A square forms a semi-regular tessellation with which of the following regular polygons?
A. Trapezoid and hexagon
B. Pentagon and hexagon
C.equilateral triangle and hexagon
D. equilateral triangle and trapezoid

Answer: 0.67

Step-by-step explanation:

In order to solve the system of equations, let's equate both values of y and solve for x using the quadratic formula:

Now, let's calculate the values of y for each value of x:

Therefore the solutions are (1, 7) and (5/2, 10).

Correct option: second one.

The possible values of k are k = 2 and k = -2. These are the values of the constant k for which f(x) is continuous at x = 2.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.

To determine the values of the constant k for which f(x) is continuous at x = 2, we need to ensure that the left-hand limit, the right-hand limit, and the value of f(x) at x = 2 are all equal.

First, let's find the left-hand limit as x approaches 2. We evaluate the function for x < 2:

f(x) = x² + 5kx    (for x < 2)

Taking the limit as x approaches 2 from the left side (x < 2), we have:

lim(x→2-) f(x) = lim(x→2-) (x² + 5kx) = 2² + 5k(2) = 4 + 10k

Next, let's find the right-hand limit as x approaches 2. We evaluate the function for x > 2:

f(x) = k²x + 4x + 4    (for x > 2)

Taking the limit as x approaches 2 from the right side (x > 2), we have:

lim(x→2+) f(x) = lim(x→2+) (k²x + 4x + 4) = k²(2) + 4(2) + 4 = 2k² + 8 + 4 = 2k² + 12

Now, let's evaluate the value of f(x) at x = 2:

f(x) = 3k² - 4    (for x = 2)

f(2) = 3k² - 4

For f(x) to be continuous at x = 2, the left-hand limit, the right-hand limit, and the value of f(x) at x = 2 should all be equal. Therefore, we set up the following equation:

4 + 10k = 2k² + 12 = 3k² - 4

Simplifying, we have:

2k² + 8 = 3k² - 4

Rearranging the terms, we get:

k² - 12 = 0

Factoring, we have:

(k - 2)(k + 2) = 0

So, the possible values of k are k = 2 and k = -2. These are the values of the constant k for which f(x) is continuous at x = 2.

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Therefore,y varies inversely to x. When x = 2 and y = 21, k = 42. When y = 12, x is equal to 3.5.

When two variables vary inversely, the other decreases at the same rate as one increases. The inverse proportion can be expressed mathematically as y=k/x, where k is a constant.
To find k, we can use the given values:
y = k/x
When x = 2 and y = 21:
21 = k/2
k = 42
Now we can use k to find x when y = 12:
12 = 42/x
x = 3.5
So when y = 12, x is equal to 3.5.
Step 1: Plug the given values into the equation:
21 = k/2
Step 2: Solve for k:
k = 21 * 2
k = 42
Now that we have the value of k, we can find the value of x when y = 12.
Step 3: Plug in the values of y and k into the equation:
12 = 42/x
Step 4: Solve for x:
x = 42/12
x = 3.5
In conclusion, when y = 12, x is equal to 3.5.

Therefore,y varies inversely to x. When x = 2 and y = 21, k = 42. When y = 12, x is equal to 3.5.

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Answer:

que aa que quiere uste puntos yo tmbb ayuda

Answer: the answer is 0=0

Step-by-step explanation:

Answer:

7:25

Step-by-step explanation:

Overall it took her 130 minutes while she was out so if you put that in time measurement it would be 7:25.

Answer:

4.7

Step-by-step explanation:

Answer:

12(7 - 3)

Step-by-step explanation:

All the other do not equal anything.

The point of concurrency of three altitudes of a triangle is called its orthocenter. In the given figure O is the orthocenter.

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. Triangle ABC denotes a triangle with vertices A, B, and C. In Euclidean geometry, any three non-collinear points define a unique triangle and, by extension, a unique plane. Triangles are polygons in geometry that have three sides and three vertices. This figure is two-dimensional and has three straight sides. A triangle is a three-sided polygon. A triangle's three angles added together equals 180°.

Here,

The orthocenter of a triangle is the place at which three altitudes intersect. In the diagram, O represents the orthocenter.

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Answer:

x=6 to that's my answer

Step-by-step explanation:

2x+3=15

The side of the square of each block = 2 feet

Given,

Shelly sews a square blanket that has an area of 144 square feet.

and,  it has 36 square blocks, each the same size.

To find the approximate length of each side of a block

Now, According to the question:

36 square blocks of same size. We need to find the area of each square block. so we divide = area / square blocks

= 144/ 36

= 4

The area of each square = 4 square feet

We know that

Area of square = side ^2

Side ^2 = 4

side = \(\sqrt{4}\)

Side = 2

Hence, The side of the square of each block = 2 feet

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Answer: 8/9

Step-by-step explanation:

First, we can find a common denomiator.

The least common multiple of 2, 9, and 6 is 18.

Therefore, the lcd is 18.

1/2 = 1/2 * (9/9) = 9/18

2/9 = 2/9 * (2/2) = 4/18

1/6 = 1/6 * (3/3) = 3/18

Therefore, 1/2 + 2/9 + 1/6 = 9/18 + 4/18 + 3/18.

We can add the numerators together.

= 16/18

Divide the nuumerator and denominator by 2:

= 8/9

Answer: 31.39%

Step-by-step explanation:

Given: The ages of rocks in an isolated area are known to be approximately normally distributed with a mean of 7 years and a standard deviation of 1.8 years.

i.e. \(\mu = 7 \ \ \ \ \sigma= 1.8\)

Let X be the age of rocks in an isolated area .

Then, the probability that rocks are between 5.8 and 7.3 years old :

\(P(5.8<X<7.3)=P(\dfrac{5.8-7}{1.8}<\dfrac{X-\mu}{\sigma}<\dfrac{7.3-7}{1.8})\\\\=P(-0.667<Z<0.167)\ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=P(Z<0.167)-P(z<-0.667)\\\\=P(Z<0.167)-(1-P(z<0.667))\\\\=0.5663-(1-0.7476)\\\\=0.3139\)

\(=31.39\%\)

Hence, the percent of rocks are between 5.8 and 7.3 years old = 31.39%

The statement is true because:

if <1 is complement of < 3 , then m< 1 + m< 3 = 90°

also, < 4 is complement of < 2, them m<4 + m<2 = 90°

also, we can see that < 2 and < 3 are congruent angles and,

therefore, <1 and <4 must be congruent angles

example, let's say, m<1=30, then -> m<3 = 90 - 30 = 60

since <2 is congruent to <3, then m<2 = 60

replacing m<4 + m<2 = 90 we obtain m<4 + 60 = 90 -> then m<4 = 90 - 60 = 30

so, m<4 = m< 1

The most common method for finding complex roots of polynomials is the use of the Durand-Kerner Method. This method is based on the Newton-Raphson Method and takes advantage of the fact that complex numbers can be represented by a pair of real numbers.

1. Initialize a set of initial guesses for the roots of the polynomial.

2. Calculate the value of the polynomial at each of the initial guesses.

3. Calculate the derivative of the polynomial at each of the initial guesses.4. Calculate the new root value by subtracting the value of the polynomial at the current guess divided by the derivative of the polynomial at the current guess.

5. Repeat steps 3 and 4 until the values of the roots converge.

6. The final set of roots is the answer.

The most common method for finding complex roots of polynomials is the use of the Durand-Kerner Method. This method is based on the Newton-Raphson Method and takes advantage of the fact that complex numbers can be represented by a pair of real numbers.

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we would expect the result to be within 3 percentage points of the true population value 95 of those times.

sample of the population, we know that the result probably won’t exactly match the “true” result that we would get if we interviewed everyone in the population.

The margin of sampling error describes how close we can reasonably expect a survey result to fall relative to the true population value.

A margin of error of plus or minus 3 percentage points at the 95% confidence level means that if we fielded the same survey 100 times,

we would expect the result to be within 3 percentage points of the true population value 95 of those times.

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The compound proposition that is true is "p OR q".

To determine which compound proposition is true, we need to analyze the truth values of the individual propositions and apply logical operators to form compound propositions. Let's examine each compound proposition based on the given truth values of p, q, and r: p is true, q is false, and r is true.

1. Proposition 1: (p ∧ q) ∨ r

We have:

p is true (T)

q is false (F)

r is true (T)

Now let's evaluate the compound proposition:

(p ∧ q) ∨ r

Step 1: Evaluate (p ∧ q)

(p ∧ q) is false because q is false. (T ∧ F) is F.

Step 2: Evaluate (p ∧ q) ∨ r

Since (p ∧ q) is false (F) and r is true (T), (p ∧ q) ∨ r is true (T).

Therefore, Proposition 1, (p ∧ q) ∨ r, is true.

2. Proposition 2: ¬p ∧ (q ∨ r)

We have:

p is true (T)

q is false (F)

r is true (T)

Now let's evaluate the compound proposition:

¬p ∧ (q ∨ r)

Step 1: Evaluate ¬p

¬p is false because p is true. ¬T is F.

Step 2: Evaluate (q ∨ r)

(q ∨ r) is true because r is true. F ∨ T is T.

Step 3: Evaluate ¬p ∧ (q ∨ r)

Since ¬p is false (F) and (q ∨ r) is true (T), ¬p ∧ (q ∨ r) is false (F).

Therefore, Proposition 2, ¬p ∧ (q ∨ r), is false.

3. Proposition 3: (p ∨ q) ∧ r

We have:

p is true (T)

q is false (F)

r is true (T)

Now let's evaluate the compound proposition:

(p ∨ q) ∧ r

Step 1: Evaluate (p ∨ q)

(p ∨ q) is true because p is true. T ∨ F is T.

Step 2: Evaluate (p ∨ q) ∧ r

Since (p ∨ q) is true (T) and r is true (T), (p ∨ q) ∧ r is true (T).

Therefore, Proposition 3, (p ∨ q) ∧ r, is true.

Based on the given truth values of p, q, and r, Proposition 1 and Proposition 3 are true, while Proposition 2 is false.

It's important to note that the truth values of the individual propositions and the logical operators used to form the compound propositions determine their overall truth value. In this case, Proposition 1 and Proposition 3 have at least one true component, which makes them true. Proposition 2, on the other hand, has a false component, resulting in a false truth value.

Analyzing the truth values and evaluating compound propositions is a fundamental aspect of propositional logic. It allows us to reason about the relationships between propositions and determine the overall truth or falsity of complex statements based on the truth values of their components.

In this example, by carefully evaluating the truth values of p, q, and r and applying logical operators, we have determined the truth values of the compound propositions. This exercise demonstrates the importance of understanding the principles of propositional logic and how truth values interact when forming compound propositions.

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Answer:

1\5 of 2 litres is 400 ml.

Step-by-step explanation:

Hope this helps!!!

The slope of the given equation is (-11/3)

Given points,

(7, 12) and (18, 9)

Let the points be A and B i.e., A = (7, 12) and B = (18, 9)

A slope of a line is the change in y coordinate with respect to the change in x coordinate. The net change in y-coordinate is represented by Δy and the net change in x-coordinate is represented by Δx.

i.e., Slope of a line containing (p, q) and (r, s) is (r-p)/(s-q)

Slope = (r-p)/(s-q) (equation 1)

So now slope of line containing A, B is

(Where A = (7, 12) = (p, q) and B = (18, 9) = (r, s))

slope = \(\frac{(18 - 7)}{(9 - 12)}\)    (From equation 1)

i.e., slope = \(\frac{11}{-3}\)

So, the slope of the given line is (-11/3)

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To prove the existence of a subspace U of V such that the projection operator P can be represented as PU, we can use the properties of the projection operator and the fundamental theorem of linear algebra.

Given that P^2 = P and every vector in null P is orthogonal to every vector in range P, we know that V can be decomposed into the direct sum of range P and null P. This means that for every vector v in V, there exist unique vectors u in range P and w in null P such that v = u + w. By defining U as range P, we have V = U ⊕ null P. Since every vector in null P is orthogonal to every vector in range P, the sum of U and null P is direct.

Now, consider the action of P on an arbitrary vector v in V. Since v = u + w, where u is in U and w is in null P, applying P to v yields P(v) = P(u + w) = u. Thus, P can be represented as PU, where U is the subspace defined as range P. Therefore, we have proven that there exists a subspace U of V such that P can be represented as PU.

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Answer:63.75 :)

Step-by-step explanation:

Answer:

$63.75

Step-by-step explanation:

85 x 75/100

85/1 x 3/4

255/4 - > $63.75

- You should already know how to do this yourself as this is very easy and basic question.

The surface area of this locker is 432 square centimeters .

The right rectangular prism shown in the figure has dimensions 8 cm (length) x 6 cm (width) x 12 cm (height).

1. The top and bottom faces are both rectangles with dimensions 8 cm (length) x 6 cm (width). The area of each face is:

A = length x width = 8 x 6 = 48 cm²

Since there are two of these faces, the total area is:

2 x 48 = 96 cm²

2. The front and back faces are also rectangles with dimensions 8 cm (length) x 12 cm (height). The area of each face is:

A = length x height = 8 x 12 = 96 cm²

the total area is:

2 x 96 = 192 cm²

3. The left and right faces are rectangles with dimensions 6 cm (width) x 12 cm (height). The area of each face is:

A = width x height = 6 x 12 = 72 cm²

the total area is:

2 x 72 = 144 cm²

4. Therefore, the total surface area of the locker is the sum of all the faces:

Total surface area = 96 + 192 + 144 = 432 cm²

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Answer:

Apparently it's 4800 according to desmos.

Step-by-step explanation:

Step-by-step explanation:

x y

-3 150

-2 300

-1 600

0 4800

As you can see, for negative values of x, the area burned becomes smaller and smaller as x becomes more negative. This is because the equation y = 4800(2)^x has a base of 2, which means that as x becomes more negative, 2^x becomes smaller and smaller, causing y to become smaller and smaller as well.

The resultant of the given sum of the mixed number 1 1/4 + 4 2/3 will be 5 11/12.

The number system is a way to represent or express numbers.

Any of the multiple sets of symbols and the guidelines for utilizing them to represent numbers are included in the Number System.

As per the given sum of the mixed number,

1 1/4 + 4 2/3

⇒ 1 + 1/4 + 4 + 2/3

⇒ 1 + 4 + 1/4 + 2/3

⇒ 5 + 1/4 + 2/3

Take LCM of 1/4 and 2/3 as 12.

⇒ 5 + (3 + 8)/12

⇒ 5 + 11/12 = 5 11/12

Hence "The resultant of the given sum of the mixed number 1 1/4 + 4 2/3 will be 5 11/12".

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Answer:

(9,6)

Step-by-step explanation:

So, if we're thinking about a (fair in amount, related to something else/properly sized compared to something else) relationship, or the graph of a (fair in amount, related to something else/properly sized compared to something else) relationship, there should be two things that we're looking for. One, it should be a line. It should be a linear relationship between the two (numbers that change/things that change). Y should be some constant, some (fair in amount, related to something else/properly sized compared to something else)ity constant, times X.

rise/run

2/3 is the proportionality

(6,4) is the last point so if we apply the proportionality the next point should be located at (9,6)

please mark me brainliest :)

The values of x and y the triangles to the fight congruent are x = 3 and

y = 1.

What is congruent triangles?

Triangles with the same size and shape are said to be congruent. This implies that the corresponding sides and angles are both equal. Without comparing every angle and side of the two triangles, we can determine whether two triangles are congruent.

If given these triangles are congruent then all corresponding side must be equal

As we can see that both triangle are right triangle

Therefore hypotenuse of one triangle equal to another

x+1  = 4y   ..... (A)

And lenght ( height)  of one  must equal to another triangle

x = y +2          .... (B)

therefore

Plug the value of x = y + 2 in equation A

y + 2 + 1 = 4y

        3y = 3

          y = 1

and x = y+2

x = 1 + 2

x = 3

Hence, the values of x and y the triangles to the fight congruent are

x = 3 and y = 1.

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Complete question:

Complete question is attached below.