Answers
The value of θ in which d is maximum is 45⁰.
The maximum horizontal distance, d is determined as 40.82 m.
What is the range of a projectile?The range of a projectile is the maximum horizontal distance traveled by the projectile.
To show that the range of a projectile is equal to the formula given by:
d = (u² x sin(2θ)) / g
where;
d is the horizontal range of the projectile,we can start by analyzing the motion of the projectile. When a projectile is launched at an angle θ with an initial velocity u, it experiences two independent motions: horizontal motion and vertical motion.
The horizontal motion of the projectile is uniform and continues at a constant velocity throughout the flight. However, the vertical motion of the projectile is influenced by gravity, which acts as a constant downward force on the projectile.
The vertical motion of the projectile can be analyzed using the following equation of motion:
h = u sin(θ) t - 1/2 g t²
where;
h is the height of the projectile at time t.At the highest point of the projectile's trajectory, its vertical velocity is zero, which means that:
u sin(θ) - g t = 0
Solving for t, we get:
t = u sin(θ) / g
The time taken by the projectile to reach the ground can be calculated by setting h = 0 in the above equation of motion, which gives:
0 = u sin(θ) t - 1/2 g t²
Solving for t, we get:
t = 2u sin(θ) / g
Using the time t, we can calculate the horizontal range d of the projectile, which is given by:
d = u cos(θ) t
Substituting the value of t, we get:
d = u cos(θ) x 2u sin(θ) / g
Simplifying the above equation, we get:
d = (u² x sin(2θ)) / g
Hence, we have shown that the formula for the range of a projectile is equal to the formula given by:
d = (u² x sin(2θ)) / g.
The value of θ in which d is maximum = 45⁰
given u = 20 m/s
d = (20² x sin(2 x 45)) / 9.8
d = 40.82 m
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Related Questions
how is potential energy a scalar quantity even though it can be negative?
Answers
Explanation:
Potential energy is a scalar quantity because it has only magnitude and no direction. Its ability to be negative does not affect its scalar nature.
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What is the force required to accelerate a 500 kg object at a rate of 10 m/s^2?
Answers
Answer:
Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).
Explanation:
The force required to accelerate an object can be calculated using the formula:
force = mass x acceleration
where "mass" is the mass of the object being accelerated, and "acceleration" is the rate at which the object's velocity is changing.
In this case, the mass of the object is 500 kg, and the acceleration is 10 m/s^2. Plugging these values into the formula gives:
force = mass x acceleration
force = 500 kg x 10 m/s^2
force = 5000 N
Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).
Stop and go traffic means a lot of opportunities for acceleration. This assignment looks at a typical experience of a car in typical
rush hour traffic. Calculate the different accelerations from the graph, interpret what your answers mean and show you really
understand acceleration.
A car traveled through rush hour traffic in a city. There was a lot of starting and stopping. The graph below shows the motion of
the car for a 16 second interval of time.
Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving?
You must answer using at least two complete sentences and vocabulary words from this lesson.
Answers
Q.1 Calculate the different accelerations from the graph
At initial point (let O) the velocity was 0 m/s to reach point A when the velocity was 5 m/s it took nearly 3 seconds as we all know that acceleration is nothing but the change in velocity per unit time
\(a \: = \frac{dv}{t} \)
\(a = \frac{5 - 0}{3} = \frac{5}{3} \: m/ {s}^{2} \)
Similarly from point A to point B the acceleration was
\(a = \frac{dv}{t} = \frac{7 - 5}{3} = \frac{2}{3} m/s²\)
From Point B to C the velocity was constant so the acceleration at that point would be zero.
in the same way we can calculate acceleration for rest other points.
Q.2 Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving?
We all know that Velocity is nothing but the speed with direction. Merry Go Round and a Ferris Wheel has constant speed but dynamic direction due to which the magnitude of velocity at every point differs with different sign hence it have a constant acceleration.
A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in meters?
m
Explain your reasoning.
Since the density of water is
cm3 is
g/cm3, then the volume of 2800 g of water is
cm on each side. Converting [ cm to meters, the cube is
Proy
13 of 15
⠀⠀⠀
Next
cm³. A cubic box with a volume of [
m on each side.
Answers
The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.
Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.
Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.
So the filled cubic box has a side length of approximately 0.141 m.
A motorcycle, travelling cast, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s.Calculate a) Its acceleration b) Its final velocity c) At what time the motorcycle had covered half the total distance d) What distance the motorcycle had covered in half the total time.
Answers
The motorcycle had covered a distance of 16 meters in half the total time.
a) To calculate the acceleration, we can use the formula:
a = (v - u) / t
where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.
Given:
u = 0 m/s (initial velocity)
v = ? (final velocity)
t = 4 s (time)
s = 64 m (distance)
Using the equation of motion:
s = ut + 1/2at^2
We can rearrange the equation to solve for acceleration:
a = 2s / t^2
a = 2(64) / (4)^2
a = 128 / 16
a = 8 m/s^2
Therefore, the acceleration of the motorcycle is 8 m/s^2.
b) To find the final velocity, we can use the formula:
v = u + at
v = 0 + (8)(4)
v = 32 m/s
Therefore, the final velocity of the motorcycle is 32 m/s.
c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:
s = ut + 1/2at^2
32 = 0 + 1/2(8)t^2
16 = 4t^2
t^2 = 4
t = 2 s
Therefore, the motorcycle had covered half the total distance at 2 seconds.
d) To calculate the distance covered in half the total time, we use the formula:
s = ut + 1/2at^2
s = 0 + 1/2(8)(2)^2
s = 0 + 1/2(8)(4)
s = 0 + 16
s = 16 m
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The resistance in question is known to have an approximate value of 500 Ω. This resistance is placed in a Wheatstone bridge with three other arms having exactly 500 Ω resistances. A 3.7 V battery with negligible internal resistance is used in the circuit. The galvanometer has a resistance of 80 Ω and a current of 0.08 μA. Calculate the value of the unknown resistance.
Answers
The value of the unknown resistance is approximately 44750 Ω.
In a balanced Wheatstone bridge, the ratio of the resistances in the two arms of the bridge is equal to the ratio of the resistances in the other two arms. That is:
R1/R2 = R3/R4
where R1, R2, R3, and R4 are the resistances in the four arms of the bridge.
In this problem, the resistances in three of the arms of the bridge are all exactly 500 Ω. Let the resistance in the fourth arm (the unknown resistance) be denoted by R. The voltage across the galvanometer is zero in a balanced Wheatstone bridge, so the current through the galvanometer is also zero.
Using Ohm's law, the current through the entire circuit is given by:
I = V/(R1 + R2 + R3 + R4)
where V is the voltage of the battery, and R1, R2, R3, and R4 are the resistances in the four arms of the bridge.
The voltage drop across the 500 Ω resistances is given by:
V_500 = (500/(500+500+R)) * V
The voltage drop across the unknown resistance R is also given by:
V_R = (R/(500+500+R)) * V
Since the voltage across the galvanometer is zero, the current through the unknown resistance R is equal to the current through the 80 Ω galvanometer. Using Ohm's law, we can write:
I_R = V_R/R = I_galvanometer = 0.08 μA
Substituting the expressions for the voltages and the current into the equation for the total current, we get:
V/(500+500+500+R) = 0.08 μA
Solving for R, we get:
R = (V/0.08 μA) - 1500 Ω
Substituting the given values, we get:
R = (3.7 V)/(0.08 μA) - 1500 Ω
R = 46250 Ω - 1500 Ω
R = 44750 Ω
Therefore, the value of the unknown resistance is approximately 44750 Ω.
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Which statement describes a primary difference between an electromagnetic wave and a mechanical wave
Answers
The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.
Difference between an Electromagnet and Mechanical WaveA primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.
Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.
Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.
On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.
Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.
In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.
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A car accelerates from 20 m/s to 30m/s in 10s
,draw velocity time graph to show cars motion.find the distance its travels by calculating the area under the graphing?
Answers
Answer:
250 m
Explanation:
Refer to the attachment for the graph. Here, we are asked to calculate the distance travelled.
⇒ Area under the graph = Distance travelled by the body
Let the distance travelled by the body be S. Area under the graph will be the area of the trapezium ABCD.Area of trapezium = ½ × Sum of parallel sides × Height
\( \twoheadrightarrow \quad \sf {S = \dfrac{1}{2}\times (AD + BC) \times OC} \\ \)
\( \twoheadrightarrow \quad \sf {S = \dfrac{1}{\cancel{2}}\times (10+30) \times \cancel{10}} \\ \)
\( \twoheadrightarrow \quad \sf {S = 1\times 50 \times 5} \\ \)
\(\twoheadrightarrow \quad \boxed{\red{\sf{ S = 250 \; m}}}\\\)
❝ Therefore, distance travelled by the body is 250 m. ❞
In an experiment, a group of students will determine the dielectric constant of paper. They have the following materials available, as well as other materials traditionally available in a high school physics lab. _____ Aluminum foil _____ Sheets of paper _____ Sheets of plastic _____ Multimeters with the ability to measure capacitance(a) Outline an effective experimental procedure to gather the necessary data that can be used to determine the dielectric constant of paper. Place a check mark next to each item above that the students should use. Draw a labeled diagram to represent the setup used for this procedure.The table below shows data from a different experiment in which students measure the capacitance of different setups as they vary the distance between the two plates of the capacitor, the area of the plates, and the material inserted between the plates.Trial Capacitor Dielectric Distance Between the Plates ( m ) Area of the Plates ( m2 ) Capacitance ( F )1 paper 1.00×10−4 0.04 8.1×10−92 paper 1.00×10−4 0.09 18.3×10−93 paper 1.00×10−4 0.16 32.6×10−94 paper 1.00×10−4 0.25 49.8×10−95 paper 2.00×10−4 0.25 23.1×10−96 paper 3.00×10−4 0.25 18.9×10−97 paper 4.00×10−4 0.25 14.9×10−98 paper 5.00×10−4 0.25 9.2×10−99 plastic 1.10×10−4 0.04 11.3×10−910 plastic 1.10×10−4 0.09 25.3×10−911 plastic 1.10×10−4 0.16 45.1×10−912 plastic 1.10×10−4 0.25 70.4×10−913 plastic 2.20×10−4 0.25 35.2×10−914 plastic 3.30×10−4 0.25 23.5×10−915 plastic 4.40×10−4 0.25 17.6×10−916 plastic 5.50×10−4 0.25 14.1×10−9(b)i. What subset of the experimental trials would be most useful in creating a graph to determine the dielectric constant of paper? Explain why the selected trials are most useful.ii. Indicate below which quantities should be graphed to yield a straight line whose slope could be used to calculate a numerical value for the dielectric constant κ of paper.Vertical axis: Horizontal axis:(c) Plot the data points for the quantities indicated in part (b)(ii) on the graph below. Clearly scale and label all axes including units, if appropriate. Draw a straight line that best represents the data.(d) Use the data to determine a value for κ of paper.(e) On the axes below, sketch the Capacitance C as functions of plate separation d, plate area A, and dielectric constant κ.
Answers
(a) The students should use aluminum foil, sheets of paper, sheets of plastic, and multimeters with the ability to measure capacitance for the experiment.
What is dielectric constant?Dielectric constant, also known as relative permittivity, is a measure of a material's ability to store electrical energy in an electric field. It is defined as the ratio of the electric flux density produced by an applied electric field to the electric flux density that would be produced by the same electric field in a vacuum.
An effective experimental procedure to determine the dielectric constant of paper could involve the following steps:
Cut two pieces of aluminum foil and attach them to opposite sides of a sheet of paper using tape, leaving a small area of the foil exposed.
Measure the area of the exposed foil using a ruler and calculate the capacitance of the capacitor using a multimeter with the ability to measure capacitance.
Repeat step 2 for different distances between the plates of the capacitor by adjusting the distance between the foil pieces and measuring the capacitance at each distance.
Plot the capacitance versus distance data on a graph and determine the slope of the best-fit line.
Calculate the dielectric constant of paper using the slope of the best-fit line and the equation C = κεA/d, where C is the capacitance, A is the area of the plates, d is the distance between the plates, ε is the permittivity of free space, and κ is the dielectric constant of paper.
(b)
i. The trials with paper inserted between the plates and varying distances between the plates would be most useful in creating a graph to determine the dielectric constant of paper. Specifically, trials 1-5 would be most useful, as they all use paper as the dielectric material and vary the distance between the plates.
ii. The capacitance C should be graphed on the vertical axis, and the reciprocal of the distance between the plates (1/d) should be graphed on the horizontal axis to yield a straight line whose slope could be used to calculate the dielectric constant κ of paper.
(d) Using the data from trials 1-5 and the graph in part (c), the slope of the best-fit line is 3.77 x 10^-9 F/m. Using the equation C = κεA/d and the measured values of A and d, and ε (permittivity of free space), we can solve for the dielectric constant κ of paper as:
κ = Cd/εA = (3.77 x 10^-9 F/m) / [(8.85 x 10^-12 F/m) x (0.04 m^2)] = 10.7
Therefore, the dielectric constant of paper is approximately 10.7.
(e) See attached image for sketches of Capacitance C as a function of plate separation d, plate area A, and dielectric constant κ. The capacitance rises as the space between the plates gets closer. With a rise in plate area, the capacitance also grows. Last but not least, the capacitance increases as the dielectric constant increases at a certain plate gap and area.
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The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
Answers
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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Which lists three organic biological molecules?
O carbohydrates, salts, metals
O salts, proteins, minerals,
O proteins, lipids, carbohydrates
O lipids, metals, minerals
Answers
Answer:
B
Explanation:
I'm learning it in science.
Answer:
its not b i just took the test and b was wrong
Explanation:
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answers
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
Developer a model diagram that shows how different amounts of GPE are stored in the earth-ball system when the ball is raised to different heights on the ramp
Answers
The ball's gravitational potential energy may be calculated in proportion to the velocity obtained by the ball as it rolls down the ramp.
The following is a model of the ball's GPE;
The height of the ball is related to the square of the velocity attained when rolling down the ramp.h ∝ v²
Which is the method used to obtain the model for the GPE of the ball?The gravitational potential energy, GPE, is given as follows;
GPE = m·g·Δh
Where;
m = The mass of the ball
g = The acceleration due to gravity
Δh = The change in elevation of the ball
The gravitational energy of the ball at the ramp's beginning (lowest) point, when h = 0, is 0
When a modest amount of energy is provided to the ball by moving it slowly, it advances up the ramp for a short distance before stopping.
When more energy is provided to the ball, it moves to a higher position on the ramp.
When energy is given to the ball, it is transformed into gravitational potential energy, and the height of the ball reflects the quantity of gravitational potential energy in the ball.
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A plastic balloon that has been rubbed with wool will stick to a wall.
a. Can you conclude that the wall is charged? If not, why not? If so, where does the charge come from?
b. Draw a series of charge diagrams showing how the balloon is held to the wall.
Answers
Answer:
Explanation:
When plastic balloon is rubbed with wool , charges are created on both balloon and silk in equal amount . Rubber balloon will acquire negative charge and silk will acquire positive charge .
Now when balloon is brought near a wall , there is induction of charge on the wall due to charge on the balloon . On the near surface of wall positive charge is produced and on the surface deep inside the wall negative charge is produced . The charge deep inside goes inside the earth but the positive charge near the surface of wall can not escape . It remains trapped by negative charge on the balloon .
hence there is mutual attraction between balloon and surface of wall is just like attraction between opposite charges . But once the ballon due to mutual attraction comes in contact with the wall , the charge on balloon and on wall neutralises each other and hence after some time the balloon falls off from the wall on the ground . It does not remain attracted to wall for ever . It happens due to neutralisation of charges on balloon and wall .
What total distance did this student travel?
Answers
Seems like some of your question is missin
Explanation:
Help with (iii) and (iv) please:
A train consists of an engine and three trucks with masses and resistances to motion as shown in
Fig. 1. There is also a driving force of 37 000 N. All the couplings are light, rigid and horizontal.
(i) Show that the acceleration of the train is 0.3 ms2.
(i) Draw a diagram showing all the forces acting on truck Z in the line of its motion.
Calculate the force in the coupling between trucks Y and Z.
[3]
[4]
With the driving force removed, brakes are applied, so adding a further resistance of 11 000 N to
the total of the resistances shown in Fig. 1.
(iii) Calculate the new acceleration of the train.
(iv) Calculate the new force in the coupling between trucks Y and Z if the brakes are applied
(A) to the engine,
(B) to truck Z
In cach case state whether the force is a tension or a thrust.
[2]
[6]
Answers
(i) The total force acting on the train is the driving force minus the total resistance to motion. The total resistance to motion is the sum of the resistances of the three trucks. Therefore, the total force acting on the train is:
F = 37,000 N - (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s² = 37,000 N - 25,740 N = 11,260 N
The acceleration of the train is given by the formula:
a = F / (m1 + m2 + m3) = 11,260 N / (1,200 kg + 900 kg + 600 kg) = 0.3 m/s²
Therefore, the acceleration of the train is 0.3 m/s².
(ii) The forces acting on truck Z are the driving force, the force in the coupling between trucks Y and Z, and the resistance to motion of truck Z. The diagram showing all the forces acting on truck Z in the line of its motion is:
Driving force ≥ Truck Z ≤ Force in coupling Y and Z ≤ Resistance to motion of truck Z
(iii) With the driving force removed and brakes applied, the total resistance to motion is the sum of the resistances of the three trucks and the additional resistance due to the brakes. Therefore, the total resistance to motion is:
R = (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s²+ 11,000 N = 25,740 N + 11,000 N = 36,740 N
The total force acting on the train is the total resistance to motion. Therefore, the acceleration of the train is:
a = F / (m1 + m2 + m3) = 0 / (1,200 kg + 900 kg + 600 kg) = 0 m/s²
Therefore, the new acceleration of the train is 0 m/s².
(iv) When the brakes are applied to the engine, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z. Therefore, the force in the coupling between trucks Y and Z is:
F = 600 kg ² 9.8 m/s² + 11,000 N = 5,880 N + 11,000 N = 16,880 N
The force in the coupling between trucks Y and Z is a tension.
When the brakes are applied to truck Z, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z plus the resistance to motion of the engine and the trucks in front of truck Y. Therefore, the force in the coupling between trucks Y and Z is:
F = (600 kg + 900 kg + 1,200 kg) ₓ9.8 m/s² + 11,000 N = 17,640 N + 11,000 N = 28,640 N
The force in the coupling between trucks Y and Z is a thrust.
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a 100 kg person travels from sea level to an altitude of 5000 m. By how mans newtons does their weight change?
Answers
Answer:
Thus, the change in the weight of the person is 1.6N , option c is correct.
Explanation:
Explain physics in a essay
Answers
The scientific study of physics focuses on the underlying concepts that underpin the laws of nature. It investigates how matter, energy, space, and time behave and interact. Physics' fundamental goal is to comprehend the underlying laws and forces that create our universe.
Physics has developed theories and rules to explain a wide variety of events, from the motion of celestial bodies to the behaviour of subatomic particles, via meticulous observation, investigation, and mathematical analysis.
These theories offer a framework for comprehending and forecasting the behaviour of physical systems, such as Newton's laws of motion and Einstein's theory of relativity.
From the tiniest particles to the biggest cosmic structures, physics has enhanced our understanding of the world and sparked a host of technological advances.
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Which statement best describes the primary difference between scientific investigation and technological design?
Scientific investigation is more time consuming than technological design.
Technological design is more expensive than scientific investigation.
Technological design involves background research, and scientific investigation does not require research.
Scientific investigation involves experiments, and technological design involves products.
Su
Answers
The statement best describes the primary difference between scientific investigation and technological design is Scientific investigation involves experiments, and technological design involves products. Option D
What are scientific investigation and technological design?It can be said that both scientific investigation and technolgical design require problem-solving, creativity, and rigorous methods.
However, both of them have different objectives. While Scientific investigation seeks to expand knowledge and understanding of the natural world. Research involvs hypothesis testing and different experiments;
on the other hand, Technological design, wants to create or improve products, processes, or systems to meet specific needs or solve particular problems.
It can then be defined as the application of scientific knowledge for practical purposes.
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Ex 1) A Major League baseball pitcher throws a baseball straight up into the air and the ball travels for 4
seconds reaching a height of 52 m before returning to the pitchers hand exactly at the height that he released
it. With what velocity does the baseball strike the pitchers hand on the way back down?
Answers
Answer:
52 / 4 = 13 m/s
Explanation:
A rock is thrown straight up with an initial velocity of 25.0 m/s. What maximum height will the rock reach before starting to fall downward
Answers
Answer:
31,86m
Explanation:
mgh=(mv^2)/2
gh=v^2/2
h=v^2/2g
h=25^2/2*9 81
h=31,86m
150 km North, 50 km West
Answers
Answer:
Explanation:
Given:
S₁ = 150 km North
S₂ = 50km West
___________
L - ? Path
S - ? Moving
Path:
L = S₁ + S₂ = 150 + 50 = 200 m
Moving:
S = √ (S₁² + S₂²) = √ ( 150² + 50²) = √ ( 22500 + 2500) =
= √ (25000) ≈ 158 m
in vacuum , the shorter the wavelength of an electromagnetic wave is , the:
A. lower its frequency
B. higher its energy
C. longer its period
D. slower its speed
Answers
Answer:
Higher its Energy
Explanation:
Four cuboids are shown in the diagram below. The position of their center of mass is also shown. Which of the cuboids is the most stable.
Answers
The position of their center of mass is also shown. the square cuboids is the most stable. Hence option B is correct.
A cuboid is a six-sided solid known as a hexahedron in geometry. Quadrilaterals make up its faces. Cuboid is short for "like a cube". A cuboid is similar to a cube in that a cuboid may become a cube by varying the lengths of the edges or the angles between the faces.
The square cuboid has its center of mass on the center of square, the masses are uniformly distributed about it.
Hence option B is correct.
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The known values are given in the table below them. Find the missing values.
Answers
The value of the missing resistance, R₃ = 10.35 ohms.
The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.
The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.
What is the value of missing component of the circuit?The values of the missing component of the circuit is calculated by applying the following formula.
The total resistance of the circuit;
For R₂, R₃, 1/R = 1/R₂ + 1/R₃
1/R = 1/12 + 1/R₃
1/R = (R₃ + 1)/(12R₃)
R = 12R₃ / (R₃ + 1)
For, R₁, R₂ and R₃, total resistance;
R = 12R₃ / (R₃ + 1) + R₁
R = [12R₃ / (R₃ + 1)] + 2
R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)
R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)
R = (14R₃ + 2 ) / (R₃ + 1)
The total current in circuit is calculated as;
I = V/R
I = 30 / R
I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)
I = (30R₃ + 30) / (14R₃ + 2) ------- (1)
The voltage in parallel circuit is the same
V₂ = V₃ = 24 V
V₃ = IR₃
24 = IR₃
I = 24/R₃ --------- (2)
Solve (1) and (2) together as follows;
24/R₃ = (30R₃ + 30) / (14R₃ + 2)
30R₃² - 306R - 48 = 0
Solve the quadratic equation, using formula method.
R₃ = 10.35 ohms
I₃ = V₃/R₃
I₃ = 24 V / 10.35
I₃ = 2.32 A
If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V
The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A
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A 39.4 kg beam is attached to a wall with a link and its far end is supported by a cable such that the angle between the beam and the cable is 90 degrees. If the beam is inclined at an angle of theta = 33.1 degrees with respect to horizontal, what is the magnitude of the horizontal component of the force exerted by the link on the beam?
Answers
Answer:
192.6N
Explanation:
Let's consider the forces acting on the beam:
Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.
Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.
Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.
Let's break down the forces acting on the beam:
Vertical forces:
W (weight of the beam) - T (vertical component of tension) = 0
T = W
Horizontal forces:
F_link (horizontal component of the force exerted by the link) = ?
To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.
Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:
F_link = W * sin(θ)
Let's substitute the given values:
W = 39.4 kg * 9.8 m/s^2
θ = 33.1 degrees
F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)
Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.
An object travels 7.5 m/s toward the west . Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s. What is its mass?
Answers
Answer:
m = 2218.67 kg
Explanation:
It is given that,
Initial velocity, u = 7.5 m/s
Final speed of an object, v = 0 (at rest)
Force, F = 5.2 kN
Time, t = 3.2 s
We need to find the mass of the object. Force acting on an object is given by :
F = ma
m is mass, a is acceleration
\(F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg\)
So, the mass of the object is 2218.67 kg
The force is always equal to the product of mass and acceleration. The mass of the object is 2218.7 Kg.
An object travels 7.5 m/s toward the west.
Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s.
Now,
The initial velocity of the object is 7.5 m/s.
The final velocity of the object is 0 m/s.
The object comes to the rest position in 3.2 seconds.
The formula for finding the acceleration of the object is mentioned below:
\(v=u+at\\0=7.5+a \times 3.2\\a= -2.34375\;\rm m/s^2\)
The formula for finding the force is mentioned below:
\(F=ma\\-5.2 \times 10^3=m \times 2.34375\\m=2218.7 \ \;kg\)
Hence, the mass of the object is 2218.7 Kg.
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Consider a ball on a circular track. The ball is slowly coming to a stop which takes 15.0 seconds. At the start, the ball was moving around with 9.13 rad/s. Calculate the angular deceleration if the ball traveled across 90 radians.
The answer should be -0.42 rad/s2
I don't know how to solve it
Answers
The angular deceleration of the ball is -0.42 rad/s².
What is angular acceleration?Angular acceleration is a measure of the rate of change of angular velocity of an object rotating about an axis. When an object rotates, its angular velocity (ω) can change as a result of various factors, such as the application of an external torque or the redistribution of mass in the object.
We can use the formula for angular acceleration:
α = (ωf - ωi) / t
where
α is the angular acceleration
ωi is the initial angular velocity
ωf is the final angular velocity (which is zero in this case since the ball comes to a stop)
t is the time it takes for the ball to come to a stop
To find the initial and final angular positions, we can use the formula:
θf - θi = ωi * t + (1/2) * α * t²
where
θi is the initial angular position (0 in this case)
θf is the final angular position (90 radians in this case)
Substtuting the given values, we have:
θf - θi = ωi * t + (1/2) * α * t²
90 - 0 = (9.13 rad/s) * 15 s + (1/2) * α * (15 s)²
Simplifying and solving for α, we get:
α = -0.42 rad/s²
Therefore, the angular deceleration of the ball is -0.42 rad/s².
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If a weather service map has a circle that
is shaded completely in, what does that
mean about the cloud cover in that area?
A. There is 100% cloud cover in that area.
B. There is 0% cloud cover in that area.
C. There is a good chance of rain.
D. There are sunny skies.
Answers
Answer:
A. There is 100% cloud cover in that area.
Explanation:
Cloud cover is recorded on weather charts by shading in parts of the circle.
If there are no clouds, the circle is left white and if the sky is completely covered in cloud, the circle is shaded completely in which means 100% cloud cover in that area.
A rock is at the top of a 20 meter tall hill. The rock has a mass of 10 kg. How much potential energy does it have?
Answers
Answer:
1960 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
PE = 10 × 9.8 × 20
We have the final answer as
1960 JHope this helps you