a stone pyramid in egypt has a square base that measures 140 m on each side. the height is 91 m. what is the volume of the pyramid?

\(e-\frac{1}{e} +\frac{4}{3} 0r 3.687\)  is the value when the equation is to integrate with respect to x or y

we integrate with respect to x

Area = \(\int\limits^b_a{(f(x)-g(x))} \, dx\)

       = \(\int\limits^1_-1{e^{x}-x^{2} +1 } \, dx\)

        =\(e^{x} -\frac{x^{3} }{3} +x\)

   substitute 1 and -1 in place of x

  = \((e-\frac{1}{3}+1-\frac{1}{e} -\frac{1}{3} +1)\)

  = \(e-\frac{1}{e} + \frac{4}{3} or 3.6837\)

The diagram was attached in the given below.

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Answer:

Let's actually find the line of best fit...

m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)

m=(11*836-130*55)/(11*385-3025)

m=2046/1210  

m=93/55

b=(Σy-93Σx/55)/n

b=(55Σy-93Σx)/(55n)

b=(7150-5115)/(55*11)

b=185/55, so the line of best fit is:

y=(93x+185)/55

A)  The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.

Which means that those who do not practice at all will win about 3.36 times

B) y(13)=(93x+185)/55

y(13)≈25.34

So after 13 months of practice one would expect to win about 25.34 times.

Each bus can carry 14 students and each van can carry 6 students.

Let's assume that a van can carry 'v' students.

Let's assume that a bus can carry 'b' students.

Using this notation, we can set up the following system of equations:

For the first high school:

8v + 9b = 228

For the second high school:

4v + 5b = 124

We have two equations and two unknowns, so we can solve for 'v' and 'b'.

To do this, we can start by solving the second equation for 'b':

5b = 124 - 4v

b = (124 - 4v)/5

We can substitute this expression for 'b' into the first equation:

8v + 9((124 - 4v)/5) = 228

Multiplying both sides by 5 to eliminate the fraction:

40v + 9(124 - 4v) = 1140

Distributing the 9:

40v + 1116 - 36v = 1140

Simplifying:

4v = 24

v = 6

Substituting this value of 'v' into the equation for 'b':

5b = 124 - 4(6)

b = 14

Therefore, a van can carry 6 students, and a bus can carry 14 students.

So the answer is: Each bus can carry 14 students and each van can carry 6 students.

Answer:

2.52

Step-by-step explanation:

Given data :

\(9\sqrt{2} =2x^{2}\)

It can be solved as:

\(9\sqrt{2} =2x^{2} \\\frac{9\sqrt{2}}{2} =x^{2} \\\frac{12.72}{2} =x^{2} \\6.36=x^{2} \\x=\sqrt{6.36} \\x=2.52\)

Therefore, value of x will be 2.52

(a) The test statistic and P-value:The given information is provided as follows:σ1 = 1.6 and σ2 = 1.3The hypothesis test is defined as follows: H0: μ1 − μ2 = 0Ha: μ1 − μ2 > 0The significance level is α = 0.01.The two-tailed test for the difference between two means is given by:

(x1 ¯-x2 ¯)-(μ1-μ2)/sqrt[s1^2/n1+s2^2/n2]=t where s1^2 and s2^2 are variances of the sample 1 and sample 2 respectively. From the question, the sample size n1 = 27, and sample size n2 = 32.

Substitute the given values of n1, n2, σ1, and σ2 into the formula above to calculate the value of the test statistic:

t = [(92.7 − 87.4) − (0)] / √[(1.6^2 / 27) + (1.3^2 / 32)] = 2.28

The P-value is P(t > 2.28) = 0.013.

Hence the test statistic is 2.28 and the P-value is 0.013.The appropriate conclusion would be:Reject H0. The data suggests that the difference in average tension bond strengths exceeds 0. The P-value of 0.013 is less than the significance level α = 0.01.

(b) The probability of a type II error for the test of part (a) when μ1 − μ2 = 1:The type II error occurs when we fail to reject the null hypothesis when it is actually false. It is denoted by β.To calculate β, we need to determine the non-rejection region when the alternative hypothesis is true.

The non-rejection region is given by:t ≤ tc where tc is the critical value of t at the 0.01 level of significance and (n1 + n2 – 2) degrees of freedom.From the t-tables, tc = 2.439.

To calculate β, we need to find the probability that t ≤ tc when μ1 − μ2 = 1. Let d = μ1 − μ2 = 1.

Then,β = P(t ≤ tc; μ1 − μ2 = d) = P(t ≤ 2.439; μ1 − μ2 = 1).

Now, we have t = [(x1 ¯-x2 ¯) - (μ1-μ2)]/ sqrt [s1^2/n1 + s2^2/n2] = (x1 ¯-x2 ¯-d)/sqrt [s1^2/n1 + s2^2/n2]

Hence,P(t ≤ 2.439; μ1 − μ2 = 1) = P[(x1 ¯-x2 ¯)/ sqrt [s1^2/n1 + s2^2/n2] ≤ (2.439 − 1)/sqrt [(1.6^2/27) + (1.3^2/32)]] = P(z ≤ 0.846) = 0.7998,

where z is the standard normal distribution variable.

Therefore, the probability of a type II error for the test of part (a) when μ1 − μ2 = 1 is 0.7998.

(d) How would the analysis and conclusion of part (a) change if σ1 and σ2 were unknown but s1 = 1.6 and s2 = 1.3?The analysis would be done using the t-distribution, since σ1 and σ2 are not known and the sample size is small (n1 = 27 and n2 = 32). The hypothesis test and the test statistic are the same as in part

(a).However, the standard errors should be replaced with the estimated standard errors using the sample standard deviations s1 and s2 as follows:SE = sqrt [(s1^2/n1) + (s2^2/n2)] = sqrt [(1.6^2/27) + (1.3^2/32)] = 0.462.The t-value is calculated as:

t = [(x1 ¯-x2 ¯)-(μ1-μ2)]/SE = [(92.7 − 87.4) − (0)] / 0.462 = 11.48.The P-value is P(t > 11.48) < 0.0001. Therefore, the conclusion is the same as in part (a): Reject H0.

The data suggests that the difference in average tension bond strengths exceeds 0.

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Answer:

the diameter will be 12 cm

Step-by-step explanation:

have a nice day :)

Answer:

\(12 cm\)

Step-by-step explanation:

\(Diameter=Radius ~\) × \(2\)

\(= 6\) × \(2\)

\(= 12cm\)

--------------------------

hope it helps...

have a great day!!

Answer:

25/9 = 2 7/9 = 2.7777777778

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer: It’s 4

Step-by-step explanation:

Prism has a length of 18 centimeters, and a width of 10 centimeters, the height of the rectangular prism is 14 centimeters.

The first step to solving this problem is to set up a system of equations to represent the surface area of the composite figure. The surface area of the rectangular pyramid is 1/2 × 18 × 10 × 12 = 900 square centimeters, and the surface area of the rectangular prism is 2 × 18 × 10 + 2 × 10 × x = 360 + 20x square centimeters.

The total surface area of the composite figure is 844 square centimeters, so 900 + 360 + 20x = 844. Solving for x, we get x = 14.

The second step is to check our answer. The surface area of the rectangular pyramid is 900 square centimeters, the surface area of the rectangular prism is 360 + 20(14) = 680 square centimeters, and the total surface area of the composite figure is 900 + 680 = 1580 square centimeters. This matches the given surface area of 844 square centimeters, so our answer is correct.

Therefore, the height of the rectangular prism is 14 centimeters.

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Answer:

384800 square centimeters (cm²); 3.848 × 107 square millimeters (mm²); 1.48572E-5 square miles (mi²); 46.0217 square yards (yd²)

Step-by-step explanation:

Answer  x = -10

Step-by-step explanation:

 Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     10-4*x-(50)=0 

STEP1:Pulling out like terms

 1.1     Pull out like factors :

   -40 - 4x  =   -4 • (x + 10) 

Equation at the end of step1:

STEP2:

Equations which are never true:

 2.1      Solve :    -4   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

 2.2      Solve  :    x+10 = 0 

 Subtract  10  from both sides of the equation : 

                      x = -10

One solution was found :

 x = -10

Answer:

  m∠B ≈ 51.5°

Step-by-step explanation:

A triangle solver can find this answer simply by entering the data. If you do this "by hand," you need to first find length BC using the Law of Cosines. Then angle B can be found using the Law of Sines.

The Law of Cosines tells us ...

  a² = b² +c² -2bc·cos(A)

  a² = 21² +13² -2(21)(13)cos(91°) ≈ 619.529

  a ≈ 24.8903

The Law of Sines tells us ...

  sin(B)/b = sin(A)/a

  B = arcsin(sin(A)×b/a) = arcsin(sin(91°)×21/24.8903)

  B ≈ 57.519°

The measure of angle B is about 57.5°.

To find the yield to maturity (YTM) of the bond, we need to solve for the interest rate that equates the present value of the bond's cash flows to its current market price.

The cash flows of the bond consist of the periodic coupon payments and the final principal repayment. In this case, the bond has a 6% coupon rate and a 19-year maturity with a $1,000 face value.

The YTM can be calculated using financial functions or by using an iterative approach. Here, I will demonstrate the iterative approach using the Newton-Raphson method to solve for YTM:

Step 1: Set the parameters and initial guess

Face value (F) = $1,000

Coupon rate (C) = 6% = 0.06

Maturity (N) = 19 years

Market price (P) = $986

Initial guess for YTM (r) = 0.06 (6%)

Step 2: Set up the equation to solve

The present value of the bond's cash flows can be calculated as follows:

P = C * (1 - \((1 + r)^{(-N)}\)) / r + F / \((1 + r)^N\)

Step 3: Iterate to find the YTM

Use the Newton-Raphson method to iteratively solve for YTM until the equation is satisfied.

Repeat the following steps until convergence is achieved:

   Calculate the present value of the bond's cash flows using the current YTM guess.

   Calculate the derivative of the equation with respect to YTM.

   Update the YTM guess using the formula:\(r_new = r - (P - calculated_present_value) / derivative\)

Continue iterating until the difference between the current and previous YTM guesses is negligible (i.e., convergence is achieved).

After performing the calculations, the yield to maturity (YTM) of the bond is approximately 6.11%.

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Answer:

the part of the male private part that produces sperm is the testicles

Edit:
i just realized i answered the wrong question

The null hypothesis (H_0) and alternative hypothesis (H_1) for the given statement are: A. H_0: μ < 15, H_1: μ ≥ 15.

In the given statement, the claim is about the standard deviation of IQ scores of statistics students. The null hypothesis (H_0) represents the claim being tested, while the alternative hypothesis (H_1) represents the opposite or alternative claim.

The statement states that the standard deviation is at most 15. This implies that the population mean (μ) could be less than 15. Hence, the null hypothesis (H_0) is μ < 15, indicating that the mean is less than 15.

The alternative hypothesis (H_1) would then be the opposite claim, stating that the mean is greater than or equal to 15. Therefore, the alternative hypothesis (H_1) is μ ≥ 15, indicating that the mean is greater than or equal to 15.

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Answer:

24.59 m/s

Step-by-step explanation:

Average speed(m/s) = distance travelled(m) / time taken(s)

Distance = 220 miles

220 miles = 354,056 meters

Time taken = 4 hours

4 hours = 14,400 seconds

Average speed = distance travelled / time taken

= 354,056 / 14,400

= 24.59 meter/seconds

= 24.59 m/s

We will have the following:

We can see that the function follows a path of exponential decay, so the expression that models it is:

The calculated value of the test statistic is approximately 6.40.

To test the hypothesis that job satisfaction is the same at Baruch College and Brooklyn College, we can use a two-sample t-test.

The null hypothesis (H0) assumes that the means of the two populations are equal, while the alternative hypothesis (Ha) assumes that the means are not equal.

H0: μ1 = μ2 (Mean job satisfaction at Baruch College is equal to mean job satisfaction at Brooklyn College)

Ha: μ1 ≠ μ2 (Mean job satisfaction at Baruch College is not equal to mean job satisfaction at Brooklyn College)

We can calculate the test statistic using the formula:

t = (x1 - x2) / sqrt((s1^2 / n1) + (s2^2 / n2))

where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, n1 and n2 are the sample sizes.

Given the data:

Baruch College: mean job satisfaction score (x1) = 83.0, standard deviation (s1) = 15, sample size (n1) = 150.

Brooklyn College: mean job satisfaction score (x2) = 73.0, standard deviation (s2) = 12, sample size (n2) = 100.

Calculating the test statistic:

t = (83.0 - 73.0) / sqrt((15^2 / 150) + (12^2 / 100))

t = 10 / sqrt(1 + 1.44)

t ≈ 10 / sqrt(2.44)

t ≈ 10 / 1.561

t ≈ 6.40

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The level of measurement for a study that collects data on the number of traffic tickets is ratio. Ratio level of measurement is the highest form of measurement that can be used for statistical analysis. The data collected for this level of measurement have all the properties of the nominal, ordinal, and interval levels of measurement.

In the case of the number of traffic tickets, the data collected for this level of measurement will have a true zero point, which indicates the absence of the entity being measured, that is, zero traffic tickets.

The ratio level of measurement enables the calculation of statistical parameters such as means, variances, and standard deviations.

Additionally, arithmetic operations such as addition, subtraction, multiplication, and division can be performed on the data collected at the ratio level of measurement.

Nominal, ordinal, and interval levels of measurement are lower forms of measurement compared to ratio level of measurement.

Nominal level of measurement involves categorizing objects into groups while ordinal level of measurement has data that can be ranked. Interval level of measurement has data that can be measured on a scale that contains equal units

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Angle A in triangle ABC is approximately 76 degrees. So, correct option is A.

In a right triangle, the side opposite the right angle is called the hypotenuse, and the other two sides are called the legs. Let's consider triangle ABC, where angle B is the right angle, AC is the hypotenuse, and BC is one of the legs.

We are given that AC = 33 and BC = 32. To find angle A, we can use trigonometric ratios. In this case, we can use the sine function.

The sine of angle A is defined as the ratio of the length of the side opposite angle A (BC) to the length of the hypotenuse (AC):

sin(A) = BC / AC

Substituting the given values, we have:

sin(A) = 32 / 33

Using the inverse sine function (sin⁻¹), we can find the value of angle A:

A = sin⁻¹(32 / 33)

Using a calculator, we find that angle A is approximately 75.85 degrees. Rounding off to the nearest angle we get 76 degrees.

Therefore, angle A in triangle ABC is approximately 76 degrees. So, correct option is A.

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The mode of the sample can be larger, smaller or equal to the mode of the population, but must not be equal to the mean of the population or 500.

The mode of a sample is the value that occurs most often in the sample. The mode of a population is the value that occurs most often in the population. In a random sample, the mode of the sample can be larger, smaller or equal to the mode of the population. This is because the sample is a subset of the population and the values in the sample may not be the same as the values in the population.

The formula for calculating the mode of a sample is:

Mode = Number of times the most frequent value appears / Total number of values

For example, in a sample of 50 items from a population of 500, the mode of the sample could be equal to the mode of the population, if the most frequent value in the sample appears the same number of times as it does in the population. However, if the most frequent value in the sample appears more or less times than it does in the population, then the mode of the sample will not be equal to the mode of the population.

The mode of the sample must not be equal to the mean of the population, since the sample is a subset of the population and the values in the sample may not be the same as the values in the population. Furthermore, the mode of the sample must not be 500, since the sample is not the entire population.

The mode of the sample can be larger, smaller or equal to the mode of the population, but must not be equal to the mean of the population or 500.

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The magnitude of the vector sum of the four vectors = 278.158M

What is Magnitude?

The magnitude or size of a mathematical item defines whether it is larger or smaller than other objects of the same kind in mathematics. Formally speaking, the size of an object is the displayed outcome of an ordering—of the class of objects to which it belongs.

A = 82(cos 64 degree x +sin 64 degree y )

= 35.946 x +73.701y

B = 82 X

C= 82 Xx

D= 82 x (cos 64 degree x +sin 64 degree y)

= 35.946 x +73.701y

net = A+B+C+D

= X (35.946+82+82+35.946) + (2*73.701)

=235.892 X + 147.402Y

Magnitute = 278.158m

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The point slope from the line with slope -3/7 that passes through the point (5,8) is y-8 = -3/7 ( x-5).

Two crucial constants are present in a linear function: the slope, which is represented by the letter m, and the y-intercept, which is represented by the letter b. Y = m x + b is the slope-intercept equation's formula. The point-slope equation is a different manner that we can occasionally express the equation of a line. It reads as follows y-y₀ = m(x-x₀).

Given that :

Slope m = -3/7

passes through the point p ( 5, 8 )

Equation is  y-y₀ = m(x-x₀)

y-8=-3/7 ( x-5)

here the point slope is y-8=-3/7 ( x-5)

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The solution to the initial value problem is: y(x) = 2 * e^(4x) + x * e^(4x)

To find a general solution to the differential equation y′′ - 4y′ + 29y = 0, we first note that this is a second-order linear homogeneous differential equation with constant coefficients. The characteristic equation is given by:

r^2 - 4r + 29 = 0

Solving for r, we get a quadratic equation with complex roots:

r = 2 ± 5i

Now, we use these roots to form a general solution:

y(x) = e^(2x) (C1 * cos(5x) + C2 * sin(5x))

For the initial value problem y′′ - 8y′ + 16y = 0, y(0) = 2, y′(0) = 9, we again have a second-order linear homogeneous differential equation. The characteristic equation is:

r^2 - 8r + 16 = 0

This time, we get a repeated real root:

r = 4

So, the general solution is:

y(x) = C1 * e^(4x) + C2 * x * e^(4x)

Now, we apply the initial conditions:

y(0) = 2 = C1 * e^(0) + C2 * 0 * e^(0) => C1 = 2

y′(x) = C1 * 4 * e^(4x) + C2 * (e^(4x) + 4x * e^(4x))

y′(0) = 9 = C1 * 4 * e^(0) + C2 * e^(0) => 9 = 2 * 4 + C2 => C2 = 1

Thus, the solution to the initial value problem is:

y(x) = 2 * e^(4x) + x * e^(4x)

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Your answer should be:She can make 92 key chains with the yarns she has.

Step-by-step explanation

1. Let's add and see the total of yarns she has!

36 + 216 + 24 = 276

2. Let's divide the total we got in 1 by the yard she needs to make one key chain!

276 ÷ 3 = 92

3. Your answer should be 92.

The distance from the base of the stand to the campfire is 285.6 feet.

The angle of depression of 35 degrees.

Let's denote the distance from the base of the stand to the campfire as "x."

Since we know that,

The values of all trigonometric functions depending on the ratio of sides in a right-angled triangle are defined as trigonometric ratios. The trigonometric ratios of any acute angle are the ratios of the sides of a right-angled triangle with respect to that acute angle.

Using the tangent function, we have:

tan(35 degrees) = opposite/adjacent

tan(35 degrees) = 200/x

To find the value of x, we can rearrange the equation:

x = 200 / tan(35 degrees)

x ≈ 200 / 0.7002

x ≈ 285.6 feet

Therefore, the distance from the base of the stand to the campfire is 285.6 feet.

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The length of side of the rectangle is 6 mm

Since the rectangle has an area of A = 36 mm² and the rectangle has all its sides the same length, then, it is a square. We know that the area of a square A = L² where L = length of sides of square.

Since we require the length of sides of the rectangle, we make L subject of the formula.

So, L = √A

Now, since the area of the rectangle, A = 36 mm², substituting the value of the variable into the equation, we have

L = √A

L = √(36 mm²)

L = 6 mm

The length of side of the rectangle is 6 mm

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Answer:

Roadhouse

Step-by-step explanation:

Because