A small plane and a large plane are 6.8km from each other, at the same altitude (height). From an observation tower, the two airplanes are separated by an angle of 58°. The large plane is 5.2km from the observation tower. a. Draw a diagram to represent this situation. b. How far is the small plane from the observation tower, to the nearest tenth of a kilometer?

The given expression, \(d(n)d(n)d(n)\), represents the duration in seconds for Hailey to run her \(n^{th}\) lap. The specific values provided, 333, 777, 999, correspond to the durations of the 3rd, 7th, and 9th laps, respectively. The values 858585, 999999, and 110110110 are unrelated and do not provide any additional information about lap durations.

The expression \(d(n)d(n)d(n)\) suggests that each lap duration is represented by the function \(d(n)\), where \(n\) denotes the lap number. The specific values given (333, 777, 999) correspond to the 3rd, 7th, and 9th laps, respectively. However, the remaining values (858585, 999999, 110110110) do not appear to have a direct connection to the lap durations or the function \(d(n)\).

Without further information or a specific pattern, it is difficult to interpret the significance of the remaining values. It's important to note that more context or information about the pattern or relationship between the values would be necessary to provide a more detailed explanation or analysis.

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Answer: x-intercept: 5/4

y-intercept: -5/3

Step-by-step explanation:

We can find the y-intercept by looking at the y = mx + b form, the y-intercept would be b in that form:

4x = 3y + 5

y = 4/3x - 5/3

Next, we plug x into that equation:

We can graph it, or find it mathematically:

Set 4/3x = 5/3

4/3x * 3/4 = 5/3 * 3/4

x = 5/4

To find the series solution for the differential equation y'' + 2xy' + 2y = 0, we can assume a power series solution of the form:

Now, substitute y(x), y'(x), and y''(x) into the differential equation:

∑(n=0 to ∞) aₙn(n-1) xⁿ⁻² + 2x ∑(n=0 to ∞) aₙn xⁿ⁻¹ + 2 ∑(n=0 to ∞) aₙxⁿ = 0

We can simplify this equation by combining the terms with the same powers of x. Let's manipulate the equation step by step:

We can combine the three summations into a single summation:

∑(n=0 to ∞) (aₙ₊₂(n+1)n + 2aₙ₊₁ + 2aₙ) xⁿ = 0

Since this equation holds for all values of x, the coefficients of the terms must be zero. Therefore, we have:

This is the recurrence relation that determines the coefficients of the power series solution To find the series solution, we can start with initial conditions. Let's assume that y(0) = y₀ and y'(0) = y'₀. This gives us the following initial terms:

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Answer:

if Clara's father were to put all of the ties in a bowl, shuffle them, and pick a tie, then the chance of getting a plaid one would be a more significant percentage than the blue and green ties. let's say he will have a 40%  chance to make it simple.

The probability of choosing a plaid tie at random is 2/9.

It is a branch of mathematics that deals with the occurrence of a random event.

The total number of ties that Clara's father has is:

total = 6 + 2 + 16 + 3 = 27

The number of plaid ties is:

plaid = 6

Therefore, the probability of choosing a plaid tie at random is:

plaid/total = 6/27 = 2/9

Hence, the probability of choosing a plaid tie at random is 2/9.

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Answer: 3054 in^3

Step-by-step explanation: The formula for the volume of a sphere is V = 4/3 pi r^3, where r is radius.

Since the diameter is 18in, the radius would be 1/2 or 9in, and plugged in V is

V = 4/3(3.1415)(9)^3

Answer:

1/6*π*18^3≈3053.62806

Step-by-step explanation:

Answer:

Mala had 14 sweets at the start.

Step-by-step explanation:

7 x 2 = 14

To check, 14/2 = 7. (Dividing by 2 is the same as multiplying by 1/2)

A stochastic process X(t) is called a martingale if the expected value of X(t) given all information available up to and including time s is equal to the value of X(s).

Thus, to show that the process X(t):=e^(t/2)cos(W(t)), 0 ≤ t ≤ T is a martingale w.r.t. any filtration for Brownian motion, we need to prove that E(X(t)|F_s) = X(s), where F_s is the sigma-algebra of all events up to time s.

As X(t) is of the form e^(t/2)cos(W(t)), we can use Itô's lemma to obtain the differential form:dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt

Taking the expectation on both sides of this equation gives:E(dX) = E(e^(t/2)cos(W(t))dW) - 1/2 E(e^(t/2)sin(W(t))dt)Now, as E(dW) = 0 and E(dW^2) = dt, the first term of the right-hand side vanishes.

For the second term, we can use the fact that sin(W(t)) is independent of F_s and therefore can be taken outside the conditional expectation:

E(dX) = - 1/2 E(e^(t/2)sin(W(t)))dt = 0Since dX is zero-mean, it follows that X(t) is a martingale w.r.t. any filtration for Brownian motion.

Now, let's represent X(t) as an Itô process on the interval [0,T]. Applying Itô's lemma to X(t) gives:

dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt= dM + 1/2 e^(t/2)sin(W(t))dt

where M is a martingale with M(0) = 0.

Thus, X(t) can be represented as an Itô process on [0,T] of the form:

X(t) = M(t) + ∫₀ᵗ 1/2 e^(s/2)sin(W(s))ds

Hence, we have shown that X(t) is a martingale w.r.t. any filtration for Brownian motion and represented it as an Itô process on any time interval [0,T], T > 0.

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The figure shows the Venn diagram for the given data.

A diagram depicting mathematical or logical sets pictorially as circles or closed curves within an enclosing rectangle (the universal set), common elements of the sets being represented by the areas of overlap among the circles.

As per the given data:

Let's denote:

COLD BLOODED ANIMALS = C

WARM BLOODED ANIMALS = W

FISHES = F

Given:

All fishes are cold blooded animals.

Some, but not all, cold blooded animals are fishes

The Venn diagram will be as in the figure.

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a ball of radius 13 has a round hole of radius 3 drilled through its center. then the volume of the resulting solid is 8.5528 x 10³  units³

The radius of the ball is 13 units.

Its volume is

V₁ = (4π*13³)/3

    = 9.2028 x 10³ units³

The drilled hole has the approximate shape of a solid cylinder with radius = 3 and length = 26. Its volume is

V₂ = π*(3²)*26

    = 0.650 x 10³ units³

The volume of the resulting solid is

V₁ - V₂ = 8.5528 x 10³

Answer: 8.5528 x 10³  units³

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Given that AM = 4In, where A and M are n×n matrices.

We need to find M−1.So, first of all, we need to multiply by A-1 on both sides of AM=4

In to obtain M=A-1(4In).

Now, we can multiply on both sides by M-1 to obtain M-1M=A-1(4In)M-1.

Here, we know that MM-1=In and also A-1A=In.

So, we have In=A-1(4In)M-1On further solving, we get

M-1=1/4 A-1

This shows that option (C) 1/4A is the correct answer.

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Answer:

1st option

Step-by-step explanation:

Answer:

not sure if this is correct but i tried (1267200 feet)

Answer:

21120 ft

Step-by-step explanation:

We need to change 8 miles per hour to feet per minute

8 miles      5280 ft      1 hour

----------- * ----------      * ----------

hour          1 mile          60 minutes

704 ft/ minute

Now multiply by 30 minutes

704 ft / minute * 30 minutes =21120 ft

Answer:

The answer is B, Domain: −2≤x≤2 Range: −2≤y≤3

Step-by-step explanation

Answer:

Step-by-step explanation:

y=0.860x17+3.302

foot is 17.992 inches long

Unfortunately, I don't have access to your data so i can't give a solid answer. However, I can tell you that if your coefficeint (number before x) is greater than 0.86, you have a greater rate of change. If its smaller, its a lower rate of change.

Answer: 17.922

Step-by-step explanation:

Answer:

$1h + $2

Step-by-step explanation:

Answer:

4 + w/8 = 2

Step-by-step explanation:

To Solve:

subtract 4 from each side to get:

w/8 = -2

cross-multiply to get:

w = -16

Check:

4 + (-16/8) = 2

4 + (-2) = 2

2 = 2

Answer:

-7-11=-18

Step-by-step explanation:

the Central Limit Theorem, which states that as the sample size increases, the sampling distribution of the sample mean tends to become more normal.

The Central Limit Theorem states that as the sample size increases, the sampling distribution of the sample mean tends to become more normal. This means that the mean of the sample will be closer to the mean of the population, and the variability of the sample will be smaller. Since the sample proportion is just the mean of the sample, as the sample size increases, the distribution of the sample proportion will also become more normal. The larger the sample size, the more likely it is that the sample will accurately represent the population, and the more normal the distribution of the sample proportion will be. In other words, the sample proportion will be closer to the true population proportion, and the variability of the sample proportion will be smaller.

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Subtract 11b^2 - 4b + 7 from b^2 + 8b - 9 ?​

That is

Collecting like terms we have

Hence the result of the subtraction is

If we allow the number of edges between any two nodes to be more than two, we would need to use the adjacency matrix to accurately store that graph information.

The adjacency matrix is a matrix representation of a graph where the rows and columns represent the vertices and the values in the matrix represent the number of edges between two vertices.

In this case, we could have values greater than 1 in the matrix to represent multiple edges between two vertices.

On the other hand, the adjacency list data structure would not be able to accurately store this information, as it represents each vertex and its adjacent vertices in a linked list format.

It would be difficult to represent multiple edges between two vertices using this data structure.

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Andace needs to score at least 98 on her fifth exam to have an average of 90 or better for the five exams.

To find out what score Andace needs to get on the fifth exam, we can use the formula for the average (also known as the mean):

Average = (sum of all scores) / (number of scores)

We know that Andace needs an average of 90 or better for the five exams. Therefore, the sum of all five scores must be at least 450 (90 multiplied by 5).

The sum of Andace's first four scores is:

96 + 84 + 95 + 82 = 357

To get an average of 90 or better for the five exams, Andace needs to get a total of:

450 - 357 = 93

on her fifth exam.

Since she has already taken four exams and the maximum score she can get on her fifth exam is 100, we can subtract her first four scores from 93 to find out what she needs to score on her fifth exam:

93 - 96 - 84 - 95 - 82 = -164

Since it's not possible for Andace to score a negative number on her fifth exam, we can conclude that she needs to score at least 98 (93 - 5) to have an average of 90 or better for the five exams.

In conclusion, Andace needs to score at least 98 on her fifth exam to have an average of 90 or better for all five exams.


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GIVEN:

We are told that Barbara works 2/5 of her time doing paper work and this fraction represents 10 hours of her total working time.

Required;

To determine how many hours she will have to work in order to have 10 hours doing paper work.

Step-by-step solution.

Take note that her entire working hours is represented by 1 whole since, a fraction of it has already been identified as two-fifths.

This means

Take note that the fraction is taken as two-fifths of the total hours h and, if multiplied by the total hours, we would get 10 hours.

Hence, if we simplify the above equation, we would get the value of h as follows;

Therefore,

ANSWER:

Barbara has to work for 25 hours in order to spend 10 hours on paper work.

Answer:

Step-by-step explanation:

4+4+4+6+8+10+12+12=62

62/8=7.75

7.75-4=3.75  7.75-6=1.75 7.75-8 =0.25 7.75-10=2.25 7.75-12-4.25

3.75+3.75+3.75+1.75+0.25+2.25+4.25+4.25=24

24/8=3

MAD=3

The mean absolute deviation of the given data set is 3.

The average distance between an observation's mean and its variance is shown by the mean absolute deviation, a measure of variability. mean makes understanding simpler by using the data's original units. A wider deviation from the average is reflected by larger values. Lower values, on the other hand, are related to information points aggregating around them. The mean absolute deviation is sometimes referred to as the average absolute deviation and the mean deviation.

The given data set is 12 4 6 12 10 8 4 4

Mean of this data set is (4+4+4+6+8+10+12+12)/8=62/8 = 7.75

⇒7.75-4=3.75  7.75-6=1.75 7.75-8 =0.25 7.75-10=2.25 7.75-12-4.25 3.75+3.75+3.75+1.75+0.25+2.25+4.25+4.25=24

So mean absolute deviation will be 24/8 = 3.

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Answer:

I believe the answer is D

Step-by-step explanation:

Answer:

Just use m a t h w a y for the answer

Step-by-step explanation:

Thank me later,or dont thank me at all