A rock is thrown vertically upward with a speed of 12.0 m/s from the roof of a building that is 70.0 m above the ground. Assume free fall. Part A In how many seconds after being thrown does the rock strike the ground? Express your answer in seconds. V ΑΣΦ + → Ů ?
What is the speed of the rock just before it strikes the ground? Express your answer in meters per second.

Answer:

Explanation:

The Law of Momentum Conservation for us has the equation

\([m_rv_r+m_gv_g]_b=[m_rv_r+m_gv_g]_a\) and filling in:

\([(.50)(5.0)+(.50)(0)]=[(.50)(2.0)+(.50)v_g]\) and

2.5 = 1.0 + .50v and

1.5 = .50v so

v = 3 m/s

The final speed of the green ball is 3m/s. This can be calculated by the law of conservation of momentum. Thus, the correct option is D.

The principle of the law of conservation of momentum states that if any two objects undergo collision, then the total momentum of the objects before and after the collision will be the same if there is no external force acting on the colliding objects.

The Law of Conservation of Momentum has the equation which is:

m₁ × u₁ + m₂ × u₂ = m₁ × v₁ + m₂ × v₂

where, m₁ = mass of object 1,

u₁ = initial velocity of object 1 before collision,

m₂ = mass of object 2,

v₁ = final velocity of object 1 after collision,

v₂ = final velocity of the object 2 after collision.

0.50 × 5 + 0.50 × 0 = 0.50 × 2 + 0.50 × v₂

2.5 + 0 = 1.0 + 0.50 × v₂

2.5 - 1.0 = 0.50 × v₂

1.5 = 0.50 × v₂

1.5/ 0.5 = v₂

v₂ = 3m/s

Therefore, the correct option is D.

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The circuit shown below contains resistors R1 and R2 connected in series. They are connected to an op-amp with an open-loop gain\(\(A\)\), an input impedance \(Z_{in}\), and an output impedance \(Z_{o}\).

The op-amp input terminals are also connected to the output through a capacitor C. We are to find the input-output differential equation relating \(v_{o}\) and \(v_{i}(t)\).input-output differential equationThe voltage at the non-inverting terminal of the op-amp is given by:\($$v_{+}=v_{o}$$\)Since the inverting terminal is grounded, the voltage at that terminal is zero.

Thus, the voltage difference across the input terminals is:

\($$v_{d}\)

=\(v_{+}-v_{-}\)

=\(v_{o}$$Using KCL at node \(v_{-}\\)), we can write the following equation:

\($$\frac{v_{-}}{R_{1}}+\frac{v_{-}}{R_{2}}+\frac{v_{-}-v_{o}}{Z_{in}}\)

\(=0$$Rearranging and solving for \(v_{-}\), we get:$$v_{-}\)

=\(\frac{R_{2}}{R_{1}+R_{2}}v_{o}$$\)Using the virtual short concept of the op-amp, we know that the voltage at the input terminals is equal.

Thus, we can write\(:$$v_{+}=v_{-}$$$$v_{o}\)

=\(\frac{R_{1}+R_{2}}{R_{2}}v_{+}$$\)Taking the derivative of both sides with respect to time, we get:

\($$\frac{d}{dt}v_{o}=\frac{R_{1}+R_{2}}{R_{2}}\frac{d}{dt}v_{+}$$\)Using the fact that \(v_{+}

=\(v_{o}\), we get:$$\frac{d}{dt}v_{o}\)

=\(\frac{R_{1}+R_{2}}{R_{2}}\frac{d}{dt}v_{o}$$\)Solving for the input-output differential equation, we get:

\($$\frac{d}{dt}v_{o}-\frac{R_{1}+R_{2}}{R_{2}}v_{o}=0$$\)Thus, the input-output differential equation relating \\((v_{o}\) and \(v_{i}(t)\) is given by:$$\boxed{\frac{d}{dt}v_{o}-\frac{R_{1}+R_{2}}{R_{2}}v_{o}=0}$$\).

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Speed is an example of measurement that considers velocity.

What is velocity?

Velocity is a vector measurement of the rate and direction of motion or the speed of an object in a given direction. It is the magnitude of the rate of change of an object’s position, and is usually expressed in meters per second (m/s). Velocity is defined as the rate of change of the position of a body with respect to time. An example of velocity is a car traveling at 30 miles per hour.

It is a measure of how quickly an object is moving across a given distance, usually measured in meters per second or kilometers per hour. This is because speed is a measure of how quickly an object is moving, which is related to its velocity. Speed is calculated by dividing the distance traveled by the time it takes to travel that distance, which includes the velocity of the object.

Therefore, Speed is an example of measurement that considers velocity.

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The lower atmosphere is primarily composed of nitrogen and oxygen (about 21%). Variable gases present in smaller amounts include carbon dioxide, water vapor, methane, ozone, and trace amounts of other gases.

The lower atmosphere, also known as the troposphere, is the layer closest to the Earth's surface. It is primarily composed of nitrogen, accounting for approximately 78% of the gases present, and oxygen, which makes up about 21%. These two gases are considered the main components of the lower atmosphere.

In addition to nitrogen and oxygen, there are variable gases present in smaller amounts. One example is carbon dioxide (CO2), which plays a crucial role in the Earth's climate system as a greenhouse gas. Another variable gas is water vapor (H2O), which can vary in concentration depending on the humidity of the air. Water vapor is an important component for the Earth's weather patterns and can influence temperature and precipitation.

Other variable gases include methane (CH4), which is another greenhouse gas with a significant impact on climate change; ozone (O3), which is found in the upper troposphere and stratosphere and plays a crucial role in absorbing ultraviolet radiation from the Sun; and trace amounts of other gases such as noble gases (argon, neon, helium, etc.) and pollutants like sulfur dioxide (SO2), nitrogen oxides (NOx), and volatile organic compounds (VOCs).

The properties of air pressure and temperature change with altitude in the troposphere. Air pressure refers to the force exerted by the weight of the air molecules above a given point. As altitude increases, the density of air decreases, leading to lower air pressure. Temperature, on the other hand, generally decreases with an increase in altitude in the troposphere.

The rate at which the temperature changes with altitude is called the lapse rate. On average, the lapse rate in the troposphere is about 6.5 degrees Celsius per kilometer (3.6 degrees Fahrenheit per 1,000 feet). This means that for every kilometer you ascend in the troposphere, the temperature decreases by approximately 6.5 degrees Celsius. However, it's important to note that the actual lapse rate can vary depending on various factors such as weather conditions, geography, and time of day.

Estimating changes in air pressure with altitude can be done using the barometric formula, which takes into account the decrease in air density as altitude increases. However, it's worth mentioning that air pressure can also be influenced by weather patterns, temperature variations, and local geography.

In summary, the lower atmosphere is primarily composed of nitrogen and oxygen, with variable gases such as carbon dioxide, water vapor, methane, ozone, and trace amounts of other gases. As altitude increases in the troposphere, air pressure decreases, while temperature generally decreases at a rate of approximately 6.5 degrees Celsius per kilometer.

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Answer:

I think it may be either A. or C.

Explanation:

A factor which has the most significant influence on a liquid's surface tension is: D. The strength of the electric forces between its molecules.

Surface tension is a property of liquid such as water, which makes its surface to resist an external force due to the cohesive nature of the liquid's molecules.

Hence, the surface tension of a liquid is highly dependent on the electric (cohesive) forces of attraction existing between its molecules.

Additionally, the surface tension of a liquid is an inward force which tends to minimize its surface area rather than maximizing its surface area.

In conclusion, the strength of the electric (cohesive) forces of attraction between a liquid's molecules has the most significant influence on a liquid's surface tension.

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The study of the static behavior of DC vortex plasma torches with a button-type cathode involves examining the characteristics and performance of the torch under steady-state conditions.

Here, "static behavior" refers to the torch's behavior when operating in a stable and continuous mode without significant changes over time.In this particular study (Part I), the focus is on the button-type cathode. The cathode is an essential component of the plasma torch and plays a crucial role in the initiation and maintenance of the plasma discharge.

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Answer:

So work require will be 3888×10×10³J

Explanation:

⇒Work done=Change in kinetic energy

⇒KE=1/2mv²

⇒Mass->15000kg

⇒Velocity->72km/h

⇒KE=1/2×15000×(72)²

⇒KE=1/2×15000×5184

⇒KE=7500×5184

⇒KE=3888×10×10³J

If you have charges that were made against you but were dropped by the person who made them but are still on record, you can still take steps to address the situation. It is important to note that having charges on your record can have negative effects on your life, such as hindering your ability to secure employment and housing.

To address this situation, you may need to seek legal advice or the assistance of a criminal defense attorney. They will be able to guide you through the process of getting the charges removed from your record, or having them expunged. This will involve filing a petition to the court, providing evidence that the charges were dropped, and demonstrating that you meet the eligibility criteria for expungement or record sealing

. The process may vary depending on your location and the type of charges you faced, so it is important to seek guidance from a legal professional.To summarize, if you have charges that were made against you but were dropped by the person who made them but are still on record, you can seek legal advice or the assistance of a criminal defense attorney to have the charges removed from your record through a petition to the court.

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The linear acceleration of the person's hand is given by:

a = (mg * r)/I.

The constant acceleration of a moving item travelling in a straight line is referred to as linear acceleration. It is described as the rate at which linear velocity changes in relation to time.

Since the cylinder is suspended in midair, the tension in the string equals the weight of the cylinder, which is given by:

T = mg

where m is the mass of the cylinder and g is the acceleration due to gravity.

The torque exerted by the tension on the cylinder is given by:

τ = Tr

where r is the radius of the cylinder.

Since the center of mass of the cylinder is not moving, the net torque on the cylinder must be zero. Therefore:

τ = Iα

where I is the moment of inertia of the cylinder and α is its angular acceleration.

Substituting the expressions for τ and T, we get:

Tr = Iα

Solving for α, we get:

α = Tr/I

The linear acceleration of the person's hand is equal to the product of the angular acceleration and the radius of the cylinder:

a = αr

Substituting the expressions for α and T, we get:

a = Tr/I * r = (mg * r)/I

Therefore, the linear acceleration of the person's hand is given by:

a = (mg * r)/I.

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Answer:

Speed and distance traveled

Explanation:

Answer:

Explanation:

An Ideal Machine is a machine which gives 100 percent efficieny that is entire input energy is converted into output energy.

however this is not possible as some energy is lost due to friction, imperfect components and all. Therefore no machine is Ideal machine.

Answer:

please find attached pdf

Explanation:

The acceleration of the rock half-way between two planets is 1.086 m/s².

The parameters provided;

3M radius of planet A.

R mass of planet A.

4M radius of planet B.

2R distance between the two planets,

r = 8R

Newton's universal gravitational law is used to calculate the gravitational force half-way (4R) between the two planets;

Fg = GmAmB/r²\

Fg = G(2M x 4M)/(4R)²

Fg = 12GM²/16R²

Fg = (12 x 6.67 x 10⁻¹¹ x (7.3 x 10²³)²) / 16(5.8 x 10⁶)

Fg = 7.925 x 10²³N

The magnitude of the rock's acceleration is calculated as follows using Newton's second law of motion:

F = ma

a = F/m

a = 7.925 x 10²³/7.3 x 10²³

a = 1.086m/s²

As a result, the rock's acceleration is 1.086 m/s².

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Yes, touching the metal ball of a charged electroscope with your finger will cause the electroscope to discharge. This can be explained by the process of grounding.

An electroscope is a device used to detect the presence of electric charge. It consists of a metal rod or stem with a metal ball or leaves at the top. When the electroscope is charged, either positively or negatively, the metal ball or leaves acquire the same charge.

When you touch the metal ball of the charged electroscope with your finger, which is a conductive material, you provide a path for the excess charge to flow through your body. This process is known as grounding or earthing.

As you touch the metal ball, electrons from your body can flow onto or from the electroscope, depending on the charge of the electroscope. If the electroscope is positively charged, electrons from your body will flow onto the electroscope, neutralizing the positive charge. Similarly, if the electroscope is negatively charged, electrons will flow from the electroscope to your body, neutralizing the negative charge.

By providing a conductive path, touching the electroscope with your finger allows for the redistribution of charge, ultimately resulting in the electroscope discharging. The metal ball of the electroscope becomes neutral, and any divergence of the leaves returns to their normal position.

This discharge occurs because electrons, which are negatively charged particles, move in response to the potential difference between your body and the electroscope. The excess charge on the electroscope seeks to balance itself with the charge in your body, effectively neutralizing the electroscope.

Therefore, by touching the metal ball of a charged electroscope with your finger, you provide a pathway for the charge to flow, leading to the discharge of the electroscope.

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Answer:

25.021 sec

Explanation:

v=d/t

-2.33= - 58.3/t

t= - 58.3/-2.33

t=25.021 sec

48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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The amount of mechanical energy dissipated by air drag force as the stone travels a distance $y$ is given by $fy$.

To calculate the amount of mechanical energy dissipated by air drag force, we use the formula $fy$, where $f$ represents the air drag force and $y$ represents the distance traveled by the stone. The air drag force is proportional to the velocity of the stone and opposes its motion. As the stone moves upward, the air drag force slows it down, converting some of its kinetic energy into thermal energy. The product of the air drag force $f$ and the distance traveled $y$ gives us the amount of mechanical energy dissipated.

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Answer:

75 N

Explanation:

F = μF = 0.5(150) = 75N

Weight of a body is the force with which the earth pulls on it. So W = mg = 45 * 9.8 newtons.

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The density of CO at 1140 torr and 75.0°C is 1.44 g/L.
.

To find the density of CO at 1140 torr and 75.0°C, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure in torr, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.08206 L·atm/mol·K), and T is the temperature in Kelvin.

First, we need to convert the pressure from torr to atm:

1140 torr = 1.50 atm

Next, we need to convert the temperature from Celsius to Kelvin:

75.0°C + 273.15 = 348.15 K

Now, we can rearrange the ideal gas law equation to solve for the density:

n/V = P/RT

To find the density, we need to divide the number of moles (n) by the volume (V). We can assume that we have 1 mole of CO, so n = 1.

Substituting the values we have:

1/V = (1.50 atm)/(0.08206 L·atm/mol·K × 348.15 K)

1/V = 0.0516 L/mol

V = 19.36 L/mol

Now we have the volume, but we need to find the density. Density is mass per unit volume, so we need to find the mass of 1 mole of CO. The molar mass of CO is 28.01 g/mol.

Density = (28.01 g/mol) / (19.36 L/mol) = 1.44 g/L

Therefore, the density of CO at 1140 torr and 75.0°C is 1.44 g/L.

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.

Answer:

I'm pretty sure question one is D. Anatomy and physiology

Explanation:

normally you'd have to learn about Physiology before you move on to therapy from my knowledge...

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The magnitude of the resultant magnetic field B inside the cylinder for Bo = 0.130T is zero.

A long, thin vanadium cylinder with its axis parallel to an external magnetic field Bo in the +x-direction. At points far from the ends of the cylinder, by symmetry, all the magnetic vectors are parallel to the x-axis. At temperatures near absolute zero, Bc approaches 0.142 T for vanadium, a type-l superconductor. The normal phase of vanadium has a magnetic susceptibility close to zero.

The magnetic field H inside a long, thin superconducting wire or cylinder is given by the equation;B = μoH, where B is the magnetic field, H is the field intensity, and μo is the permeability of free space. However, when the wire is in the superconducting state, the magnetic field inside the wire is excluded. The magnetic field outside the wire is proportional to the current circulating in the wire.

London equations describe the electromagnetic behaviour of a superconductor below its critical temperature. They imply that the electric and magnetic fields will decrease exponentially within the material, which means that they are confined inside the material. The magnitude of the resultant magnetic field B inside the cylinder for Bo = 0.130T is zero.

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The resultant work that is done in moving the chair is 289.24 J.

We know that friction is a force that tends to resist the motion of a body. As such the direction of the friction must be opposite to the direction of the force that acts on the chair here.

Given that the frictional force is obtained from; μkN

μk = coefficient of kinetic friction

N = normal force

Fs = 0.40 *  21.2 N = 8.48 N

Net force = Horizontal force - Frictional force

Net force = 49.8 N - 8.48 N = 41.32 N

The resultant work = Net force * distance = 41.32 N * 7 m = 289.24 J

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For an aqueous solution to conduct an electric current, it must contain dissolved ionic compounds that dissociate into free ions. These ions act as mobile charge carriers, increasing the conductivity of the solution.

To conduct an electric current in an aqueous solution, ions must be present. An aqueous solution is a solution in which water is the solvent. When certain substances, such as salts or acids, dissolve in water, they dissociate into ions. These ions are responsible for carrying the electric charge through the solution.

Here is a step-by-step explanation of what needs to be present for an aqueous solution to conduct an electric current:

Dissolved ionic compounds: The solution must contain dissolved ionic compounds, such as sodium chloride (NaCl) or potassium nitrate (KNO3). When these compounds dissolve in water, they dissociate into positive and negative ions.

Free ions: The dissolved ionic compounds break apart into positively charged ions (cations) and negatively charged ions (anions). These free ions are able to move around in the solution.

Mobile charge carriers: The free ions act as mobile charge carriers that can transport electric charge through the solution. They carry the electric current by moving towards oppositely charged electrodes when a potential difference (voltage) is applied across the solution.

Conductivity: The presence of free ions increases the conductivity of the solution. Conductivity is a measure of how well a substance can conduct an electric current. The higher the concentration of free ions, the greater the conductivity of the solution.

Closed circuit: To observe the conduction of electric current in an aqueous solution, a closed circuit is required. This includes a source of electric potential (e.g., battery) and electrodes that are immersed in the solution. The electrodes serve as connection points for the current to enter and exit the solution.

For an aqueous solution to conduct an electric current, it must contain dissolved ionic compounds that dissociate into free ions. These ions act as mobile charge carriers, increasing the conductivity of the solution. By connecting the solution to a closed circuit, the movement of ions allows the electric current to flow through the solution.

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Given,

pH of bleach = 12

pH of detergent= 8 to 10

pH of eye drops = 7

pH of lemon juice 1 to 3

pH of tea = 4 to 6

On rearranging samples from most acidic to most basic,

1. Lemon juics

2. Tea

3. eye drops

4. detergent

5. Bleach

Answer:

20 N exerts no torque about the pivot.

14 N exerts a counterclockwise torque of 14 * .3 = .42 N-m

6  exerts a clockwise torque of 6 * .7 = .42 N-m

The meter stick will not turn because there is no net torque on the meter stick.

La densidad del metal como se requiere en la pregunta es 7.8 * 10 ^ 3 Kg / m ^ 3.

Sabemos que ese empuje hacia arriba = peso en aire - peso en líquido

Peso en el aire = 63,5 * 10 ^ -3 Kg * 10 m / s ^ 2 = 0,635 N

Peso en líquido = 55,4 * 10 ^ -3 Kg * 10m / s ^ 2 = 0,554 N

Empuje hacia arriba = 0,635 N - 0,554 N = 0,081 N

Pero ;

Empuje hacia arriba = Volumen * densidad del fluido * aceleración debido a la gratitud

volumen = empuje hacia arriba / densidad del fluido * aceleración debido a la gratitud

volumen = 0.081 N / 1000 * 10

Volumen = 8.1 * 10 ^ -6 m ^ 3

Densidad = masa / volumen

Densidad = 63,5 * 10 ^ -3 Kg / 8,1 * 10 ^ -6 m ^ 3

= 7,8 * 10 ^ 3 kg / m ^ 3

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The direction of this current's magnetic force on an electron that is moving perpendicular to the page and outward from it on the left side of the wire is downward.

What is Magnetic force?

The force exerted by a magnetic field on a moving charged particle is known as a magnetic force. It is described by the formula F = q(v x B), where F is the magnetic force, q is the particle's charge, v is the particle's velocity, and B is the magnetic field.

The right-hand rule states that when a wire-carrying current is held in the right hand with the thumb pointing in the direction of the current, the fingers will curl in the direction of the magnetic field lines created by the current.

The magnetic field lines will create clockwise circles around the wire because, in this instance, the current flows from the top of the page downward.

Now imagine an electron on the left side of the wire traveling perpendicular to the page. The electron will experience a magnetic force since it travels in a direction perpendicular to both the magnetic field and the current.

We can use the left-hand rule for a negative charge to determine the direction of this force. If the left hand is held with the fingers pointing toward the magnetic field and the thumb pointing toward the electron's velocity, the palm will face the order of the force on the electron.

The thumb points to the left because the electron leaves to the left. The fingers curl because the magnetic field lines go clockwise around the wire. Therefore, the magnetic force acting on the electron is directed downward because the palm is facing downward.

Therefore, the magnetic pull exerted by this current on an electron traveling outward and perpendicular to the page on the wire's left side is directed downward.

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