Answer:
P₂ = 130.18 kPa
Explanation:
In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:
P₁/T₁ = P₂/T₂ (1)
From here, we can solve for the Pressure at 273 K:
P₂ = P₁ * T₂ / T₁ (2)
Now, all we need to do is replace the given data and solve for P₂:
P₂ = 340 * 273 / 713
P₂ = 130.18 kPaHope this helps
How many g are in 3 mol of Iron II Carbonate FeCO3
Answer:
348 g FeCO3
Explanation:Use your 3 mol's and find the atomic number of Iron II and CO3 which i think is 115.854 so you multiply it by the 3 and that should give you your grams in FeCO3.
The shutdown decision can be restated in terms of producer surplus by saying that a firm should produce in the short run as long as revenue exceeds producer surplus. producer surplus exceeds fixed cost. producer surplus exceeds variable cost. producer surplus is positive. profit and producer surplus are equal.
The shutdown decision can be restated in terms of producer surplus by saying that A, a firm should produce in the short run as long as revenue exceeds producer surplus
Producer surplus represents the difference between the revenue received by the firm and the minimum amount needed to cover variable costs. If the producer surplus is positive, it indicates that the firm is covering its variable costs and contributing towards fixed costs. In this situation, it is financially viable for the firm to continue production, even if it's not generating profit.
However, if the producer surplus becomes negative, the firm is unable to cover its variable costs, and a shutdown may be the optimal decision. It is important to note that the focus is on variable costs rather than fixed costs or profit, as fixed costs will still need to be paid regardless of production levels. So therefore the shutdown decision, in terms of producer surplus, the correct answer is A. a firm should continue production in the short run as long as the producer surplus exceeds variable costs.
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Suppose the body is projected from the ground at 24.5 m/s, 60* above the horizontal. Find the (a) time of flight, (b) range, and (c) maximum height.
helppppppp (ᗒᗣᗕ)՞
a. t = 4.33 s
b. R = 53.04 m
c. H = 22.97 m
Further explanationGiven
vo=initial velocity=24.5 m/s
Angle = θ = 60°
Required
(a) time of flight, (b) range, and (c) maximum height.
Solution
Parabolic motion
a. time to flight
t = (2vo sin θ) / g
t = (2 x 24.5 x sin 60) / 9.8
t = 4.33 s
b. range (horizontal range) :
R = (vo² sin2θ )/g
R =(24.5² sin 120)/9.8
R = 53.04 m
c. maximum height
H = (vo²sin²θ)/2g
H = (24.5²sin²60)/2.9.8
H = 22.97 m
based on your knowledge of elimination reactions, propose a detailed mechanism that explains the formation of 2,3-dimethylbutadiene.
The formation of 2,3-dimethylbutadiene (also known as isoprene) can be explained by an elimination reaction, specifically, the dehydrohalogenation of 2,3-dimethyl-2-chlorobutane. Here is a proposed mechanism for this reaction:
Step 1: Protonation of the chloroalkane
The 2,3-dimethyl-2-chlorobutane molecule reacts with an acid (such as sulfuric acid or hydrochloric acid) to form its corresponding carbocation. In this step, a proton from the acid adds to the chlorine atom, resulting in the formation of a carbocation intermediate.
Step 2: Formation of the double bond
The carbocation intermediate undergoes an elimination reaction, where a hydrogen atom adjacent to the carbocation is abstracted by a base (such as a chloride ion) to form a C=C double bond. This step involves the removal of a proton from one of the beta carbons (carbon atoms adjacent to the positively charged carbon) and the formation of a new pi bond.
Step 3: Deprotonation
In this step, a base (such as water or hydroxide ion) deprotonates the resulting alkene to form the final product, 2,3-dimethylbutadiene (isoprene).
Overall reaction:
2,3-dimethyl-2-chlorobutane → 2,3-dimethylbutadiene + HCl
The proposed mechanism involves the initial protonation of the chloroalkane, followed by the formation of a carbocation intermediate and the subsequent elimination of a proton to form the double bond. Finally, deprotonation occurs to generate the desired product, 2,3-dimethylbutadiene.
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PLEASE HELP!?Consumers must eat other organisms for energy. Which organisms are consumers in this food chain?
Answer:
Consumers must consume other organisms to get the food that they need and are known as Heterotrophs as they cannot make their own glucose. These consumers eat producers (plants). Herbivores are considered as first order consumers. These consumers eat consumers and producers (animals and plants).
Witch element is the number 14 on the periodic table
Answer:Silicon
Explanation:
Silicon - Element information, properties and uses | Periodic Table.
Royal Society of Chemistry › 14 › si...
Silicon - Element information, properties and uses | Periodic Table
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Styrene has the empirical formula CH with a molar mass of 104. 13 g/mol. Approximately how many hydrogen atoms are present in a 52 g sample of styrene?
The Styrene has the empirical formula CH with a molar mass of 104. 13 g/mol. The number of hydrogen atoms are present in a 52 g sample of the styrene is 4.63 × 10²² H atoms.
The Empirical formula of styrene CH
The molecular formula = n(empirical formula)
n = 8
The Molecular formula of styrene = C₈H₈
1 mol of styrene has the 8 moles of the C and the 8 moles of H and the 1 mol .
The molecular mass = 104.13 grams.
104.14 g (1 mol of C₈H₈) have the 8 moles of H
Moles of 52 g = (52 × 8) / 104.13
= 3.99 moles
1 mole of particles= 6.02×10²³ atoms
The number of hydrogen atoms= 3.99 mol . 6.02×10²³ atoms / 1 mol
= 4.63 × 10²² H atoms.
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Which types of radioactive decay is shown in all of the equations in the image? What are two indicators of the type of decay occurring?
There are two signs of alpha decay. The matrix 4/2He is used in all of the equations to represent the emission of an alpha particle, which is a helium nucleus made up of two protons and two neutrons.
What transpires in each of the three primary forms of radioactive decay?The nucleus loses two protons during alpha decay. The nucleus either acquires or loses a proton during beta decay. There is no change in the proton count during gamma decay.
The nuclear equation illustrates what radioactive decay.Alpha decay can be described by a nuclear equation. If the total numbers of protons and neutrons on both sides of the arrow are equal, the equation is balanced. Alpha decay is one of the four types of radioactive decay.
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5. Base your answer to the following question on the informationbelow and on your knowledge of chemistryA metal worker uses a cutting torch that operates by reactingacetylene gas, C2H2(g), with oxygen gas, O2(g), as shown inthe unbalanced equation below.CH,(g) + 0,(g) → CO2(g) + H2O(g) + heat
In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient.
The proper balancing for this question is:
2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O
Therefore the coefficients are:
2, 5, 4, 2
How many non-bonding electrons are on the central atom in the optimized Lewis structure of PO4 3- in which the formula charges are minimized?
In the optimized Lewis structure of PO4 3-, there are zero non-bonding electrons on the central atom.
First, let's look at the Lewis structure of PO4 3-. The central atom is phosphorus (P), which is bonded to four oxygen (O) atoms. Each oxygen atom is bonded to the central phosphorus atom with a single bond, and each oxygen atom also has three pairs of non-bonding electrons.
The Lewis structure of PO4 3- looks like this:
O
/
P - O - O
\
O
Each single bond in the structure represents two electrons, so there are a total of eight bonding electrons around the central phosphorus atom. Phosphorus has five valence electrons, so there are a total of thirteen valence electrons around the central atom.
To minimize the formula charges, we need to make sure that the central atom has a full octet of eight electrons. Since there are already eight bonding electrons around the central atom, there are no non-bonding electrons on the central atom.
Therefore, the answer to the question is zero non-bonding electrons on the central atom in the optimized Lewis structure of PO4 3- in which the formula charges are minimized.
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Give one example of erosion.
SCIENCE
Answer: a rock being in one place over a long time and eventually wearing away
Explanation:
:)
SOMEONE PLEASE HELP ME WITH THIS
Answer:
A:genes
Explanation:
the brain doesn’t carry genetic information
the heart pumps blood to other parts of the body
And chromosomes carry the genetic information
what component in the solar cell provides electrons to replace the electrons released by the dye?
The component in the solar cell system which provides electrons to replace the electrons released by the dye simply is the graphite layer.
How the graphite layer release electrons to replace the dye electronsThe graphite layer is one of the major parts oth the solar cell. It help in the provision of electrons by acting as a counter electrode within the electrolyte. In order, this layer is part responsible for replacing electrons produced by dyes.
In conclusion, we can now confirm from all said and done from above that the solar cell too has a way of producing electrons.
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In a concentration cell, what drives the movement of electrons from the anode to the cathode?.
In a concentration cell, the movement of electrons from the anode to the cathode is driven by the difference in concentration of the electrolyte solution between the two electrodes.
The electrode with the higher concentration of ions will have a higher tendency to lose electrons and become the anode, while the electrode with the lower concentration of ions will have a higher tendency to gain electrons and become the cathode. This movement of electrons creates an electric current that can be harnessed for various applications.
In a concentration cell, the movement of electrons from the anode to the cathode is driven by the difference in ion concentrations between the two half-cells. This concentration gradient leads to a potential difference, which provides the driving force for the electron flow.
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Identify an equation in pint form for the line perpendicular to y=1/4x-7 that passes through (-2,-6)
Answer:
Explanation:
An equation in point-slope form for the line perpendicular to y=1/4x-7 and passing through (-2,-6) is:
y - (-6) = -4(x - (-2))
This equation can also be written in slope-intercept form (y = mx + b) as:
y = -4x + 4
The slope of the line is -4 because it is perpendicular to the line y=1/4x-7 and the slope of that line is 1/4. The point (-2,-6) is the point where the line passes through, so the y-intercept is 4.
A 23. 6 g sample of Na3PO4 (molar mass 163. 94 g/mol) is dissolved in enough water to produce
750. ML of solution
Calculate the concentration of Nations in solution.
Write your answer using three significant figures.
The concentration of sodium ion, Na⁺ in the solution, given that 23.6 grams of Na₃PO₄ is dissolved in 750 mL of water is 0.576 M
How to determine the concentration of sodium ion, Na⁺ ?We'll begin by obtaining the molarity of the solution. This is illustrated below:
Mass of Na₃PO₄ = 23.6 gMolar mass of Na₃PO₄ = 163.94 g/molMole of Na₃PO₄ = 23.6 / 163.94 = 0.144 moleVolume = 750 mL = 750 / 1000 = 0.75 LMolarity = ?Molarity = mole / volume
Molarity = 0.144 / 0.75
Molarity = 0.192 M
Finally we shall determine the concentration of the sodium ion, Na⁺. Details below:
Na₃PO₄(aq) <=> 3Na⁺(aq) + PO₄³⁻(aq)
From the balanced equation above,
1 mole of Na₃PO₄ contains 3 moles of Na⁺
Therefore,
0.192 M Na₃PO₄ will contain = 0.192 × 3 = 0.576 M Na⁺
Thus, the concentration of Na⁺ is 0.576 M
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Given : 4.50 molte
How many moles of ammonia would you get if 4.50 moles of hydrogen gas
reacted
Sheet may help you to answer
his questio
Positive ions
the solution
Negative ions in the solution
Zinc ion (Zn2+)
Chloride ion (CH)
Iron(Ill) ion (Fe3+)
Hydroxide ion (OH)
Hydrogen ion (H+)
Nitrate ion (NO3-)
Copper(II) ion (Cuz)
Sulfate ion (SO42-)
(bi): Which ELEMENT IS MOST likely to be formed at the negative
electrode?
1 point
Your answer
Answer:
nitrate ion,, because it the most electronegative element,,it be formed at the anode
8.) a solution is made where 0.878 moles hcl is added to water that has a total volume of solution of 1855ml. what is the ph of the solution. hcl(aq) → h (aq) cl−(aq)
The pH of the HCl solution made by adding 0.878 moles HCl to water that has a total volume of a solution of 1855ml is 0.33.
To find the pH of the solution, follow these steps:
1. Calculate the concentration of HCl in the solution: Divide the moles of HCl by the volume of the solution in liters.
0.878 moles HCl / (1855 mL * 0.001 L/mL) = 0.473 M (molar concentration)
2. Since HCl is a strong acid, it will dissociate completely in water to form \(H^+\) ions and \(Cl^-\) ions:
HCl(aq) → \(H^+\)(aq) + \(Cl^-\)(aq)
3. The concentration of \(Cl^-\) ions in the solution will be equal to the concentration of HCl since it dissociates completely:
[ \(Cl^-\)] = 0.473 M
4. Use the formula for pH to find the pH of the solution:
pH = - \(log_{10}\) [ \(Cl^-\)]
pH = - \(log_{10}\) (0.473)
5. Calculate the pH:
pH ≈ 0.33
Therefore, the pH of the solution is approximately 0.33.
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Question 13 of 25
What is the safe way to test the smell of a chemical?
O A. Wafting the vapors toward your nose
O B. Pouring the chemicals into your nose
O C. Placing your nose in the container
O D. Breathing in deeply
what is the purpose of changing the eluting solvent from pentane to ether between the two fractions? please explain your answer, being sure to mention important intermolecular forces and how they relate to the compounds being eluted
We are aware that ether is a polar solvent and pentane is an apolar one. The less polar material moves quicker while more polar component travels slower.
By use of polar interactions, the sample that has to be separated will be adsorbed to the stationary phase comprised of alumina or silica gel. The eluting solvent will be used to elute these adsorbed molecules. Both polar and non-polar solvents may be used as these eluting agents. The interactions with the polar molecules that are adsorbed to the chromatographic column grow when the polarity of the eluting solvent is increased. Pentane is less polar than ether when compared. As a result, polar molecules are separated from and eluted from the stationary phase using ether. This is due to the fact that polar solvents may dissolve polar substances due to polar interactions.
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What is the density of a 700 kg object with a volume of 649 m'? (Density: D™)
0.927 kg/m
3.4543 kg/m
1.079 kg/m
4.543 kg/m
Answer: 1.079 kg/m3
Explanation:
The formula for the density is as follows as; Here, D is the density, m is the mass and V is the volume. Density is inversely proportional to the volume and it is directly proportional to the mass. It is given in the problem that density of an object is 700 kg having volume .
Consider the Solutions A-E:
A - 150 mM NaCl
B - 100 mM glucose + 100 mM NaCl
C - 100 mM Drug X (a small non-polar molecule) + 150 mM NaCl D - 150 mM MgCl2
E - 300 mM fructose
1. What would happen if red blood cells were placed in Solution A
2. What will the tonicity of solutions B, C, D and E be, compared to solution A and each other?
When red blood cells are placed in Solution A, which contains 150 mM NaCl, no significant changes occur because the concentration of sodium chloride is similar to that of the cells' internal environment. The isotonic nature of Solution A ensures that there is no net movement of water across the cell membrane, resulting in the cells maintaining their normal shape and size.
However, when comparing the tonicity of Solutions B, C, D, and E to Solution A and each other, differences arise. Tonicity refers to the osmotic pressure exerted by a solution on a cell and is influenced by the concentration of solutes within the solution. Solutions B and E both contain additional solutes along with NaCl.
Solution B, consisting of 100 mM glucose and 100 mM NaCl, has a higher tonicity compared to Solution A. Glucose cannot freely cross the cell membrane, creating an osmotic gradient that draws water into the red blood cells, causing them to swell.
Solution C contains 100 mM Drug X, a small non-polar molecule, along with 150 mM NaCl. Since Drug X is non-polar, it can freely cross the cell membrane. The presence of Drug X does not significantly affect the tonicity compared to Solution A, as it does not create an osmotic gradient.
In contrast, Solution D, which contains 150 mM MgCl2, has a higher tonicity than Solution A. MgCl2 dissociates into Mg2+ and Cl- ions, both of which cannot cross the cell membrane easily. The higher concentration of impermeable ions creates an osmotic gradient, leading to water loss from the red blood cells and causing them to shrink.
Lastly, Solution E consisting of 300 mM fructose has a higher tonicity compared to Solution A. Fructose cannot freely cross the cell membrane, resulting in an osmotic gradient that draws water into the red blood cells, causing them to swell.
In summary, placing red blood cells in Solution A does not produce significant changes in the cells. However, when comparing the tonicity of Solutions B, C, D, and E to Solution A and each other, variations in osmotic pressure occur due to the presence of different solutes.
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Hydrated sodium tetraborate is heated
to drive off the water. You find there are
0.01312 mol Na2B4O7 and 0.1311 mol
H2O in the sample. What is the formula
of the hydrate?
A. Na2B4O7 H₂O
B. Na2B4O7 2H₂O
C. Na2B4O7-10H₂O
D. Na2B4O7-13H₂O
Answer: C. Na2B4O7•10H2O
Explanation:
Hope this helps :)
The formula is tetrasodium borate-Na2B4O7.10H2O
Given- 0.0132 mol Na2B4O7 and 0.1311 mol H2O
Step 1Using the molar mass of the anhydrous Na2B4O7 and its mass percentage, we can calculate the molar mass of the hydrate (if we look at it as 100% of the mass) by stoichiometry.
Molar mass of Na = (22.990 g/mol)
Molar mass of B = (10.811 g/mol)
Molar mass of O = (15.999 g/mol)
Molar mass of Na2B4O7= 2⋅22.990 g/mol +4⋅10.811 g/mol +7⋅15.999 g/mol = 201.217 g/mol
201.217g/mol : 52.8%=x g/mol : 100%
x g/mol = 201.217 g/mol⋅100%÷52.8 %
x g/mol= 381.093 g/mol
Step 2In 381.093 g of hydrate, we have 201.217 g of anhydrous Na2B4O7 , the rest of the mass is water.
381.093g−201.217g= 179.876 g of water
Molar mass of H = 1.008 g/mol
Molar mass of O = 15.999 g/mol
Molar mass of H2O= 1.008 g/mol+ 15.999g/mol = 18.015 g/mol
179.876g ÷18.015 = 9.98= 10 moles of water per mole of hydrate.
The Law of Conservation of Mass states that
a.
matter cannot be created or destroyed.
b.
matter is destroyed through fire.
c.
matter is converted into energy.
d.
matter cannot move at the speed of light.
Answer:
The answer is A I think sorry if I'm wrong
How many moles of nickel are in
a 117 g Ni sample? The molar
mass of nickel is 58.69 g/mol.
A. 2.00 moles
B. 176 moles
C. 0.502 moles
D. 6,900 moles
Answer: A. 2.00 moles
Explanation:
To determine the number of moles of nickel in a 117 g Ni sample, we can divide the mass of the sample by the molar mass of nickel:
moles = mass ÷ molar mass
= 117 g ÷ 58.69 g/mol
= 2 moles
Therefore, there are approximately 2 moles of nickel in a 117 g Ni sample and the correct answer is A. 2.00 moles
It is important to note that the molar mass of a substance is defined as the mass of one mole of that substance. One mole of a substance is equal to \(6.022\) × \(10^{23}\) units of that substance, which is known as Avogadro's number. The molar mass of a substance is often used to convert between mass and number of moles, as shown in the calculation above.
how many nitrogen atoms should appear on the right side of this equation 2AgNO3+Cu=?
Answer:
One.
Explanation:
Both sides of the equation need 2 Silver atoms, 1 Nitrogen, 3 Oxygen and 1 Copper to be balanced which is the same as the side of reactants.
if 8 moles of water decompose into diatomic hydrogen and oxygen, how many moles of O2 are produced?
2H2O--->2H2+O2
4 moles of \(O_{2}\) are produced if 8 moles of water decompose into diatomic hydrogen and oxygen
In this chemical equation, 2 moles of water produce 1 mole of oxygen gas. Therefore, to determine how many moles of \(O_{2}\) are produced from 8 moles of water, we can use a proportion.
2 moles of \(H_{2}O\) = 1 mole of \(O_{2}\)
So, 8 moles of \(H_{2}O\) = x moles of \(O_{2}\)
We can cross-multiply to solve for x:
2 moles of \(H_{2}O\) * x moles of \(O_{2}\) = 8 moles of \(H_{2}O\) * 1 mole of \(O_{2}\)
2x = 8
x = 4
Therefore, 8 moles of water decomposing will produce 4 moles of oxygen gas.
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What force causes a ball to move
Answer: aerodynamic force
Explanation:
The time-varying aerodynamic force causes the ball to move erratically. This motion is the source of the "dancing" knuckleball that confuses both batters and catchers alike.
Based on the data provided, do the Super Snail Snacks work? Explain your answer
Answer: No
Explanation: The snacks did not work because the result of the snails either stayed the same, or decreased.