A stone is dropped from the top of a cliff. The splash it makes when striking the water below is heard 4.1s later. The speed of sound in air is 343 m/s. How high is the cliff?

An image will be located at the focal point of a lens or mirror under specific circumstances.

When an object is placed at a specific distance from the lens or mirror, known as the object distance, and certain conditions are met, the resulting image will be formed exactly at the focal point.

For a lens, there are two scenarios in which the image can be located at the focal point:

When the object is placed at infinity: In this case, the incoming light rays from the object are parallel to each other. When these parallel rays pass through a converging lens, they will converge at a single point on the opposite side of the lens. This point is the focal point, and the image is formed precisely at that location.

When the object is placed at the focal point: If the object is placed exactly at the focal point of a converging lens, the light rays will become parallel after passing through the lens. As a result, no image will be formed on the other side of the lens. Instead, the light rays will continue to travel parallel to each other, making it impossible to locate the image anywhere other than at the focal point itself.

For mirrors, the situation is similar:

For a concave mirror: If the object is placed at infinity, the incoming parallel rays will reflect off the concave mirror and converge at the focal point. Therefore, the image will be located precisely at the focal point.

For a convex mirror: Since convex mirrors are diverging mirrors, the image formed by a convex mirror is always virtual and located on the same side as the object. As a result, it is not possible for the image to be located at the focal point of a convex mirror.

It is important to note that these conditions are specific and rely on the specific properties and characteristics of lenses and mirrors. In most practical situations, the object distance will not be at infinity or exactly equal to the focal length, resulting in the formation of images at different positions. The location and characteristics of the image will depend on the object distance and the type of lens or mirror being used.

In summary, an image will be located precisely at the focal point of a lens or mirror when the object is placed at infinity or at the focal point itself for a converging lens. For a concave mirror, an image will be formed at the focal point when the object is placed at infinity. However, for a convex mirror, the image formed will always be virtual and located on the same side as the object, and therefore, it will not be located at the focal point.

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Thus, a swinging pendulum has its greatest kinetic energy and least potential energy in the vertical position, in which its speed is greatest and its height least; it has its least kinetic energy and greatest potential energy at the extremities of its swing, in which its speed is zero and its height is greatest.

Answer:

Ted is correct

Explanation:

The equation for gravitational potential energy is PE = m·g·h

The equation for gravitational kinetic energy is KE = 1/2·m·v²

Where:

m = Mass of the object (The racing car)

g = Acceleration due to gravity

h = The height to which the object is raised

v = Velocity of motion of the object

From the principle of conservation of energy, energy can neither be created nor destroyed but changes from one form to another, we have;

Potential energy gained from location at height h = Kinetic energy gained as the object moves down the level ground

m·g·h = 1/2·m·v² canceling like terms gives

g·h = 1/2·v²

v = (√2·g·h)

If the speed is doubled, we have

2·v = 2× (√2·g·h) =  (√2·g·4·h)

Therefore, if 2·v = v₂ then v₂ =  (√2·g·4·h)

Since g, the acceleration due to gravity, is constant, it means that the initial  height must be multiplied or increased 4 times to get the new height, that is we have;

v₂ =  (√2·g·4·h) = (√2·g·h₂)

Where:

4·h = h₂

Which gives;

v₂² = 2·g·h₂

1/2·v₂² = g·h₂

1/2·m·v₂² = m·g·h₂ Just like in the first relation

Therefore, Ted is correct s they need to go up four times the initial height to double the speed.

The correct option is 20000 kg m /s.

What is Momentum ?

Momentum is a concept in physics that describes an object's tendency to continue moving in its current direction at a constant speed. It is a vector quantity, meaning it has both magnitude and direction. The momentum of an object is defined as the product of its mass and velocity, and is represented by the equation: p = mv, where p is momentum, m is mass, and v is velocity.

In simple terms, momentum can be thought of as the "motion" of an object, and the larger the mass and velocity of an object, the greater its momentum. Momentum is a conserved quantity, which means that the total momentum of a system remains constant unless acted upon by an external force.

Given , Mass = 1000kg

Speed = 20 m/s

momentum = mv = 20000 kg m /s

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Answer:  

Mass = Size, Weight = Heaviness

Explanation:

Mass is how much matter that is in an object

Weight is a measurement that indicates how heavy something

2

Explanation:

2 times 5 is 10/ 20+10=30

The time taken for the car to accelerate to the given speed is 10 seconds.

The acceleration of the car is the change in the velocity of the car with time.

a = Δv/Δt

where;

The initial velocity of the car = 0 mi/hr = 0 m/s

The final velocity of the car = 60 mi/hr = 26.82 m/s

The acceleration of the electric car = (26.82 m/s - 0 m/s) / 30 s = 0.89 m/s²

When the final velocity of the car = 80 mi/hr = 35.76 m/s, the time taken to reach the speed is calculated as follows;

v = u + at

where;

t = (v - u)/a

t = (35.76 - 26.82) / 0.89

t = 10 s

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Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body. In the attachment we can see a free body diagram which is a schematic of the forces without the details of the bodies.

               N-W = 0

               fr = ma

where N is the normal, W the weight of the body, fr the friction force, m the mass and a the acceleration

The friction force is a macroscopic representation of the interactions between the two surfaces, it is given by the expression

             fr = μ N

where μ is the coefficient of friction between the two surfaces.

We substitute

             μ mg = m a

             a = μ g

Kinematics study the movement of bodies, looking for relationships between position, speed and acceleration.

             v= v₀ – at t

In this case they give tables and graphs with the values ​​of time and speed, where we can see that the relationship is a straight line that has as equation

            y = ax +b

Where y is the dependent variable, x is the independent variable, a is the slope, and b is the cutoff point.

If we relate the two equations:

          a = mug

          μ = \(\frac{a}{g}\)

Using linear regression the slope and cutoff point is:

The man.

The slope is a = -0.8 m/s² and the cut-off point b= 4.86 m/s.

Let's calculate the coefficient of friction.

          μ =  \(\frac{0.8}{9.8}\)  

          μ  = 0.082

The child.

The slope is a = -0.98 m/s² and the cut-off point b= 4.72 m/s.

We calculate the coefficient of friction.

          μ  = \(\frac{0.98}{9.8}\)  

          μ  = 0.1

The relationship between the two coefficients of friction is

        \(\frac{\mu_{man} }{\mu_{boy}} = \frac{0.082}{0.1}\)  

         \(\frac{\mu_{man}}{\mu_{boy}} = 0.82\)

The results are very exact since there are values ​​of several points in the route and the graphical analysis gives the best possible value for all the points.

There are some variables not taken into account, one of the most important is friction with the wind and wind speed.

In conclusion using Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:

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What characteristics have led humanity to convert most temperate grasslands to use for agriculture or grazing land?

When trees receive sufficient rainfall and grow quickly, they do not overproduce. Because nutrients decompose rapidly, the growing season is relatively long.

Explanation: Brainliest please

Using the principle of conservation of energy, we can calculate the force constant of a spring and the period of oscillation of a weight attached to the spring. However, to solve for the mass of the weight, we need more information about its oscillation.

When the weight W is suspended from the spring and reaches its equilibrium position, the potential energy stored in the spring is equal to the gravitational potential energy of the weight W:

\(1/2 k x^2\)= m g h

where k is the force constant of the spring, x is the displacement of the spring from its equilibrium position (31.9 cm in this case), m is the mass of the weight W, g is the acceleration due to gravity, and h is the height of the weight W above the ground (which we can assume is zero).

We can solve for the force constant of the spring:

k = (2 m g h) / \(x^2\)

Next, we can find the period of oscillation of the spring when the weight W is pulled down to a position 55.1 cm below its equilibrium position. The period of oscillation is given by:

T = 2π √(m / k)

where m is the mass of the weight W and k is the force constant of the spring that we just calculated.

Finally, we can use the period of oscillation to find the frequency of oscillation:

f = 1 / T

We now have expressions for the force constant of the spring, the period of oscillation, and the frequency of oscillation, all in terms of the mass of the weight W, which is unknown.

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we can estimate it by assuming that the radius is 1 meter. In that case, the moment of inertia would be I = 8.3 N.m * 1 meter / 62 rad/s2 ≈ 0.13 kg·m2.

Radius is a line segment that connects two points on the circumference of a circle, with one endpoint at the centre of the circle and the other endpoint at any point on the circumference. Radius is also the length of this line segment. It is an important concept in geometry, trigonometry, and calculus, and is used to measure the size and shape of circles, as well as other curved figures. Radius is typically represented by the letter ‘r’, and the length of a radius is half the circumference of the circle.

The moment of inertia of a ceiling fan is calculated using the equation I = F * radius / angular acceleration, where F is the applied force, radius is the distance from the center of the fan to the point where the force is applied, and angular acceleration is the angular acceleration of the fan.

In this case, the moment of inertia is calculated as I = 8.3 N.m * radius / 62 rad/s2. Since the radius is not given, we cannot calculate the exact moment of inertia.

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Generally, only half back and ends are eligible to catch or receive passes from the quarterback in football.

A halfback (HB) is an offensive position in American football. His duties involve lining up in the backfield and carrying the ball on most rushing plays

Half back can catch the ball from the backfield on short passing plays as they are an receiver.

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Given our knowledge of the sport, the position amongst those listed that are eligible to catch or receive passes is the Running back position.

Therefore, there is a wide range of positions that are eligible to receive passes from the quarterback, including all those that are not offensive positions. Of those listed, the only non-offensive position is the Running back.

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If a thin thread is placed between a screen and a bright source of light, a pattern of of parallel light and dark strips appears on the screen. This phenomenon is called the diffraction of light.

When a thin thread comes in the path of light waves, it obstructs the upfront of the light wave causing the change in the phase difference of the wave. Overlapping of these different waves of different phase differences cause the dark and light pattern appearance on the wall.  On the other hand, thin thread also cast a thin shadow due to the obstruction in the path of light. Pattern on the wall depends on the phase difference in the wave-upfront.

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Answer:

yes

Explanation:

this is simple

the horizontal line is adjacent

the vertical line is opposite

recall that cos x=adj/hyp

adj=hyp(cos x)

while opp=hyp(sin x)

You push your 0.70-kg pillow across your bed with a constant force of 19 n. The bed provides a frictional force of 6.0N in part a. The acceleration of the center of mass of the pillow is  18.58 m/s.

To find the acceleration of the middle of a mass of the pillow, we will observe Newton's 2nd regulation of motion, which states that the acceleration of an object is directly proportional to the internet force performing on it and inversely proportional to its mass.

In this situation, the pillow is pushed with a consistent pressure of 19N, whilst the mattress provides a frictional pressure of 6.0 N in the opposite route. The internet forces acting on the pillow is the difference between these two forces:

Net pressure = Applied force - Frictional pressure = 19 N - 6.0 N = 13 N.

Now, we can use Newton's 2d law:

Net force = Mass × Acceleration.

Rearranging the equation to clear up for acceleration:

Acceleration = Net pressure / Mass.

Substituting the values:

Acceleration = 13 N / 0.70 kg.

Simplifying the expression:

Acceleration ≈ 18.57 m/s².

Therefore, the acceleration of the middle of mass of the pillow is about 18.57 m/s².

This method that for every kilogram of mass in the pillow, it stores a force of 18.57 N, ensuing in an acceleration of 18.58 m/s². The acceleration represents the price of alternate of pace, indicating how speedy the pillow's pace and route are converting under the effect of the net force.

The higher the net pressure or the decrease in the mass, the more the acceleration. In this case, the pillow stories a sizeable acceleration due to the notably small mass and the massive net pressure applied.

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Answer:Velocity can be represented by an arrow, with the length of the arrow representing speed and the way the arrow points representing direction. Objects have the same velocity only if they are moving at the same speed and in the same direction. ... The SI unit for velocity is m/s, plus the direction the object is traveling.

According to the static equilibrium, the tension in the wire would be 24.62 N

Since all parts of the system are at rest (Ftotal = Ttotal = 0), we will be using static equilibrium. An object is said to be in a state of static equilibrium when all of the forces acting on it are in equilibrium with one another and the object is not moving in regard to the relative plane.

Thus, the tension in the wire would be:

                                           2Fy = m × g

Fy = (m × g) ÷ 2

Fy = (0.5 × 9.8) ÷ 2

Fy = 2.45 N

                                       Sinθ = 2 ÷ √(4+400)

F = Fy ÷ Sinθ

F = 2.45 ÷ 0.0995

F = 24.62 N

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(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge. (b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

The electric field at a point due to a point charge is given by the equation E = k * q / r², where E is the electric field, k is the electrostatic constant (k = 9 x 10⁹Nm² /C² ), q is the charge, and r is the distance between the charges.

(a) To find the electric field at a point 5.0 cm from the negative charge, we need to calculate the electric field due to both charges and then subtract the electric field due to the positive charge from the electric field due to the negative charge.

The electric field due to the negative charge (q2) is given by E2 = k * q2 / r², where q2 = -6.4 x 10⁻⁸  C and r = 5.0 cm = 0.05 m.

Plugging in the values, we get E2 = (9 x 10 Nm² /C² ) * (-6.4 x 10 C) / (0.05 m)² = -2.58825 x 10⁵ N/C.

The negative sign indicates that the electric field due to the negative charge is directed towards the negative charge.

(b) To find the force on an electron placed at that point, we need to calculate the force due to both charges and then subtract the force due to the positive charge from the force due to the negative charge.

The force between two charges is given by the equation F = k * |q1 * q2| / r², where F is the force, q1 and q2 are the charges, and r is the distance between the charges.

The force on the electron due to the negative charge (q2) is given by F2 = k * |q2 * e| / r², where q2 = -6.4 x 10⁻⁸ C, e is the charge of an electron (e = -1.6 x 10⁻¹⁹ C), and r = 5.0 cm = 0.05 m.

Plugging in the values, we get F2 = (9 x 10⁹ Nm²/C²) * |-6.4 x 10⁻⁸ C * -1.6 x 10⁻¹⁹ C| / (0.05 m)² = 2.58825 x 10⁻⁵ N.

The positive sign indicates that the force on the electron is directed away from the negative charge, which is towards the positive charge.

So, the answers to the given questions are:

(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge.

(b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

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When a switch is closed, it completes the circuit, allowing electricity to flow through it. In a circuit with multiple bulbs, the amount of electricity that flows through each bulb depends on the resistance of the bulb.

After the switch is closed, the brightness of the bulbs will depend on their individual resistances. If all three bulbs have the same resistance, then they will all be equally bright. However, if one of the bulbs has a higher resistance than the others, it will be dimmer than the other two bulbs. Conversely, if one of the bulbs has a lower resistance than the others, it will be brighter than the other two bulbs.

In conclusion, the brightness of the bulbs after the switch is closed will depend on their individual resistances. If all three bulbs have the same resistance, they will be equally bright, but if one bulb has a higher or lower resistance than the others, it will be either dimmer or brighter than the other bulbs.

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The electric field inside the non-conductor sphere would be different. For a non-conductor sphere, the charge is distributed uniformly throughout the sphere, rather than being concentrated on the surface as in a conductor.

The electric field outside a uniformly charged solid sphere (conductor or non-conductor) is given by:

E = kQ/R^2

where k is the Coulomb constant, Q is the total charge on the sphere, and R is the radius of the sphere.

For the given solid metal sphere with a radius of 2.00 m and a total charge of -4.20 μC, we have:

E = (9.0 × 10^9 N·m^2/C^2) × (-4.20 × 10^-6 C) / (2.00 m)^2

E ≈ -9.86 N/C

The electric field is negative, which indicates that the direction of the electric field is inward, toward the center of the sphere.

For a solid non-conductor sphere that is uniformly charged throughout, the electric field outside the sphere can still be calculated using the same formula. The total charge Q on the sphere and the radius R of the sphere would be the same as for the metal sphere. Therefore, the magnitude of the electric field outside the solid non-conductor sphere would be the same as for the metal sphere:

E = kQ/R^2

E = (9.0 × 10^9 N·m^2/C^2) × (-4.20 × 10^-6 C) / (2.00 m)^2

E ≈ -9.86 N/C

However, the electric field inside the non-conductor sphere would be different. For a non-conductor sphere, the charge is distributed uniformly throughout the sphere, rather than being concentrated on the surface as in a conductor. Therefore, the electric field inside the non-conductor sphere would be zero. This is because the electric field due to one element of charge is cancelled by the electric field due to an opposite element of charge located on the opposite side of the sphere.
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Answer:

multiply that and divided by 45

Answer:

4.444444444 km

Explanation:

200/45=4.444444444

The bus travels 4.444444444 kilometers in a minute

a star is in a circular orbit around a supermassive black hole at the center of a distant galaxy, and the  from the central black hole to the star is 1000 AU and the star orbits once every 10 years.The mass of the black hole can be calculated using the formula: {eq}M = \frac{v^2 r}{G} {/eq}

Where, v = velocityr = radius of the orbitG = Gravitational constant{eq}G = 6.67 \times 10^{-11}\;m^3\;kg^{-1}\;s^{-2} {/eq}We have to convert 1000 AU to meters. 1 AU is equal to 149.6 × 10⁹ meters. So 1000 AU is equal to 149.6 × 10⁹ × 1000 meters. Therefore r = 149.6 × 10⁹ × 1000 meters = 1.496 × 10¹² distant , the velocity of the star, {eq}v = \frac{2 \pi r}{T} {/eq}Where, T is the period of the orbit.T = 10 years = 10 × 365 × 24 × 3600 = 315360000 seconds

So, {eq}v = \frac{2 \pi \times 1.496 \times 10^{12}}{315360000} {/eq} = 2.98 × 10⁴ m/sSubstituting the values of v, r, and G in the equation above, we get:{eq}M = \frac{(2.98 \times 10^4)^2 \times 1.496 \times 10^{12}}{6.67 \times 10^{-11}} {/eq}= 1.44 × 10⁴ solar massesTherefore, the mass of the black hole is 1.44 × 10⁴ solar masses (main answer).Explanation:In summary, to calculate the mass of a black hole, the formula M = v²r/G must be used.

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Answer:

Disadvantage:

Answer:

It sounds great mate :) very well written

Explanation:

Answer:

1). Average speed = 1.5 m per second

2). Average velocity = 1.5 m per second

Explanation:

1). Since, speed is a scalar quantity

   Therefore, average speed of the trip = \(\frac{\text{Total distance covered}}{\text{Total time taken}}\)

    From the graph attached,

   Total distance covered = 10 + 10 + 20 + 0 + 20 + 30

                                           = 90 meters

   Total time taken = 60 seconds

    Average speed = \(\frac{90}{60}\)

                               = 1.5 meter per second

2). Velocity is a vector quantity.

    Therefore, average velocity = \(\frac{\triangle d}{\triangle t}\)

                                                   = \(\frac{d_{60}-d_0}{60-0}\)

                                                   = \(\frac{90-0}{60-0}\)

                                                   = 1.5 meter per second                        

Answer:

a

Explanation:

closed syteym m if the object

Answer: The law of conservation of energy is a physical law that states energy cannot be created or destroyed but may be changed from one form to another. Another way of stating this law of chemistry is to say the total energy of an isolated system.

Explanation:

Answer:

the sun gives off energy to the color panel

Answer:

28.8kg

Explanation:

h1=8m

h2=2m

h2-h1=6m

k=48 N/m

g=10m/(s^2)

w=F

10m=6*48

m=28.8kg

A boat travelling through the sea while being affected by two forces resulted in the following calculations: acceleration = 0.2, distance = 10 meters, and final velocity = 2 m/s.

Newton's Second Law of Motion is given by this formula;

acceleration=\(\frac{Netforce}{mass}\)

Acceleration is the rate of change in both the direction and speed of velocity over time. So when something moves faster or more slowly in a straight line, it is referred to as pushed.

A metre per secondly per second (m/s2) is used to measure acceleration. Definition. The snewton is the unit of force responsible for producing an accelerating of one m / s2 per second when applied to a mass about one kilogram.

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