A rectangular block of wood has dimensions 240mm×20.5cm×0.040m. calculate its volume in cm³.

Answer:

m = 6.082 x 10⁻¹⁶ kg = 6.082 x 10⁻¹⁰ mg

Explanation:

First, we find the the surface area of the cell wall. Since, the cell is spherical in shape. Therefore, surface area of cell wall will be:

A = 4πr²

where,

A = Surface Area = ?

r = Radius of Cell = Diameter/2 = 2.2 μm/2 = 1.1 μm = 1.1 x 10⁻⁶ m

Therefore,

A = 4π(1.1 x 10⁻⁶ m)²

A = 15.2 x 10⁻¹² m²

Now, we find the volume of the cell wall. For that purpose, we use formula:

V = At

where,

V = Volume of the Cell Wall = ?

t = Thickness of Wall = 40 nm = 4 x 10⁻⁸ m

Therefore,

V = (15.2 x 10⁻¹² m²)(4 x 10⁻⁸ m)

V = 60.82 x 10⁻²⁰ m³

Now, to find mass of cell wall, we use formula:

ρ = m/V

m = ρV

where,

ρ = density of water = 1000 kg/m³

m = Mass of Wall = ?

Therefore,

m = (1000 kg/m³)(60.82 x 10⁻²⁰ m³)

m = 6.082 x 10⁻¹⁶ kg = 6.082 x 10⁻¹⁰ mg

The mass of the cell wall in mg is 6.082 × 10⁻¹⁰ mg

Since we assume the cell to be spherical and the wall to be a thin spherical shell, the volume of the cell wall V = At where

So, V = 4πR²t

Substituting the values of the variables into the equation, we have

V = 4πR²t

V = 4π(1.1 × 10⁻⁶ m)² × 40 × 10⁻⁹ m.

V = 4π(1.21 × 10⁻¹² m²) × 40 × 10⁻⁹ m.

V = 193.6π × 10⁻²¹ m³

V = 608.21 × 10⁻²¹ m³

V = 6.0821 × 10⁻¹⁹ m³

V ≅ 6.082 × 10⁻¹⁹ m³

We know that density of cell wall, ρ = m/v where m = mass of cell wall and V = volume of cell wall.

Making m subject of the formula, we have

m = ρV

Since we assume the density of the cell wall to be equal to that of pure water, ρ = 1000 kg/m³

So, m = ρV

m = 1000 kg/m³ × 6.082 × 10⁻¹⁹ m³

m = 6.082 × 10⁻¹⁶ kg

Converting to mg, we have

m = 6.082 × 10⁻¹⁶ kg × 10⁶ mg/kg

m = 6.082 × 10⁻¹⁰ mg

So, the mass of the cell wall in mg is 6.082 × 10⁻¹⁰ mg

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The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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The distance between the glass to have the given heat loss is 2.54 m.

The given parameters:

The area of the glass window is calculated as follows;

\(A = 0.6 \times 0.9\\\\A = 0.54 \ m^2\)

The distance between the glass is calculated as follows;

\(Q = \frac{KA \Delta T}{\Delta x} \\\\\Delta x = \frac{kA \Delta T}{Q} \\\\\Delta x = \frac{0.8 \times 0.54 \times 24 }{4.09} \\\\\Delta x = 2.54 \ m\)

Thus, the distance between the glass to have the given heat loss is 2.54 m.

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Dimensions are measured using a Vernier Caliper  (option A)

A device renowned for its accuracy in measuring the size of objects, the Vernier caliper functions with two jaws to hold an object steady as its scale offers readings. It can assess both external and internal measurements as well as depth with precision.

The Vernier caliper is made up of two main parts: the main scale and the vernier scale. The main scale is a graduated scale that is used to read the measurement in millimeters. The vernier scale is a smaller scale that is used to read the measurement in fractions of a millimeter.

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The time required for half of the oil droplets to coalesce is 34.65 minutes.b) Calculation to find how long it takes for practically all of the oil droplets to coalesce:To find the time it would take for practically all of the oil droplets to coalesce, we need to use the following formula and solve for time when n is equal to 0.0 = e^(-0.02t)-infinity = -0.02tNo oil droplets remain after an infinite amount of time. Therefore, it takes an infinite amount of time for all the oil droplets to coalesce.Answer: It takes an infinite amount of time for all the oil droplets to coalesce.

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The resistance of the wire bent through 180 degrees at its mid point and the two halves are twisted together 0.25R.

The resistance of a wire directly proportional to the length of the wire and inversely proportional to the area of the wires.

R = ρL/A

where;

When the piece of wire is bent through 180 degrees at its mid point and the two halves are twisted together. So, the length is halved (l/2) and the area of cross section is doubled (2A).

\(R =\rho \frac{\frac{1}{2} l}{2A} \\\\R = \frac{1}{4} (\frac{\rho L}{A} )\\\\R_{new} = \frac{R}{4}\)

Thus, the resistance of the wire bent through 180 degrees at its mid point and the two halves are twisted together 0.25R.

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Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

According to the question the magnetic field is -3.925 x 10⁻⁶ T.

A magnetic field is an invisible force field created by a magnet or a moving electric charge. This field is made up of magnetic lines of force that move outward from the magnet or electric charge and can interact with other magnets and electric charges. The magnitude and direction of the force can be determined by measuring the strength and direction of the magnetic field.

The magnetic field can be determined using the equation:
F = qv x B,
where F is the force, q is the particle's charge, v is its velocity, and B is the magnetic field.
We can rearrange this equation to solve for B:
B = F / (qv)
In our case, the charge of the particle is 80 μC, its velocity is 20iˆ km/s, and the force is given by F = ma = (10g)(-9.8jˆ m/s²) = -98 mN.
Substituting these values into the equation, we find that the magnetic field is:
B = -98 mN / (80 μC x (20iˆ km/s)) = -3.925 x 10⁻⁶ T.

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Oldest: Red Giant in globular cluster M13 AND red main-sequence star in globular cluster M13

Middle: the sun

Youngest: Hot, blue main-sequence star in disk

What is globular cluster?

Globular clusters, which include tens of thousands to millions of stars, are stable, firmly bound clusters. They are connected to all different kinds of galaxies. Globular clusters are strongly gravitationally bound and often larger than open clusters.

As a result, the Milky Way's globular clusters (which house extremely old stars) show a spherical component, whilst the open clusters, other young stars, and star-forming areas show a disk-shaped component.

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Here is a draft of the worksheet for the three main plate boundary types:

Plate Boundary (Movement)      Convergent (Colliding)

Diagram

        ||

        ||

        ||

Lithosphere (Created or Destroyed)  

       Created

Geologic Process      Mountain building

Real World Example

        Himalayas (Along India-Eurasia plate boundary in Asia)

References        

APA reference for research      

Plate Boundary (Movement)        Divergent (Separating)

Diagram

          |||||

Lithosphere (Created or Destroyed)      

        Destroyed  

Geologic Process        

         Volcanic eruptions and rift valleys

Real World Example  

        Mid-Atlantic Ridge (Between North America and Europe plates)

References        

         APA reference          

Plate Boundary (Movement)     Transform (Sliding)

Diagram

          |||||||||

Lithosphere (Created or Destroyed)  

       Neither          

Geologic Process  

       Earthquakes

Real World Example        

         San Andreas Fault (California, USA along Pacific-North America plates)

References

          APA reference

Answer:

The first one!

Explanation:

:D

Answer:

The value is   \(t =  14.129 \  minutes\)    

Explanation:

From the question we are told that

  The distance of planet Tatoone is  \(d =  1.7 \ AU  =  1.7 *1.496* 10^{11}=2.543*10^{11} \ m\)

   The  speed of light is  \(c =  3.0*10^{8} \  m/  s\)

Generally the time taken is mathematically represented as

     \(t =  \frac{d}{c}\)

=> \(t =  \frac{2.543*10^{11}}{3.0*10^{8} }\)

=>    \(t =  847.7 \  s\)

Now converting to minutes

       \(t =  \frac{847.7}{60}\)

   =>     \(t =  14.129 \  minutes\)    

Answer:

Explanation:

Given;

output power of the incandescent lightbulb , P = 120 W

input voltage, V = 200 V

The resistance of the filament is calculated as;

\(P = \frac{V^2}{R}\)

Where;

R is the resistance of the filament

\(R = \frac{V^2}{P} \\\\R = \frac{200^2}{120} \\\\R = 333.33 \ ohms\)

The rms current is given as;

\(P = I_{rms} V_{rms}\\\\I_{rms} = \frac{P}{V_{rms}} \\\\I_{rms} =\frac{120}{200}\\\\ I_{rms} = 0.6 \ A\)

Answer:

Because of melting and freezing a higher heat will make something a plasma or liquid by melting it. by freezing you can make a liquid or gas solid.

Explanation:

Answer:

Gravitational potential energy is the greatest

Explanation

It is the highest point of a roller coaster.

Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.

Explanation: I think I'm very stupid

Answer:As the temperature increases, the helium in the ballon expands.

Explanation:

I took the quiz already

The answer is C) As the temperature increases, the helium in the balloons expands.

Have a blessed day!

Answer: You take the biggest number and subtract it from the smallest number.

Explanation: Hope this helps.

Answer:

Subtract the minimum data value from the maximum data value to find the data range.

Explanation:

\(Hope\) \(this\) \(helps!\)

I believe the answer would be protentional because they have the potential energy in them to lift the hammer.

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

The true length of the field is 70.538 m.

The length of the field is calculated by applying the following formula;

ΔL = L₀αΔθ

where;

The change in the length of the field is calculated as;

ΔL = 70.5 x ( 1.8 x 10⁻⁵ ) x ( 50 - 20 )

ΔL = 0.038 m

The true length of the field = 70.5 m + 0.038 m = 70.538 m

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Answer:

E = h f - h f0    

E is the energy of the emitted photon - h f is the energy in an incident photon of frequency f

h f0 is the energy required to remove an electron from the metal being considered

If h f is not equal to or greater than h f0 then no photons will be emitted.

The star of a cross-country team is Ken Runfast. Ken recently ran for 12.4 minutes at an average speed of 5 m/s. After then, Ken's average speed was 6.1.

Distance is the overall movement of an item with consideration of direction. Regardless of an object's starting or ending position, distance can be defined as the amount of ground it has covered.

We can determine an object's actual size by learning how far away it is. The area an object occupies in the sky can be measured. The distance from it must then be determined in order to determine its true size. An thing appears smaller the further it is away.

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Answer:

concave

Explanation:

the middle of the concave lens is narrow and the edges are flattened.

CNT can act as antennas for radios and other electromagnetic gadgets.

They're additionally fairly solid, lightweight, and have first rate electric, thermal and mechanical residences. because of this, they maintain the capability for the development of many thrilling future materials. they may also keep the important thing to building the substances and structures of the destiny, including area elevators.

CNT can act as antennas for radios and other electromagnetic gadgets. Conductive CNTs are utilized in brushes for commercial electric powered automobiles. They replace traditional carbon black. The nanotubes enhance electric and thermal conductivity because they stretch thru the plastic matrix of the brush.

Moreover, exceptional houses of carbon nanomaterials, together with huge surface-to-extent ratio, excessive conductivity, and electron mobility at room temperature, have led to severe advances in electrochemical sensors.

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Explanation:

Dimensions help understand how physical amounts are related to their dependence on basic or fundamental volumes, i.e. how the body's dimensions rely on mass, time, length and temperature.

Understanding dimensions is of utmost importance as it helps us in studying the nature of physical quantities mathematically. The basic concept of dimensions is that we can add or subtract only those quantities which have same dimensions. Also, two physical quantities are equal if they have same dimensions.

Kepler’s laws are useful when the sun is located on a permanent spot and they can be considered purely descriptive.

Kepler’s laws are a set of scientific models to understand the motion (movement) of the planets around the sun.

These laws state that a planet's orbit can be considered as elliptical around the Sun and this motion rate is constant over time, thereby Kepler's laws are descriptive and do not explain planetary movement.

In conclusion, Kepler’s laws are useful when the sun is located on a permanent spot and they can be considered purely descriptive.

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Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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Answer:

17,190 years old

Explanation:

A p e x