A sample of steel is added to a 100-mL graduated cylinder with 45.0 mL of water. Ifthe resulting water level is 55.5 mL, what is the volume of the steel
Answers
This problem is providing the total volume of a graduated cylinder, 100 mL with 45.0 mL of water, but when adding a piece of steel, the volume rises to 55.5 mL so the volume of the metal is required and found to be 10.5 mL according to:
Displaced volume:In chemistry, density experiments require the use of a well-measured volume of water in order to add the density-unknown object so the difference in the volume lead to the that of the object.
In such a way, since 45.0 mL of water is risen to 55.5 mL upon the addition of the steel, one can calculate the difference in order to get the volume of steel as 55.5 mL comprises both water and the object:
\(V^{steel}=55.5mL-45.0 mL\\\\V^{steel}=10.5 mL\)
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Related Questions
When naming an ionic compound what must always
come first the anion or the cation? (Metal or
nonmetal)
Answers
Answer:
Cation / metal
Explanation:
When we named ionic compound we always write cation first. Let's take an example.
Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion. Both atoms are bonded together electrostatic attraction occur between anion and cations and ionic compound is formed. When we naming it we write " sodium " first which indicate sodium cation ( Na⁺) while anion which is Cl⁻ is always written at the end. When we naming ionic compound we ended the name of anion with "ide". Sodium indicate metal while chloride ion indicate non metal. it means metal comes first while naming ionic compound.
At a fixed pressure, if the temperature is doubled, the volume of a gas will be
Answers
Answer:
Doubled.
Explanation:
The relationship between the temperature and the volume of a gas at a constant pressure can be described using Charles' law:
V₁*T₂ = V₂*T₁That means that the temperature and the volume of a gas are directly proportional: The higher the temperature, the higher the pressure. If one of those factors is increased twofold, the other one will be increased twofold as well.
Given three (3.00) moles of gold (Au), how many grams do you have?
a. 66 g
b. 197 g
C. 591 g
d. 6.02 x 1023 g
Answers
aluminum reacts with excess hydrochloric acid to form aqueous aluminum chloride and of hydrogen gas over water at and . how many grams of aluminum reacted? the partial pressure of water at is . round your answer to significant figures.
Answers
Answer:0.0324
g Al
Explanation:We're asked to find the number of grams of
Al
that reacted, given some
H
2
(
g
)
product characteristics.
Let's first write the chemical equation for this reaction:
2
Al
(
s
)
+
6
HCl
(
a
q
)
→
2
AlCl
3
(
a
q
)
+
3
H
2
(
g
)
The total pressure of the gaseous system is given as
751
mm Hg
, and the partial pressure of water vapor is
26.8
mm Hg
at
27
o
C
. The pressure of hydrogen gas is thus
P
total
=
P
H
2
O
+
P
H
2
P
H
2
=
751
mm Hg
−
26.8
mm Hg
=
724
mm Hg
This pressure in atmospheres is
724
mm Hg
(
1
l
atm
760
mm Hg
)
=
0.953
atm
We'll now use the ideal gas equation to find the number of moles of
H
2
formed:
(
T
=
27
o
C
+
273
=
300
K
)
n
=
P
V
R
T
=
(
0.953
atm
)
(
0.0465
L
)
(
0.082057
L
∙
atm
mol
∙
K
)
(
300
K
)
=
0.00180
mol H
2
(volume converted to liters here)
Using the coefficients of the chemical equation, we'll now find the relative number of moles of
Al
that react:
0.00180
mol H
2
(
2
l
mol Al
3
mol H
2
)
=
0.00120
mol Al
Lastly, we'll use the molar mass of aluminum (
26.98
g/mol
) to find the number of grams that reacted:
0.00120
mol Al
(
26.98
l
g Al
1
mol Al
)
=
0.0324
g Al
Thus,
0.0324
grams of aluminum
reacted.
can someone please give me a very simple definition of nuclear fusion make it as simple as possible
Answers
Answer: Nuclear fusion is a nuclear reaction where atomic nuclei of a low atomic number fuse to form a heavier nucleus releasing energy.
Explanation:
What is the volume of 0.200 mol of an ideal gas at 200. kpa and 400. k? use p v equals n r t. and r equals 8.314 startfraction l times kilopascals over moles time k endfraction.. 0.83 l 3.33 l 5.60 l 20.8 l
Answers
3.33 liter is the volume of 0.200 mole of an ideal gas at 200 kPa pressure and 400 K temperature.
What is ideal gas equation?Ideal gas equation for gas will be written as:
PV = nRT, where
P = pressure of gas = 200 kPa
n = moles of gas = 0.2 mole
T = temperature of gas = 400K
R = universal gas constant = 8.314 L.Pa/K.mole
V = to find?
On putting all these values on the above equation, we calculate for V as:
V = (0.2×8.314×400) / 200 = 3.325 = 3.33 L
Hence, option (2) is correct i.e. 3.33 L.
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11.0 L of hydrogen and 5.52 L of oxygen are exploded together in a reaction tube. What volume of water vapor was formed, at STP?
Answers
Answer:
11.0 L
Explanation:
The equation for this reaction is given as;
2H2 + O2 --> 2H2O
2 mol of H2 reacts with 1 mol of O2 to form 2 mol of H2O
At STP;
1 mol = 22.4 L
This means;
44.8 L of H2 reacts with 22.4 L of O2 to form 44.8 L of H2O
In this reaction, the limiting reactant is H2 as O2 is in excess.
The relationship between H2 and H2O;
44.8 L = 44.8 L
11.0 L would produce x
Solving for x;
x = 11 * 44.8 / 44.8
x = 11.0 L
Which statements describe band theory? Check
all that apply.
Electrons all have approximately the same
energy.
Electrons move among orbitals of different
energies.
Electrons move freely among atoms
(delocalized)
Answers
Answer:
B and C is corrent i got it right on edge
Explanation:
Answer:
Electrons move among orbitals of different energies.
Electrons move freely among atoms (delocalized).
Explanation:
70 g of a solid solute is added to 50 g of water at 20 °c, and it all dissolves. when additional solute is added, it does not dissolve. identify the solute.
Answers
70 g of a solid solute is added to 50 g of water at 20 °c, and it all dissolves. when additional solute is added, it does not dissolve. KI is the solute.
What is solute ?
A solute is a substance that has dissolved in a solution. Molecules of the solvent often outnumber those of the solute in a fluid solution. In our daily lives, salt and water are two of the most prevalent solutes. Salt becomes a solute when it is dissolved in water.
What is solvent?
Solvents are employed to dissolve the substances that serve as the formulation's solutes. The components of these solutes can be solids, liquids, or gases. The use of a suitable solvent in conjunction with the solute is required to create a solution.
given: 70g of solute is added to 50g of water at 20degree C
solution: at 20degree C,
since graph is for 100g of water
multiple by 2
2 x 50g of water=100g of water
similarly 2 x 70g of solute= 140g of solute
at 20degree C, The solute KI falls at 140g
Therefore , KI is the solute
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Hydrogen fluoride reacts with ammonia in an acid-base reaction:
HF (aq) + NH3 (aq) -->
a. Determine the products made by completing the reaction above.
b. Identify and label one of the conjugate acid-base pairs.
Please I will give brainliest I’m stuck
Answers
Answer: a) \(HF(aq)+NH_3(aq)\rightarrow NH_4^+(aq)+F^-(aq)\)
b) \(NH_4^+\): conjugate acid of \(NH_3\)
\(F^-\) : conjugate base of \(HF\)
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given reaction:
\(HF(aq)+NH_3(aq)\rightarrow NH_4^+(aq)+F^-(aq)\)
Here \(HF\) is loosing a proton, thus it is considered as an acid and after losing a proton, it forms \(F^-\) which is a conjugate base.
Similarly ,\(NH_3\) is gaining a proton, thus it is considered as an base and after gaining a proton, it forms \(NH_4^+\) which is a conjugate acid.
What are the intermolecular forces present in acetone?.
Answers
Acetone has a dipole, so dipole-dipole forces will be present. Water has a dipole and can also hydrogen bond, as can isobutyl alcohol.
You complete a titration and find that you need 2.5 mL of a 0.1M NaOH to neutralize 250 mL of
the river water.
How many moles of NaOH did you use to neutralize the river water?
Answers
Answer:
0.00025 mole
Explanation:
The number of moles of a substance can be mathematically derived from the following formula
1. mass of substance (in grams)/molar mass of substance (in grams/mole)
2. molarity of substance (in mol/dm3) x volume of substance (in dm3)
In this case, the molarity and volume of NaOH are provided, hence, the second formula will be applicable.
2.5 mL of NaOH was used = 0.0025 dm3
Number of mole of NaOH that was used to neutralize the river water:
= 0.1 x 0.0025 = 0.00025 mole
The number of mole of NaOH used to neutralize the river water is 0.00025 mole.
help me with this question please
Answers
Answer:
Noble gases b/c its melts quicly that why enjoy
The defendant was charged with setting fire to an abandoned building. which type of arson does this represent?
Answers
The defendant was charged with setting fire to an abandoned building is third degree type of Arson.
What is Arson?
The act of starting a fire or explosion with the intent to destroy tangible or intangible property is known as arson. The type of property, its worth, the defendant's intent, and whether the property was occupied all play a role in the penalty for arson. For crimes that include bodily harm or the potential for harm to human life, states normally impose the highest penalties. A person must intentionally start a fire on property or have the knowledge that their actions will result in the property being burned or destroyed in order to be charged with arson. A person's actions must be irresponsible in order for accidental fires to be declared arson.Learn more about the Arson with the help of the given link:
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A sample of a certain substance weighs 25 mg. One year later, the sample weighs 19.95 mg. What is the half-life of the substance, in years?
Answers
The substance's half-life is determined to be 1.46 years on average.
In this case, the sample of the substance weighs 25 mg initially and decreases to 19.95 mg after one year. To determine the half-life, we can use the equation,
\(Finalmass = Initial mass*(1/2)^{t/halflife}\), where the time elapsed is t. Rearranging the equation, we have,
\(\frac{19.95 }{25} = (\frac{1}{2})^{1 / half-life}\\\)
Taking the logarithm base 2 of both sides, we get:
log2(19.95 / 25) = (1 / half-life) * log2(1/2)
Solving for half-life, we find,
half-life ≈ (1 / log2(1/2)) * log2(19.95 / 25)
half-life ≈ (1 / log2(1/2)) * (-1)
half-life ≈ 1.46 years
Hence, the compound's half-life is 1.46 years.
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Identify one way Ultra Violet Rays can be harmful to humans? Thank you so much!
Answers
Answer
It can Blind humans
Explanation:
Calculate the final concentration of the solution when water is added to prepare each of the following solutions.
Answers
The final concentration of the solution, when water is added, would be 0.033 M.
To calculate the final concentration of a solution when water is added, we need to consider the initial concentration and the volume before dilution, as well as the volume of water added. The final concentration is determined by the ratio of the initial solute concentration to the total volume of the solution after dilution.
The formula to calculate the final concentration (Cf) is:
Cf = (Ci * Vi) / (Vi + Vw)
Where:
Cf = Final concentration
Ci = Initial concentration
Vi = Initial volume
Vw = Volume of water added
Let's consider an example. Suppose we have a solution with an initial concentration of 0.1 M and an initial volume of 100 mL. If we add 200 mL of water to this solution, we can calculate the final concentration as follows:
Cf = (0.1 M * 100 mL) / (100 mL + 200 mL)
Cf = (0.1 M * 100 mL) / 300 mL
Cf = 0.033 M
In summary, to calculate the final concentration of a solution when water is added, we use the formula Cf = (Ci * Vi) / (Vi + Vw), where Ci is the initial concentration, Vi is the initial volume, and Vw is the volume of water added. The final concentration is determined by the ratio of the initial solute concentration to the total volume of the solution after dilution.
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Gaseous chlorine, Cl2, was combined with 0.532g of Titanium, and 2.108 g of TixCly were collected. What is the empirical formula of titanium chloride?
Answers
Answer:
TiCl₄
Explanation:
From the law of conservation of mass, the mass of the reactants must equal the mass of the products. In other words:
\(\displaystyle \text{m Cl$_2$} + \text{ m Ti} = \text{ m Ti$_x$Cl$_y$}\)
Find the mass of chlorine gas reacted:
\(\displaystyle \begin{aligned} \text{ m Cl$_2$} + (0.532 \text{ g}) & = (2.108 \text{ g)} \\ \\ \text{m Cl$_2$} & = 1.576 \text{ g} \end{aligned}\)
Find the number of moles of each reactant using their respective molecular weights:
\(\displaystyle 1.576 \text{ g Cl$_2$} \cdot \frac{1 \text{ mol Cl$_2$}}{70.90\text{ g Cl$_2$}} \cdot \frac{2\text{ mol Cl}}{1\text{ mol Cl$_2$}} = 0.04446\text{ mol Cl}\)
And:
\(\displaystyle 0.532\text{ Ti} \cdot \frac{1\text{ mol Ti}}{47.87\text{ g Ti}} = 0.0111\text{ mol Ti}\)
To find the empirical formula, all values by the smallest value:
\(\displaystyle \begin{aligned} \frac{0.0111\text{ mol Ti}}{0.0111} & = \frac{0.04446\text{ mol Cl}}{0.0111} \\ \\ 1\text{ mol Ti} & \approx 4\text{ mol Cl}\end{aligned}\)
Hence, there are four moles of chlorine for every one mole of titanium.
In conclusion, our empirical formula is TiCl₄.
7. What color would a solution with pH 5.5 be when mixed with phenolphthalein indicator
Answers
C is produced as a result of combustion of organic matter with insufficient oxygen. a. Methane WA MTU M b. Benzene TO Ci Carbon dioxide Od. Carbon monoxide Oe. Mercury Om du
Answers
The correct answer is Carbon Monoxide (CO). When organic matter is burned with insufficient oxygen, it leads to incomplete combustion and the production of various gases, including carbon monoxide. Carbon monoxide is a colorless, odorless gas that is extremely poisonous and can be fatal in high concentrations.Carbon dioxide (CO2) is a product of complete combustion and is not produced when there is insufficient oxygen.Benzene is a hydrocarbon compound composed of six carbon atoms and six hydrogen atoms, and it is not produced from combustion.Methane (CH4) is a hydrocarbon compound composed of one carbon atom and four hydrogen atoms, and it is not produced from combustion.Mercury is a metallic element and is not related to combustion.
for the following endothermic reversible reaction at equilibrium, how will removing no(g) affect it? 4no(g) 6h2o(g) rightwards harpoon over leftwards harpoon with blank on top 4nh3(g) 5o2(g)
Answers
Removing NO(g) from the equilibrium of the endothermic reversible reaction will shift the equilibrium to the left, resulting in an increase in the production of NO(g) and H₂O(g) while consuming NH₃(g) and O₂(g).
For the endothermic reversible reaction at equilibrium, removing NO(g) will affect it as follows:
Reaction: 4NO(g) + 6H₂O(g) ⇌ 4NH₃(g) + 5O₂(g)
Since this is an endothermic reaction, it means that the reaction absorbs heat from its surroundings when it proceeds in the forward direction (left to right). At equilibrium, the rates of the forward and reverse reactions are equal.
When you remove NO(g) from the system, you are essentially decreasing the concentration of NO(g) in the reaction mixture. According to Le Chatelier's principle, the system will counteract this change by shifting the position of equilibrium to restore the balance.
In this case, the equilibrium will shift to the left to replenish the NO(g) that was removed. This means the reaction will proceed more in the reverse direction (right to left), producing more NO(g) and H₂O(g) while consuming NH₃(g) and O₂(g).
In summary, removing NO(g) from the endothermic reversible reaction at equilibrium will cause the reaction to shift to the left, producing more NO(g) and H₂O(g) while consuming NH₃(g) and O₂(g).
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Consider the chemical equations shown here.
2H2(g) + O2(g) → 2H2O(g) AH, = -483.6 kJ = 2 =-241.8 kJ/mol
302(9) ► 203(9) AH2 = 284.6 kJ = 2 = 142.3 kJ/mol
What is the overall enthalpy of reaction for the equation shown below?
3H2(g) + O2(g) → 3H20 (g)
____kJ
Answers
Answer:
-867.7kJ
Explanation:
3H2(g)+O3(g)—>3H2O(g)=
-867.7kJ
Can you think of something you do or a hobby you have that is physics
related? Explain your thinking as to how what you do is Physics related.
Answers
You can take physics as a hobby and also it is great that you like both maths and physics as well and also want to be an computer science engineer because physics and math
what volume of 0.100 m na3po4 is required to precipitate
Answers
Therefore, 562.5 mL (or 0.5625 L) of the 0.100 M Na₃PO₄ solution is required to precipitate all the lead(II) ions from 150.0 mL of 0.250 M Pb(NO₃)₂.
To determine the volume of 0.100 M Na₃PO₄ needed to precipitate all the lead(II) ions from 150.0 mL of 0.250 M Pb(NO₃)₂, we first need to determine the stoichiometry of the reaction between Na₃PO₄ and Pb(NO₃)₂ and then use the concept of stoichiometry to calculate the volume.
The balanced chemical equation for the reaction between Na₃PO₄ and Pb(NO₃)₂ is:
3Na₃PO₄ + 2Pb(NO₃)₂ → Pb₃(PO₄)₂ + 6NaNO₃
From the equation, we can see that the ratio of Na₃PO₄ to Pb(NO₃)₂ is 3 ratio 2.
To find the number of moles of Pb(NO₃)₂ present in the given volume (150.0 mL), we use the formula:
moles = concentration × volume
moles of Pb(NO₃)₂ = 0.250 M × 0.150 L = 0.0375 moles
According to the stoichiometry, 3 moles of Na₃PO₄ are needed to react with 2 moles of Pb(NO₃)₂.
Therefore, the moles of Na₃PO₄ required would be:
moles of Na₃PO₄ = (3/2) × moles of Pb(NO₃)₂ = (3/2) × 0.0375 = 0.05625 moles
Now, we can use the formula for moles to determine the volume of the 0.100 M Na₃PO₄ solution required.
volume = moles / concentration
volume = 0.05625 moles / 0.100 M = 0.5625 L = 562.5 mL
Therefore, 562.5 mL (or 0.5625 L) of the 0.100 M Na₃PO₄ solution is required to precipitate all the lead(II) ions from 150.0 mL of 0.250 M
Pb(NO₃)₂.
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Pls help
Three gases are added to a single tan of the same size. The first gas is currently at 303.9kPa, the second at 1900tor and the third at 132.3PSI. To one
decimal place, what are the percentages for each gas of the total pressure in the tank?
Answers
Answer:
See Explanation
Explanation:
We must first convert the gas pressures to a common unit. I choose to convert all pressures to kiloPascal.
Since;
1 kilopascal = 7.501 torrs
X. =1900tor
X= 1900 × 1/7.501
X= 253.3 Kpa
Since 1 PSI =6.895 kilopascals
132.3PSI = 132.3 × 6.895/1
= 912.2 Kpa
Total pressure = 303.9kPa + 912.2 Kpa + 253.3 Kpa = 1468.8 kPa
For first gas;
303.9/1468.8 × 100 = 20.7%
For second gas;
912.2/1468.8 × 100 = 62.1%
For the third gas;
253.3/ 1468.8 × 100 = 17.2%
List six elements with only 1 electron in an s orbital
Answers
Answer:
\(Lithium=Li2s^1\\Sodium=Na3s^1\\Potassium=K4s^1\\Rubidium=Rb5s^1\\Cesium=Cs6s^1\\Francium=Fr7s^1\)
Explanation:
When it comes to electron configuration and orbitals, it's important to first identify what exactly we are trying to identify. Below is a given example:
\(He1s^2\)
\(He=element\)
\(1=level\)
\(s=orbital\)
\((exponent)^2=electrons\)
Looking at the periodic table, identify the alkali metal family on the periodic table, or group one elements:
\(Lithium=Li2s^1\\Sodium=Na3s^1\\Potassium=K4s^1\\Rubidium=Rb5s^1\\Cesium=Cs6s^1\\Francium=Fr7s^1\)
Notice how each configuration has an exponent of \(1\), representative of a single electron in their s-orbital.
A bicyclist decelerates with a force of -350 N. If the cyclist and bicycle have a total mass of 100 kg, what is the acceleration?
Answers
Explanation: students
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A bicyclist slow with a force of 3.5 x 10^2 N. if the bicyclist and bicycle have a total mass of 1.0 x 10^2 kg, what is the acceleration
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Answer:
Acceleration = 3.5 [m/s^2]
Explanation:
We can solve this problem using Newton's second law, which states that the sum of forces on a body is equal to the product of the mass by the acceleration
F = 350 [N]
m = 100 [kg]
Using Newton's second law we have:
F = m*a
where:
F = force [N]
a = acceleration or desacceleration [m/s^2]
therefore:
a = 350/100
a = 3.5 [m/s^2]
If one mole of carbon atoms weighs 12 grams, What is the mass ( in grams ) of 1 atom of carbon ?
Answers
Answer:
1.9992x10^-23
Explanation:
The thing is 6.022*10^23 atoms of carbon is 12g. so 1 atom of carbon will contain:
12/6.022*10^23 = 1.9992x10^-23
hope its clear and helps...
A large plate of thickness L = 4cm with constant thermal conductivity K =1.5W/m/k and without hear generation. Faces A and B are at temperature 120°C and 300°C respectively. Assuming that the direction for y and z directions are so large that the temperature gradients are significant in the x-direction only. Calculate the steady state temperature distribution in the plate using control volume approach. Assume the plate is subdivided into five control volumes. The governing equation is
d/dx(K dT/dx) = 0
Answers
The steady state temperature distribution in the plate can be calculated using the control volume approach.
1. Divide the plate into five control volumes, labeled as 1, 2, 3, 4, and 5, from left to right.
2. Apply the control volume approach to each control volume.
3. Consider the control volume 1. The equation for control volume 1 is:
d/dx(K dT1/dx) = 0
4. Integrate the equation with respect to x over the control volume 1:
∫(d/dx(K dT1/dx))dx = ∫0dx
5. Simplify the equation:
K dT1/dx = C1
6. Integrate the equation with respect to x:
∫(K dT1/dx)dx = ∫C1dx
7. Simplify the equation:
KT1 = C1x + C2
8. Repeat the same steps for the remaining control volumes, substituting the appropriate control volume number and constants (C) for each control volume.
9. Apply the boundary conditions. For face A, T1 = 120°C, and for face B, T5 = 300°C. Use these boundary conditions to determine the constants C1 and C2 for control volume 1 and C4 and C5 for control volume 5.
10. Finally, substitute the determined values of C1, C2, C4, and C5 into the equations for each control volume to obtain the steady state temperature distribution in the plate.
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Question 5(Multiple Choice Worth 4 points)
(06.03 MC)
The graph shows the changes in the phase of ice when it is heated.
Phase Change of Ice
C-
Temperature
(C)
B
A-
solid
liquid
25
gas
50 75 100
Time (min)
Which of the following temperatures describes the value of B?
O0 °C, because it is the melting point of ice.
O 100 °C, because it is the boiling point of water.
O Greater than 0 °C, because A represents the temperature at which ice melts.
O Greater than 100 °C, because A represents the temperature at which water evaporates
Answers
The temperatures that describes the value of B is A, 0 °C, because it is the melting point of ice.
What does the graph represent?The graph shows that the temperature of the ice is increasing as it is heated. The point at which the line changes from solid to liquid is the melting point of ice. This is the temperature at which the ice changes its phase from solid to liquid. The melting point of ice is 0 °C.
The other options are incorrect. The boiling point of water is 100 °C, and the temperature at which water evaporates is also 100 °C. The temperature at point A is greater than 0 °C, but it is not greater than 100 °C.
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