A set of electric trains are powered by a 9 V battery. What is the resistance of the trains if they draw 4.0 A of current?

Answer:

It is D

Explanation:

The explanation why the marble undergoes oscillatory motion should be option D.

An object should be classified as the motion oscillates related to an equilibrium position because of the restoring force or torque.  This motion should be significant to study various phenomena like electromagnetic waves, molecules. etc. In the case when the gravitational force should be exerted on the marble here the magnitude and the direction should be the same.

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Answer:

Explanation:

iphotosynthesis 2coal burning 3electric motor 4 electricity generator 5 waterturbines 6 solar bulb

We want to find the magnitude and direction of the ball's displacement. We will see that the magnitude is 1.76m and the direction is 70.74°

We define displacement as the difference between the final position and the initial position.

To define a position we first need to define a coordinate system, we will use east as the positive x-axis and north as the positive y-axis.

The ball starts at the point (0m, 0m).

First, it is displaced 3.34m to the north, so the new position is (0m, 3.34m).

Then 1.60m southeast, assuming that southeast means exactly 45° between east and south (positive x-axis and negative y-axis)

This implies that the ball moves:

So the new position is:

(0m + 1.13m, 3.34m - 1.13m) = (1.13m, 2.21m)

Finally, there is a displacement of 0.783m southwest, where southwest would be an angle of 225° measured counterclockwise from the positive x-axis, so the components of motion are:

0.783m*cos(225°) = -0,55m

0.783m*sin(225°) = -0.55m

So the final position of the ball is:

(1.13m - 0.55m , 2.21m -0.55m) = (0.58m, 1.66m)

So now we have the final position, because the initial position is (0m, 0m) the magnitude of the displacement will just be the magnitude of the final position, which is:

M = √( (0.58m)^2 + (1.66m)^2 ) = 1.76m

And the direction measured from the positive x-axis (east) is given by the Arctangent of the quotient between the y-component and the x-component, so the angle is:

A = Atg(1.66m/0.58m) = 70.74°

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Answer:

the period of oscillation of the given object is 0.14 s

Explanation:

Given;

mass of the object, m = 3 kg

extension of the spring, x = 0.085 m

The spring constant is calculated as follows;

\(F = mg = \frac{1}{2} ke^2\\\\2mg = ke^2\\\\k = \frac{2mg}{e^2} \\\\k = \frac{2\times 3 \times 9.8}{(0.085)^2} \\\\k = 8,138.41 \ N/m\)

The angular speed of a 4 kg object is calculated as follows;

\(\omega = \sqrt{\frac{k}{m} } \\\\\frac{2\pi }{T} = \sqrt{\frac{k}{m} } \\\\T= 2\pi \sqrt{\frac{m}{k} } \\\\T = 2\pi \sqrt{\frac{4}{8138.41} }\\\\T = 0.14 \ s\)

Therefore, the period of oscillation of the given object is 0.14 s

The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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( a) The acceleration of the box in the absence of friction is 8.49 m/s².

(b) The acceleration of the box in the presence of friction is 1.7 m/s².

(c) The speed of the box at the bottom of the incline is 18.44 m/s.

The acceleration of the box if no friction is present is calculated by applying Newton's second law of motion.

mg cosθ = ma

g cosθ = a

where;

The acceleration of the box in the absence of friction is calculated as;

a = ( 9.8 ) x ( cos 30 )

a = 8.49 m/s²

The acceleration of the box in the presence of friction is calculated as;

Ff = ma

where;

μmg cosθ = ma

μg cosθ = a

( 0.2 x 9.8 x cos 30 ) = a

1.7 m/s² = a

The speed of the box at the bottom of the incline is calculated as follows;

v² = u² + 2ah

where;

v² = 0 + 2ah

v = √ ( 2ah )

h = L sinθ

v = √ ( 2 x a x L sinθ )

v = √ ( 2 x 1.7 x 200 x sin 30 )

v = 18.44 m/s

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(a) The rock has a weight w according to

w = m g

where m is its mass and g = 9.80 m/s² is the magnitude of the acceleration due to gravity. So

w = (20.0 kg) (9.80 m/s²) = 196 N

(b) Charmander kicks the rock with an upward force (magnitude f ) that overcomes the weight of the rock, and the net force on it is 230 N. This means

f - w = 230 N

f - 196 N = 230 N

f = 426 N

(c) I think the question is supposed to say, "What is the acceleration of the rock," and not asking about Charmander's acceleration. By Newton's second law, the net force on the rock is equal to its mass times its acceleration:

230 N = (20.0 kg) a

a = (230 N) / (20.0 kg)

a = 11.5 m/s²

The temperature of air as measured by a thermometer that is not insulated from radiation or moisture is known as the dry-bulb temperature (DBT).

The actual thermodynamic temperature is DBT, which is typically thought of as the air temperature. It measures the heat content of the atmosphere and relates the mean kinetic energy of the air molecules directly. Temperature is typically expressed in kelvins (K), degrees Fahrenheit (°F), or degrees Celsius.

Dry bulb temperature does not reflect the quantity of moisture in the air, in contrast to wet bulb temperature. It is crucial to take this into account when planning a building for a certain environment. One of the "most essential climate variables for human comfort," according to Nall

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:6 hours

Explanation:

72km/22km

1.3 m/s is the speed . when Alison rode her skateboard 39 meters in 22 seconds.

Option C is correct

Divide the distance traveled by the time required to cover that distance to determine an object's speed. This formula is speed=distance/time (s=d/t). A unit of distance is divided by a unit of time in the speed equation.

Calculating Speed and Velocity The ratio of the object's total distance over a period of time to that period is used to determine speed. The ratio of a displacement interval to the time taken, on the other hand, allows one to calculate velocity.

speed=distance/time (s=d/t )

S = 32 / 22 = 1.3 m/s

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

Following are the calculation to the friction force:

The substring tension force is provided as follows:  

\(\to T-m_{1}g=0 \\\\\to T = m_{1}g \\\\\)

       \(= (68\ kg) (9.81 \ \frac{m}{s^2} ) (\frac{ 1\ N}{ 1\ kg \cdot \frac{m}{s^2}}) \\\\ = (68 ) (9.81 ) ( 1\ N) \\\\= 667.08\ N \\\\\)

Therefore, the friction force on the box is "667 N".

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The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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Please find attached photograph for your answer. Hope it helps! Please do comment

Answer:

Hans Christian Oersted

Explanation:

Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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Answer:

36m

Explanation:

a = 4 m/s^2

u = 0 ( it's starting from rest )

t = 3

a=v-u/t ....... 4=(v-0)/3, v = 12m/s

Using s=d/t,

12=d/3,

d= 36m

If an object starts from rest and accelerates at a rate of 4 m/s2 for 3 seconds, then its displacement from the start position would be 44.1 meters.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

As given in the problem If an object starts from rest and accelerates at a rate of 4 m/s² for 3 seconds,

S = ut + 1/2 × a × t²

S = 0 + 0.5 × 9.8 × 3²

S = 44.1 meters

Thus, If an object starts from rest and accelerates at a rate of 4 m/s2 for 3 seconds, then its displacement from the start position would be 44.1 meters.,

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The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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Melvina's potential energy is 54,880 Joules.

To calculate Melvina's potential energy, we need to use the formula for gravitational potential energy:

Potential energy = mass × gravitational acceleration × height

Potential energy is a measure of the energy an object possesses due to its position relative to other objects. In this case, Melvina's potential energy is a result of her height above the ground. As she stands on the ledge of the burning building, her potential energy is stored and can be converted into other forms of energy if she were to jump or fall. The potential energy will decrease as she descends, and it will be converted into kinetic energy (energy of motion).

Given that Melvina has a mass of 70 kg and the ledge is 80 m above the ground, we can substitute the values into the formula:

Potential energy = 70 kg × 9.8 m/s² × 80 m

Calculating this, we find:

Potential energy = 54,880 Joules

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Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of

tan(θ) = 15.80   →   θ ≈ 86.38°

The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of

∑ F = P - (M + m) g sin(θ) = (M + m) a

(see the attached free body diagram)

where

P = magnitude of the push

g = 9.80 m/s²

a = 2.53 m/s²

and M and m are the given masses.

Then the system requires a push of

P = (M + m) (a + g sin(θ))

P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

P ≈ 233 N

If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is

∑ F = T - M g sin(θ) = M a

where

T = tension in the rope

Then

T = M (a + g sin(θ))

T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

T ≈ 175 N

Answer:

a) 202.7 N

b) 58.1 N

c) 74.1º N of E.

d) 210.9 N

Explanation:

a)

      \(F_{Ay} = F_{A} * cos \theta = 155 N* cos 22 = 143.7 N (1)\)

      ⇒ Fy = FH + FAy = 59 N + 143.7 N = 202.7 N (2)

b)

      \(F_{x} = F_{A} * sin \theta = 155 N* sin 22 = 58.1 N (3)\)

c)

       \(tg \theta = \frac{F_{y}}{F_{x}} = \frac{202.7N}{58.1N} = 3.5 (4)\)

      ⇒ θ = tg⁻¹ (3.5) = 74.1º N of E. (5)

d)

      \(F_{DS} = \sqrt{(F_{x} ^{2} +F_{y} ^{2})} = \sqrt{(58.1N)^{2}) + (202.7N)^{2} } = 210.9 N (6)\)

The mass of the planet orbiting through the path can be calculated using its period of orbit, and radius . Here, the mass of the planet be 7.11 × 10³⁰ kg.

The orbital period of a spatial object is the time taken to revolve around a star or another spatial object through out an elliptical orbit.

The mass of the star can be calculated using the formula :

m = 4 π r³/G T²

given,

r = 4 Au = 4 × 1.5 × 10¹¹ m

T = 4 years = 12.6 × 10⁷ seconds.

G = gravitational constant 6.67 × 10⁻¹¹ m³/kg s²

Then M = 4 × 3.14 × (4 × 1.5 × 10¹¹ m)³/ 6.67 × 10⁻¹¹ m³/kg s² × ( 12.6 × 10⁷ s)²

             = 7.11 × 10³⁰ kg.

Therefore, the mass of the planet is 7.11 × 10³⁰ kg..

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Answer:

which on a is the question

Answer:

the second one force=mass*acceleration

Explanation:

Newton explains that taking the mass of an object times its acceleration will determine the force the so-called object will exert.

The length of the brass at a temperature rise of 100 K is 2.0036 m

From the question given above, the following data were obtained:

Original length (L₁) = 2 m

Temperature rise (ΔT) = 100 K

Coefficient of linear expansion (α) = 18×10¯⁶ K¯¹

The final length of the brass can be obtained as follow:

α = L₂ – L₁ / L₁ΔT

18×10¯⁶ = L₂ – 2 / (2 × 100)

18×10¯⁶ = L₂ – 2 / 200

Cross multiply

L₂ – 2 = 18×10¯⁶ × 200

L₂ – 2 = 0.0036

Collect like terms

L₂ = 0.0036 + 2

L₂ = 2.0036 m

Thus, the length of the brass at a temperature rise of 100 K is 2.0036 m

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Answer:

the deeper into the ocean you go, the more pressure is exerted on you

Explanation: