A store manager increased the price of an item by the same percent twice. By what percent was the price increased a second time if the item became 1. 44 times more expensive?.

The value of sin is 56°45' which is the very closest to 0.8363. Option B is correct.

For finding the value of sin 56°45', we use trigonometric tables or a calculator for computing the answer

Transfigure the given angle to decimal form, and we get:

56°45' = \(56+\frac{45}{60}\)= 56.75°

Then by using a calculator or trigonometric tables for computing, we find the value of sin 56.75 degrees. So, the closest value to sin 56.75° is approximately 0.8363.

So, the correct answer is 0.8363.

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Answer:

wcsvbth5435y4wte3rwth54u3

Answer:

Answer to the triangle will be 12

Step-by-step explanation:

This will be twelve determined by the other sides

a. To find dy/dx of the given implicit function T(x+y²)/(y-x²)(x+2), we can use the quotient rule. Applying the quotient rule, we differentiate the numerator and denominator separately with respect to x, treating y as a constant. Simplifying the expression gives us the final result for dy/dx in terms of T'(x+y²).

b. To evaluate the limit lim x→2+ Tln(x - 2) / In(x² - 4) using L'Hôpital's Rule, we differentiate the numerator and denominator with respect to x. Applying the rule repeatedly until we reach an indeterminate form, we differentiate the numerator and denominator multiple times. Finally, we substitute x = 2 into the expression to obtain the value of the limit.



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300 meters per minute: 3600 meters per hour

YW BRAINLIEST PLEASE

Answer:

\( \sqrt{32 \div 2 = } 82 \\ \)

Answer:.714

Step-by-step explanation:

divide 100 by 140

Reason: Any point in the shaded yellow region has an x coordinate larger than 1. Points on the dashed boundary line are not part of the solution set.

Answer:

C

Step-by-step explanation:

\(A=x\leq 1\\ B=x\geq 1\\ C=x>1\)

Hope this helps

Answer:its D

Step-by-step explanation:

took the test

The monopolist will produce 6342.22 units of cooking gas.

We have,

Demand function: Q = 8800 - 20P

Cost function: TC = 20Q + 0.05\(Q^2\)

We can start by finding the monopolist's revenue function, which is the product of quantity and price:

R = PQ = (8800 - 20P)P = 8800P - 20\(P^2\)

The monopolist's marginal revenue (MR) is the derivative of the revenue function with respect to quantity:

MR = dR/dQ = 8800 - 40P

To maximize profits, the monopolist sets marginal revenue equal to marginal cost (MC):

MR = MC

Since the cost function is TC = 20Q + 0.05\(Q^2\), the marginal cost (MC) is the derivative of the cost function with respect to quantity:

MC = dTC/dQ = 20 + 0.1Q

8800 - 40P = 20 + 0.1Q

8800 - 40P = 20 + 0.1(8800 - 20P)

8800 - 40P = 20 + 880 - 2P

-40P + 2P = 20 + 880 - 8800

-38P = -7900

P = 7900/38 ≈ 207.89

Therefore, the monopolist will charge a price of $207.89 to maximize profits.

To find the quantity of cooking gas produced, we can substitute the price into the demand function:

Q = 8800 - 20P

Q = 8800 - 20(207.89)

Q ≈ 6342.22

Therefore, the monopolist will produce 6342.22 units of cooking gas.

To calculate the monopolist's profit, we subtract the total cost (TC) from total revenue (TR):

TR = PQ = (8800 - 20P)P

TC = 20Q + 0.05\(Q^2\)

Profit = TR - TC

Profit = (8800P - 20\(P^2\)) - (20Q + 0.05\(Q^2\))

Substituting the price and quantity values:

Profit = (8800(207.89) - 20(207.89)²) - (20(6342.22) + 0.05(6342.22)²)

Profit = 965,066.958 - 2,138,032.12642

Profit = 1,172,008.12642

In this case, the demand function is

Q = 8800 - 20P, and

supply function is the monopolist's marginal cost curve = 20 + 0.1Q.

Setting the demand equal to the supply:

8800 - 20P = 20 + 0.1Q

Substituting Q = 8800

8800 - 20P = 20 + 880

P= 395

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Answer: 1110

Step-by-step explanation:

Answer:

1,110

Step-by-step explanation:

1. Multiply to the powers(?)

10 x 10 x 10 = 1000

10 x 10 = 100

10 = 10

2. Add

1000 + 100 + 10 = 1110

In anova, by dividing the mean square between groups by the mean square within groups, a(n) Analysis of variance  statistic is computed.

What is Analysis of variance ?

What are some instances where ANOVA has been applied?

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Answer:

B........... length = 5

Answer:

this answer is length= 20 in

Answer:

the answer is .8

hope this helps

Answer:

Step-by-step explanation:

the formula is named the point slope formula for a reason.   and  you have show both of them in the question , the slope and the point are given

y - y1 = m(x-x1)

so for your answer

y-(-2) = 4(x-5)

y+2 = 4(x-5)    is the right answer

The angle between two pointers say, no. 12 and no. 8 in a clock is 120° or 2.094 radians.

According to given question, we can say clock is showing 8:00 am. At 8'o clock the two pointers will just touch the no. 12 and no. 8. In a clock at the centre angle 360° must be divided into 12 equal or similar sections. The value of angle for each section in clock is 360° / 12 = 30° .

The counting of angle is always anti clock wise direction so , at 12 the two pointers postion is 360° .. As time passes the angle0 reduces each section ( 1 hour ) by 30° ..as every hours one pointers remains at no. 12 ..

At 8'o clock 8 such sections reduced .

Now, the angle between two pointers is 360° - 8× 30 = 360° - 240° = 120°..

Using the formula for reducing degree to radians , 1 degree = π / 180° radians

=> 120 ° × π / 180° radians = 2.094 radians .

Thus, the angle between two pointers no. 12 and no. 8 is 2.094 radians.

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5 out of 30 and 7 is greater than

Answer:

B because it doesn't have a line under it cause when it has a line under it the dot would be closed

The degree of that polynomial is 5

What is the Degree of Polynomial?

The degree of polynomial is the highest degrees of individual term.

The first is to find each term.

The term is 3\(p\)\(q^{4}\), 2\(p^{2}\)\(q\), and \(q^{3}\) (or can also be written as 3\(p^{1}\)\(q^{4}\), 2\(p^{2}\)\(q^{1}\), and \(p^{0}\)\(q^{3}\)

The next step is to add up the exponents for each term and select the highest result.

3\(p^{1}\)\(q^{4}\) : 1+4 = 5
2\(p^{2}\)\(q^{1}\) : 2+1 = 3
\(p^{0}\)\(q^{3}\) : 0+3 = 3

Therefore the degree of polynomial is 5

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{(5, 2), (4, 2), (3, 2), (2, 2), (1, 2)}, {(−8, −3), (−6, −5), (−4, −2), (−2, −7), (−1, −4)} and {(−6, 4), (−3, −1), (0, 5), (1, −1), (2, 3)} are the sets of ordered pairs considered as a function.

{(−4, −2), (−1, −1), (3, 2), (3, 5), (7, 10)} is not a function.

In mathematics, ordered pair is a pair of numbers that are written in a specific order. They are generally written in (x, y) form. For example (3, 5) is an ordered pair.

The function can also be represented by a set of ordered pairs. A function Is a set of ordered pairs in which no two different ordered pairs have the same value of x coordinate.

Option (a) : {(5, 2),(4, 2),(3, 2),(2, 2),(1, 2)}

No two ordered pairs have the same value of the x coordinate.

So it is a function.

Option (b) : {(-4, -2),(-1, -1),(3, 2),(3, 5),(7, 10)}

Two ordered pairs have the same value of x coordinate (3, 2) and (3, 5).

So, it can not be considered a function.

Option (c) : {(-8, -3),(-6, -5),(-4, -2),(-2, -7),(-1, -4)}

No two ordered pairs have the same value of the x coordinate.

So it is a function.

Option (d) : {(-6, 4),(-3, -1),(0, 5),(1, -1),(2, 3)}

No two ordered pairs have the same value of the x coordinate.

So it is a function.

Therefore, Options (a), (c), and (d) are the functions.

Option (b) is not a function.

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The correct answer is (a) event. An event is a subset of outcomes from the sample space. It represents a specific outcome or set of outcomes that we are interested in. Events can be simple, consisting of a single outcome, or they can be compound, consisting of multiple outcomes.

For example, consider rolling a fair six-sided die. The sample space is {1, 2, 3, 4, 5, 6}. Let's say we are interested in the event of rolling an even number. The event in this case would be {2, 4, 6}, which is a subset of the sample space.

Events can also be mutually exclusive, meaning they cannot occur at the same time, or they can be independent, meaning the occurrence of one event does not affect the probability of the other event occurring.

In summary, an event is a subset of outcomes from the sample space and represents a specific outcome or set of outcomes that we are interested in. It is an important concept in probability theory.

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total days = 3+5+2+2 = 12

Sunny days = 3

Divide the sunny days by the total number of days

P = 3/12 = 0.25

The time taken to reach the maximum height is 1.25 seconds.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a ball is thrown into the air with an upward velocity of 40ft/s. Its height h in feet after t seconds is given by the function h(t) = -16t² + 40t + 10.

To calculate the time to get the maximum height to differentiate the function with respect to t and equate it with zero,

h(t) = -16t² + 40t + 10.

(d/dt)h(t) = ( d / dt ) { -16t² + 40t + 10 } = 0

( d / dt ) { -16t² + 40t + 10 } = 0

-32t  + 40 = 0

-32t = -40

t = 40 / 32

t = 1.25 seconds

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The vertices of the ellipse are (-4,2) and (4,2), since these points lie on the major axis of the ellipse which is horizontal.

Two of the focuses given in the issue, (−4,2) and (4,2), are both situated on a similar even line. This implies that the significant hub of the oval should be level. Two different focuses given in the issue, (2,2) and (- 9,2), are likewise situated on this level line. Thusly, the focal point of the oval is the midpoint between the focuses (- 4,2) and (4,2), which is (0,2).

The other two focuses given in the issue, (−5,5) and (−5,−1), are situated on an upward line that goes through the focal point of the oval. This implies that the minor pivot of the oval should be vertical.

The vertices of the oval are the places where the significant hub meets the circle. Since the significant hub goes through the focuses (−4,2) and (4,2), the vertices of the oval are (- 4,2) and (4,2).

In this way, the vertices of the oval are (- 4,2) and (4,2).

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The optimal values of these parameters are:

a. β₁ = 0

b. β₂ = 0

The linear regression y = β1 + β2x + e, assuming that the sum of squared errors (SSE) takes the following form:

SSE = 382 + 681 + 382 + 18β1β2

Derive the partial derivatives of SSE with respect to β1 and β2 and solve the optimal values of these parameters.

Given that SSE = 382 + 681 + 382 + 18β1β2 ∂SSE/∂β1 = 0 ∂SSE/∂β2 = 0

Now, we need to find the partial derivative of SSE with respect to β1.

∂SSE/∂β1 = 0 + 0 + 0 + 18β2 ⇒ 18β2 = 0 ⇒ β2 = 0

Therefore, we obtain the optimal value of β2 as 0.

Now, we need to find the partial derivative of SSE with respect to β2. ∂SSE/∂β2 = 0 + 0 + 0 + 18β1 ⇒ 18β1 = 0 ⇒ β1 = 0

Therefore, we obtain the optimal value of β1 as 0. Hence, the partial derivative of SSE with respect to β1 is 18β2 and the partial derivative of SSE with respect to β2 is 18β1.

Thus, the optimal values of β1 and β2 are 0 and 0, respectively.

Therefore, the answers are: a. β₁ = 0 b. β₂ = 0

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Answer:

130 inches

Step-by-step explanation:

Area = Length · Width

Solve for the Right Triangle

6 · 11 = 66 inches

Area = Length · Width

Solve for the square

Since the width isn't fully given, we must add 5 + 3 = 8 inches

5 · 8 = 40 inches

Area = Length · Width

Solve for the Rectangle

8 · 3 = 24 inches

Now add the results: 66 + 40 + 24 = 130 in^2

Answer:

the naswer is 10

Step-by-step explanation:

Answer:

10(6)

Step-by-step explanation:

Hope it's right.....

Absolute value which means even negative integers are considered as positive

The inverse function for this problem is given as follows:

\(f^{-1}(x) = \left(\frac{x}{6}\right)^7\)

The function for this problem is given as follows:

\(f(x) = 6\sqrt[7]{x}\)

In the notation y = f(x), we have that:

\(y = 6\sqrt[7]{x}\)

First we must exchange the variables x and y, hence:

\(x = 6\sqrt[7]{y}\)

Then we must isolate the variable y, as follows:

\(\sqrt[7]{y} = \frac{x}{6}\)

\(y = \left(\frac{x}{6}\right)^7\)

\(f^{-1}(x) = \left(\frac{x}{6}\right)^7\)

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