A strong acid has a weak bond to its acidic proton, whereas a weak acid has a strong bond to its acidic proton. Explain.

Answers

Answer 1

Strong acids have mostly ions in solution, therefore the bonds holding H and A together must be weak. Strong acids easily break apart into ions.

On the other hand, a weak acid like acetic acid is only partially dissociated in aqueous medium and thus the solution mainly contains undissociated acetic acid which proves that CH3COO− is a stronger base than H2O.

What is acid?

Any substance that tastes sour in water solution, turns blue litmus paper red, reacts with some metals to release hydrogen, reacts with bases to form salts, and stimulates chemical reactions is considered an acid (acid catalysis).

An acid is a chemical substance, typically a liquid, that contains hydrogen and can interact with other substances to form salts. Some acids react with other materials and burn or dissolve them.

Acids are frequently encountered in daily life. They exist naturally in foods, are found in cells and digestive systems, and are used in numerous regular chemical reactions. Strong acids that are frequently used include nitric acid, phosphoric acid, sulfuric acid, and hydrochloric acid.

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Related Questions

What are the spectator ions when K2S(aq) and CaCl2(aq) are combined?
A) Ca2+ and CI
B) Ca2+ and S2-
OC) K and and CI
OD) K+ and S2-

Answers

The spectator ions when \(K_{2}S\)(aq) and \(CaCl_{2}\)(aq) are combined are option D) K+ and S2-.

In the reaction between \(K_{2}S\) and \(CaCl_{2}\), the K+ ions and CI- ions are not involved in any chemical changes. They remain in the solution in their original ionic form before and after the reaction. These ions are called spectator ions because they do not participate in the overall reaction.

The reaction between \(K_{2}S\) and \(CaCl_{2}\) can be represented as follows:

\(K_{2}S\)(aq) + \(CaCl_{2}\)(aq) → 2KCl(aq) + CaS(s)

In this reaction, the K+ ions and CI- ions simply combine to form KCl, which remains dissolved in the solution. The \(Ca_{2+}\) ions from \(CaCl_{2}\) react with the S2- ions from \(K_{2}S\) to form the insoluble compound CaS, which precipitates out of the solution.

Therefore, the spectator ions in this reaction are K+ and \(S_{2+}\).

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Which two changes would make this reaction reactant-favored?
2H₂+02 2H₂O + energy
A. Reducing the pressure
B. Increasing the pressure
C. Reducing the temperature
D. Increasing the temperature

Answers

C. Reducing the temperature, is the two changes would make this reaction reactant-favored 2H₂+O₂ 2H₂O + energy

To make the given reaction reactant-favored, we need to shift the equilibrium towards the left side, favoring the formation of reactants (H₂ and O₂) rather than products (H₂O). This can be achieved by considering the impact of pressure and temperature on the reaction.

A. Reducing the pressure:

Reducing the pressure would not favor the reactants. According to Le Chatelier's principle, decreasing the pressure will shift the equilibrium towards the side with a higher number of moles of gas. In this case, both sides of the reaction have the same number of moles of gas (two moles), so reducing the pressure will not have a significant effect.

B. Increasing the pressure:

Increasing the pressure would not favor the reactants either. Again, according to Le Chatelier's principle, increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. As both sides have the same number of moles of gas, changing the pressure will not impact the equilibrium.

C. Reducing the temperature:

Reducing the temperature would favor the reactants. The reaction is exothermic (releases energy), and according to Le Chatelier's principle, decreasing the temperature favors the reaction that produces heat. Therefore, reducing the temperature would shift the equilibrium towards the reactants (H₂ and O₂) side.

D. Increasing the temperature:

Increasing the temperature would not favor the reactants. In an exothermic reaction, increasing the temperature would shift the equilibrium towards the products (H₂O) side to absorb the additional heat.

In conclusion, reducing the temperature (option C) would make the reaction reactant-favored, favoring the formation of H₂ and O₂ rather than H₂O. Therefore, Option C is correct.

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31.The following equation represents which of the following types of reaction?4 H3PO4 ---> P4 + 5 O2 + 6 H2OSelect one:a. Decomposition.b. Double replacement.c. Single replacement.d. Synthesis.

Answers

Answer

A. Decomposition.

Explanation

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

the reaction of amino acids to form peptides involves which pair of functional groups?a. two carboxyl groupsb. an amino and a carboxyl groupc. two amino groupsd. a carboxyl and an alcohol group

Answers

The reaction of amino acids to form peptides involves a pair of functional groups consisting of an amino and a carboxyl group.

Amino acids are the building blocks of peptides and proteins, and they have an amino group (-NH2) and a carboxyl group (-COOH) attached to a central carbon atom. When two amino acids come together, the amino group of one amino acid reacts with the carboxyl group of the other amino acid, forming a peptide bond (-CO-NH-) and releasing a molecule of water. This process is called condensation or dehydration synthesis. The resulting peptide bond links the two amino acids together, and the chain can continue to grow as more amino acids are added.

The reaction of amino acids to form peptides involves the combination of an amino group and a carboxyl group. This process is known as a peptide bond formation or condensation reaction, in which the amino group (NH2) of one amino acid reacts with the carboxyl group (COOH) of another amino acid. This reaction results in the release of a water molecule (H2O) and the formation of a covalent bond between the two amino acids, creating a peptide. The peptide bond is represented as -CONH- and plays a crucial role in forming the primary structure of proteins.

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A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is a stainless-steel cylinder that measures
48.0cm
wide and
57.6cm
high. The maximum safe pressure inside the vessel has been measured to be
3.40MPa
.
For a certain reaction the vessel may contain up to
2.45kg
of carbon dioxide gas. Calculate the maximum safe operating temperature the engineer should recommend for this reaction. Write your answer in degrees Celsius. Round your answer to
3
significant digits.

Answers

The maximum safe operating temperature the engineer should recommend for this reaction is approximately 1063.77 degrees Celsius.

To calculate the maximum safe operating temperature, we need to consider the dimensions of the vessel, the maximum safe pressure, and the amount of gas inside.

First, let's convert the dimensions of the vessel from centimeters to meters:

Width = 48.0 cm = 0.48 m

Height = 57.6 cm = 0.576 m

Next, we need to calculate the volume of the vessel:

Volume = π * (radius)^2 * height

The radius of the vessel can be calculated as half of the width:

Radius = 0.48 m / 2 = 0.24 m

Volume = π * (0.24 m)^2 * 0.576 m

Volume ≈ 0.099 m^3

Now, we can use the ideal gas law to determine the maximum safe operating temperature. The ideal gas law is given by:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Rearranging the equation to solve for T:

T = (PV) / (nR)

To calculate the number of moles, we can use the molar mass of carbon dioxide (CO2):

Molar mass of CO2 = 12.01 g/mol (for carbon) + 2 * 16.00 g/mol (for oxygen)

Molar mass of CO2 ≈ 44.01 g/mol

Converting the mass of carbon dioxide from kilograms to grams:

Mass of CO2 = 2.45 kg * 1000 g/kg

Mass of CO2 = 2450 g

Now, we can calculate the number of moles:

Number of moles = Mass of CO2 / Molar mass of CO2

Number of moles = 2450 g / 44.01 g/mol

Number of moles ≈ 55.67 mol

The gas constant R is approximately 8.314 J/(mol·K).

Now, we can substitute the values into the equation:

T = (3.40 MPa * 0.099 m^3) / (55.67 mol * 8.314 J/(mol·K))

T ≈ 1063.77 K

Converting from Kelvin to Celsius:

T ≈ 1063.77 °C

The maximum safe operating temperature that the engineer should recommend for this reaction is approximately 1063.77 degrees Celsius.

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The number that identifies an atom is the same as the number of: *

Answers

Explanation:

atomic number = proton

How many moles of NaBr are there in 0. 50 liters of a 2. 1M NaBr solution?

Answers

Answer:

Explanation:

mOLARITY IS moles/L

moles = M X L

2.1 X 0.50 = 1.05 moles NaBr or 1.1 moles NaBr to correct sig figs

what is the binding energy in kj/mol ag for silver-109? kj/mol 47 62 the required masses (g/mol) are:

Answers

The binding energy per nucleon for silver-109 is 1.285 × 10⁻¹¹ kJ/mol.

In order to calculate the binding energy per nucleon, which is expressed in units of energy per mole of nuclei (kJ/mol), we need to use the following equation:

BE/A = (Δmc²)/A

where BE/A is the binding energy per nucleon, Δm is the mass defect (the difference between the actual mass of the nucleus and the sum of the masses of its constituent nucleons), c is the speed of light, and A is the mass number (the total number of protons and neutrons) of the nucleus.

The atomic mass of silver-109 is 108.90585 g/mol, so its mass number is 109. We also have the required masses of its constituent nucleons, which are 47 for protons and 62 for neutrons.

Using the atomic masses of silver-109 and its constituent nucleons, we can calculate the mass defect as follows:

Δm = (108.90585 g/mol - (47 × 1.007825 g/mol + 62 × 1.008665 g/mol)) = 0.008601 g/mol

where 47 and 62 are the numbers of protons and neutrons in the nucleus, respectively.

Converting the mass defect to energy using Einstein's famous equation E = mc² we get:

ΔE = Δmc² = (0.008601 g/mol) × (299792458 m/s)² = 7.732 × 10⁻⁴ J/mol

Finally, we convert the energy per nucleus to energy per mole of nuclei and then to kilojoules per mole by dividing by the Avogadro constant and multiplying by 10⁻³:

BE/A = ΔE/A × N_A × 10⁻³ = (7.732 × 10⁻⁴ J/mol)/(6.022 × 10²³ mol⁻¹) × 10⁻³ = 1.285 × 10⁻¹¹kJ/mol

Therefore, the binding energy per nucleon for silver-109 is 1.285 × 10⁻¹¹kJ/mol.

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What population and what problems were addressed in the first psychological clinic?-

Answers

The first psychological clinic addressed the population with mental health problems, providing specialized treatment and resources for comprehensive evaluations, diagnoses, and therapy.

The clinic emerged in response to the growing need for addressing mental health issues. It aimed to provide a dedicated space for individuals suffering from psychological problems, such as anxiety, depression, and other disorders. The main problem it addressed was the lack of resources and specialized treatment for mental health conditions.

The clinic offered comprehensive evaluations, diagnoses, and therapy to better understand and address these issues. It played a crucial role in reducing the stigma associated with mental health problems and providing support to those in need. In conclusion, the first psychological clinic was established to cater to the population with mental health problems, providing specialized treatment and resources for comprehensive evaluations, diagnoses, and therapy.

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what kind of molecular collisions will not lead to the formation of product in a reaction? only those without sufficient kinetic energy. only those with the wrong orientation, regardless of the kinetic energy. collisions between molecules that have more energy than the minimum required. those without sufficient kinetic energy and with the wrong orientation. those with effective collisions.

Answers

In a chemical reaction, not all molecular collisions result in the formation of products. There are several factors that can prevent the formation of products in a reaction. Let's explore these factors:

1. "Collisions without sufficient kinetic energy": For a reaction to occur, molecules must collide with enough energy to overcome the activation energy barrier.
2. "Collisions between molecules with more energy than the minimum required": It is worth noting that collisions between molecules with excess energy can still lead to product formation, as long as the other conditions for successful collisions (sufficient kinetic energy and proper orientation) are met.

On the other hand, collisions with sufficient kinetic energy and the correct orientation are termed "effective collisions" and have the potential to result in the formation of products. To summarize, not all molecular collisions in a reaction lead to product formation. Only collisions with sufficient kinetic energy and the correct orientation have the potential to result in successful reactions and the formation of products.

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Chemical properties of water and oxygen for class 8

Answers

Oxygen is a colorless, odorless, tasteless gas. It changes from a gas to a liquid at a temperature of -182.96°C (-297.33°F). The liquid formed has a slightly bluish color to it. Liquid oxygen can then be solidified or frozen at a temperature of -218.4°C (-361.2°F).Oxygen is a colorless, odorless, tasteless gas. It changes from a gas to a liquid at a temperature of -182.96°C (-297.33°F). The liquid formed has a slightly bluish color to it. Liquid oxygen can then be solidified or frozen at a temperature of -218.4°C (-361.2°F).Chemical formula H2OOxygen is a colorless, odorless, tasteless gas. It changes from a gas to a liquid at a temperature of -182.96°C (-297.33°F). The liquid formed has a slightly bluish color to it. Liquid oxygen can then be solidified or frozen at a temperature of -218.4°C (-361.2°F).Chemical formula H2OMolar mass 18.01528(33) g/molOxygen is a colorless, odorless, tasteless gas. It changes from a gas to a liquid at a temperature of -182.96°C (-297.33°F). The liquid formed has a slightly bluish color to it. Liquid oxygen can then be solidified or frozen at a temperature of -218.4°C (-361.2°F).Chemical formula H2OMolar mass 18.01528(33) g/molOdour NoneOxygen is a colorless, odorless, tasteless gas. It changes from a gas to a liquid at a temperature of -182.96°C (-297.33°F). The liquid formed has a slightly bluish color to it. Liquid oxygen can then be solidified or frozen at a temperature of -218.4°C (-361.2°F).Chemical formula H2OMolar mass 18.01528(33) g/molOdour NoneDensity Solid: 0.9167 g/ml at 0 °C Liquid: 0.961893 g/mL at 95 °C 0.9970474 g/mL at 25 °C 0.9998396 g/mL at 0 °C

A study was conducted of 90 adult male patients following a new treatment for congestive heart failure. One of the variables measured on the patients was the increase in exercise capacity (in minutes) over a 4-week treatment period. The previous treatment regime had produced an average increase of μ=2 minutes. The researchers wanted to evaluate whether the new treatment had increased the value of μ in comparison to the previous treatment. The data yielded y(bar)=2.17 and s=1.05.
(a) if the actual value of mu is 2.1 and alpha is reduced from 0.05 to 0.01, what would be the effect on the power curve?
(b) If the sample size is reduced from 90 to 50, what would be the effect on the power curve?

Answers

a. Decreasing alpha from 0.05 to 0.01 makes the significance level more stringent. You will be less likely to reject the null hypothesis, even when it's false. This increases the probability of a Type II error, thus potentially reducing the power of the test. The power curve will shift to the left.

b. If the sample size is reduced from 90 to 50, the effect on the power curve is that it will also shift towards the left.

What more should you know about decreasing the alpha and the power curve?

The power curve is a graph that shows the probability of rejecting the null hypothesis as a function of the true value of the mean.

In the given scenarios of this study, Reducing the significance level and reducing the sample size will shift the power curve to the left, indicating a decrease in the statistical power of the test.

The power of a statistical test is the probability that it correctly rejects the null hypothesis when the alternative hypothesis is true.

a) Reducing alpha from 0.05 to 0.01 means that we are more stringent in our assessment of whether the new treatment is effective.

This will result in a decrease in the power of the test, meaning that it is less likely that we will be able to detect a difference between the new treatment and the previous treatment.

b) If the sample size is reduced from 90 to 50, the effect on the power curve is that it will also shift towards the left.

This is because a smaller sample size decreases the power of the test. A larger sample size provides more information and thus makes it more likely to correctly reject the null hypothesis when the alternative hypothesis is true.

Therefore, by reducing the sample size, you are decreasing the likelihood of detecting a true effect if one exists, thus reducing the power of the test.

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How many molecules are present in 2.00 mol of KCl?

Answers

Answer:

The question specified 2 moles of potassium chloride. Clearly, there are 2 moles of chloride ions. How many moles of chloride ions in 95.2 g

a compound has the molecular formula c5h10o, and strong absorptions at 1100 and 3350 cm−1. which is the most likely structure for the compound?

Answers

According to the given statement Cyclopentanol  is the most likely structure for the compound.

Which is a molecular formula *?

The chemical formula for a molecular cell's molecular formula lists the variety of atoms that make up the unit. A subscript under oxygen in CO2, for instance, indicates that there are two oxygen atoms there, but a subscript under carbon indicates that there is just one carbon atom present.

What role does the molecular formula perform?

All the components that make up a chemical may be identified with the use of molecular formulae. For instance, it informs us that water is composed of hydrogen and oxygen. It is also possible to determine how many atoms of each kind are included in a molecule.

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Chameleons have modified their feet into pincher-like grippers to hold onto branches. Ignore the prehensile tail for this problem. This panther chameleon has a mass of 150 grams, and the coefficient of friction between its skin and the branch is 0.5 If the chameleon did not grip at all, and just relied on body weight and friction, how much force would it take to make the chameleon slip, in Newtons? If the chameleon grips with a force of 2 Newtons on each foot, how much force would make it slip if gripping with all four feet in Newtons? Include the prior force in addition to the effect of gripping. Chameleons can move upside-down on branches. How many feet must the chameleon grip with to prevent itself from slipping off? 1

Answers

It would take a force of approximately 0.735 Newtons to make the chameleon slip without gripping and a force of approximately 7.265 Newtons would make the chameleon slip when gripping with a force of 2 Newtons on each foot.

To calculate the force required to make the chameleon slip without gripping, we can use the equation:

Force = Frictional force

The frictional force can be determined using the equation:

Frictional force = coefficient of friction * Normal force

Without gripping:

Given:

Mass of the chameleon (m) = 150 grams = 0.15 kg

Coefficient of friction (μ) = 0.5

The normal force is equal to the weight of the chameleon, which can be calculated as:

Normal force = mass * acceleration due to gravity

= m * g

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Normal force = 0.15 kg * 9.8 m/s^2

= 1.47 N

Frictional force = μ * Normal force

= 0.5 * 1.47 N

= 0.735 N

Therefore, it would take a force of approximately 0.735 Newtons to make the chameleon slip without gripping.

With gripping:

If the chameleon grips with a force of 2 Newtons on each foot (total of four feet), the gripping force should be considered in addition to the effect of friction.

Total gripping force = Gripping force per foot * Number of feet gripping

= 2 N/foot * 4 feet

= 8 N

To determine the force required to make the chameleon slip while gripping, we subtract the gripping force from the frictional force:

Force to make chameleon slip with gripping = Frictional force - Total gripping force

= 0.735 N - 8 N

= -7.265 N (negative sign indicates the force required to overcome the gripping force)

Therefore, a force of approximately 7.265 Newtons would make the chameleon slip when gripping with a force of 2 Newtons on each foot.

Number of feet required to prevent slipping:

To prevent itself from slipping off, the chameleon must grip with at least three feet. Gripping with three feet ensures stability and prevents the body from rotating or tilting, which would lead to slipping.

Therefore, the chameleon must grip with at least three feet to prevent itself from slipping off.

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EASY QUESTION (PLEASE HELP THE INTERNET ISN'T SUCH A BIG HELP RIGHT NOW)
Things microscopes have helped scientists discover about cells.

Answers

Answer:

Again, Microscopes discovered a lot of things in biology like the prokaryotic cells, Bacteria and Archaea, aswell as parts of an organelle/cell.

What is the volume of 0.58 moles
of H2 gas at STP?

Answers

Answer:

volume = 0.013 m³

Explanation:

The question asks us to calculate the volume of 0.58 moles of H₂ gas at STP.

To do this, we must use the ideal gas equation:

\(\boxed{pV = nRT}\),

where:

• p = pressure in Pa

• V = volume in m³

• n = number of moles

• R = molar gas constant (8.31 Jkg⁻¹K⁻¹)

• T = temperature in K

From the question, we know that the number of moles of H₂ is 0.58. Therefore,  n = 0.58. We also know that the volume is asked for when the gas is at STP, therefore: T = 273 K, and p = 101.3 × 10³ Pa.

Using this data and the formula above, we can calculate the volume of the gas:

pV = nRT

⇒ 101.3 × 10³  ×  V = 0.58 × 8.31 × 273

⇒ V = \(\frac{0.58 \times 8.31 \times 273}{101.3 \times 10^3}\)

⇒ V = 0.013 m³

Therefore, the volume of the gas is 0.013 m³.

How many Joules of heat are needed to raise the temperature of 500. grams of water from 15.0ºC to 20.0ºC?

Answers

Answer: 2,090J

The equation to find the specific heat is determined by the equation q = mcΔT, where q = total heat, m=mass, c = specific heat, and ∆T change in temperature.

Recall that the specific heat capacity for water is 4.18J/gºC

So, plug this along with your specific values into the equation.

q = 100g * (4.18J/gºC) * (20.0ºC-15.0ºC)
q = 2090J

how many bonded atoms in borane (BH3)?

Answers

Answer: In this case, there are a total of 4 atoms (1 boron atom and 3 hydrogen atoms) bonded together in the molecule.

Explanation:  Borane is a chemical compound that contains one boron atom bonded to three hydrogen atoms. The chemical formula for borane is BH3, indicating that it contains one boron atom bonded to three hydrogen atoms. Borane is a molecule, which means it is composed of two or more atoms bonded together chemically. In this case, there are a total of 4 atoms (1 boron atom and 3 hydrogen atoms) bonded together in the molecule.

Answer : three bonds
Borane (BH3) is a Lewis acid that has one B atom and three H atoms. In the Lewis structure of borane, each hydrogen atom is bonded to boron by a single bond (BH3). Only three bonds surround the boron atom, and there are no lone pairs on the boron atom.

Ozzie wanted to do another experiment with a stronger H2O2 solution to check the accuracy of the experiment by calculating the theoretical volume of O2(g) it would produce. Then he could compare his experimental volume of O2(g) to the theoretical volume of O2(g). He used 7.40 mL of 3.53 M H2O2 and the partial pressure of O2 was 0.9604 atm and the temperature was 294.05 K. What volume of O2(g) could he theoretically produce (in mL)

Answers

The theoretical volume of oxygen produced is 0.934 mL. Therefore, the volume of \(O_2\)(g) that Ozzie could theoretically produce is 0.934 mL.

The chemical equation for the decomposition of hydrogen peroxide is

\(2H_2O_2(l)-> 2H_2O(l) + O_2(g)\)

A mole ratio of 1:1 exists between the volume of oxygen produced and the volume of hydrogen peroxide decomposed. This is expressed in terms of Avogadro's principle: 1 mole of a gas occupies 24.5 L at standard temperature and pressure (STP).

When a solution of hydrogen peroxide is decomposed, the volume of oxygen gas produced can be calculated using the ideal gas law as given below :PV = nRT

Where,P = pressure of the gas (atm)V = volume of the gas (L)n = number of moles of the gasR = ideal gas constant = 0.0821 L atm/(mol K)T = temperature of the gas (K)

Number of moles of \(O_2\) produced can be calculated as follows:

0.9604 atm (V) = n (0.0821 L atm/mol K) (294.05 K)n = 0.0381 mol .

As given earlier, the mole ratio of \(H_2O_2\) to\(O_2\) is 1:1, i.e.,0.0381 mol \(O_2\)= 0.0381 mol \(H_2O_2\)Volume of \(H_2O_2\) used = 7.40 mL = 0.00740 L . Concentration of\(H_2O_2\)used = 3.53 M .

Molar mass of\(H_2O_2\)= 34 g/molTherefore, number of moles of\(H_2O_2\) used = 0.00740 L × 3.53 mol/L = 0.0261 molVolume of O2 produced can be calculated as follows:0.0381 mol \(O_2\) × 24.5 L/mol = 0.934 mL .

The theoretical volume of oxygen produced is 0.934 mL. Therefore, the volume of \(O_2\)(g) that Ozzie could theoretically produce is 0.934 mL.

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Match the terms with their definitions.

Tropical air masses


Polar air masses

1.
These air masses are warm and formed near the equator.

2.
These air masses are cold and formed near the north or south poles.

Answers

Tropical matches with 1
Polar matched with 2

A sample of oxygen gas has a volume of 4 L when the pressure is equal to 30 kPa. The gas is allowed to expand into a 2.75 L container. Calculate the new pressure of the gas.

Answers

When the petrol expands inside a 2.75 L container, its new pressure is 43.6 kPa.

Calculation-

The initial and final volumes of the gas are given as:

V1 = 4 L (initial volume)

V2 = 2.75 L (final volume)

The ideal gas law states that an ideal gas's pressure, volume, and molecular weight are related by:

PV = nRT

where R is the gas constant (8.31 J/(mol K) at standard conditions), T is the absolute temperature, P is the pressure, V is the volume, n is the number of moles, and V is the volume.

As the gas's temperature and number of moles are both constant in this situation, we may write:

P1V1 = P2V2

where P1 is the initial pressure and P2 is the final pressure.

Substituting the given values, we get:

P2 = P1V1/V2 = (30 kPa)(4 L)/(2.75 L) = 43.6 kPa

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A 100.0-mL aliquot of 0.200 M aqueous potassium hydroxide is mixed with 100.0 mL of 0.200 M
aqueous magnesium nitrate.
(a) Write a balanced chemical equation for any reaction that occurs.
(b) What precipitate forms?
(c) What mass of precipitate is produced?
(d) Calculate the concentration of each ion remaining in solution after precipitation is complete.

i mostly need help on the last one

Answers

The balanced equation of the reaction is:

2 KOH (aq) + Mg(NO₃)₂ ---> Mg(OH)₂ (s) + 2 KNO₃ (aq)

The precipitate formed is magnesium hydroxide.

The mass of precipitate produced is 0.58 g.

The concentration of the ions remaining in the solution are:

[Mg²⁺] = 0.05 M

[NO₃⁻] = 0.1 M

What is the balanced equation of the reaction of aqueous potassium hydroxide and aqueous magnesium nitrate?

The balanced equation of the reaction of aqueous potassium hydroxide and aqueous magnesium nitrate is given below:

2 KOH (aq) + Mg(NO₃)₂ ---> Mg(OH)₂ (s) + 2 KNO₃ (aq)

Magnesium hydroxide is obtained as a precipitate in the reaction above.

The mass of precipitate produced is calculated as follows:

moles of KOH (aq) reacting = 0.200 * 100 / 1000 = 0.02 moles

moles of Mg(NO₃)₂ reacting = 0.2 * 100 / 1000 = 0.02 moles

From the equation of reaction, KOH is the limiting reagent.

Moles of precipitate formed = 0.02 / 2 = 0.01 moles

molar mass of Mg(OH)₂ (s) = 58 g/mol

Mass of precipitate formed = 0.01 * 58

Mass of precipitate formed = 0.58 g

Moles of Mg(NO₃)₂ remaining = 0.02 - 0.01 = 0.01 moles

total volume of solution = 200 mL or 0.2 L

The concentration of each ion remaining in the solution is as follows:

[Mg²⁺] = 0.01 / 0.2 = 0.05 M

[NO₃⁻] = 0.01 * 2 / 0.2 = 0.1 M

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Write a complete, balanced chemical equation where tin metal reacts with aqueous hydrochloric acid to produce tin(II) chloride and hydrogen gas. Include states.

From the equation, which element is oxidized, and which element is reduced?

Answers

Answer:

Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)

Explanation:

The net reaction is Z n ( s ) + 2 H + ( a q ) → Z n 2 + ( a q ) + H 2 ( g ) The C l − ions are spectators - they don't change.

What defines the mass number of an isotope? the sum of the neutrons and protons the sum of the neutrons and electrons the number of neutrons the number of protons

Answers

Answer:

The mass number of an isotope is the sum of neutrons and protons.

Explanation:

In any elemental isotope, the only things that will affect molar mass and mass number is the number of protons and neutrons. Electrons are not counted because we usually assume they are equal to the amount of protons and have no weight.

Protons are what gives the element its atomic number and the neutrons determine the type of isotope it is within the element.

For instance:

There can be a regular Carbon - 12

But there are isotopes like Carbon - 13 and Carbon - 14.

*The number of protons stays the same but the number of neutrons are different

Which units express heat capacity? J/°C, J/K, cal/°C, cal/K J/(gi°C), J/(giK), cal/(gi°C), cal/(giK) J, cal °C, K

Answers

Answer:

a

Explanation:

The heat capacity of a substance is the heat energy required to rise its temperature per one degree Celsius. Hence its unit is J/°C.

What is heat capacity ?

Heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius or 1 Kelvin. It is expressed in the following units:

Joules per degree Celsius (J/°C)

Joules per Kelvin (J/K)

Calories per degree Celsius (cal/°C)

Calories per Kelvin (cal/K)

Joules per gram per degree Celsius (J/(g·°C))

Joules per gram per Kelvin (J/(g·K)) etc.

If in terms of simply the energy, then, The following units are used.

Joules (J) , Calories (cal) , Degrees Celsius (°C), Kelvin (K)

The choice of unit depends on the specific application and the system of units being used. The SI unit for heat capacity is J/K, while the traditional unit is cal/°C.

The use of per gram units is common in the context of specific heat capacity, which is the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 degree Celsius or 1 Kelvin.

Therefore, here, the unit of heat capacity is J/°C.

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CH3OH can be synthesized by the reaction:
CO(g) + 2 H20) — CH3OH)
What volume of CH3OH gas (in L) can be synthesized if 18.6 L of Hy gas completely reacts at STP conditions?

Answers

Answer:

5

Explanation:

Iron(111)Carbonate +cesium > cesium carbonate +iron balced

Answers

Balanced chemical equation for the given reaction is Fe₂(CO₃)₃ + 6Cs → 3Cs₂CO₃ + 2Fe.

What is balanced equation?

Balanced chemical equations are those equations in which all entities are present in equal amount on reactant side as well as on product side.

Given balanced chemical reaction is:
Fe₂(CO₃)₃ + 6Cs → 3Cs₂CO₃ + 2Fe

Above given equation is a balanced chemical equation where all atoms of reactant as well as of products are present in same amount.

Hence, required balanced equation is Fe₂(CO₃)₃ + 6Cs → 3Cs₂CO₃ + 2Fe.

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Who am I? Most of us have characteristics of both metal and nonmetals—dull or shiny, brittle, malleable or ductile.


Metalloids


Metals


Nonmetals

Answers

the answer to your question is

Answer:

Meralloids is the answer because they contain all of those characteristics

Which postulate of john dalton's atomic theory was quickly proved wrong by jj thomson and robert millikan?

Answers

The postulate oh John Dalton's atomic theory that was quickly proved wrong by JJ Thomson and Robert Mullikan was that atoms are indivisible.

Dalton was the first scientist to give a theory about atoms in which he gave several postulates like

1) Atoms of same particles are identical in shape, size and color.

2) Atom is the smallest unit of any matter.

3) Atoms can neither be created nor be destroyed.

4) Atoms of different elements combine with each other in fixed number or ratios to give new molecules.

Although Dalton's model initially got much appreciation but one postulate that is atoms is the smallest unit of any matter which means atoms are indivisible was proved wrong by JJ Thomson through his discovery of of electrons and by Robert Millikan through his discovery of the elementary charge of an electron.

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