A soccer player kicking a ball; the ball soaring through the air and landing on the ground

Answer:

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The interval of acceleration of the bus will be 2.19 seconds.

An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change.

Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.

Acceleration is a vector quantity.

SI unit of acceleration is m/s.

According to the question, the given values are :

Acceleration, a=-4.1 m/s²

Initial velocity, u=9.0 m/s and,

Final velocity, v=0 m/s

By using Equation of motion, i.e.,

v=u+at

⇒0 m/s=9m/s+(-4.1 m/s²)(t)

⇒-9 m/s=-4.1 m/s²×t

t=(-9 m/s)/(-4.1 m/s²)

t= 2.19 seconds.

Hence, the time interval of acceleration of the bus will be 2.19 seconds.

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When the bus is fully loaded, the center of gravity rises to 1.73 m, and the critical angles are 35.3 degrees for the unloaded bus and 30.6 degrees for the loaded bus, respectively.

Theoretically, the body's total weight is concentrated at a location called the center of gravity.

The main distinction between the centers of mass and gravity is that the center of gravity refers to the location where the total weight of the body is balanced, whereas the center of mass refers to the location where the body's complete mass is directed.

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Answer:

That people are motivated by a series of five universal needs.

Explanation:

Answer:

C

Explanation:

it's the measure of the force of gravity pulling the object towards the centre of the Earth and this value differs at various locations away from the equator and highest at the poles

Answer:

1730nm

Explanation:

Observed wavelength λ= 1.9 millimeters

Red shift of photons = 1100

Emitted wavelength = λo

Red shift = λ - λo/ λo = 1100

= [(1.9x10^-3 - λo)/ λo] = 1100

= 1.9x10^-3 - λo = 1100 λo

= 1.9x10^-3 = 1100 λo + λo

= 1.9x10^-3 = 1101 λo

We divide through by 1101 to get the value of lambda

1.9x10^-3/1101 = λo

λo = 0.000001726

λo = 1726nm

This is approximately

λo = 1730nm

Thank you!

Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

Answer:

The coil rotates due to its inertia.

Maximum torque occurs when the plane of the coil is parallel to the magnetic field - consider the directions involved in F = I L B - the resulting force is perpendicular to I and B

Plastic deformation occurs when stress is removed and the material does not go back to its original shape.

The capacity of a solid material to undergo permanent deformation, also known as plastic deformation, is defined as the ability of a material to change its shape in a way that is irreversible in response to external pressures being applied.  

Plasticity can be seen, for instance, in a piece of solid metal that has been bent or pounded into a new shape. This is because permanent changes have occurred inside the material itself. Yielding is a term used in the field of engineering to describe the shift from an elastic behavior to a plastic behavior.

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Answer:

i think it's C thx correct me if wrong

The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.

Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).

From the given,

The capacitive reactance (Xc) = 375ω

capacitance (C) = 3.25μF

capacitive reactance Xc = 1/(2π×f×C)

Frequency (f) = 1/(2π×Xc×C)

                     = 1/(2×3.14×375×3.25×10⁻⁶)

                     = 131 s⁻¹.

Thus, the frequency of the capacitive reactance is 131 s⁻¹.

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Answer:

r= 1.09×10^-4

Explanation:

Given

V=speed=4.0×10^5 m/s

B= magnetic field= 0.040 T

©=angle= 35°

m= mass of electron= 9.11×10^-31

q= charge of electron= 1.60×10^-19

solution

qv×B= mv²/r

qvBsin©=mv²/r

qBsin©=mv/r

r=mv/qBsin©

r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)

r= 1.09×10^-4 m

a) r = 1.09 * \(10^{-4}\) m

b) Distance travelled : 6.845 *  \(10^{-4}\) m    

An electron is a  stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

given

charge of electron : 1.6 * \(10^{-19}\) C

mass of electron = 9.11 * \(10^{-31}\) kg

v = 4.0 x 10 m/s

B =  0.040 T

theta = 35 degrees

since ,

force in magnetic field on electron = centripetal force

a) q(v*B) = m \(v^{2}\) / r

q v B sin(theta) =  m \(v^{2}\) / r

r =m v /q B sin(theta)

r =  9.11 * \(10^{-31}\) * 4.0 x \(10^{5}\)/ 1.6 * \(10^{-19}\) sin (35)

r = 1.09 * \(10^{-4}\) m

b)  far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr

 = 2 * 3.14 * 1.09 * \(10^{-4}\) m  = 6.845 *  \(10^{-4}\) m  

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Answer:

combustion reaction

glucose,oxygen

carbon dioxide,water,energy

8

no. required balanced equation is:

C6H12O6+6O2--->6CO2+6H2O+energy

endothermic as it needs heat in the form of sunlight.

Gravitational Potential Energy , Kinetic Energy and velocity of panther just before hitting the ground will be 790.41599 J , 990.41599 J , 5.6523m/s respectively.

Mass is 62 kg with a height 1.3m .

Gravitational Potential Energy means product of mass , gravitational acceleration and height . Mathematically, GPE= mgh

GPE= 62 x 1.3 x 9.8

= 790.41599 J

Energy lost = Final energy- GPE

Final Energy Δ =  790.41599 J + 200 J

=990.41599 J

To find Velocity of panther just before hitting the ground V:-

Δ⇒mV²/2

990.41599 J= 62 V²/2

V²= {990.41599 x 2}/62

= 31.9489029

V=5.6523m/s

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Answer:   Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.

(The energy acquired by the objects upon which work is done)

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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Answer:

D

Explanation:

Michael Faraday is probably best known for his discovery of electromagnetic induction, his contributions to electrical engineering and electrochemistry or due to the fact that he was responsible for introducing the concept of field in physics to describe electromagnetic interaction.

Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.

Electrical engineering is an engineering discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism.

Electrochemistry is the branch of physical chemistry that studies the relationship between electricity, as a measurable and quantitative phenomenon, and identifiable chemical change, with either electricity considered an outcome of a particular chemical change or vice versa.

Answer:

general steps of performing an autopsy:

1. The body is identified and the relevant information about the deceased is collected.

2. A visual examination of the body is performed to look for any abnormalities or signs of injury.

3. The external examination is followed by an internal examination. The body is opened up to examine the organs, including the brain, heart, lungs, liver, and kidneys, for any signs of disease or injury.

4. The organs are weighed, measured and dissected.

5. Tissue samples are taken and sent for laboratory analysis.

6. The cause of death is determined based on the autopsy findings, and a report is generated.

7. The body is then closed and prepared for release to the family for funeral arrangements.

It is important to note that the specific steps involved may vary depending on the type of autopsy being conducted and the circumstances surrounding the death.

Explanation:

Answer:

Explanation:

(a) To find the density of the oil, we can use the formula for pressure difference in a fluid column:

ΔP = ρgh

where ΔP is the pressure difference, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column.

Plugging in the given values, we have:

0.125 atm = ρgh = ρ(9.81 m/s^2)(1.50 m)

Solving for ρ, we get:

ρ = 0.125 atm / (9.81 m/s^2 x 1.50 m) ≈ 0.00847 g/cm^3

Therefore, the density of the oil must be approximately 0.00847 g/cm^3.

(b) On Mars, the acceleration due to gravity is 0.379 times that of Earth, or g_Mars = 0.379g_Earth. The pressure difference between the top and bottom of the oil column will be:

ΔP_Mars = ρgh_Mars = ρg_Earth(0.379)(1.50 m)

Using the density we found in part (a), we have:

ΔP_Mars = (0.00847 g/cm^3)(9.81 m/s^2)(0.379)(1.50 m) / (1 atm/101325 Pa)

ΔP_Mars ≈ 0.019 atm

So, the pressure difference between the top and bottom of the oil column on Mars will be approximately 0.019 atm, or about 0.15 times the pressure difference on Earth.

Answer:

The pressure difference (in Earth's atmosphere) between the top and bottom of the oil column on Mars is 0.045 atm.

Explanation:

(a) To find the density of the oil, we can use the formula for pressure difference in a fluid column: ΔP = ρgh, where ΔP is the pressure difference, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column.

We know that the pressure difference is 0.125 atm, the height of the column is 1.50 m, and the acceleration due to gravity on Earth is 9.81 m/s². Plugging in these values, we get:

0.125 atm = ρ(9.81 m/s²)(1.50 m)

Solving for ρ, we get:

ρ = 0.00803 g/cm³

Therefore, the density of the oil must be 0.00803 g/cm³.

(b) If the vehicle is taken to Mars, where the acceleration due to gravity is 0.379g, we can use the same formula to find the pressure difference:

ΔP = ρgh

We know that the height of the column is still 1.50 m, but the acceleration due to gravity is now 0.379g. Plugging in these values, we get:

ΔP = (0.00803 g/cm³)(9.81 m/s²)(0.379)(150 cm)

Solving for ΔP, we get:

ΔP = 0.045 atm

Therefore, the pressure difference (in Earth's atmosphere) between the top and bottom of the oil column on Mars is 0.045 atm.

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Hope it helps you

Mona's conclusion that convection is the main way that energy escapes from the water when there is no lid may or may not be a good conclusion, depending on the context and information provided.

Convection is a process of heat transfer that involves the movement of fluids (in this case, the water) due to differences in temperature. It occurs when warmer portions of the fluid rise and cooler portions sink, creating a circulating flow.

To determine if Mona's conclusion is valid, additional information is needed. Factors such as the presence of other heat transfer mechanisms (such as radiation or evaporation), the specific setup of the experiment, and the conditions under which the observations were made are essential.

If Mona's experiment only considered convection as the primary mechanism for energy escape and excluded other factors, her conclusion might be incomplete or inaccurate. To draw a more comprehensive conclusion, it is necessary to consider other potential heat transfer mechanisms and perform further investigations or provide additional supporting data.

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There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

Answer:

Curran is testing out a newly waxed hallway floor by sliding in his socks.

He runs from one end of the hallway and starts sliding midway going all

the way to the right. The forces acting on Curran as he is sliding are

represented in the diagram below. Identify the forces and match them

correctly to the n

Water waves approaching the shore will slow down. The statement describes another change that occurs as the wavelength decreases. Thus, the correct option is A.

Wavelength can be defined as the distance between any two corresponding points of two consecutive waves. Corresponding points refers to two points or particles in the same phase in the same medium. The points that have completed identical fractions of their periodic motion.

As a wave approaches the shore of water it slows down from drag on the bottom when the water depth is less than half the wavelength. The waves here gets closer together and taller than other parts. Orbital motions of water molecules becomes increasingly elliptical, especially on the bottom of the water.

When the wave touches the bottom of water, friction cause the waves to slow down. As one wave slows down, the other wave behind it catches up to it, thus decreasing the wavelength.

Therefore, the correct option is A.

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Answer:

(Question)  Which measure does not change when a wave moves from one medium to another?

(Answer)  frequency

(Question)  Water waves approaching the shore will slow down. Which statement describes another change that occurs?

(Answer)  The wavelength decreases.

(Question)  As a wave travels from one medium to another, its wavelength triples. Which statement describes the speed and frequency in the new medium?

(Answer)  The speed will triple, and the frequency will stay the same.

(Question)  Sonar systems used in water send out sound waves that reflect off the environment and then are detected. As water gets denser, the speed of sound in water increases. What would happen to the wavelength of a sonar wave as it moves into water with a 5% higher speed of sound?

(Answer)  The wavelength would increase by 5%.

(Question)  An earthquake sends seismic waves outward from the epicenter. The waves travel through different media in different directions. What will be true for all people who feel the earth shaking?

(Answer)  The earth will rise and fall with the same frequency.

Explanation:

I just finished the quick check

Hi there!

Part 1:

Assuming this is from the work-energy unit, we can use the work-energy theorem to solve.

Since the block starts from rest:

Initial energy = GPE = mgh

Final energy = KE = 1/2mv²

We are only given the diagonal distance of the ramp, so we must solve for its height using trigonometry.

sin(30) = O/H

Hsin(30) = 11.9sin(30) = 5.95 m

Now, solve by setting the GPE and KE equal:

mgh = 1/2mv²

gh = 1/2v²

v = √2gh

v = √2(9.8)(5.95) = 10.8 m/s

Part 2:

Now, we can use the equation for work:

W = ΔKE

The final velocity of the block after sliding is 0 m/s, so:

W = 1/2mv²

Recall the equation for work:

W = Fdcosθ

Since friction works AGAINST motion, cos(180) = -1.

Thus, the work done by friction is:

W = -Fd

Recall the equation for kinetic friction:

F = μmg

Thus:

0 = 1/2mv² - Fd

0 = 1/2mv² - μmg

μmgd = 1/2mv²

Cancel out the mass and rearrange to solve for the coefficient of friction:

μgd = 1/2v²

μd = 0.5v²/gd

μ = 0.5(10.8²)/(9.8)(21) = 0.283

Part 3:

The energy lost due to friction is equivalent to the WORK DONE by friction, which is equivalent to the initial kinetic energy of the block at the bottom of the ramp.

Thus:

W = 1/2mv² = Fd

W = 1/2(10)(10.8²) = 583.1 J

Answer:

4.44 hr

Explanation:

distance= rate*time

400km/(90 km/hr)=time

time=4.44 hr

Answer:

For the aceleration we have:

Vf = Vo + a * t

Clearing "a":

a = (Vf - Vo) / t

Replacing and resolving:

a = (34 m/s - 0 m/s) / 21 s

a = 34 m/s / 21 s

a = 1,61 m/s^2

The aceleration of the vehicle is 1,61 meters per second squared