A roller coaster features a near vertical drop of 95 meters. If the initial velocity was zero, the mass of the cart and riders was 1,000 kg, and the velocity at the end of the drop was 35 m/s, how much of the potential energy was converted into thermal energy?319 kJ218 kJ342 kJ276 kJ

Answers

Answer 1

Given:

• Vertical drop = 95 meters

,

• Initial velocity = 0 m/s

,

• Mass of cart and riders = 1000 kg

,

• Final velocity = 35 m/s

Let's find the amount of potential energy converted to thermal energy.

For the potential energy, we have:

PE = mgh

Also thermal energy is a form of kinetic energy.

Thus, for the thermal energy, we have:

\(KE=\frac{1}{2}mv^2\)

Now, to find the difference, we have:

\(\begin{gathered} PE-KE \\ \\ =(\text{mgh)}-(\frac{1}{2}mv^2) \end{gathered}\)

Where:

g is acceleration due to gravity = 9.8 m/s^2

v is the final velocity = 35 m/s

h is the height = 95 meters

m is the mass

Thus, we have:

\(\begin{gathered} (1000\times9.8\times95)-(\frac{1}{2}\times1000\times35^2) \\ \\ =931000-612500 \\ \\ =318500\text{ J }\approx319000\text{ }\approx319\text{ kJ} \end{gathered}\)

Therefore, the amount of potential energy converted into thermal energy is 319 kiloJoules.

ANSWER:

319 kJ


Related Questions

What impact does your family have on air pollution? Find out how much carbon dioxide your family’s car releases.

a. First find out how many gallons of gasoline your family’s car holds when the tank is full. (Often this is stated somewhere in the owner’s manual.)

b. Estimate how many gallons of gasoline are used each week by your family. You can do this by finding out how many times a week gasoline is put in the car and about how many gallons is put in each time.

c. Now calculate how many pounds of carbon dioxide are emitted each week by your family’s use of the car. How many pounds are emitted each month? Each year?

Answers

My family car has a tank size of 19 gallons, and it is fueled twice a week at about 8 gallons each time. It's yearly carbon emission is about 16,254 pounds per year.

The family car's emission

To estimate the weekly gasoline consumption, we multiply the number of refills (2) by the amount of gasoline added each time (8 gallons):

Therefore weekly gasoline consumption 2 refills/week at 8 gallons per refill = 16 gallons/week

c. The emission factor for carbon dioxide is approximately 19.55 pounds per gallon.

Therefore, to obtain the weekly emissions,

Multiply the weekly gasoline consumption 16 gallons by the emission factor of carbon dioxide 19.55 pounds per gallon.

Weekly carbon dioxide emissions is 16 gallons/week * 19.55 pounds/gallon

= 312.8 pounds/week

Monthly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a month approximately 4.35) to get the monthly carbon dioxide emissions

Monthly carbon dioxide emissions is 312.8 pounds per week * 4.35 weeks per month

≈ 1,359 pounds/month

Yearly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a year approximately 52 to get the yearly carbon dioxide emissions.

Yearly carbon dioxide emissions is 312.8 pounds per week * 52 weeks per year

≈ 16,254 pounds/year

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A truck travels up a hill with a 6.9" incline.
The truck has a constant speed of 24 m/s.
What is the horizontal component of the
truck's velocity?
Answer in units of m/s.

Answers

With the application of resolution of vectors, the horizontal velocity is 23.99995 m/s

What is Uniform Speed ?

Uniform speed is also known as constant speed. This can be defined when the distance travel by an object per time taken is constant.

Given that a truck travels up a hill with a 6.9" incline. The truck has a constant speed of 24 m/s.

First convert minute to degree.

1 minute = 0.0166667

6.9 minute = 6.9 × 0.016667 = 0.115 degree

The formula for the horizontal component of the truck's velocity will be UcosФ, while the vertical component is UsinФ

Substitute all the parameters into the equation.

Horizontal velocity = 24cos 0.115 = 23.99995 m/s

Therefore, the horizontal component of the truck's velocity will be 23.99995 m/s which can be approximated to 24 m/s

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Question 6 of 10
Which statements below are true?
Check all that apply.
A. Displacement measurements must include magnitude, unit, and
direction.
B. If motion starts and stops at the same location, then the
displacement is zero.
C. Distance can be fully described with a magnitude and a unit.
D. Distance is always less than or equal to the magnitude of the
displacement.

Question 6 of 10Which statements below are true?Check all that apply.A. Displacement measurements must

Answers

Answer:

A, AND B,

Explanation: just trust me bro

Assignment: Calculating Speed Investigation

Data Analysis:
Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.





2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.







3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.








4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.








5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.






Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.
Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.












Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?




2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your own

Answers

Answer:

Assignment: Calculating Speed Investigation

Data Analysis:

Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.

2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.

3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.

4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.

5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.

Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.

Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.

Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?

2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your own

Explanation:

Assignment: Calculating Speed Investigation

Data Analysis:

Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.

2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.

3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.

4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.

5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.

Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.

Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.

Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?

2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your ownWhich sentence uses a superlative adjective correctly?

Anthony is running more quickly than anyone else on the field.

Shalon is a very talented pianist.

That is the best chocolate cake I have ever tasted.

Ani is the better gymnast of the two.

Which statement best compares and contrasts the purpose of "PROSERPINE" to that of "How Old Man Winter Was Driven Back"?

The Greek myth explains the creation of the earth, while the Iroquois myth also explains why there is evil in the world.

The Greek myth explains the creation of the earth, while the Iroquois myth also explains the creation of the moon.

The Greek myth explains the changing of the seasons as well as the existence of the underworld, while the Iroquois myth also explains the changing of the seasons.

The Greek myth explains the creation of the moon, while the Iroquois myth explains the creation of the sun.

Read the passages:

from "How Old Man Winter Was Driven Back"

"I, too, am powerful, and I am young! I do not fear you. When I touch the earth, it grows soft and warm. Every living thing stirs in its sleep,—birds and bees, flowers and trees, animals and men. When I speak, the sleeping sun awakes. See! Already he begins to send down his arrows. Hasten! that they may not find you, on the trail to the North Sky."

from "How the World Was Made"

Even some of the trees went to sleep. Only the cedar, the pine, the spruce, the holly, and the laurel were awake all seven nights. Therefore they are always green. They are also sacred trees. But to the other trees it was said, “Because you did not stay awake, therefore you shall lose your hair every winter.”

Which best uses textual evidence to compare and contrast these two myths?

Both myths show the change in seasons as a violent battle.

In "How Old Man Winter Was Driven Back," the change in

PLEAS HELP
Answer the questions in the picture pleas

PLEAS HELPAnswer the questions in the picture pleas

Answers

False - Not all poisons are made in labs. Many naturally occurring substances can also be poisonous, such as certain plants and animals.

True - People can be exposed to toxins through ingestion (eating or drinking), inhalation (breathing in), injection (such as with drugs), and absorption through the skin.

False - Poisoning is not a very common method of murder today. While it does happen, other methods such as firearms, suffocation, and blunt force trauma are more common.

False - There are more than 4 types of controlled substances. In the United States, controlled substances are categorized into 5 schedules based on their potential for abuse and medical use.

Wat are the controller substance?

The 5 groups of controlled substances in the US are:

Schedule I: Substances with no currently accepted medical use and a high potential for abuse, such as heroin and LSD.

Schedule II: Substances with a high potential for abuse and dependence, but also with currently accepted medical uses, such as morphine and cocaine.

Schedule III: Substances with a lower potential for abuse and dependence than Schedule II drugs, but still with accepted medical uses, such as anabolic steroids and some barbiturates.

Schedule IV: Substances with a lower potential for abuse and dependence than Schedule III drugs, such as benzodiazepines and some prescription stimulants.

Schedule V: Substances with the lowest potential for abuse and dependence, such as cough medicines containing small amounts of codeine.

The common effects of each group vary, but they can include pain relief, sedation, euphoria, and other psychoactive effects.

Anabolic steroids can have many harmful effects on the body, including:

Liver damageHigh blood pressureIncreased risk of heart disease and strokeDecreased fertilityMood swings and aggressionAcne and other skin problemsHair loss

Alcohols can be toxic to many tissues in the body, including the liver, brain, and gastrointestinal tract.

Bioterrorism is the deliberate release of biological agents (such as bacteria or viruses) with the intent to harm or kill people, animals, or plants.

Strychnine is a highly toxic substance that can cause muscle spasms and convulsions, leading to respiratory failure and death. Other symptoms can include restlessness, agitation, and high blood pressure.

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How much stronger is the electric force between two
protons than the gravitational force between them?

Answers

Answer:

Explanation:

The electric force between two protons is 10^36 times stronger than the gravitational force between them.

Answer:

Electric force is 1.23 x 10³⁶ times stronger than gravitational force.

Explanation:

First, we will calculate the gravitational force using Newton's Law:

\(F_G = \frac{Gm^2}{r^2}\\\\\)

where,

F_G = Gravitational Force = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

m = mass of proton = 1.67 x 10⁻²⁷ kg

r = distance between protons

Therefore,

\(F_G = \frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^2)(1.67\ x\ 10^{-27}\ kg)^2}{r^2}\\\\F_G = \frac{1.86\ x\ 10^{-64}\ Nm^2}{r^2}\\\\\)

Now, we will calculate the electrostatic force using Colomb's Law:

\(F_E = \frac{kq^2}{r^2}\\\\\)

where,

F_E = Electrostatic Force = ?

k = Colomb's Constant = 9 x 10⁹ Nm²/C²

q = charge of proton = 1.6 x 10⁻¹⁹ C

r = distance between protons

Therefore,

\(F_E = \frac{(9\ x\ 10^{9}\ Nm^2/kg^2)(1.6\ x\ 10^{-19}\ C)^2}{r^2}\\\\F_E = \frac{2.3\ x\ 10^{-28}\ Nm^2}{r^2}\\\\\)

Dividing both forces:

\(\frac{F_E}{F_G} = \frac{2.3\ x\ 10^{-28}}{1.86\ x\ 10^{-64}}\)

F_E = 1.23 x 10³⁶ F_G

Therefore, electric force is 1.23 x 10³⁶ times stronger than gravitational force.

22. How do we correct the issue of flipped imagery caused by mirrors?

Answers

To correct the issue of flipped imagery caused by mirrors you can use a technique called "mirror flipping". Mirror flipping involves using a second mirror to reflect the reflected image from the first mirror which then flips it back to its original orientation

Alternatively you can use a prism to correct the orientation of the image. A prism is a transparent object that can bend light. By placing it infront of the mirror you can reflect the twice, effectively helping in the correction of the orientation of the image

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When an electric current flows through a wire a
magnetic field is created. To increase the power
of the magnetic field you would
A. decrease the number of coils in the wire
Bkeep the same number of coils in the wire
Cincrease the number of coils in the wire
Dremove the coils from the wire​

Answers

Answer:

Option C. is correct

Explanation:

The magnetic field is the area around a magnet in which there is magnetic force. When an electric current flows through a wire a  magnetic field is created. A single wire does not produce a strong magnetic field. So, to increase the power  of the magnetic field, increase the number of coils in the wire.

For 2 non-perpendicular vectors, R is calculated by component method.
5. A baseball player leaves the bench and runs A= 25 m [E] and then B=40 m [SW].
Draw these two vectors, determine their x- and y-components, then draw their
resultant vector R by triangle method .Use scale 5 m= 1 cm. Calculate R by
component method and compare with the graphical value.

Answers

Answer:

30.3 meters, 172 degrees.

Explanation:

Lia lives in the mountains of Colorado. Her aunt came to visit and had a difficulty breathing for a few days until she adjusted to the higher altitude. Which explanation best describes the reason for this difficulty

Answers

There is decreased pressure on the air molecules as one moves higher and the air is thinner

What happens at high altitude?

We know that the air pressure decreases with height. This implies that the air is thinner as you move up to higher altitude. This is the idea behind the use of the phrase; "Thin air".

Now, owing to the fact that there is decreased pressure on the air molecules as one moves higher and the air is thinner, it is much harder to breath until her aunt adjusts to the higher altitude.

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The engine of a boat (m = 2280 kg) exerts an
1800 N force northward, while the current
pushes it 1050 N eastward.
What is the magnitude of the acceleration
of the boat?

Answers

Answer:

a = 0.9139 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

The forces are on two different axes, x & y axes (North and East). In this way, the Pythagorean theorem should be used to determine the total force.

Fx = 1800 [N]

Fy = 1050 [N]

\(F = \sqrt{(F_{x} )^{2} +(F_{y} )^{2} } \\F=\sqrt{(1800)^{2} +(1050)^{2} } \\F=2083[N]\)

Now using Newton's second law.

ΣF = m*a

where:

F = force = 2083.8 [N] (units of Newtons)

m = mass = 2280 [Kg]

a = acceleration [m/s²]

2083.8 = 2280*a

a = 0.9139 [m/s²]

If a bus is traveling at 12m/s and a passenger on the bus is walking to the back of the bus at a velocity of 5m/s, what is the relative velocity of the passenger relative to the ground?​

Answers

The relative velocity is 17m/s.

The relative velocity of the passenger relative to the ground can be found by applying the concept of relative motion.

speed of bus (vb)=12m/s

speed of passenger inside the bus(vp)= 5m/s opposite to the speed of bus

speed of passenger relative to the ground = v

v= vb+vp

v= 12+(-5), since passenger is traveling in opposite direction

v=7m/

Therefore, the velocity of passenger relative to the ground is 7m/s.

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1. Which of the following values are vectors? (Choose all that apply)
Increase of 19 Kelvin
21 kilometers north
1 cm in the positive c-direction
11.5 mm
O 74°C
4 meters

Answers

The vector values are '21 kilometers north'   and '1 cm in the positive c-direction'.

Given:

The following values:

Increase of 19 Kelvin 21 kilometers north 1 cm in the positive c-direction 11.5 mm 74°C 4 meters

To find:

The vector values from the given values.

Solution:

The vector quantities are those quantities with magnitude and direction.

Scalar quantities are those quantities with only magnitude and no direction.

Increase of 19 Kelvins: Only a magnitude no direction, scalar quantity.21 kilometers north: Magnitude and the direction, vector quantity.1 cm in the positive c-direction: Magnitude, and the direction, vector quantity.11.5 mm: Only a magnitude no direction, scalar quantity.O 74°C: Only a magnitude no direction, scalar quantity.4 meters: Only a magnitude no direction, scalar quantity.

The vector values are '21 kilometers north'   and '1 cm in the positive c-direction'.

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Which of the following is NOT true about the mass of an object?

A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.

Answers

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of
strength-training
is Laasya performing?

Answers

Laasya is performing resistance training by lifting a table and moving it to another room to expand the space in her room. The correct option to this question is D.

Strength training By putting your muscles up against resistance, resistance training builds muscle strength. Free weights, weight machines, resistance bands, and your own body weight are all used in various types of resistance training. To get the most out of their training, beginners should go two or three times per week.Resistance training is founded on the idea that, when called upon, the body's muscles will struggle to overcome a resisting force. Resistance exercise has both advantages and disadvantages.Resistance exercises include planks, sit-ups, squats, push-ups, leg raises, and leg extensions. You and a small amount of room are all that are needed for these strength training exercises.

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Complete question : Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of strength-training is Laasya performing?

a. Endurance

b. Isometric

c. Isotonic

d. Resistance

explain why the length of the pendulum is measured from the lower part of the wooden clamp

Answers

The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.

The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.

The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.

As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.

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a stationary 165 kg football player is tackled by a 178 kg player running at 8 m/s. How fast are they moving after the collision ?

Answers

After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Does the principle of conservation of momentum is constant inside a certain problem domain?

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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A cheetah is running at a speed of 20.1 m/s in a direction of 53 north of west. Find the components of the cheetah's velocity along the following directions.(a) the velocity component due north____m/s(b) the velocity component dug west____m/s

Answers

The situation described is shown below:

From the diagram we notice that the velocity due north will be related to the opposite leg of the angle given and the west component will be related to the adjacent leg. With this in mind:

a)

The component due north can be calculated using the sine function since it is related to the opposite leg, then we have:

\(\begin{gathered} v_N=20.1\sin53 \\ v_N=16.1 \end{gathered}\)

Therefore, the velocity component due north is 16.1 m/s

b)

This component will be related to the cosine function, then we have:

\(\begin{gathered} v_W=20.1\cos53 \\ v_W=12.1 \end{gathered}\)

Therefore, the velocity component due west is 12.1 m/s

A cheetah is running at a speed of 20.1 m/s in a direction of 53 north of west. Find the components of

Use the table to answer the question below.

I need urgent help please please please please please please please please please please please please please please please please please. D:​

Use the table to answer the question below.I need urgent help please please please please please please

Answers

Explanation:

Here is the first one....you should try the second one...

Use the table to answer the question below.I need urgent help please please please please please please

An aircraft is in level flight at 225 km/hr through air at standard conditions. The lift coefficient at this speed is 0.45 and the drag coefficient is 0.065. The mass of the aircraft is 900 kg. Calculate the effective lift area for the aircraft and the required engine thrust and power to maintain level flight.

Answers

Answer:

- the effective lift area for the aircraft is 8.30 m²

- the required engine thrust is 1275 N

- required power is 79.7 kW

Explanation:

Given the data in the question;

Speed V = 225 km/hr = 62.5 m/s

The lift coefficient CL = 0.45

drag coefficient CD = 0.065

mass = 900 kg

g = 9.81 m/s²

a)  the effective lift area for the aircraft

we know that for a steady level flight, weight = lift and thrust = drag

Using the equation for the lift force

F\(_L\) = C\(_L\)\(\frac{1}{2}\)ρV²A = W

we substitute

0.45 × \(\frac{1}{2}\) × 1.21 × ( 62.5 )² × A = ( 900 × 9.81 )

1081.05 × A = 8829

A = 8829 / 1081.05

A = 8.30 m²

Therefore, the effective lift area for the aircraft is 8.30 m²

b) the required engine thrust and power to maintain level flight.

we use the expression for drag force

F\(_D\) = T = C\(_D\)\(\frac{1}{2}\)ρV²A

we substitute

= 0.065 × \(\frac{1}{2}\) × 1.21 × ( 62.5 )² × 8.30

T = 1275 N

Since drag and thrust force are the same,

Therefore, the required engine thrust is 1275 N

Power required;

P = TV

p = 1275 × 62.5

p = 79687.5 W

p = ( 79687.5 / 1000 )kW

p = 79.7 kW

Therefore, required power is 79.7 kW

I KNOW YALL SEE THIS I NEED HELP GOD WILL GIVE U MANY BLESSING HELP A POOR SOUL OUT THE RECENT QUESTIONSSSSSSSSSSSSS. ://///

Answers

Answer:

ok

Explanation:

will do

Answer:

sure

Explanation:

How have humans
changed the area and how might this affect recovery after the flood?

Answers

Answer:

Explanation:

Loss of lives and property: Immediate impacts of flooding include loss of human life, damage to property, destruction of crops, loss of livestock, non-functioning of infrastructure facilities and deterioration of health condition owing to waterborne diseases. Flash floods, with little or no warning time, cause more deaths than slow-rising riverine floods.

Loss of livelihoods: As communication links and infrastructure such as power plants, roads and bridges are damaged and disrupted, economic activities come to a standstill, resulting in dislocation and the dysfunction of normal life for a period much beyond the duration of the flooding. Similarly, the direct effect on production assets, be it in agriculture or industry, can inhibit regularly activity and lead to loss of livelihoods. The spill over effects of the loss of livelihoods can be felt in business and commercial activities even in adjacent non-flooded areas.

Decreased purchasing and production power: Damage to infrastructure also causes long-term impacts, such as disruptions to clean water and electricity, transport, communication, education and health care. Loss of livelihoods, reduction in purchasing power and loss of land value in the flood plains lead to increased vulnerabilities of ties living in the area. The additional cost of rehabilitation, relocation of people and removal of property from flood-affected areas can divert the capital required for maintaining production.

Mass migration: Frequent flooding, resulting in loss of livelihoods, production and other prolonged economic impacts and types of suffering can trigger mass migration or population displacement. Migration to developed urban areas contributes to the overcrowding in the cities. These migrants swell the ranks of the urban poor and end up living in marginal lands in cities that are prone to floods or other risks. Selective out-migration of the workforce sometimes creates complex social problems.

Psychosocial effects: The huge psycho-social effects on flood victims and their families can traumatize them for long periods of time. The loss of loved ones can generate deep impacts, especially on children. Displacement from one’s home, loss of property and livelihoods and disruption to business and social affairs can cause continuing stress. The stress of overcoming these losses can be overwhelming and produce lasting psychological impacts.

Hindering economic growth and development: The high cost of relief and recovery may adversely impact investment in infrastructure and other development activities in the area and in certain cases may cripple the frail economy of the region. Recurrent flooding in a region may discourage long-term investments by the government and private sector alike. Lack of livelihoods, combined with migration of skilled labour and inflation may have a negative impact on a region’s economic growth. Loss of resources can lead to high costs of goods and services, delaying its development programmes.

Political implications: Ineffective response to relief operations during major flood events may lead to public discontent or loss of trust in the authorities or the state and national governments. Lack of development in flood-prone areas may cause social inequity and even social unrest posing threat to peace and stability in the region.

Suppose a door is 1 meter wide. Calculate the difference in the amount torque exerted on the door when someone pushes with a constant force of 100N at the handle side of the door compared to the middle of the door. Assume the force is perpendicular to the surface of the door.

Answers

Answer:

Δτ = 50 N.m

Explanation:

The torque applied on an object is given by the product of the force applied on it and the perpendicular distance between the force and the axis of rotation of the object. That is:

τ = F r

where,

τ = Torque applied on the object

F = Force applied on it

r = distance from axis of rotation

FOR HANDLE SIDE OF DOOR:

τ₁ = F r₁

where,

τ₁ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₁ = distance from axis of rotation = 1 m

Therefore,

τ₁ = (100 N)(1 m)

τ₁ = 100 N.m

FOR MIDDLE OF DOOR:

τ₂ = F r₂

where,

τ₂ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₂ = distance from axis of rotation = 1 m/2 = 0.5 m

Therefore,

τ₂ = (100 N)(0.5 m)

τ₂ = 50 N.m

Now, the difference between the amount of torque in both cases is:

Δτ = τ₁ - τ₂

Δτ = 100 N.m - 50 N.m

Δτ = 50 N.m

Derive, using newtons second law

m1 = 559.5g
m2 = 569.3g
ay = ?
g = ?

a_y=g((m_2-m_1)/(m_2+m_1 ))

Answers

Answer:

Explanation:

convert the mass from g to kg

1 g = 0,001 kg

m1 =559,5 g = 5,595 kg

m2 = 569,3 g = 5,569 kg

Newtons second Law

F = m *a = m * g

g = 10 m/s^2

a_y = g ((m_2 - m_1) / (m_2+m_1))

a_y = 10 m/s^2 * ((5,569kg -5,595kg) / (5,569kg + 5,595kg))

a_y = 10 m/s^2 [(-0,026kg) / 11,164kg]

a_y = 10 m/s^2 (-0,0023)kg

a_y = - 0,023 kg m / s^2

A 0.14-km wide river flows with a uniform speed of 4.0 m/s toward the east. It takes 20 s for a boat to cross the river to a point directly north of its departure point on the south bank. What is the speed of the boat relative to the water

Answers

Answer:

The right approach is "8.1 m/s". A further explanation is provided below.

Explanation:

According to the table,

Speed of Boat

= \(\frac{s}{t}\)

\(V_b=\frac{140}{20}\)

\(V_a = 4 \ m/s\)

\(V_B = 7 \ m/s\)

Now,

⇒  \((V_{relative})^2 = (7)^2+(4)^2\)

or,

⇒  \((V_r)^2=49+16\)

              \(=65\)

         \(V_r=\sqrt{65}\)

              \(=8.1 \ m/s\)

Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform acceleration towards (-)direction, Uniform deceleration towards (+) direction and Uniform deceleration towards (-) direction in displacement time graph.Can you draw the shapes for each type ?

Answers

Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform

This problem concerns the properties of circular orbits for a satellite of mass m orbiting a planet of mass M in an almost circular orbit of radius r. In doing this problem, you are to assume that the planet has an atmosphere that causes a small drag due to air resistance. "Small" means that there is little change during each orbit so that the orbit remains nearly circular, but the radius can change slowly with time. The following questions will ask about the net effects of drag and gravity on the satellite's motion, under the assumption that the satellite's orbit stays nearly circular. Use G if necessary for the universal gravitational constant.

What is the potential energy U of the satellite?Express your answer in terms ofm, M, G, and r.What is the kinetic energy K of the satellite?Express the kinetic energy in termsof m, M, G, and r.

Answers

Answer:

A) U = - GMm/r

B) K = 0.5 mGM/r

Explanation:

A) The potential energy U of the satellite

U = - GMm/r

G = universal gravitational constant which is ( 6.67e-11 Nm^2/c^2 )

M = mass of the planet

m = mass

r = distance ( radius )

B) Kinetic energy

kinetic energy expressed as K = 0.5 m Vo^2

NOTE : Vo^2 = GM / r

hence kinetic energy will be expressed as

K = 0.5 mGM/r

The large block shown is =16.0 cm
wide, =19.0 cm
long, and =25.00 cm
high with a mass of 4.55 kg.
This block is passing through air (density of air air=1.43kg/m3).
Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient of Γ=0.822
. See the hint panel for the drag force equation.

Answers

The terminal velocity of the block is approximately 2.08 m/s when it is traveling downward with a drag coefficient of 0.822.

How to calculate terminal velocity?

To calculate the terminal velocity of the block, we need to use the equation for terminal velocity which is:

v_terminal = sqrt((2mg)/(ρAC_d))

where:

m is the mass of the blockg is the acceleration due to gravity (9.81 m/s^2)ρ is the density of the airA is the cross-sectional area of the blockC_d is the drag coefficient

First, let's convert the dimensions of the block from centimeters to meters:

width = 16.0 cm = 0.16 m

length = 19.0 cm = 0.19 m

height = 25.0 cm = 0.25 m

Next, let's calculate the cross-sectional area of the block:

A = width * length = 0.16 m * 0.19 m = 0.0304 m^2

Now we can substitute the values into the equation for terminal velocity:

v_terminal = sqrt((24.55 kg9.81 m/s^2)/(1.43 kg/m^30.0304 m^20.822))

v_terminal = 2.08 m/s

Therefore, the terminal velocity of the block is approximately 2.08 m/s when it is traveling downward with a drag coefficient of 0.822.

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a group of factory requires 5 MW to operate . calculate the number of turbines needed to meet the need if the average output of each turbine is 0.5W

Answers

The number of turbines needed to meet the need if the average output of each turbine is 0.5W is 10000000 turbines

Data obtained from the question

From the question given above, the following data were obtained:

Total power required = 5 MW = 5 × 1000000 = 5000000 WPower per turbine = 0.5 WNumber of turbines =?

How to determinethe number of turbines needed

From the given data, we can simply determine the number of turbines needed by the factory as follow:

Number of turbines = Total power / Power per turbine

Number of turbines = 5000000 / 0.5

Number of turbines = 10000000 turbines

Therefore, the number of turbines needed by the factory is 10000000 turbines

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Four passengers with combined mass 250 kg compress the springs of a car with worn out shock absorbers by 4.00cm when they enter it. Model the care and passengers as a single body on a single ideal spring. If the loaded has a period of vibration of 1.08 s, what is the period of vibration of the empty car?

Answers

Answer:

The time period of the empty car will be "1.00 s".

Explanation:

The given values in the question will be:

Mass,

m = 250 kg

Loaded car's time period will be:

T = 1.08 s

Shock absorbers compression,

x = 4 cm

or,

  = 0.04 m

Now,

Weight of passengers will be:

⇒  \(F=mg\)

         \(=250\times 9.8\)

         \(=2450 \ N\)

The spring constant of shock absorbers will be:

⇒  \(k=\frac{F}{x}\)

        \(=\frac{2450}{0.04}\)

        \(=61.250 \ N/m\)

As we know,

Time period, \(T = 2 \pi\sqrt{\frac{M}{k} }\)

On substituting the values, we get

                   \(1.08=2\pi \sqrt{\frac{M}{61250} }\)

                  \(\frac{M}{61250}=0.02955\)

                      \(M=0.02955\times 61250\)

                           \(=1809.6 \ kg\) (Total mass of car as well as its passengers)

Now,

The mass of the empty car will be:

⇒  \(m'=M-m\)

          \(=1809.6-250\)

          \(=1559.6 \ kg\)

hence,

The time period of empty car will be:

⇒  \(T'=2\pi\sqrt{\frac{m'}{k} }\)

         \(=2\pi\sqrt{\frac{1559.6}{61250} }\)

         \(=2\pi \sqrt{0.0254}\)

         \(=1.003 \ s\)

or,

         \(=1.00 \ s\)

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