A racing car has a uniform acceleration of 6 m/s2. In 10s it will cover:

Answer:

A solar flare as it may harm satellites and aircrafts flying near poles

Explanation:

Since solar flare is electro magnetic waves going to Earth the waves will mostly get absorbed by the north and south poles resulting in the aurora borealis, but if the solar flare is strong enough it may stop communications and engines in satellites and aircrafts and in result harming them

Answer:

A solar flare as it may harm satellites and aircrafts flying near poles

Explanation:

Answer:

1620000J

Explanation:

Given parameters:

Resistance  = 24ohm

Current  = 5A

Time  = 45min

Unknown:

Work done = ?

Solution:

Electrical work done is given as the product of power with time;

  Electrical work done  = power x time

     Power  = I²R

 Electrical work done  = I²R x time

Convert the given time to seconds;

          1min  = 60s

          45 min  = 45 x 60  = 2700s

Now,

  Work done  = 5² x 24 x 2700 = 1620000J

Hi there!

On an incline, the acceleration due to gravity is: (g = 9.81 m/s²)

a = gsinФ ≈ 1.196 m/s²

We can use the following kinematic equation to solve:

vf² = vi² + 2ad

Since the car will start to roll back when v = 0 m/s, we can write that vf = 0.

0 = vi² + 2ad

Plug in values:

0 = 31² + 2(-1.196)(d)

Rearrange for d:

31²/(2.392) = d

d = 401.756 m

The car will coast for 7885.49 meters before starting to roll back down.

The car is subject to two forces: the force of gravity, which is pulling it down the hill, and the force of friction, which is trying to slow it down. The force of friction is equal to the coefficient of friction between the tires and the road multiplied by the normal force, which is equal to the weight of the car.

The car will stop coasting when the force of gravity is equal to the force of friction. We can set up an equation to find the distance the car will coast before stopping:

d = (\(v^{2}\)) / (2 * μ * g * sin(θ))

where:

d is the distance the car will coast before stopping

v is the initial speed of the car

μ is the coefficient of friction between the tires and the road

g is the acceleration due to gravity

θ is the angle of the slope

Plugging in the values from the problem, we get:

d = \((31 m/s)^2\) / (2 * 0.01 * 9.8 m/\(s^{2}\) * sin(7.0°))

d = 7885.49 meters

Therefore, the car will coast for 7885.49 meters before starting to roll back down.

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Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)

The magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.

So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.

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Answer:

sorry but I don't know what exactly I'm supposed to calculate.you never actually stated it

An example of energy transformation of chemical to thermal to light to sound is Crackling fireplace.

Energy transformation, which we also know as energy conversion, is described as the process of changing energy from one form to another. Energy is a quantity that provides the capacity to perform work or moving, or provides heat.

A Crackling fireplace starts the process of energy transformation from being a chemical to thermal \via heat and then makes a sound.

When an explosive goes off, chemical energy that was stored in it is changed and transferred into sound energy, kinetic energy, and thermal energy.

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Example of energy transformation of chemical to thermal to light to sound is a Crackling fireplace.

Energy transformation which is also know as energy conversion is described as the changing of energy from one form to another. Energy is a quantity that provides the capacity to perform work or moving, or provides heat.

A Crackling fireplace starts the process of energy transformation from being a chemical to thermal through heat and then makes the crackling sound.

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Answer:

5 units to the left

Explanation:

I had the same question :)

Answer:

ultraviolet light

plz mark me as brainliest.

Answer:

Ultra violet

Explanation:

when heated, the molecules of the liquid in the thermometer move faster, causing them to get a little further apart. this results in movement up the thermometer. when cooled, the molecules of the liquid in the thermometer move slower, causing them to get a little closer together.

Answer:

B. They do not provide explanations for why they are true.

C. They are considered to be proven facts.

Explanation:

edge 2021

The statements describe scientific laws but not theories or hypotheses are they do not provide explanations for why they are true and they are considered to be proven facts.

The law given by the experimenters or scientists after years of observations and experiments based on the scientific reasons are called scientific laws.

The laws are not the proven facts. They even don't explain why the scientific laws are true.

Thus, the correct option is B and C.

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Answer: 30 Years Old

Explanation: The constitution has around three qualifications for service in the U.S. Senate, Your age must be at least 30 years.

Answer: a

Explanation:

Answer: pretty far actually

Explanation:

Answer:

3feet

Explanation:

Answer:

Speed of a child on the rim is 4.25 m/s.

Explanation:

Given;

diameter of the merry-go-round, d = 5.0 m

period of the motion, t = 3.7 s

one complete rotation of the merry-go-round = πd

one complete rotation of the merry-go-round = π(5) = 15.71 m

Speed is given as distance / time

speed of a child on the rim = 15.71 / 3.7

speed of a child on the rim = 4.25 m/s

Therefore, speed of a child on the rim is 4.25 m/s.

Jake's speed relative to the ground is 14 m/s. Here option C is the correct answer.

Relative velocity is calculated using the formula: relative velocity = velocity of object 1 - velocity of object 2

In this case, Jake's velocity relative to the ground is 4 m/s (his jogging speed) - (-10 m/s) (the velocity of the flatcar).

Relative velocity = 4 m/s + 10 m/s = 14 m/s.

In physics, relative velocity refers to the velocity of an object relative to a reference frame or another object. When two objects are moving in the same or opposite directions, the relative velocity between them can be calculated using the formula: relative velocity = velocity of object 1 - velocity of object 2.

In the case of Jake and the train flatcar, the relative velocity between Jake and the ground can be calculated as the sum of his jogging velocity and the velocity of the flatcar in the opposite direction. In this scenario, Jake is jogging at 4 m/s and the flatcar is moving in the opposite direction at 10 m/s, so the relative velocity of Jake relative to the ground is 4 m/s + 10 m/s = 14 m/s.

Complete question:

Jogging Jake runs at 4 m/s along a train flatcar that moves at 10 m/s in the opposite direction. Jake's speed relative to the ground is______Choose matching term

A - 5 m/s

B - 11 m/s

C - 14 m/s

D - 16 m/s

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Given :

A pinball machine launches a .045 kg ball at a speed of 9.2 m/s.

To Find :

The potential energy of the spring just before it launched the pinball.

Solution :

We know, their is no external force applied on system.

It means that kinetic energy will remains constant.

Initial Energy = Final Energy

\(K.E_i + P.E_i = K.E_f + P.E_f\\\\0 + P.E_i= \dfrac{mv^2}{2}+ 0\\\\P.E_i = \dfrac{0.045 \times 9.2^2}{2}\ J\\\\P.E_i = 1.9044\ J\)

Therefore, the potential energy of the spring just before it launched the pinball os 1.9044 J.

The angle measured counterclockwise from the positive x-axis is θ = 50.4°

Here we know that the vector is:

V = < -177 cm, -214 cm>

To get the correspondent angle for this vector, we can think that this is the hypotenuse of a right triangle, such that the y-component and x-component are the cathetus.

Then, to get the angle (measured counterclockwise from the positive x-axis) is given by:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Tan(θ) = (-214cm)/(-177 cm)

Using the inverse tangent function we get:

Atan(Tan(θ)) = Atan((-214cm)/(-177 cm))

θ = 50.4°

So the angle is 50.4°

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The part of a road vehicle which must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency is the tyre.

This is referred to as a force that resists the motion of one object against another when they roll or slide against each other.

When dealing with braking, the main factor is to have sufficient friction between the road surface and tyre to bring the vehicle to a standstill. If the tyres are wornout there won't be enough friction to make the vehicle stop during emergencies which is therefore the reason why it was chosen as the correct choice.

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The amount of load lifted by the pulley when the efficiency is 60% and effort is 50 N is determined as 30 N.

The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;

E = L / E   x  100%

where;

The amount of load lifted by the pulley is calculated as;

60 = L / 50   x 100%

60 = 100L / 50

100L = 50 x 60

100 L = 3000

L = 3000 / 100

L = 30 N

Thus, the amount of load lifted by the pulley is 30 N.

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Answer:

The minimum force, F, required for the block to just start to move is equal to the force of static friction, f s:

f s = (µ)s x N

where N is the normal force (the force perpendicular to the surface) = m x g = 2.0 kg x 9.8 m/s^2 = 19.6 N

f s = (µ)s x N = 0.50 x 19.6 N = 9.8 N

The force, F, required for the block to continue to move at a constant velocity is equal to the force of kinetic friction, f k:

f k = (µ)k x N = 0.30 x 19.6 N = 5.88 N

If a force is applied greater than the force required for the block to continue to move at a constant velocity, the block will accelerate. If the applied force is greater than the minimum force required for the block to just start to move, the block will begin moving.

The combined speed of the two cars when they stick together is obtained as 1.5 m/s.

In physics, momentum is a measure of an object's motion, and it is defined as the product of an object's mass and velocity. Mathematically, momentum (p) can be expressed as:

p = m * v

where m is the mass of the object and v is its velocity.

Momentum is a vector quantity, which means it has both magnitude and direction. The direction of the momentum vector is the same as the direction of the object's velocity.

We know that;

Momentum before Collison = Momentum after collsion

(9000 * 3) + 0 = (9000 + 9000)v

v = 27000/18000

v = 1.5 m/s

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Answer:

no se pregúntale a otro gracias cuidate :)

For the pair of fuzzy dice hanging by a string from the rearview mirror, while accelerating from a stop-light to 28 m/s in 6.0 s, the string makes an angle of 25.5 degrees with the vertical.

An angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle.

Parameters given include:

velocity: 28,/s time= 6.0 seconds

a = v/t = 28m/s / 6.0s = 4.667 m/s²

Taking into account the forces acting on the dice...there is a force of gravity acting straight down with a magnitude of mg.

so we have that

Angle = tan-1(a/g)

Angle = tan-1(4.667 / 9.8) =  25.5 degrees.

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Answer:

4.6 Joules

Explanation:

K=1/2*MV^2

1/2 * 2.1kg * 2.1^2m/s

==4.6305  Joules

simplified to 4.6 Joules

Answer:

it will stay still. unless its in space.

Explanation:

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

3. The incident ray passing through the center of the lens continues undeviated.

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

When a ray of light traveling parallel to the principal axis (the horizontal line passing through the center of the lens) enters a converging lens, it refracts and bends toward the principal axis. After refraction, the ray passes through the focal point on the opposite side of the lens. This rule is essential in understanding the behavior of light rays in converging lenses.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

When a ray of light passes through the focal point before entering the lens, it refracts and emerges parallel to the principal axis. This rule implies that light rays that enter the lens at different angles converge and meet at the focal point on the opposite side.

3. The incident ray passing through the center of the lens continues undeviated.

When a ray of light passes through the center of a lens, it continues in a straight line without deviating from its path. This rule is derived from the fact that the refractive index of the lens material is the same throughout, resulting in no change in the direction of light passing through the center of the lens.

These rules of refraction for converging lenses help in understanding how light rays interact with the lens and how the lens focuses incoming light. By applying these rules, one can predict the behavior of light rays and determine the location and characteristics of images formed by converging lenses.

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