A STEAM tutoring center offers a robotics class and an app development class to its members. There are 280 members, all of which are registered for at least one class this spring. If 75% of members registered for a robotics class and 50% registered for an app development class, how many members registered for both robotics and app development?

Answer:

2:9

Step-by-step explanation:

Answer:

2:11

Step-by-step explanation:

There are 2 hockey jerseys and 11 TOTAL. Total is including the hockey jerseys aswell

The length of PM is √74.

Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

We have,

ΔPMK is a right triangle.

So,

PM² = PK² + MK²

PM² = 5² + 7²

PM² = 25 + 49

PM² = 74

PM = √74

Thus,

PM is √74.

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x = 36

Answer:

Yes

Step-by-step explanation:

So quadratic formulas help

Answer:

Regardless of where point D is located on the circle, a right triangle is formed between points A, B, and C. The right angle of the triangle is ∠ABC.

Step-by-step explanation:

PLATO

Answer:

Regardless of where point D is located on the circle, a right triangle is formed between points A, B, and C. The right angle of the triangle is ∠ABC.

Driving a personal car would be the most cost-effective mode of transportation for this commute, with a total daily cost of approximately $4.60 ($3.60 for gas + $1 for travel time).

Based on the given information, the most cost-effective mode of transportation for this commute would be to drive a personal car. Taking public transportation or carpooling may be more environmentally friendly options, but they may not save as much money as driving alone.

Assuming an average speed of 60 miles per hour on the highway, the commute would take approximately 20 minutes each way, or 40 minutes round-trip. This means the total cost of travel time for each workday would be $40 ($60/hour x 2/3 hour).

Using a cost calculator such as GasBuddy, we can estimate that the cost of driving 20 miles per day (round-trip) would be around $3.60 per day, assuming an average fuel efficiency of 25 miles per gallon and a gasoline price of $2.50 per gallon.

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Answer:

what is the question?

Step-by-step explanation:

ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok

Answer:

639

Step-by-step explanation:

If we have two pairs  (x₁, y₁) and (x₂, y₂) on the table, use the following formula to get the slope:

a = (y₂ - y₁)/(x₂ - x₁)

A general linear equation in the slope-intercept form can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

Now, if the linear equation has a table with some values:

X    Y

x₁    y₁

x₂   y₂

x₃   y₃

etc...

Then you can select any two of the pairs on the table, for example (x₁, y₁) and (x₂, y₂), and use the following formula to get the slope:

a = (y₂ - y₁)/(x₂ - x₁)

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Answer:

Step-by-step explanation:

The circumference is either pi*d or 2 pi r

Use pi*d

3.14 * 14 = 43.96

Answer:

43.96 m

Step-by-step explanation:

\(C = \pi \: d = 3.14 \times 14 = 43.96 \: m\)

Answer:

kcf (keep change flip)

Step-by-step explanation:

Answer:

x=2 or x=5

Step-by-step explanation:

Answer:

D. X<-3

Step-by-step explanation:

1. distribute the equation ( get the varibles to one side )

The critical region is determined based on the alpha level, which is the probability of making a Type I error (rejecting the null hypothesis when it is true). An alpha level of .01 means that there is a 1% chance of making a Type I error.

If Chastity ran a hypothesis test with an alpha level of .01 and her test statistic fell outside of the critical region, it means that the test statistic does not provide enough evidence to reject the null hypothesis.

In this case, Chastity should fail to reject the null hypothesis and accept it as the plausible explanation. This implies that there is not enough evidence to support the alternative hypothesis.

When a test statistic falls outside of the critical region, it indicates that the observed data is not extreme enough to reject the null hypothesis. The critical region is determined based on the alpha level, which is the probability of making a Type I error (rejecting the null hypothesis when it is true). An alpha level of .01 means that there is a 1% chance of making a Type I error.

In summary, when Chastity's test statistic falls outside of the critical region, she should fail to reject the null hypothesis and accept it as the plausible explanation. This means that there is not enough evidence to support the alternative hypothesis at the given alpha level of .01.

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The cost of the fine in Denver is $100.

The mathematical operation that would be used to determine the cost of the fine in Denver is subtraction. Subtraction is the mathematical operation that is used to determine the difference between two or more numbers. The sign used to denote subtraction is - . Other mathematical operations are addition, division and multiplication.

In order to determine the cost of the fine in Denver, subtract $200 from the cost of the fine in Colorado Springs.

The equation that represents the cost of the fine in Denver is:

Cost of the fine in Colorado Springs = $200 + cost of the fine in Denver

$350 = $200 + x

In order to determine the value of x, subtract $200 from both sides of the equation.

$350 - $200 = x

x = $100

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a. np = 8.91 and nq = 18.09 where n = 27 and p = 0.33

b. np = 3.75 and nq = 21.25 where n = 25 and p = 0.15

c. np = 9.68 and nq = 34.32 where n = 44 and p = .22

a. Given n =  27

          p = 0.33

np = 27 x 0.33

     = 8.91

nq = 27 x (1 - 0.33)

    = 18.09

For the approximation of binomial distribution, the sample size must be greater than 10 for both the products np and n(1-p) to approximate the binomial distribution by a normal distribution.

Since here np < 10 approximation is not applicable.

μp = np = 27 x 0.33  

             = 8.91

σp = √npq = √(27)x (.33) x (1 - 0.33)

              = 2.443

b.  n = 25 and p = 0.15

   np = 25 x 0.15

         = 3.75

   nq = 25 x (1 - 0.15)

    = 21.25

Approximation is not possible because np < 10.

c. n = 44 and p = .22

   np = 44 x 0.22

         = 9.68

   nq = 44 x (1 - 0.22)

    = 34.32

Since here np< 10 approximation is not possible.

μp = np = 44 x 0.22  

             = 9.68

σp =√npq = √(44)x (.22) x (1 - 0.22)

              = 2.747

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Answer:

Step-by-step explanation:za

Jjas

Answer:

A. 2 (0)=0

B. 2 (2)=4

Step-by-step explanation:

You have to multiply the X numbers by 2 for example 2x , x=2 , 2x2=4

The probability of randomly selecting a pen, a ruler, and a pencil without replacement from the given bag is 5/168.

We have,

Pencils= 2

Ruler = 1

Pens = 5

Total items in the bag: 2 pencils + 1 ruler + 5 pens = 8 items

Now, the Probability of selecting a pen first

P(pen) = 5/8

and, Probability of selecting a ruler second

P(ruler) = 1/7

and Probability of selecting a pencil last

P(pencil) = 2/6 = 1/3

So, the overall probability is

P(pen, ruler, pencil) = P(pen) x P(ruler) x P(pencil)

                    = (5/8) x (1/7) x (1/3)

                    = 5/168

Therefore, the probability of randomly selecting a pen, a ruler, and a pencil without replacement from the given bag is 5/168.

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Answer:

Alright let's do this.

First Rewrite the question:

What operation do u use to find the cost of a drink and a popcorn for one person? ​

Ok when solving you need to take Maria's name and only use first letter.

I am just going to show the you how to do the question.

________________________________________________________

P= Popcorn (Cost: $8.00)

D= Drink (Cost: $5.00)

M (Maria) = $8 + $5 = (Answer)

F (Her Friend) = $8 + $5 = (Answer)

A quick way to solve to find the total cost for 2 people.

8 x 2 = 16

5 x 2 = 10

The total cost that Maria has to pay for her and her friend is $26.00.

The operation used is Addition or Multiplication.

----------------------------------------------------------------------------------------------------------

Hope this helps! Have a great day!

Answer:

Slope: -3/5

Step-by-step explanation:

Answer:

0.989

Step-by-step explanation:

The formula for Margin of Error is:

z × Standard deviation/√n

Where

z = z score for 99% confidence Interval

= 2.576

n = 61 people

Standard deviation = $3

Hence,

Margin of Error

= 2.576 × 3/√61

= 0.989

a. The class width for all intervals in this frequency distribution is 3.

b. Calculating the class midpoints for all intervals, we get:

32-35: 33.5

36-39: 37.5

40-43: 41.5

44-47: 45.5

48-51: 49.5

52-55: 53.5

56-59: 57.5

c. Calculating the class boundaries for all intervals, we get:

32-35: 30.5-36.5

36-39: 34.5-39.5

40-43: 38.5-43.5

44-47: 42.5-47.5

48-51: 46.5-51.5

52-55: 50.5-55.5

56-59: 54.5-59.5

The number of full oscillations that any wave element performs in one unit of time is how we determine the frequency of a sinusoidal wave.

To find the class width, class midpoints, and class boundaries for the given frequency distribution, let's analyze the temperature intervals and frequencies:

Temperature (°F)    Frequency

32-35                      1

36-39                      3

40-43                      5

44-47                      11

48-51                      7

52-55                      7

56-59                      1

(a) Class width:

The class width is the difference between the upper and lower boundaries of each temperature interval. In this case, all the intervals have the same width.

Class width = Upper boundary - Lower boundary

For example, in the first interval (32-35), the lower boundary is 32 and the upper boundary is 35.

Class width = 35 - 32 = 3

The class width for all intervals in this frequency distribution is 3.

(b) Class midpoints:

The class midpoint is the average value of the upper and lower boundaries of each interval. It represents the central value of the interval.

Class midpoint = (Upper boundary + Lower boundary) / 2

For example, in the first interval (32-35), the lower boundary is 32 and the upper boundary is 35.

Class midpoint = (35 + 32) / 2 = 33.5

Calculating the class midpoints for all intervals, we get:

32-35: 33.5

36-39: 37.5

40-43: 41.5

44-47: 45.5

48-51: 49.5

52-55: 53.5

56-59: 57.5

(c) Class boundaries:

The class boundaries are the values that separate each interval. They are calculated by adding or subtracting half of the class width from the upper and lower boundaries.

For example, in the first interval (32-35), the lower boundary is 32 and the upper boundary is 35, and the class width is 3.

Lower class boundary = Lower boundary - (0.5 * class width) = 32 - (0.5 * 3) = 32 - 1.5 = 30.5

Upper class boundary = Upper boundary + (0.5 * class width) = 35 + (0.5 * 3) = 35 + 1.5 = 36.5

Calculating the class boundaries for all intervals, we get:

32-35: 30.5-36.5

36-39: 34.5-39.5

40-43: 38.5-43.5

44-47: 42.5-47.5

48-51: 46.5-51.5

52-55: 50.5-55.5

56-59: 54.5-59.5

Note: The class boundaries are inclusive of the lower boundary and exclusive of the upper boundary.

These are the calculations for the class width, class midpoints, and class boundaries for the given frequency distribution.

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To find the class width, subtract the lower class limit from the upper class limit. To find the class midpoints, add the lower and upper class limits and divide by 2. To find the class boundaries, subtract 0.5 from the lower class limit and add 0.5 to the upper class limit.

(a) Class width:

To find the class width, we subtract the lower class limit from the upper class limit. For example, the class width for the first class interval (32-35) is 35 - 32 = 3.

(b) Class midpoints:

To find the class midpoints, we add the lower class limit and the upper class limit and divide the sum by 2. For example, the class midpoint for the first class interval (32-35) is (32 + 35) / 2 = 33.5.

(c) Class boundaries:

To find the class boundaries, we subtract 0.5 from the lower class limit and add 0.5 to the upper class limit. For example, the class boundaries for the first class interval (32-35) are (32 - 0.5) and (35 + 0.5).

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To find the probability that a participant selected at random found the products favorable, we can calculate the weighted average of the favorable responses from both the industry-sponsored and non-industry-funded studies.

For the industry-sponsored studies, 65% of participants found the products favorable, and for the non-industry-funded studies, 47% found the products favorable. Since there were 65 industry-sponsored studies and 35 non-industry-funded studies, the overall probability is:

(65/100) * 0.65 + (35/100) * 0.47 = 0.4225 + 0.1645 = 0.587 or 58.7%

If a randomly selected participant found the product favorable, we can use Bayes' theorem to calculate the probability that the study was sponsored by the food industry given this favorable response. The calculation is:

P(Industry-sponsored | Favorable) = (P(Favorable | Industry-sponsored) * P(Industry-sponsored)) / P(Favorable)

P(Favorable | Industry-sponsored) = 0.65

P(Industry-sponsored) = 65/100

P(Favorable) = 0.587

P(Industry-sponsored | Favorable) = (0.65 * (65/100)) / 0.587 ≈ 0.719 or 71.9%

Similarly, if a randomly selected participant found the product unfavorable, we can use Bayes' theorem to calculate the probability that the study had no industry funding given this unfavorable response. The calculation is:

P(No industry funding | Unfavorable) = (P(Unfavorable | No industry funding) * P(No industry funding)) / P(Unfavorable)

P(Unfavorable | No industry funding) = 0.36

P(No industry funding) = 35/100

P(Unfavorable) = 1 - P(Favorable) = 1 - 0.587 = 0.413

P(No industry funding | Unfavorable) = (0.36 * (35/100)) / 0.413 ≈ 0.305 or 30.5%

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By proving both implications, we conclude that the statement "If and only if (d \mid n) and (c \mid (n/d)) then (c \mid n) and (d \mid (n/c))" is true.

To prove the statement "If and only if (d \mid n) and (c \mid (n/d)) then (c \mid n) and (d \mid (n/c))", we need to show two implications:

If (d \mid n) and (c \mid (n/d)), then (c \mid n) and (d \mid (n/c)).

If (c \mid n) and (d \mid (n/c)), then (d \mid n) and (c \mid (n/d)).

Let's prove each implication separately:

If (d \mid n) and (c \mid (n/d)), then (c \mid n) and (d \mid (n/c)):

Assume that (d \mid n) and (c \mid (n/d)).

Since (d \mid n), we can write (n = kd) for some integer (k).

Now, (c \mid (n/d)) implies that (\frac{n}{d} = mc) for some integer (m).

Substituting (n = kd) into the second equation, we get (\frac{kd}{d} = mc), which simplifies to (k = mc).

This shows that (c \mid k), and since (n = kd), we have (c \mid n).

Furthermore, from (k = mc), we can rewrite it as (m = \frac{k}{c}).

Since (\frac{k}{c}) is an integer, this implies that (d \mid k), which gives us (d \mid (n/c)).

Thus, we have shown that if (d \mid n) and (c \mid (n/d)), then (c \mid n) and (d \mid (n/c)).

If (c \mid n) and (d \mid (n/c)), then (d \mid n) and (c \mid (n/d)):

Assume that (c \mid n) and (d \mid (n/c)).

Since (c \mid n), we can write (n = lc) for some integer (l).

Now, (d \mid (n/c)) implies that (\frac{n}{c} = md) for some integer (m).

Substituting (n = lc) into the second equation, we get (\frac{lc}{c} = md), which simplifies to (l = md).

This shows that (d \mid l), and since (n = lc), we have (d \mid n).

Furthermore, from (l = md), we can rewrite it as (m = \frac{l}{d}).

Since (\frac{l}{d}) is an integer, this implies that (c \mid l), which gives us (c \mid (n/d)).

Thus, we have shown that if (c \mid n) and (d \mid (n/c)), then (d \mid n) and (c \mid (n/d)).

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Answer: were you born yesterday

Step-by-step explanation:

Step-by-step explanation:

W^2 = 46.

We know that 6^2 = 36 and 7^2 = 49.

Therefore W should be between 6 and 7.

well, let's say that the first solution is 7 liters and has "x" percent of acid, how much acid total in it? well, 7x, keeping in mind that "x" is a decimal form.

likewise, the second solution is 3 liters and has 15% acid, so how much acid is there in that one?  (15/100) * 3 = 0.45, so

\(\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&7&x&7x\\ \textit{2nd solution}&3&0.15&0.45\\ \cline{2-4}&\\ mixture&10&0.29&2.9 \end{array}~\hfill \implies 7x~~ + ~~0.45~~ = ~~2.9 \\\\[-0.35em] ~\dotfill\\\\ 7x=2.45\implies x=\cfrac{2.45}{7}\implies x=0.35~\hfill \stackrel{\textit{converting to \%}}{0.35\cdot 100}\implies \stackrel{\%}{35}\)

Answer:

  35%

Step-by-step explanation:

Let c represent the concentration of acid in the unknown solution. Then total amount of acid in the mix is ...

  7c +3(0.15) = (7+3)(0.29)

  7c +0.45 = 2.9 . . . . . . . . . eliminate parentheses

  7c = 2.45 . . . . . . . . . . . . subtract 0.45

  c = 0.35 = 35% . . . . . . divide by 7

The concentration of the first solution is 35%.

Answer:

tex] \frac{(x {}^{6} - 2)}{(x { }^{ - 4} + 3)} \)