A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution?
A. 11 M
B. 14 M
C. 1 × 10−14 M
D. 1 × 10−11 M

Answer:

I think it is C

Explanation:

I just do.

Answer:

The ocean is made up of salt water, which is a combination of fresh water, plus minerals collectively called "salts." These salts aren't just sodium and chloride (the elements that make up our table salt), but other minerals such as calcium, magnesium, and potassium, among others.

Explanation:The answer is since particles can be found in ocean water It is a compound, since it results from the combination of elements It is a solution

Explanation:

There are several pieces of evidence that can be used to identify chemical changes, other than a change in color. Some of these include the production of a gas, the formation of a precipitate, a change in temperature, and a change in the state of matter (e.g. from a solid to a liquid or vice versa). For example, if a solid substance is added to a liquid and bubbles of gas are produced, this is evidence of a chemical change. Similarly, if two clear solutions are mixed together and a solid precipitate forms, this is also evidence of a chemical change. Additionally, if a substance is heated and it changes from a solid to a liquid or from a liquid to a gas, this is also evidence of a chemical change.

The purpose of this experiment is to observe the effects of chemical bonding on a simulated environment.

Observations from the simulation include the movement of atoms in the simulation indicated an attraction between them, the molecules formed clusters, suggesting an attraction between molecules, and molecules and atoms moved further apart, indicating a repulsive force between them.

A lonic bond is a type of chemical bond that forms when electrons are transferred between two atoms with different electronegativities, creating ions of opposite charges. While a covalent bond is a type of chemical bond that forms when two atoms share a pair of electrons, creating a bond between them.

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Answer:

Option C

Explanation:

In Lewis dot structure the valence electrons are represented as dots around the symbol.

For example,

In hydrogen valence electron is only one it can be represented as,

H·

We know that in covalent bonding atoms share their electron to complete the octet. Thus, their Lewis dot structure would be represented as,

H:H

This is the Lewis dot structure of H₂.

In given atom X their are  2 valence electrons (3s²) thus its Lewis dot structure contain two dots around the symbol.

Option C is correct answer because it has only two dots which actually represent valence electrons.

Other options are incorrect because symbol X has more than two electrons/dots.

The order of reaction for A in this reaction is 3

In the given chemical reaction, A(g) + B(g) → AB(g), the concentration of A is tripled while the concentration of B is held constant. As a result, the rate of reaction increases by a factor of 27. To determine the order of reaction for A, we can use the rate law expression.

The general rate law expression for this reaction is:
Rate = k[A]^m[B]^n

Since the concentration of B is held constant, we can focus on the change in concentration of A and its effect on the reaction rate:
Initial rate = k[A]^m
Final rate = k[3A]^m

The final rate is 27 times the initial rate:
27 * (k[A]^m) = k[3A]^m

Now, we can solve for the order of reaction (m) for A:
27 = (3A)^m / A^m
27 = 3^m

From this equation, we can see that m = 3, as 3^3 = 27. Therefore, the order of reaction for A in this reaction is 3, meaning the reaction rate is directly proportional to the cube of the concentration of A.

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Protons (the number on the right of calcium-40 represents number of protons). The tiniest component of ordinary matter, an atom, makes up a chemical element.

Neutral or ionized atoms make up every solid, liquid, gas, and plasma. Atoms typically have a diameter of 100 picometers or less. Due to quantum effects, they are so small atoms that it is impossible to precisely anticipate their behavioral using traditional physics, as if they were tennis balls, for example.

The positively charged particles called protons are found in the hydrogen atom's nucleus. Protons, electrons, and neutrons are the building blocks of an atom. An atom's nucleus, which is located in the middle, contains all of its mass.

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Answer:ionic radius increases down the

Explanation:

Answer:

125 grams of HNO3

Explanation:

(8.75g N2O) x (1/44g N2O) x (10mol HNO3) x (63.02g HNO3/ 1mol HNO3) = 125g HNO3

In this exercise we have to use our knowledge of chemistry to calculate the final amount in grams for nitrogen monoxide, as:

125 grams of HNO3

Thus, to make these calculations it will be necessary to observe the given equation:

\(4Zn + 10 HNO3 \rightarrow 4Zn(NO3)2 + N2O + 5 H2O\)

So after performing the stoichiometry we can perform the calculations as follows:

\((8.75g N2O) * (1/44g N2O) *(10mol HNO3) * (63.02g HNO3/ 1mol HNO3)\\ = 125g HNO3\)

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Answer:

2 lol

Explanation:

Answer is chemical change

The concentration of 1-iodopropane doubles and the concentration of sodium hydroxide quadruples, the reaction rate of this SN2 reaction is 8 times faster.

To determine how much faster the reaction rate is when the concentration of 1-iodopropane doubles and the concentration of sodium hydroxide quadruples in this SN2 reaction, follow these steps:

1. Recall the rate law for an SN2 reaction:

rate = \(k[A][B]\), where k is the rate constant, and [A] and [B] represent the concentrations of the two reactants.

2. Let the initial concentrations of 1-iodopropane and sodium hydroxide be [A] and [B], respectively. Then, the initial reaction rate is:

Initial rate = \(k[A][B]\).

3. Now, the concentration of 1-iodopropane doubles (2[A]) and the concentration of sodium hydroxide quadruples (4[B]).

4. Calculate the new reaction rate with these adjusted concentrations:

New rate = \(k(2[A])(4[B]) = 8k[A][B]\).

5. To find how much faster the reaction rate is, divide the new rate by the initial rate:

(new rate / initial rate) =  \(\frac{(8k[A][B])}{(k[A][B])}\).

6. Simplify the expression:

\(\frac{(8k[A][B])}{(k[A][B])}=8\)

So, when the concentration of 1-iodopropane doubles and the concentration of sodium hydroxide quadruples, the reaction rate of this SN2 reaction is 8 times faster.

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Answer:

The solution formed is acidic

pH = 0.87

Explanation:

The acid-base reaction of NaOH with HCl is:

NaOH + HCl → NaCl + H₂O

Where 1 mole of NaOH reacts with 1 mole of HCl

In the problem, moles of NaOH and HCl are:

NaOH: 0.0250L × (0.525mol / L) = 0.013125 moles NaOH

HCl: 0.0750 × (0.355mol / L) = 0.026625 moles HCl

As moles of HCl > moles NaOH, HCl is in excess and the solution formed is acidic

Moles in excess of HCl are:

0.026625 moles - 0.013125 moles = 0.0135 moles HCl

As the volume of the solutions is 25.0mL + 75.0mL = 100.0mL = 0.100L, molarity of HCl after reaction is:

0.0135 moles HCl / 0.100L = 0.135M HCl = 0.135M H⁺

As pH is defined as - log [H⁺], pH of the solution is:

pH = -log 0.135M H⁺ = 0.87

pH = 0.87

The pH of the resulting solution of the acid and base mixture is; Acidic with a PH = 0.87

We are given;

Volume of NaOH = 25 mL = 0.025 L

Volume of HCl = 75 mL = 0.075 L

Concentration of NaOH = 0.525 M

Concentration of HCl = 0.355 M

Total volume of solution = 0.025 + 0.075 = 0.1 L

Now, the the equation of the reaction is;

HCl + NaOH = NaCl + H2O

We can see that 1 mole of HCl reacts with 1 mole of NaOH.

Since; number of moles = Volume × concentration

Number of moles of HCl = 0.075 × 0.355

Number of moles of HCl = 0.026625 moles

Similarly;

Number of moles of NaOH = 0.025 × 0.525

Number of moles of NaOH = 0.013125 moles

We can see that the number of moles of HCl is greater than that of NaOH and as such there is excess HCl acid in the mix.

Thus,

Excess moles of HCl acid = 0.026625 - 0.013125

Excess moles of HCl acid = 0.0135 moles

Concentration of this excess HCl is gotten by the formula;

M = Excess moles/total volume

M = 0.0135/0.1

M = 0.135 M

PH of this excess concentration is;

PH = -log [H+]

PH = -log [0.135]

PH = 0.87

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The acceleration for the second part of the race is 0.3m/s².

Acceleration is the amount by which a speed or velocity increases. The acceleration can be calculated by dividing the speed of the object by the time taken as follows:

Acceleration = speed/time

According to this question, Sally is swimming 6 meters every 2 seconds, however, this increase in speed took 10 seconds.

The speed Sally is swimming is 3m/s i.e. 6/2. Hence, the acceleration can be calculated as follows:

Acceleration = 3m/s ÷ 10s

Acceleration = 0.3m/s²

Therefore, 0.3m/s² is the acceleration for the second part of the race.

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It could be that a new cold or warm air mass is moving in, and the weather might become different as a result.

An air mass is a volume of air described by its temperature and humidity in meteorology. Air masses encompass hundreds or thousands of square miles and adapt to the properties of the area underneath them. They are categorised based on latitude and whether they originate on land or in the sea.

The four primary types of air mass that will effect the weather in North America are maritime tropical (signified with mT), continental tropical (signified with cT), maritime polar (signified with mP), and continental polar (signified with cP) (which uses cP).

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A pentapeptide is a type of peptide or protein molecule made up of five amino acid residues. Peptides are linear chains of amino acids that play important roles in biological processes, such as cell signaling, catalysis, and structure formation.

At pH 1.5, the pentapeptide, ERNFW, would have a positive charge on its nitrogen (N) and negative charge on its carboxyl (COOH) group, causing it to be in its protonated form. At pH 7.0, which is close to neutral, the pentapeptide would be in its neutral form as the positive and negative charges would cancel each other out. At pH 12.5, the pentapeptide would have a negative charge on its nitrogen and positive charge on its carboxyl group, causing it to be in its deprotonated form. The charge of the pentapeptide, ERNFW, changes depending on the pH, affecting its overall structure.

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Answer:

1.5 mol of Oxygen will react with 2 mol of Aluminium

The stoichiometry of a chemical reaction, is the relationship between the quantities of reactants and products before, during, and following chemical reactions. This is represented as a ratio of reactants to products.

Consider the following reaction: aA + bB ⇄ cC + dD.

The stoichiometry for this reaction, is the ratio of coefficients:

a : b : c : d. When attempting mole calculations and other quantitative chemistry problems, we are required to follow the stoichiometry always, unless stated otherwise. (This situation would occur in the presence of an excess/limiting reagent).

For the following reaction:

\(\boxed{\rm 4Al_{\,(s)}+3O_{2\,(g)} \rightarrow 2Al_2O_{3\,(s)}}\)

The stoichiometry is 4 : 3 : 2.

∴ moles of O₂ = 3/4 × moles of Al = 3/4 × 2 = 1.5 mol

∴ 1.5 mol of Oxygen will react with 2 mol of Aluminium

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The strength of metallic bonds is dependent on the protons, delocalized electrons and ions.

The strength of a metallic bond is dependent on:

The strength of metallic bonds is dependent on the protons, delocalized electrons and ions.

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Answer

Explanation

Atomic mass =  abundances1 x relative mass 1+ abundances 2 x relative mass 2 ...etc

   =  ( 60.4% x 68.9257 + 39.6% x 70.9249)

    = 0.604 x 68.9257  +  0.396 x 70.9249)

     =  69.72 amu

The element with 2 isotopes, one representing 60.4 % of the atoms (68.9257 amu) and the other representing the rest (70.9249 amu), has an atomic mass of 69.7 amu. The element is Gallium.

An element has 2 isotopes. The sum of their abundances is 100%. If the abundance of isotope 1 is 60.4%, the abundance of isotope 2 is:

\(ab_1 + ab_2 = 100 \% \\ab_2 = 100\% - ab_1 = 100 \% - 60.4 \% = 39.6 \%\)

Isotope 1 has an abundance of 60.4% and a mass of 68.9257 amu, while Isotope 2 has an abundance of 39.6% and a mass of 70.9249 amu. The atomic mass is the weighted average of the mass by the abundance.

\(am = \frac{68.9257 amu \times 60.4 + 70.9249 amu \times 39.6 }{100} = 69.7 amu\)

The element with this atomic mass is Gallium.

The element with 2 isotopes, one representing 60.4 % of the atoms (68.9257 amu) and the other representing the rest (70.9249 amu), has an atomic mass of 69.7 amu. The element is Gallium.

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Answer:

the aNSWRER TOP UR QUESTION IS THAT I NMEED TO ANSWER THIS SO I DONT HAVE TO WQATCH ADS  LOL

Explanation:

DSADSDASDASDASDSDSDSDSDS and i knowq chem is bio chwem is

To determine the amount of NH3 (ammonia) that can be produced from 140 grams of H2 (hydrogen), we need to use the balanced chemical equation for the reaction between hydrogen and ammonia:

3H2 + N2 → 2NH3

From the equation, we can see that the mole ratio between H2 and NH3 is 3:2. This means that 3 moles of H2 react to produce 2 moles of NH3.

First, we calculate the number of moles of H2 using its molar mass. The molar mass of H2 is 2.02 g/mol.

Moles of H2 = Mass of H2 / Molar mass of H2 = 140 g / 2.02 g/mol = 69.31 mol

Since the mole ratio between H2 and NH3 is 3:2, we can calculate the moles of NH3 that can be produced:

Moles of NH3 = (69.31 mol H2) × (2 mol NH3 / 3 mol H2) = 46.21 mol NH3

Finally, we calculate the mass of NH3 using its molar mass. The molar mass of NH3 is 17.03 g/mol.

Mass of NH3 = Moles of NH3 × Molar mass of NH3 = 46.21 mol × 17.03 g/mol = 786.75 g

Therefore, 786.75 grams of NH3 can be produced from 140 grams of H2.

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The ozone hole is largely a consequence of the use of chlorofluorocarbon refrigerants. Therefore, option C is correct.

The ozone layer can e described as a region of Earth's stratosphere that absorbs the Sun's ultraviolet radiation. Ozone layer contains a high concentration of ozone to other parts of the atmosphere, although small in relation to other gases in the stratosphere.

The ozone layer consists less than 10 ppm of ozone, while the average ozone concentration in atmosphere as a whole is about 0.3 ppm. The ozone layer is found in the lower portion of the stratosphere, from approximately 15 to 35 km above Earth, although its thickness varies seasonally as well as geographically.

The ozone layer can be depleted by man made compounds, such as chlorofluorocarbons (CFCs) and bromofluorocarbons.

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Answer: 10 mg

Explanation:

First, take 17,190 divided by 5730 = 3 half-life

We know that after each half-life, the sample will decrease by half

80 mg = 0 half-life

40 mg = 1 half- life

20 mg = 2 half-life

10 mg = 3 half-life

Explanation:

Equation balanced:

2 H₂O -> 2 H₂ + O2

So if 1.97 mol of O2 is produced, it was needed 3.94 moles of H2O.

Let's transform to grams using the molar mass of water:

18 g --- 1 mol

x g --- 3.97 mol

x = 70.92 g

Answer: 70.92 g

The purpose of applying thin coatings of carbon and TiO2 in the experiment is to enhance the properties of the material's surface. Carbon coating improves the material's electrical conductivity, while TiO2 (titanium dioxide) coating increases its photocatalytic activity.

The purpose of applying thin coatings of carbon and TiO2 in this experiment is to enhance the properties of the materials being coated. Carbon is a widely used material in coating applications due to its excellent electrical conductivity and mechanical properties. In this experiment, it is used to improve the electrical conductivity of the material being coated. TiO2, on the other hand, is used to improve the material's optical properties. It is known to be an efficient photocatalyst, which means that it can help in the degradation of organic pollutants in the air and water. Additionally, TiO2 coatings have been shown to have self-cleaning properties, which can be useful in applications where cleanliness is critical. The thin coatings of carbon and TiO2 are applied to achieve the desired properties while minimizing the weight and thickness of the coatings.

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Answer:

Chemists use a solution called Universal Indicator to identify acids and bases. ... The Universal Indicator Color Guide shows that Universal Indicator turns red when it is added to a strong acid, it turns purple when it is added to a strong base, and it turns a yellowish-green when it is added to a neutral solution.

Explanation:

Answer:

Phenolphthalein

Explanation:

The reduction of 1-decyne to decane requires two equivalents of hydrogen gas. This is because the reaction involves the addition of two hydrogen atoms to the triple bond of the 1-decyne molecule, resulting in the formation of a decane.

Each hydrogen atom contributes one electron to form a bond with one of the carbon atoms in the triple bond, and the reaction requires two such additions to convert the triple bond to a single bond. Therefore, two equivalents of hydrogen gas are needed to provide the necessary hydrogen atoms for the reduction to take place.

The reaction is typically carried out using a palladium or platinum catalyst under mild conditions of temperature and pressure. The reduction of alkynes to alkanes is an important organic reaction with many applications in organic synthesis and industrial processes.

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D) [Co(NH3)5Cl](NO3)2. This complex ion has four 3d electrons associated with the cobalt transition metal. [Mn(H2O)6]3+ has five 3d electrons, [Cr(NH3)6]3+ has three 3d electrons, Ti atom has two 3d electrons, and K3[Fe(CN)6] has no transition metals with 3d electrons.

The number of 3d electrons is important in determining the electronic configuration and properties of transition metal complexes. The transition metal in this complex is Chromium (Cr), which has an atomic number of 24. Its electronic configuration is [Ar]3d^5 4s^1. When it forms a 3+ ion (Cr^3+), it loses one 4s and two 3d electrons, leaving four 3d electrons: [Ar]3d^4. The ligands (NH3) do not contribute to the metal's electron count, so [Cr(NH3)6]3+ is the correct option with four 3d electrons associated with the transition metal.

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