A soccer ball is moving horizontally at a speed of 4.0 m/s. It then undergoes a constant acceleration. After 8.00 s, the ball is moving at 4.8m/s. What is the ball's displacement?

Answer:

there are 235cm in 2.35m

Answer:

Explanation:

Red light has longer waves, with wavelengths around 620 to 750 nm.

Patient C would be given a more severe diagnosis.

Option C is correct.

Diagnosis is considered as the process of determining which disease or condition explains a person's symptoms and signs.

Axis V rating scale is also called the Global Assessment of Functioning; the GAF went from 0 to 100 and provides a way to summarize in a single number just how adaptively a person was functioning overall.

So in the scenario above, Patient C was given a more severe diagnosis since the value is lower. In the Axis V  rating scale, the lower the number, the greater the danger.

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Complete question:

Patients A, B, C, and D all have similar symptoms and situational stressors. The major difference is that patient A's Axis V rating scale is 77, patient B's is 92, patient C's is 15, and patient D's rating scale is 32.

Which of the patients would be given a more severe diagnosis?

A.

Patient A

B.

Patient B

C.

Patient C

D.

Patient D

Answer:

What illustration

Explanation:

Answer:

D

Explanation:

LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL

COHETE.

\(F_{y}\) = 700000 N(sen 90° - 20°) - 560000 N = 97785 N

The approximate vertical component of the net force that is propelling the rocket away from Earth is 112,000 N. Option B is correct.

The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. The thrust force is pointing upwards at an angle of 20 degrees, and the weight of the rocket is pointing downwards. The thrust force is the force that is generated by the rocket engine. It is the force that propels the rocket upwards.

The weight of the rocket is the force of gravity acting on the rocket. It is the force that pulls the rocket downwards. The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. If the net force is positive, the rocket will accelerate upwards. If the net force is negative, the rocket will accelerate downwards. If the net force is zero, the rocket will remain at rest.

net force = thrust force + weight

vertical component of net force = thrust force * cos(angle)

vertical component of net force = 700,000 N * cos(20 degrees) = 112,000 N. Option B is correct.

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Answer:

Your answer is the following...

(b)"Many valence electrons are shared between the atoms"

Explanation:

Answer:

b

Explanation:

edge 2020

Answer:

Violations. A violation occurs when a player violates the rules in a manner which does not result in physical contact ( e.g. throwing a pass during an approach to the goal line; illegal guarding position by the marker; not establishing a pivot foot after carrying the disc in from out-of-bounds, etc.)

The object of Ultimate Frisbee is to gain points by scoring goals. The disc may only be passed, and a goal is scored when a player successfully passes the disc to a teammate in the end zone which that team is attacking. The team with the most points at the end of the game is declared the winner.

Explanation:

Vert (Vertical) Stack – The most common offensive play in Ultimate Frisbee. The Mailman – An intense offensive tactical maneuver to guarantee a gain of at least 70% of the field. TurboDisc – Can be added to almost any play to ensure max effectiveness.

If contact occurs and the thrower drops the disc, the count stops until the thrower picks up the disc and continues with play. The defensive player will have to back up 5 yards (15 feet) to allow a free throw from the offensive player.

The force exerted by the object having a mass of 5 kg is 10.79 N

The mass of the object, m = 5 kg

The velocity of the object from rest, v = 47.5 m/s

The time taken, t = 22 s

The formula to find the force exerted on the object is

              F = ma

where m is the mass of the object

           a is the acceleration of the object

But we know that

          a = v/t

where v is the velocity of the object

           t is the time taken

So, let us substitute the equation of the acceleration in the force equation, we get

          F = mv/t

Now, let us substitute the known values in the above equation,

        F = 5 x 47.5 / 22

           = 237.5 / 22

           = 10.79

Therefore, the force exerted by the object is 10.79 N

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To find the length of the ramp, we can use the equation for mechanical advantage (MA), which is:

MA = load / effort

The mechanical advantage of the ramp is 4, which means that for every 4 units of distance the load is moved, the effort required is moved 1 unit of distance. Therefore the effort is 4 times shorter than the load distance.

We know that the load distance is the height of the pyramid, which is 146m. So, we can use this information to find the effort distance.

Effort distance = Load distance / MA

Effort distance = 146m / 4 = 36.5m

So, the ramp would need to be 36.5m long in order to provide a mechanical advantage of 4.

Answer:

The speed of the Porsche =  180 km/h

The speed of the Ferrari =  200 km/h

Explanation:

The distance of one lap = 2 km

The distance the Ferrari laps the Porsche = 9 laps

The distance the Ferrari will lap the Porsche with 10 km/h less speed = 18 laps

Let the speed of the Ferrari = S\(_F\), the speed of the Porsche = S\(_P\), and the time that lapse before two cars lapped = t

we have;

S\(_F\) × t₁ - S\(_P\) × t = 2 km

S\(_P\) × t₁ = 9 laps × 2 km/lap = 18 km

S\(_P\) × t₁ = 18 km

S\(_F\) × t₁ =  2 km + S\(_P\) × t = 2 km + 18 km = 20 km

S\(_F\) × t₁ =  20 km

∴

Similarly, we are given that the following relation;

(S\(_F\) - 10) × t₂ - S\(_P\) × t₂ = 2 km...(2)

From which we have;

S\(_P\) × t₂ = 18 laps × 2 km/lap = 36 km

S\(_P\) × t₂ = 36 km

(S\(_F\) - 10) × t₂ = 2 km + 36 km = 38 km

(S\(_F\) - 10) × t₂ = 38 km

Therefore, given that S\(_P\) × t₂ (36 km) = 2 × S\(_P\) × t₁ (18 km), we have;

S\(_P\) × t₂ = 2 × S\(_P\) × t₁

t₂ = 2×t₁

Equation (2) becomes;

(S\(_F\) - 10) × 2×t₁ - S\(_P\) × 2×t₁ = 2 km...(2)

From which we have;

(S\(_F\) - 10) × 2×t₁  = 38 km

(S\(_F\) - 10) × 2×t₁  = 38 km

2 × t₁ × S\(_F\) - 2 × t₁ × 10 = 38 km

∵ S\(_F\) × t₁ =  20 km, we have;

2 × 20 km - 2 × t₁ × 10 = 38 km

2 × t₁ × 10 = 2 × 20 km - 38 km = 2 km

20 × t₁ = 2 km

t₁ = 2/20 = 0.1 hour = 6 minutes

Therefore, we have;

S\(_P\) × t₁ = 18 km

S\(_P\) × 0.1 h = 18 km

S\(_P\)  = 18 km/0.1 h = 180 km/h

The speed of the Porsche = S\(_P\) = 180 km/h

S\(_F\) × t₁ =  20 km

S\(_F\) × 0.1 h =  20 km

S\(_F\)  =  20 km/0.1 h = 200 km/h

The speed of the Ferrari = S\(_F\) = 200 km/h

The current flowing in each circuit arrangement depends on the total resistance of the circuit.

To calculate the total resistance of each circuit, we can use the formula:

Total Resistance = R1 + R2 + R3

a. To create a current of 1 ampere, we can use the following circuit:

  (check image 1)

b.  To create a current of 2 amperes, we can use the following circuit:

(check image 2)

The total resistance of this circuit is:

1 ohm + 2 ohm + 1 ohm = 4 ohms

Using Ohm's Law, we can calculate the voltage required to create a current of 2 amperes:

V = IR

V = 2A x 4 ohm = 8V

Therefore, we need to connect three batteries in series to create a voltage of 4.5V, and another three batteries in series to create a voltage of 4.5V, and connect both sets of batteries in parallel to create a voltage of 9V.

c. To create a current of 3 amperes, we can use the following circuit:

(check image 3)

The total resistance of this circuit is:

1 ohm + 1 ohm + 1 ohm = 3 ohms

Using Ohm's Law, we can calculate the voltage required to create a current of 3 amperes:

V = IR

V = 3A x 3 ohm = 9V

Therefore, we need to connect all four batteries in series to create a voltage of 6V, and then connect two sets of these batteries in parallel to create a voltage of 12V.

d. To create a current of 6 amperes, we cannot use these components as they will create a circuit with a total resistance of less than 0.25 ohms, which will exceed the maximum current that can flow through the components and may damage them. In order to create a circuit with a higher resistance that can handle a current of 6 amperes, we would need to add additional resistors in series with the bulbs.

For example, we could add a 1 ohm resistor in series with the 3 ohm bulb to create a circuit with a total resistance of 7 ohms:

(check image 4)

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Answer:

It is a physical change, just because it can be reversed

Explanation:

\(.\)

The effective resistance of the Parallel circuit is 3 ohms.

option B.

In a parallel circuit, the sum of the currents through each path is equal to the total current that flows from the source.

The total resistance or effective resistance in a Parallel circuit with the following formula:

1/Rt = 1/R1 + 1/R2

where;

1/Rt = 1/4 + 1/12

1/Rt = (3 + 1 ) / 12

Rt = ( 12 ) / ( 4 )

Rt = 3 ohms

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Answer:

V = ω A sin ω t       can be used to describe SHM

When sin ω t = 1 (the maximum value possible)

V = ω A          at equilibrium sin ω t = 1

Answer:

Yes

Explanation:

The most common energy that is lost in electronic devices is in the form of heat energy.

Answer:

Keyboard and Mobile devices

Explanation:

got it right on edge 2021

Answer:

Outlook allows users to insert symbols and characters not located on the  

keyboard

, but they can have shortcut keys.  

Inserting horizontal lines in the message body breaks up different sections and mostly benefits people using Outlook on  

mobile devices

.

Explanation:

The nearsighted person needs to stand 10 cm away from the flat mirror.

There must be a total of 20 cm between the eye and the image of his face.

Be aware that we know the distance between a plane mirror and the item is equal to the distance between the mirror and the image (formed behind it). indicating the object distance (the distance between the nearsighted man's face and the mirror) by

\(d_{0} +(-d_{i} )\\d_{i} =d_{0} \\2d_{0} =20 cm \\d_{0} =10 cm\)

The nearsighted person needs to stand 10 cm away from the flat mirror.

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It requires 288 joules of heat to raise the temperature of a 225-g lead ball from 15.0°C to 25.0°C.

The formula to calculate the amount of heat, Q required to raise the temperature of an object is:

Q = mcΔT

Where:

Q = the amount of heat (in joules, J)

m = the mass of the object (in kilograms, kg)

c = the specific heat capacity

ΔT = the change in temperature

In this problem, we are given:

m = 225 g = 0.225 kg

ΔT = (25.0°C - 15.0°C) = 10.0°C

c = 128 J/kg*K

plugging in the values

Q = mcΔT

Q = (0.225 kg)(128 J/kg*K)(10.0°C)

Q = 288 J

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Answer:

The frequency at which the string will create a standing wave be  with three loops is 8.6 Hz

Explanation:

The speed of the of the wave, v = 12.9 m/s

The number of loops of the standing wave = 3 loops

The length of the string = 2.00 m

Given that one loo = half of the wavelength, we have;

Three loops = 3 × half = One and half wavelength  = 1.5·λ

The frequency of a wave = f = v/λ

Therefore, we have;

The frequency, f = 12.9/1.5 = 8.6 Hz

The frequency at which the string will create a standing wave be  with three loops = 8.6 Hz.

Answer:

9.675

Explanation:

got it right on acellus

Answer:   biogeochemical process

Explanation:

GPS readings of longitude and latitude are based on wgs84. Option 3.

GPS readings of longitude and latitude are based on the WGS84 (World Geodetic System 1984) coordinate reference system.

WGS84 is widely used as the standard coordinate system for GPS (Global Positioning System) positioning and navigation.

It provides a consistent and globally recognized framework for accurately determining and representing locations on Earth's surface.

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Early sulfate reducers set the stage for the evolution of

b) photosynthesis, the first form which harvested hydrogens from h2s.

The two energy-carrying molecules ATP and NADPH are then added to the Calvin Cycle in plants along with carbon dioxide to produce the glucose molecule, which has a longer half-life than the other two energy-carrying molecules.

The Krebs Cycle is used by bacteria. Carbon fixation, reduction reactions, and RuBP regeneration all take place in three steps.

Even though they only occur when light is present, these processes are known as light-independent reactions.

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Answer:

73.34 mph to 2dp

Explanation:

veolcity = distance/ time

55 / 0.75 = 73.34 mph

Answer:

As per Provided Information

we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.

\( \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}\)

Substituting the value and let's solve it

\( \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} \)

Now, let's calculate the force applied to stop the car .

\( \pink{\boxed{\bf \: F = ma}}\)

Substituting the value we get

\( \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N\)

Here , negative sign show that the " Force is acting in opposite direction of the motion"

Therefore,

The ball will travel 1.28 m from the table before it hits the floor which is less than maximum horizontal distance covered by the object

Range is the maximum horizontal distance covered by an object when projected into the air.

Given that a ball rolls off the top of a 2.8 m tall table with a horizontal velocity of 1.7 m/s.

The time taken by the ball can be calculated by using the formula

h = ut + 1/2gt²

u = 0 with the assumption that the ball is dropped.

2.8 = 0 + 1/2 × 9.8 × t²

2.8 = 4.9t²

t² = 2.8/4.9

t² = 0.57

t = √0.57

t = 0.756 s

We can know how far the ball will travel from the table before it hits the floor by using the formula

R = ut

The vertical time will be the same with the horizontal time.

R = 1.7 × 0.756

R = 1.285 m

Therefore, the ball will travel 1.28 m from the table before it hits the floor.

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(a)The maximum uncertainty in the horizontal position is 1.75 m / 2 = 0.875 m.(b)The minimum uncertainty in the horizontal velocity of the marble is approximately 2.38 x 10^-33 m/s.(c)it does not provide information about the actual velocity of the marble. (d)the longest time the marble could remain on the table is 7.35 x 10^32 seconds.

The Heisenberg uncertainty principle states that there is a fundamental limit to the precision with which certain pairs of physical properties of a particle, such as position and momentum, can be known simultaneously. Let's address the questions based on this principle:

(a) To determine the maximum uncertainty in the horizontal position of the marble, we need to consider the width of the tabletop. The maximum uncertainty in position can be estimated as half the width of the tabletop, since the marble can be anywhere within that range. Therefore, the maximum uncertainty in the horizontal position is 1.75 m / 2 = 0.875 m.

(b) According to the Heisenberg uncertainty principle, the product of the uncertainties in position and momentum is greater than or equal to a certain minimum value. Mathematically, it is expressed as Δx * Δp ≥ h/4π, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is the reduced Planck's constant (approximately 6.626 x 10^-34 J·s). In this case, we're interested in the uncertainty in the horizontal velocity, which is related to momentum.

The mass of the marble is given as 10.0 g, which is equivalent to 0.01 kg. Since the marble is gently placed on the tabletop, we can assume a negligible initial momentum. Therefore, we can estimate the minimum uncertainty in horizontal velocity (Δv) as follows:

Δx * Δp ≥ h/4π

Δx * m * Δv ≥ h/4π

Δv ≥ h/4π(m * Δx)

Substituting the values, Δx = 0.875 m and m = 0.01 kg, we can calculate the minimum uncertainty in horizontal velocity:

Δv ≥ (6.626 x 10^-34 J.s) / (4π * (0.01 kg) * (0.875 m))

Δv ≥ 2.38 x 10^-33 m/s

Therefore, the minimum uncertainty in the horizontal velocity of the marble is approximately 2.38 x 10^-33 m/s.

(c) The uncertainty principle tells us that the product of the uncertainties in position and momentum (or velocity) has a lower limit. Since the minimum uncertainty in the horizontal velocity is non-zero, it implies that the marble cannot have an exactly zero horizontal velocity. However, it does not provide information about the actual velocity of the marble.

(d)To estimate the longest time the marble could remain on the table, we can calculate the time it would take for the marble to traverse the entire width of the tabletop with its minimum uncertainty velocity. Assuming a constant velocity, we can use the equation:

Time = Distance / Velocity

Time = 1.75 m / (2.38 x 10^-33 m/s)

Time ≈ 7.35 x 10^32 seconds

Comparing this time to the age of the universe (approximately 14 billion years), we find that the time it would take for the marble to traverse the tabletop is incredibly long. In fact, it is many orders of magnitude larger than the age of the universe, indicating that the marble could essentially remain on the table indefinitely from a practical perspective.

However, it's important to note that this analysis is based on the fundamental principles of quantum mechanics and the uncertainty principle. In classical physics, the marble would come to rest due to friction and other factors. The uncertainty principle is primarily applicable to microscopic particles and not macroscopic objects like marbles in everyday scenarios.

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Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

Given:

Voltage input (V) = 30V

Initial speed (w) = 0

Step size (h) = 0.4s

Time at which speed is to be determined (t) = 0.8s

We need to determine the speed (w) at t = 0.8s using Heun's method.

We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)

At t = 0 and w = 0 (initial conditions), we have:

k₁ = 0.02 + 0.06(0) = 0.02

We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)

So, at t = 0.4s and w = 0 (initial conditions), we have:

k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048

So, W₂ = w₁ + (k₁ + k₂)(h/2)

   = 0 + (0.02 + 0.02048)(0.4/2)

   = 0.04048(0.2)

   = 0.008096

Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

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The complete question is:

The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.

We can verify the Newton's second law of motion mathematically by using the momentum impulse relation.

The rate of change of a body's momentum is directly proportional to the applied force and occurs in the direction in which the force operates, according to Newton's Second Law of Motion. where F is the applied force, M is the body's mass, and A is the resulting acceleration.

One way to state Newton's second law of motion is as follows:

Force is inversely correlated with change in momentum and time.

Now, F is directly proportional to mv-mu t or m(v-u) t [where (v-u) represents the acceleration, or change in velocity].

As a result, we discover that F is inversely proportional to m.

By using a constant k, this relationship F is directly proportional to ma can be transformed into an equation.

Thus, F=kma (where k is constant)

The preceding equation is now F=ma or Force= Mass*Acceleration because the value of k in SI units is 1.

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