a sample of gas occupying 350. ml at 25.0 °c is cooled to –25.0 °c. what volume will it occupy if the pressure remains constant?

The chemical formula for aluminum oxide based on ionic bonding from valence electrons is Al₂O₃.

The chemical formula of a compound is a symbolic representation of its chemical composition.

Chemical formulae gives information about the elements that constitute the molecules of a compound and also about the ratio in which the atoms of these elements combine to form such molecules.

In this compound, aluminum (Al) donates three electrons to oxygen (O), resulting in the formation of Al³⁺ cations and O²⁻ anions. The ionic bond is formed between these oppositely charged ions, resulting in the formula Al₂O₃.

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Answer:

Please find how these data prove the law of multiple proportions below

Explanation:

The law of multiple proportions was proposed by an English chemist called John Dalton. The law states that when two elements combine and to form more than one compound. The weights/masses of the second element in the two compounds, which combines with a fixed ratio of the first element, is in a simple whole number ratio.

In this question, Nitrogen is said to combine with oxygen to give three different compounds as follows:

A) laughing gas containing 63.65% nitrogen i.e. 0.6365g

This means that the mass of oxygen will be (1-0.6365) = 0.3635g

B) colorless gas containing 46.68% nitrogen i.e. 0.4668g

This means that the mass of oxygen will be 0.5332g

C) brown toxic gas containing 30.45% nitrogen i.e. 0.3045g

This means that the mass of oxygen will be 0.6955g

The ratios of oxygen in the three compounds is therefore:

0.3635: 0.5332: 0.6955

Divide this ratio by the smallest number (0.3635)

0.3635/0.3635 = 1

0.5332/0.3635 = 1.467

0.6955/0.3635 = 1.913

Multiply this ratio by 2, we have:

2: 2.9 : 3.8

Hence, the simple whole number ratio is 2:3:4.

This proves the law of multiple proportions that oxygen is in simple whole number ratio in the three different compounds.

The volume of 3.5 mol of an ideal gas at a pressure of 3 atm and at temperature of 0°C is 26.227 L

The volume of the ideal gas can be solved using the ideal gas equation of state:

PV=nRT

Where

p is the gas pressure

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the ideal gas of this problem:

n = 3.5 mol (number of moles)

p = 3 atmospheres (pressure)

T = 0°C= 0+273°K =273 °K

R= the gas constant = 0.082Latm/mol °K

Solving for V gives the volume of the gas.

V= nRT

      P

V = 3.5 mol x 0.082Latm/mol °K x 273 °K

                              3 atm

V =  26.227 L

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1-methylcyclohexene is expected to be formed in greater amounts because of it's more thermodynamic stability than 3-methylcyclohexene.

Methylcyclohexane is a colorless liquid with a faint, benzene-like odor that is used as a solvent and to manufacture organic chemicals. Flash point of Methylcyclohexane is 25 °F  and density is 0.811 g/mL at 20 °C. 1-Methylcyclohexanol falls in a tertiary alcohol category.

Cyclohexene is a hydrocarbon with the formula of C₆H₁₀. This cycloalkene is a colorless liquid but with a sharp smell and is an intermediate in various industrial processes. Cyclohexene is not very stable for long term storage with exposure to light and air as it forms peroxides.

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Answer:

i think it is b im not sure

Explanation:

Best describes a mole is it contains 6.02×10²³ particles of a given substance

Mole is the amount of substance that contain the same number of elementary entities and according to the Avogadro's law number of elementary entities in the substance is 6.02×10²³ and these elementary entities could be atoms, ions, molecules etc and we use the mole to express the amount of substances and one mole of any substance is the equal to its atomic mass and molecular mass which is expressed in gram and the number of particles present in one mole of any substance is 6.02×10²³

Therefore the statement which is correct for mole is  it contains 6.02×10²³ particles of a given substance

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NH3 is the most nucleophilic molecule among the options, while BH3 is the least nucleophilic molecule. HC≡CNa and CH3CH2ONa are also strong nucleophiles due to the presence of the metal ion, while CH3CH2OH has some nucleophilic character but is less nucleophilic than the other options.

Nucleophilicity refers to the ability of a molecule to donate a pair of electrons to form a new covalent bond. The most nucleophilic molecule among the options is NH3, which has a lone pair of electrons on the nitrogen atom that can be easily donated to a molecule in need of electrons. NH3 is often used in organic synthesis as a nucleophile. On the other hand, BH3 is the least nucleophilic molecule among the options due to its lack of a lone pair of electrons. This makes it difficult for BH3 to donate electrons to form a new covalent bond.
HC≡CNa and CH3CH2ONa are both organometallic compounds that have strong nucleophilic properties due to the presence of the metal ion. These compounds have negatively charged carbon atoms that can easily donate a pair of electrons to form a new covalent bond. Finally, CH3CH2OH is a polar molecule that has some nucleophilic character, but it is less nucleophilic than NH3, HC≡CNa, and CH3CH2ONa.
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The properties of the given element, Pb, is as follows:

The periodic table is an arrangement of the elements in increasing order of atomic number.

The atoms of elements are composed of three sub-atomic particles;

The element Lead, Pb,  is a metallic element found in the periodic table and has an atomic number of 82 and an average atomic mass of 207.2

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Answer: sorry

Explanation:

j

Answer:

Explanation:

Na₂S₂O₃ + 4Cl₂ + 5H₂O → 2NaHSO₄ + 8HCl.

                4 moles                               8 moles

4 moles of Cl₂ forms 8 moles of HCl

.25 moles of Cl₂ forms 8 x .25 / 4 moles of HCl

HCl formed = .50 moles .

E is the answer .

The chemical formula for an ionic compound represents the ratio of the combined ions present in a sample.

A sample of an ionic compound doesn't represent a multiple of distinct molecules, like a sample of a covalent compound, where the chemical formula does represent the number of atoms in a single, differentiated molecule. Ionic compounds form crystal lattices where each positively charged cation is surrounded by negatively charged anions and vice versa. Thus, the chemical formula of an ionic compound merely describes the ratio of cations and anions present in the crystal lattice.
The total number of ions in the lattice can, on the other hand, be calculated using the mass of the sample and Avogadro's number.

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a) The hydroxide ion concentration is 10 M

b) The number of moles of the hydrogen ions is 1 * 10^- 13 moles

c) The pH of the solution is 4.

We know that the pH of the solution has to do with the amount of the hydrogen ions that we have in a solution. Looking at the fact that the number of the hydrogen or the hydroxide ions that is in the solution is the basis that we can use to decide whether the solution can be said to be acidic or not.

a) If the pH has been given for the solution as 13 then

Hydrogen ion concentration = Antilog (-13) = 1 * 10^-13 M

It then follows that; \([OH^-] [H^+] = 1 * 10^-14\)

Then \(OH^-\) = 1 * 10^-14/1 * 10^-13 M

= 10 M

The number of moles per liter of the hydrogen ions would be;

Concentration * volume

= 1 * 10^-13 M * 1 L

= 1 * 10^-13 moles

If the hydrogen ion concentration is  1.0 × 10^–4 then the pH of the solution = - log( 1.0 × 10^–4)

= 4

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Answer:

Use Table B in your Student Guide to answer the questions about ion concentrations.

A solution with a pH = 13 has approximately how many moles of OH– ions per liter?  ⇒ 0.1

How many moles of H+ would this same solution have per liter?

⇒ 0.0000000000001

(Use the decimal form of your answer.)

A different solution with an H+ concentration of 1.0 × 10–4 would have a pH = 4.

Explanation:

he is right on the last question but not the rest

14.4 g of carbon are required. Since the coefficients of CH4 and CO2 are both 1, every mole of CH4 that is consumed results in the production of one mole of CO2.

It indicates that a mole of carbon atoms weighs 12 grammes and a mole of hydrogen atoms weighs one gramme (nearly exactly) (again, almost exactly). A mole of methane should weigh 16 grammes as it is made up of 1 mole of carbon and 4 moles of hydrogens.

1 mol C divided by 1 mol CH4 yields 1.2 moles of carbon.

1 mol C divided by 12 g C results in 14.4 grammes of C.

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The mass of NaCl that reacted with F2 gas is approximately 202 grams.

To determine the mass of NaCl that reacted with F2 gas, we can use the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. In this case, we are given the volume of F2 gas (15.0 liters), the temperature (280 K), and the pressure (1.50 atm).

First, we need to convert the volume of F2 gas to moles using the ideal gas law equation. Rearranging the equation to solve for moles, we have n = PV / RT. Substituting the given values, we get

n = \((1.50 atm * 15.0 L) / (0.0821 atm L/mol K * 280 K)\).

Calculating this, we find that the number of moles of \(F_2\) gas is approximately 0.804 moles.

From the balanced chemical equation, we can see that 1 mole of\(F_2\) gas reacts with 2 moles of NaCl. Therefore, the number of moles of NaCl that reacted with F2 gas is half the number of moles of \(F_2\) gas, which is 0.402 moles.

Finally, we can calculate the mass of NaCl using its molar mass. The molar mass of NaCl is 58.44 g/mol. Multiplying the number of moles (0.402 moles) by the molar mass, we find that the mass of NaCl that reacted with \(F_2\) gas is approximately 202 grams.

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The binding energy of a nucleus refers to the minimum energy required to separate the nucleus into its constituent nucleons. The binding energy per nucleon (BE/A) is a more useful quantity than the absolute binding energy (BE) since it takes into account the number of nucleons present.

The more tightly bound a nucleus is, the higher its binding energy per nucleon. The equation that determines the binding energy is given by the formula, E=Δmc² where E is the binding energy, Δm is the mass defect, and c is the speed of light. The mass defect is the difference between the actual mass of a nucleus and the sum of the masses of its individual protons and neutrons. The mass of antimony-121 is the sum of the masses of its constituent nucleons, given by: Mass of antimony-121 = (71 x 1.00783 u) + (50 x 1.00867 u) = 120.90380 u The actual mass of antimony-121 is 120.90380 u. Using the mass of each nucleon and the actual mass of antimony-121, the mass defect of the nucleus can be determined as follows: Mass defect (Δm) = [71(1.00783 u) + 50(1.00867 u)] - 120.90380 u= 0.1471 u The binding energy can then be calculated using the formula: E = Δmc²= (0.1471 u)(1.66054 x 10^-27 kg/u)(2.99792 x 10^8 m/s)^2= 2.539 x 10^-10 J/mol To convert this to kilojoules per mole, we can divide by 1000:2.539 x 10^-10 J/mol = 2.539 x 10^-13 kJ/mol Therefore, the binding energy of antimony-121 is 2.539 x 10^-13 kJ/mol.

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When current is allowed to flow, the species that gets oxidized depends on the specific conditions of the system. However, based on the given options, the likely species to be oxidized would be A) Cr₂O₇²⁻.

When current flows in a system, oxidation and reduction reactions occur simultaneously at different electrode surfaces. The species that gets oxidized is the one that loses electrons. In the given options, Cr₂O₇²⁻ and MnO⁴ are both polyatomic ions with high positive oxidation states, while Cr³⁺ and Mn²⁺ have lower positive oxidation states. H³⁺ refers to a hydrogen ion, which is not a likely candidate for oxidation in this context.

In the case of Cr₂O₇²⁻, it has a higher positive oxidation state compared to Cr³⁺. Therefore, it is more likely to undergo oxidation and lose electrons when current is allowed to flow. The half-reaction for the oxidation of Cr₂O₇²⁻ to Cr³⁺ can be represented as follows:

Cr₂O₇²⁻ (aq) → 2Cr³⁺ (aq) + 3e⁻

This reaction involves the reduction of another species, which gains the electrons released during the oxidation of Cr₂O₇²⁻. It's important to note that the actual species being oxidized or reduced can vary depending on the specific conditions of the system, such as pH and the presence of other reactants.

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Answer:

I think the answer could be 13 i hope this helps

Answer:

The reaction absorbs energy ( + or exothermic)

Explanation:

When the temperature of a thermometer increases during a chemical reaction, then the reaction absorbs energy (+ or endothermic). Therefore, the correct option is B.

A rise in the temperature of a thermometer during a chemical reaction is a sign that the system is absorbing energy. This implies that the reaction is endothermic, meaning that energy must be supplied for it to proceed. Generally, endothermic reactions take heat from the environment and raise the temperature. Chemical bonds are broken and the process is accelerated by the absorbed energy.

Therefore, the correct option is B.

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You can fill in the table for other elements and their respective isotopes by determining the appropriate number of protons, neutrons, and electrons based on the given isotope mass number and atomic number.

To accurately fill in the table with the correct number of subatomic particles for the elements given the isotope mass number, we need to consider the composition of atoms and their respective subatomic particles. Atoms are composed of protons, neutrons, and electrons.

The number of protons in an atom is equivalent to its atomic number, which uniquely identifies the element. The number of neutrons can be determined by subtracting the atomic number from the isotope mass number. Electrons in a neutral atom are equal to the number of protons.

Let's take an example using the isotope mass number:

Isotope: Carbon-14 (mass number = 14)

Element: Carbon (atomic number = 6)Based on the atomic number and isotope mass number, we can determine the number of subatomic particles as follows:

Protons: 6 (same as the atomic number)

Neutrons: 14 - 6 = 8

Electrons: 6 (same as the number of protons in a neutral atom)

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Answer:

The noble gases(neon, helium, argon)

Explanation:

In the ground state, noble gas atom has a completely filled valence electron shell. Space makes up the majority of an atom.

The smallest unit of matter that may be split without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. Electric forces, which link electrons towards the nucleus of atoms, cause them to be drawn to any positive charge.

Space makes up the majority of an atom. The remainder is made up of a cloud of negatively charged electrons around a positively charged nucleus made up of protons and neutrons. Compared to electrons, that are the smallest charged particles in nature, the nucleus is tiny and dense. In the ground state, noble gas atom has a completely filled valence electron shell.

Therefore, in the ground state, noble gas atom has a completely filled valence electron shell.

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How many pages is 5000 words? Double spaced, 5000 words is around 20 pages; single spaced about 10 pages. Now, if you're using an unconventional formatting or margins you could see different results, however, with standard word processor defaults and a 12 point Arial or Times New Roman font your output should be very similar. Examples of 5000 word count pages include college theses, dissertation research, or very comprehensive, in-depth blog posts.

Answer: 5000 words is 10 pages single spaced or 20 pages double spaced.

Pages by Word Count

Use our handy table to discover how many pages a given word count yields, single or double spaced, in Times New Roman or Arial 12 point font.

Word Count Pages (single spaced) Pages (double spaced) Font Size

250 WORDS ½ PAGE 1 PAGE 12 POINT

300 WORDS ⅔ PAGE 1⅓ PAGES 12 POINT

400 WORDS ⅘ PAGE 1⅗ PAGES 12 POINT

500 WORDS 1 PAGE 2 PAGES 12 POINT

600 WORDS 1⅓ PAGE 2⅔ PAGES 12 POINT

750 WORDS 1½ PAGES 3 PAGES 12 POINT

800 WORDS 1⅗ PAGES 3⅕ PAGES 12 POINT

1000 WORDS 2 PAGES 4 PAGES 12 POINT

1200 WORDS 2⅖ PAGES 4⅘ PAGES 12 POINT

1500 WORDS 3 PAGES 6 PAGES 12 POINT

2000 WORDS 4 PAGES 8 PAGES 12 POINT

2500 WORDS 5 PAGES 10 PAGES 12 POINT

3000 WORDS 6 PAGES 12 PAGES 12 POINT

3500 WORDS 7 PAGES 14 PAGES 12 POINT

4000 WORDS 8 PAGES 16 PAGES 12 POINT

5000 WORDS 10 PAGES 20 PAGES 12 POINT

6000 WORDS 12 PAGES 24 PAGES 12 POINT

7500 WORDS 15 PAGES 30 PAGES 12 POINT

8000 WORDS 16 PAGES 32 PAGES 12 POINT

10000 WORDS 20 PAGES 40 PAGES 12 POINT

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Answer: combination reaction

as calcium oxide and water combine it forms a single product, calcium hydroxide.

if you like my answer, please mark me brainliest !! thanks !! <3

The empirical formula of the product in question 5.79 can be determined by finding the ratio of the elements present.

Given that a 29.3 g sample of Ti reacts with O2 to form 48.9 g of product, we need to calculate the moles of Ti and O in the reaction. The molar mass of Ti is 47.87 g/mol, so the moles of Ti in the sample is:

moles of Ti = mass of Ti / molar mass of Ti

moles of Ti = 29.3 g / 47.87 g/mol = 0.612 mol

To find the moles of O, we can use the difference in mass between the sample and the product:

mass of O = mass of product - mass of Ti

mass of O = 48.9 g - 29.3 g = 19.6 g

The molar mass of O is 16.00 g/mol, so the moles of O in the product is:

moles of O = mass of O / molar mass of O

moles of O = 19.6 g / 16.00 g/mol = 1.225 mol

Now we can find the empirical formula by dividing the number of moles of each element by the smallest number of moles:

Empirical formula = Ti(0.612 mol) O(1.225 mol) = TiO2

Therefore, the empirical formula of the product is TiO2.

The given information provides the masses of titanium (Ti) and oxygen (O) in the reaction. By converting these masses to moles and comparing their ratios, we determine the empirical formula of the product to be TiO2. This means that the product contains one titanium atom and two oxygen atoms per formula unit.

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At a temperature of 100 °C, the specific heat at constant volume of water vapor is 1.46 kJ/(kgK), and the molar mass of water is approximately 18 g/mol. How many degrees of freedom related to rotation or vibration are fully available to water molecules at this temperature? There are four vibrational degrees of freedom and two rotational degrees of freedom available to a water molecule.

Here's why: Water molecules are non-linear, which means they have 3N-6 vibrational degrees of freedom and 3 rotational degrees of freedom. So, let's calculate the number of degrees of freedom of a water molecule by using the following formula:

Degrees of freedom = 3N - 6, where N is the number of atoms in the molecule. In the case of water, there are three atoms (two hydrogens and one oxygen), so we have:

N = 3, Degrees of freedom = 3N - 6= 3(3) - 6= 3

So, there are three vibrational degrees of freedom in a water molecule. Now, let's calculate the number of rotational degrees of freedom by using the following formula:

Degrees of freedom = 3, if the molecule is linear, Degrees of freedom = 2, if the molecule is non-linear. In the case of water, the molecule is non-linear, so we have:

Degrees of freedom = 2

So, there are two rotational degrees of freedom in a water molecule. Therefore, there are four vibrational or rotational degrees of freedom fully accessible to water molecules at this temperature.

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The first feldspars to form are rich in the mineral calcium.

To recap, the initial feldspars that form are calcium-rich.

Any of a group of minerals called aluminosilicates that contain calcium, sodium, or potassium are called feldspar. More than half of the Earth's crust is made up of feldspars, and a sizable portion of the literature on mineralogy is devoted to them.

Calcium-rich Plagioclase is the first feldspar to form when cooling magma cools, but as crystallization proceeds, plagioclase gradually gains sodium content.

Feldspar's structure is built on aluminosilicate tetrahedra, each of which contains an aluminum or silicon ion and four oxygen ions around it.

Each oxygen ion generates a three-dimensional network that each tetrahedron adjacent shares. Here, we can see the crankshaft chains, which are lengthy chains of aluminosilicate tetrahedra.

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The dosage of 26mg can be prepared using approximately 1.625 mL of the 40mg in 2.5 mL solution.

The dosage of 22mg can be prepared using approximately 1.222 mL of the 36mg per 2 mL strength solution.

To calculate the dosage using ratio and proportion, we can set up a proportion based on the strength of the solution.

40mg in 2.5 mL solution will be used to prepare a 26mg dosage.

Let X represent the mL of the solution needed to prepare the 26mg dosage.

We can set up the proportion as follows:

40mg/2.5mL = 26mg/X mL

Cross-multiplying and solving for X, we have:

40mg * X mL = 2.5mL * 26mg

40X = 65

X = 65/40

X ≈ 1.625 mL

For the second question:

36mg per 2 mL strength solution is used to prepare 22mg.

Let Y represent the mL of the solution needed to prepare the 22mg dosage.

We can set up the proportion as follows:

36mg/2mL = 22mg/Y mL

Cross-multiplying and solving for Y, we have:

36mg * Y mL = 2mL * 22mg

36Y = 44

Y = 44/36

Y ≈ 1.222 mL

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Answer:Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Explanation:

Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​