A string of length 30cm has one end attached to a fixed point and the other to a mass of 100g which revolves in a horizontal circle 80 times per minute. Calculate (i) the angle of inclination of the string to the vertical, and (ii) the tension T in the string.​

Answer:

a survey

Explanation:

how kids like the playground or they do not like it at all

(a) The time taken before the student catches the bus is 11.52 seconds.

(b) The distance the student have to run before she overtakes the bus is 63.36 m.

(c) The speed of the bus is 2.0 m/s.

(d) If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.

Apply the principle of relative velocity as follows;

(Vs - Vb)t = D

where;

(Vs - at)t = D

where;

(5.5 - 0.173t)t = 40.4

5.5t - 0.173t² = 40.4

0.173t² - 5.5t + 40.4 = 0

solve the quadratic equation using formula method;

a = 0.173, b = -5.5, c = 40.4

t = 11.52 seconds or 20.27 seconds

so the minimum time taken by the student to over take the bus is 11.52 seconds

d = vt

d = 5.5 m/s x 11.52 s = 63.36 m

v = at²

v = 0.173 x (11.52)

v = 2.0 m/s

If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.

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\(position \\ \\ \)

Taking into account the definition of potential energy, potential energy is the energy an object has due to its position.

Potential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity. So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

Where:

In summary, potential energy is the energy an object has due to its position.

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Answer:

bbibinononobyvtcrxrxextcyvubuvububububububbu

Answer:

im just gettin these points babbbyyyyyy

Explanation:

This question involves the concepts of the law of conservation of momentum.

The ratio of their speeds will be "-1.19".

"80-kg skater" has the higher speed.

According to the Law of Conservation of Momentum, the total momentum of an isolated system always remains constant. Therefore,

\(Total\ Momentum\ Before\ Collision =Total\ Momentum\ After\ Collision \\\\m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

where,

Therefore,

\((80\ kg)(0\ m/s)+(95\ kg)(0\ m/s)=(80\ kg)(v_{80})+(95\ kg\ kg)(v_{95})\\\\\frac{v_{80}}{v_{95}}=-\frac{95\ kg}{80\ kg\ kg}\\\\\frac{v_{80}}{v_{95}}=-1.19\)

It is clear that the speed of skater A (80 kg skater) will be higher.

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A collection of items, measurements, or entities taken from a population in such a manner as to ensure each has the same chance of being included is a simple random sample. [TRUE]

A simple random sampling technique is a technique for obtaining samples that are directly carried out on the sampling unit. Thus each sampling unit as an isolated population element has the same opportunity to become a sample or to represent the population. This method is carried out when members of the population are considered homogeneous

Requirements for using the simple random sampling technique:

The disadvantages of this simple random sampling technique include:

While the advantage of this simple random sampling technique is that it is easy to apply.

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Humans would need a breathable environment like that on Earth in the living section of a colony on Venus in order to survive. Nitrogen, oxygen, and trace amounts of other gases, such as carbon dioxide, make up the majority of the atmosphere on Earth.

The clouds are made of sulfuric acid, and the atmosphere is primarily carbon dioxide, the same gas that causes the greenhouse effect on Venus and Earth. And the heated, high-pressure carbon dioxide acts corrosively at the surface.

For instance, compared to Earth, which has 99% nitrogen and oxygen in its atmosphere, Venus and Mars both contain more than 98% carbon dioxide and nitrogen.

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Answer:

a

 \(k = 457333.3 N/m\)

b

\(x_a =0.09\ m\)      

Explanation:

From the question we are told that

    The total mass of  three people is  \(M = 2.00*10^{2} \ kg\)

     The mass of the car is  \(m_c = 1.200 *10^{3} \ kg\)

     The compression of the car spring is  \(x = 3 \ cm = 0.03 \ m\)

Generally the spring constant is mathematically represented as

          \(k = \frac{F}{x}\)

Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as        

=>       \(F = (M +m_c) *g\)

=>       \(F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8\)

=>       \(F = 13720 \ N\)

So

        \(k = \frac{13720}{0.03}\)

=>     \(k = 457333.3 N/m\)

Generally if the mass which the car is loaded with is  \(m = 3.00*10^{2} \ kg\)

Then the force experienced by the spring is  

         =>       \(F_a = (m +m_c) *g\)

         =>       \(F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8\)

         =>       \(F_a = 41160 \ N\)

Generally from the above formula the compression is  

       \(x_a = \frac{F_a}{k}\)

=>    \(x_a = \frac{41160}{457333.3}\)

=>    \(x_a =0.09\ m\)      

Answer:Obtuseness of psychical iodine

Explanation:

gamma ray acuteness eventually have an obtuse effect on physical iodine meaning due to the phthagoras theorem the calculus formula would work

To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:

F = I * L * B * sin(θ)

where:

F is the magnetic force,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field, and

θ is the angle between the wire and the magnetic field.

In this case, the values are:

I = 30 A (current in the wire)

L = 2.0 m (length of the wire)

B = 55 mT = 0.055 T (magnitude of the magnetic field)

θ = 20° (angle between the wire and the magnetic field)

Substituting the values into the formula:

F = 30 A * 2.0 m * 0.055 T * sin(20°)

Calculating sin(20°):

F = 30 A * 2.0 m * 0.055 T * 0.3420

F ≈ 1.5714 N

Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.

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Answer: No.

Explanation:

Radiometer dating is used on igneous rocks.

Unlike the other two rock types, sedimentary annd metamorphisis, all igneous rocks possess one specific age/ time of origin.

Answer: WORK

Explanation:

Answer:

work

Explanation:

got it right on edge:p

Answer:

Okay

It is electric charge

Time needed = t = 20.83 s

Given

car speed = 85 km/h

truck speed = 73 km/h

Required

the time it takes for the car to reach the truck

Solution

When the car reaches the truck, the distance between them will be the same

x car - 250 m = x truck

General formula for distance (d) :

d = v.t

So the equation becomes :

85t-250 = 73t

12t=250

t = 20.83 s

Answer:

c) It decreases.

Explanation:

If you treat this as a case of momentum of the sled while sledding on a friction-less ice, then mass and velocity are directly proportional. This means increasing either mass or velocity , the momentum of the object increases proportionally.

In this question, when the child falls sideways off the sled, the mass reduces, the velocity experiences the same causing a decrease in momentum .

Light travels faster in air than in glass because air is an optically rarer medium.

The term speed of light refers to the speed with which light travels through diverse materials. We know that light travels faster in air than in glass owing the the difference in the nature and composition of the two materials.

Hence, the explanation of the student concerning the differences in angles does not account for the differences in the speed of light in materials. Light travels faster in air than in glass because air is an optically rarer medium.

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Answer:

The time to attain the maximum angular velocity is 0.33 s.

Explanation:

Given;

angular acceleration of the fan, α = 150 rad/s²

maximum angular velocity, \(\omega_f\) = 50 rad/s

When a fan is switched on, the initial angular velocity, \(\omega_i = 0\)

The time to attain the maximum angular velocity is given by;

\(\omega_f = \omega_i +\alpha t\\\\50 = 0 + 150t\\\\t = \frac{50}{150}\\\\t = 0.33 \ s\)

Therefore, the time to attain the maximum angular velocity is 0.33 s.

A closed system is a system that is completely isolated from its environment. The physical universe, as we currently understand it, appears to be a closed system. An open system is a system that has flows of information, energy, and/or matter between the system and its environment, and which adapts to the exchange.

D makes the most sense, but you just have to put two and two together and go with your gut feeling, first cross out the answers that don't make sense (A didnt make sense) and go from there! I hope the little bit above me helped you answer or decide :) Good luck!

Answer: Around 0:35 Pm or 12:35 Am

Explanation:

The equation that describes the cooling of objects can be written as:

T(t) = Ta + (Ti - Ta)*e^(k*t)

Where Ta is the ambient temperature, here Ta = 25°C.

Ti is the initial temperature of the body, we have Ti = 37°C.

t is the time.

k is a constant.

So our equation is:

T(t) = 25°C +12°C*e^(k*t)

at 2pm, the temperature was 33°C

at 3pm, the temperature was 31°C.

we want to find the hour where we have our t = 0, suppose this hour is X.

then we can write our times as:

2pm ---> 2 - X

3pm ----> 3 - X

and our equations are:

33°C = 25°C + 12°C*e^(k2 - k*X)

31° = 25°C + 12°C*e^(k3 - k*X)

So we have two equations and two variables, let's solve the system.

first, simplify it a bit, for the first eq:

33 - 25 = 12*e^(k2 - k*X)

8/12 = e^(k2 - k*X)

ln(8/12) = k*2 - k*X

for the second equation we have:

31 - 25 = 12*e^(k3 - k*X)

6/12 = e^(k3 - k*X)

ln(6/12) = k*3 - k*X

So our equations are:

1) ln(2/3) = 2*k - X*k

2) ln(1/2) = 3*k - X*k

First, let's isolate one of the variables in one of the equations. let's isolate k in the first equation.

ln(2/3)/(2-X) = k

now we can replace it in the second equation:

ln(1/2) = 3*ln(2/3)/(2 - X) - X*ln(2/3)/(2-X)

now let's solve it for X, i will take a = ln(1/2) and b = ln(2/3) so it is easier to read.

a = 3*b/(2 - X) - X*b/(2 - X)

a*(2 - X) = 3*b - X*b

2a - aX = 3b - Xb

X(a - b) = 2a - 3b

X = (2*ln(1/2) - 3*ln(2/3))/(ln(1/2) - ln(2/3)) = 0.590

now, knowing that one hour has 60 minutes, then this is:

0.59*60m = 35 minutes

So the hour of death is 0:35 Pm or 12:35 Am

Answer:

t=  16.75 s

Explanation:

We will solve this exercise using the kinematic expressions

corridor that goes at constant speed, suppose that its speed is v₁ = 20 m/s, it does not appear in the statement, we start counting the time when it passes the policeman.

           x₁ = v₁ t

The policeman starts from rest, so his initial velocity is zero and he has an acceleration a = 2.70 m /s², to use the same time counter we take into account that the policeman left at = 1.00 s after passing the corridor

           x₂ = v₀ (t-t₀) + ½ a (t-t₀)²

           x₂ = ½ a (t-1)²

at the point where the two meet, the position must be the same

           x₁ = x₂

          v₁ t = ½ a (t-1)²

          (t-1)² = \(\frac{2 v_1 t}{a}\)

           t² - 2t + 1 - \frac{2 v_1 t}{a} +1 = 0

           t² - 2(1 + \(\frac{v_1}{a}\)) t  +1

let's we solve the second degree equation

          t² - 2 ( 1 + \(\frac{20}{2.7}\)) t + 1=0

          t² - 16.81 t +1=0

          t = [ 16.81 ± \(\sqrt{ 16.81^2 - 4 )}\) ] /2

          t = [16.81 ± 16.695]/2

          t₁=  16.75 s

          t2= 0.06 s

Time t₂ is less than the reaction time of humans, so the correct answer is the first time

            t=  16.75 s

Part 1

Since there is no friction, there is n force opposing the downward movement of the block. The freebody diagram of the block is shown below

The force pulling the block down the ramp = mgSinθ

From the information given,

θ = 30

m = 9

g = 9.8

Thus,

Force = 9 x 9.8Sin30 = 44.1

Recall, Force = mass x acceleration

acceleration = force/mass = 44.1/9 = 4.9 m/s^2

The block accelerated to the bottom at 4.9 m/s^2

The block started from rest, thus, initial velocity = 0

Distance travelled = 11 m

We want to calculate the final velocity at the bottom. We would apply the formula,

v^2 = u^2 + 2as

where

v = final velocity

u = initial velocity

a = acceleration

s = diatance

Thus,

v^2 = 0^2 + 2 x 4.9 x 11 = 107.8

v = square root of 107.8 = 10.38

The speed of the block at the bottom of the ramp = 10.38 m/s

b) The movement of the block on the floor is opposed by friction. Fr represents frictional force. Fa is the frorce moving the block forward.

Recall, Fa = 44.1N

Frictional force = normal reaction x coefficient of friction

The block travels 20.8 m on the floor before coming to rest. Thus,

initial velocity = 10.38

final velocity = 0

We would find the acceleration by applying the formula

v^2 = u^2 - 2as

The negative sign is because the block was decelerating. Thus,

0^2 = 10.38^2 - 2 x a x 20.8

10.38^2 = 2 x a x 20.8

107.744 = 41.6

a = 107.744/41.6 = 2.59

Force with which the block moved on the floor = 9 x 2.59 = 23.31N

Recall, frictional force = 9 x 9.8 x coefficient of friction

Thus,

44.1 - 88.2 x coefficient of friction = 23.31

88.2 x coefficient of friction = 44.1 - 23.31 = 20.79

coefficient of friction = 20.79/88.2

coefficient of friction = 0.24

c) The height of the block above the ground is calculated by

height = 11 cos30 = 9.53

Potential energy = mgh

Potential energy of block at the top = 9 x 9.8 x 9.53 = 840.55 J

Kinetic energy of the block when it came to a stop = 0

Thus, Mechanical energy lost due to friction = 840.55 - 0 = 840.55 J

(a) To double the resistance of a resistor made of constantan, it must be raised to a temperature of approximately 100°C.

(b) To cut the resistance of a resistor made of constantan in half, it must be cooled to approximately -200°C.

(c) These results are unreasonable because constantan has a positive temperature coefficient of resistivity, meaning that its resistance increases as temperature increases and decreases as temperature decreases.

(d) The assumption that constantan has a constant temperature coefficient of resistivity is unreasonable, as it actually has a positive temperature coefficient of resistivity.

We know that the resistance has to do with the opposition that is offered to the flow of current and the resistance would depend on the kind of material that have been used in the resistor.

We also have to know that the resistance of the resistor would depend on the temperature and as such the resistance does vary with the temperature of the system.

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The kinetic energy of the skier at the beginning is 0 J and at the end is 50,000 J. The potential energy of the skier at the beginning is 50,000 J and at the end is 0 J.

In the figure, the letter "J" stands for "Joule," the unit used to quantify energy. The work performed by a force of one newton acting through one metre is equivalent to one joule, a unit of work or energy in the International System of Units (SI). Its unit of measure is the Joule, named after the English physicist James Prescott Joule, and it measures 107 ergs, or roughly 0.7377 foot-pounds.

The total of the kinetic and potential energies at every given position in this figure is equal, which serves as an illustration of the rule of conservation of energy. As a result, in the scenario as it is, energy is being preserved.

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The force in the cord ab is 37.6 lb when being lifted at a constant speed, and the angle u for balance.

The rotation of the earth is an example of a body that is moving with uniform velocity when its speed is increasing throughout an interval of time.

The sum of the forces in each direction must be zero in order to lift the block at a steady speed.

XFx = 0 : F sin θ − T sin 20° = 0

XFy = 0 : T cos 20° − F cos θ − 20 = 0

The tension in cord CAD stays constant throughout because there is no friction on the pulley: F = 20 lb.

20 sin θ − T sin 20° = 0......... (1)

T cos 20° − 20 cos θ − 20 = 0 ........(2)

Solve equation (1) for T

T = 20 sin θ/sin 20

and substitute it into equation (2).

(20 sin θ/sin 20°)cos 20° − 20 cos θ − 20 = 0

cot 20°sin θ − cos θ − 1 = 0

cot 20°sin θ − 1 = cos θ

cot 20°sin θ − 1 = √1 − sin2θ

cot²20°sin²θ − 2 cot 20°sin θ + 1 = 1 − sin²θ

(cot²20° + 1) sin²θ − 2 cot 20°sin θ = 0

csc²20°sin²θ − 2 cot 20°sin θ = 0

(csc²20°sin θ − 2 cot 20°) sin θ = 0

csc²20°sin θ − 2 cot 20° = 0 or sin θ = 0

sin θ = 2 cot 20°/csc² 20°

= 2 cos 20°sin 20° = sin 40° or sin θ = 0

θ = 40° or θ ≠ 0°.

Substitute this nonzero value for θ into the formula for T.

T =20 sin θ/sin 20°

≈ 37.6 lb

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Answer:25N/

Explanation:

A. The value of x in the given circular geometry is determined as 9.75.

The value of x can be calculated by applying the following rules of geometry as shown below.

angle AC = angle at the center

angle at center = twice angle at circumference

147 = 2(6x + 15)

147 = 12x + 30

147 - 30 = 12x

117  = 12x

x = 117/12

x = 9.75

Thus, the value of x in the given circular geometry is determined as 9.75.

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The work done by \(\vec F\) along the given path C from A to B is given by the line integral,

\(\displaystyle \int_C \mathbf F\cdot\mathrm d\mathbf r\)

I assume the path itself is a line segment, which can be parameterized by

\(\vec r(t) = (1-t)(-2\,\vec\imath + 5\,\vec\jmath) + t(4\,\vec\imath+7\,\vec\jmath) \\\\ \vec r(t) = (6t-2)\,\vec\imath+(2t+5)\,\vec\jmath \\\\ \vec r(t) = x(t)\,\vec\imath + y(t)\,\vec\jmath\)

with 0 ≤ t ≤ 1. Then the work performed by F along C is

\(\displaystyle \int_0^1 \left(6x(t)^3\,\vec\imath-4y(t)\,\vec\jmath\right)\cdot\frac{\mathrm d}{\mathrm dt}\left[x(t)\,\vec\imath + y(t)\,\vec\jmath\right]\,\mathrm dt \\\\ = \int_0^1 (288(3t-1)^3-8(2t+5)) \,\mathrm dt = \boxed{312}\)

Answer:

At the tip of the pistil

Explanation:

Hope it helped!