.3756.002.502.67
Answers
Resistance(R) of a device is given by
\(\begin{gathered} R=\text{ }\frac{V}{I}\begin{cases}V={potential\text{ difference = 4.00V}} \\ I={current=\text{ 1.50 A}}\end{cases} \\ \therefore R=\text{ }\frac{4.00}{1.50}=2.67\Omega\text{ \lparen Approx\rparen} \end{gathered}\)Final answer is :- 2.67 ohm
If a force of 2N is applied on a surface with area of 4sq. M,then find the pressure exerted on that surface?
Answers
Pressure is defined as the force per unit area and can be calculated as:0.5 Pa (pascals)
As per the data given in the above question are as bellow,
The provided data are as bellow,
p = F / A
where:
F = 2 N (applied force)
A = 4 m^2 (surface area)
So, the pressure exerted on the surface can be calculated as:
p = 2 N / 4 m^2
= 0.5 N/m^2
= 0.5 Pa (pascals)
The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. The units used to indicate pressure vary.
The standard unit of pressure is a pascal (Pa). Given that a pascal is a relatively small unit of pressure, the kilopascal is the most appropriate measurement for commonplace gas pressures (kPa). 1000 pascals make up one kilopascal. The atmosphere is another frequently used measurement of pressure (atm)
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If the near point of your eye is at 75 cm, you have A) Myopia and you need converging lens to correct your vision. B) Myopia and you need diverging lens to correct your vision. C) Presbyopia and you need diverging lens to correct your vision. D) Hyperopia and you need converging lens to correct your vision. E) Hyperopia and you need diverging lens to correct your vision.
Answers
If the near point of your eye is at 75 cm, you have hyperopia and you need converging lens to correct your vision.
Hyperopia, also known as farsightedness, is a common eye condition in which light entering the eye focuses behind the retina instead of directly on it. This can make distant objects appear clear, but nearby objects may appear blurry.
In this case, the near point of the eye is farther away than the typical distance of 25 cm, indicating that the eye has a refractive error that causes light to focus too far back in the eye. This means that the eye needs a converging lens, which is a convex lens that bends light inward, to help focus light on the retina and correct the vision.
On the other hand, myopia, also known as nearsightedness, occurs when light entering the eye focuses in front of the retina instead of directly on it, causing distant objects to appear blurry. Myopia can be corrected with a diverging lens, which is a concave lens that bends light outward.
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why are metal spiked shoes a good ideas fro golfers to wear on a stormy day
Answers
Actually, metal spiked shoes are not necessarily a good idea for golfers to wear on a stormy day. In fact, many golf courses have banned metal spikes altogether due to their potential to damage the course. Instead, golfers often wear soft-spiked shoes on stormy days.
which provides better traction on wet and slippery surfaces. Soft spikes are made of rubber or other synthetic materials, which also help to protect the greens and fairways. So while spiked shoes are important for golfers to maintain stability and prevent slipping, it's important to choose the right type of spikes for the course conditions and rules.
1. Traction: The metal spikes provide excellent grip on wet and slippery ground, helping golfers maintain their footing and stability during swings.
2. Stability: The spiked shoes prevent golfers from slipping or sliding, allowing them to maintain proper stance and balance during their swing, which is essential for accurate shots.
3. Drainage: Metal spiked shoes allow water to pass through more easily, which helps keep the golfer's feet drier and more comfortable in wet conditions.
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A drop of oil of volume 10 ^-10 m3 spreads out on water to make a circular film radius 10^-1m what is the thickness of the film
Answers
Answer:
The thickness of the film is = 3.183e-9m
Explanation:
It will help us if we understand that the shape of the circular film can be approximated to be a cylinder. The height of this cylinder, or its thickness, in this case, will be very small.
Since we can approximate the shape of the drop of oil to be a cylinder, after it has spread out on the surface of the water, we can use the cylindrical geometric formulas to find out how thick the film is.
The volume of a cylinder = \(\pi r^2 h\)
our radius is given as \(10^{-1}m = 0.1m\)
the volume is \(10 ^{-10} m^3=1e-10m^3\)
Remember that our task is to find the height of the cylinder. We can do this by making the height the subject of the formula.
\(h = \frac{Volume}{\pi r^2} = \\\\\frac{1e-10}{\pi \times 0.1^2} = 3.183e-9m\)
Therefore, the thickness of the film is = 3.183e-9m
A static body of mass 80 kg, a force act upon it is 45N move against friction 7.5N, after 5sec the force become zero, so the body stops after ... sec.
40
35
25
None of them
I need the answer urgently
Answers
This means that the body stops immediately after the force acting on it becomes zero. Therefore, the correct answer is None of them.
What is Velocity?
Velocity is a physical quantity that describes the speed and direction of motion of an object. It is a vector quantity, which means that it has both magnitude and direction.
To calculate the time taken by the body to stop, we need to use the concept of Newton's second law of motion, which states that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass.
The initial force acting on the body is 45 N, and the frictional force opposing its motion is 7.5 N. Therefore, the net force acting on the body is:
Net force = 45 N - 7.5 N = 37.5 N
Using Newton's second law of motion, we can calculate the acceleration of the body:
Acceleration = Net force / Mass = 37.5 N / 80 kg = 0.469 m/\(s^{2}\)
Now, to find the time taken by the body to stop, we can use the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity (which is zero), a is the acceleration, and t is the time taken.
When the force acting on the body becomes zero, the body continues to move with the same velocity until it comes to a stop. Therefore, the final velocity is also zero.
0 = 0 + 0.469 * t
t = 0 / 0.469 = 0 seconds
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If your engine is flooded with gasoline, you should push the ____ to the floor and hold for _____.
a. accelerator, 5 seconds
b. accelerator, 1 minute
c. brake, 1 minute
d. brake, 5 seconds
Answers
If your engine is flooded with gasoline, you should push the brake, to the floor and hold for 5 seconds.
What is gasoline?Gasoline or petrol is a transparent, petroleum-derived flammable liquid that is used primarily as a fuel in most spark-ignited internal combustion engines. Gasoline is already considered frozen if it turns into a thick sludge or wax. To totally avoid frozen gasoline inside the car, focus on preventing the fuel line from freezing during winter. Stale gasoline can be dangerous as it contains a combination of over 150 chemicals that can destroy both animal and human lives. Gasoline vapors are heavier than air, so they settle on the ground and travel like a liquid. Because of this, they often find their way into drains, basements, and sewer lines.
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1. What is the difference between the particles oscillate in transverse and longitudinal waves
Answers
Two parallel plates have an area of0.188 m². How much charge must youplace on them to create a 37000 N/Cfield between the plates?[?]. 10⁰¹ C
Answers
Given:
The area of the plate is: A = 0.188 m²
The field produced between the plates is: E = 37000 N/C
To find:
The charge to be placed on the plates.
Explanation:
The electric field produced between two parallel plates is given as:
\(E=\frac{Q}{A\epsilon_0}\)Here, Q is the charge on the parallel plates and ε₀ is the permittivity of free space having a value of 8.85 × 10⁻¹² C²/N.m²
Rearranging the above equation, we get:
\(Q=EA\epsilon_0\)Substituting the values in the above equation, we get:
\(\begin{gathered} Q=37000\text{ N/C}\times0.188\text{ m}^2\times8.85\times10^{-12}\text{ C}^2\text{/N.m}^2 \\ \\ Q=6.156\times10^{-8}\text{ C} \end{gathered}\)Final answer:
The amount of charge to be placed on parallel plates is 6.156 × 10⁻⁸ C.
HELP!!
A particular electric car is supplied with 300 kJ of chemical energy by the battery. Of this, a total of 70.5 kJ of energy is wasted as heat.
Calculate the overall efficiency of the electric car.
Answers
\(\\ \sf\longmapsto 300-70.5=229.5kJ\)
We know
\(\boxed{\sf Efficiency=\dfrac{Used\:Energy}{Supplied\:Energy}\times 100}\)
\(\\ \sf\longmapsto Efficiency=\dfrac{229.5}{300}\times 100\)
\(\\ \sf\longmapsto Efficiency=\dfrac{229.5}{3}\)
\(\\ \sf\longmapsto Efficiency=76.5\%\)
Suppose you manage a factory that uses many electric motors. The motors create a large inductive load to the electric power line as well as a resistive load. The electric. company builds an extra-heavy distribution line to supply you with two components of current: one that is 90⁰ out of phase with the voltage and another that is in phase with the voltage. The electric company charges you an extra fee for "reactive volt-amps" in addition to the amount you pay for the energy you use. You can avoid the extra fee by installing a capacitor between the power line and your factory. The following problem models this solution. In an R L circuit, a 120-V/rms, 60.0 -Hz source is in series with a 25.0-mH inductor and a 20.0-Ω resistor. What are (c) What capacitor must be added in series to make the power factor equal to 1 ?
Answers
You need to add a capacitor of approximately 26.8 microfarads (μF) in series to make the power factor equal to 1 in your RL circuit.
To make the power factor equal to 1, we need to introduce a capacitor in series with the RL circuit. The capacitor will compensate for the inductive reactive power and bring the circuit into a balanced state.
In this case, we have a 120 V/rms, 60.0 Hz source in series with a 25.0 mH inductor and a 20.0 Ω resistor.
To calculate the value of the capacitor, we first need to determine the reactive power of the inductive load. Reactive power (Q) can be calculated using the formula:
Q = Vrms * Irms * sin(θ)
Where Vrms is the rms voltage, Irms is the rms current, and θ is the phase angle between the voltage and current.
Since the power factor needs to be equal to 1, the phase angle (θ) should be 0.
In an RL circuit, the current lags the voltage by an angle θ. In this case, the inductive load is causing the current to lag behind the voltage. To compensate for this, we need to introduce a capacitive reactance (Xc) that leads the current.
The capacitive reactance (Xc) can be calculated using the formula:
Xc = 1 / (2 * π * f * C)
Where f is the frequency (60.0 Hz) and C is the capacitance.
To make the power factor equal to 1, the reactive power of the capacitor should be equal and opposite to the reactive power of the inductor. Therefore, we can equate the reactive powers:
Q(inductor) = -Q(capacitor)
Vrms * Irms * sin(θ_inductor) = -Vrms * Irms * sin(θ_capacitor)
Since sin(θ) for both the inductor and capacitor should be equal, we can cancel out the voltage and current terms:
sin(θ_inductor) = -sin(θ_capacitor)
The sine function is an odd function, which means sin(-x) = -sin(x). Therefore, we can conclude that:
θ_inductor = -θ_capacitor
Since θ = 0 for a power factor of 1, we have:
θ_inductor = -θ_capacitor = 0
Now, let's calculate the value of the capacitor needed to achieve a power factor of 1:
Xc = XL (since Xc = -XL for a power factor of 1)
1 / (2 * π * f * C) = XL
C = 1 / (2 * π * f * XL)
XL is the inductive reactance, which can be calculated using the formula:
XL = 2 * π * f * L
XL = 2 * π * 60.0 Hz * 25.0 mH
XL ≈ 9.42 Ω
Now, we can substitute the value of XL into the equation to calculate the required capacitance:
C = 1 / (2 * π * 60.0 Hz * 9.42 Ω)
C ≈ 2.68 × 10^(-5) F or 26.8 μF
Therefore, you need to add a capacitor of approximately 26.8 microfarads (μF) in series to make the power factor equal to 1 in your RL circuit.
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The principal objective of our booster club is to raise money for new marching band uniforms. Which definition best helps readers find the correct meaning of principal in this sentence
Answers
The definition that best helps readers find the correct meaning of "principal" in this sentence is: "Principal - noun: the person with the highest authority or most important position in an organization, institution, or group."
In the given sentence, the word "principal" is used as a noun, referring to a person. The context indicates that the booster club has a specific objective, which is to raise money for new marching band uniforms. Therefore, it is logical to infer that "principal" in this sentence refers to a person who holds the highest authority or most important position in the booster club. This person would play a crucial role in leading the club, making decisions, and overseeing the fundraising efforts.
By understanding the definition of "principal" as the person with the highest authority or most important position, readers can grasp the intended meaning of the sentence and recognize the key objective of the booster club.
In the given sentence, the word "principal" refers to the person with the highest authority or most important position in the booster club. This understanding aligns with the objective stated, which is to raise money for new marching band uniforms.
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You carry a 20 N bag of dog food up a 6.0 m flight of stairs. How much work was done?
Answers
120 J
Explanation:
Formula Of Work= Work= Force x Displacement
Work= 20 N x 6.0
Work= 120 Joules
The reason I put joules because the Unit of work is joules
which of the following is a form of kinetic energy?
Answers
Answer:
hope this helps.
Explanation:
______
If you're the white mouse, what will you do in order for you to survive
Answers
Answer:
If I was the white mouse, I would either find somewhere to hide that matches my fur color to camoflouge with or dig into the dirt so less visible.
To find white colour habitat.
What will I do for my survival?If I was the white mouse, I would find white colour place for living because in that white colour the predators can't see me and i will be safe from them so we can conclude that finding white colour habitat is the best choice to safe myself.
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A mass of 337 g is attached to a spring and set into simple harmonic motion with a period of 0.256 s. If the total energy of the oscillating system is 6.74 J,determine the following.
(a) maximum speed of the object
m/s
(b) force constant
N/m
(c) amplitude of the motion
m
I want details.
Answers
The amplitude of the motion is 0.087 m.
A mass of 337 g is attached to a spring and set into simple harmonic motion with a period of 0.256 s. If the total energy of the oscillating system is 6.74 J,
Given:
Mass (m) = 337 g = 0.337 kg
Period (T) = 0.256 s
Total energy (E) = 6.74 J
To find the maximum speed of the object (a):
We know that the total energy of the oscillating system is the sum of its kinetic energy (KE) and potential energy (PE):
E = KE + PE
At the point of maximum displacement (i.e. at the ends of the oscillation), all of the energy is in the form of kinetic energy, so we can write:
\(E = (1/2)mv^2\)
where v is the maximum speed of the object.
Rearranging the equation, we get:
\(v = sqrt(2E/m)\)
Plugging in the values, we get:
v = sqrt(2 x 6.74 / 0.337) = 7.36 m/s
Therefore, the maximum speed of the object is 7.36 m/s.
To find the force constant (b):
The period of simple harmonic motion is given by:
\(T = 2πsqrt(m/b)\)
where b is the force constant.
Rearranging the equation, we get:
\(b = 4π^2m / T^2\)
Plugging in the values, we get:
\(b = 4π^2 x 0.337 / 0.256^2 = 547.4 N/m\)
Therefore, the force constant is 547.4 N/m.
To find the amplitude of the motion (c):
The amplitude of the motion is given by:
\(A = sqrt(2E/bm)\)
Plugging in the values, we get:
\(A = sqrt(2 x 6.74 / (547.4 x 0.337)) = 0.087 m\)
Therefore, the amplitude of the motion is 0.087 m.
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The next closest star to Earth, Proxima Centuri, is 4.25 lightyears away. How far is that in meters?
Answers
Answer:
4.0208 x 10^16 meters
Explanation:
speed of light in m/s * # seconds in a year * 4.25 years =
2.99792 x 10^8 * 3600*24*365.25 * 4.25 = 4.0208 x 10^16 m
A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.
Answers
(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.
(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:
Energy = Power × Time
Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:
Time = Energy ÷ Power
Converting the energy to watt-hours (Wh):
Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh
Converting the power to watt-hours (Wh):
Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh
Now we can calculate the time:
Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours
Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.
(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.
In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.
This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.
(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.
In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.
(d) The electromagnetic field output from an antenna can be represented by two main regions:
Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.
Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation. The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.
The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.
In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.
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if kinetic energy of a body of mass 10 kg is 2000 J find velocity
Answers
Answer:
I guess answer is 10m/s.
Explanation:
Kinetic Energy=1/2 mv^2
or,2000J=1/2×10kg×v^2
or2000J=5kg.v^2
or,2000J/5kg=v^2
or,100J/kg=v^2
or,v=10m/s
The asteroid, Ida, has a small moon, Dactyl, that orbits at a speed of 5.66 m/s in an orbit of radius 90, 000m . What is Ida's mass?
Answers
Answer:
4.3 x 10^16 kg
Explanation:
M = rv^2/G =[90,000 x 5.66^2] / [6.67 x 10^-11]
M = 43,226,446,776,611,694 = 4.3 x 10^16 kg - Ida's mass.
Answer:
Explanation:
the person on top of me was correct 4.3 10^16 i have it in my notes from when i was in school :) so they are right
Describe the shape of a field created by a bar magnet
Answers
Answer:
its circular
Explanation:
How can larger telescopes
give astronomers a more precise picture of the distances to the nearest stars?
Answers
Answer:
Explanation:
"Larger telescopes" generally means larger apertures. This is the part of the telescope which collects the light. The more light collected, the more clear the picture becomes
An object was thrown straight up to land on a platform of 3.2 m high. What isthe least initial velocity needed from the ground level to do this? (using g9.81 ms 2).
Answers
ANSWER
7.95 m/s
EXPLANATION
The least initial velocity is the one for which when the object reaches the height of the platform its velocity is zero. From the velocity equation we have,
\(v=v_o-gt\)If v = 0,
\(v_o=gt\)To find the velocity we have to find the time. From the displacement equation,
\(y=v_ot-\frac{1}{2}gt^2\)Replace v0 by the expression above,
\(\begin{gathered} y=gt^2-\frac{1}{2}gt^2 \\ y=\frac{1}{2}gt^2 \end{gathered}\)We know that the height of the platform is 3.2m. Solving this equation for t,
\(t=\sqrt[]{\frac{2y}{g}}=\sqrt[]{\frac{2\cdot3.2m}{9.81m/s^2}}\approx0.81s\)If the object is in the air for 0.81 seconds before reaching the platform, its initial velocity is,
\(v_o=gt=9.81m/s^2\cdot0.81s=7.95m/s\)The least initial velocity needed from ground level for the object to reach the platform is 7.95 m/s
what mass, in grams, of nacl needs to be added to 1.7 kg of water in order to create a solution with a freezing point of -4.1 °c? the freezing point depression constant of water is 1.86 ºc/m.
Answers
218.4 grams of NaCl needs to be added to 1.7 kg of water in order to create a solution with a freezing point of -4.1 °C.
Determine the mass of NaClTo find the mass of NaCl needed to create a solution with a freezing point of -4.1 °C, we can use the freezing point depression equation:
ΔTf = Kf × m
Where ΔTf is the change in freezing point, Kf is the freezing point depression constant of the solvent, and m is the molality of the solution. Rearranging the equation to solve for m, we get:
m = ΔTf / Kf
Plugging in the given values, we get:
m = (-4.1 °C) / (1.86 °C/m) = -2.2 mol/kg
Since we have 1.7 kg of water, the total number of moles of NaCl needed is:
-2.2 mol/kg × 1.7 kg = -3.74 mol
To find the mass of NaCl, we can use the molar mass of NaCl (58.44 g/mol):
-3.74 mol × 58.44 g/mol = -218.4 g
So the mass of NaCl needed is 218.4 g.
Therefore, 218.4 grams of NaCl needs to be added to 1.7 kg of water in order to create a solution with a freezing point of -4.1 °C.
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In terms of diameter, the planet saturn is larger than _______ , but smaller than _______.
Answers
Answer:
Larger than mercury, venus, earth, mars, uranus, neptune
smaller than jupiter
a truck travels up a hill with a 13.0 ◦ incline. the truck has a constant speed of 21.0 m/s. what is the horizontal component of the truck’s velocity?
Answers
Answer:
20.46m/s
Explanation:
\(21 \times \cos(13) = 20.46\)
The drop time can be calculated as follows: where y is the vertical height of the table and g is the
acceleration due to gravity. How did the calculated drop time compare to the average of your measured drop
times? Find the percent error using the following equation:
What factors might cause the differences?
Answers
Answer:
Tt can be calculated by copy
6tyhfdytythftyhyhfytfyht
Answers
Answer:
Six is the only number that is both the sum and the product of three consecutive positive numbers.
Explanation: