A. Step 1B. Step 2 C. Jamie did not make a mistake

The mode of the given observations 2, 5, 3, 2, 4, 6, 2, 4 is 2, so the correct answer is 1) 2.

To find the mode of a set of observations, we need to identify the value that appears most frequently.

Let's analyze the given observations: 2, 5, 3, 2, 4, 6, 2, 4.

Looking at the observations, we can see that the number 2 appears three times, while the numbers 5, 3, 4, and 6 appear only once each.

Since the number 2 appears more frequently than any other number in the set, the mode of these observations is 2.

Therefore, the correct answer is 1) 2.

The mode is a measure of central tendency that represents the most commonly occurring value in a data set.

It can be useful in identifying the most frequent value or category in a dataset.

In this case, the mode of the given observations is 2 because it appears more frequently than any other number.

It's important to note that a dataset can have multiple modes if there are two or more values that occur with the same highest frequency. However, in this specific case, the number 2 is the only value that appears more than once, making it the mode.

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Answer:

0.25km

Step-by-step explanation:

6x-7+3x-29= 180 (co interior angles are supplementary)

9x-36 =180

9x = 216

x = 24

6x - 7 = 6(24) - 7 =137

137= 8y+17 (vertically opposite angles)

120 = 8y

so, y = 15

answer:

the missing variables are

x=24

y=15

The number that belongs in the green box using sine rule is 13.96.

The rule of sine or the sine rule states that the ratio of the side length of a triangle to the sine of the opposite angle, which is the same for all three sides.

To calculate the number that belongs in the green box, we use the formula below

Formula:

From the diagram,

Given:

Substitute these values into equation 1

Solve for x

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The missing code that can be used to replace / missing code / so that the code segment works as intended is x >= 10.

The code segment is intended to store the sum of all multiples of 10 between 10 and 100, inclusive. The value of x starts at 100 and is decremented by 10 on each iteration of the loop, until it reaches 10. The sum of all the multiples of 10 between 10 and 100 is stored in the variable total.

The missing code in the while statement determines when the loop will stop. If we use x >= 10 as a replacement for / missing code /, the loop will run as long as x is greater than or equal to 10. When x reaches 10, the loop will stop.

Here's the complete code:

int x = 100;

int total = 0;

while(x >= 10)

{

   total = total + x;

   x = x - 10;

}

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Your question is incomplete but probably the complete question is:

Consider the following code segment, which is intended to store the sum of all multiples of 10 between 10 and 100, inclusive (10 + 20 + ... + 100), in the variable total.

int x = 100;

int total = 0;

while( / missing code / )

{

total = total + x;

x = x - 10;

}

Which of the following can be used as a replacement for / missing code / so that the code segment works as intended?

A x < 100

B x <= 100

C x > 10

D x >= 10

E x != 10

Answer:

The best type of graph for displaying the range of a data set is a box-and-whisker plot. A box-and-whisker plot is a type of graphical display that shows the distribution of a set of data. It uses a box to represent the middle 50% of the data, with a line inside the box to represent the median. Whiskers extend from the box to show the range of the data outside the box.

A pie chart is best used for displaying proportions or percentages, and would not be suitable for showing the range of a data set.

A bar graph is best used for displaying categorical data, such as comparing the frequency of different categories, and would not be suitable for displaying the range of a data set.

A stem-and-leaf plot is useful for showing the distribution of a set of data, but may not be the best option for displaying the range of the data set.

Answer:

Step-by-step explanation:

\(\sqrt{2} cos x-1=0\\cos x=\frac{1}{\sqrt{2} } =cos (\frac{\pi }{4} ),cos (2\pi -\frac{\pi }{4} )\\cos x=cos(2n\pi +\frac{\pi }{4} ),cos(2n\pi +\frac{7\pi }{4} )\\x=2n\pi +\frac{\pi }{4} ,2n\pi +\frac{7\pi }{4} \\n=0\\x=\frac{\pi }{4} ,\frac{7\pi }{4}\)

The given expression expressed in the form (x+A)^2+B is (x - 6)² + 65

A = -6 and B = 65

From the question, we are to express the given expression in the form (x + A)^2+B by completing the square

The given expression is

x² -12x + 101

Using the completing the square method

x² -12x + 101

Divide the coefficient of x by 2 and then square it

The coefficient of x is -12

Dividing by 2, we get

-12/2 = -6

Squaring

(-6)²

Now, add and subtract this value from the expression

x² -12x + (-6)² + 101 - (-6)²

Then, we can write that

(x - 6)² + 101 - (-6)²

(x - 6)² + 101 - 36

(x - 6)² + 65

Thus,

The given expression expressed in the form (x+A)^2+B is (x - 6)² + 65

By comparison,

A = -6

and

B = 65

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Answer:

$\(45\)

Step-by-step explanation:

\(30\)% \(\mathrm{of}\) $\(150\)

\(=\frac{30}{100}\times 150\\\)

\(=\) $\(45\)

The third force is 1600 N backwards.  third force is the frictional force between the motorbike's tires and the road. It is pointing backwards, and its magnitude is equal to the difference between the two forces shown in the diagram.

The motorbike is traveling at a constant speed, so the net force acting on it is zero. This means that the third force must be equal in magnitude to the sum of the other two forces, but opposite in direction.

The two forces shown in the diagram are 2800 N forwards and 1200 N backwards. Therefore, the magnitude of the frictional force is 2800 N - 1200 N = 1600 N.

The direction of the frictional force is backwards, because it is opposing the motion of the motorbike. Therefore, the third force is 1600 N backwards.

Here is a breakdown of the steps involved in solving for the third force:

We are given that the motorbike is traveling at a constant speed.

This means that the net force acting on the motorbike is zero.

We are given the magnitudes of two of the forces acting on the motorbike.

The third force must be equal in magnitude to the sum of the other two forces, but opposite in direction.

Therefore, the magnitude of the frictional force is 2800 N - 1200 N = 1600 N.

The direction of the frictional force is backwards, because it is opposing the motion of the motorbike.

Therefore, the third force is 1600 N backwards.

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Answer:

Buffalo

Thats the answer because temp is decreasing back so 10 is higher plus lower than all

The simplified form of the expression 4x(x + 1) − (3x − 8)(x + 4) is -3x^2 - 4x - 32.

To simplify the expression 4x(x + 1) − (3x − 8)(x + 4), we can expand the parentheses and combine like terms.

Expanding the first term, we get 4x^2 + 4x.

Expanding the second term, we have -(3x)(x) - (3x)(4) - (-8)(x) - (-8)(4), which simplifies to -3x^2 - 12x - (-8x) - (-32), further simplifying to -3x^2 - 12x + 8x - 32.

Combining like terms, we obtain -3x^2 - 4x - 32.

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The completely factorized form of the expression q² - 4 is (q + 2)(q - 2).

Given the expression in the question:

q² - 4

To factorize the expression q² - 4 completely, we can use the formula for the difference of squares.

The difference of squares formula states that :

a² - b² can be factored as (a + b)(a - b).

Given that:

q² - 4

Replace 4 with 2²
q² - 2²

From this expression, let a = x and b = 2

a² - b² =  (a + b)(a - b)

q² - 2² = (q + 2)(q - 2)

Therefore, the factored form is (q + 2)(q - 2).

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Multiplication of the given matrix is not possible by definition of matrix multiplication.

Since, To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

We have to given that;

Expression for multiply,

⇒ [4, 0, -1, 2, -3, -1] x [0, 1, -3, 1]

Since, We can see that;

First matrix have order 1 x 6

And, Second matrix have order 1 x 4

We know that;

Matrix multiplication is possible when number of column in first matrix is same as number of rows in second matrix.

Hence, By given matrices we get;

Number of column in first matrix (6) ≠ number of rows in second matrix (1)

So, Multiplication of the given matrix is not possible by definition of matrix multiplication.

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9:16 -> 3:8

How?

Divide each side by 2 (the GCF).

10:12 -> 5:6

How?

Divide each side by 2 (the GCF).

20:16 -> 5:4

How?

Divide each side by 4 (the GCF).

24:36 -> 2:3

How?

Divide each side by 12 (the GCF).

Answer:

9: 16 for 9 to 16; is the simplest form for 9/16 cuz nothing can go into 9 and 16

5 : 6 for 10 to 12; cuz 10 divided by 2 is 5 and 12 divided by 2 is 6!

5: 4 for 20 to 16; cuz 20 divded by 4 is 5 and 16 divded by 4 is 4

lastly is 2:3 for 24 to 36; why? well it's ciz 24 divided by 12 is 2 and 36 divedde by 12 is 3

hope this helps and pls don't delate my answer!

Answer:

the slope is 3/5 so,

y=3/5x+3

Step-by-step explanation:

just solve for the slope and the coordinate point are gives you the b!

The calculated price per video game for store A is $1.79 per game

From the question, we have the following parameters that can be used in our computation:

The price per video game for store A is calculated as

Price per video game = Total price/Number of games

using the above as a guide, we have the following:

Price per video game = 8.95/5

Evaluate the quotient

So, we have

Price per video game = 1.79

Hence, the price per video game for store A is $1.79 per game

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1.1. Accumulated depreciation:

The accumulated depreciation for the machine bought on 1 July 2013 would be R150,000 as of 31 March 2016.

1.2. Machine realization:

The machine bought in 2013 was sold for R120,000 on 30 June 2015, resulting in a profit/loss on the sale of R10,000.

1.1. Accumulated Depreciation:

To calculate the accumulated depreciation, we need to determine the annual depreciation expense for each machine and then accumulate it over the years.

Machine bought on 1 July 2013:

Cost: R250,000

Depreciation rate: 20% per annum on cost

Depreciation expense for the year ended 31 March 2014: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2015: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2016: 20% of R250,000 = R50,000

Accumulated depreciation for the machine bought on 1 July 2013:

As of 31 March 2014: R50,000

As of 31 March 2015: R100,000

As of 31 March 2016: R150,000

1.2. Machine Realisation:

To record the sale of the machine bought in 2013, we need to adjust the machine's value and the accumulated depreciation.

Machine's original cost: R250,000

Accumulated depreciation as of 30 June 2015: R100,000

Net book value as of 30 June 2015:  

R250,000 - R100,000 = R150,000.

On 30 June 2015, the machine was sold for R120,000.

Realisation amount: R120,000

To record the sale:

Debit Cash: R120,000

Debit Accumulated Depreciation: R100,000

Credit Machine: R250,000

Credit Machine Realisation: R120,000

Credit Profit/Loss on Sale of Machine: R10,000 (difference between net book value and realisation amount).

These entries will reflect the appropriate balances in the ledger accounts and properly close off the accounts for the years ended 31 March 2016.

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Answer:

Around $1.47

Step-by-step explanation:

To find the unit rate you need to have a denominator of one. (5.89/4 = x/1)

All you have to do is divide 5.89 by 4 and you get 1.4725 and if you round that to the nearest 100th place you get 1.47.

So 1 once cost $1.47

I hope this helps, and have a great day!

There is a significant difference in the quality of the peaches between the two distributors because:

A confidence interval is a term that connote an estimate (plus or minus) the variation that may be seen in that specific estimate.

A 95% confidence interval implies that if a person do a research such as (two different distributors, e.g. WholeFruits and GreenGroce) and took 100 different samples and then compute a 95% confidence interval for each sample, it therefore means that about 95 of the 100 confidence intervals will hold the true mean value (μ).

See options below

We are 95% confident that the proportion of non sell-able items for Whole Fruits is anywhere between 0.064 and 0.156 LOWER than the proportion of non sell-able items for Green Grocer.

We are 95% confident that the proportion of non sell-able peaches for Whole Fruits is about -0.064 and 0.156.

We are 95% confident that the proportion of non sell-able items for Whole Fruits is anywhere between 0.156 LOWER and 0.064 HIGHER than the proportion of non sell-able items for Green Grocer.

We are 95% confident that the proportion of non sell-able peaches from Whole Fruits is anywhere between 0.064 and 0.156.

We are 95% confident that the proportion of non sell-able items for Whole Fruits is anywhere between 0.064 and 0.156 HIGHER than the proportion of non sell-able items for Green Grocer.

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Answer:

37.5

Step-by-step explanation:

divide 15 by 2/5

The left-hand side of the equation represents the logarithm of 64 with base x, and it is not possible to find a real value of x that satisfies the equation.

solve the equation logₓ(64) + 5 = 2, we can follow these steps:

Step 1: Move the constant term to the other side of the equation:

logₓ(64) = 2 - 5

logₓ(64) = -3

Step 2: Rewrite the equation in exponential form:

x^(-3) = 64

Step 3: Rewrite 64 as a power of x:

x^(-3) = x^6

Step 4: Set the exponents equal to each other:

-3 = 6

The equation -3 = 6 is not true, which means there is no real solution to the given equation.

Therefore, the equation logₓ(64) + 5 = 2 has no solution in the real number system.

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The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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Answer:

Mr. Alcazar baked 810 cookies.

Step-by-step explanation:

Given that Mr. Alcazar bakes 6 batches of 60 cookies and five batches of 90 cookies, to determine the amount of cookies that he cook, the following calculation must be performed:

(6 x 60) + (5 x 90) = X

360 + 450 = X

810 = X

Therefore, according to the calculation that has been made, Mr. Alcazar baked 810 cookies.

Answer:

A = 228 tickets

Step-by-step explanation:

We need to set up a system of equation to find the number of adult tickets sold, where A represents the adult tickets and S represents the student tickets.

Because the number of adult and student tickets together equals 506, we have A + S = 506.

Because there are 56 more student tickets than adult tickets we have A + 56 = S

And the way the system is already set up allows us to use substitution.

Thus, we have:

\(A + S=506\\A+56 = S\\\\A+A+56 =506\\2A+56=506\\2A=456\\\\A=228\\228+56=S\\278=S\)

The number of student tickets was not necessary to find in this problem, but I found anyway just in case you wanted check the work or wanted to prove the validity of the values.

Answer:

0> 1/2

Step-by-step explanation:

The zeros with each multiplicity are given as follows:

The factor theorem is used to define the functions, which states that the function is defined as a product of it's linear factors, if x = a is a root, then x - a is a linear factor of the function.

Considering the linear factors of the function in this problem, the zeros are given as follows:

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