A sample of 4. 25 moles of Hydrogen at 20. 0 ⁰C occupies a volume of 25. 0 L. Under what pressure is this sample?

Answer:

Explanation:

The balanced chemical equation is Cl2 + 2KBr → 2KCl + Br2. The amount of bromine is calculated as follows:

11.0 g KBr (1mol KBr/119.002g KBr * 1mol Br2/2mol KBr * 159.808g Br2/1mol Br2= 7.39 g Br2.)

The partial pressure of fluorine (\( F_{2}\)) in the vessel is 2.0. The correct option to this question is B.

To find the partial pressure of fluorine, we need to add up the partial pressures of all the gases in the vessel.

Partial pressure of \( N_{2}\) = 1.2 atm

Partial pressure of \( F_{2}\) = 2.0 atm

Partial pressure of \( H_{2}\) = 1.0 atm

Adding these together gives us a total pressure of 4.2 atm. However, we know that the total pressure of the vessel is actually 5.5 atm. This means that there must be some additional gas in the vessel that we haven't accounted for.

To find the partial pressure of fluorine, we can subtract the partial pressures of nitrogen and hydrogen from the total pressure:

Total pressure = partial pressure of \( F_{2}\) + partial pressure of \( F_{2}\) + partial pressure of \( H_{2}\)

5.5 atm = 1.2 atm + partial pressure of \( F_{2}\) + 1.0 atm

Solving for partial pressure of F2:

partial pressure of \( F_{2}\) = 5.5 atm - 1.2 atm - 1.0 atm

partial pressure of \( F_{2}\) = 3.3 atm

Therefore, the partial pressure of fluorine \( F_{2}\) in the vessel is 2.0 atm.

The correct answer is B) 2.0 atm.

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Answer:

Yes, they are useful.

Explanation:

They allow us to make use of strengths and benefits of a particular element while not being hampered by it's faults.

However, keep in mind that 20 mSv per year is the recommended amount for any radiation worker and is still regarded quite safe. This is the most radiation most of us will ever be exposed to.

after 1st half life , remaining sample would be 100/2=50 g

after 2nd half life , remaining sample would be 50/2=25 g

after 3rd half life , remaining sample would be 25/2= 12.5 g

The half-life of a radionuclide is the amount of time it takes for half of its radioactive atoms to decay. A decent rule of thumb is that you will have less than 1% of the initial quantity of radiation after seven half-lives. Click here to learn more about half life.

A short-term and whole-body dosage would result in rapid sickness, such as nausea and a reduction in white blood cell count, followed by death.

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42.08 years of  time must pass before there is an acceptable radiation level at the site.​

What is the half-life of a radioactive material?

The half life of a radioactive substance is the period of time during which its mass or number of atoms is decreased to half of what it was initially. The time it takes for a radioactive substance (or half of its atoms) to break down or transform into another substance is commonly used to define half-life.

Radioactivity, as its name suggests, is the act of generating radiation without any external cause. This is accomplished by an atomic nucleus that is unstable for whatever reason and "wants" to surrender some energy in order to change its configuration to one that is more stable.

After first half-life will remain 2560/2 i.e. 1280g of radioactive substance.

After second half-life will remain 1280/2 i.e. 640g

After 3rd half-life will remain 640/2 i.e. 320g

After 4th half-life will remain 160g

After 5th half-life will remain 80g

After 6th, 7th and 8th half-life will remain 40g, 20g and 10g respectively

It takes 8 half-lives to reach acceptable level of radiation i.e. 8*5.26 years

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Answer:The process of photosynthesis in plants converts carbon dioxide and water into glucose and oxygen. The balanced equation for this reaction is:

6 CO2 + 6 H2O --> C6H12O6 + 6 O2

This equation tells us that for every 6 molecules of carbon dioxide (CO2) that are consumed, 1 molecule of glucose (C6H12O6) is produced, along with 6 molecules of oxygen (O2).

Given that we have 760.0 grams of carbon dioxide and a sufficient amount of water, we can use the balanced equation and the molar mass of glucose to calculate the amount of glucose that will be produced.

First, we need to convert the given amount of carbon dioxide to moles. We can do this by using the molar mass of carbon dioxide, which is 44.01 g/mol.

760.0 g CO2 / 44.01 g/mol = 17.3 moles CO2

Next, we can use the balanced equation to determine the number of moles of glucose that will be produced. Since the ratio of CO2 to glucose is 6:1, for every 6 moles of CO2, 1 mole of glucose will be produced.

17.3 moles CO2 / 6 = 2.88 moles glucose

Finally, we can convert the number of moles of glucose to grams using the molar mass of glucose, which is 180.16 g/mol

2.88 moles glucose * 180.16 g/mol = 517.3 grams glucose

Therefore, plants will produce 517.3 grams of glucose using 760.0 grams of carbon dioxide and a sufficient amount of water.

Explanation:

Answer:

Explanation:

What is the reducing agent in the reaction 2N a + 2H 2O → 2N aOH + H 2? Sodium metal. You're dealing with a redox reaction in which sodium metal, Na, is being oxidized to sodium cations, Na+, and hydrogen is being reduced to hydrogen gas, H2.

When two MOS transistors, M1 and M2, are connected in series with the same width but different channel lengths, the overall behavior can be analyzed using the long-channel model

The long-channel model assumes that the channel length of a MOS transistor is significantly larger than the technology scaling limits, thereby neglecting the short-channel effects. In this case, M1 and M2 have the same width but different channel lengths, denoted as L1 and L2, respectively.

In the long-channel model, the key factor determining the behavior of a MOS transistor is its channel length. A longer channel length results in higher resistance and reduced current flow. Therefore, the transistor with the longer channel length (M2) will exhibit higher resistance compared to the transistor with the shorter channel length (M1).

When two transistors are connected in series, the overall behavior is dominated by the transistor with the higher resistance. In this scenario, since M2 has the longer channel length, it will have a higher resistance compared to M1.

Consequently, the overall behavior of M1 and M2 connected in series will be influenced primarily by the characteristics of M2 due to its higher resistance.

Therefore, using the long-channel model, we can conclude that the behavior of M1 and M2 connected in series will be primarily determined by the transistor with the longer channel length, M2, due to its higher resistance.

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Zinc amalgam (Zn(Hg)) with hydrochloric acid (HCl) produces hydrogen gas (H2) and a solution of zinc chloride (ZnCl2) in water (H2O).

When zinc amalgam (Zn(Hg)) is added to hydrochloric acid (HCl), a redox reaction takes place. The HCl donates hydrogen ions (H+) to the Zn(Hg) and forms zinc chloride (ZnCl2) and hydrogen gas (H2) as products. The balanced chemical equation for this reaction is:

Zn(Hg) + 2HCl(aq) → ZnCl2(aq) + H2(g)

The zinc amalgam acts as a reducing agent and reduces the hydrogen ions (H+) in the hydrochloric acid (HCl) to form hydrogen gas (H2). The hydrogen gas is produced as bubbles, which can be observed during the reaction.

The solution formed is a clear, colorless solution of zinc chloride (ZnCl2) dissolved in water (H2O). This reaction is a common demonstration of the reactivity of metals with acids and the production of hydrogen gas.

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Answer:

1 cl =10 ml

so

4.22cL= 4.22×10= 42.2 mL

Answer:

the order in which orbitals 4f,5p,5d,and 6s are filled is clacium.

Answer:

Explanation:

The speed of the rocket can be found by using the formula

\(v = \frac{d}{t} \\ \)

where

d is the distance

t is the time

From the question we have

\(v = \frac{1400}{11} \\ = 127.272727...\)

We have the final answer as

Hope this helps you

To Find :

The STP moles of 67.2 L CO.

Solution :

We know, molar volume at STP is used to converted into moles by :

1 moles = 22.4 L STP

So, number of moles in 67.2 L CO is :

\(n=\dfrac{67.2}{22.4}\\\\n = 3 \ moles\)

Therefore, number of STP moles are 3.

Hence, this is the required solution.

The type of reaction that is represented by these diagrams (attached) are given as:  "condensation polymerization" (Option D)

Any type of polymer in polymer science that undergoes a condensation reaction during the polymerization process is referred to as a condensation polymer (i.e. a little molecules, methanol or water is derived as a metabolite).

The provided reaction is an example of condensation polymerization because it involves the combination of two monomers, which produces a big polymer and water as a byproduct.

Condensation polymers make significant contributions to the packaging, insulation, and textile sectors as far as real-world application of same is concerned.

Also examples of times that are condensation polymers and that have silicon rather than carbon as part of their molecular or structural make up are;

In conclusion, it is to be noted that The type of reaction that is represented by these diagrams (attached) are given as:  "condensation polymerization"

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Answer:

condensation polymerization

Explanation:

100g of NaNO3 will dissolve in 100 grams of water

A homogeneous mixture of solutions of one or more solutes in a solvent. Adding sugar cubes to your tea or coffee is an example of a common solution. The ability of a sugar molecule to dissolve easily is called solubility. The term solubility can therefore be defined as the property of a substance (solute) to dissolve in a particular solvent. A solute is a substance that is either a solid, liquid, or gaseous solution in a solvent.          

Here it is given that in 100g of water at temperature 35°C the amount of NaNO3 will dissolve is 100g we get it from the solubility curve

The graphical relationship between solubility and temperature is called the solubility curve. A solubility curve shows the change in solubility of a solid at different temperatures in a solvent. In the figure, temperature variation is plotted on the x-axis and solubility is plotted on the y-axis.

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Answer:

33

Explanation:

Answer:

The valence electrons are the only parts of an atom that make chemical bonds. Noble gases don't form chemical bonds because they have a full outer shell (8 electrons).

Lead (II) acetate and sodium iodide do interact. In an oral solution in water, each of these salts mix to produce acid solution plus lead (II) iodide.

Baking soda, often known as sodium bicarbonate, is a food additive. It is also applied as both an organic deodorant to get rid of chemicals that make things smell bad in carpets and refrigerators. Calcium chloride, also known as "road salt," is a salt-like substance used to de-ice sidewalks and roads.

The analysis concluded there's no cause for worry regarding carcinogenicity. This information leads to the conclusion that the drug is not dangerous and that a calcium chloride carcinogenicity research was not performed.

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Answer:

D

Explanation:

Answer:

\(C_2H_4O_2\)

Explanation:

¡Hola!

En este caso, dado que conocemos la composición porcentual del compuesto, es posible primero obtener la formula empírica al asumir que dichos porcentajes son gramos, que se vuelven moles con las masas atómicas de carbono, hidrógeno y oxígeno respectivamente:

\(n_C=40gC*\frac{1molC}{12.01 gC}=3.33molC \\\\n_H=6.7gH*\frac{1molH}{1.01gC}=6.6molH\\\\n_O=53.3gO*\frac{1molO}{16.00gO}=3.33molO\)

De este modo, ahora obtenemos las relaciones molares entre ellos, con el fin de obtener los subíndices en la fórmula empírica:

\(C:\frac{3.33}{3.33}=1\\\\ H:\frac{6.6}{3.33}=2\\\\O:\frac{3.33}{3.33}=1\)

Por consiguiente, la fórmula empírica es:

\(CH_2O\)

Finalmente, dado que la masa molar del compuesto es 6.0/0.10=60g/mol (dada la masa y las moles), es posible notar que como la masa molar de la fórmula empírica es 30; esta es dos veces la molecular, por lo que esta ultima resulta:

\(C_2H_4O_2\)

¡Saludos!

Answer:

i dissagree bcause it is the same substance just a diffrent about so it will NOT melt at a diffrent temp

Explanation:

brainlyest?

agreed

Explanation:

if you put a stick of butter into a hot pan it will melt realitvely slow. now image a small sliced piece of butter into a slightly warm pan. It will also melt. There for a lower teampurature melting less of an object can me equaled out to the same time as a warmer tempuarture for a larger same object.

Answer: 24.0g of NaCl.

The number seems the highest, but I am not in Honors Chem (I am taking honors biology), so I do not know.

The ring of 4-methylcyclohexanone is more likely to ring flip compared to 4-tert-butylcyclohexanone due to the smaller size of the methyl group.

In cyclohexane, chair conformations can interconvert by a ring flip. In the axial position of a cyclohexane ring, bulkier substituents experience more steric strain than in the equatorial position. Therefore, the stability of a cyclohexane ring is dependent on the position of the substituents.

In 4-tert-butylcyclohexanone, the bulky tert-butyl group is located at the axial position of the cyclohexane ring, resulting in a destabilized conformation. In contrast, in 4-methylcyclohexanone, the smaller methyl group is located at the axial position, which results in a lower degree of destabilization.

Therefore, due to the smaller size of the methyl group in 4-methylcyclohexanone, the ring is more likely to flip compared to 4-tert-butylcyclohexanone, which has a more hindered axial position due to the larger tert-butyl group.

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In the given reaction, 2 moles of CuCl2 reacts with 4 moles of KI and gives 2 moles of CuI, 4 moles of KCl and 1 mole of I2.The balanced chemical equation for the reaction is;`2CuCl2 + 4KI → 2CuI + 4KCl + I2`If 4 moles of CuCl2 reacts with 4 moles of KI.

The limiting reagent, we will have to calculate the number of moles of I2 formed when 4 moles of each reactant are taken. The balanced chemical equation tells us that 2 moles of CuCl2 produces 1 mole of I2 and 4 moles of KI produce 1 mole of I2.Therefore,4 moles of CuCl2 will produce (1/2) x 4 = 2 moles of I2 and 4 moles of KI will produce 4/4 = 1 mole of I2.So, the limiting reagent is KI as it produces only 1 mole of I2 which is less than the 2 moles of I2 produced by 4 moles of CuCl2.

The given balanced chemical equation is,`2CuCl2 + 4KI → 2CuI + 4KCl + I2`To find out the limiting reagent, we have to calculate the number of moles of I2 formed when 4 moles of each reactant are taken. The balanced chemical equation tells us that 2 moles of CuCl2 produces 1 mole of I2 and 4 moles of KI produce 1 mole of I2.Therefore,4 moles of CuCl2 will produce (1/2) x 4 = 2 moles of I2 and 4 moles of KI will produce 4/4 = 1 mole of I2.So, the limiting reagent is KI as it produces only 1 mole of I2 which is less than the 2 moles of I2 produced by 4 moles of CuCl2.

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The answer is B hydro sphere

Answer:

Light gates

Explanation:

Light gates are used because of their accuracy. They can be set to react very quickly when the beam is broken which eliminates human reaction time errors.

The atomic number of an element represents the number of protons in an atom of that element. Since the isotope given is Mn-59, the atomic number of manganese (Mn) remains the same, which is 25.

If an atom of Mn-59 has a charge of +5, it means that it has lost 5 electrons. The number of protons in an atom is equal to its atomic number, and the number of electrons is equal to the number of protons in a neutral atom. Therefore, if the atom has lost 5 electrons, the number of protons remains the same, which is 25.

So, an atom of Mn-59 with a charge of +5 has 25 protons.

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The final temperature of the gas is approximately 40.96 Kelvin.

To determine the final temperature of the gas, we can use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.

First, let's convert the given temperatures to Kelvin. We have:

Initial temperature: -125 degrees Celsius = 148 K (approximate)

Final temperature: Unknown

The initial conditions of the gas are as follows:

Initial pressure (P1) = 1.25 atm

Initial volume (V1) = 1250 mL = 1.25 L (since 1 L = 1000 mL)

Initial temperature (T1) = 148 K

The final conditions of the gas are as follows:

Final pressure (P2) = 50.0 atm

Final volume (V2) = 325 mL = 0.325 L

Final temperature (T2) = Unknown

Using the ideal gas law, we can set up the following equation:

(P1 * V1) / T1 = (P2 * V2) / T2

Substituting the known values:

(1.25 atm * 1.25 L) / 148 K = (50.0 atm * 0.325 L) / T2

Simplifying the equation:

T2 = (50.0 atm * 0.325 L * 148 K) / (1.25 atm * 1.25 L)

T2 = 40.96 K

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