A proton (q = 1.60×10−19 C, m = 1.67×10−27 kg) moves in a uniform magnetic field B⃗ = (0.540 T)i^.

At t = 0 the proton has a velocity components vx = 1.50×105 m/s, vy=0, and vz = 2.10×105 m/s.

(a) What is the magnitude of the magnetic force acting on the proton?

(b) In addition to the magnetic field there is a uniform electric field in the +x-direction, E⃗ =(2.30×104 V/m)i^.
Will the proton have a component of acceleration in the direction of the electric field?

Answer:

5.6 m/s

Explanation:

m = 0.25 kg, h = 2 m

initail energy = mgh = 0.25 * 9.81 * 2 = 4.91 J

80% of 4.91 J converted to final kinetic energy mv^2/2

so 0.8 * 4.91 = 0.25*v^2/2

v^2 = 2*0.8*4.91/0.25 = 31.4

v = 5.6 m/s

Answer:

11.9 m/s

Explanation:

a = F/m = 25 / 12 = 2.08 m/s^2.

a=change in v/change in time

2.08 times 5.7= v

. = 11.88 m/s

If a net force of 25 N is applied for 5.7 s to a 12 kg box initially at rest, then the speed of the box at the end of the 5.7 - s interval would be 11.875 m / s .

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem we have to find the speed of the box at the end of the 5.7-s interval, if a net force of 25 N is applied for 5.7 s to a 12 kg box initially at rest ,

F = m × a

25 N = 12 ×a

a = 2.08  m / s²

Now by using the first equation of the motion,

v = u + a × t

v = 0 + 2.08 × 5.7

v = 11.875 m / s

Thus, the speed of the box at the end of the 5.7-s interval would be 11.875 m / s .

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Answer:

Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector. So displacement cannot be more than distance.

The size of an object's displacement can never be greater than the distance the object travels by the object because displacement is the shortest distance traveled between the initial and the final position.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.

Displacement can never be greater than the distance covered by any moving body.

Since displacement is the smallest distance between the beginning and final positions, the size of an object's displacement can never be more than the distance the object travels.

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Table A agrees with the information in the problem. After 25.0 seconds, the velocity of the plane is 187 m/s.

Based on the given problem, we need to determine the velocity of a plane after 25.0 seconds. The plane is initially flying east at a velocity of 115 m/s, and it experiences an acceleration of 2.88 m/s² in the northwest direction.

Let's analyze each option and calculate the final velocity (Vf) of the plane after 25.0 seconds:

Option A:

Vi = 115 m/s

a = 2.88 m/s²

t = 25.0 s

Using the equation Vf = Vi + at, we can calculate:

Vf = 115 m/s + (2.88 m/s²)(25.0 s) = 115 m/s + 72 m/s = 187 m/s

Option B:

V₁ = 2.04 m/s

a = 2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 2.04 m/s + (2.04 m/s²)(25.0 s) = 2.04 m/s + 51 m/s = 53.04 m/s

Option C:

V₁ = 115 m/s

a = -2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 115 m/s + (-2.04 m/s²)(25.0 s) = 115 m/s - 51 m/s = 64 m/s

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Answer:

See below

Explanation:

Average speed =  (0+ 10)/2 = 5 m/s

 then to cover 50 m     will take    50 m / 5 m/s  = 10 seconds

     change in velocity/ change in time = acceleration = 10/10 = 1 m/s^2

The work function of the metal is W₀ = hν₀

The electrons on and near the surface of the metal are expelled when light of continuous intensity and frequency that is greater than the threshold frequency falls on an electrode in a vacuum glass tube. For the sake of simplicity, assume that each photon releases one electron. Now that the light is consistent in intensity, the quantity of photons released and those that collide with the surface will likewise be constant, leading to a constant quantity of electrons released from the metal surface. But because they are at various speeds, the ejected electrons each have a varied amount of kinetic energy.

Therefore, from above we can said, that the minimum energy of an electron from the metal surface is known as work function.

W₀ = hν₀

In above equation, h is plank constant its value is 6.626 × 10⁻³⁴J-s and ν₀

is the frequency of incident radiation.

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Answer:

Nat gas

Explanation:

Approx:

Natural gas 38%       coal 21%       oil  19%

If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.

Option A is correct.

impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.

If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.

Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.

As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.

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The quadratic equation for the resistance ratio is 6E-06 t^2 + 0.00341t +1.

The temperature at which electric resistance would be double is  293.25 Fahrenheit.

Resistance predicted at 71 degrees is 1.2724.

What is resistance ratio?

The resistance ratio is the difference between the thermometer's resistance at the ice point and its resistance at a given temperature (t) (t0).

Temp t

in

degrees

(x) c(t) / c(0) (y) (x)2 (x)3 (x)4  xy x2 y

0 1 0 0 0 0 0

10 1.0393 100 1000 10000 10.393 103.93

20 1.0798 400 8000 16000 21.596 431.92

30 1.1215 900 27000 81000 33.645 1009.35

40 1.1644 1600 64000 2560000 46.576 1863.04

sum =100 5.405 3000 100000 2667000 112.21 3408.24

a. To calculate equation in the form of y = ax^2 + bx +c

Substituting the values calculated above in the formula

= 112.21 - (100*5.405) /5 =4.11

= 100000 - (3000*100)/5 =40000

= 2667000 -1800000 = 867000

a = { [ Σ x2 y * Σ xx ] - [Σ xy * Σ xx2 ] } / { [ Σ xx * Σ x2x 2] - [Σ xx2 ]2 }

= 6E-06

b = { [ Σ xy * Σ x2x2 ] - [Σ x2y * Σ xx2 ] } / { [ Σ xx * Σ x2x 2] - [Σ xx2 ]2 }

= 0.00341

c = [ Σ y / n ] - { b * [ Σ x / n ] } - { a * [ Σ x 2 / n ] } = 1.012

So the equation is c(t)/c(0) = 6E-06 t^2 + 0.00341t +1

b). c(t)/c(0) =2

Putting in the quadratic equation found above-

2 = 6E-06 t^2 + 0.00341t +1

1 = 0.00341t  (neglecting the square term)

t = 293.25 fahrenheit

c). at 71 degrees

c(t)/c(0) = 0.030246+0.24211+1.012

= 1.27235

Resistance predicted at 71 degrees = 1.2724

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The scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable.

Observation is the first step of the scientific method, which then requires to raise a question that will be answered by a testable hypothesis.

The scientific method is a series of well-established steps used to collect scientific empirical data/evidence, which allow to test a given hypothesis.

In conclusion, the scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable..

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Answer: The focal length of the lens is 2.60 cm

Explanation:

The equation for lens formula follows:

\(\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\)

where,

f = focal length = ? cm

v = image distance = 2.9 cm

u = Object distance = -25 cm

Putting values in above equation, we get:

\(\frac{1}{f}=\frac{1}{2.9}-\frac{1}{(-25)}\\\\\frac{1}{f}=\frac{1}{2.9}+\frac{1}{(25)}\\\\\frac{1}{f}=\frac{25+2.9}{2.9\times 25}\\\\f=\frac{72.5}{27.9}=2.60cm\)

Hence, the focal length of the lens is 2.60 cm

The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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If the participants hadn't been reassigned, age would have been a confounding variable. Option D

A confounding variable is a variable that is associated with both the independent variable and the dependent variable.

In this case, age is associated with both video game playing and mood. Younger people are more likely to play video games, and they are also more likely to have better moods.

If the participants hadn't been reassigned, the difference in mood between the experimental and control groups could have been due to the difference in age, not the difference in video game playing.

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Answer:

a. Muscular endurance

is correct answer

please mark me as brainliest

Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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The emergent angle of the first wavelength is 25.53⁰.

The emergent angle of the second wavelength is 26⁰.

The angle each beam leave the the prism is calculated using Snell's law as follows;

\(n_1 si n\theta _1 = n_2 sin\theta_2\)

The emergent angle of the first wavelength is calculated as follows;

\(sin(45) = 1.64sin\theta_1\\\\sin\theta _1 = \frac{sin(45)}{1.64} \\\\sin\theta _1 = 0.431\\\\\theta_1 = sin^{-1} ( 0.431)\\\\\theta_1 =25.53 ^0\)

The emergent angle of the second wavelength is calculated as follows;

\(sin(45) = n_2 sin(\theta_2)\\\\sin(45) = 1.62 sin(\theta_2)\\\\sin(\theta_2) = \frac{sin(45) }{1.62} \\\\sin(\theta_2) = 26^0\)

"Your question is not complete, it seems be missing the following information";

A parallel beam of light containing two wavelengths, λ1 = 465 nm and λ2 = 652 nm, enters the silicate flint glass of an equilateral prism. At what angles, θ1 and θ2, does each beam leave the prism. Use n455nm = 1.64 and n642nm =1.62. The incident angle is 45⁰.

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Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.

Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.

Hence, cheese is made up of casein proteins that are present in the milk.

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The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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The force that accelerates a 0.010 kg bullet from rest to a speed of 1100 m/s in a distance of 1 meter is 11 newton.

Force is the entity that changes the motion of an object. It is calculated by multiplying the mass by acceleration.

Mass is the weight of an object per unit. Acceleration is a change in the rate of velocity.

F = ma

The mass is 0.010 kga change

convert into grams = 10 grams

The acceleration is  1100 m/s

putting the value in the formula

1100 x 10 = 11, 000

convert into kg = 11

Thus, the size force accelerates is 11 N.

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Answer:

B. 8,437.5 J

Explanation:

Given the following data;

Height = 400m

Mass = 75kg

Velocity = 15m/s

Time = 10 secs

To find the kinetic energy of the skier?

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

Substituting into the equation, we have;

\( K.E = \frac{1}{2}*75*15^{2}\)

\( K.E = 37.5*225\)

K.E = 8,437.5 Joules.

Answer:

Refraction involves passing through a boundary (choice a) and changing speed (choice ... A ray of light in air is incident on an air-to-glass boundary at an angle of 30. ... If the index of refraction of the glass is 1.65, what is the angle of the refracted ray ... The critical angle is the angle of incidence (which is always in the more ...

Explanation:

Answer:

350 ft/s²

Explanation:

First, convert mph to ft/s.

58 mi/hr × (5280 ft/mi) × (1 hr / 3600 s) = 85.1 ft/s

Given:

v₀ = 85.1 ft/s

v = 0 ft/s

t = 0.24 s

Find: a

v = at + v₀

a = (v − v₀) / t

a = (0 ft/s − 85.1 ft/s) / 0.24 s

a = -354 ft/s²

Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².

Answer:

2613.3 pa

Explanation:

p=F/A

p=ma/A

p=200×9.8/0.75

p=2613.3

Answer:

Hooke law describes the behaviour of elastic material under tension

Answer:

KE = 60.91875 J

Explanation:

First, convert the mass of the ball into kg, since we want the answer in J (SI system):

150 g = 0.15 kg

then use the kinetic energy formula

\(KE=\frac{1}{2} m*v^{2} \\KE=\frac{1}{2} (0.15)*(28.5)^{2}\\KE=60.91875 J\)

This question involves the concepts of wave speed, wavelength, and frequency.

The frequency of the wave in seawater will be "2.68 Hz".

The relationship between speed, wavelength, and frequency of the wave can be given by the following formula:

\(v=f\lambda\\\\\lambda =\frac{v}{f}\)

Here, the wavelength of the wave is a constant property. Therefore,

\(\frac{v_1}{f_1}=\frac{v_2}{f_2}\)

where,

Therefore,

\(\frac{3950\ m/s}{7.05\ Hz}=\frac{1500\ m/s}{f_2}\\\\f_2=\frac{(1500\ m/s)(7.05\ Hz)}{3950\ m/s}\)

f₂ = 2.68 Hz

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Answer: B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.

Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.

As the Heat of vaporization for methyl alcohol  (1100) is almost half as that of Heat of vaporization for water (2257) , it means  Methyl alcohol requires less than half as much energy per kg to evaporate than water does.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The velocity of the conducting bar is 6.6 m/s.

Resistance, R = 8.5 Ω

Length of the bar, l = 1.1 m

Magnetic field, B = 2 T

Current in the bar, I = 1.7 A

The expression for motional emf is given by,

ε = B x l x v

where v is the velocity of the conducting bar.

a) Applying Ohm's law,

I x R = Blv

Therefore, v = IR/Bl

v = 1.7 x 8.5/(2 x 1.1)

v = 6.6 m/s.

b) Power delivered to the resistor,

P = (Blv)²/R = (2 x 1.1 x 6.6)²/8.5

P = 24.8 W

c) Force exerted on the bar,

F(ext) = B²l²v/R = (2 x 1.1)²x 6.6/8.5

F(ext) = 3.75 N

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Answer:

620nm

Explanation:

According to the question,

As we know,

→ \(t = \frac{\lambda}{2n}\)

or,

→ \(\lambda = 2tn\)

By putting the values, we get

      \(= 2\times 233\times 10^{-9}\times 1.33\)

      \(= 620 \ nm\)

Thus the above response is correct.

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