Answer:
3.5 meters
Step-by-step explanation:
Equation: p = 0.8L
Given: p = 2.80
To find the length of a piece of nylon rope that costs $2.80, input the given value of p(2.80) into the equation and solve for L:
p = 0.8L
2.8 = 0.8L
Divide both sides by .8 to isolate L:
\(\frac{2.8}{0.8} =\frac{0.8L}{0.8}\)
3.5 = L
The length of a piece of nylon rope that costs $2.80 is 3.5 meters long.
A suitcase marked at $40 was sold at $32. What was the percentage of discount for the suitcase?
Answer:
Step-by-step explanation:
32/40
=0.8
so it's 20% off since it's a decay.
. (3 points) for a simple linear regression, if the sum of squares for error (sse) is 40 and the sum of squares due to the model (ssm) is 60, what is ? (a) 1.50 (b) 0.40 (c) 0.60 (d)
If the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60, therefore, the answer is (c) 0.60.
Based on your question, the coefficient of determination (R²) for a simple linear regression, given the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60.
To calculate R², follow these steps:
1. Calculate the total sum of squares (SST): SST = SSE + SSM
2. Divide SSM by SST: R² = SSM / SST
Now, let's apply the values from your question:
To calculate, we use the formula:
= SSM / SSM + SSE)
Plugging in the given values, we get:
= 60 / (60 + 40) = 0.6
SST = SSE + SSM = 40 + 60 = 100
R² = SSM / SST = 60 / 100 = 0.60
So, the coefficient of determination (R²) is 0.60, which corresponds to option (c).
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can you give me all of the answers using the following directions please.
Answer:
1234567890
Step-by-step explanation:
Answer:
1234567890
Step-by-step explanation:
Find the slope of the line y+3= – 1 18 (x+6)
Answer:
-118
Step-by-step explanation:
y = 3 = -118(x + 6) Distributive property
y + 3 = -118x - 708 Subtract 3 from both sides
y = -118x - 711
The number before the x is the slope: -118
Let Xi, i=1,2,3 be independent random variables from N(i,i2) distributions. For each of the following, use the Xi's to construct a statistic with the indicated distribution.
(a) chi-squared distribution with v=3 degrees of freedom.
(b) t distribution with v=2 degrees of freedom.
(c) F distribution with v1=1 and v=2 degrees of freedom.
a) For chi-squared distribution with v=3 degrees of freedom, the statistic that can be constructed using Xi's is:
X2 = Σ i=1 3 (Xi − i)2 / 3.
X2 has chi-squared distribution with 3 degrees of freedom.
b) For t-distribution with v=2 degrees of freedom, the statistic that can be constructed using Xi's is:
T = (X1 − 1) / [(X2/2)0.5].
T has t-distribution with 2 degrees of freedom.
c) For F-distribution with v1=1 and v=2 degrees of freedom, the statistic that can be constructed using Xi's is:
F = [(X1 − 1)/1] / [(Σi=2 to 3 Xi2) / 2].
F has F-distribution with 1 and 2 degrees of freedom.
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There are cows and ostriches on a farm. In total there are 44 animals and they have a total of 100 legs. How many cows are on the farm
6 cows are there on the farm, 38 ostriches, for a total of 44 animals. they have a total of 100 legs.
To solve this problem, we need to use algebra. Let's let "c" represent the number of cows on the farm and "o" represent the number of ostriches on the farm. We know that there are 44 animals in total, so:
c + o = 44
We also know that cows have 4 legs and ostriches have 2 legs, and that there are a total of 100 legs on the farm. So:
4c + 2o = 100
Now we have two equations with two variables, so we can solve for one of the variables and then substitute it into the other equation to solve for the other variable. Let's solve for "o" in the first equation:
o = 44 - c
Now we can substitute this into the second equation:
4c + 2(44-c) = 100
Simplifying:
4c + 88 - 2c = 100
2c = 12
c = 6
So there are 6 cows on the farm. To check, we can substitute this into the first equation:
6 + o = 44
o = 38
So there are 6 cows and 38 ostriches on the farm, for a total of 44 animals. And the total number of legs is:
4(6) + 2(38) = 100
So this answer checks out.
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the height of seaweed of all plants in a body of water are normally distributed with a mean of 10 cm and a standard deviation of 2 cm. which length separates the lowest 30% of the means of the plant heights in a sampling distribution of sample size 15 from the highest 70%? round your answer to the nearest hundredth. use the z-table below:
The value of seaweed height that divides the bottom 30% from the top 70% is 8.96 cm.
What is a Normal distribution in statistics?
Data in a normal distribution are symmetrically distributed and have no skew. The majority of values cluster around a central region, with values decreasing as one moves away from the center. In a normal distribution, the measures of central tendency (mean, mode, and median) are all the same.
Given data:
X: height of seaweed.
X~N (μ;σ²)
μ= 10 cm
σ= 2 cm
We have to find the value of the variable X that separates the bottom 0.30 of the distribution from the top 0.70
P(X ≤ x) = 0.30
P(X ≥ x) = 0.70
Now by using the standard normal distribution,
we have to find the value of Z that separates the bottom 0.30 from the top 0.70 and then use the formula
Z = (X - μ)/σ
translates the Z value to the corresponding X value.
P(Z ≤ z) = 0.30
In the body of the table look for the probability of 0.30 and reach the margins to form the Z value. The mean of the distribution is "0" so below 50% of the distribution you'll find negative values.
z= -0.52
Now you have to clear the value of X:
Z= (X - μ)/σ
X= (Z * σ) + μ
X = (-0.52 * 2) + 10
= 8.96
hence, the value of seaweed height that divides the bottom 30% from the top 70% is 8.96 cm.
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The Bay announced it would open a 9000-plus square metre freestanding store in the new West Grand Promenade. This would be the largest store on the promenade, with other smaller stores selling food, tires, and shoes. How else can this particular Bay store be described
This Bay store can also be described as a big box retailer store.
Big Box Retailer
A big box retailer is a physically enormous retail store that is typically a component of a chain of stores (also known as a hyper store, supercenter, superstore, or megastore). By extension, the phrase, big box retailer can also refer to the business that runs the store.
The Bay Store as a Big Box
There are numerous retail chains that only operate in Canada, aside from the large American big box retailer stores like Walmart Canada and the formerly-existent Target Canada. These include places like Hudson's Bay by Home Outfitters, Loblaws by Real Canadian Superstore, Rona, Winners by HomeSense, Canadian Tire by Mark's & Sport Chek, Shoppers Drug Mart, Chapters by Indigo Books and Music, Sobeys, and several others.
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Of the 40 randomly chosen students surveyed, 27 are involved in extracurricular activities at school. There are 680 students at the school. Predict the number of students in the school who are involved in after-school activities. (Please answer the right answer and how you got the answer)
Answer:
It's around 459. So 460 if need to round
Step-by-step explanation:
So, 40 randomly chosen people do not represent the whole school, but using the ratio 27:40 you are given in the equation, you can divide the number of students (680) by the surveyed students (40) to get 17. What this means is there is 17 groups of 40 in the school, so to distribute the amount of people who are in a after-school activity, you must multiply 17 x 27 to get the assumption of about 459 kids. Hopefully you understand =)
A woman on a road trip drives a car at different constant speeds over several legs of the trip. 5 he drives for 50.0 min at 60.0 km/h,13.0 min at e0.0 kmy. and 60.0 minak 45.0 km/h and spends 25.0 min eating lunch and buying gss. (a) What is the total distance traveled over the entire trip (in kan)? lim (b) What is the average speed for the entire trin (in Lmph)? kmath
(a) The total distance traveled over the entire trip is approximately 94.9998 km.
(b) The average speed for the entire trip is approximately 38.51 km/h.
(a) To calculate the total distance traveled over the entire trip, we need to add up the distances covered during each leg of the trip.
Distance = Speed * Time
For the first leg:
Speed = 60.0 km/h
Time = 50.0 min = 50.0/60 = 0.8333 hours (converted to hours)
Distance1 = 60.0 km/h * 0.8333 hours = 49.9998 km
For the second leg:
Speed = 0.0 km/h (car is not moving)
Time = 13.0 min = 13.0/60 = 0.2167 hours (converted to hours)
Distance2 = 0.0 km/h * 0.2167 hours = 0 km
For the third leg:
Speed = 45.0 km/h
Time = 60.0 min = 60.0/60 = 1 hour
Distance3 = 45.0 km/h * 1 hour = 45.0 km
Total Distance = Distance1 + Distance2 + Distance3
Total Distance = 49.9998 km + 0 km + 45.0 km
Total Distance ≈ 94.9998 km
Therefore, the total distance traveled over the entire trip is approximately 94.9998 km.
(b) To calculate the average speed for the entire trip, we can use the formula:
Average Speed = Total Distance / Total Time
Total Time = (Time spent driving leg 1) + (Time spent driving leg 2) + (Time spent driving leg 3) + (Time spent eating lunch and buying gas)
Time spent driving leg 1 = 50.0 min = 50.0/60 = 0.8333 hours (converted to hours)
Time spent driving leg 2 = 13.0 min = 13.0/60 = 0.2167 hours (converted to hours)
Time spent driving leg 3 = 60.0 min = 60.0/60 = 1 hour
Time spent eating lunch and buying gas = 25.0 min = 25.0/60 = 0.4167 hours (converted to hours)
Total Time = 0.8333 hours + 0.2167 hours + 1 hour + 0.4167 hours
Total Time ≈ 2.4667 hours
Average Speed = 94.9998 km / 2.4667 hours
Average Speed ≈ 38.51 km/h
Therefore, the average speed for the entire trip is approximately 38.51 km/h.
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I need this fast!! Sam scores 4 goals per game. What is the rate unit of this rate?
A. games
B. goals per game
C. 4
D. goals
Answer:
B: goals per game
Step-by-step explanation:
She will atleast score 4 goals per game
Which expression represents the greatest value?
A.
B. -2 +0.5
U
-2 + (-1)
D.
-2+1
-2 + (-0.5)
Answer: I hope this helps.
Step-by-step explanation:
Answer:
The correct answer is -2+1.
So yeah
is an angle in a right-angled triangle.
tan 0
=
23
52
What is the value of 0?
Give your answer in degrees to 1 d.p.
Yes, an angle in a right-angled triangle is always present. Without any additional information about the triangle, it is impossible to determine the value of the angle in question.
In a right-angled triangle, one of the angles is a right angle, which measures 90 degrees. The other two angles in the triangle are acute angles and their measures always add up to 90 degrees.
To find the value of the angle in question, we need to know some additional information about the triangle. If we have the lengths of two sides of the triangle, we can use trigonometric ratios to find the measure of the angle.
For example, if we know the length of the side opposite the angle and the length of the hypotenuse (the longest side of the triangle), we can use the sine ratio to find the measure of the angle.
If we know the length of the side adjacent to the angle and the length of the hypotenuse, we can use the cosine ratio.
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two numbers with a sum of 15
Answer:
7+8=15
Step-by-step explanation:
Complex variables. Complete the following tasks for f(x) = 1/(1
+ x^2)
a) Compute the integral ƒ(0) 21/72 L f(x) dx. b) Assume k> 0 and compute the integral -ikx ƒ(k) = = - 12/17 f(x)e- tkr dar. 2п -[infinity] c) Assume k < 0 and compute the integral ƒ(k)= = 212/72 * f(x) e
In complex analysis, for the function f(x) = 1/(1 + x^2), the integral of f(x) over a specified range and the integral involving complex variables can be computed. The first integral evaluates to 21/72, while the second integral for k > 0 equals -12/17 f(x)e^(-tkr) and the third integral for k < 0 is 212/72 times f(x)e^(tkr).
a) To compute the integral ƒ(0) 21/72 L f(x) dx, we need to integrate the function f(x) = 1/(1 + x^2) over the range specified by L. The integral of f(x) with respect to x is given by arctan(x), and evaluating it at the upper limit (L) and subtracting the value at the lower limit (0) gives us the result. Plugging in the values, we obtain ƒ(0) 21/72 L f(x) dx = (1/2)arctan(L) - (1/2)arctan(0) = (1/2)arctan(L) = 21/72.
b) Assuming k > 0, we are given the integral -ikx ƒ(k) = - 12/17 f(x)e^(-tkr) dx. Here, we have a complex variable, k, and the integral involves both the function f(x) and the exponential term e^(-tkr). Integrating this expression requires evaluating each term separately and applying the appropriate rules of integration. By performing the calculations, we arrive at the result of -ikx ƒ(k) = - 12/17 f(x)e^(-tkr) = - 12/17 arctan(k) e^(-tkr).
c) Assuming k < 0, we are asked to compute the integral ƒ(k) = 212/72 * f(x) e^(tkr). Similar to part (b), we need to integrate the function f(x) multiplied by the exponential term e^(tkr). Again, we evaluate each term individually and apply integration rules to obtain the result. The integral ƒ(k) = 212/72 * f(x) e^(tkr) evaluates to 212/72 arctan(k) e^(tkr).
In summary, for the function f(x) = 1/(1 + x^2), the given integrals are evaluated as follows: ƒ(0) 21/72 L f(x) dx = 21/72, -ikx ƒ(k) = - 12/17 f(x)e^(-tkr) = - 12/17 arctan(k) e^(-tkr) (for k > 0), and ƒ(k) = 212/72 * f(x) e^(tkr) = 212/72 arctan(k) e^(tkr) (for k < 0).
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a statistics professor has 115 students in a statistics class and would like to estimate the number of hours each student studied for the last exam. a random sample of 41 students was found to study an average of 7.3 hours with a standard deviation of 1.9 hours. the 98% confidence interval to estimate the average number of hours studying for the exam is
The 98% confidence interval for the average number of hours studying for the exam is approximately 6.61 to 7.99 hours. The correct option is d.
To calculate the 98% confidence interval for the average number of hours studied, we need to use the sample mean (7.3 hours), sample standard deviation (1.9 hours), sample size (41 students), and the appropriate Z-score for a 98% confidence level.
Step 1: Find the Z-score for a 98% confidence level.
Using a Z-table or calculator, the Z-score for a 98% confidence interval is approximately 2.33.
Step 2: Calculate the standard error.
Standard error (SE) = (sample standard deviation) / sqrt(sample size) = 1.9 / sqrt(41) ≈ 0.297
Step 3: Calculate the margin of error.
Margin of error (ME) = Z-score * standard error = 2.33 * 0.297 ≈ 0.692
Step 4: Calculate the confidence interval.
Lower limit = sample mean - margin of error = 7.3 - 0.692 ≈ 6.61
Upper limit = sample mean + margin of error = 7.3 + 0.692 ≈ 7.99
This means that we can be 98% confident that the true mean of hours studied for the entire class of 115 students lies within this range. The closest answer choice to these values is option D (6.11 and 8.49).
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HELPP ANYBODY KNOW THE ANSWERS TO THE BLANKS IN THE GRAPH?
Answer:
5,234
Step-by-step explanation:
In ΔMNO, the measure of ∠O=90°, the measure of ∠N=48°, and NO = 73 feet. Find the length of MN to the nearest tenth of a foot.
Answer:109.1 feet
Step-by-step explanation:
What function uses the ADJACENT and the HYPOTENUSE?
\text{SOH-CAH-TOA}
SOH-CAH-TOA
\cos N = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{73}{x}
cosN=
hypotenuse
adjacent
=
x
73
\cos 48=\frac{73}{x}
cos48=
x
73
x\cos 48=73
xcos48=73
Cross multiply.
\frac{x\cos 48}{\cos 48}=\frac{73}{\cos 48}
cos48
xcos48
=
cos48
73
Divide each side by cos 48.
x=\frac{73}{\cos 48}=109.0968\approx 109.1\text{ feet}
x=
cos48
73
=109.0968≈109.1 feet
Type into calculator and roundto the nearest tenth of a foot.
In the figure to the right, it AC=22 and BC=19, what is the radius?
What is the reason that Della is crying at the beginning of the story?
Della was crying because she doesn't have enough money to brought the present for her husband Jim.
Basically, the O Henry's story of "The gift of Magi" has the central them as Love. In this story, he sets up a contrasted picture in life- love among the ruins- the acute poverty in the family and the sacrifice of the greatest possessions of the family.
In this stage he defines how their possession has helped Jim and Della, that's the hero and heroine to conquer poverty they were in.
Now, the reason behind Della's cry was she had only one dollar and eighty seven cents and with this small amount she could not buy a good present for her dear husband.
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A baseball player earns $3 million in 2015. During the next 15 years, the earnings increase 4% each year.
a. Write an exponential growth model giving the earnings y (in millions of dollars) t years after 2015. Write the base of the model as a decimal.
An exponential growth model is y=
b. In which year will the player's earnings first exceed $5,000,000?
Answer:
\(y=3*1.04^{t}\)
in 2029
Step-by-step explanation:
\(y=3*1.04^{t}\)
\(when y=5\\t=\frac{ln(5/3)}{ln(1.04)} =13.02 ..\)
have to round it up to 14 to exceed
How fair is 50% of 140 yards?
60yards
50yards
70yards
80yards
For what values of a, y=bx-1 will not be a tangent to the graph of y=x^2+a(x-1), for any value of b?
For any value of b, the line y = bx - 1 will not be a tangent to the graph of y = x^2 + a(x - 1) if and only if |b - a| < 2√(a - 1).
How did we get the value?To determine whether the line y = bx - 1 is a tangent to the graph of y = x^2 + a(x - 1), we need to find the points of intersection of the line and the parabola. If there is no intersection, then the line cannot be a tangent to the parabola.
Substituting y = bx - 1 into the equation for the parabola, we get:
bx - 1 = x^2 + a(x - 1)
Rearranging terms, we get:
x^2 + (a - b)x + (1 - a) = 0
For the line to not be a tangent to the parabola, this quadratic equation must have no real solutions (i.e., the discriminant b^2 - 4ac must be negative). Therefore, we have:
(a - b)^2 - 4(1 - a) < 0
Simplifying and expanding, we get:
a^2 + b^2 - 2ab - 4a + 4 < 0
Rearranging terms, we get:
b^2 - 2ab + a^2 < 4a - 4
The left-hand side is a perfect square: (b - a)^2. Therefore, we can write:
(b - a)^2 < 4(a - 1)
Taking the square root of both sides, we get:
|b - a| < 2√(a - 1)
Therefore, for any value of b, the line y = bx - 1 will not be a tangent to the graph of y = x^2 + a(x - 1) if and only if |b - a| < 2√(a - 1).
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Jennifer made these measurements on ABC,BC must be-?
Answer:
between 10 and 12
Step-by-step explanation:
Given the measure of angles:
m∠B = 70°
m∠C = 60°
m∠A = 50°
We know m∠B = 70° because the sum of interior angles in a triangle is equal to 180°.Following this information, since the side lengths are directly proportional to the angle measure they see:
Angle B is the largest angle. Therefore, side AC is the longest side of the triangle since it is opposite of the largest angle.
Angle C is the smallest angle, so the side AB is the shortest side.
Therefore, side BC must be between 10 and 12 inches.
help please, i don’t understand
In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.
Answer:
89.8 feet
Step-by-step explanation:
In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.
We would solve the above question using Sine rule
The formula is given as:
DB/sin D = BC/sin B
93/sin 90 = BC/sin 75
We cross multiply
sin 90 × BC = 93 × sin 75
BC = 93 × sin 75/sin 90
BC = 89.83 feet
Approximately BC = 89.8 feet
Indicate which statements are True and which are False. (1.1) Let Pn be the set of polynomial functions f of degree n defined by relations of the form f(x)=C0xn+C1xn−1+⋯+Cn, where n is a fixed non-negative integer, the coefficients C0,C1,…,Cn are all integers and C0=0. Then the set Pn is countable. [2] (1.2) The union of an arbitrary family of open sets in R is open. [2] (1.3) If F=[1,2]∪[3,4]∪[5,6]∪{7}. Then F is closed. [ ] (1.4) The intersection of an arbitrary collection of compact sets in R is compact. [2] (1.5) Let X=(1,21,31,41,51,…) and Y=(21,11,41,31,61,51,…) be two sequences in R. Then Y is a subsequence of X. [2] (1.6) Every uniformly continuous function is a Lipschitz function. [2] (1.7) The condition of continuity is necessary for a function to be Riemann integrable. [2] (1.8) If functions f and g are not Riemann integrable on [a,b], then function fg may be integrable on [a,b]. [2] (1.9) If a sequence (fn) conveges uniformly to f on [a,b] and x0 is a point of [a,b] such that limx→x0fn(x)=an for all n∈N, then the sequence (an) need not converge. [ ] (1.10) Let (fn) be a sequence of Riemann integrable functions fn:[a,b]→ R converging uniformly to f:[a,b]→R. Then f is Riemann integrable.
1.1) True. The set of polynomial functions of degree n with integer coefficients, excluding the zero coefficient, is countable.
1.2) True. The union of any collection of open sets in R is open.
1.3) False. The set [1, 2] ∪ [3, 4] ∪ [5, 6] ∪ {7} is not closed because it does not include all its limit points.
1.4) True. The intersection of any collection of compact sets in R is compact.
1.5) False. The sequence Y is not a subsequence of X.
1.6) True. Every uniformly continuous function is also a Lipschitz function.
1.7) True. Continuity is necessary for a function to be Riemann integrable.
1.8) True. The product of two functions that are not individually Riemann integrable can still be integrable.
1.9) False. If a sequence converges uniformly to a function at a point, the sequence of function values also converges at that point.
1.10) True. If a sequence of Riemann integrable functions converges uniformly to a function, the limit function is also Riemann integrable.
(1.1) Let Pn be the set of polynomial functions f of degree n defined by relations of the form f(x) = C0xn + C1xn−1 + ⋯ + Cn, where n is a fixed non-negative integer, the coefficients C0, C1, ..., Cn are all integers, and C0 ≠ 0. Then the set Pn is countable.
- True. The set Pn is countable because it can be put in a one-to-one correspondence with the set of all polynomials with integer coefficients, which is countable.
(1.2) The union of an arbitrary family of open sets in R is open.
- True. The union of any collection of open sets in R is open. This property is a fundamental property of open sets.
(1.3) If F = [1,2] ∪ [3,4] ∪ [5,6] ∪ {7}, then F is closed.
- False. The set F is not closed because it does not contain all its limit points. Specifically, the limit point 2 is not included in F.
(1.4) The intersection of an arbitrary collection of compact sets in R is compact.
- True. The intersection of any collection of compact sets in R is compact. This is a property known as finite intersection property.
(1.5) Let X = (1,21,31,41,51, ...) and Y = (21,11,41,31,61,51, ...) be two sequences in R. Then Y is a subsequence of X.
- False. Y is not a subsequence of X. A subsequence of a sequence is obtained by selecting terms from the original sequence in their respective order. Y does not follow this pattern in relation to X.
(1.6) Every uniformly continuous function is a Lipschitz function.
- True. Every uniformly continuous function is also a Lipschitz function. Uniform continuity implies a bounded rate of change, which satisfies the Lipschitz condition.
(1.7) The condition of continuity is necessary for a function to be Riemann integrable.
- True. Continuity is a necessary condition for a function to be Riemann integrable. If a function is not continuous, it may not be integrable using the Riemann integral.
(1.8) If functions f and g are not Riemann integrable on [a,b], then function fg may be integrable on [a,b].
- True. The product of two functions, each of which is not Riemann integrable, can still be integrable. The integrability of the product is not solely dependent on the individual integrability of the functions.
(1.9) If a sequence (fn) converges uniformly to f on [a,b], and x0 is a point of [a,b] such that limx→x0fn(x) = an for all n∈N, then the sequence (an) need not converge.
- False. If the sequence (fn) converges uniformly to f on [a,b], and the point x0 is such that limx→x0fn(x) = an for all n∈N, then the sequence (an) will also converge to the same limit as the function f at x0.
(1.10) Let (fn) be a sequence of Riemann integrable functions fn:[a,b]→ R converging uniformly to f:[a,b]→R. Then f is Riemann integrable.
- True. If a sequence of Riemann integrable functions converges uniformly to a function, then the limit function is also Riemann integrable. Uniform convergence preserves integrability.
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PLEASE HELP
What would be my first step?
3 + 4 x 6 - 4 =
addition
subtraction
division
multiplication
Need postulate with explanation
ΔABD ≅ ΔCBD based on the SAS Congruence Postulate.
What is the SAS Congruence Postulate?The SAS Congruence Postulate is a principle in geometry that states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
Since B is the midpoint of AC, therefore AB ≅ CB (one pair of congruent sides).
Based on the reflexive property of congruence, BD ≅ BD (another pair of congruent sides).
Since AC is perpendicular to BD, therefore angles ABD and CBD are right angles, which means <ABD ≅ <CBD (one pair of included congruent angles).
Therefore, based on the SAS congruence postulate, ΔABD ≅ ΔCBD.
Learn more about the SAS congruence postulate on:
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Help me please with #12
Answer:
Am am not that big brain
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