A pure tone with a frequency f1 = 800 Hz is modulated by a frequency f2 = 160 Hz. The primary sidebands are______ Hz and ______Hz. The virtual pitch heard will be the related fundamental, _______Hz.

Answer:

A change of odor

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1. The impedance of a series RLC circuit can be calculated using the formula Z = √((R^2) + ((Xl - Xc)^2)), where R is the resistance, Xl is the inductive reactance and Xc is the capacitive reactance.

At a frequency of 600 MHz, the inductive reactance can be calculated using the formula Xl = 2πfL, where L is the inductance. Thus, Xl = 2π(600 x 10^6)(3.5 x 10^-3) = 1319.5 Ω. The capacitive reactance can be calculated using the formula Xc = 1/(2πfC), where C is the capacitance. Thus, Xc = 1/(2π(600 x 10^6)(4400 x 10^-12)) = 543.63 Ω. Therefore, Z = √((10,000^2) + ((1319.5 - 543.63)^2)) = 10,990.7 Ω.

2. The resonance frequency for a series RLC circuit can be calculated using the formula f = 1/(2π√(LC)), where L is the inductance and C is the capacitance. Thus, f = 1/(2π√(3.5 x 10^-3)(4400 x 10^-12)) = 615.5 MHz.

3. The resonance frequency does not depend on the resistance in a series RLC circuit because at resonance, the reactances of the inductor and capacitor cancel each other out and the circuit becomes purely resistive. Therefore, the resistance does not affect the resonance frequency.

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Answer:

E = h ν = h c / λ

E = (6.63E-34 J-s * 3.00E8 m/s) / 757.7E-9 m

E = 2.62E-19 J

Note 1 eV = 1.60E-19 J

ν = c / λ = 3.00E8 / 110.9E-9 = 2.71E15 / sec

How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

Substituting the given values, we get: E = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(757.7 x 10^-9 m)E = 2.61 x 10^-19 JTherefore, the energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. What is the frequency (in Hz) of light that has a wavelength of 110.9 nm  The frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. The frequency of light is given by the formula:f = c/λwhere f is the frequency, c is the speed of light, and λ is the wavelength of the light.

Substituting the given values, we get:f = (3.00 x 10^8 m/s)/(110.9 x 10^-9 m)f = 2.70 x 10^15 Hz Therefore, the frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

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Answer:

option a

Explanation:

a- All matter is composed of small particles.

Explanation:

The following are the basic assumptions of the Kinetic Molecular Theory: The volume occupied by the individual particles of a gas is negligible compared to the volume of the gas itself. ... Gas particles are in a constant state of random motion and move in straight lines until they collide with another body.

Answer:

A SCALE

Explanation:

Answer:

The magnetic polarity of a magnet can affect the current flowing in a loop of wire by inducing an electromotive force (EMF) in the loop. When a magnet with a changing magnetic field is moved near a loop of wire, the magnetic field induces a voltage in the wire, which in turn generates an electric current.

Object b will have had a greater change in its velocity than object a, Object a will have a lower velocity than object b.  

When object b is thrown straight down, it experiences acceleration due to gravity, which increases its velocity in the downward direction. Object a, on the other hand, is thrown straight up, experiences deceleration, and its velocity decreases over time.Since object a is thrown upward and experiences deceleration, its velocity decreases over time.

Object b is thrown downward and experiences acceleration due to gravity, so its velocity increases over time. Consequently, after 2 seconds, object a will have a lower velocity compared to object b. This is because the initial velocities and accelerations are equal in magnitude but opposite in direction for both objects.

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Answer:

1754.3 m

Explanation:

331*5.3=1754.3

The heat changes that occur in the various change of state processes are as follows:

A change of state is the change of a substance from one physical state to another physical state, for example, from liquid to gas.

Matter undergoes physical changes as its condition changes. The chemical composition or physical characteristics of matter are unaffected by these reversible modifications. Melting, freezing, sublimation, deposition, condensation, and evaporation are a few of the processes that can change a substance's state.

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Answer:

The field is the negative of the slope of the plot of the electric potential.

Explanation:

thanks for question

When a diffraction grating having a specified number of slits per unit length is illuminated by a beam of light, a pattern of bright spots or dark lines is produced on a screen placed perpendicular to the beam. Therefore, the wavelength of the light diffracted by the grating is 0.00072516 mm.

A pattern of this kind is called a diffraction pattern. A diffraction grating is a device that divides light into its component colors and produces diffraction patterns. It is used for analyzing light and determining the wavelengths of the different colors that make up the light.

The equation used to find the wavelength of light diffracted by a grating is

`d*sin(theta) = n*lambda`.

Here, d is the distance between two successive slits on the grating, theta is the angle of diffraction, n is the order of the diffraction, and lambda is the wavelength of the light. To determine the wavelength of the light in this case, we will use the given data and the above equation. The first-order diffraction angle is 34° and the diffraction grating has 750 slits/mm. Therefore, the distance between two successive slits on the grating is d = 1/750 mm = 0.001333 mm. The order of diffraction is 1.Using the above equation, we have`0.001333*sin(34) = 1*lambda`

Simplifying, we get `lambda = 0.00072516 mm`

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The time taken by the ball to reach the surface of the moon that drops from a height of 1.5 m from the moon is 1.36s.

Given that the acceleration of gravity on the surface of the moon is, \(a=g=1.62 ms^{-2}\). The distance of the ball from the surface is the height of the ball from the surface. So, \(h=d=1.5 m\).

Since the ball is dropped under gravity or free-fall motion from rest, then the initial velocity is zero (i.e.) \(v=0ms^{-1}\). Let t be the time taken by the ball to reach the surface of the moon.

By the equation of motion, the equation is given by \(h=v_{0} t+\frac{1}{2}gt^{2}\), where g is the gravity, t is the time taken by an object, h is the distance of the object, and \(v_{0}\) is the initial velocity of an object from the rest.

Substitute the values of h, g, and \(v_{0}\) in the above equation, and we get

\(1.5=(0)t+\frac{1}{2}(1.62)t^{2}\)

\(1.5=0.81t^{2}\)

\(t^{2} =\frac{1.5}{0.81}\)

\(t^2=1.852\)

\(t=\pm1.36s\)

The time taken cannot be negative.

Therefore, The time taken by the ball to reach the surface of the moon is 1.36s.

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Answer:

Watershed should be your answer!

The term personality traits has to do with the essentials of a person. One of the five big  personality trait that affects people negatively if they have to much of it is neuroticism.

The term personality traits refers to those traits that characterize an individual. They have the capacity to affect a person positively or negatively.

One of the five big  personality trait that affects people negatively if they have to much of it is neuroticism.

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Answer:

The penguins are gliding foward without stopping because there is no external force changing their state.

Explanation:

Newtons first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

From a collection of six 2.3 kΩ the smallest combined Resistance possible is 383.6 Ω.

To find the smallest resistance that can be made by combining six 2.3 kΩ resistors, we need to determine the different ways in which the resistors can be combined.

Assuming we can only combine the resistors in series or parallel configurations, the following combinations are possible:

1. All resistors in series:

Total resistance = 2.3 kΩ + 2.3 kΩ + 2.3 kΩ + 2.3 kΩ + 2.3 kΩ + 2.3 kΩ

= 13.8 kΩ

2. All resistors in parallel:

Total resistance = 1 / (1/2.3 kΩ + 1/2.3 kΩ + 1/2.3 kΩ + 1/2.3 kΩ + 1/2.3 kΩ + 1/2.3 kΩ)

≈ 383.6 Ω

Therefore, the smallest resistance that can be made by combining six 2.3 kΩ resistors is approximately 383.6 Ω.

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Given,

The velocity of the spaceship in as observed by an observer at the earth, v=0.75c

The time interval as observed by the observer on the earth, t₁=2.5 s

The time elapsed in the ship's frame of reference is given by,

On substituting the known values,

Thus the time elapsed for an observer in the spaceship is 3.79 s

Answer:

Joules

Explanation:

The unit for Energy is Joules, which is equal to kg m²/s².

The gravitational potential energy is calculated as:

Where m is mass (kg), g is gravity (m/s²) and h is the height (m). So, the unit of the potential energy is:

Therefore, the answer is joules.

Answer:

The number of moles of air that escape is approximately 0.027 moles

Explanation:

The room temperature, T₁ = 20 °C = 298.15 K

Atmospheric pressure, P₁ = 1.0 atm

The volume of the container, V₁ = 3.5 L

The final temperature of the air in the container after heating on the Bunsen burner, T₂ = 95 °C = 368.15 K

The container opened finally

The ideal gas equation is P·V = n·R·T

∴ n = P·V/(R·T)

Where;

R = The universal gas constant = 0.08205 L·atm/(mol·K)

Therefore, we get;

n₁ = 1.0 × 3.5/(0.08205 × 298.15) ≈ 0.143

The number of moles, n₁ ≈ 0.143 moles

When the gas is heated to 95 °C, the number of moles becomes

n₂ =  P₂·V₂/(R·T₂)

P₂ = 1.0 atm atmospheric pressure, V₂ = 3.5 L, the volume of the container, T₂ =

∴ n₂ = 1.0 × 3.5/(0.08205 × 368.15) ≈ 0.116

The number of moles of air remaining in the container, n₂ ≈ 0.116 moles

The number of moles of air that escape, n = n₁ - n₂

∴ n = 0.143 - 0.116 = 0.027

The number of moles of air that escape, n ≈ 0.027 moles

The terminal speed of a raindrop is proportional to the square of the radius.

If the radius is doubled, the terminal speed will quadruple.

The terminal speed of a raindrop is the speed at which the drag force from air resistance balances the force of gravity. The drag force is given by F = pACv^2/2, where p is the density of air, A is the cross-sectional area, C is the drag coefficient, and v is the speed.

The cross-sectional area of a spherical raindrop is A = πr^2, where r is the radius of the raindrop.

The force of gravity is given by F = mg, where m is the mass of the raindrop and g is the acceleration due to gravity.

For a raindrop to reach its terminal speed, the drag force must equal the force of gravity. This means that pACv^2/2 = mg.

Solving for v, we get v = (2mg)/(pCπr^2).

The terminal speed is proportional to the square of the radius. This means that if the radius is doubled, the terminal speed will quadruple.

v = (2mg)/(pCπr^2)

If r = 2r, then v = (2mg)/(pCπ(2r)^2) = 4 * (2mg)/(pCπr^2) = 4v

Therefore, the terminal speed will quadruple.

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The resultant velocity of the aircraft is 3015 Km/hr while the direction is 5.7 degrees North of east

The resultant  vector is that vector that has the same effect is magnitude and direction as the two vectors acting together. Recall that velocity is a vector quantity. This implies that the magnitude and the direction of the velocity is very important.

The resultant velocity would now be obtained by considering the directions of the two velocities hence we have to work geometrically and not algebraically. We have to know that the plane is flying east at 3000 km/h. If the plane encounters a cross-wind of 300 km/h that is directed to the north

Thus the resultant velocity is;

R = √(3000)^2 + (300)^2

R = √9 * 10^6 + 9 * 10^4

R = 3015 Km/hr

The direction of this resultant velocity is;

Tan-1 (300/3000)

= 5.7 degrees North of east

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Answer:

-28990N

Explanation:

F = mass * acceleration = 2899kg * 10m/s^2 = -28990N (because it is a normal force applying pressure upward).

Answer:

B. Winter

Explanation:

The critical angle of the transparent material is 35.3 degrees.

The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:

sin(critical angle) = sin(90 degrees) / sin(angle of refraction)

sin(critical angle) = 1 / sin(32 degrees)

sin(critical angle) = 0.574

critical angle = arcsin(0.574)

critical angle = 35.3 degrees

Therefore, the critical angle of the transparent material is 35.3 degrees.

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Answer:

The answer is high

Explanation:

I just took the test :))

Higher frequency and higher pitch are produced by sounds with shorter wavelengths. So, long waves sound low and short waves sound high.

Physical characteristics of waves, such as transmission, reflection, polarization, diffraction, and refraction, are examples of wave attributes.

Waves are described mathematically using terms like wavelength, frequency, and amplitude.

Sound and light are two examples of common waves we encounter. Whether you're discussing waves or vibrations.

All of them may be classified according to the following four factors: amplitude, wavelength, frequency, and speed.

According to the graph, pitch perception is influenced by tone strength; below 1000 Hz, pitch tends to decrease with increasing loudness, and beyond 1000 Hz, pitch tends to increase.

Therefore, high pitch that is heard when waves are closely spaced together.

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The wall of the bulb of a thermometer is made thin beause allow the heat from sample being measured to reach the liquid quickly for fast response and quick reading (improves the quickness of response by the thermometer). ... — has a vacuum above the liquid column so there is no resistance to the expanding liquid.

To design separate oscillators of 97 kHz and 79 MHz using the NE555 timer and a crystal oscillator.

Follow the steps below:

Designing an oscillator with the NE555 timer for a frequency of 97 kHz:

1. Connect pins 1 (Ground) and 8 (Vcc) of the NE555 to the appropriate power supply.

2. Connect pin 4 (Reset) to Vcc to disable the reset function.

3. Connect pin 5 (Control Voltage) to Ground.

4. Connect a resistor (R1) and a capacitor (C1) in series between pins 6 (Threshold) and 7 (Discharge). Choose values for R1 and C1 to set the desired time constant.

5. Connect pin 2 (Trigger) to the junction of R1 and C1.

6. Connect pin 3 (Output) to an appropriate load or circuit.

7. Provide necessary decoupling capacitors and stabilize the power supply.

8. Adjust the values of R1 and C1 to achieve the desired frequency of 97 kHz.

Designing an oscillator with a crystal oscillator for a frequency of 79 MHz:

1. Choose a crystal oscillator with a resonant frequency of 79 MHz.

2. Connect the crystal oscillator component to the appropriate pins of a suitable oscillator circuit or microcontroller.

3. Provide necessary decoupling capacitors and stabilize the power supply.

4. Configure the oscillator circuit or microcontroller to use the crystal oscillator component as the clock source.

5. Program or adjust the oscillator circuit or microcontroller to generate an output signal with a frequency of 79 MHz.

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