The EMF induced in a single wire loop with an area of 0.0940 m² is in a uniform magnetic field which has an initial value of 3.80 T, is perpendicular to the plane of the loop, and decreases at a constant rate of 0.190 T = 0.34 V. And the current induced in the loop = 0.57 A.
The EMF inducedInduced electromotive force or induced emf is the potential difference at the ends of the coil which will produce an induced electric current.
An induced electric current appears as long as there is a change in magnetic flux.
The equation is:
ε = d∅/dt
We have,
The area of the loop = 0.0940m²
The change in magnetic field with time = (3.80 T - 0.190 T) = 3.61 T
So, the EMF induced:
ε = d∅/dt
= {(0.0940m²) (3.61)} / 1
= 0.34 V
And the current induced in the loop =
I = ε/R
= 0.34 V / 0.600 Ω
= 0.57 A
The question is incomplete, it should be:
A single loop of wire with an area of 0.0900m2 is in a uniform magnetic field that has an initial value of 3.8 T, is perpendicular to the plane of the loop, and is decreasing at a constant rate of 0.190 T/s.
(a) What emf is induced in this loop?
(b) If the loop has a resistance of 0.600O, find the current induced in the loop.
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When you drop a pebble into a pond, the energy from the pebble acts on the water and causes waves. What is the wave?
Group of answer choices
The water moving away
The pebble falling through the water
The visible form of energy.
Answer:
The visible form of energy
Explanation:
Watch a video on it, and took test and got it right :)
Answer:
The visible form of energy
Explanation:
Tarzan (who has mass 80.0 kg) is running across the jungle floor with speed 7.00 m/s as
shown in Figure 1. Tarzan grabs a large bunch of bananas (15.0 kg) and grabs a vine in an attempt to swing up to his monkey who is 3.00 m above him as in Figure 2.
i. What is Tarzan’s momentum before he grabs the bananas? [2 points]
ii. What is Tarzan’s speed just after he grabs the bananas? [4 points]
iii. Can Tarzan swing high enough to reach his monkey? Justify your answer. [2 points]
We are given:
Mass of Tarzan before swinging = 80 kg
Mass of Tarzan when swinging = 80 + 15 = 95 kg
Velocity of Tarzan = 7 m/s
The height of the rock Tarzan's monkey is sitting on = 3 m
__________________________________________________________
Momentum of Tarzan before swinging:
We know that:
Momentum = Mass*Velocity
Momentum = 80 * 7
Momentum = 560 kg m/s
__________________________________________________________
Speed of Tarzan after grabbing the bananas:
The momentum of Tarzan will remain the same but his mass will increase
So, Since Momentum = New Mass* velocity
560 = 95 * v [where v is the velocity of Tarzan]
v = 5.9 m/s
__________________________________________________________
Finding the Initial and Final KE and PE:Here, KE = Kinetic Energy and PE = Potential Energy
Initial and Final KE:
We know that KE = 1/2*(mv²)
Initial KE:
Initial KE = 1/2*(mv²) [where v is the velocity after picking the bananas]
Initial KE = 1/2*(95*5.9²)
Initial KE = 1653.5 Joules
Final KE:
Final KE = 1/2*(mv²)
[where v is the velocity at the maximum point of the swing]
Since Tarzan will be at rest at the maximum point of the swing, v = 0 m/s
Final KE = 1/2*(95*0²)
Final KE = 0 Joules
Initial and Final PE:
We know that:
PE = mgh
[where g is the acceleration due to gravity and h is the height]
Initial PE:
Since the height of Tarzan from the ground was 0 m at the beginning of the swing, h = 0
Initial PE = 95*10*0
Initial PE = 0 Joules
Final PE:
Let the maximum height of Tarzan be h m
Final PE = 95*10*h
Final PE = 950(h)
__________________________________________________________
Finding the maximum height Tarzan will reach:Here, KE = Kinetic Energy and PE = Potential Energy
From the law of conservation of momentum, we know that:
Initial KE + Initial PE = Final KE + Final PE
Replacing the variables:
1653.5 + 0 = 0 + 950h
1653.5 = 950h
h = 1653.5/950 [dividing both sides by 950]
h = 1.74 m
Therefore, the maximum height reached by Tarzan is 1.74 m
but since his monkey is sitting 3 m high, he will NOT be able to reach his monkey
Which statement about traits is true?
The traits represent the people's characteristics patterns of thoughts, feelings and also behaviour.
Which statement about traits is true?Traits are distinguishing qualities or characteristics, typically one belonging to a person. A trait has a characteristic that someone has. These characteristics may be positive and maybe negative. We can easily recognize the trait of someone by looking at his behaviour like his walking style, speaking style and many other things. We can change the trait of a person by doing work on him. This is due to the traits that some people are more likely to act, think, and feel in certain ways than others.
So we can conclude that the traits represent people's characteristics patterns of thoughts, feelings and also behaviour.
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a mass of air occupied 150 cm3 at 20°c and 760 mmhg pressure. calculate it volume when heated to 100°c and constant pressure
Answer:
191 cm³
Explanation:
We'll begin by converting celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 20 °C
Initial temperature (T₁) = 20 °C + 273
Initial temperature (T₁) = 293 K
Final temperature (T₂) = 100 °C
Final temperature (T₂) = 100 °C + 273
Final temperature (T₂) = 373 K
Finally, we shall determine the final volume of the air. This can be obtained as follow:
Initial volume (V₁) = 150 cm³
Initial temperature (T₁) = 293 K
Final temperature (T₂) = 373 K
Pressure = constant
Final volume (V₂) =?
V₁/T₁ = V₂/T₂
150 / 293 = V₂ / 373
Cross multiply
293 × V₂ = 150 × 373
293 × V₂ = 55950
Divide both side by 293
V₂ = 55950 / 293
V₂ ≈ 191 cm³
Thus, the final volume of the air is 191 cm³
Calculate the force needed to accelerate a car of a mass 1000 kg by 3 m/s2
Answer:
3000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1000 × 3
We have the final answer as
3000 NHope this helps you
A motorcycle reaches the speed of 40 m / s, how far does it travel in 10 seconds?
Answer:
d = 200 m
Explanation:
Data:
Initial Velocity (Vo) = 0 m/s Final Velocity (Vf) = 40 m/s Time (t) = 10 s Distance (d) = ?Use formula:
\(\boxed{d=\frac{Vf+Vo}{2}*t}\)Replace:
\(\boxed{d=\frac{40\frac{m}{s}+0\frac{m}{s}}{2}*10s}\)Sum in the numerator:
\(\boxed{d=\frac{40\frac{m}{s}}{2}*10s}\)It divides:
\(\boxed{d=20\frac{m}{s}*10s}\)Simplify the seconds (s), and multiply:
\(\boxed{d=200\ m}\)How far does it go?
Travel a distance of 200 meters.
Select the correct answer. Which graphs show the correct relationship between kinetic energy and mass? A. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases upwards B. Graph representing the relationship between mass on the x-axis and kinetic energy on the y-axis. the curve starts at the origin and keeps on increasing C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis D. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases as it goes with a small bend Reset Next
C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.
What is kinetic energy?
Kinetic energy is the energy possessed by a body due to its motion.
K.E = ¹/₂mv²
where;
m is mass of the objectThe kinetic energy of a body is directly proportional to the mass of the object.
Thus, the correct relationship between kinetic energy and mass is Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.
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(b) The block takes time tup to slide up the ramp a distance x The block then takes time down to slide back down to the bottom of the ramp, where it has speed up. Is flows greater than equal to
or less tup?
tdown >tup -tdown = tup .tdown
In a clear, coherent paragraph-length response that may also contain figures and/or equations, explain your reasoning. If you need to draw anything other than what you have shown in part (a) to
assist in your response, use the space below. Do NOT add anything to the figures in part (a).
Newton's second law allows finding the result for the comparison of the rise and fall times of the block on the ramp is:
The acceleration of the two processes is the same, if the initial velocity is equal, the times are equal.
Newton's second law establishes a relationship between the net force, the masses and the acceleration of the bodies.
∑ F = m a
Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
The reference system is a coordinate system with respect to which the forces are drawn, in the attached we can see a free body diagram of the block going up and down the ramp, in this case the x axis is parallel to the ramp and the y axis it is perpendicular.
Let's use trigonometry to find the components of weight.
sin θ = \(\frac{W_x}{W}\)
cos θ = \(\frac{W_y}{W}\)
Wₓ = W sin θ
\(W_y\) = W cos θ
Let's write Newton's second law for each axis.
Case 1. block slides down.
x- axis
Wₓ = ma
mg sin θ = ma
a = g sin θ
Case 2. block rises
X axis
- Wₓ = m a
- m gsin θ = a
a = - g sin θ
We can see that the acceleration is the same in two two cases, if the block has the same initial speed, the rise and fall time is the same.
y = v₀ t - ½ a t²
y = ½ a t²
In conclusion using Newton's second law we can find the result for the comparison of the rise and fall times of the block on the ramp is:
The acceleration is the same, if the initial velocity is the same, the times of going up and down are the same.
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Express your answers in meters per second in ascending order separated by a comma.
The time taken for the displacement is 10 s.
Initial position, X₁ = 2 m
Final position, X₂ = 3m
Therefore, the displacement,
ΔX = X₂ - X₁
ΔX = 1m
The time taken for this displacement,
Δt = 30 - 20
Δt = 10 s
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Your question was incomplete, but most probably your question will be: How long did it take the object to get from the position x = 2.0 m to the position x = 3.0 m? Express your answer(s) using two significant figures. If there is more than one answer enter your answers in ascending order separated by commas.
Can blind people dream?
Just wondering because I've always wanted to know.
Answer:
yea yes they can they lose their retina but they can dream
____ are the foundation of psychoanalytic theory.
Answer:
an unconscious needs rooted in childhood are the foundation of psychoanalytic theory.
Explanation:
2. A student drives 7.8-km trip to school and averages a speed of
32.6 m/s. On the return trip home, the student travels with an
average speed of 36.8 m/s over the same distance. What is the
average speed (in m/s) of the student for the two-way trip? (Be
careful.) Also, what is the total time taken for the trip?
Answer:
The total time is: t=451.22 sec
The average speed is: V=34.57 m/s
Explanation:
Average speed
The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).
\(\displaystyle V=\frac{x}{t}\)
Since the student makes the trip in two parts, we have to calculate the total distance and the total time.
We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is
x=2*7,800 m=15,600 m
The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:
\(\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec\)
The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:
\(\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec\)
The total time is:
\(t=239.26\ sec+211.96\ sec=451.22\ sec\)
\(\boxed{t=451.22\ sec}\)
The average speed is:
\(\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s\)
\(\boxed{\displaystyle V=34.57\ m/s}\)
please help answering A,B,C in screenshots thank you!
The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
To plot the velocity vs. time graph, we'll use the given data points:
Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0
Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0
Let's plot these points on a graph:
Time (s) [x-axis] | Velocity (m/s) [y-axis]
--------------------------------------------
2.0 | 6.0
4.0 | 7.0
6.0 | 8.0
8.0 | 9.0
10.0 | 10.0
12.0 | 11.0
After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.
Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.
Using the formula for calculating the slope of a line:
Slope (k) = (Change in velocity) / (Change in time)
For the first two points:
Change in velocity = 7.0 - 6.0 = 1.0 m/s
Change in time = 4.0 - 2.0 = 2.0 s
Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²
Therefore, the slope of the graph is 0.5 m/s².
Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².
Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).
To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:
d = 0.5 * 1.5 = 0.75 meters
Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
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The probable question may be:
An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.
Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.
Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0
A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will
B. What is the physical significance of the slope value computed in part A?
C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.
Two moles of helium gas initially at 170 K
and 0.23 atm are compressed isothermally to
1.78 atm.
1): Find the final volume of the gas. Assume
that helium behaves as an ideal gas. The
universal gas constant is 8.31451 J/K · mol.
Answer in units of m3
2): Find the work done by the gas.
Answer in units of kJ.
3): Find the thermal energy transferred.
Answer in units of kJ.
The gas's final volume is 0.129 m³ times its beginning volume.
The work done by the gas is -2.6226 kJ, indicating that work is being done on the gas.
The transmitted thermal energy is also -2.6226 kJ.
How to calculate volume, work done and thermal energy?Using the ideal gas law to solve for the final volume of the gas:
PV = nRT
where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.
Since the process is isothermal, the temperature remains constant at 170 K, therefore:
P₁V₁ = P₂V₂
where P₁ and V₁ = initial pressure and volume, and P₂ and V₂ = final pressure and volume.
Substituting the given values:
(0.23 atm)(V₁) = (1.78 atm)(V₂)
Solving for V₂:
V₂ = (0.23/1.78)V₁ = 0.129 V₁
So the final volume of the gas is 0.129 times the initial volume.
To find the work done by the gas, use the formula:
W = -∫PdV
where the integral is taken from the initial volume V₁ to the final volume V₂. Since the process is isothermal:
W = -nRT ln(V₂/V₁)
Substituting the given values:
W = -(2 mol)(8.31451 J/K·mol)(170 K) ln(0.129) = -2622.6 J = -2.6226 kJ
So the work done by the gas is -2.6226 kJ, which means work is done on the gas.
The thermal energy transferred during the process is equal to the work done by the gas, since the process is isothermal and there is no change in internal energy. Therefore, the thermal energy transferred is also -2.6226 kJ.
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What kind of machines do astronautical engineers work with?
The astronautical engineers work with machine that fly outside the Earth's atmosphere.
What is aerospace engineering?
The design, development, testing, and production of aircraft, spacecraft, and associated systems and equipment fall within the purview of aerospace engineering. The two main and overlapping sections of the field—aeronautical engineering and astronautical engineering—have historically concentrated on issues relating to air and space flight.
The theory, technique, and application of flight within the earth's atmosphere are the main topics of aeronautical engineering.The science and technology of spacecraft and launch vehicles are the main areas of interest in astronautical engineering.Learn more about aerospace and aeronautical engineering here:
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a converging lens forms a real image four times the size of the objects and 60 cm from the optical centre of the lens.
i) find the focal length of the lens ii)what is the distance between the object and its image when they have the same size?
i) The focal length of the lens can be determined using the lens formula:
1/f = 1/v - 1/u
Where:
f = focal length of the lens
v = image distance from the optical center of the lens (positive for real image)
u = object distance from the optical center of the lens (positive for object on the same side as the incident light)
Given:
Image distance (v) = 60 cm
Object distance (u) = ?
Magnification (m) = -4 (negative because the image is real and inverted)
The magnification is given by the formula:
m = -v/u
Substituting the given values, we have:
-4 = -60/u
Simplifying the equation, we find:
u = 15 cm
Now we can substitute the values of u and v into the lens formula:
1/f = 1/60 - 1/15
Simplifying the equation, we get:
1/f = (1 - 4)/60
1/f = -3/60
1/f = -1/20
Taking the reciprocal of both sides, we find:
f = -20 cm
ii) The distance between the object and its image when they have the same size can be found using the magnification formula:
m = -v/u
Given:
Magnification (m) = 1 (since the object and image are of the same size)
Image distance (v) = ?
Object distance (u) = ?
Substituting the values into the magnification formula, we have:
1 = -v/u
Since the magnification is positive, the image is virtual and upright. Therefore, the image distance (v) is negative.
We know from part (i) that the object distance (u) is 15 cm. Substituting these values into the equation, we find:
1 = -v/15
Rearranging the equation, we have:
v = -15 cm
Therefore, the distance between the object and its image when they have the same size is 15 cm.
To know more about the i) The focal length of the lens can be determined using the lens formula:
1/f = 1/v - 1/u
Where:
f = focal length of the lens
v = image distance from the optical center of the lens (positive for real image)
u = object distance from the optical center of the lens (positive for object on the same side as the incident light)
Given:
Image distance (v) = 60 cm
Object distance (u) = ?
Magnification (m) = -4 (negative because the image is real and inverted)
The magnification is given by the formula:
m = -v/u
Substituting the given values, we have:
-4 = -60/u
Simplifying the equation, we find:
u = 15 cm
Now we can substitute the values of u and v into the lens formula:
1/f = 1/60 - 1/15
Simplifying the equation, we get:
1/f = (1 - 4)/60
1/f = -3/60
1/f = -1/20
Taking the reciprocal of both sides, we find:
f = -20 cm
ii) The distance between the object and its image when they have the same size can be found using the magnification formula:
m = -v/u
Given:
Magnification (m) = 1 (since the object and image are of the same size)
Image distance (v) = ?
Object distance (u) = ?
Substituting the values into the magnification formula, we have:
1 = -v/u
Since the magnification is positive, the image is virtual and upright. Therefore, the image distance (v) is negative.
We know from part (i) that the object distance (u) is 15 cm. Substituting these values into the equation, we find:
1 = -v/15
Rearranging the equation, we have:
v = -15 cm
Therefore, the distance between the object and its image when they have the same size is 15 cm.
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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?
The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and 6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.
4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.For more questions on speed
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What is temperature?
A. A type of heat transfer
ANUN
B. The measure of an object's "hotness"
APATIN
HERRE
C. Electromagnetic waves
Digita
D. The energy transferred between objects
H
The term temperature has to do with the measure of an object's "hotness".
What is temperature?The term temperature has to do with how hot or cold a body is. In other words, the word temperature brings us to call to mind the degree of hotness or coldness of a body.
Succinctly put, the term temperature has to do with the measure of an object's "hotness".
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Please help with this diagram as soon as possible.
a vector has a magnitude of 34 meters and an angle of 26 degrees what is the y-component of the vector? (i'd appreciate if anyone could answer this)
The y-component of the vector is approximately 14.67 meters.
To find the y-component of the vector, we need to use trigonometry. Given that the vector has a magnitude of 34 meters and an angle of 26 degrees, we can break down the vector into its x and y components.
Step 1: Identify the known values:
Magnitude of the vector (r) = 34 meters
Angle (θ) = 26 degrees
Step 2: Determine the y-component using trigonometry:
The y-component can be found using the formula:
y = r * sin(θ)
Step 3: Calculate the y-component:
Substituting the known values into the formula:
y = 34 * sin(26 degrees)
y ≈ 14.67 meters
Therefore, the y-component of the vector is approximately 14.67 meters.
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A car travels 85 km in the first half hour of a trip. The car continues to travel for 2 more hours and travels 200 km. What was the average speed of the car for the trip?
Answer:
50
Explanation:
Please please help!!!
The half-life of uranium-238 is about 4.5 billion years. How does this isotope's long half-life make it useful for finding the
age of rocks on Earth and in space?
Answer:
Because the half-life is as long as Earth has existed, virtually all rocks on Earth still have most of their uranium-238. So, measurements can easily be obtained.
Explanation:
exact answer from pluto/ edmentum
The significant part of the chemical composition of rocks is uranium. The half -life of uranium is close to the age of earth. Hence, by measuring the uranium content in rocks we can predict its age.
What is uranium?Uranium is 92nd element in periodic table. It is an actinide element. All the actinides are radioactive in which the most common is uranium. They all undergo radioactive decay process. Radioactive decay is a first order reaction. The rate constant K can be written as:
k = 1/t ln (W0/Wt)
where t is the tome of decay, W0 be the initial amount and Wt is the amount after time t.
here k = 0.693/t1/2
By this relation we can find t the age of a substance, if know the amounts and half life t1/2. Uranium is present in rocks and minerals. Uranium undergo nuclear decay and will forms its isotopes or new products.
Thus, by measuring the current amount of uranium in rocks by knowing the half life of uranium we can predict the age of rocks.
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A person pushes an object of mass 5.0 kg along the floor by applying a
force. If the object experiences a friction force of 10 N and accelerates at
18 m/s^2, what is the magnitude of the force exerted by the person?
Answer:
The magnitude of the force exerted by the person is 100 N
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = ma
Where a is the acceleration of the object.
The net force is the sum of all forces exerted over a body. When an object is moved along a rough surface it experiences two horizontal forces and two vertical forces (provided there is no vertical component of the applied force).
The vertical forces are the Normal and the Weight and they are balanced, i.e.: N = W = mg.
The horizontal forces are The applied force (Fa) and the friction force (Fr). They are not balanced because the object is accelerated in that direction. The net force is:
Fn = Fa - Fr
Applying the first equation:
Fa - Fr = ma
Solving for Fa:
Fa = Fr + ma
Substituting the given values m=5 kg, Fr=10 N, \(a=18\ m/s^2\).
Fa = 10 + 5*18 = 10 + 90 = 100
Fa = 100 N
The magnitude of the force exerted by the person is 100 N
Basically.
Given: F + m x a
Equation: 10 N + 5.0 kg x 18 m/s2
Solve: 100 N
Hooke’s Law Problem:
A ball of mass m = 2.60 kg, starting from rest, falls a vertical distance h = 55 cm before striking a vertically coiled spring, which compresses an amount BY = 15 cm. Determine the spring stiffness constant of the spring. Assume the spring has negligible mass, and ignore air resistance. Measure all distances
from the point where the ball first touches the uncompressed
spring (y=0 at this point).
The spring stiffness constant of the spring is 1276.44 N/m.
We know that Hooke’s Law is given by, F = -kx, where F is the force applied to an object, x is the displacement caused by the force, and k is the spring constant.
Therefore, the spring stiffness constant of the spring is given by k = -F / x.Let us first determine the potential energy of the ball, which will be equal to the kinetic energy of the ball when it strikes the spring. We can use the formula, PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the vertical distance fallen by the ball.
Therefore, the potential energy of the ball is given by,PE = mgh= 2.60 kg × 9.81 m/s² × 0.55 m= 14.38 JNow, the ball will transfer all its potential energy to the spring, which will store it as potential energy in the form of elastic potential energy. Therefore, the elastic potential energy stored in the spring is given by, PE = (1/2)kx², where x is the compression of the spring.
Therefore, we have,PE = (1/2)kx²
= (1/2)k (0.15 m)²
= 0.01125 k J
Setting the two expressions for PE equal to each other, we get,1
4.38 J = 0.01125 k JK
= (14.38 J) / (0.01125 J/k)
= 1276.44 N/m
Therefore, the spring stiffness constant of the spring is 1276.44 N/m.
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Calculate the final displacement from 0 if an object first moves 4 cm to the left and then 5 cm to the right
Answer:
The final displacement would be 2cm to right.
PLEASE HELP ME
1) If a bus travelling at 20 m/s is subject to a steady deceleration of 5 m/s2, how long will it
take to come to rest?
Answer:
Bus will take 4 seconds before it comes to rest.
Explanation:
Initial Velocity of bus = u = 20 ms⁻¹
Final Velocity of bus = v = 0 ms⁻¹
Deceleration of bus = a = -5 ms⁻²
Time taken by bus before it comes to rest = t = ?
Using the equation formula
a = (v - u)/t
-5 = (0 - 20) / (t)
t = -20/-5
t = 4 sec
Therefore, Bus will take 4 seconds before it comes to rest.
A bullet is shot straight up with an initial speed of 180 m/s. How long is the bullet in the air and how high does the bullet go? (neglect air resistance)
Answer:
Explanation:
Time of flight is the time taken by the bulet in air. Time of flight is expressed as T = Usinθ/g where;
U is the initial velocity = 180m/s
θ is the angle of launch = 90° (Since the bullet is shot upwards)
g is the acceleration due to gravity = 9.81m/s²
T = 180sin90/9.81
T = 180/9.81
T = 18.35s
Hence the bullet will spend 18.35s in air
The height covered by the bullet is the maximum height. Maximum height is expressed as;
H = u²sin²θ/2g
H = 180²sin²90/2(9.81)
H = 180/19.62
H = 9.17m
Hence the bullet will go 9.17m high
An airplane takes off at an acceleration of 2m/s2. If it continues accelerating at that rate what will the airplane change in velocity be, in m/s, 60 seconds after take off
The airplane change in velocity be 120 m/sec
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
acceleration = velocity/time
Velocity = acceleration * time
Velocity = 60*2
Velocity = 120 m/sec
The airplane change in velocity be 120 m/sec
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U WILL GET 25 POINTS PLEASE HELP
Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 2.857 m/s/s. The acceleration lasts for 15.5 s. What is the final speed of the car and how much ground does it cover during this acceleration?
Answer:
Hopefully, this is right.
Explanation:
Answer is 5.43.
A 0.842g sample of Hydrogen 3 decays until 0.0526g remains. How many half lives have occurred?
A 0.842g sample of Hydrogen-3 decays to 0.0526g. Approximately 4.206 half-lives have occurred.
To determine the number of half-lives that have occurred, we can use the decay equation and the concept of exponential decay. The decay equation for radioactive decay is given by:
N(t) = N₀ * (1/2)^(t/T),\((1/2)^(^t^/^T^),\)
where N(t) is the remaining amount of the substance at time t, N₀ is the initial amount, t is the time elapsed, and T is the half-life of the substance.
In this case, we have an initial mass of 0.842g (N₀) and a remaining mass of 0.0526g (N(t)). We can set up the equation as follows:
0.0526g = 0.842g \(* (1/2)^(^t^/^1^2^.^3^2)\),
where t represents the number of half-lives that have occurred.
To solve for t, we can take the logarithm of both sides of the equation:
log(0.0526g/0.842g) = log\([(1/2)^(^t^/^1^2^.^3^2^)\)].
Using the logarithmic property log(\(a^b\)) = b*log(a), we can rewrite the equation as:
log(0.0526g/0.842g) = (t/12.32) * log(1/2).
Simplifying further:
log(0.0526g/0.842g) = (t/12.32) * (-log2),
where log2 is the logarithm base 2.
Now, we can solve for t:
t = (12.32 * log(0.0526g/0.842g)) / (-log2).
Using the given values and performing the calculation, we find:
t ≈ 4.206.
Therefore, approximately 4.206 half-lives have occurred.
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